prisms. parts of a prism base face height base face height
TRANSCRIPT
TOTAL SURFACE AREA
The sum of the areas of each face.
T.A. = ph + 2B
p = perimeter of the base
h = height of the prism
A right triangular prism is shown. Find the total surface area since the volume = 315.
h
7 6.54
10.5 T.A. = T.A. = phph + 2B + 2BV= Bh = 315V= Bh = 315
V= (V= (½·10.5·4)½·10.5·4)h = h = 315315V= 21h = V= 21h = 315315 h = 15h = 15
p = 10.5 + 7 + 6.5p = 10.5 + 7 + 6.5h = 15h = 15
B =B =½·10.5·4 = 21½·10.5·4 = 21
T.A. = T.A. = 24(15) + 24(15) + 2(21)2(21)T.A. = T.A. = 402402
Find the total surface area and volume of the pyramid.
25 m
24 m 20 m
T.A. = T.A. = ½½pl pl + B+ B p = 14(4) = 56p = 14(4) = 56 l = 24l = 24 B = 14 (14) = 196B = 14 (14) = 196
T.A. = T.A. = ½½(56)(24) (56)(24) + 196 = + 196 = 868868
V = ⅓BhV = ⅓Bh
B = 14(14) = 196B = 14(14) = 196
h = 20h = 20
V = ⅓BhV = ⅓Bh⅓⅓(196)(20)(196)(20)1306.666661306.66666
TOTAL SURFACE AREA
T.A. = 2пrh + 2B
r = radius of the base
h = height of the cylinder
B= area of the base
Find the total surface area and volume.
7 in
24 in
T.A. = 2T.A. = 2ппrhrh + 2B + 2B
h = 24h = 24
r = 7r = 7
B = B = ππrr22 = = ππ(7)(7)22 = 49πT.A. = T.A. = 22ππ(7)(24) +(7)(24) + 2(49π)
T.A. = T.A. = 336336ππ + + 98π = 434π
V = V = ππr r 22hh
V = V = ππ(7) (7) 2 2 (24)(24)
V = 1176 V = 1176 ππ
TOTAL SURFACE AREA
T.A. = пrl + B
r = radius of the base
l = slant height of the cone
B= area of the base
Find the total surface area and volume.
16 meters
17 meters
T.A. =T.A. = ππrl rl + B+ B
T.A. = T.A. = ππ(8)(17) + (8)(17) + 6464ππ
B = 8B = 82 2 ππ = = 6464ππ
T.A. = 136T.A. = 136ππ + 64 + 64ππT.A. =T.A. = 200200ππ
V = ⅓V = ⅓ππrr22hh
V = V = ⅓⅓ππ((8822)15)15V = 320V = 320ππ