phys632 l8 ch 28 mag field 10
TRANSCRIPT
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Lecture 8 Magnetic Fields Ch. 29
Cartoon Magnesia, Bar Magnet with N/S Poles, Right Hand Rule
Topics
Permanent magnets
Magnetic field lines,
Force on a moving charge,
Right hand rule,
Force on a current carrying wire in a magnetic field,
Torque on a current loop
Demos Compass, declinometer, globe, magnet
Iron fillings and bar magnets
Compass needle array
Pair of gray magnets
CRT illustrating electron beam bent bent by a bar magnet - Lorentz law
Gimbal mounted bar magnet
Wire jumping out of a horseshoe magnet. Coil in a magnet
Elmo
Polling
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Magnetic Fields
Magnetism has been around as long as there has been an Earth with
an iron magnetic core.
Thousands of years ago the Chinese built compasses for navigation inthe shape of a spoon with rounded bottoms on which they balanced
(Rather curious shape for people who eat with chopsticks).
Certain natural rocks are ferromagnetic having been magnetized by
cooling of the Earths core.
Show a sample of natural magnetic rock. Put it next to many
compasses.
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Magnetisms Sociabilities
Magnetism has always has something of a mystic aura about it. It is
usually spoken of in a favorable light.
Animal magnetism, magnetic personality, and now you can wear
magnetic collars, bracelets, magnetic beds all designed to make you
healthier even grow hair.
We do not have the same feeling about electricity. If you live near
electric power lines, the first thing you want to do is to sue the electric
company.
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Compass and Declinometer
In 1600 William Gilbert used a compass needle to show how it orienteditself in the direction of the north geographic pole of the Earth, which
happens to be the south magnetic pole of the Earths permanentmagnetic field.
Show compass and declinometer. Each has a slightly magnetizedneedle that is free to rotate. The compass lines up with the componentof the magnetic field line parallel to the surface of the Earth. Thedeclinometer lines up with the actual magnetic field line itself. It saysthat the angle between the field lines and the surface is 71 degrees asmeasured from the south.
Earths magnetic field
Basically there are two types of magnets: permanent magnets andelectromagnets
Show field lines for a bar magnet. Show bar magnet surroundedby compass needle array.
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Permanent Magnets
Bar magnet is a model of a ferromagnetic material that can be
permanently magnetized. Other ferromagnetic materials are
cobalt and nickel.
The origin of magnetism in materials is due mostly to the spinning
motion of the charged electron on its own axis. There is a small
contribution from the orbital motion of the electron.
+
a
v
Electronorbiting
nucleus
Magnetic dipole
Magnetic
dipole
s
Electron
spinning onits axis
e
-
Atomic origin of magnetic field
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Permanent Magnets (continued)
In ferromagnetic materials there are whole sections of the iron
called domains where the magnetism does add up fromindividual electrons. Then there are other sections or domains
where contributions from different domains can cancel.
However, by putting the iron in a weak magnetic field you can
align the domains more or less permanently and produce a
permanent bar magnet as you see here.
In nonmagnetic materials the contributions from all
The electrons cancel out. Domains are not even formed.
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Magnetic field lines donot stop at surface.
They are continuous.
They make completeloops.
Field lines for a bar
magnet are the same as
for a current loop
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Magnetic field lines
Similarities to electric lines
A line drawn tangent to a field line is the direction of the field at thatpoint.
The density of field lines still represent the strength of the field.
Differences
The magnetic field lines do not terminate on anything. They formcomplete loops. There is no magnetic charge on as there was electriccharge in the electric case. This means if you cut a bar magnet in halfyou get two smaller bar magnets ad infinitum all the way down to theatomic level Magnetic atoms have an atomic dipole not a monopoleas is the case for electric charge.
They are not necessarily perpendicular to the surface of the
ferromagnetic material.
AdEfluxElectric
AdBfluxMagnetic
E
B
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Definition of magnetic Field
definition of a magnetic field
The units of B are or in SI units(MKS).
This is called a Tesla (T). One Tesla is a very strong field.
A commonly used smaller unit is the Gauss. 1 T = 104 G
(Have to convert Gauss to Tesla in formulas in MKS)
In general the force depends on angle . This iscalledthe Lorentz Force
qv
FB
)( .s
mC
N
).( mAN
BvqF
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In analogy with the electric force on a point charge, the corresponding
equation for a force on a moving point charge in a magnetic field is:
Magnitude of
Direction of F is given by the right hand rule (see next slide).
If = 90, then the force = and the particle moves in a circle.
v B sin(0o) = 0 F = 0
F B
v
BvqFm
EqFe
sinqvBFm
qvB
If the angle between v and B is = 0, then the force = 0.
Consider a uniform B field for simplicity.
Bv
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Use right hand rule tofind the direction ofF
+Positive Charge
Rotate v into B through the smaller angle and the force F will be in the directiona right handed screw will move.
BvqFm
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Motion of a point positive charge in a magnetic field.
For a + charge, the particle rotates counter clockwise.
For a - charge, the particle rotates counter clockwise.
This means kinetic energy remains constant.
The magnitude of velocity doesnt change.
Then the particle will move in a circle forever.
The B field provides the centripetal force needed for circular motion.
= qvBsin90o
Direction is given by the RHR (right
hand rule)
Magnitude of F = qvB
B is directed into the paper
r
x
x x
x
x
x
F
v
F
v
Fv +
F
v
B
BvqFm
SinceFv andFd, then the magnetic force
does no work on the charge. Work = 0
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Find the radius r and period of motion for a + charge
moving in the magnetic field B. Use Newtons 2nd Law.
