recursion chapter 17 instructor: scott kristjanson cmpt 125/125 sfu burnaby, fall 2013

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Recursion Chapter 17 Instructor: Scott Kristjanson CMPT 125/125 SFU Burnaby, Fall 2013

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Slides based on Java Foundations 3rd Edition, Lewis/DePasquale/Chase 3 Scott Kristjanson – CMPT 125/126 – SFU Wk11.3 Slide 3 Recursion Recursion is a programming technique in which a method can call itself to fulfill its purpose A recursive definition is one which uses the word or concept being defined in the definition itself In some situations, a recursive definition can be an appropriate way to express a concept Before applying recursion to programming, it is best to practice thinking recursively

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Page 1: Recursion Chapter 17 Instructor: Scott Kristjanson CMPT 125/125 SFU Burnaby, Fall 2013

Recursion Chapter 17

Instructor: Scott Kristjanson

CMPT 125/125

SFU Burnaby, Fall 2013

Page 2: Recursion Chapter 17 Instructor: Scott Kristjanson CMPT 125/125 SFU Burnaby, Fall 2013

Wk11.3 Slide 2Slides based on Java Foundations 3rd Edition, Lewis/DePasquale/Chase

2

Scott Kristjanson – CMPT 125/126 – SFU

Scope

Introduction to Recursion: The concept of recursion Recursive methods Infinite recursion When to use (and not use) recursion Using recursion to solve problems

• Solving a maze• Towers of Hanoi

Page 3: Recursion Chapter 17 Instructor: Scott Kristjanson CMPT 125/125 SFU Burnaby, Fall 2013

Wk11.3 Slide 3Slides based on Java Foundations 3rd Edition, Lewis/DePasquale/Chase

3

Scott Kristjanson – CMPT 125/126 – SFU

Recursion

Recursion is a programming technique in which a method can call itself to fulfill its purposeA recursive definition is one which uses the word or concept being defined in the definition itselfIn some situations, a recursive definition can be an appropriate way to express a conceptBefore applying recursion to programming, it is best to practice thinking recursively

Page 4: Recursion Chapter 17 Instructor: Scott Kristjanson CMPT 125/125 SFU Burnaby, Fall 2013

Wk11.3 Slide 4Slides based on Java Foundations 3rd Edition, Lewis/DePasquale/Chase

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Scott Kristjanson – CMPT 125/126 – SFU

Recursive Definitions

Consider the following list of numbers:24, 88, 40, 37

Such a list can be defined recursively:A LIST is a: number

or a: number comma LIST

That is, a LIST can be a number, or a number followed by a comma followed by a LIST

The concept of a LIST is used to define itself

Page 5: Recursion Chapter 17 Instructor: Scott Kristjanson CMPT 125/125 SFU Burnaby, Fall 2013

Wk11.3 Slide 5Slides based on Java Foundations 3rd Edition, Lewis/DePasquale/Chase

5

Scott Kristjanson – CMPT 125/126 – SFU

Recursive Definitions

LIST: number comma LIST

24 , 88, 40, 37

number comma LIST

88 , 40, 37

number comma LIST

40 , 37

number

37

Page 6: Recursion Chapter 17 Instructor: Scott Kristjanson CMPT 125/125 SFU Burnaby, Fall 2013

Wk11.3 Slide 6Slides based on Java Foundations 3rd Edition, Lewis/DePasquale/Chase

6

Scott Kristjanson – CMPT 125/126 – SFU

Infinite Recursion

All recursive definitions must have a non-recursive partIf they don't, there is no way to terminate the recursive pathA definition without a non-recursive part causes infinite recursionThis problem is similar to an infinite loop -- with the definition itself causing the infinite “looping”The non-recursive part is called the base case

Page 7: Recursion Chapter 17 Instructor: Scott Kristjanson CMPT 125/125 SFU Burnaby, Fall 2013

Wk11.3 Slide 7Slides based on Java Foundations 3rd Edition, Lewis/DePasquale/Chase

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Scott Kristjanson – CMPT 125/126 – SFU

Recursion in Math

Mathematical formulas are often expressed recursivelyN!, for any positive integer N, is defined to be the product of all

integers between 1 and N inclusiveThis definition can be expressed recursively:

1! = 1N! = N * (N-1)!

