pansystem manual test cases_consolidated 07 jan 2013 (infosys qa)

SUMMARY

WorkFlows No of Test Cases No of Test StepsInterference 1 53

GasWell 10 214Pan-WellFlo 2 10

Decon 1 38PDA 2 40

Fractured 2 72General 4 130

OWD 1 76Ex 1 2 71Ex 2 1 42Ex 3 6 99Ex 4 5 66Ex 5 2 47Ex 6 1 43Ex 7 1 70Ex 8 1 64Ex 9 2 43

Ex 10 1 44Ex 11 1 66Ex 12 1 22Ex 13 4 107Ex 14 1 40Ex 15 2 95Ex 16 1 30Ex 17 1 69Ex 18 1 37Total 57 1688

SUMMARY

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11 0 0 00 0 0 00 0 0 00 0 0 00 0 0 00 0 0 00 0 0 00 0 0 00 0 0 00 0 0 00 0 0 00 0 0 00 0 0 0

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S. No Test Name Test Case Number Step Name Step1 Fluid Type 1

Well Orientation 2

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Layer Parameters 8

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Interference Test Design

Interference Test Design1.panx

Cration of Observer well

Producer Well properties

Observer Well properties

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Interference Test Design 1a_simulation.panx

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Interference Test Design 1b.panx

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Test Description (Action)Open Interference Test Design1.panx. Go to Data Preparation> Well, reservoir & fluid description. Click on Analytical Model.Under Fluid Control, Fluid Type should be Oil.

Under Well Control tab, Principal Well orientation should be vertical.

Under Well Control tab, Click on Add well.Enter "Observer" as the new well name on the Add New Well window.Click OK.

Select the" P-Well1;Active" well and rename the Well Name as Producer. Click on Well parameters…Enter the Wellbore Radius as 0.3 ft

Click on Wellbore Storage Model Parameters… and enter 0.01 as Wellbore Storage.Click OK. Under Well Parameters-Producer window click OK.

Select the" Observer;Active" well and click on Well parameters…Enter the Wellbore Radius as 0.3 ft.Enter 2500 as the Y Position.

Click on Wellbore Storage Model Parameters… and enter 0.01 as Wellbore Storage.Click OK. Under Well Parameters-Observer window click OK.

Under Layer Control tab, click on Layer parameters….Enter the following information: Formation Thickness: 25 ft; Porosity = 0.2; Layer Pressure = 4000 psia; Layer Temperature = 200 degF

Radial homogeneous should be selected as the Reservoir Model. Click on Model parameters…Under Reservoir Model Parameters tab , enter 250 md as the Radial Permeability and 5 as the Skin.

Under Offset Well Completions tab, enter 0 as the Skin for Well2. Click OK. On the Layer parameters - Layer 1 Interpretation 1 dialogue Click OK.

Under Layer Control tab, click on Layer Fluid parameters….Enter the following information: Bo = 1.3; Uo = 2.5 cp; Ct = 1e-05 (psi-1). Click OK.Under Well, Reservoir & Fluid Description window click Ok to return to the main screen.

Click on Data Preparation > Test Design > Edit Test Design.

On the Select Well screen that appears, select Producer on the drop down menu. Click OK.

Under the Edit Test Design, enter the following information: Row 1: Time = 400; Oil Flow Rate = 1000 STB/day; No. OF Steps = 200; Format = 2;Row 2: Time = 1000; Oil Flow Rate = 0 STB/day; No. OF Steps = 200; Format = 2. Click OK.

Under the Test Design dialogue, Initial Wellbore Pressure should be 4000 psia. Click OK .

A plot should appear. Under the Navigation Pane a new data set appears for the Producer well called TEST DESIGN: Test rate.Click on Data grid.

Under Data View window, make sure the values are correct as per the Expected Results. Click OK.

Click on Data Preparation > Test Design > Edit Test Design. Import the data to the Interference Test Design1.panx file which should be already selected. Click OK.

On the Select Well screen that appears, select Observer on the drop down menu. Click OK.

Click NO to the "Do you wish to use the principal well times?" Confirm dialogue.

Under the Test Design dialogue, Initial Wellbore Pressure should be 4000 psia. Click OK .

Under the Edit TEST DESIGN, enter the following information: Row 1: Time = 400; Test Rate = 0 STB/day; Row 2: Time = 1000; Oil Flow Rate = 0 STB/day; . Click OK.

A plot should appear. Under the Navigation Pane a new data set appears for the Observer well called TEST DESIGN: Test rate.Click on Data grid.


Select Simulation > Analytical simulation > Advanced Simulation. Select OK on the Advanced Simulation Control dialogue.

Test Overview plot shows up on screen

A dialogue should appear showing the calculating steps. Click OK.

Double click on TEST DESIGN: Sim P data set on the Navigation Pane.

Click on Data grid.


Click on Analysis. Analysis Selection dialogue appears.Select Radio button for Producer . Click OK.

Click on Data grid.


Open Interference Test Design 1a_simulation.panx Click OK.Go to Analysis > Conventional Analysis > Log-Log.

Click on Data grid.

Open Interference Test Design 1b.panx.

Test Overview plot shows up on screen


Double click on SIMULATED: Sim P data set on the Navigation Pane.

Click on Data grid.


On the Navigation Pane, remove the SIMULATED: Sim Q Total by going into the Navigation Pane, right clicking on it and selecting Remove column from workspace. Click YES to the " Are you sure you want to remove this Column?" Remove dialogue.

On the Navigation Pane, remove the SIMULATED: Sim Q#1 by going into the Navigation Pane, right clicking on it and selecting Remove column from workspace. Click YES to the " Are you sure you want to remove this Column?" Remove dialogue.

Click on Analysis.On the Analysis Selection Dialogue that appears, Observer radio button should be selected.Click OK

Click on Data grid.

Go to Analysis > Conventional Analysis > Type Curves

Go to Analysis> Tools. Click Type curve match

Close the application


Click on Data grid.


Type Curve Method : Default and Type Curve Starting Stage :Interference test (const rate drawdown/inj'n) should be highlighted. Default Type Curves radio button should be selected.Click OK.

Click Type curve match. In the Verify Selected Nearest Curve window, Nearest curve should be : 1. Click OK.

Expected Results StatusOil radio button should be selected.

Principal Well orientation, Vertical/Slanted button radio should be selected.

