please start bellwork # hw, red pen, book on desk
TRANSCRIPT
![Page 1: Please start Bellwork # HW, red pen, book on desk](https://reader036.vdocuments.mx/reader036/viewer/2022062516/56649db95503460f94aa910e/html5/thumbnails/1.jpg)
Please start Bellwork #
HW, red pen, book on desk.
![Page 2: Please start Bellwork # HW, red pen, book on desk](https://reader036.vdocuments.mx/reader036/viewer/2022062516/56649db95503460f94aa910e/html5/thumbnails/2.jpg)
3-23-11
HW, red pen, book on desk.
![Page 3: Please start Bellwork # HW, red pen, book on desk](https://reader036.vdocuments.mx/reader036/viewer/2022062516/56649db95503460f94aa910e/html5/thumbnails/3.jpg)
Surface Area: Prisms and Cylinders
Lesson 10-5 p.527
![Page 4: Please start Bellwork # HW, red pen, book on desk](https://reader036.vdocuments.mx/reader036/viewer/2022062516/56649db95503460f94aa910e/html5/thumbnails/4.jpg)
Surface Area
Surface area is the area of the sum of all of the surfaces of a space figure.
In other words, it is the area of the net.
![Page 5: Please start Bellwork # HW, red pen, book on desk](https://reader036.vdocuments.mx/reader036/viewer/2022062516/56649db95503460f94aa910e/html5/thumbnails/5.jpg)
Surface Area
3 cm
3 cm
2 cm5 cm
Notice that there are 2 bases (front and back) that are identical. There are also two faces (the top and bottom) that are identical.In addition there are two sides (right and left) that are identical.
![Page 6: Please start Bellwork # HW, red pen, book on desk](https://reader036.vdocuments.mx/reader036/viewer/2022062516/56649db95503460f94aa910e/html5/thumbnails/6.jpg)
Surface Area
To find the surface area, find the area of each surface and add them together.
3 cm
3 cm
2 cm5 cm
First, let’s calculate the front and back:A = bhA = 3 (2) = 6 sq. cm. for the front and 6 sq. cm. for the back.
Next, let’s look at the top and bottom:A = bhA = 5 (3) = 15 sq. cm for the top and 15 sq. cm for the bottom.
Last, let’s calculate the right and left sidesA = bhA = 5 (2) = 10 sq. cm for the right sideand 10 sq. cm for the left side.
![Page 7: Please start Bellwork # HW, red pen, book on desk](https://reader036.vdocuments.mx/reader036/viewer/2022062516/56649db95503460f94aa910e/html5/thumbnails/7.jpg)
Surface Area
To find the surface area, find the area of each surface and add them together.
3 cm
3 cm
2 cm5 cm
First, let’s calculate the front and back:A = bhA = 3 (2) = 6 sq. cm. for the front and 6 sq. cm. for the back.
Next, let’s look at the top and bottom:A = bhA = 5 (3) = 15 sq. cm for the top and 15 sq. cm for the bottom.
Last, let’s calculate the right and left sidesA = bhA = 5 (2) = 10 sq. cm for the right sideand 10 sq. cm for the left side.
If we add up all the areas,(6 + 6 + 15 + 15 + 10 + 10)we get 62 sq. cm. That is thetotal surface area of the prism.
![Page 8: Please start Bellwork # HW, red pen, book on desk](https://reader036.vdocuments.mx/reader036/viewer/2022062516/56649db95503460f94aa910e/html5/thumbnails/8.jpg)
Surface Area
Another way to calculate the surface area is to measure the net:
3 cm
3 cm
2 cm5 cm
3 cm
2 cm
5 cm
![Page 9: Please start Bellwork # HW, red pen, book on desk](https://reader036.vdocuments.mx/reader036/viewer/2022062516/56649db95503460f94aa910e/html5/thumbnails/9.jpg)
Surface Area
Another way to calculate the surface area is to measure the net:
3 cm
3 cm
2 cm5 cm
3 cm
2 cm
5 cm
If you calculate the area of each face (or piece)the answer is still 62 sq. cm.
10 15 10
15
6
6
![Page 10: Please start Bellwork # HW, red pen, book on desk](https://reader036.vdocuments.mx/reader036/viewer/2022062516/56649db95503460f94aa910e/html5/thumbnails/10.jpg)
Try This
Find the surface area:
10 in
4 in
3 in
![Page 11: Please start Bellwork # HW, red pen, book on desk](https://reader036.vdocuments.mx/reader036/viewer/2022062516/56649db95503460f94aa910e/html5/thumbnails/11.jpg)
Try This
Find the surface area:
10 in
4 in
3 in
164 sq. in.
