passive low pass and high pass filter

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    Lab 08: Passive First Order LowPass & High Pass Filter

    Experiment 08

    To design R low pass & high pass !lter "ir"#it with "#to$%re#en"' o% ()H*+ also draw a %re#en"' response: ,a-

    magnit#de response ,b- phase response.

    To design RL low pass & high pass !lter "ir"#it with "#to$

    %re#en"' o% ()H*+ also draw a %re#en"' response: ,a-

    magnit#de response ,b- phase response.

    /ntrod#"tion:

    This laboratory studies the use of passive components to create lters to separateportions of time-dependent waveforms. Filters are an essential tool in our complexworld of mixed signals both electronic and otherwise. Passive components(resistors capacitors and inductors! have long served as lter components foreverything from selecting radio stations to ltering out electrical noise.

    E12T/O32L O45ET/6E7"(#! $earn the general lter types" %igh-pass $ow-pass.

    (&! $earn to alter lter type by changing contacts for output voltage.

    ('! $earn phase angle at cuto for simple )* and )$ lters.

    (+! ,esign simple lter.

    (! Freuency response (amplitude and phase!.

    EPER/9E3T2L O45ET/6E7"

    (#! *alculate and measure cuto freuency for series )* and )$ lters.

    (&! ,esign simple )* low-pass / high pass lter.

    ('! ,esign simple )$ low-pass / high pass lter.

    (+! 0ode plots for series lters.

    PREL24"

    Reading"

    (#! 1tudy the 0ac2ground section of this $aboratory.(&! 1tudy textboo2 *hapter #+ (#+.# -#+.+!.

    ;ritten"

    3ote: 4e%ore the starts o% sim#lation ma

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    Lab 08: Passive First Order LowPass & High Pass Filter

    (#!1imulate the circuit shown in Fig (! Fig (3! Fig (4! and Fig (5! in $Tspice and)ecord the simulation result in Table # Table & Table ' and Table +.

    (&!12etch the 0ode Plots of the simulation results recorded in Table # Table &Table ' and Table +.

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    Lab 08: Passive First Order LowPass & High Pass Filter

    E=1/P9E3T 23 92TER/2L7

    ,igital Function 6enerator ,igital 7scilloscope with Probes. 0read 0oard *apacitors 8nductors )esistors

    4a"

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    Lab 08: Passive First Order LowPass & High Pass Filter

    P(c)=Pmax

    2

    Filter; lter is a circuit that is designed to pass signals with desired freuencies andre

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    Lab 08: Passive First Order LowPass & High Pass Filter

    Phase Bode Plot for First-Order Low Pass Filter

    High Pass Filter

    ; high pass lter passes high freuencies and re

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    Lab 08: Passive First Order LowPass & High Pass Filter

    Phase Bode Plot for First-Order High Pass Filter

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    Lab 08: Passive First Order LowPass & High Pass Filter

    esign o% R Low Pass Filter

    The cuto freuency for )* circuit is given below

    c= 1

    RC, fc=

    1

    2RC(1)

    The derivation of equation (1) is given in Appendix A Fig ,(- R

    Low Pass Filter ir"#it

    Let C=10nF ,C=9.08nF(By Capacitance Meter )Put C=9.08n F fc=5KHzEquatin(1)

    510

    2(3)(9.08109)

    R=1

    R=3.5K!

    Ma"e #ure t$at t$e CapacitrRe#i#trf t$i# %a&u#i# a%ai&a'&eLa'( t$er)i#e * t$e

    ca&acu&atin# accr*in+ t$e a%ai&a'&e %a&ue#

    The transfer function of circuit shown in g ('! is

    H()= 1

    1+-RC >>Derivation is given in Appendix A

    Equatin(1 ) c= 1

    RC

    H()= 1

    1+-

    c

    |H()|= 1

    (1 )2+( c)

    2(2)

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    Lab 08: Passive First Order LowPass & High Pass Filter

    =tan1(c)(3)

    .t can 'e #eenequatin# (2 )(3 ) t$at at =0,|H( )|=1=0

    .t can 'e #eenequatin# (2 )(3 ) t$at at =/ ,|H( )|=0=900

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    Lab 08: Passive First Order LowPass & High Pass Filter

    esign o% R High Pass Filter

    The values of ) and * are same as found in)* low pass lter circuit.