A new well data set should be created on the Navigation pane called Observer

The Well1 name should change to Producer on the Navigation Pane

Grid should contain 400 rows and 4 columns .Row 1;Time Hours=0.00100000004749745;TEST DESIGN:Test Rate=1000;Time (Hours)=0;TEST DESIGN:Rate Schedule=0Row 200;Time Hours=400;TEST DESIGN:Test Rate=1000;Time (Hours)=0;TEST DESIGN:Rate Schedule=0Row 400;Time Hours=1000;TEST DESIGN:Test Rate=0;Time (Hours)=0;TEST DESIGN:Rate Schedule=0

Grid should contain 2 rows and 4 columns .Row 1;Time (Hours)=400;TEST DESIGN:Test Rate=0;Time (Hours)=0;TEST DESIGN:Rate Schedule=0Row 2;Time (Hours)=1000;TEST DESIGN:Test Rate=0;Time (Hours)=0;TEST DESIGN:Rate Schedule=0

Verify by reading the Plot title: Test Overview Plot

On the Navigation Pane, 3 different data sets are created for each the Producer and Observer wells. For the Producer, they are called TEST DESIGN: Sim P; TEST DESIGN: Sim Q Total; TEST DESIGN: Sim Q#1.For the Observer, they are called SIMULATED:Sim P; Simulated Sim Q Total; SIMULATED: Sim Q#1.

A plot should appear. Verify by reading the Plot title: Data Edit Plot

Grid should have 400 rows and 4 columns.Row 1: Time Hours = 0.00100000004749745; Sim P = 3994.6333889282; Time Hours = 0; Rate Schedule = 0;Row 2: Time Hours = 0.0010669672170036; Sim P = 3994.27425324749; Time Hours = 0; Rate Schedule = 1000;Row 3: Time Hours = 0.0011384189880884; Sim P = 3993.8913398121; Time Hours = 400; Rate Schedule = 1000;Row 200 : Time Hours = 400; Sim P = 2946.5868959281; Time Hours = 0; Rate Schedule = 0;Row 400 : Time Hours = 1000; Sim P = 3981.23701022201; Time Hours = 0; Rate Schedule = 0.

Test Overview appears on Navigation Pane: TEST DESIGN:Sim P

Grid should contain 400 rows and 5 columns .Row 1;Time (Hours)=0.00100000004749745;TEST DESIGN:Test Rate=1000;TEST DESIGN:Sim P=3994.6333889282;Time (Hours)=0;TEST DESIGN:Rate Schedule=0Row 2; Row 200;Time (Hours)=400;TEST DESIGN:Test Rate=1000;TEST DESIGN:Sim P=2946.5868959281;Time (Hours)=0;TEST DESIGN:Rate Schedule=0Row 400;Time (Hours)=1000;TEST DESIGN:Test Rate=0;TEST DESIGN:Sim P=3981.23701022201;Time (Hours)=0;TEST DESIGN:Rate Schedule=0

A log -log plot shows up.On the Navigation Pane a new data set called Log-Log:TP2 is created.Verify by reading the Plot title: Log-Log Plot

Verify by reading the Plot titile: Test Overview Plot

Grid should contain 200 rows and 4 columns .Row 1;Elapsed Time (hours) - Tp=400.0000=0.00100000004749745;Sim P:TP2=5.36651642087145;Elapsed Time (hours) - Tp=400.0000=0.00106914339295372;Sim P Deriv:TP2=5.73555556803877Row 100;Elapsed Time (hours) - Tp=400.0000=0.749130824896724;Sim P:TP2=796.083450367417;Elapsed Time (hours) - Tp=400.0000=0.80092823383842;Sim P Deriv:TP2=77.7862695624575Row 200;Elapsed Time (hours) - Tp=400.0000=600;Sim P:TP2=1034.65065882994;Elapsed Time (hours) - Tp=400.0000=0;Sim P Deriv:TP2=0A plot should appear. Verify by reading the Plot title: Data Edit Plot

Grid should contain 400 rows and 2 columns .Row 1;Time (Hours)=0.00100000004749745;SIMULATED:Sim P=4000Row 200;Time (Hours)=400;SIMULATED:Sim P=3966.43255958282Row 400;Time (Hours)=1000;SIMULATED:Sim P=3983.92715277401The SIMULATED:Sim Q Total should be removed from the Navigation Pane

The SIMULATED:Sim Q#1 should be removed from the Navigation Pane

Test Overview appears on Navigation Pane: Test Overview:Sim P

Select Type Curve window will appearA set of type curves will show up.

Grid should contain 400 rows and 4 columns .Row 1;Time (Hours)=0.00100000004749745;SIMULATED:Sim P=4000;Time (Hours)=0.001;SIMULATED:Rate Schedule=0Row 200;Time (Hours)=400;SIMULATED:Sim P=3966.43255958282;Time (Hours)=0;SIMULATED:Rate Schedule=0Row 400;Time (Hours)=1000;SIMULATED:Sim P=3983.92715277401;Time (Hours)=0;SIMULATED:Rate Schedule=0

A type curve plot shows up. On the Navigation Pane a new data set called Type Curve Type Curve: TP1 is created.Verify by reading the Plot titile: Type Curve Plot

Grid should contain 55 rows and 4 columns .Row 1;Elapsed Time (hours)=12.0744413901108;Sim P:TP1=0.000137223398724018;Elapsed Time (hours)=12.8830994821347;Sim P Deriv=0.0037598519224448Row 28;Elapsed Time (hours)=69.4984716242095;Sim P:TP1=2.70144681888041;Elapsed Time (hours)=74.1526542999936;Sim P Deriv=7.41477395530473Row 55;Elapsed Time (hours)=399.999;Sim P:TP1=33.5674404171764;Elapsed Time (hours)=0;Sim P Deriv=0

Match ResultsModel 1Radial homogeneousInfinitely actingTypecurve0Ct k kh

S. No Test Name Test Case Number Step Name Step1 Ex 7.1.panx 1

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Gas Well Testing

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Ex 7.1.1.panx Continuation 2425

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2 Ex 7.2.panx 1

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Gas Rate Dependent Skin Analysis Flow

After Flow

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910

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4 Gas Deliverability.panx IPR Flow After Flow 1

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Gas Deliverability

Analysis

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Gas Deliverability_1.panx

LIT Analysis Flow After Flow

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C & n Analysis Flow After Flow

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Gas Deliverability3.panx

Gas Rate Dependent Skin Analysis

Isochronal Test

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LIT Analysis Isochronal

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C & n Analysis Isochronal

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Test Description (Action)

Click on Data Grid

Click Calculate All.

Click OK .

Open Ex 7.1.panx. Click on TESTC-Pressure 1 in the Workspace window


Go to Data Preparation > Well, reservoir & Fluid description. Click Analytical model.

In Well, Reservoir & Fluid control Description> Fluid Control tab, check that Fluid type is Gas.

