polarity in molecules - pennsylvania state...
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CH110 Hyrbrid Orbitals 1LRSVDS
Chapter 9 part 2: Polarity in Molecules,
Valence Bond Theory
Read: BLB 9.3–5
HW: BLB 9.33, 35, 38, 43, 47;
Packet 9:8-16
Know:
polarity of molecules
molecular orbitals
orbital hybridization
Which Skill Check Test Bonus Deadlineis Approaching??__________________________________
When is EXAM 2???
_______________________________
CH110 Hyrbrid Orbitals 2LRSVDS
Polarity in Molecules
• Just because a
molecule possesses
polar bonds does not
mean the molecule as
a whole will be polar.
Dipole Moment (µ)
• How can wedetermine theoverall dipolemoment for themolecule?
CH110 Hyrbrid Orbitals 3LRSVDS
Dipole Moment
For a diatomic molecule: µ = Q r
| r | units = debye (D)•!!!• = 3.33 x10"30 C-m
+Q "Q
For two charges (+1 and -1) separated by 1 Å
µ = 4.79 D per Å
Where Q = 1.6 x10"19 C = charge of an electron
For a polyatomic molecule: µ depends on:
1.
2.
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Which molecules are
polar?
CH110 Hyrbrid Orbitals 5LRSVDS
Dipole Trends in H-X
HX bondlength Å
µ(exp)D
µ(ionic)D
!EN % ionic
HF 0.92 1.82 4.41 1.9 41%
HCl 1.27 1.08 6.08 0.9 18%
HBr 1.41 0.82 6.75 0.7 12%
HI 1.61 0.44 7.71 0.4 6%
If the H-X bond were ionic, µ(ionic) = Q r
If the H-Cl bond was ionic (r = 1.27 Å )µ = 4.79 D /Å x 1.27 Å = 6.08 D
However, experimental data show:µ = 1.08 D
Compare the two values:µ(exp) /µ(ionic) x 100 =
1.08/6.08 x 100 = 18%
The bond is only 18% ionic
(82% covalent; polar covalent)
CH110 Hyrbrid Orbitals 6LRSVDS
Oxidation Numbers, Formal
Charges, and Partial Charges
+1 -1 0 0 +# "#
H-Cl H-Cl H-Cl # = 0.18oxidation formal partial chargesnumbers charges (experimental)
Dipole moment (µ) Measures:
CH110 Hyrbrid Orbitals 7LRSVDS
Polarity of Molecules
A molecule is polar if there is a NET
charge separation between two "ends"of the molecule: molecule has a
negative "end" and a positive "end".
Requirements to have a net dipole:1.
2.
_________________________________
To determine the polarity of a moleculethat has more than 2 atoms:
1.
2.
3.
4.
CH110 Hyrbrid Orbitals 8LRSVDS
Examples
CO2 O=C=O
electronegativity:C = 2.5 O = 3.5
EPG:MG:bond dipoles? Net dipole moment?_________________________________
CF4
electronegativity:C = 2.5 F = 4.0
EPG:MG:
Bond dipoles?Net dipole moment?
F
CF
F
F
CH110 Hyrbrid Orbitals 9LRSVDS
Examples
H2O
electronegativity:H = 2.1 O = 3.5
EPG:MG:bond dipoles? Net dipole moment?_________________________________
CH3Cl
electronegativity:H = 2.1 C = 2.5 Cl = 3.0
EPG:MG:
Bond dipoles?Net dipole moment?
OH
H
C
Cl
H
HH
CH110 Hyrbrid Orbitals 10LRSVDS
Examples
NH3
electronegativity:H = 2.1 N = 3.0
EPG:MG:
Net dipole moment?
NH
HH
NF
FF
NH3 vs. NF3
µ= 1.47 D µ = 0.24 D
[electronegativity: H = 2.1 N = 3.0 F = 4.0]
lone-pairs also have small dipolespartial cancellation of bond dipoles in NF3
CH110 Hyrbrid Orbitals 11LRSVDS
Chapter 9 part 3: Valence Bond Theory
Read: BLB 9.4–5
HW: BLB 9:43, 47;
Packet 9:12-16
Know:
molecular orbitals
orbital hybridization
CH110 Hyrbrid Orbitals 12LRSVDS
How are bonds made?
Lewis structures: location and number ofbonding and lone-pair electrons
VSEPR: spatial distribution of electrons, shape ofmolecule
How have we described electron distribution inatoms?
What is the electron distribution in molecules?
Molecular Orbitals
Two models:
Valence Bond Theory
Valence orbitals on one atom overlap
with valence orbitals on another atom:
this overlap is a covalent bond.
Molecular Orbital Theorya better model that uses wave theory, BUT not
covered in Chem 110 ! [studied in Chem 112
and organic chemistry]
CH110 Hyrbrid Orbitals 13LRSVDS
Overlap and Bonding
• Covalent bonds formed through the
sharing of electrons by adjacent
atoms.
• Only occurs when orbitals on the
two atoms overlap.
CH110 Hyrbrid Orbitals 14LRSVDS
Overlap and Bonding
Two forces operating:• increased overlap of atomic orbitals
(better sharing) brings atoms together
• closer distance between nuclei increasespositive-positive charge repulsion
balance of forces ! bond length (0.74 Å for H2)
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How can atomic orbitals
overlap to form observed
geometries?
CH110 Hyrbrid Orbitals 16LRSVDS
Bonding in CH4
Carbon ground-state configuration:
Using only open (unpaired) subshell electrons:
Expect:"CH2" molecule90o bond angles.
What if we “Promote” 2 electrons?
If all subshell electrons participated in bonding, this"CH4" molecule would have:
1.2.3.4.
However,
" Real molecule is tetrahedral" 109.5o bond angles," all bonds are equal length and strength
H
C H
CH110 Hyrbrid Orbitals 17LRSVDS
Bonding Orbitals in Be
• Consider beryllium:
– No singly-occupied
orbitals
– Can’t form Bonds?
• Absorb Energy– Now form 2 bonds?
– Bonds equal?
CH110 Hyrbrid Orbitals 18LRSVDS
Hybrid Orbitals• Mixing the s and p orbitals yields two
degenerate orbitals that are hybrids ofthe two orbitals.
– These sp hybrid orbitals have ____ lobeslike a p orbital.
– One of the lobes is larger and morerounded as is the s orbital.
!The sp orbitals are higher in energy than the 1sorbital but lower than the 2p.
CH110 Hyrbrid Orbitals 19LRSVDS
Hybrid Orbitals on Be
• These two degenerate sp orbitals wouldalign themselves 180° from each other.
• This is consistent with the observedgeometry of beryllium compounds:linear.
CH110 Hyrbrid Orbitals 20LRSVDS
Hybrid orbitals on B
Using a similar model for boron leads
to…
…________ degenerate sp2 orbitals.
CH110 Hyrbrid Orbitals 21LRSVDS
Hybrid Orbitals on C
With carbon we get…
…_____ degenerate sp3 orbitals.
CH110 Hyrbrid Orbitals 22LRSVDS
Naming Hybrid Orbitals
NOTE:1. start with four atomic orbitals
s px py pz
2. end up with four hybridorbitals
4 sp3
# orbitals name of orbital
Each hybrid orbital iscomposed of:
CH110 Hyrbrid Orbitals 23LRSVDS
Hybrid Orbitals Using d Orbitals
CH110 Hyrbrid Orbitals 24LRSVDS
Hybrid Orbitals
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Deduce the Hybridization from
Molecular Shape
NH H
H
N
H
H
H
Formula Structure Hybridization
OH
H
O
H
H
B
F
F
F
F
BF
F