physics / higher physics 1a
TRANSCRIPT
Physics / Higher Physics 1A
Electricity and Magnetism
Revision
Electric Charges
Two kinds of electric charges
Called positive and negative
Like charges repel
Unlike charges attract
Coulomb’s Law
In vector form,
is a unit vector
directed from q1 to q2
Like charges produce a
repulsive force between
them
F12
ke
q1q
2
r2
ˆ r
ˆ r
The Superposition Principle
The resultant force on q1 is the vector
sum of all the forces exerted on it by
other charges: F1 = F21 + F31 + F41 + …
Electric Field
Continuous charge distribution
2ˆe
e
o
qk
q r
FE r
2 20
ˆ ˆl imi
i
e i eq
i i
q d qk k
r r
E r r
Electric Field Lines – Dipole
The charges are
equal and opposite
The number of field
lines leaving the
positive charge
equals the number
of lines terminating
on the negative
charge
Electric Flux
0
s u r fa c e
l imi
E i iA
E A d
E A
E E
i A
icos
i E
i A
i
Gauss’s Law
qin is the net charge inside the surface
E represents the electric field at any point on the
surface
E E d A
qin
0
Field Due to a Plane of Charge
The total charge in the surface is σA
Applying Gauss’s law
Field uniform everywhere
E 2 EA
A
0
, and E
2 0
Properties of a Conductor in
Electrostatic Equilibrium
1. Electric field is zero everywhere inside conductor
2. Charge resides on its surface of isolated conductor
3. Electric field just outside a charged conductor is perpendicular to the surface with magnitude σ/εo
4. On an irregularly shaped conductor surface charge density is greatest where radius of curvature is smallest
Work done by electric field is F.ds = qoE.ds
Potential energy of the charge-field system is
changed by ΔU = -qoE.ds
For a finite displacement of the charge from A
to B, the change in potential energy is
Electric Potential Energy
B
B A oA
U U U q d E s
Electric Potential, V
The potential energy per unit charge, U/qo, is the electric potential
The work performed on the charge is W = ΔU = q ΔV
In a uniform field
B
A
o
UV d
q
E s
B B
B AA A
V V V d E d E d E s s
Equipotential Surface
Any surface consisting
of a continuous
distribution of points
having the same
electric potential
For a point charge
e
qV k
r
From V = -E.ds = -Exdx
Along an equipotential surfaces V = 0 Hence E ds
i.e. an equipotential surface is perpendicular to the electric field lines passing through it
Finding E From V
x
d VE
d x
V Due to a Charged
Conductor
E · ds = 0
So, potential difference
between A and B is zero
Electric field is zero inside
the conductor
So, electric potential
constant everywhere inside
conductor and equal to
value at the surface
Cavity in a Conductor
Assume an irregularly
shaped cavity is inside a
conductor
Assume no charges are
inside the cavity
The electric field inside the
conductor must be zero
Definition of Capacitance
The capacitance, C, is ratio of the charge on either conductor to the potential difference between the conductors
A measure of the ability to store charge
The SI unit of capacitance is the farad (F)
QC
V
Capacitance – Parallel Plates
Charge density σ = Q/A
Electric field E = /0 (for conductor) Uniform between plates, zero elsewhere
C Q
V
Q
Ed
Q
Q
0A
d
0A
d
Capacitors in Parallel
Capacitors can be replaced with one capacitor with a capacitance of Ceq
Ceq = C1 + C2
Capacitors in Series
Potential differences add up to the battery voltage
Q Q1 Q
2
V V1 V
2
V
Q
V1
Q1
V
2
Q2
1
C
1
C1
1
C2
Energy of Capacitor
Work done in charging the capacitor appears as electric potential energy U:
Energy is stored in the electric field
Energy density (energy per unit volume)
uE = U/Vol. = ½ oE2
2
21 1( )
2 2 2
QU Q V C V
C
Capacitors with Dielectrics
A dielectric is a nonconducting material that, when placed between the plates of a capacitor, increases the capacitance
For a parallel-plate capacitor
C = κCo = κεo(A/d)
Rewiring charged capacitors
Two capacitors, C1 & C2 charged to same potential difference, Vi.
Capacitors removed from battery and plates connected with opposite polarity.
Switches S1 & S2 then closed. What is final potential difference, Vf?
Q1i, Q2i before; Q1f, Q2f after.