    The transfer function of circuit shown in g (3! is

    H()= 1

    1+ 1

    -RC

    (4)

    >>,erivation is given in ;ppendix 0 Fig ,>- R HighPass Filter ir"#it

    Equatin(1 ) c= 1

    RC

    Put RC= 1

    ct$e Equatin(4)

    H()= 1

    1+ 1

    -RC

    = 1

    1-c

    |H()|= 1

    (1 )2+(c)

    2(5)

    =tan1(c)=tan1(c

    )(6)

    .t can 'e #eenequatin# (5 )(6 ) t$at at=0,|H()|=0=900

    .t can 'e #eenequatin# (5 )(6 ) t$at at=/ ,|H( )|=1=00

    C=10nF

    R=3.5K !

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    Lab 08: Passive First Order LowPass & High Pass Filter

    esign o% RL Low Pass ir"#it

    The cuto freuency for )* circuit is given below

    c=R

    L, fc=

    R

    2L(7)

    The derivation of equation (7) is given in Appendix C

    Let L=10mH Fig ,?- RL Low Pass Filter

    ir"#it

    Ma"e #ure t$at t$e in*uctr f t$i# %a&u# i# a%ai&a'&eLa'

    Put L=1mH fc=5KHzt$e Equatin(7)

    R=2 fcL

    R=2 510310103

    R=314.1!

    Ma"e #ure t$at t$e in*uctrre#i#trf t$i#%a&u# i# a%ai&a'&eLa' ( t$er)i#e * t$e

    ca&acu&atin# accr*in+ t$e a%ai&a'&e in*uctr %a&ue

    The transfer function of circuit shown in g ('! is

    H()= 1

    1+-L

    R

    (8) >>Derivation is given in Appendix C

    Equatin(7 ) c=R

    L

    Put L

    R=

    1

    c t$e Equatin(8)

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    Lab 08: Passive First Order LowPass & High Pass Filter

    H()= 1

    1+-

    c

    |H()|= 1

    (1 )2+( c)

    2(9)

    =tan1(c)(10)

    .t can 'e #eenequatin# (9 )(10 ) t$at at =0,|H()|=1=0

    .t can 'e #eenequatin# (9 )(10 ) t$at at =/ ,|H( )|=0=900

    esign o% RL High Pass ir"#it:

    The values of ) and $ is same as foundin )$ low pass lter circuit.

    The transfer function of circuit shown in g (5! is

    Fig ,8- RL High Pass

    Filter ir"#it

    H()= 1

    1+ R

    -L

    (11)

    Equatin(7 ) c=RL

    PutR

    L=ct$e Equatin(11)

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    Lab 08: Passive First Order LowPass & High Pass Filter

    H()= 1

    1+R

    -L

    = 1

    1-c

    |H()|= 1

    (1 )2+(c)

    2(12)

    =tan1(c)=tan1(c

    )(13)

    .t can'e #eenequatin# (12)(13 )t$at at =0,|H( )|=0=900

    .t can'e #eenequatin# (12)(13 )t$at at =/,|H( )|=1=00

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    Lab 08: Passive First Order LowPass & High Pass Filter

    Tas< @ R Low Pass Filter:

    #! 1et up the circuit shown in Fig ,(-. ?se the function generator F6=@ for thesupply voltage vin#: AP-P.

    &! *onnect channels # and & of the oscilloscope to measure As and Aoutsimultaneously.

    '! Aary the freuency from :: %B to #: 2%B in steps indicated in Table # andrecord the indicated value. Cith each freuency change ma2e sure that Ain isstill #:App.

    a! ?sing the data of Table # s2etch a 0ode plots of the of the lterDs output

    voltage.

    Tas< A R High Pass Filter:

    )epeat the Tas2 # for the circuit shown in Fig (3! and record your result in Table

    &

    Tas< B RL Low Pass Filter:

    )epeat the Tas2 # for the circuit shown in Fig (4! and record your result in Table

    '

    Tas< C RL High Pass Filter:

    )epeat the Tas2 # for the circuit shown in Fig (5! and record your result in Table

    +

    Post Lab:

    #! Chy are capacitors preferred over inductors in lter designE&! *reate 0ode plots of the magnitude transfer functions of your low-pass and

    high-pass lters. The theoretical plots (using measured values of resistorsand capacitors! should be drawn as lines. 8nclude your data (ta2en at #>#:

    # & and #: times the cuto freuency! as points.'! *ompare the measured results and simulation results.

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    Lab 08: Passive First Order LowPass & High Pass Filter

    al"#lated Res#lts:

    Tas< @: Passive R Low Pass Filter

    Fre#en"'

    ,)HD-(ra* /#) |H()|= 1

    (1 )2+ 2

    H()=20 log0

    0(*B) =tan1(c)

    :.:#fcG

    :.#f*G

    :.fc G

    fc G

    &fc G

    +fc G3fc G

    5fc G

    #:fc G

    #::fc G

    Table @ ,R Low Pass Filter-

    Tas< A: Passive R High Pass Filter

    Fre#en"',)HD- (ra* /#) |H()|= 1

    (1 )2+c

    2 H()=20 log0

    0(*B) =tan1(

    c)

