parallel and perpendicular lines

13
Parallel and Perpendicular Lines

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Page 1: Parallel and perpendicular lines

Parallel and Perpendicular Lines

Page 2: Parallel and perpendicular lines

Parallel Lines

Two lines with the same slope are said to be parallel lines. If you graph them they will never intersect.

We can decide algebraically if two lines are parallel by finding the slope of each line and seeing if the slopes are equal to each other.

We can find the equation of a line parallel to a given line and going through a given point by:

a.) first finding the slope m of the given line; b.) finding the equation of the line through the given point with slope m.

Page 3: Parallel and perpendicular lines

Testing if Lines are Parallel

Are the lines parallel?

12 3 9 and -8 2 14x y x y

Find the slope of 12 3 9

3 12 9

4 3

x y

y x

y x

The slope m = -4

Find the slope of 8 2 14

2 8 14

4 7

x y

y x

y x

The slope m = -4

Since the slopes are equal the lines are parallel.

Page 4: Parallel and perpendicular lines

Graphs of Parallel Lines

The red line is the graph of y = – 4x – 3 and the blue line is the graph ofy = – 4x – 7

Page 5: Parallel and perpendicular lines

Practice Testing if Lines are Parallel

Are the lines 6 3 5 and 2 4 4x y y x parallel? (click mouse for answer)

6 3 5

3 6 5

52 32

x y

y x

y x

m

2 4 4

2 2

2

y x

y x

m

Since the slopes are differentthe lines are not parallel.

Are the lines 2 4 and 2 4 12x y x y parallel? (click mouse for answer)

2 4

2 4

1 221

2

x y

y x

y x

m

2 4 12

4 2 12

1 321

2

x y

y x

y x

m

Since the slopes are equalthe lines are parallel.

Page 6: Parallel and perpendicular lines

Constructing Parallel Lines

Find the equation of a line going through the point (3, -5) and parallel to 2 83y x

Using the point-slope equation where the slope m = -2/3 and

the point is (3, -5) we get 25 33

25 232 33

y x

y x

y x

Page 7: Parallel and perpendicular lines

Practice Constructing Parallel Lines

Find the equation of the line going through the point (4,1) and parallel to (click mouse for answer) 3 7y x

1 3 4

1 3 12

3 13

y x

y x

y x

Find the equation of the line going through the point (-2,7) and parallel to (click mouse for answer) 2 8x y

7 2 2

7 2 2

7 2 4

2 3

y x

y x

y x

y x

Page 8: Parallel and perpendicular lines

Perpendicular Lines

Perpendicular lines are lines that intersect in a right angle. We can decide algebraically if two lines are perpendicular by

finding the slope of each line and seeing if the slopes are negative reciprocals of each other. This is equivalent to multiplying the two slopes together and seeing if their product is –1.

We can find the equation of a line perpendicular to a given line and going through a given point by:

a.) first finding the slope m of the given line;

b.) finding the equation of the line through the given point

with slope = –1 /m.

Page 9: Parallel and perpendicular lines

Testing if Lines Are Perpendicular

1Are the lines 2 5 and 4 perpendicular?

2x y y x

Find the slope of 2 5 2

2 5

x y m

y x

1 1Find the slope of 4

2 2y x m

Since the slopes are negative reciprocals of each other the lines are perpendicular. 1

2 12

Page 10: Parallel and perpendicular lines

Graphs of Perpendicular Lines

The red line is the graph of y = – 2x + 5 and the blue line is the graph ofy = – 1/2 x +4

Page 11: Parallel and perpendicular lines

Practice Testing if Lines Are Perpendicular

Are the lines 6 3 5 and 2 4 4 perpendicular?x y y x 6 3 5

3 6 5

52 32

x y

y x

y x

m

2 4 4

2 2

2

y x

y x

m

Since the slopes are not negative reciprocals of each other (their product is not -1) the lines are not perpendicular

Are the lines 2 4 and 4 2 6 perpendicular?x y x y 2 4

2 4

1 221

2

x y

y x

y x

m

4 2 6

2 4 6

2 3

2

x y

y x

y x

m

Since the slopes are negative reciprocals of each other (their product is -1) the lines are perpendicular.

Page 12: Parallel and perpendicular lines

Constructing Perpendicular Lines

Find the equation of a line going through the point (3, -5) and perpendicular to 2 83y x

The slope of the perpendicular line will be m = 3/2 Using

the point-slope equation where the slope m = 3/2 and

the point is (3, -5) we get 35 323 95 2 2

3 192 2

y x

y x

y x

Page 13: Parallel and perpendicular lines

Practice Constructing Perpendicular Lines

Find the equation of the line going through the point (4,1) and perpendicular to (click mouse for answer) 3 7y x

11 431 41 3 31 1

3 3

y x

y x

y x

Find the equation of the line going through the point (-2,7) and perpendicular to (click mouse for answer) 2 8x y

17 2217 2217 121 82

y x

y x

y x

y x