significant figures
DESCRIPTION
Significant Figures. Significant Figure Rules. 1. All Nonzeros are significant. 523 g = 3 sig figs 4222 cm 3 = 4 sig figs. 2. All numbers between significant figures are significant. 4,404 g = 4 sig figs 9.005 mm = 4 sig figs 5,000,102 mg = 7 sig figs. - PowerPoint PPT PresentationTRANSCRIPT
Significant Figure Rules
1. All Nonzeros are significant.523 g =
3 sig figs
4222 cm3=
4 sig figs
2. All numbers between significant figures are significant.4,404 g = 4 sig figs9.005 mm = 4 sig figs5,000,102 mg = 7 sig figs
3. All final zeros past the decimal are significant.9509.90 cm =
6 sig figs
52.000 km =
5 sig figs
4. Zeros used solely as placeholders are NOT significant.42,000 L = 2 sig figs42,000.00 L = 7 sig figs0.000802 g = 3 sig figs
1. Find the part of the problem with the least number of sig figs.142 m x 1552 m x 0.25 m =
Which measurement has the least?
0.25 m only has 2 sig figs.
2. Round your answer so it has that number of sig figs.
142 m x 1552 m x 0.25 m =55,096=
55,000
3. UnitsWhen multiplying, add the exponents.142 m x 1552 m x 0.25 m =55,000 m3
When dividing, subtract the exponents.
12 g3 ÷ 6 g = 2 g2
18 g ÷ 2 cm3 = 9 g/ cm3
1. Find the least accurate measurement in the problem.14.3 g + 99 g + 40 g =
40 g is the least accurate measurement. It is rounded to the nearest 10
2. Make your answer match the least accurate measurement. 14.3 g + 99 g + 40 g =
153.3 g must be rounded to the nearest ten
The answer is 150 g
More Examples300 g - 193 g - 21.2 g =
85.8
Since 300g is the least accurate measurement, your answer must be rounded to the nearest 100.
The answer is 100 g
Examples cont.14.2 m + 12.36 m =
26.56
Since 14.2 is the least accurate measurement, the answer must be rounded to the nearest tenth.
26.6 m