Solve the following equations for x. Show work!Round to 2 decimal places. 1.

2.

3.

4.

5. Keith has $7200 to invest for 5 years compounded continuously. What interest rate would he need to get in order to have $10080 in 5 years?

6. Darla buys a laptop for $550. If the value of the laptop depreciates 29% each year, how many years until the laptop is only worth $220?

Warmup 12-10

2ln5x 23 31

293 11 143xe

27log (4 20) 63x

2 176 19 73x

Solve the following equations for x. Show work!Round to 2 decimal places. 1.

2.

3.

4.

5. Keith has $6400 to invest at 4.25% interest compounded quarterly. How many years would it take him to double his money?

6. Carla has $5600 to invest for 7 years, with interest compounded continuously. What interest rate would she need in order to have $9800 at the end of the 7 years?

Warmup 12-10

7ln(4x 32) 52 94

3 395 41 266xe

8log (5 65) 95 63x

6 439 57 173x

Algebra 2 Normal Curve Analysis Practice

The mean and standard deviation are given for several classes below. For each one, set up and label a normal curve for each data set including the mean and 3 standard deviation marks on each side. Then for each curve give the test score range that would account for 68%, 95% and 99% of the scores.

1. Class 1 : mean = 84 and standard deviation = 4

68% = __________ 95% = __________ 99% = ___________

2. Class 2: mean = 79 and standard deviation = 6.

68% = __________ 95% = __________ 99% = ___________

3. Class 3 mean = 73 and standard deviation = 8

68% = __________ 95% = __________ 99% = __________ 4. Class 4 mean = 82 and standard deviation = 5

68% = __________ 95% = __________ 99% = __________

5. Class 5 mean = 76 and standard deviation = 7

68% = __________ 95% = __________ 99% = __________ 6. Class 6 mean = 88 and standard deviation = 3

68% = __________

95% = __________ 99% = __________

Use the graph from #3 above to answer to find what percentage of the data is in each range given below.

7. Greater than 65

8. Between 57 and 81

9. Between 65 and 97

10. Greater the 89

11. Less than 81

12. Between 73 and 97

Use the graph from #6 above to answer to find what percentage of the data is in each range given below. 7. Less than 91

8. Between 82 and 97

9. Greater than 91

10. Between 79 and 88

11. Less than 94

12. Between 82 and 97

Ticket out the door 12-10Normal Curve Percentages

The mean and standard deviation are given for a class below. Set up and label a normal curve for the data set including the mean and 3 standard deviation marks on each side. Then give the test score range that would account for 68%, 95% and 99% of the scores.

1. Class 1 : mean = 74 and standard deviation = 9

68% = __________ 95% = __________

99% = ___________

Use your curve above to tell what percentage is:

2. Greater than 65?

3. Between 56 and 101?

4. Between 47 and 74?

5. Less than 92?

6. Greater than 83?

7. Less than 74?

Standard Normal Curve

-3 -2 -1 0 1 2 3 x - 3 x - 2 x - x x + x + 2 x + 3

x = mean of data set

= standard deviation of data set

Important % ranges for NORMAL CURVE DATA:1. Between -1 and 1 = 68% of the data(or the “middle 68%”)2. Between -2 and 2 = 95% of the data3. Between -3 and 3 = 99.7% of the data

.15% 2.35% 13.5% 34% 34% 13.5% 2.35% .15%

EXAMPLESFinding Standard Normal Curve Percentages

The mean and standard deviation are given for a class below. Set up and label a normal curve for the data set including the mean and 3 standard deviation marks on each side. Then give the test score range that would account for 68%, 95% and 99% of the scores.

1. Class 1 : mean = 75 and standard deviation = 5

68% = __________ 95% = __________

99% = ___________

Use the curve above to tell what percentage is:

2. Less than 85?

3. Greater than 70?

4. Between 60 and 80?

5. Greater than 80?

6. Less than 70?

7. Between 75 and 90?

EXAMPLES(cont)Finding Standard Normal Curve Percentages

The mean and standard deviation are given for a class below. Set up and label a normal curve for the data set including the mean and 3 standard deviation marks on each side. Then give the test score range that would account for 68%, 95% and 99% of the scores.

8. Class 2 : mean = 67 and standard deviation = 11

68% = __________ 95% = __________

99% = ___________

Use the curve above to tell what percentage is:

9. Greater than 78?

10. Between 56 and 100?

11. Less than 89?

12. Between 45 and 78?

13. Greater than 56?

14. Less than 45?