Quiz on Homework 10 and 111. For what purpose is a

manometer used?2. Explain how a gas exerts

pressure on its container.3. Which gas exerts less

pressure, the one on the right or the left?

4. What is the value of standard atmospheric pressure in kPa.

5. If the difference in height in the manometer on the left is 75mm, and atmospheric pressure is 100 kPa, what is the pressure of the gas in the left manometer?

Gas molecules bounce against the sidesof the container, Pressure = Force/Area therefore,the more collisions, the more pressure.

A manometer is used to measure gas pressure.

101.3 kPa

The gas on the left exerts less pressure

Pgas = 100 – 75/7.5Pgas = 90 kPa

Due: HW 11: Define and draw a labeled diagram of a manometerand a barometer. Take notes on page 381 sample problem; Do #1-8 page 382Due: HW #12: Do #25 28 and 40 page 390 and 391. If you have trouble deciding

when to add, and when to subtract atmospheric pressure, first draw a sketchof the manometer. Add atmospheric pressure if gas pushes more than atmosphere.Due: HW #13 Notes page 384 385; Do #29, 30 page 391Due Tomorrow: HW 14 # 32,33,34 page 391Due Wednesday: HW 15: Notes page 385; Do # 16 p 388; #35,43 page 391Extra Credit: #44,45,46, 48,49,50 page 392 (20 pts) (label it HW #16)Whatever is not done in class is due Friday, April 30. HW 14 Due Tuesday, Test Wed.

Patm – h/7.5

Patm + h/7.5

How do you solve these problems?1. An open manometer, such as the one in figure 15.4, is filled with

mercury and connected to a container of hydrogen. The mercury level is 62 mm higher in the arm of the tube connected to the gas.

Use this model ( Patm - ht/7.5) kPaAtmospheric pressure is 97.7 kPa. What is the pressure of the hydrogen in kilopascals?

Patm – ht/7.5

97.7kPa – (62mm/7.5kPa/mm)

= 97.7 kPa – 8.3 kPa= 89.4 kPa

Temperature and Heat

• Temperature is the average kinetic energy of molecules.

• Absolute zero is -273.15oC,

-273oC.

• To convert from Celsius to Kelvin add 273

• To convert to Celsius subtract 273.

• One Celsius degree = 1 Kelvin degree!

Do #9- 12 in class9. a. 86K

b. 191 K

c. 533 K

d. 321 K

e. 894 K

= -187oC

= - 82oC

= 260oC

= 48oC

= 621oC

- 273K

- 273K

- 273K

- 273K

- 273K

10. a. 23oC

b. 58oC

c. -90oC

d. 18oC

e. 25oC

+ 273K = 296 K

+ 273K = 331 K

+ 273K = 183 K

+ 273K = 291 K+ 273K = 298 K

11 a. 559oC b. 417 oCc. 111oCd. -253 oCe. – 213 oC

12. N2 = 28g/mole F2 = 38 g/mole CO2 = 44g/mole O2 = 32 g/mole

N2 moves the fastestbecause it weighs theleast.

States of matter

Gases move rapidly filling the entire container.

Gases form when atomsdo not have enough attractiveforce to stay near each other.

Liquids consist of disorganized atoms/moleculeswhich are attracted to each other.

Solids are organized structureswith lots of attraction and little“freedom” to move

most movement

leastmovement

How do you solve problems with closed end manometers or barometers?

2. A closed manometer, like the one in figure 15.4, is filled with mercury and connected to a container of nitrogen. The difference in the height of mercury in the two arms is 691 mm. What is the pressure of the nitrogen in kilopascals?

691 mm/ 7.5 mm/kPa

Since the “other side”has a pressure of zero,adding or subtracting changesnothing!

Pnitrogen = 92.1 kPa

How do you solve these problems?3. An open manometer connected to a tank of argon has a mercury

level 38 mm higher in the atmospheric arm.

Use this model ( Patm + ht/7.5) kPaIf Atmospheric pressure is 96.3 kPa, what is the pressure of Argon in kPa?

Patm + ht/7.5

96.3kPa + (38mm/7.5kPa/mm)

= 96.3 kPa – 5.1 kPa= 101.4 kPa

Answers to homework• page 382 1-8 (1/2 credit if the work is not shown)

1. 89.4 kPa2. 92.1 kPa

3. 101.4 kPa4. 11.5 kPa5. All matter is composed of small particles; these particles are in constant

motion; all collisions between particles are perfectly elastic.6. Gas molecules collide with the walls of the container holding the gas,

and each collision exerts a force on the container. The force of collision and the number of collisions cause pressure.

7. In an open-arm manometer one arm of the U-tube is open to the atmosphere. The gas being studied exerts pressure on the other arm. In a closed-arm manometer, there is a vacuum above the liquid in one arm. If a closed-arm manometer is used to measure atmospheric pressure, it is called a barometer. An open-arm manometer measures the difference in pressure between the atmosphere and the gas sample. A closed-arm manometer measures pressure independently of atmospheric pressure.

8. 16.0 kPa; 10.7 kPa

# 27. An open manometer like the one in figure 15.4 is used to measure the pressure of a gas sample. The mercury level is 24 mm higher in the arm open

to the atmosphere What is the pressure, in kilopascals,of the gas in the container if the air pressure is 100.3 kilopascals?

• Patm = 100.3 + 24/7.5

• Patm = 103.5kPa

# 26. In a closed manometer, assume that the height of the levels differs by 522 mm Hg. What is the pressure, in kilopascals, of the gas

in the container?

• Pgas = 522/7.5

• Pgas = 69.6 kPa

Answers to the rest of the questionsare:27. 103.5 kPa28. 106.7 kPa29. The temperature increasesdirectly (proportionally) with an increasein Kinetic energy.30. Absolute zero means all molecularmotion ceases (stops).

Homework where work is shown only merits ½ credit!