In Well, Reservoir & Fluid control Description> Well Control tab, check that Principal Well Orientation is Vertical.Click Well Parameters. In Well Parameters window enter Wellbore Radius = 0.4 ft .Wellbore Storage Model should be Classic Wellbore storage. Click OK.

In Well, Reservoir & Fluid control Description> Layer Control tab, click Layer parameters. Enter: Formation thickness = 16 ft; Porosity= 0.2, Layer Pressure = 7148 psia, Layer Temperature = 283 deg F, Water saturation = 0.45. Gas Saturation should be 0.55 and Rock Compressibility = 0.0000e+000. Reservoir model = Radial homogeneous. Click OK.

In Well, Reservoir & Fluid control Description> Layer Control tab, click Layer Fluid parameters. Check "Use EOS". Click on "Gas Composition..." button.

Enter the following gas composition: Methane = 76.8, Ethane = 8.82, Propane = 3.2, n-butane = 1.14, Iso- butane = 0.49, n-pentane = 0.57, iso-pentane = 0.42, Hexanes = 0.74, C7+ = 5.11, CO2 = 1.54, Nitrogen = 1.17, H2S = 0 . Then Click Calculate.

Click OK to return to the " Gas Fluid Parameters -Layer 1" window.

Click "Pseudo tables…" button on "Gas Fluid Parameters - Layer 1" window.

Click OK on the message box.

Close the plot.

Close the plot.

Click Calculate in "Gas Fluid Parameters - Layer 1"..

Open Ex 7.1.1.panx file.Go to Analysis >> Conventional Analysis >> Log-Log

Click on Data Grid

On "Pseudo Table Editing - Layer 1" window, select P/Viscosity/Z Table. Click Plot

On "Pseudo Table Editing - Layer 1" window, select Viscosity/ Ct Table. Click Plot

On "Pseudo Table Editing - Layer 1" window, select m(p) Table . Click Plot

Close the plot.Click OK on the "Pseudo Table Editing - Layer 1".

Click OK to return to Well, Reservoir & Fluid Description window. Then Click OK.

Go to Analysis >> Conventional Analysis >> Test Overview.


Click Analysis >> Tools >> Unit slope. On the "Define Line" message, Wellbore Storage radio button should be already selected. Click OK.

Click Analysis >> Conventional Analysis >> Semi-Log.

Click on Data Grid

Click OK on the "Define Line" message box.

Click on Data Grid

Click Analysis >> Tools >> Zero Slope. On the "Define Line" message, Radial flow radio button should be already selected. Click OK.


Click Analysis >> Tools >> Fit line of known slope. On the "Known Line" dialogue, enter -382.95 as the Line Slope. Click OK.

Go to Analysis >> Tools >> Confirm Results. Click Ok on Confirm Results message box.

Open Ex 7.2.panx. Go to Analysis >> Conventional Analysis >> Log-Log.


Click on Data Grid

Go to Analysis >> Tools >> Auto match point selection

Go to Analysis >> Tools >> Best fit line


Click Analysis >> Tools >> Zero Slope. On the "Define Line" message, Radial flow radio button should be already selected. Click OK.


On "Global Point Selection" dialogue, enter 2 on Maximum Required number of points.Click OK.

Click OK.

Open Ex 7.3.panx.


Go to Analysis >> Tools >> Confirm Results. Click Ok on Confirm Results message box.

Go to Analysis >> Skin Analysis >> Rate-Dependent Skin Analysis.

Click Analysis >> Tools >> Fit line of known slope. On the "Known Line" dialogue, enter 20.28665 as the Line Slope. Click OK.


Click on Analysis >> Tools >> Fit parallel lines

Click OK on the "Define Line" message box.Click on Analysis >> Analysis Tools >> Fit parallel lines

Click OK on the "Define Line" message box.Click on Analysis >> Analysis Tools >> Fit parallel lines

Click OK on the "Define Line" message box.Click on Analysis >> Tools >> Confirm ResultsClick OK on the "Confirm Results" messageGo to Analysis >> Skin analysis >> Skin vs Flow Rate

Click on Data Grid


Click on Analysis >> Tools >> Confirm ResultsClick OK on the "Confirm Results" message



Click on Analysis >> Skin Analysis >> Correct for Rate Dependency.

Click OK on "Correct for Rate Dependency" dialogue. Go to Analysis >> Conventional Analysis >> Semi-Log

Go to Analysis >> Workflow >> Test Overview

Go to Deliverability >> IPR >> Calculate IPR

Click on Data Grid

Go to Simulation >> Analytical simulation >> Quick Match

On the Quick Match dialogue. Click Calculate and then OK/Confirm.

Open Gas Deliverability.panx. Go to Analysis > Workflow > Test Overview

On "Transient Welltest & LIT Results"dialogue, click on Calculate.

Click OK. Click on Quick Match Results tab on Navigation Pane.


Click on Data Grid

Click OK.

Click OK.

Click on Data Grid

Click OK.

Click OK. Go to Deliverability >> IPR >> IPR Trans/Log-Log


Open Gas Deliverability_1.panx. Go to Deliverability >> Gas Deliverability >> LIT.


Click Deliverability >> Gas Deliverability >> Fit line of known slope. On the "Known Line" dialogue, enter 5.67 as the Line Slope. Click OK.

Click on Data Grid

Click on >> Deliverability >> Gas Deliverabiltity >> Confirm Results. Click OK. Go to Deliverability >> IPR >> Calculate IPR.


Click OK. Go to Deliverability >> IPR >> IPR-LIT/Linear IPR


Click OK. Go to Deliverability >> IPR >> IPR -LIT/Log-Log

Click on Data GridUnder Data View window, make sure the values are correct as per the Expected Results. Click OK.

Go to Deliverability >> IPR >> IPR -Both/Linear


Click on Data Grid

Click OK.

Click OK.

Click on Data Grid

Click OK. Go to Deliverability >> IPR >> IPR -Both/Log-Log


Open Gas Deliverability_2.panx. Go to Deliverability >> Gas Deliverability >> C+n.

Click OK.

On "C & n Results"dialogue, click on Calculate.

Click on Data Grid




Click OK. Go to Deliverability >> IPR >> IPR-Exrt/Linear IPR

Click OK. Go to Deliverability >> IPR >> IPR -Ext/Log-Log

Click on Data Grid



Click OK. Go to Deliverability >> IPR >> IPR -Stab/Linear

Click on Data Grid

Click OK. Go to Deliverability >> IPR >> IPR -Stab/Log-Log

Click on Data Grid


Click OK. Go to Deliverability >> IPR >> IPR -Both/Linear

Click on Data Grid



Click on Data Grid

Click OK.



Open Gas Deliverability_3.panx. Go to Analysis > Conventional Analysis >> Semi-Log.

