precipitation rxns solubility, stoichiometry, and net ionic equations
TRANSCRIPT
Precipitation Rxns
Solubility, Stoichiometry, and
Net Ionic Equations
Precipitation Rxns: One Kind of Double Replacement (Metathesis) Rxn
Pb(NO3)2(aq) + 2KI(aq) PbI2(s) + 2KNO3(aq)yellow solid
What Happens on the ‘Nanoscale’?
Draw a picture of what is present in Pb(NO3)2(aq) and KI(aq) before mixing.
Draw a picture of what is present after mixing.
Pb(NO3)2(aq) + 2KI(aq) PbI2(s) + 2KNO3(aq)yellow solid
What Cation-Anion Combinations Precipitate?
Identify the cation and anion present in each solution before mixing.
After mixing, look for evidence that certain cations/anions tend to ppt
(Investigate This #2.32)
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Results of 2.32 Mixing Tests
Which combinations result in pptn?
Which do not?
Categorize tendency of each cation and each anion to ppt
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KNO3 KBr K2SO4 K2CO3 K2C2O4 K3PO4
NaCl
CaCl2
LiCl
BaCl2
Solubility Rules
From Your Text (p.100-101)
Appendix G of the Lab Manual (more extensive list)
CoCl2.6H2O and Na3PO4 Solutions (Investigate This 2.38)
Na3PO4(aq) contains colorless Na+(aq) and colorless PO4
3-(aq)
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CoCl2.6H2O(aq) contains pink Co2+
(aq) and colorless Cl-(aq)
If the Solutions in 2.38 Are Mixed …
mix
blue solid forms
centrifuge
What products form? Na3PO4(aq) + CoCl2(aq) ?
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When Rxn Is Complete
Supernatant contains only Na+(aq) and Cl-(aq)
Blue ppt of Co3(PO4)2 is present
2Na3PO4(aq) + 3CoCl2(aq) Co3(PO4)2 (s) + 6NaCl(aq)
Three Ways to Write Eqn for 2.38
Whole formula equation
Ionic equation
Net ionic equation (excludes spectator ions)3Co2+(aq) + 2PO4
3-(aq) Co3(PO4)2(s)
2Na3PO4(aq) + 3CoCl2(aq) Co3(PO4)2 (s) + 6NaCl(aq)
6Na+(aq) + 2PO43-(aq) + 3Co2+(aq) + 6Cl-(aq)
Co3(PO4)2 (s) + 6Na+(aq) + 6Cl-(aq)
The Experiment in 2.38
3Co2+(aq) + 2PO43-(aq) Co3(PO4)2(s)
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add Na3PO4 (aq)
CoCl2.6H2O(aq)
mix
centrifuge
blue solid forms
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The Experiment in 2.38
3Co2+(aq) + 2PO43-(aq) Co3(PO4)2(s)
Do This For ONE Assigned Tube:
See table on the worksheet for information about M and V for the reactant solutions
Determine the number of moles of each reactant moles = M*V
Stoichiometry Calculations (2.38)
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0.00090 mole 0.00045 mole Co2+
0.00090mole
0.00045 mole
0.00045 mole PO4
3-
Do This For Assigned Tube:
Identify which reactant will be consumed entirely (limiting reactant) and which will be in excess
Calculate the amount of each reactant left after rxn
Calculate the yield in moles
of Co3(PO4)2
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0.00090 mole
More Stoichiometry Calculations (2.38)
Reaction Stoichiometry Results
Tube Co2+ excess or completely consumed?
PO43- excess or
completely consumed?
Moles Co2+ left at end
Moles PO43-
left at endMoles of Co3(PO4)2
1 consumed excess 0 0.00030 0.00030
2 excess consumed 0.00022 0 0.00023
3 consumed excess 0 0.00060 0.00015
4 consumed excess 0 0.00015 0.00015
3Co2+(aq) + 2PO4
3-(aq) Co3(PO4)2(s)
Why is supernatant in tube #2 pink?
Why are supernatants in other tubes colorless?
Why is the amount of blue ppt not the same in all the tubes?
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Final Questions About 2.38