sp lecture 20 - ac circuits lecture 20 - ac...electricity & magne?sm lecture 20, slide 22...

29
AC Circuits Maximum currents & voltages Phasors: A Simple Tool Electricity & Magnetism Lecture 20 Today’s Concept: Electricity & Magne?sm Lecture 20, Slide 1

Upload: others

Post on 04-Aug-2020

8 views

Category:

Documents


0 download

TRANSCRIPT

Page 1: SP Lecture 20 - AC Circuits Lecture 20 - AC...Electricity & Magne?sm Lecture 20, Slide 22 Consider the harmonically driven series LCR circuit shown. V max = 100 V I max = 2 mA V Cmax

ACCircuitsMaximumcurrents&voltages

Phasors:ASimpleTool

Electricity & MagnetismLecture 20

Today’sConcept:

Electricity&Magne?smLecture20,Slide1

Page 2: SP Lecture 20 - AC Circuits Lecture 20 - AC...Electricity & Magne?sm Lecture 20, Slide 22 Consider the harmonically driven series LCR circuit shown. V max = 100 V I max = 2 mA V Cmax

Comments

doesn'tacapacitorblowupwhencurrentisthewrongway?

Howdoyouknowwhichwaythecurrentisgoingwhenitstartsorwhatorienta?ontodrawthevectorsatthestart?

Thepre-lecturesaresohardtofollowthattobequitehonesthemightaswellbespeakingklingon.Formulasflashbeforemyeyesasfastasmygradeswilldropinthisclass.Pleaseexplaintheseconceptsdifferentlythanthepre-lecture.

Page 3: SP Lecture 20 - AC Circuits Lecture 20 - AC...Electricity & Magne?sm Lecture 20, Slide 22 Consider the harmonically driven series LCR circuit shown. V max = 100 V I max = 2 mA V Cmax
Page 5: SP Lecture 20 - AC Circuits Lecture 20 - AC...Electricity & Magne?sm Lecture 20, Slide 22 Consider the harmonically driven series LCR circuit shown. V max = 100 V I max = 2 mA V Cmax

Resistors

R I = VR/R = Vmax/R sin(ωt)

Amplitude=Vmax/R

ε = Vmaxsin(ωt)

Electricity&Magne?smLecture20,Slide3

Page 6: SP Lecture 20 - AC Circuits Lecture 20 - AC...Electricity & Magne?sm Lecture 20, Slide 22 Consider the harmonically driven series LCR circuit shown. V max = 100 V I max = 2 mA V Cmax

Capacitors

C I = VmaxωC cos(ωt)

whereXC=1/ωC islikethe“resistance” ofthecapacitorXCdependsonω

Amplitude=Vmax/XC

I = dQ/dt

Q = CV = CVmaxsin(ωt)

90o

ε = Vmaxsin(ωt)

Electricity&Magne?smLecture20,Slide4

Page 7: SP Lecture 20 - AC Circuits Lecture 20 - AC...Electricity & Magne?sm Lecture 20, Slide 22 Consider the harmonically driven series LCR circuit shown. V max = 100 V I max = 2 mA V Cmax

Inductors

L I = − (Vmax/ωL) cos(ωt)

Amplitude = Vmax/XL

whereXL=ωL islikethe“resistance” oftheinductorXLdependsonω

dI/dt = VL = Vmaxsin(ωt)

90o

ε = Vmaxsin(ωt)

Electricity&Magne?smLecture20,Slide5

Page 8: SP Lecture 20 - AC Circuits Lecture 20 - AC...Electricity & Magne?sm Lecture 20, Slide 22 Consider the harmonically driven series LCR circuit shown. V max = 100 V I max = 2 mA V Cmax

RL Clicker Question

AnRLcircuitisdrivenbyanAC generatorasshowninthefigure.