Go to Analysis >> Skin Analysis >> Rate-Dependent Skin Analysis.


Click on Analysis >> Tools >> Fit parallel lines

Click OK on the "Define Line" message box.Click on Analysis >> Tools >> Fit parallel lines

Click OK on the "Define Line" message box.Click on Analysis >> Tools >> Confirm ResultsClick OK on the "Confirm Results" messageGo to Analysis >> Skin analysis>> Skin vs Flow Rate

Click on Data Grid


Click on Analysis >> Tools >> Confirm ResultsClick OK on the "Confirm Results" message




Click on Analysis >> Skin analysis >> Correct for Rate Dependency.

Click OK on "Correct for Rate Dependency" dialogue. Go to Analysis >> Conventional Analysis >> Semi-Log

Go to Analysis >> Workflow >> Test Overview

Click OK.

Open Gas Deliverability_4.panx.


Click on Data Grid

Go to Simulation >> Analytical simulation >> Quick Match

On the Quick Match dialogue. Click Calculate and then OK/Confirm.


Click OK. Click on the Quick Match Results tab on the Navigation Pane.

Click on Data Grid

Click OK.

Click OK.


Click OK. Go to Deliverability >> IPR >> IPR Trans/Log-Log


Open Gas Deliverability_5.panx. Go to Deliverability >> Gas Deliverability >> LIT.

Click on Data Grid

Click OK.



Click OK. Click Deliverability >> Gas Deliverability >> Fit parallel lines.





Click on Data Grid

Click OK. Go to Deliverability >> IPR >> IPR -LIT/Log-Log

Click on Data Grid

Click OK. Go to Deliverability >> IPR >> IPR-LIT/Linear IPR


Go to Deliverability >> IPR >> IPR -Both/Linear

Click on Data Grid


Click on Data Grid



Click OK.

Click OK.

Click on Data Grid

Click OK.


Open Gas Deliverability_5.panx. Go to Deliverability >> Gas Deliverability >> C+n.



Click Deliverability >> Gas Deliverability >> Fit parallel lines.


On "C & n Results"dialogue, click on Calculate.

Click on Data Grid

Click OK. Go to Deliverability >> IPR >> IPR-Exrt/Linear IPR


Click OK. Go to Deliverability >> IPR >> IPR -Ext/Log-Log

Click on Data Grid

Click OK. Go to Deliverability >> IPR >> IPR -Stab/Linear

Click on Data Grid


Click OK. Go to Deliverability >> IPR >> IPR -Stab/Log-Log

Click on Data Grid



Click OK. Go to Deliverability >> IPR >> IPR -Both/Linear


Click on Data Grid



Expected Results StatusThe pressure and rate history plot will show.

Gas Composition window will pop up

Gas gravity is calculated and should be 0.85634087

" Pseudo Table Editing -Layer-1" window will pop up

Grid should contain 431 rows and 4 columns .Row 1;Time (Hours)=5.3667;TESTC:Pressure 1=7147.54;Time (Hours)=5.6667;TESTC:Rate Schedule=0Row 216;Time (Hours)=26.3098;TESTC:Pressure 1=4966.99;Time (Hours)=0;TESTC:Rate Schedule=0Row 431;Time (Hours)=47.833328;TESTC:Pressure 1=6619.299805;Time (Hours)=0;TESTC:Rate Schedule=0Well, Reservoir & Fluid control Description window should appear.

Gas specific gravity text box is now filled out and should read 0.8563408786

A " Pseudo Table Data - Layer 1" window shows up. Number of Steps should be 201, Start Pressure = 0 psia, and End Pressure = 10000 psia.

A message box apears saying " All calculations completed successfully"

"Z Factor and Viscosity vs. Pressure" plot appears.

"Ct and Viscosity vs. Pressure" plot appears.

"m(p) vs. Pressure" plot appears.

PVT properties are calculated. Make sure that Bg = 0.00350461, Ug = 0.0327313; Cg = 6.7003e-005; Ct = 4.2085e-005 and Z = 1.19063.

The Test Overview plot is displayed.Verify by reading the Plot title: Test Overview Plot

A Log - Log plot should be displayed.Verify br reading the plot title: Log-Log Plot.

Grid should contain 31 rows and 4 columns .Row 1;Elapsed Time (hours) - Tp=3.0000=0.0999990000000004;Pressure 1:TP2=332.944752432;Elapsed Time (hours) - Tp=3.0000=0.199999999999999;Pressure 1 Deriv:TP2=761.890875058067Row 16;Elapsed Time (hours) - Tp=3.0000=1.600003;Pressure 1:TP2=1552.26740006823;Elapsed Time (hours) - Tp=3.0000=1.700003;Pressure 1 Deriv:TP2=170.426226900335Row 31;Elapsed Time (hours) - Tp=3.0000=3.058037;Pressure 1:TP2=1613.585036224;Elapsed Time (hours) - Tp=3.0000=0;Pressure 1 Deriv:TP2=0On Navigation pane, Line Results should display: Model 1Radial homogeneousInfinitely actingLog-LogCs = 0.1411 bbl/psi TP2V = 2105.907 bbl TP2

Line ResultsModel 1Radial homogeneousInfinitely actingLog-LogCs = 0.1411 bbl/psi TP2k = 0.83045 md TP2kh = 13.287 md.ft TP2V = 2105.907 bbl TP2

The Radial flow plot will be displayed.Verify by reading the plot title: Radial Flow Plot

Grid should contain 31 rows and 2 columns .Row 1;Horner Time Function - Tp=3.0000=30.9999699996999;Pressure 1:TP2=719.2510632Row 16;Horner Time Function - Tp=3.0000=2.87497585942026;Pressure 1:TP2=1938.57371083623Row 31;Horner Time Function - Tp=3.0000=1.98101069411521;Pressure 1:TP2=1999.891346992A "Define Line" message box appears. Radial flow radio button should be already selected.

On Navigation pane, Line Results should display: Model 1Radial homogeneousInfinitely actingSemi-LogdpS = -2365.2 psi TP2FE = 1.4093 TP2k = 2.43 md TP2kh = 38.88 md.ft TP2P* = 6222.968 psia TP2Rinv = 150.612 ft TP2S = -1.6687 TP2Log-LogCs = 0.1411 bbl/psi TP2k = 0.83045 md TP2kh = 13.287 md.ft TP2V = 2105.907 bbl TP2

A Log - Log plot should be displayed.Verify br reading the plot title: Log-Log Plot.

A "Global Point Selection" window appears.