    :.:#fcG

    :.#f*G

    :.fc G

    fc G

    &fc G

    +fc G

    3fc G

    5fc G

    #:fc G

    #::fc G

    Table A ,R High Pass Filter-

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    Lab 08: Passive First Order LowPass & High Pass Filter

    al"#lated Res#lts:

    Tas< B: Passive RL Low Pass Filter

    Fre#en"'

    ,)HD-(ra* /#) |H()|= 1

    (1 )2+ 2

    H()=20 log0

    0(*B) =tan1(c)

    :.:#fcG

    :.#f*G

    :.fc G

    fc G

    &fc G

    +fc G3fc G

    5fc G

    #:fc G

    #::fc G

    Table B ,RL Low Pass Filter-

    Tas< C: Passive RL High Pass Filter

    Fre#en"'

    ,)HD-(ra* /#) |H()|= 1

    (1 )2+c

    2H()=20 log

    0

    0(*B) =tan1( c)

    :.:#fcG

    :.#f*G

    :.fc G

    fc G

    &fc G

    +fc G

    3fc G

    5fc G

    #:fc G

    #::fc G

    Table C ,RL High Pass Filter-

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    Lab 08: Passive First Order LowPass & High Pass Filter

    7e"tion C 9eas#rement Tables

    @ame" HHHHHHHHHHHHHHHHHHHHHHHHHH )eg. @oHHHHHHHHHHHHHHHHHHHHHHH

    Tas< @: Passive R Low Pass FilterAin (p-p! G #: AP-P

    Fre#en"'

    ,)HD-(ra* /#) 6o#t,PP- H()=

    0

    0H()=20 log

    0

    0(*B) (*e+ree#)

    :.:#fcG

    :.#f*G

    :.fc Gfc G

    &fc G

    +fc G

    3fc G

    5fc G

    #:fc G

    #::fc G

    Table @ ,R Low Pass Filter-

    Tas< A: Passive R High Pass FilterAin (p-p! G #: AP-P

    Fre#en"'

    ,)HD-(ra* /#) 6o#t,PP- H()=

    0

    0H()=20 log

    0

    0(*B) (*e+ree#)

    :.:#fcG

    :.#f*G

    :.fc G

    fc G

    &fc G+fc G

    3fc G

    5fc G

    #:fc G

    #::fc G

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    Lab 08: Passive First Order LowPass & High Pass Filter

    Table A ,R High Pass Filter-

    7e"tion C 9eas#rement Tables

    @ame" HHHHHHHHHHHHHHHHHHHHHHHHHH )eg. @o

    HHHHHHHHHHHHHHHHHHHHHHH

    Tas< B: Passive RL Low Pass FilterAin (p-p! G #: AP-P

    Fre#en"'

    ,)HD-(ra* /#) 6o#t,PP- H()=

    0

    0H()=20 log

    0

    0(*B) (*e+ree#)

    :.:#fcG

    :.#f*G:.fc G

    fc G

    &fc G

    +fc G

    3fc G

    5fc G

    #:fc G

    #::fc G

    Table B ,RL Low Pass Filter-Tas< C: Passive RL High Pass Filter

    Ain (p-p! G #: AP-P

    Fre#en"'

    ,)HD-(ra* /#) 6o#t,PP- H()=

    0

    0H()=20 log

    0

    0(*B) (*e+ree#)

    :.:#fcG

    :.#f*G

    :.fc G

    fc G&fc G

    +fc G

    3fc G

    5fc G

    #:fc G

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    Lab 08: Passive First Order LowPass & High Pass Filter

    #::fc GTable C ,RL High Pass Filter-

    3ame: Reg. 3o

    4ode Plot %or R Low Pass Filter:

    agnit#de

    4-

    IType a uote from the

    document or the summary of

    an interesting point. Jou can

    position the text box anywhere

    in the document. ?se the

    ,rawing Tools tab to changethe formatting of the pull

    uote text box.K

    Fre#en"'

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    Lab 08: Passive First Order LowPass & High Pass Filter

    3ame: Reg. 3o

    4ode Plot %or R High Pass Filter:

    ase

    egree-

    e#en"'

    agnit#de

    4-

    IType a uote from thedocument or the summary of

    an interesting point. Jou can

    position the text box anywhere

    in the document. ?se the

    ,rawing Tools tab to change

    the formatting of the pull

    uote text box.K

    Fre#en"'

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    Lab 08: Passive First Order LowPass & High Pass Filter

