protein structure: myoglobin as an example

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Protein Structure: Myoglobin as an Example John Kendrew solved the structure of myoglobin in 1959 No Computers! Myoglobin is a globular protein consisting of 153 amino acids and a prosthetic group : A Heme Myoglobin has no -sheets and is 100% -helical with respect to secondary structure (we won’t count turns) There are 8 helices, labelled A through H Polar amino acids are on the surface and hydrophobic amino acids are in the core of the protein This is a standard arrangement in proteins Two histidines help lock the heme group into position Hydrophobic interactions b/w the heme group and hydrophobic amino acids in the core complete the binding of the heme

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Protein Structure: Myoglobin as an Example. John Kendrew solved the structure of myoglobin in 1959 No Computers! Myoglobin is a globular protein consisting of 153 amino acids and a prosthetic group : A Heme - PowerPoint PPT Presentation

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Page 1: Protein Structure:  Myoglobin as an Example

Protein Structure: Myoglobin as an Example

• John Kendrew solved the structure of myoglobin in 1959– No Computers!

• Myoglobin is a globular protein consisting of 153 amino acids and a prosthetic group: A Heme

• Myoglobin has no -sheets and is 100% -helical with respect to secondary structure (we won’t count turns)

– There are 8 helices, labelled A through H

• Polar amino acids are on the surface and hydrophobic amino acids are in the core of the protein– This is a standard arrangement in proteins

• Two histidines help lock the heme group into position• Hydrophobic interactions b/w the heme group and

hydrophobic amino acids in the core complete the binding of the heme

Page 2: Protein Structure:  Myoglobin as an Example
Page 3: Protein Structure:  Myoglobin as an Example

The Heme Group

• Heme consists of a metal ion, Fe (II), and a porphyrin ring– The ring is a planar structure

• Fe (II) can accommodate 6 coordinate bonds, forming an octahedral arrangement– The porphyrin nitrogens

provide 4 of these

• An imidazole nitrogen of a histidine in helix F provides a 5th bond

• Oxygen binds to Fe (II) to complete the arrangement

Page 4: Protein Structure:  Myoglobin as an Example

Hydrophobic Interactions help anchor the porphyrin ring

His 97 and Arg 45 help anchor the ring

His 93 Interacts with the Fe (II)

Page 5: Protein Structure:  Myoglobin as an Example

The histidine above the porphyrin ring (on the same side of the ring as where oxygen binds)

This off-centered binding forces any other molecule that would bind to the Fe (II) to bind less optimally

•Carbon monoxide is a good example

•It also allows oxygen to dissociate formt he iron

•If the binding was too strong, the Fe (II) - Oxygen bond wouldn’t break

Page 6: Protein Structure:  Myoglobin as an Example

Quick Thoughts on Protein Folding

• There are literally millions of possible ways a simple protein can fold, but only one conformation that works

• Hydrophobic interactions help drive protein folding– Not so much the hydrophobic groups attracting each other (That only involves London

Forces, right?)

– The dipole-dipole interactions between water molecules in solution are much stronger and push the hydrophobic side chains aside

• The entropy of the universe must increase in a spontaneous process, and protein folding is a spontaneous process– When water molecules surround a nonpolar compound, they are

restricted in the number of hydrogen bonds then can form which represents a lower entropy

– By having the hydrophobic residues sequestered in the core of the folded protein, the water molecules are free to form up to 4 hydrogen bonds each.

• This freedom represents greater entropy, thus helping drive folding of the protein

Page 7: Protein Structure:  Myoglobin as an Example

Protein Folding: Myoglobin

QuickTime™ and aYUV420 codec decompressor

are needed to see this picture.

QuickTime™ and aYUV420 codec decompressor

are needed to see this picture.

Note Placement of hydrophobic residues (green)Where are the side chains pointing?

Note Placement of polar residues (blue)Where are the side chains pointing?

