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PROJECT TITLE: DATE OF

SEISMIC LOAD

Seismic load is calculated as per ASCE 7-2005 for frame type of structure, the steel frameis moment resistance in tranverse direction and braced in the longitudenal direction.

The stucture has an overall height of m above ground

SEISMIC CALCULATIONS TO ASCE 7-05

The Seismic Base Shear, V , in a given direction shall be determined in accordance with following equation:

V = Cs x W (Eq. 12.8-1)

Cs = = Seismic response coefficient (Eq. 12.8-2)

( R / I )

2

Sds = x Sms = Design spectral acceleration parameter (Eq. 12.8-2)

3

Sms = Fa x Ss

Sm1 = F1x S 1

The value of Ss S1

Ss =

S1 =

Fa = (Table 11.4-1)

F1 = (Table 11.4-2)

Sms = x =

Sm1 = x =

2 2

Sds = x Sms = x =

3 3

Transverse Frame, on the structure are moment - resisting steel frames

R = (Table 12-2-1)

0.13 0.09

12

3.5

1.6 0.081 0.13

2.4 0.023 0.06

Sds

and

0.081

0.023

1.6

2.4

3

By

CKD

Seismic Load Calculation

SEISMIC to ASCE 7-05 .xlsASCE 7-2005 2/15/20161:19 PM

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Longitudinal Stabilityis by ordinary braced frames, for steel & concrete

R = (Table 12-2-1)

Occupancy Category is considered to be category 3 - Special Occupancy Structures.

Seismic Importance Factor I = (Table 11-5-1)

Transverse

Cs = = x = Transverse (Eq. 12.8-2)

( R / I )

Longitudinal

Cs = = x = Longitudinal (Eq. 12.8-2)

( R / I )

T = Fundamental Period of the structure

Ta . Approximate fundamental period

Ta = Ct x hn^(x) where hnis height of structure, for top of structure at = m above grade level

Ct = (Table 12-8-2)

x = (Table 12-8-2)

Ta = x ( ) ^ = Sec Transverse

Ct = (Table 12-8-2)

x = (Table 12-8-2)

Ta = x ( ) ^ = Sec Longitudinal

The maximum design base shear

Cs = (Table 12-8-3)

( R / I ) x T

2 2

Sd1 = x Sm1 = x = (Eq. 11.4-4)3 3

x

Cs = = Transverse

x

x

Cs = = Longitudinal

x

0.04 1.25

3.25 0.31

39.36 0.8

0.02 39.36 0.75

0.02

3.5 0.53

Sd1

Sds

0.04 1.25

0.025

Sds 0.09

1.25 0.033

0.028

0.8

1.25

Seismic Load Calculation

0.09

3.25

0.06

1.25 0.031

0.75

0.028 0.53

0.31

3.5

3.25

31/0/1900

0.04

12

0.045

By 0

CKD 0

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The minimum design base shear

Cs = (Eq. 12.8-5)

Therefore,

Cs = Transverse

Cs = Longitudinal

V = Cs x W (Eq. 12.8-1)

V = x W Transverse

V = x W Longitudinal

0.01

0.0309

0.033

0.031

0.033

Seismic Load Calculation 1/0/1900 3

CKD 0

0By

SEISMIC to ASCE 7-05 .xlsASCE 7-2005 2/15/20161:19 PM