What is the period of revolution of the motion?
qvBr
mvmaF
2
qB
mvr
Radius of the orbit
Important formula in
Physics
v
ar
r
va
2
T2r
v
2m
qB period T
Note the period is independent of the radius, amplitude, and velocity. Example of simple
harmonic motion in 2D.
T is also the cyclotron period.
It is important in the design of the cyclotron accelerator. Of course, this is important
because today it is used to make medical isotopes for radiation therapy.
m
qBf
tf
2
1
Cyclotron frequency
v qBr/m
x
x x
x
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Example: If a proton moves in a circle of radius 21 cm perpendicular to a
B field of 0.4 T, what is the speed of the proton and the frequency of
motion?
1
m
qBf
2
f 1.6 1019C (0.4T)
(2) 1.67 1027 kg
f1.6 (0.4)
(6.28) 1.67108Hz 6.1106Hz
Hzf
6101.6
2
m
qBrv
v 1.6 1019C (0.4T) 0.21m
1.67 1027 kg
v 1.6 (0.4) 0.21
1.67108 m
s
8.1106 ms
s
mv 6101.8
v
r
x x
x x
x x
x
x
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Use right hand rule to
find the direction ofF
+
NegativeCharge
Rotate v into B through the smaller angle and the force F will be in the oppositeDirection a right handed screw will move.
BvqFm
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Suppose we have an electron . Which picture is correct?
x
Noyes B
v
F F
x
x
x
x
x
x
x
v
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Example of the force on a fast moving proton due to the earths
magnetic field. (Already we know we can neglect gravity, but can
we neglect magnetism?) Magnetic field of earth is about 0.5 gauss.
Convert to Tesla. 1 gauss=10-4 Tesla
Let v = 107 m/s moving North.
What is the direction and magnitude of F?
Take B = 0.5x10-4 T and v perpendicular B to get maximum effect.
T105.010C106.1qvBF 4s
m719
m
N108F 17m
(a very fast-moving proton)
metervolts19 100C106.1qEF
e
Fe 1.6 1017N
V x B is into the
paper (west).
Check with globe
Earth
F i i i if i fi ld
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Force on a current-carrying wire in a uniform magnetic field
When a wire carries current in a magnetic field, there is a force on thewire that is the sum of the forces acting on each charge that is
contributing to the current.
vd is the drift
velocity of the
positive charges.
+
Cross sectional area A of
the wire
ivd
F
L
n = density of positive mobile charges
Number of charges = nAL
orL is a vector in the direction of the current i
with magnitude equal to the length of the wire.
Also
v isperpendicular to B
B (Out of the paper)
F (qv B)(nAL)
F nqvALB Current,i nqvA
iLBF
BLidFd
BLiF
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Show force on a wire in a magnetic field
BLiF
Current
up
Current
down
Drift velocity
of electrons
Torques on current loops
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Torques on current loops
Electric motors operate by connecting a coil in a magnetic field to a current
supply, which produces a torque on the coil causing it to rotate.
P i
a
b
Above is a rectangular loop of wire of sides a and b carrying current Iand is
in a uniform magnetic field B that is perpendicular to the normal n.
Equal and opposite forces are exerted on the sides a. No
forces exerted on b since i is parallel to B
Since net force is zero, we can evaluate torque at any point.
Evaluate it at P. Torque tends to rotate loop until plane is
perpendicular to B.
F iaB
i
B
B
F
F
A=ab = area of loop
B
Normal
b
b sin
Normal
Fbsin iaBbsin iABsin
Multiply by N for N loops NiABsin
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Galvanometer
i di l i ll d
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Magnetic dipole moment is called vec
U
B
Ep-U
Ep
Recall that for Electric dipole moment pNiABsin
NiA
Bsinr
r
rB
How do you define the direction of ?
RHR
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Demo: show torque on current loop (galvanometer)
Can you predict direction of rotation?
Example
A square loop has N = 100 turns. The area of the loop is 4 cm2 and it
carries a current I = 10 A. It makes an angle of 30o with a B field
equal to 0.8 T. Find the magnetic moment of the loop and the torque.
Demo: Show worlds simplest electric motor
(scratch off all insulation on one end)
Scratch off half on the other end
Momentum will carry it turn
(no opportunity for current to reverse coil direction)
mNTmABTmAmANiA
.16.05.08.0.4.030sin.4.010410100
2
224
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Electron moving with speed v in a crossed electric
and magnetic field in a cathode ray tube.
F q
E q
v
B
ye
Electric field bends particle upwards
Magnetic field bends it downwards
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Discovery of the electron by J.J. Thompson in 1897
2
2
mv2
qELy
1. E=0, B=0 Observe spot on screen
2. Set E to some value and measure y the deflection
3. Now turn on B until spot returns to the original position
B
Ev
qvBqE
4 Solve foryE2
LB
q
m 22
This ratio was first measured by Thompson
to be lighter than hydrogen by 1000
Show demo of CRT
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Chapter 28 Problem 18
An alpha particle (q = +2e, m = 4.00 u) travels in a circular path ofradius 5.00 cm in a magnetic field with B = 1.60 T. Calculate the
following values.
(a) the speed of the particle
(b) its period of revolution
(c) its kinetic energy
(d) the potential difference through which it would have to be
accelerated to achieve this energy
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Chapter 28 Problem 37
A 2.3 kg copper rod rests on two horizontal rails 2.4 m apart andcarries a current of 60 A from one rail to the other. The
coefficient of static friction between rod and rails is 0.51. What
is the smallest magnetic field (not necessarily vertical) that
would cause the rod to slide?
(a) magnitude and direction
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Chapter 28 Problem 47
A circular coil of 130 turns has a radius of 1.50 cm.
(a) Calculate the current that results in a magnetic dipole moment of 2.30Am2.
(b) Find the maximum torque that the coil, carrying this current, canexperience in a uniform 20.0 mT magnetic field.