physics 1161 lecture 11 rc circuits
DESCRIPTION
Physics 1161 Lecture 11 RC Circuits. 1. 2. t = 2RC. Time Constant Demo. Example. Each circuit has a 0.5 F capacitor charged to 9 Volts. When the switch is closed:. Which system will be brightest? Which lights will stay on longest? Which lights consume more energy?. t = RC/2. 1. 2. - PowerPoint PPT PresentationTRANSCRIPT
Physics 1161 Lecture 11RC Circuits
Time Constant Demo
• Which system will be brightest?• Which lights will stay on longest?• Which lights consume more energy?
2
Each circuit has a 0.5 F capacitor charged to 9 Volts.When the switch is closed:
1
= 2RC = RC/2
Time Constant Demo
• Which system will be brightest?• Which lights will stay on longest?• Which lights consume more energy?
2
Each circuit has a 0.5 F capacitor charged to 9 Volts.When the switch is closed:
1
= 2RC = RC/2
2 I=2V/R
1
Same U=1/2 CV2
Preflight 11.1, 11.3
2R
C R
S2
Both switches are initially open, and the capacitor is uncharged. What is the current through the battery just after switch S1 is closed?
1) Ib = 0
2) Ib = /(3R)
3) Ib = /(2R)
4) Ib = /R
S1
Ib
+
-
+
+
-
-
Both switches are initially open, and the capacitor is uncharged. What is the current through the battery after switch 1 has been closed a long time?
1) Ib = 0 2) Ib = V/(3R) 3) Ib = V/(2R) 4) Ib = V/R
15%
4%
62%
19%
50% 0% 35% 15%
Practice!
Calculate current immediately after switch is closed:
Calculate current after switch has been closed for 0.5 seconds:
Calculate current after switch has been closed for a long time:
Calculate charge on capacitor after switch has been closed for a long time:
R
CE
S1
R=10C=30 mF
E =20 Volts
-
Practice
Calculate current immediately after switch is closed:
Calculate current after switch has been closed for 0.5 seconds:
Calculate current after switch has been closed for a long time:
Calculate charge on capacitor after switch has been closed for a long time:
R
CE
S1
R=10C=30 mF
E =20 Volts
- I0R - q0/C = 0I
+
+
+
-
-
- - I0R - 0 = 0
I0 = /R
After a long time current through capacitor is zero!
- IR - q∞/C = 0
+ 0 - q∞ /C = 0q∞ = C
0
t
RCI I e
0.5
RCeR
0.5
10 0.0320
10e
0.5
10 0.0320
10e
0.38 A
Both switches are closed. What is the final charge on the capacitor after the switches have been closed a long time?
1 2 3 4
25% 25%25%25%
IR
S2S1
+- R
+
-
C
2R+ -1. Q = 02. Q = C /33. Q = C /24. Q = C
Charging: Intermediate Times
Calculate the charge on the capacitor 310-3 seconds after switch 1 is closed.
q(t) = q(1-e-t/RC)
C R1
S2
S1
Ib
+
-
+
+
-
-
R1 = 20
R2 = 40
ε = 50 Volts
C = 100FR2
Charging: Intermediate Times
C R1
S2
S1
Ib
+
-
+
+
-
-
Calculate the charge on the capacitor 310-3 seconds after switch 1 is closed.
q(t) = q(1-e-t/R2C)
= q(1-e-310-3 /(4010010-6)))
= q (0.53)
Recall q = ε C
= (50)(100x10-6) (0.53)
= 2.7 x10-3 Coulombs
R1 = 20
R2 = 40
ε = 50 Volts
C = 100FR2
RC Circuits: Discharging
• KLR: ____________
• Just after…: ________– Capacitor is still fully charged
• Long time after: ____________
• Intermediate (more complex)– q(t) = q0 e-t/RC
– Ic(t) = I0 e-t/RC
C
R
S1
+
+
I-
-
S2
q
RC 2RC
t
RC Circuits: Discharging
• KLR: q(t) / C - I(t) R = 0
• Just after…: q=q0– Capacitor is still fully charged– q0 / C - I0 R = 0 I0 = q0/(RC)
• Long time after: Ic=0– Capacitor is discharged– q / C = 0 q = 0
• Intermediate (more complex)– q(t) = q0 e-t/RC
– Ic(t) = I0 e-t/RC
C
R
S1
+
+
I-
-
S2
q
RC 2RC
t
Preflight 11.5After switch 1 has been closed for a long time, it is opened and switch 2 is closed. What is the current through the right resistor just after switch 2 is closed?
1) IR = 0
2) IR = /(3R)
3) IR = /(2R)
4) IR = /R
KLR: -q0/C+IR = 0
Recall q is charge on capacitor after charging:q0= C (since charged w/ switch 2 open!)- + IR = 0 I = /R
2R
C R
S2S1
IR
+
-
+
+
-
-
+
-
27%
27%
4%
42%
After being closed for a long time, the switch is opened. What is the charge Q on the capacitor 0.06 seconds after the switch is opened?
E = 24 Volts
R = 4
C = 15 mF
RC
2R
E
S1
1. 0.368 q0
2. 0.632 q0
3. 0.135 q0
4. 0.865 q0
After being closed for a long time, the switch is opened. What is the charge Q on the capacitor 0.06 seconds after the switch is opened?
1 2 3 4
25% 25%25%25%
E = 24 Volts
R = 4
C = 15 mF
RC
2R
E
S1
q(t) = q0 e-t/RC
= q0 (e-0.06 /(4(1510-3)))
= q0 (0.368)
1. 0.368 q0
2. 0.632 q0
3. 0.135 q0
4. 0.865 q0