Q1i = C1Vi; Q2i = -C2Vi
So Q=Q1i+Q2i=(C1-C2)Vi
But Q= Q1f+Q2f (charge conserved)
With Q1f = C1Vf; Q2f = C2Vf hence Q1f = C1/C2 Q2f
So, Q=(C1/C2+1) Q2f
With some algebra, find Q1f = QC1/(C1+C2) & Q2f = QC2/(C1+C2)
So V1f = Q1f / C1 = Q / (C1+C2) & V2f = Q2f / C2 = Q / (C1+C2)
i.e. V1f = V2f = Vf, as expected
So Vf = (C1 - C2) / (C1 + C2) Vi, on substituting for Q
Magnetic Poles
Every magnet has two poles
Called north and south poles
Poles exert forces on one another
Like poles repel
N-N or S-S
Unlike poles attract
N-S
Magnetic Field Lines for a Bar Magnet
Compass can be used to trace the field lines
The lines outside the magnet point from the North pole to the South pole
Direction
FB perpendicular to plane formed by v & B
Oppositely directed forces are exerted on charges of different signs
cause the particles to move in opposite directions
Direction given by Right-Hand Rule
Fingers point in the direction of v
(for positive charge; opposite direction if negative)
Curl fingers in the direction of B
Then thumb points in the direction of v x B; i.e. the direction of FB
The Magnitude of F
The magnitude of the magnetic force on a charged particle is FB = |q| vB sin
is the angle between v and B
FB is zero when v and B are parallel
FB is a maximum when perpendicular
Force on a Wire
F = I L x B
L is a vector that points in the direction of the current (i.e. of vD)
Magnitude is the length L of the segment
I is the current = nqAvD
B is the magnetic field
Force on a Wire of Arbitrary Shape
The force exerted segment ds is
F = I ds x B
The total force is
Ib
d a
F s B
Force on Charged Particle
Equating the magnetic & centripetal forces:
Solving gives r = mv/qB
F qvB mv
2
r
Biot-Savart Law
dB is the field created by the current in the length segment ds
Sum up contributions from all current elements I.ds
B
0
4
I d s ˆ r
r2
B for a Long, Straight Conductor
B
0I
2 a
B for a Long, Straight Conductor, Direction
Magnetic field lines are circles concentric with the wire
Field lines lie in planes perpendicular to to wire
Magnitude of B is constant on any circle of radius a
The right-hand rule for determining the direction of B is shown Grasp wire with thumb in direction of
current. Fingers wrap in direction of B.
Magnetic Force Between Two Parallel Conductors
Parallel conductors carrying currents in the same direction attract each other
Parallel conductors carrying currents in opposite directions repel each other
F1
0I
1I
2
2 al
Definition of the Ampere
The force between two parallel wires can be used to define the ampere
When the magnitude of the force per unit length between two long parallel wires that carry identical currents and are separated by 1 m is 2 x 10-7 N/m, the current in each wire is defined to be 1 A
F1
l
0I
1I
2
2 a with
0 4 10
7 T m A
-1
Ampere’s Law
The line integral of B . ds around any closed path equals oI, where I is the
total steady current passing through any surface bounded by the closed path.
B ds 0I
Field in interior of a Solenoid
Apply Ampere’s law
The side of length ℓ inside the
solenoid contributes to the field
Path 1 in the diagram
BdsBdd1path 1path
sBsB
B 0
N
l
I 0nI
Ampere’s vs. Gauss’s Law
Integrals around closed path vs. closed surface. i.e. 2D vs. 3D geometrical figures
Integrals related to fundamental constant x source of the field.
Concept of “Flux” – the flow of field lines through a surface.
B ds 0I
E dA q
0
Gauss’ Law in Magnetism
Magnetic fields do not begin or end at any point i.e. they form closed loops, with the number of lines
entering a surface equaling the number of lines leaving that surface
Gauss’ law in magnetism says:
B B .d A 0
Faraday’s Law of Induction
The emf induced in a circuit is directly proportional to the rate of change of the magnetic flux through that circuit
Nd
B
dt
QuickTime™ and a
Cinepak decompressor
are needed to see this picture.
Ways of Inducing an emf
Magnitude of B can change with time
Area enclosed, A, can change with time
Angle can change with time
Any combination of the above can occur
d
dt
BA cos
Motional emf
Motional emf induced in a conductor moving through a constant magnetic field
Electrons in conductor experience a force, FB = qv x B that is directed along ℓ
In equilibrium, qE = qvB or E = vB
Sliding Conducting Bar
Magnetic flux is
The induced emf is
Thus the current is
d
B
dt
d
dt
Blx Bldx
dt
Blv
B Blx
I
R
Blv
R
Induced emf & Electric Fields
A changing magnetic flux induces an emf and a current in a conducting loop
An electric field is created in a conductor by a changing magnetic flux
Faraday’s law can be written in a general form:
Not an electrostatic field because the line integral of E.ds is not zero.
E .ds d
B
dt
Generators
Electric generators take in energy by work and transfer it out by electrical transmission
The AC generator consists of a loop of wire rotated by some external means in a magnetic field
Rotating Loop
Assume a loop with N turns, all of the same area, rotating in a magnetic field
The flux through one loop at any time t is:
B = BA cos = BA cos wt
Nd
B
dt
NABd
dt
cos w t NAB w sin w t
Motors
Motors are devices into which energy is transferred by electrical transmission while energy is transferred out by work
A motor is a generator operating in reverse
A current is supplied to the coil by a battery and the torque acting on the current-carrying coil causes it to rotate
Eddy Currents
Circulating currents called eddy currents are induced in bulk pieces of metal moving through a magnetic field
From Lenz’s law, their direction is to oppose the change that causes them.
The eddy currents are in opposite directions as the plate enters or leaves the field
Equations for Self-Inductance
Induced emf proportional to the rate of change of the current
L is a constant of proportionality called the inductance of the coil.
L L
dI
dt
Inductance of a Solenoid
Uniformly wound solenoid having N turns and length ℓ. Then we have:
B 0nI
0
N
l
I
B BA
0
NA
l
I
L N
B
I
0N
2
A
l
Energy in a Magnetic Field
Rate at which the energy is stored is
Magnetic energy density, uB, is
II
d U dL
d t d t
U L IdI
0
I
12LI
2
uBU
Al
B
2
2 0
RL Circuit
Time constant, tL / R, for the circuit
t is the time required for current to reach 63.2% of its max value
I R
1 e Rt
L
R1 e
tt