periodic trends
DESCRIPTION
Periodic Trends. Atomic Properties. Depend on: Number of protons – attractive nuclear force Number of electrons – shielding effect of electron shells Distance of electrons from nucleus – distance decreases nuclear force. Atomic Properties. Atomic radius. Metallic and covalent radii. - PowerPoint PPT PresentationTRANSCRIPT
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Periodic Trends
Barbara A. Gage PGCC CHM 1010
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Atomic Properties
• Depend on:– Number of protons – attractive nuclear
force– Number of electrons – shielding effect of
electron shells– Distance of electrons from nucleus –
distance decreases nuclear force
Barbara A. Gage PGCC CHM 1010
2
1F
distance
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Atomic Properties
• Atomic radius
Barbara A. Gage PGCC CHM 1010
Metallic and covalent radii.
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Atomic Properties
Click on image above to go to the Periodic Trends excelet
Barbara A. Gage PGCC CHM 1010
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Barbara A. Gage PGCC CHM 1010
SAMPLE PROBLEM 8.3
Ranking Elements by Atomic Size
PLAN:
SOLUTION:
PROBLEM: Using only the periodic table (not Figure 8.15)m rank each set of main group elements in order of decreasing atomic size:
(a) Ca, Mg, Sr
(b) K, Ga, Ca (c) Br, Rb, Kr (d) Sr, Ca, Rb
Elements in the same group increase in size and you go down; elements decrease in size as you go across a period.
(a) Sr > Ca > Mg
These elements are in Group 2A(2).
(b) K > Ca > Ga
These elements are in Period 4.
(c) Rb > Br > Kr
Rb has a higher energy level and is far to the left. Br is to the left of Kr.
(d) Rb > Sr > Ca
Ca is one energy level smaller than Rb and Sr. Rb is to the left of Sr.
Silberberg, Principles of Chemistry
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Atomic Properties
• Ionization energyenergy required to remove an
electron from a neutral, gaseous atom
Cl (g) Cl1+ + e-
K (g) K1+ + e-
Barbara A. Gage PGCC CHM 1010
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Barbara A. Gage PGCC CHM 1010
Figure 8.12 First ionization energies of the main-group elements.
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Barbara A. Gage PGCC CHM 1010
SAMPLE PROBLEM 8.4
Ranking Elements by First Ionization Energy
PLAN:
SOLUTION:
PROBLEM: Using the periodic table only, rank the elements in each of the following sets in order of decreasing IE1:
(a) Kr, He, Ar (b) Sb, Te, Sn (c) K, Ca, Rb (d) I, Xe, Cs
IE decreases as you proceed down in a group; IE increases as you go across a period.
(a) He > Ar > Kr
(b) Te > Sb > Sn
(c) Ca > K > Rb
(d) Xe > I > Cs
Group 8A(18) - IE decreases down a group.
Period 5 elements - IE increases across a period.
Ca is to the right of K; Rb is below K.
I is to the left of Xe; Cs is furtther to the left and down one period.
Silberberg, Principles of Chemistry
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Barbara A. Gage PGCC CHM 1010
Table 8.4
Silberberg, Principles of Chemistry
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Atomic Properties
• Electron affinityenergy change when an electron
is added to a neutral atom to form a negative ion
Cl + e- Cl-
K + e- K1-
Barbara A. Gage PGCC CHM 1010
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Barbara A. Gage PGCC CHM 1010
Figure 8.14 Electron affinities of the main-group elements.
Silberberg, Principles of Chemistry
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Barbara A. Gage PGCC CHM 1010
Figure 8.15 and 8.16
Trends in four atomic properties.
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Ionic Properties
• Ionic radiusradius of the ionic form of an
atom
Barbara A. Gage PGCC CHM 1010
Figure 8.21
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Barbara A. Gage PGCC CHM 1010
Figure 8.22 Ionic vs. atomic radii.
Silberberg, Principles of Chemistry
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Barbara A. Gage PGCC CHM 1010
SAMPLE PROBLEM 8.8
Ranking Ions by Size
PLAN:
SOLUTION:
PROBLEM: Rank each set of ions in order of decreasing size, and explain your ranking:
(a) Ca2+, Sr2+, Mg2+
(b) K+, S2-, Cl - (c) Au+, Au3+
Compare positions in the periodic table, formation of positive and negative ions and changes in size due to gain or loss of electrons.
(a) Sr2+ > Ca2+ > Mg2+
(b) S2- > Cl - > K+
These are members of the same Group (2A/2) and therefore decrease in size going up the group.
The ions are isoelectronic; S2- has the smallest Zeff and therefore is the largest while K+ is a cation with a large Zeff and is the smallest.
(c) Au+ > Au3+
The higher the + charge, the smaller the ion.
Silberberg, Principles of Chemistry