ForwhatdrivingfrequencyωofthegeneratorwillthecurrentthroughtheresistorbelargestA)ωlargeB)CurrentthroughRdoesn’tdependonω C)ωsmall

L

R

XL = ωL

Asω → 0, sodoesXL

As ω → 0, resistanceofcircuit→R currentgetsbigger

Electricity&Magne?smLecture20,Slide6

impedance

Page 9: SP Lecture 20 - AC Circuits Lecture 20 - AC...Electricity & Magne?sm Lecture 20, Slide 22 Consider the harmonically driven series LCR circuit shown. V max = 100 V I max = 2 mA V Cmax

R Imax = Vmax/R VR inphasewithI

L Imax = Vmax/XL VL 90o aheadofIXL = ωL

C Imax = Vmax/XC VC 90o behind IXC = 1/ωC Currentcomesfirstsinceit

chargescapacitor

Becauseresistorsaresimple

Oppositeofcapacitor

Likeawireathighω

Likeawireatlowω

Summary

Electricity&Magne?smLecture20,Slide7

Page 10: SP Lecture 20 - AC Circuits Lecture 20 - AC...Electricity & Magne?sm Lecture 20, Slide 22 Consider the harmonically driven series LCR circuit shown. V max = 100 V I max = 2 mA V Cmax

Vmax = Imax XL

Vmax = Imax XC

Vmax = Imax RV inphasewithI

V 90o behind I

V 90o aheadofI

MakessensetowriteeverythingintermsofIsincethisisthesameeverywhereinaone-loopcircuit: Imax XL

Imax XC

Imax R

Phasorsmakethis simpletosee

Alwayslooksthesame. Onlythelengthswillchange

εmax

“Doyouhaveanyfancy-schmancysimula?onsfortoshowme?”

Electricity&Magne?smLecture20,Slide8

Page 11: SP Lecture 20 - AC Circuits Lecture 20 - AC...Electricity & Magne?sm Lecture 20, Slide 22 Consider the harmonically driven series LCR circuit shown. V max = 100 V I max = 2 mA V Cmax

AC Circuit Simulations

hfp://www2.epsd.us/robo?cs/phet/en/simula?on/circuit-construc?on-kit-ac.html

Page 12: SP Lecture 20 - AC Circuits Lecture 20 - AC...Electricity & Magne?sm Lecture 20, Slide 22 Consider the harmonically driven series LCR circuit shown. V max = 100 V I max = 2 mA V Cmax

Imax XL

Imax XC

Imax R Imax XL

Imax R

Imax XC

εmax

Butnowweareaddingvectors:

Imax XL

Imax XC

Imax R

εmax

The Voltages still Add Up

Electricity&Magne?smLecture20,Slide9

Page 13: SP Lecture 20 - AC Circuits Lecture 20 - AC...Electricity & Magne?sm Lecture 20, Slide 22 Consider the harmonically driven series LCR circuit shown. V max = 100 V I max = 2 mA V Cmax

Imax XL

Imax XC

Imax R

εmax

Make this Simpler

Imax XL

Imax XC

Imax R

Electricity&Magne?smLecture20,Slide10

Page 14: SP Lecture 20 - AC Circuits Lecture 20 - AC...Electricity & Magne?sm Lecture 20, Slide 22 Consider the harmonically driven series LCR circuit shown. V max = 100 V I max = 2 mA V Cmax

Imax R

εmax = Imax ZImax(XL − XC)

Make this Simpler

Imax XL

Imax XC

Imax R

Electricity&Magne?smLecture20,Slide11

Page 15: SP Lecture 20 - AC Circuits Lecture 20 - AC...Electricity & Magne?sm Lecture 20, Slide 22 Consider the harmonically driven series LCR circuit shown. V max = 100 V I max = 2 mA V Cmax

Imax R

εmax = Imax Z

Imax(XL − XC)

Make this Simpler

Electricity&Magne?smLecture20,Slide12

Page 16: SP Lecture 20 - AC Circuits Lecture 20 - AC...Electricity & Magne?sm Lecture 20, Slide 22 Consider the harmonically driven series LCR circuit shown. V max = 100 V I max = 2 mA V Cmax

Imax R

εmax = Imax Z

Imax(XL − XC)

R(X

L − XC )

φ

φ

ImpedanceTriangle

Make this Simpler

Electricity&Magne?smLecture20,Slide13

Page 17: SP Lecture 20 - AC Circuits Lecture 20 - AC...Electricity & Magne?sm Lecture 20, Slide 22 Consider the harmonically driven series LCR circuit shown. V max = 100 V I max = 2 mA V Cmax

