sequences series and binomial theorem
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Sequences, Series and Binomial theorem
A sequenceis a set of numbers arranged in a definite order.
1,2, 3, , , where 1, 2, 3, , , are called terms.
Arithmetic Sequence and Series
A sequence {} in which each term differs from the previous one by the sameconstant (common difference) is called arithmetic sequence.
+ =The general termcan be found using the formula
= + ( )
The Sum () of the first terms of an arithmetic sequence {} is calledarithmetic seriesand given by = ( + )or = [ + ( )]
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Example
An arithmetic sequence has a 1stterm of 80 and a 24thterm of 172. Find the 74thterm,
an expression for the general term and the sum .
Solution
Using the formula = + ( )we have that
24 =1 + (24 1) =172 80
23=
92
23= 4
Thus,74 =1 + (74 1) = 8 0 + (74 1)4 = 372
The general term is = + ( )and the sum = [ + ( )]
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Geometric Sequence and Series
A sequence {} in which each term can be obtained from the previous one bymultiplying by a non-zero constant (common ratio) is called geometricsequence.
+ =The general termcan be found using the formula
=
The Sum () of the first n terms of an geometric sequence {} is calledgeometric seriesand given by
=()
, || < 1 or =()
, || > 1
The Sum to infinity () of geometric series is given by = , || < 1
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Example
A geometric sequence has a 4thterm of 32 and a 7thterm of 256. Find the 10thterm, an
expression for the general term and the sum .
Solution
Using the formula =we have that4 =141 32 =13 (1)
7 =171 256 =16 (2)
Dividing the two equations we have =
32256 3 = 8 = 2
and 32 =13 32 =123 1 = 4
Thus,10 =11 = 4 2101 = 2048
The general term is =
and the sum =()
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Sigma Notation
Sigma notation is a way of expressing sums uses the Greek letter
=1
where is the index of summation taking values from 1to .
Properties of Sigma Notation
( ) =
=1
=1
=1
=
=1
=1
=1=
Useful formulas of Sigma Notation
=
=1
( + 1)2
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8/12/2019 Sequences Series and Binomial Theorem
6/7
2
=1=
( + 1)(2 + 1)6
3
=1=
2( + 1)24
Binomial Theorem
( +) =
=0
where = !!()!
and !is the product of the first n positive integers for 1! = 1 2 3 and 0!=1
Example
Using the binomial theorem, expand (3 + 1)4
Solution
Using the formula
( +) =
=0
we have that
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8/12/2019 Sequences Series and Binomial Theorem
7/7
(3 + 1)4 = = 4(3)414 =4=0 40(3)40 + 41(3)41 +
4
2(3
)42 +
4
3(3
)43 +
4
4(3
)44 = 4!
0!(40)!81
4 + 4!
1!(41)!27
3 +
+ 4!
2!(42)! 92 + 4!
3!(43)! 3 + 4!
4!(44)! = 814 + 1083 + 542 + 12 + 1
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