A factorial is defined in terms of another factorial until the base case of 1! is reached

Page 8: Recursion Chapter 17 Instructor: Scott Kristjanson CMPT 125/125 SFU Burnaby, Fall 2013

Wk11.3 Slide 8Slides based on Java Foundations 3rd Edition, Lewis/DePasquale/Chase

8

Scott Kristjanson – CMPT 125/126 – SFU

Recursive Programming

When a method invokes itself; it is called a recursive methodThe code of a recursive method must handle both the base case and the recursive caseEach call sets up a new execution environment, with new parameters and new local variablesAs always, when the method completes, control returns to the method that invoked it (which may be another instance of itself)

Page 9: Recursion Chapter 17 Instructor: Scott Kristjanson CMPT 125/125 SFU Burnaby, Fall 2013

Wk11.3 Slide 9Slides based on Java Foundations 3rd Edition, Lewis/DePasquale/Chase

9

Scott Kristjanson – CMPT 125/126 – SFU

Recursive Programming

Consider the problem of computing the sum of all the integers between 1 and N, inclusive

If N is 5, the sum is1 + 2 + 3 + 4 + 5

This problem can be expressed recursively as:

The sum of 1 to N is N plus the sum of 1 to N-1

Page 10: Recursion Chapter 17 Instructor: Scott Kristjanson CMPT 125/125 SFU Burnaby, Fall 2013

Wk11.3 Slide 10Slides based on Java Foundations 3rd Edition, Lewis/DePasquale/Chase

10

Scott Kristjanson – CMPT 125/126 – SFU

Recursive Programming

The sum of the integers between 1 and N:

Page 11: Recursion Chapter 17 Instructor: Scott Kristjanson CMPT 125/125 SFU Burnaby, Fall 2013

Wk11.3 Slide 11Slides based on Java Foundations 3rd Edition, Lewis/DePasquale/Chase

11

Scott Kristjanson – CMPT 125/126 – SFU

Recursive Programming

A recursive method that computes the sum of 1 to N:

public int sum(int num){ int result; if (num == 1) result = 1; // Base Case else result = num + sum(num-1); // Recursion Step return result;}

Page 12: Recursion Chapter 17 Instructor: Scott Kristjanson CMPT 125/125 SFU Burnaby, Fall 2013

Wk11.3 Slide 12Slides based on Java Foundations 3rd Edition, Lewis/DePasquale/Chase

12

Scott Kristjanson – CMPT 125/126 – SFU

Recursive Programming

Tracing the recursive calls of the sum methodpublic int sum(int num){ int result; if (num == 1) result = 1; else result = num + sum(num-1); return result;}

Page 13: Recursion Chapter 17 Instructor: Scott Kristjanson CMPT 125/125 SFU Burnaby, Fall 2013

Wk11.3 Slide 13Slides based on Java Foundations 3rd Edition, Lewis/DePasquale/Chase

13

Scott Kristjanson – CMPT 125/126 – SFU

Recursion vs. Iteration

Just because we can use recursion to solve a problem, doesn't mean we shouldFor instance, we usually would not use recursion to solve the sum of 1 to NThe iterative version is easier to understand (in fact there is a formula that computes it without a loop at all)You must be able to determine when recursion is the correct technique to use

Page 14: Recursion Chapter 17 Instructor: Scott Kristjanson CMPT 125/125 SFU Burnaby, Fall 2013

Wk11.3 Slide 14Slides based on Java Foundations 3rd Edition, Lewis/DePasquale/Chase

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Scott Kristjanson – CMPT 125/126 – SFU

Recursion vs. Iteration

Every recursive solution has a corresponding iterative solutionA recursive solution may simply be less efficientFurthermore, recursion has the overhead of multiple method invocationsHowever, for some problems recursive solutions are often more simple and elegant to express

Page 15: Recursion Chapter 17 Instructor: Scott Kristjanson CMPT 125/125 SFU Burnaby, Fall 2013

Wk11.3 Slide 15Slides based on Java Foundations 3rd Edition, Lewis/DePasquale/Chase

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Scott Kristjanson – CMPT 125/126 – SFU

Direct vs. Indirect Recursion

A method invoking itself is considered to be direct recursion

A method could invoke another method, which invokes another, etc., until eventually the original method is invoked again

For example, method m1 could invoke m2, which invokes m3, which invokes m1 again

This is called indirect recursion It can be more difficult to trace and debug

Page 16: Recursion Chapter 17 Instructor: Scott Kristjanson CMPT 125/125 SFU Burnaby, Fall 2013