Grid should contain 99 rows and 4 columns .Row 1;Elapsed Time (hours)=0.0999910000000029;Pressure 1:TP7=84.7961070614368;Elapsed Time (hours)=0.200001;Pressure 1 Deriv:TP7=11.3748076582235Row 50;Elapsed Time (hours)=5.066658;Pressure 1:TP7=122.940266433174;Elapsed Time (hours)=5.166661;Pressure 1 Deriv:TP7=9.44086072141783Row 99;Elapsed Time (hours)=10.066658;Pressure 1:TP7=127.296136885208;Elapsed Time (hours)=0;Pressure 1 Deriv:TP7=0On Navigation pane, Line Results should display: Line Results Model 1 Radial homogeneous Infinitely acting Log-Log k = 0.97192 md TP7 kh = 15.551 md.ft TP7


Grid should contain 99 rows and 2 columns .Row 1;Superposition Time Function=153.769806022218;Pressure 1:TP7=1372.35002801Row 50;Superposition Time Function=4.21660163948667;Pressure 1:TP7=1834.27579800173Row 99;Superposition Time Function=2.67616921506915;Pressure 1:TP7=1887.02538917587

A "Define Line" Message box is displayed. Radial flow radio button should already be selected.

On Navigation pane, Line Results should display: Line Results Model 1 Radial homogeneous Infinitely acting Semi-Log dpS = 81.885 psi TP7 FE = 0.98587 TP7 k = 3.2665 md TP7 kh = 52.264 md.ft TP7 P* = 6956.548 psia TP7 Rinv = 316.827 ft TP7 S = 0.0961 TP7 Log-Log k = 0.97192 md TP7 kh = 15.551 md.ft TP7

On Navigation pane, Line Results should display: Line ResultsModel 1Radial homogeneousInfinitely actingSemi-LogdpS = 81.885 psi TP7FE = 0.98587 TP7k = 3.2665 md TP7kh = 52.264 md.ft TP7P* = 6956.548 psia TP7Rinv = 316.827 ft TP7S = 0.0961 TP7Log-Logk = 0.97192 md TP7kh = 15.551 md.ft TP7



A "Define Line" message box appears. TP3: Radial flow radio button should be already selected.

On Navigation pane, Line Results should display: Line ResultsModel 1Radial homogeneousInfinitely actingSemi-Logk = 3.7445 md TP*




Skin vs FlowRate plot will be displayed. Verify by reading the plot title: Skin vs Flowrate Plot

Grid should contain 4 rows and 2 columns .Row 1;Normalised Flow Rate (MMscf/day)=3.95;SvQ Data=0.0125152663261474Row 2;Normalised Flow Rate (MMscf/day)=10.55;SvQ Data=1.04813529002413Row 3;Normalised Flow Rate (MMscf/day)=15.615;SvQ Data=2.08375531372211A "Define Line" message box appears. Skin Calculation radio button should be already selected.

On Navigation pane, Line Results should display: Line ResultsModel 1Radial homogeneousInfinitely actingSVQD = 1.8244e-4 1/(Mscf/day) TP1F = 3.2159 psi2/cp/(Mscf/day)2 TP1S = -0.7214 TP1

" Correct for rate Dependency" dialogue is displayed. Verify that Non -Darcy flow coefficient (F) = 3.21586 psi2/cp/(Mscf/day)2.

The Radial flow plot will be displayed.Verify by reading the plot title: Radial Flow Plot-Rate Dependent Skin Analysis(F=3.21586)

Quick Match dialogue shows up.

"Transient Welltest & LIT Results"dialogue is displayed.

Test Overview plot is displayed. Verify by reading the plot title: Test Overview Plot

On the Navigation pane, Line Results should display: Quick Match Results 1Radial homogeneousInfinitely actingConstant compressibilityCs = 0 bbl/psiV = 0 bbl(k/u)g = 114.402 md/cpk = 3.7445 mdkh = 59.913 md.ftS = -0.7214D = 1.8244e-4 1/(Mscf/day)Pi = 7133.369 psia

Test Overview Plot is displayed. Veriify by reading the plot title: Test Overview

Verify the following values: Layer Pressure = 6948; Dietz Shape Factor = 31.62; Drainage Area = 640;k = 3.3406; s = -2.94166; D = 0.000249257; B = 105850; F = 4.92491; AOF = 12.09.

IPR Plot is displayed. Verify by reading the plot title : "Sandface Deliverability Plot". On the Navigation pane, Quick Match Results should display: IPR ResultsRadial homogeneousInfinitely actingIPR-Trans Test B = 105850.064 psi2/cp/(Mscf/day)F = 4.9249 psi2/cp/(Mscf/day)2AOF = 12.09 MMscf/day

Grid should contain 200 rows and 2 columns .Row 1;Flow Rate (MMscf/day)=12.0900284398057;IPR-Trans Test=14.6499996185303Row 100;Flow Rate (MMscf/day)=8.53961222858388;IPR-Trans Test=3463.90452242138Row 200;Flow Rate (MMscf/day)=-9.37789079159388E-14;IPR-Trans Test=6948.00000000003

Transient IPR plot appears. Verify by reading the title plot: Sandface AOF Plot. On the Navigation pane, Line Results should display: IPR ResultsModel 1Radial homogeneousInfinitely actingIPR-Trans Test B = 105850.064 psi2/cp/(Mscf/day) TP1F = 4.9249 psi2/cp/(Mscf/day)2 TP1AOF = 12.09 MMscf/day TP1

Grid should contain 2 rows and 2 columns .Row 1;Flow Rate (MMscf/day)=12.0900284398057;IPR-Trans Test=1279.73028372863Row 2;Flow Rate (MMscf/day)=0.000120900284398056;IPR-Trans Test=0.0127973028372863A "Select test type" window appears. Flow-after-Flow radio button should be already selected.

A "LIT Analysis - Flow-after-Flow test" window appears. Layer pressure should be 6948 psia. Sandface pressures radio button should be already selected.

A LIT plot shows up. Verify by reading the plot title: Sandface LIT Plot.

Grid should contain 4 rows and 2 columns .Row 1;Flow Rate (MMscf/day)=3.95;Sandface LIT Plot: LIT Data: Flow After Flow=90.5730025460254Row 2;Flow Rate (MMscf/day)=6.6;Sandface LIT Plot: LIT Data: Flow After Flow=110.096991716879Row 3;Flow Rate (MMscf/day)=9.015;Sandface LIT Plot: LIT Data: Flow After Flow=123.4835132134Row 4;Flow Rate (MMscf/day)=12.11;Sandface LIT Plot: LIT Data: Flow After Flow=136.770947787614A "Define Line" message box appears. Extended Flow radio button should be already selected.