Page 8: Protein Structure:  Myoglobin as an Example

Chapter 6: Enzymes as Catalysts

• Proteins perform many functions in the cell:– Structural roles, Signalling, DNA binding, Energy

Transduction, Metabolism and many, many more

• Perhaps the most important role proteins play is to serve as catalysts– Enzymes are protein catalysts– Enzymes increase the reaction rate by up to 1020

times• Non-enzymatic catalysts typically only increase the rate

100 to 10000 fold

Page 9: Protein Structure:  Myoglobin as an Example

Kinetics versus Thermodynamics

Standard Free Energy of Reaction

G°= G°Products - G°Reactants

• The reaction rate depends of the Activation Energy (EA):

EA= G°Transition State - G°Reactants

• An enzyme lowers the activation energy– Helps substrate move to

transition state

Page 10: Protein Structure:  Myoglobin as an Example

Enzyme Catalyzed Reactions

• An enzyme cannot make a nonspontaneous reaction occur

• Let’s look at the reaction of glucose and oxygen:

C6H12O6 + 6O2 --> 6CO2 + 6H2OG° = -2880 kJ/mole

• This is a spontaneous reaction, but we have all seen sugar sitting on a tabletop in the open air– The sugar doesn’t spontaneously combust because the Activation

energy for the process is too high

Page 11: Protein Structure:  Myoglobin as an Example

Enzyme Catalyzed Reactions

• An enzyme decreases the activation energy barrier

• This allows the reaction to proceed at an appreciable rate

• By lowering the thermodynamic barrier, we can greatly increase the rate (kinetics) of the reaction

Page 12: Protein Structure:  Myoglobin as an Example

The Effect of Temperature

• Most reaction rates increase as the temperature increases

• For nearly every enzyme, this is true up to a point…– Thermal

denaturation

Page 13: Protein Structure:  Myoglobin as an Example

Kinetics: Expressing/Describing the Rate of a Reaction

• A rate is traditionally expressed as the:

• The substance can be a reactant or a product– If it is a reactant, the rate will have a ____ sign

A + B --> P

change in concentration or amount of a substance

time

Rate = -Δ[A]

t=

-Δ[B]

t=

Δ[P]

t

Rate refers to rate of product formation or rate of reactant disappearance

(See the excellent review link on the “Useful Links” page)

Page 14: Protein Structure:  Myoglobin as an Example

Kinetics: Rate Equation

A + B --> P

The rate of the reaction is slightly different than strictly looking at the rate of disappearance of reactant or formation of product

Rate of Reaction = k[A]f[B]g

– where f and g must be empirically determined

Page 15: Protein Structure:  Myoglobin as an Example

Reaction Orders

• The reaction order is an indicator of the details of the reaction mechanism– How many molecules are involved in the

reaction– The role of the catalyst in the reaction– Specifics of the system

• We’ll only be concerned with 0th, 1st and 2nd order reactions.

Page 16: Protein Structure:  Myoglobin as an Example

Zero Order ReactionsA --> B

Reaction rate = k[A]0

• The reaction rate is independent of the substrate concentration– Catalyst concentration is what matters in this case

• For enzyme catalyzed reactions, we may see such a reaction order when the substrate concentration is VERY high and the enzyme molecules are completely saturated

• The cars over the bridge analogy (Six lanes down to 2)

Page 17: Protein Structure:  Myoglobin as an Example

1st Order Reactions

A --> P

Reaction rate = k[A]1

• This reaction is first order with respect to reactant A– What does this mean?

Page 18: Protein Structure:  Myoglobin as an Example

2nd Order Reactions

Glycogenn + Pi --> Glucose-1-Phosphate + Glycogenn-1

Reaction rate = k[Glycogenn]1[Pi]1

• Both glycogen AND Pi have a role in the reaction– The reaction is first order with respect to each

reactant, but it is a Second order reaction overall– What does this mean?

• Change either reactant concentration and what would happen to the rate?