φ

R (XL − X

C )

VCmax = Imax XC

VLmax = Imax XL

VRmax = Imax R

Summary

Imax = εmax / Z

εmax = Imax Z

Electricity&Magne?smLecture20,Slide14

Page 18: SP Lecture 20 - AC Circuits Lecture 20 - AC...Electricity & Magne?sm Lecture 20, Slide 22 Consider the harmonically driven series LCR circuit shown. V max = 100 V I max = 2 mA V Cmax

Imax XL

Imax R

εmax

Example: RL Circuit Xc = 0

Electricity&Magne?smLecture20,Slide15

Page 19: SP Lecture 20 - AC Circuits Lecture 20 - AC...Electricity & Magne?sm Lecture 20, Slide 22 Consider the harmonically driven series LCR circuit shown. V max = 100 V I max = 2 mA V Cmax

ABC

DrawVoltagePhasors

CheckPoint 2

Imax XL

Imax R

εmax

Electricity&Magne?smLecture20,Slide16

Page 20: SP Lecture 20 - AC Circuits Lecture 20 - AC...Electricity & Magne?sm Lecture 20, Slide 22 Consider the harmonically driven series LCR circuit shown. V max = 100 V I max = 2 mA V Cmax

ABC

CheckPoint 4

DrawVoltagePhasorsImax XL

Imax R

εmax

Electricity&Magne?smLecture20,Slide17

Page 21: SP Lecture 20 - AC Circuits Lecture 20 - AC...Electricity & Magne?sm Lecture 20, Slide 22 Consider the harmonically driven series LCR circuit shown. V max = 100 V I max = 2 mA V Cmax

TheCURRENTisTHECURRENT

ABCD

φ isthephasebetweengeneratorandcurrent

φ

CheckPoint 6

Imax XL

Imax R

εmax

Electricity&Magne?smLecture20,Slide18

Page 22: SP Lecture 20 - AC Circuits Lecture 20 - AC...Electricity & Magne?sm Lecture 20, Slide 22 Consider the harmonically driven series LCR circuit shown. V max = 100 V I max = 2 mA V Cmax

CheckPoint 8

ABC

Whatdoesthevoltagephasordiagramlooklikewhenthecurrentisamaximum?

IXc

IRε

IXL

IXc

IR

εIXL

Electricity&Magne?smLecture20,Slide19

Page 23: SP Lecture 20 - AC Circuits Lecture 20 - AC...Electricity & Magne?sm Lecture 20, Slide 22 Consider the harmonically driven series LCR circuit shown. V max = 100 V I max = 2 mA V Cmax

Whatdoesthevoltagephasordiagramlooklikewhenthecapacitorisfullycharged?

ABC

IXc

IRε

IXL

IXc

IR

εIXL

CheckPoint 10

Electricity&Magne?smLecture20,Slide20

Page 24: SP Lecture 20 - AC Circuits Lecture 20 - AC...Electricity & Magne?sm Lecture 20, Slide 22 Consider the harmonically driven series LCR circuit shown. V max = 100 V I max = 2 mA V Cmax

CheckPoint 12

Whatdoesthevoltagephasordiagramlooklikewhenthevoltageacrosscapacitorisatitsposi?vemaximum?

A B C

IXc

IRε

IXL

IXc

IR

εIXL

Electricity&Magne?smLecture20,Slide21

Page 25: SP Lecture 20 - AC Circuits Lecture 20 - AC...Electricity & Magne?sm Lecture 20, Slide 22 Consider the harmonically driven series LCR circuit shown. V max = 100 V I max = 2 mA V Cmax

ConceptualAnalysisThemaximumvoltageforeachcomponentisrelatedtoitsreactanceandtothe

maximumcurrent.Theimpedancetriangledeterminestherela?onshipbetweenthemaximum

voltagesforthecomponentsStrategicAnalysis

UseVmaxandImaxtodetermineZ UseimpedancetriangletodetermineRUseVCmaxandimpedancetriangletodetermineXL

C

RLV

Calculation

Electricity&Magne?smLecture20,Slide22

ConsidertheharmonicallydrivenseriesLCRcircuitshown.Vmax = 100 V Imax = 2 mA VCmax = 113 V Thecurrentleadsgeneratorvoltageby45o

LandRareunknown.