On the Navigation pane, Line Results should display: Line ResultsModel 1Radial homogeneousInfinitely actingLITAOF = 13.708 MMscf/day TP*B = 68141.875 psi2/cp/(Mscf/day) TP*F = 5.67 psi2/cp/(Mscf/day)2 TP*


Verify the following values: Layer Pressure = 6948; Dietz Shape Factor = 31.62; Drainage Area = 640;k = 3.3406; s = -2.94166; D = 0.000249257; B = 105850; F = 4.92491; AOF = 12.09; Under LIT Analysis Data: Rate-dependent skin Flow Coefficient (F) = 5.67; Darcy Flow Coefficient (B) = 68141.9, Rate-Dependent Skin Coefficient (D) = 0.000286967; AOF = 13.7083

IPR LIT Plot is displayed. Verify by reading the plot title : "Sandface Deliverability Plot". On the Navigation pane, Line Results should display: IPR ResultsModel 1Radial homogeneousInfinitely actingLITAOF = 13.708 MMscf/day TP*B = 68141.875 psi2/cp/(Mscf/day) TP*F = 5.67 psi2/cp/(Mscf/day)2 TP*IPR-LIT B = 68141.9 psi2/cp/(Mscf/day) TP1F = 5.67 psi2/cp/(Mscf/day)2 TP1AOF = 13.708 MMscf/day TP1

Grid should contain 200 rows and 4 columns .Row 1;Flow Rate (MMscf/day)=13.7082856392939;IPR-LIT=14.6499996185303;Flow Rate (MMscf/day)=3.95;IPR- AnnotationIPR-LIT=5974.04Row 2;Flow Rate (MMscf/day)=13.7076972946082;IPR-LIT=49.4909543943166;Flow Rate (MMscf/day)=6.6;IPR- AnnotationIPR-LIT=4966.99Row 3;Flow Rate (MMscf/day)=13.7059463668609;IPR-LIT=84.3319091701028;Flow Rate (MMscf/day)=9.015;IPR- AnnotationIPR-LIT=3894.03Row 100;Flow Rate (MMscf/day)=10.0804871670052;IPR-LIT=3463.90452242138;Flow Rate (MMscf/day)=0;IPR- AnnotationIPR-LIT=0Row 200;Flow Rate (MMscf/day)=0;IPR-LIT=6948.00000000003;Flow Rate (MMscf/day)=0;IPR- AnnotationIPR-LIT=0

LIT IPR plot appears. Verify by reading the title plot: Sandface AOF Plot. On the Navigation pane, Line Results should display:IPR ResultsModel 1Radial homogeneousInfinitely actingLITAOF = 13.708 MMscf/day TP*B = 68141.875 psi2/cp/(Mscf/day) TP*F = 5.67 psi2/cp/(Mscf/day)2 TP*IPR-LIT B = 68141.9 psi2/cp/(Mscf/day) TP1F = 5.67 psi2/cp/(Mscf/day)2 TP1AOF = 13.708 MMscf/day TP1

Grid should contain 4 rows and 4 columns .Row 1;Flow Rate (MMscf/day)=13.7082856392939;IPR-LIT=934.108629204204;Flow Rate (MMscf/day)=3.95;IPR- AnnotationIPR-LIT=269.2971850568Row 2;Flow Rate (MMscf/day)=0.000137082856392939;IPR-LIT=0.00934108629204203;Flow Rate (MMscf/day)=6.6;IPR- AnnotationIPR-LIT=479.6549453314Row 3;Flow Rate (MMscf/day)=0;IPR-LIT=0;Flow Rate (MMscf/day)=9.015;IPR- AnnotationIPR-LIT=652.4016958688Row 4;Flow Rate (MMscf/day)=0;IPR-LIT=0;Flow Rate (MMscf/day)=12.11;IPR- AnnotationIPR-LIT=824.778770708

A comparison plot between Transient and LIT IPR appears. Verify by reading the title plot: Sandface Deliverability Plot. On the Navigation pane, Line Results should display: IPR ResultsModel 1Radial homogeneousInfinitely actingLITAOF = 13.708 MMscf/day TP*B = 68141.875 psi2/cp/(Mscf/day) TP*F = 5.67 psi2/cp/(Mscf/day)2 TP*IPR-Trans Test B = 105850.064 psi2/cp/(Mscf/day) TP1F = 5.67 psi2/cp/(Mscf/day)2 TP*IPR-Trans Test B = 105850.064 psi2/cp/(Mscf/day) TP1F = 4.9249 psi2/cp/(Mscf/day)2 TP1AOF = 12.09 MMscf/day TP1IPR-LIT B = 68141.9 psi2/cp/(Mscf/day) TP1F = 5.67 psi2/cp/(Mscf/day)2 TP1AOF = 13.708 MMscf/day TP1

Grid should contain 200 rows and 6 columns .Row 1;Flow Rate (MMscf/day)=12.090028453899;IPR-Trans Test=14.6499996185303;Flow Rate (MMscf/day)=13.7082856392939;IPR-LIT=14.6499996185303;Flow Rate (MMscf/day)=3.95;IPR- AnnotationIPR-Trans Test=5974.04Row 100;Flow Rate (MMscf/day)=8.53961224037105;IPR-Trans Test=3463.90452242138;Flow Rate (MMscf/day)=10.0804871670052;IPR-LIT=3463.90452242138;Flow Rate (MMscf/day)=0;IPR- AnnotationIPR-Trans Test=0Row 200;Flow Rate (MMscf/day)=0;IPR-Trans Test=6948.00000000003;Flow Rate (MMscf/day)=0;IPR-LIT=6948.00000000003;Flow Rate (MMscf/day)=0;IPR- AnnotationIPR-Trans Test=0

A comparison plot between Transient and LIT IPR appears. Verify by reading the title plot: Sandface AOF Plot. On the Navigation pane, Line Results should display: IPR ResultsModel 1Radial homogeneousInfinitely actingLITAOF = 13.708 MMscf/day TP*B = 68141.875 psi2/cp/(Mscf/day) TP*F = 5.67 psi2/cp/(Mscf/day)2 TP*IPR-Trans Test B = 105850.064 psi2/cp/(Mscf/day) TP1F = 4.9249 psi2/cp/(Mscf/day)2 TP1AOF = 12.09 MMscf/day TP1IPR-LIT B = 68141.9 psi2/cp/(Mscf/day) TP1F = 5.67 psi2/cp/(Mscf/day)2 TP1AOF = 13.708 MMscf/day TP1

Grid should contain 4 rows and 6 columns .Row 1;Flow Rate (MMscf/day)=12.090028453899;IPR-Trans Test=1279.73028205034;Flow Rate (MMscf/day)=13.7082856392939;IPR-LIT=934.108629204204;Flow Rate (MMscf/day)=3.95;IPR- AnnotationIPR-Trans Test=269.2971850568Row 2;Flow Rate (MMscf/day)=1.2090028453899E-04;IPR-Trans Test=0.0127973028205034;Flow Rate (MMscf/day)=0.000137082856392939;IPR-LIT=0.00934108629204203;Flow Rate (MMscf/day)=6.6;IPR- AnnotationIPR-Trans Test=479.6549453314Row 4;Flow Rate (MMscf/day)=0;IPR-Trans Test=0;Flow Rate (MMscf/day)=0;IPR-LIT=0;Flow Rate (MMscf/day)=12.11;IPR- AnnotationIPR-Trans Test=824.778770708A "Select test type" window appears. Flow-after-Flow radio button should be already selected.