Wk11.3 Slide 16Slides based on Java Foundations 3rd Edition, Lewis/DePasquale/Chase

16

Scott Kristjanson – CMPT 125/126 – SFU

Indirect Recursion

Page 17: Recursion Chapter 17 Instructor: Scott Kristjanson CMPT 125/125 SFU Burnaby, Fall 2013

Wk11.3 Slide 17Slides based on Java Foundations 3rd Edition, Lewis/DePasquale/Chase

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Scott Kristjanson – CMPT 125/126 – SFU

Maze Traversal

We've seen a maze solved using a stackThe same approach can also be done using recursionThe run-time stack tracking method execution performs the same functionAs before, we mark a location as "visited" and try to continue along the pathThe base cases are:

• a blocked path• finding a solution

Page 18: Recursion Chapter 17 Instructor: Scott Kristjanson CMPT 125/125 SFU Burnaby, Fall 2013

Wk11.3 Slide 18Slides based on Java Foundations 3rd Edition, Lewis/DePasquale/Chase

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Scott Kristjanson – CMPT 125/126 – SFU

// Attempts to recursively traverse the maze. public boolean traverse(int row, int column) { boolean done = false; if (maze.validPosition(row, column)) { maze.tryPosition(row, column); // mark this cell as tried if (row == maze.getRows()-1 && column == maze.getColumns()-1) done = true; // the maze is solved else { done = traverse(row+1, column); // down if (!done) done = traverse(row, column+1); // right if (!done) done = traverse(row-1, column); // up if (!done) done = traverse(row, column-1); // left } if (done) // this location is part of the final path maze.markPath(row, column); } return done; }}

Traversing a Maze Using Recursion

Page 19: Recursion Chapter 17 Instructor: Scott Kristjanson CMPT 125/125 SFU Burnaby, Fall 2013

Wk11.3 Slide 19Slides based on Java Foundations 3rd Edition, Lewis/DePasquale/Chase

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Scott Kristjanson – CMPT 125/126 – SFU

The Towers of Hanoi

The Towers of Hanoi is a puzzle made up of three vertical pegs and several disks that slide onto the pegsThe disks are of varying size, initially placed on one peg with the largest disk on the bottom and increasingly smaller disks on topThe goal is to move all of the disks from one peg to another following these rules:

• Only one disk can be moved at a time

• A disk cannot be placed on top of a smaller disk

• All disks must be on some peg (except for the one in transit)

Page 20: Recursion Chapter 17 Instructor: Scott Kristjanson CMPT 125/125 SFU Burnaby, Fall 2013

Wk11.3 Slide 20Slides based on Java Foundations 3rd Edition, Lewis/DePasquale/Chase

20

Scott Kristjanson – CMPT 125/126 – SFU

Towers of Hanoi

The initial state of the Towers of Hanoi puzzle:

Page 21: Recursion Chapter 17 Instructor: Scott Kristjanson CMPT 125/125 SFU Burnaby, Fall 2013

Wk11.3 Slide 21Slides based on Java Foundations 3rd Edition, Lewis/DePasquale/Chase

21

Scott Kristjanson – CMPT 125/126 – SFU

Towers of Hanoi

A solution to the three-disk Towers of Hanoi puzzle:

Page 22: Recursion Chapter 17 Instructor: Scott Kristjanson CMPT 125/125 SFU Burnaby, Fall 2013

Wk11.3 Slide 22Slides based on Java Foundations 3rd Edition, Lewis/DePasquale/Chase

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Scott Kristjanson – CMPT 125/126 – SFU

Towers of Hanoi

A solution to the Towers of Hanoi can be expressed recursively

To move N disks from the original peg to the destination peg:

• Move the topmost N-1 disks from the original peg to the extra peg

• Move the largest disk from the original peg to the destination peg

• Move the N-1 disks from the extra peg to the destination peg

The base case occurs when a peg contains only one disk

Page 23: Recursion Chapter 17 Instructor: Scott Kristjanson CMPT 125/125 SFU Burnaby, Fall 2013

Wk11.3 Slide 23Slides based on Java Foundations 3rd Edition, Lewis/DePasquale/Chase

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Scott Kristjanson – CMPT 125/126 – SFU

