se 402 2 balancing equations
TRANSCRIPT
5.4 To represent chemical change in the form of balanced equations
Balancing Equations
All matter is made up of atoms
Atoms combine in chemical reactions to form compound
Each element has the same type of atoms
NaOHNa – 1 atomO - 1 atomH - 1 atom
NH4NO3
N - 2 atomsH - 4 atomsO - 3 atoms
C3H5(NO3)2 C - 3 atomsH - 5 atomsN - 2 atomsO - 6 atoms
TRICKY
4 C2H4 C - 8 atomsH - 16 atoms
Watch outfor the # in front!
The number in front of the entire molecule tells how many molecules there is. In this
example there are 4 molecules!
C has 2 atoms but there are 4 molecules so
that means there is 8 atoms all together
How many atoms are in each element for these compounds?
H – 1 atomN – 1 atomO – 3 atoms
H – 4 atom
N – 4 atomO – 12 atoms
Cu – 4 atom S – 2 atom
1. HNO3 2. 4HNO3 3. 2Cu2S
4. NH4NO3 5. 2Fe2SO4
N– 2 atomH – 4 atomO – 3 atoms
Fe– 4 atomS – 2 atomO – 8 atoms
H – 2 atomN – 2 atomO – 6 atoms
Cu – 1 atom
O – 4 atomS – 1 atoms
Ca – 2 atom O – 4 atom H – 4 atoms
9. 4C3H5(NO3)2 10. 4Fe2SO4C– 12 atomN – 8 atomH – 20 atomsO – 24 atoms
Fe– 8 atom
S – 4 atomO – 16 atoms
6. 2HNO3 7. CuSO4 8. 2Ca(OH)2
In all chemical reactions, the number of atoms of each element in the reactants will be equal to the number of atoms of each element in the products.
2H2 + O2 2H2O (balanced equation)
Reactants = Products
Hydrogen (H) = 4 atoms Oxygen (O) = 2 atoms
Hydrogen (H) = 4 atomsOxygen (O) = 2 atoms
0.5 L
NaOH + HCl NaCl + H2O
First list all the elements separately on each side
Na = Na =O = O =H = H =Cl = Cl =
Reactants = Products
Count all your atoms for each element
1 atom 1 atom1 atom 1 atom2 atoms 2 atoms1 atom 1 atom
YES…it is a
balanced equation
0.5 L
H = H = O = O =
2 2 2H O H O Reactants = Products
First list all the elements separately on each side
0.5 L
H = 2 atoms H = 2 atomsO = 2 atoms O = 1 atom
2 2 2H O H O Second, count the number of atoms for the reactants and # of atoms for the products for each element
Reactants = Products
These are not the
same…..so this equation is
NOT balanced!
0.5 L
H = 2 atoms H = 2 atomsO = 2 atoms O = 1 atom
2 2 2__ __ ___H O H O
NEVER EVER add a number directly into compound!!! (only in front!)
2
2
44
2
2 2 22 2H O H O The final balanced equation is
Never Here!
Add a number (co-efficient) in front of one or more of the molecules to make the equation balanced.
Fe2O3 + C CO2 + Fe Reactants = Products
Fe = Fe =O = O =C = C =
2 atoms 1 atom3 atoms 2 atoms1 atom 1 atom
6 64
33
4
The final balanced equation is:
2 3 22 3 3 4Fe O C CO Fe
Al + CuCl2 AlCl3 + Cu Reactants = Products
Al = Al =Cu = Cu =Cl = Cl =
1 atom 1 atom1 atom 1 atom2 atoms 3 atoms6 63
223
The final balanced equation is:
2 32 3 2 3Al CuCl AlCl Cu
Na2CO3 + Ca(OH)2 CaCO3 + NaOH Reactants = Products
Na = Na =C = C =O = O =H = H =Ca = Ca =
2 atoms 1 atom1 atom 1 atom5 atoms 4 atoms2 atoms 1 atom1 atom 1 atom
52
2
2 3 2 3 Na CO + Ca(OH) CaCO + 2 NaOH
A solution of sodium carbonate (Na2CO3) reacts with a solution of calcium hydroxide (Ca(OH)2) to give precipitate of calcium carbonate (CaCO3) and a solution of sodium hydroxide (NaOH). Write a balanced equation for this reaction
o When balancing equationso First list elements on each sideo Second count atoms for each
elemento Add a number in front of molecule
to balance the atoms
o NEVER EVER add a number in between a molecule!!! (always put it in front)
WORKSHEET # 11 Study guide, Module 3, page 38