A "C&n Analysis - Flow-after-Flow test" window appears. Layer pressure should be 6948 psia. Sandface pressures radio button should be already selected.

A C&n plot shows up. Verify by reading the plot title: Sandface C&n Plot.

"C & n Results"dialogue is displayed.

Grid should contain 4 rows and 2 columns .Row 1;Flow Rate (MMscf/day)=3.95;Sandface C&n Plot: C and n Data: Flow After Flow=12.5855500784Row 2;Flow Rate (MMscf/day)=6.6;Sandface C&n Plot: C and n Data: Flow After Flow=23.6037143399Row 3;Flow Rate (MMscf/day)=9.015;Sandface C&n Plot: C and n Data: Flow After Flow=33.1112343591Row 4;Flow Rate (MMscf/day)=12.11;Sandface C&n Plot: C and n Data: Flow After Flow=43.32808319A "Define Line" message box appears. Extended Flow radio button should be already selected.

On the Navigation pane, Line Results should display: Line ResultsModel 1Radial homogeneousInfinitely actingC&nAOF = 14.919 MMscf/day TP*C = 1.8129e-6 MMscf/day/psi2n TP*n = 0.9 TP*

Verify the following values: Layer Pressure = 6948; Dietz Shape Factor = 31.62; Drainage Area = 640;k = 3.3406; s = -2.94166; Under Extended Data: C Coefficient = 1.81293e-06; n Exponent = 0.9; AOF = 14.9186; Under Stabilized Data: Stabilized Flowing Pressure = 2224.1; Stabilized Flow Rate = 10.5031; Stabilized C Coefficient = 1.40678e-06; Stabilized AOF = 11.5763

Extended IPR Plot is displayed. Verify by reading the plot title : "Sandface Deliverability Plot". On the Navigation pane, Line Results should display: IPR ResultsModel 1Radial homogeneousInfinitely actingC&nAOF = 14.919 MMscf/day TP*C = 1.8129e-6 MMscf/day/psi2n TP*n = 0.9 TP*Extended C = 1.8129e-6 MMscf/day/psi2n TP1n = 0.9 TP1AOF = 14.919 MMscf/day TP1

Grid should contain 200 rows and 4 columns .Row 1;Flow Rate (MMscf/day)=14.9185617248914;Extended=14.6499996185303;Flow Rate (MMscf/day)=3.95;IPR- AnnotationExtended=5974.04Row 100;Flow Rate (MMscf/day)=11.5355747557135;Extended=3463.90452242138;Flow Rate (MMscf/day)=0;IPR- AnnotationExtended=0Row 200;Flow Rate (MMscf/day)=0;Extended=6948.00000000003;Flow Rate (MMscf/day)=0;IPR- AnnotationExtended=0Extended Log-Log IPR plot appears. Verify by reading the title plot: Sandface AOF Plot. On the Navigation pane, Line Results should display: IPR ResultsModel 1Radial homogeneousInfinitely actingC&nAOF = 14.919 MMscf/day TP*C = 1.8129e-6 MMscf/day/psi2n TP*n = 0.9 TP*Extended C = 1.8129e-6 MMscf/day/psi2n TP1n = 0.9 TP1AOF = 14.919 MMscf/day TP1

Grid should contain 4 rows and 4 columns .Row 1;Flow Rate (MMscf/day)=14.9185617248933;Extended=48.274704;Flow Rate (MMscf/day)=3.95;IPR- AnnotationExtended=12.5855500784Row 2;Flow Rate (MMscf/day)=0.01;Extended=1.43666772594895E-02;Flow Rate (MMscf/day)=6.6;IPR- AnnotationExtended=23.6037143399Row 4;Flow Rate (MMscf/day)=0;Extended=0;Flow Rate (MMscf/day)=12.11;IPR- AnnotationExtended=43.32808319

A Stabilized IPR plot appears. Verify by reading the title plot: Sandface Deliverability Plot. On the Navigation pane, Line Results should display: IPR ResultsModel 1Radial homogeneousInfinitely actingC&nAOF = 14.919 MMscf/day TP*C = 1.8129e-6 MMscf/day/psi2n TP*n = 0.9 TP*Stabilized C = 1.4068e-6 MMscf/day/psi2n TP1n = 0.9 TP1AOF = 11.576 MMscf/day TP1

Grid should contain 200 rows and 4 columns .Row 1;Flow Rate (MMscf/day)=11.5763369504425;Stabilized=14.6499996185303;Flow Rate (MMscf/day)=10.5031064768356;IPR- AnnotationStabilized=2224.1Row 100;Flow Rate (MMscf/day)=8.95124494919292;Stabilized=3463.90452242138;Flow Rate (MMscf/day)=0;IPR- AnnotationStabilized=0Row 200;Flow Rate (MMscf/day)=0;Stabilized=6948.00000000003;Flow Rate (MMscf/day)=0;IPR- AnnotationStabilized=0A Stabilized Log-Log IPR plot appears. Verify by reading the title plot: Sandface AOF Plot. On the Navigation pane, Line Results should display: IPR ResultsModel 1Radial homogeneousInfinitely actingC&nAOF = 14.919 MMscf/day TP*C = 1.8129e-6 MMscf/day/psi2n TP*n = 0.9 TP*Stabilized C = 1.4068e-6 MMscf/day/psi2n TP1n = 0.9 TP1AOF = 11.576 MMscf/day TP1

Grid should contain 2 rows and 4 columns .Row 1;Flow Rate (MMscf/day)=11.5763369504439;Stabilized=48.274704;Flow Rate (MMscf/day)=10.5031064768356;IPR- AnnotationStabilized=43.32808319Row 2;Flow Rate (MMscf/day)=0.01;Stabilized=0.019043714625647;Flow Rate (MMscf/day)=0;IPR- AnnotationStabilized=0A comparison plot between Extended and Stabilized IPR appears. Verify by reading the title plot: Sandface Deliverability Plot. On the Navigation pane, Line Results should display: IPR ResultsModel 1Radial homogeneousInfinitely actingC&nAOF = 14.919 MMscf/day TP*C = 1.8129e-6 MMscf/day/psi2n TP*n = 0.9 TP*Extended C = 1.8129e-6 MMscf/day/psi2n TP1n = 0.9 TP1AOF = 14.919 MMscf/day TP1Stabilized C = 1.4068e-6 MMscf/day/psi2n TP1n = 0.9 TP1AOF = 11.576 MMscf/day TP1