WhatisXL,thereactanceoftheinductor,atthisfrequency?

~

Page 26: SP Lecture 20 - AC Circuits Lecture 20 - AC...Electricity & Magne?sm Lecture 20, Slide 22 Consider the harmonically driven series LCR circuit shown. V max = 100 V I max = 2 mA V Cmax

CompareXLandXCatthisfrequency:

A)XL < XC B)XL = XC C)XL > XC D)Notenoughinforma?on

Thisinforma?onisdeterminedfromthephaseCurrentleadsvoltage

VL = ImaxXL VC = ImaxXC

VR (phaseofcurrent)

VL

VC V leads

IR

V

45ο

Calculation

C

RLV

Electricity&Magne?smLecture20,Slide23

ConsidertheharmonicallydrivenseriesLCRcircuitshown.Vmax = 100 V Imax = 2 mA VCmax = 113 V Thecurrentleadsgeneratorvoltageby45o

LandRareunknown.

WhatisXL,thereactanceoftheinductor,atthisfrequency?

~

Page 27: SP Lecture 20 - AC Circuits Lecture 20 - AC...Electricity & Magne?sm Lecture 20, Slide 22 Consider the harmonically driven series LCR circuit shown. V max = 100 V I max = 2 mA V Cmax

WhatisZ,thetotalimpedanceofthecircuit?

A)B)C)D)35.4 kΩ50 kΩ 21.1 kΩ70.7 kΩ

Calculation

C

RLV

Electricity&Magne?smLecture20,Slide24

ConsidertheharmonicallydrivenseriesLCRcircuitshown.Vmax = 100 V Imax = 2 mA VCmax = 113 V Thecurrentleadsgeneratorvoltageby45o

LandRareunknown.

WhatisXL,thereactanceoftheinductor,atthisfrequency?

~

Page 28: SP Lecture 20 - AC Circuits Lecture 20 - AC...Electricity & Magne?sm Lecture 20, Slide 22 Consider the harmonically driven series LCR circuit shown. V max = 100 V I max = 2 mA V Cmax

WhatisR?A)B)C)D)

Z = 50 kΩ

sin(45°) =0.707

cos(45°) =0.70735.4 kΩ50 kΩ 21.1 kΩ70.7 kΩ

= 50 kΩ × 0.707

= 35.4 kΩ

Calculation

C

RLV

DeterminedfromimpedancetriangleR

Z = 50kΩ

(XC − XL)45ο R = Z cos(45o)

Electricity&Magne?smLecture20,Slide25

ConsidertheharmonicallydrivenseriesLCRcircuitshown.Vmax = 100 V Imax = 2 mA VCmax = 113 V Thecurrentleadsgeneratorvoltageby45o

LandRareunknown.

WhatisXL,thereactanceoftheinductor,atthisfrequency?

~

Page 29: SP Lecture 20 - AC Circuits Lecture 20 - AC...Electricity & Magne?sm Lecture 20, Slide 22 Consider the harmonically driven series LCR circuit shown. V max = 100 V I max = 2 mA V Cmax

A)B)C)D)

Z = 50 kΩ

R = 35.4kΩ

WhatisXC?

35.4 kΩ50 kΩ 21.1 kΩ70.7 kΩ

VCmax = ImaxXC

Calculation

ConsidertheharmonicallydrivenseriesLCRcircuitshown.Vmax = 100 V Imax = 2 mA VCmax = 113 V Thecurrentleadsgeneratorvoltageby45o

LandRareunknown.

WhatisXL,thereactanceoftheinductor,atthisfrequency?

~

C

RLV

XL = XC − R

XL = 56.5 kΩ − 35.4 kΩ

R

Z(XC − XL)

45ο

Westartwiththeimpedancetriangle:

Electricity&Magne?smLecture20,Slide26