sampling distribution of the sample mean
DESCRIPTION
Sampling Distribution of the Sample Mean. Example. Take random sample of 1 hour periods in an ER. Ask “how many patients arrived in that one hour period ?” Calculate statistic, say, the sample mean. Sample 1:231 Mean = 2.0 Sample 2:342Mean = 3.0. Situation. - PowerPoint PPT PresentationTRANSCRIPT
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Sampling Distribution of the Sample Mean
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Example
• Take random sample of 1 hour periods in an ER.
• Ask “how many patients arrived in that one hour period ?”
• Calculate statistic, say, the sample mean.Sample 1: 2 3 1 Mean = 2.0
Sample 2: 3 4 2 Mean = 3.0
![Page 3: Sampling Distribution of the Sample Mean](https://reader035.vdocuments.mx/reader035/viewer/2022070407/56814388550346895db00685/html5/thumbnails/3.jpg)
Situation• Different samples produce different results.
• Value of a statistic, like mean, SD, or proportion, depends on the particular sample obtained.
• But some values may be more likely than others.
• The probability distribution of a statistic (“sampling distribution”) indicates the likelihood of getting certain values.
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Let’s investigate how sample means and standard deviations vary….
(click here for Live Demo)
Web link to try it yourself:http://www.ruf.rice.edu/~lane/stat_sim/sampling_dist/
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Sampling Distribution of Sample Mean
IF:
• data are normally distributed with mean and standard deviation , and
• random samples of size n are taken, THEN:
The sampling distribution of the sample means is also normally distributed.
The mean of all of the possible sample means is .
The standard deviation of the sample means (“standard error of the mean”) is
nXSE )(
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Example
• Adult nose length is normally distributed with mean 45 mm and standard deviation 6 mm.
• Take random samples of n = 4 adults.• Then, sample means are normally distributed with
mean 45 mm and standard error 3 mm [from ].mm 34/6/)( nXSE
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Using empirical rule...
• 68% of samples of n=4 adults will have a sample mean nose length between 42 and 48 mm.
• 95% of samples of n=4 adults will have a sample mean nose length between 39 and 51 mm.
• 99% of samples of n=4 adults will have a sample mean nose length between 36 and 54 mm.
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What happens if we take larger samples?
• Adult nose length is normally distributed with mean 45 mm and standard deviation 6 mm.
• Take random samples of n = 36 adults.
• Then, sample means are normally distributed with mean 45 mm and standard error 1 mm [from 6/sqrt(36) = 6/6].
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Again, using empirical rule...• 68% of samples of n=36 adults will have a sample
mean nose length between 44 and 46 mm.
• 95% of samples of n=36 adults will have a sample mean nose length between 43 and 47 mm.
• 99% of samples of n=36 adults will have a sample mean nose length between 42 and 48 mm.
• So … the larger the sample, the less the sample means vary.
![Page 10: Sampling Distribution of the Sample Mean](https://reader035.vdocuments.mx/reader035/viewer/2022070407/56814388550346895db00685/html5/thumbnails/10.jpg)
What happens if data are not normally distributed?
Let’s investigate that, too …
Sampling Distribution Demo: (Live Demo)
http://www.ruf.rice.edu/~lane/stat_sim/sampling_dist/
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Central Limit Theorem• Even if data are not normally distributed, as long as
you take “large enough” samples, the sample averages will at least be approximately normally distributed.
• Mean of sample averages is still • Standard error of sample averages is still
• In general, “large enough” means more than 30 measurements, but it depends on how non-normal population is to begin with.
nXSE /)(
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0.0 0.2 0.4 0.6 0.8 1.00
1
2
3
n = 2
0.0 0.2 0.4 0.6 0.8 1.00
1
2
Population: Triangular
0 .0 0 .2 0 .4 0.6 0 .8 1 .0
0
1
2
3
4
n = 4
The Shape of the Sampling Distribution
X
0.0 0.2 0.4 0.6 0.8 1.00
1
2
n = 1
0 .0 0 .2 0 .4 0 .6 0 .8 1 .00
1
2
3
4
5
n = 10
sX ' ofon Distributi
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0.0 0.2 0.4 0.6 0.8 1.00
1
2
n = 100.0 0.2 0.4 0.6 0.8 1.0
1
2
3
n = 2
The Shape of the Sampling Distribution
Population: Uniform
0.0 0.2 0.4 0.6 0.8 1.00
1
2
3
n = 4
0.0 0.2 0.4 0.6 0.8 1.00
1
2
3
4
n = 10
0.0 0.2 0.4 0.6 0.8 1.00
1
2 XsX ' ofon Distributi
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0 1 2 30.0
0.2
0.4
0.6
0.8
1.0
n = 4
0 1 20.0
0.4
0.8
1.2
n = 10
The Shape of the Sampling Distribution
Population: Exponential
0 1 2 3 4 5 60.0
0.2
0.4
0.6
0.8
1.0
n = 1
0 1 2 3 4 5 60.0
0.2
0.4
0.6
0.8
1.0
X
0 1 2 3 40.0
0.2
0.4
0.6
0.8
n = 2
sX ' ofon Distributi
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The Shape of the Sampling Distribution
Population: U-shaped
0.0 0.2 0.4 0.6 0.8 1.00
1
2
3
n = 1
0.0 0.2 0.4 0.6 0.8 1.00
1
2
3
n = 2
0.0 0.2 0.4 0.6 0.8 1.00
1
2
3
n = 4
0.0 0.2 0.4 0.6 0.8 1.00
1
2
3
n = 10
0.0 0.2 0.4 0.6 0.8 1.00
1
2
3 X
sX ' ofon Distributi
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__ (Central Limit Theorem)
X is approximately Normally distributed for large samples.
(i.e. when the sample size n is large)
The Shape of the Sampling Distribution
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