![Page 12: Please start Bellwork # HW, red pen, book on desk](https://reader036.vdocuments.mx/reader036/viewer/2022062516/56649db95503460f94aa910e/html5/thumbnails/12.jpg)
Surface Area
We can do the same procedure with a triangular prism:
3 ft
4 ft
6 ft5 ft
How many faces or surfaces are there?
![Page 13: Please start Bellwork # HW, red pen, book on desk](https://reader036.vdocuments.mx/reader036/viewer/2022062516/56649db95503460f94aa910e/html5/thumbnails/13.jpg)
Surface Area
We can do the same procedure with a triangular prism:
3 ft
4 ft
6 ft5 ft
How many faces or surfaces are there?Notice there are 5 surfaces.There are 2 triangles, there is the back,the floor or bottom, and the slanted face.
![Page 14: Please start Bellwork # HW, red pen, book on desk](https://reader036.vdocuments.mx/reader036/viewer/2022062516/56649db95503460f94aa910e/html5/thumbnails/14.jpg)
Surface Area
First calculate the triangles: A = bh 3 (4) = 6 sq. ft. (1st triangle)
2 2 6 sq. ft. (2nd triangle)
3 ft
4 ft
6 ft5 ft
![Page 15: Please start Bellwork # HW, red pen, book on desk](https://reader036.vdocuments.mx/reader036/viewer/2022062516/56649db95503460f94aa910e/html5/thumbnails/15.jpg)
Surface Area
First calculate the triangles: A = bh 3 (4) = 6 sq. ft. (1st triangle)
2 2 6 sq. ft. (2nd triangle)
Next calculate the back: A = bh A = 6 (3) = 18 sq. ft. (back)
Next is the floor: A = bh A = 6 (4) = 24 sq. ft. (floor)
3 ft
4 ft
6 ft5 ft
![Page 16: Please start Bellwork # HW, red pen, book on desk](https://reader036.vdocuments.mx/reader036/viewer/2022062516/56649db95503460f94aa910e/html5/thumbnails/16.jpg)
Surface Area
First calculate the triangles: A = bh 3 (4) = 6 sq. ft. (1st triangle)
2 2 6 sq. ft. (2nd triangle)
Next calculate the back: A = bh A = 6 (3) = 18 sq. ft. (back)
Next is the floor: A = bh A = 6 (4) = 24 sq. ft. (floor)
Add them all up for a total of 84 sq. ft.
3 ft
4 ft
6 ft5 ft
![Page 17: Please start Bellwork # HW, red pen, book on desk](https://reader036.vdocuments.mx/reader036/viewer/2022062516/56649db95503460f94aa910e/html5/thumbnails/17.jpg)
Surface Area
First calculate the triangles: A = bh 3 (4) = 6 sq. ft. (1st triangle)
2 2 6 sq. ft. (2nd triangle)
Next calculate the back: A = bh A = 6 (3) = 18 sq. ft. (back)
Next is the floor: A = bh A = 6 (4) = 24 sq. ft. (floor)
Finally find the area of the slant:
A = bh = 6 (5) = 30 sq. ft.
Add them all up for a total of 84 sq. ft.
3 ft
4 ft
6 ft5 ft
![Page 18: Please start Bellwork # HW, red pen, book on desk](https://reader036.vdocuments.mx/reader036/viewer/2022062516/56649db95503460f94aa910e/html5/thumbnails/18.jpg)
Surface Area
We can also calculate the area of a cylinder.
3 m
5 m
What are the shapes that make up acylinder?
![Page 19: Please start Bellwork # HW, red pen, book on desk](https://reader036.vdocuments.mx/reader036/viewer/2022062516/56649db95503460f94aa910e/html5/thumbnails/19.jpg)
Surface Area
We can also calculate the area of a cylinder.
3 m
5 m
What are the shapes that make up acylinder?Did you remember that there are two circles, and a rectangle?
![Page 20: Please start Bellwork # HW, red pen, book on desk](https://reader036.vdocuments.mx/reader036/viewer/2022062516/56649db95503460f94aa910e/html5/thumbnails/20.jpg)
Surface Area
This one is best calculated by looking at the net.
3 m
It is easy to calculate the area of the circles,
2r = 3.14 (3)2
= 28.26 sq. m
(remember there are 2circles so multiply 28.26times 2 to get 56.52 sq. m
5 cm
![Page 21: Please start Bellwork # HW, red pen, book on desk](https://reader036.vdocuments.mx/reader036/viewer/2022062516/56649db95503460f94aa910e/html5/thumbnails/21.jpg)
Surface Area
So we know the circles have a total of 56.52 sq. m. but what about the rectangle?
3 m
5 cm
We can easily see that the heightIs 5 cm, but what is the value ofthe base?
![Page 22: Please start Bellwork # HW, red pen, book on desk](https://reader036.vdocuments.mx/reader036/viewer/2022062516/56649db95503460f94aa910e/html5/thumbnails/22.jpg)
Surface Area
So we know the circles have a total of 56.52 sq. m. but what about the rectangle?
