POLYMATH Results 03-01-2015, Rev5.1.233

Calculated values of the DEQ variables

Variable initial value minimal value maximal value final value t 0 0 20, 20, FA 100, 57,210025 100, 57,210025 FB 0 0 9,057314 1,935926 FC 0 0 61,916043 61,916043 FAout 0 0 11,831954 11,831954 FBout 0 0 29,022096 29,022096 X 0 0 0,4278998 0,4278998 kcA 1, 1, 1, 1, kcB 40, 40, 40, 40, k 10, 10, 10, 10, vo 100, 100, 100, 100, FAo 100, 100, 100, 100, FT 100, 100, 122,24311 121,06199 x 0 0 0,4278998 0,4278998 vF 20, 20, 20, 20, CTo 1, 1, 1, 1, CA 1, 0,472568 1, 0,472568 CB 0 0 0,074786 0,0159912 RA 1, 0,472568 1, 0,472568 RB 0 0 2,9914392 0,6396478 CC 0 0 0,5114408 0,5114408 kc 0,01 0,01 0,01 0,01 rA -10, -10, -0,542836 -0,542836

ODE Report (RKF45)

Differential equations as entered by the user [1] d(FA)/d(t) = rA-RA [2] d(FB)/d(t) = -rA-RB [3] d(FC)/d(t) = -2*rA [4] d(FAout)/d(t) = RA [5] d(FBout)/d(t) = RB [6] d(X)/d(t) = (-rA+RA)/100

Explicit equations as entered by the user [1] kcA = 1 [2] kcB = 40 [3] k = 10 [4] vo = 100 [5] FAo = 100 [6] FT = FA+FB+FC [7] x = (FAo-FA)/FAo [8] vF = 20 [9] CTo = 1 [10] CA = CTo*FA/FT [11] CB = CTo*FB/FT [12] RA = kcA*CA [13] RB = kcB*CB [14] CC = CTo*FC/FT [15] kc = 1/100 [16] rA = -k*(CA-((CB*CC^2)/kc))

Independent variable variable name : t initial value : 0 final value : 20

Precision Step size guess. h = 0,000001 Truncation error tolerance. eps = 0,000001

General number of differential equations: 6 number of explicit equations: 16