Towers of Hanoi

The number of moves increases exponentially as the number of disks increasesThe recursive solution is simple and elegant to express and program, but is very inefficientHowever, an iterative solution to this problem is much more complex to define and program

public class SolveTowers{

// Creates a TowersOfHanoi puzzle and solves it. public static void main(String[] args) { TowersOfHanoi towers = new TowersOfHanoi(3); towers.solve(); } }

Page 24: Recursion Chapter 17 Instructor: Scott Kristjanson CMPT 125/125 SFU Burnaby, Fall 2013

Wk11.3 Slide 24Slides based on Java Foundations 3rd Edition, Lewis/DePasquale/Chase

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Scott Kristjanson – CMPT 125/126 – SFU

public void solve() { moveTower(totalDisks, 1, 3, 2); System.out.println("Done!");}

private void moveTower(int numDisks, int start, int end, int temp) { /* Recursion Base Case */ if (numDisks == 1) moveOneDisk(start, end); else { /* Recursive Steps */ moveTower(numDisks-1, start, temp, end); moveOneDisk(start, end); moveTower(numDisks-1, temp, end, start); } } private void moveOneDisk(int start, int end) {System.out.println("Move one disk from " + start + " to " + end);}

Towers of Hanoi

Move one disk from 1 to 3Move one disk from 1 to 2Move one disk from 3 to 2Move one disk from 1 to 3Move one disk from 2 to 1Move one disk from 2 to 3Move one disk from 1 to 3Done!

Page 25: Recursion Chapter 17 Instructor: Scott Kristjanson CMPT 125/125 SFU Burnaby, Fall 2013

Wk11.3 Slide 25Slides based on Java Foundations 3rd Edition, Lewis/DePasquale/Chase

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Scott Kristjanson – CMPT 125/126 – SFU

Analyzing Recursive Algorithms

To analyze the time complexity of a loop, we determined the time complexity of the body of the loop, multiplied by the number of loop executions

Similarly, to determine the time complexity of a recursive method, we determine the complexity of the body of the method, multiplied by the number of times the recursive method is called

In our recursive solution to compute the sum of integers from 1 to N, the method is invoked N times and the method itself is O(1)

So the order of the overall solution is N*O(1) = O(N)

Page 26: Recursion Chapter 17 Instructor: Scott Kristjanson CMPT 125/125 SFU Burnaby, Fall 2013

Wk11.3 Slide 26Slides based on Java Foundations 3rd Edition, Lewis/DePasquale/Chase

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Scott Kristjanson – CMPT 125/126 – SFU

Analyzing Recursive Algorithms

For the Towers of Hanoi puzzle, moving one disk is O(1)But each call to moveTower results in calling itself twice more, so to compute cost for N > 1:

N = 1 : f(1) = 1 = 21 – 1 = 1N = 2 : f(2) = 2*f(n-1) + f(1) = 22 – 1 = 3N = 3 : f(3) = 2*f(n-1) + f(1) = 23 – 1 = 7 . . . N = n : f(n) = 2*f(n-1) + f(1) = 2n – 1

moveTower has exponential cost! f(n) = 2n – 1 ∊ O(2n)As the number of disks increases, the number of required moves increases exponentially

Recursion can be elegant, but it can quickly become expensive

Page 27: Recursion Chapter 17 Instructor: Scott Kristjanson CMPT 125/125 SFU Burnaby, Fall 2013

Wk11.3 Slide 27Slides based on Java Foundations 3rd Edition, Lewis/DePasquale/Chase

27

Scott Kristjanson – CMPT 125/126 – SFU

Key Things to take away:

Recursion:• Recursion is a programming technique where a method calls itself• Any recursive method must have a non-recursive base case• Each recursive method call creates a new set of variables and parameters• Cost of Recursive methods can be analyzed similar to iterative processing• Recursive solutions are often very elegant and compact but may lead to

expensive CPU or Space complexity

Page 28: Recursion Chapter 17 Instructor: Scott Kristjanson CMPT 125/125 SFU Burnaby, Fall 2013

Wk11.3 Slide 28Slides based on Java Foundations 3rd Edition, Lewis/DePasquale/Chase

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Scott Kristjanson – CMPT 125/126 – SFU

References:

1. J. Lewis, P. DePasquale, and J. Chase., Java Foundations: Introduction to Program Design & Data Structures. Addison-Wesley, Boston, Massachusetts, 3rd edition, 2014, ISBN 978-0-13-337046-1