Page 19: Protein Structure:  Myoglobin as an Example

Section 6.4: Enzyme-Substrate Binding

• There are 3 major players to consider when evaluating enzyme-catalyzed reactions:

1. The enzyme: The catalyst2. Substrate: The Reactant / Starting Material3. Product: The product of the reaction / What is

released from the enzyme after the reaction

• For the rest of the chapter, we’re going to focus on the interplay between these species

Page 20: Protein Structure:  Myoglobin as an Example

Scheme of an Enzyme-Catalyzed Reaction

1. The Enzyme BINDS the substrate, forming the E·S complex

(Note the terminology: Big Thing BINDS Little Thing, not the other way around)

2. The E·S complex forms the Transition State (EX‡) species, which then rapidly forms the product

3. The Product rapidly dissociates from the enzyme, regenerating the catalyst

Page 21: Protein Structure:  Myoglobin as an Example

Formation of the E·S Complex

• The substrate is bound to the active site of the enzyme

– Usually (but not always) by covalent means

• There are two models that have been created to describe this process:

Page 22: Protein Structure:  Myoglobin as an Example

Formation of the E·S Complex:

Lock and Key model

• The active site has a complementary shape to the substrate.– It exactly fits the substrate– Doesn’t take into account Conformational Flexibility!– Has fallen into disfavor due to its simplicity

Page 23: Protein Structure:  Myoglobin as an Example

Formation of the E·S Complex:

Induced Fit model

• The active site changes shape are the substrate binds, thereby allowing a low energy complex to form.• This model allows for substrate variability

– ADH will react with several aliphatic alcohols– Cytochrome P450s can handle various drugs

• There is a limit: Splenda vs Sucrose

Page 24: Protein Structure:  Myoglobin as an Example

Formation of the E·S Complex

• What would happen if the E·S complex was perfect?– Think about the energy in the diagram– What would EA be?

Page 25: Protein Structure:  Myoglobin as an Example

Formation of the Transition State EX‡ and Product Release

• The bond substrate must adopt a conformation of the transition state– By this we mean A LOT of things…

• The substrate and the reactive residues of the enzyme are in close proximity

• Partial bonds are forming, other bondsare breaking, atoms are shifting around

• Proximity and Orientation determine rate

• Due to its high energy level, the transition state is just as its name implies: Transitory

• As soon as the transition state complex is formed, the product is released

Page 26: Protein Structure:  Myoglobin as an Example
Page 27: Protein Structure:  Myoglobin as an Example

Let’s Look at 2 Different Enzyme Catalyzed Reactions

1. Chymotrypsin• Catalyzes the

hydrolysis of peptide bonds AND ester bonds– Peptide hydrolysis is its

primary function

• We can take advantage of the ester hydrolysis function to monitor the Activity of the enzyme using p-nitrophenylesters

2. Aspartate transcarbamoylase

• The enzyme catalyzes the formation of carbamoyl aspartate from carbamoyl phosphate and aspartate

• We can monitor the activity of the enzyme directly by spectrophotometry

Page 28: Protein Structure:  Myoglobin as an Example

Chymotrypsin-catalyzed Ester Hydrolysis

• At low [Substrate], the activity is low

• As more substrate is added, the rate increases until it reaches a maximum

Page 29: Protein Structure:  Myoglobin as an Example

Aspartate Transcarbamoylase

• As the [Substrate] increases, the activity does not increase as much until a critical concentration is reached

• The sigmoidal curve seen for this reaction is indicative of something else going on…

ALLOSTERY!

Page 30: Protein Structure:  Myoglobin as an Example

Allostery

• Allostery is defined as: “Of or involving a change in the shape of and activity of an enzyme that results from molecular binding with a regulatory substance at a site other than the enzymatically active one.”

Huh?

• When a substrate (or an inhibitor) binds to the enzyme somewhere OTHER than the active site, a conformational change may occur that allows more substrate to bind (or less) at other subunits in the quaternary structure and increase (or decrease) the activity.

Page 31: Protein Structure:  Myoglobin as an Example

Allostery

Positively allosterically regulated by ATP and negatively by CTP

•ATP binds to the R subunits and causes the C subunits to open up and bind substrate

•CTP causes the C subunits to close up

The sigmoidal curve seen for ATCase is an example of Positive Cooperativity caused by allostery