3 m
5 cm
We can easily see that the heightIs 5 cm, but what is the value ofthe base?
The base of the rectangle is theCIRCUMFERENCE of the circle.
![Page 23: Please start Bellwork # HW, red pen, book on desk](https://reader036.vdocuments.mx/reader036/viewer/2022062516/56649db95503460f94aa910e/html5/thumbnails/23.jpg)
Surface Area
3 m
5 cm
To find the circumference of the circle, remember the formula is d
So, C = 3.14 (6) = 18.84 cm
![Page 24: Please start Bellwork # HW, red pen, book on desk](https://reader036.vdocuments.mx/reader036/viewer/2022062516/56649db95503460f94aa910e/html5/thumbnails/24.jpg)
Surface Area
3 m
5 cm
To find the circumference of the circle, remember the formula is d
So, C = 3.14 (6) = 18.84 cm
18.84 cm
OK, so A = bh A = 18.84 (5)
= 94.2 sq. cm.
Remember that the area of theTwo circles totaled 56.52 sq. cm?
The last step is to add the 94.2 Plus the 56.52 to get a total of150.72
![Page 25: Please start Bellwork # HW, red pen, book on desk](https://reader036.vdocuments.mx/reader036/viewer/2022062516/56649db95503460f94aa910e/html5/thumbnails/25.jpg)
Try This
Find the surface area
10 ft
4 ft.
![Page 26: Please start Bellwork # HW, red pen, book on desk](https://reader036.vdocuments.mx/reader036/viewer/2022062516/56649db95503460f94aa910e/html5/thumbnails/26.jpg)
Try This
Find the surface area
10 ft
4 ft.
First find the area of the two circles. What is the total of The two circles?
![Page 27: Please start Bellwork # HW, red pen, book on desk](https://reader036.vdocuments.mx/reader036/viewer/2022062516/56649db95503460f94aa910e/html5/thumbnails/27.jpg)
Try This
Find the surface area
10 ft
4 ft.
First find the area of the two circles. What is the total of The two circles?
100.48 sq. ft.
![Page 28: Please start Bellwork # HW, red pen, book on desk](https://reader036.vdocuments.mx/reader036/viewer/2022062516/56649db95503460f94aa910e/html5/thumbnails/28.jpg)
Try This
Find the surface area
10 ft
4 ft.100.48 sq. ft. (area of the two circles)
Next find the area of the rectangle. The base is the sameas the circumference of the circle. Find the circumferenceof the circle.
25.12 cm
![Page 29: Please start Bellwork # HW, red pen, book on desk](https://reader036.vdocuments.mx/reader036/viewer/2022062516/56649db95503460f94aa910e/html5/thumbnails/29.jpg)
Try This
Find the surface area
10 ft
4 ft.100.48 sq. ft. (area of the two circles)
25.12 cm = the base of the rectangle.
Find the area of the rectangle:
![Page 30: Please start Bellwork # HW, red pen, book on desk](https://reader036.vdocuments.mx/reader036/viewer/2022062516/56649db95503460f94aa910e/html5/thumbnails/30.jpg)
Try This
Find the surface area
10 ft
4 ft.100.48 sq. ft. (area of the two circles)
25.12 cm = the base of the rectangle.
Find the area of the rectangle:
A of rectangle = 251.2 sq ft.
![Page 31: Please start Bellwork # HW, red pen, book on desk](https://reader036.vdocuments.mx/reader036/viewer/2022062516/56649db95503460f94aa910e/html5/thumbnails/31.jpg)
Try This
Find the surface area
10 ft
4 ft.100.48 sq. ft. (area of the two circles)
A of rectangle = 251.2 sq ft.
Now find the total surface area.
![Page 32: Please start Bellwork # HW, red pen, book on desk](https://reader036.vdocuments.mx/reader036/viewer/2022062516/56649db95503460f94aa910e/html5/thumbnails/32.jpg)
Try This
Find the surface area
10 ft
4 ft.100.48 sq. ft. (area of the two circles)
A of rectangle = 251.2 sq ft.
Now find the total surface area.
351.68 sq. ft.
![Page 33: Please start Bellwork # HW, red pen, book on desk](https://reader036.vdocuments.mx/reader036/viewer/2022062516/56649db95503460f94aa910e/html5/thumbnails/33.jpg)
PA#42
P.530 #1-6
Print out CAT 6 Review for 7th grade standards.
![Page 34: Please start Bellwork # HW, red pen, book on desk](https://reader036.vdocuments.mx/reader036/viewer/2022062516/56649db95503460f94aa910e/html5/thumbnails/34.jpg)
3-23-11
PA#43
P.530 #8-13
Print out CAT 6 Review for 7th grade standards. Pages 9-30