    3ame: Reg. 3o

    4ode Plot %or RL Low Pass Filter:

    ase

    egree-

    e#en"'

    agnit#de

    4-

    IType a uote from the

    document or the summary of

    an interesting point. Jou can

    position the text box anywhere

    in the document. ?se the

    ,rawing Tools tab to change

    the formatting of the pull

    uote text box.K

    Fre#en"'

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    Lab 08: Passive First Order LowPass & High Pass Filter

    3ame: Reg. 3o

    4ode Plot %or RL High Pass Filter:

    ase

    egree-

    e#en"'

    agnit#de

    4-

    IType a uote from the

    document or the summary of

    an interesting point. Jou can

    position the text box anywhere

    in the document. ?se the

    ,rawing Tools tab to change

    the formatting of the pull

    uote text box.K

    Fre#en"'

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    Lab 08: Passive First Order LowPass & High Pass Filter

    2ppendix 2 ,R Low Pass Filter-

    From the circuit diagram0

    is given by0=

    1

    -C

    R+ 1

    -C

    0

    0

    0=

    1

    1+-RC

    ;s we 2now that0

    0=H()

    H()= 1

    1+-RC(1)

    ase

    egree-

    e#en"'

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    Lab 08: Passive First Order LowPass & High Pass Filter

    |H()|= 11+(RC)

    ;t = c

    |H()| G :.4:4 1

    0.707= 1

    1+(cRC)

    0.7072=

    1

    1+(cRC)2

    0.5= 1

    1+(cRC)2

    0.5+0.5 (cRC)2=1

    0.5 (cRC)2=10.5

    (cRC)2=

    0.5

    0.5

    (cRC)2=1

    c2=

    1

    (RC)2

    c= 1

    RC(2)

    fc= 1

    2 RC

    2ppendix 4 ,R High Pass Filter-

    From the circuit diagram0

    is given by

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    Lab 08: Passive First Order LowPass & High Pass Filter

    0= R

    R+ 1

    -C

    0

    0

    0=

    1

    1+ 1

    -RC

    ;s we 2now that0

    0=H()

    H()= 11+

    1

    -RC

    (5)

    |H()|= 1

    1+ 1

    (RC)

    ;t = c

    |H()| G :.4:4

    1+ 1

    ( c RC)

    0.707=1

    1uaring both sides

    1+ 1

    ( c RC)

    0.7072=1

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    Lab 08: Passive First Order LowPass & High Pass Filter

    1+ 1

    ( c RC)

    0.5=1

    ( c RC)

    1+1

    0.5

    ( c RC)2=1

    0.5+0.5

    ( c RC)2=10.50.5

    (cRC)2=

    0.5

    0.5

    (cRC)2=1

    c2=

    1

    (RC)2

    c= 1

    RC

    fc= 1

    2 RC

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    Lab 08: Passive First Order LowPass & High Pass Filter

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    Lab 08: Passive First Order LowPass & High Pass Filter

    2ppendix ,RL Low Pass Filter-

    From the circuit diagram 0 is given by

    0= R

    R+-L0

    0

    0=

    R

    R(1+-L

    R )

    ;s we 2now that

    0

    0=H()

    H()= 1

    1+ -LR

    |H( )|= 1

    1+(L

    R)

    ;t = c

    |H()| G :.4:4

    0.707= 1

    1+(cL

    R)

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    Lab 08: Passive First Order LowPass & High Pass Filter

    0.7072=

    1

    1+

    (

    cL

    R

    )

    2

    0.5= 1

    1+( cLR)2

    0.5+0.5( cLR)2

    =1

    0.5( cLR)2

    =10.5

    ( cLR)2

    =0.5

    0.5

    (cL

    R)2

    =1

    c2=

    R2

    L2

    c=R

    L

    f= R2L

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    Lab 08: Passive First Order LowPass & High Pass Filter

    2ppendix ,RL High Pass Filter-

    From the circuit diagram0

    is given by

    0= -L

    R+-L0

    0

    0

    =-L

    -L( R-L+1)

    ;s we 2now that

    0

    0=H()

    H()= 1

    1+

    R

    -L

    |H( )|= 1

    1+( R

    L )

    ;t = c

    |H()| G :.4:4

    0.707= 1

    1+( R

    cL )

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    Lab 08: Passive First Order LowPass & High Pass Filter

    0.7072=

    1

    1+

    (

    R

    cL

    )

    2

    0.5= 1

    1+( RcL )2

    0.5+0.5

    ( R

    cL

    )

    2

    =1

    0.5( RcL )2

    =10.5

    ( RcL )2

    =0.5

    0.5

    ( RcL )

    2=1

    c2=

    R2

    L2

    c=R

    L

    f= R

    2L