Grid should contain 200 rows and 6 columns .Row 1;Flow Rate (MMscf/day)=14.9185617248914;Extended=14.6499996185303;Flow Rate (MMscf/day)=11.5763369504425;Stabilized=14.6499996185303;Flow Rate (MMscf/day)=3.95;IPR- AnnotationExtended=5974.04Row 100;Flow Rate (MMscf/day)=11.5355747557135;Extended=3463.90452242138;Flow Rate (MMscf/day)=8.95124494919292;Stabilized=3463.90452242138;Flow Rate (MMscf/day)=0;IPR- AnnotationExtended=0Row 200;Flow Rate (MMscf/day)=0;Extended=6948.00000000003;Flow Rate (MMscf/day)=0;Stabilized=6948.00000000003;Flow Rate (MMscf/day)=0;IPR- AnnotationExtended=0

A comparison plot between Extended and Stabilized Log -Log IPR appears. Verify by reading the title plot: Sandface AOF Plot. On the Navigation pane, Line Results should display: IPR ResultsModel 1Radial homogeneousInfinitely actingC&nAOF = 14.919 MMscf/day TP*C = 1.8129e-6 MMscf/day/psi2n TP*n = 0.9 TP*Extended C = 1.8129e-6 MMscf/day/psi2n TP1n = 0.9 TP1AOF = 14.919 MMscf/day TP1Stabilized C = 1.4068e-6 MMscf/day/psi2n TP1n = 0.9 TP1AOF = 11.576 MMscf/day TP1

Grid should contain 5 rows and 6 columns .Row 1;Flow Rate (MMscf/day)=14.9185617248933;Extended=48.274704;Flow Rate (MMscf/day)=11.5763369504439;Stabilized=48.274704;Flow Rate (MMscf/day)=3.95;IPR- AnnotationExtended=12.5855500784Row 3;Flow Rate (MMscf/day)=0;Extended=0;Flow Rate (MMscf/day)=0;Stabilized=0;Flow Rate (MMscf/day)=9.015;IPR- AnnotationExtended=33.1112343591Row 5;Flow Rate (MMscf/day)=0;Extended=0;Flow Rate (MMscf/day)=0;Stabilized=0;Flow Rate (MMscf/day)=10.5031064768356;IPR- AnnotationExtended=43.32808319The Radial flow plot will be displayed.Verify by reading the plot title: Radial Flow Plot

A warning message is displayed : " Rate -dependent skin analysis is based on fitting lines to infinite-acting radial flow portions of your data. Be careful if you have boundaries present ".

The Radial flow plot will be displayed.Verify by reading the plot title: Radial Flow Plot-Rate Dependent Skin Analysis


On Navigation pane, Line Results should display: Line ResultsModel 1Radial homogeneousClosed systemSemi-Logk = 1.2969 md TP*



Skin vs FlowRate plot will be displayed. Verify by reading the plot title: Skin vs Flowrate Plot

Grid should contain 3 rows and 2 columns .Row 1;Normalised Flow Rate (MMscf/day)=2.8;SvQ Data=-1.72214071750389Row 2;Normalised Flow Rate (MMscf/day)=3.93;SvQ Data=-1.53486722586207Row 3;Normalised Flow Rate (MMscf/day)=5.62;SvQ Data=-1.34759373422026A "Define Line" message box appears. Skin Calculation radio button should be already selected.

On Navigation pane, Line Results should display: Line ResultsModel 1Radial homogeneousClosed systemSVQD = 1.3109e-4 1/(Mscf/day) TP1F = 0.94817 psi2/cp/(Mscf/day)2 TP1S = -2.0868 TP1

" Correct for rate Dependency" dialogue is displayed. Verify that Non -Darcy flow coefficient (F) = 0.948166 psi2/cp/(Mscf/day)2.

The Radial flow plot will be displayed.Verify by reading the plot title: Radial Flow Plot-Rate Dependent Skin Analysis(F=0.948166)

Quick Match dialogue shows up.


Test Overview plot is displayed. Verify by reading the plot title: Test Overview Plot

A Closed System message is displayed. Variable well position radio button should already be selected.

On the Navigation pane, Line Results should display: Quick Match Results 1Radial homogeneousClosed systemCorrected compressibilityCs = 0 bbl/psiV = 0 bbl(k/u)g = 40.136 md/cpk = 1.2969 mdkh = 129.692 md.ftS = -2.0868D = 1.3109e-4 1/(Mscf/day)L1 NF = 550 ftL2 NF = 550 ftL3 NF = 550 ftL4 NF = 550 ftArea = 27.778 acresOGIP = 8.3313 bscfPi = 7972.521 psia

Test Overview Plot is displayed. Veriify by reading the plot title: Test Overview

Verify the following values: Layer Pressure = 7952; Dietz Shape Factor = 30.8815; Drainage Area = 27.7778; k = 1.28515; s = -2.94224; D = 0.000283301; B = 27735.7; F = 2.06786; AOF = 29.239.

IPR Plot is displayed. Verify by reading the plot title : "Sandface Deliverability Plot". On the Navigation pane, Quick Match Results should display: IPR ResultsRadial homogeneousInfinitely actingIPR-Trans Test B = 27735.678 psi2/cp/(Mscf/day)F = 2.0679 psi2/cp/(Mscf/day)2AOF = 29.239 MMscf/day

Grid should contain 200 rows and 2 columns .Row 1;Flow Rate (MMscf/day)=29.2389956987126;IPR-Trans Test=14.6499996185303Row 100;Flow Rate (MMscf/day)=21.8624049696149;IPR-Trans Test=3963.38190935605Row 200;Flow Rate (MMscf/day)=3.77115260012542E-13;IPR-Trans Test=7951.99999999997Transient IPR plot appears. Verify by reading the title plot: Sandface AOF Plot. On the Navigation pane, Line Results should display: IPR ResultsModel 1Radial homogeneousInfinitely actingk = 1.29 md TP*SLS = -2.942 TP1SVQD = 2.83E-004 1/(Mscf/day) TP1SVQF = 2.07 psi2/cp/(Mscf/day)2 TP1SVQIPR-Trans Test B = 27735.678 psi2/cp/(Mscf/day) TP1F = 2.0679 psi2/cp/(Mscf/day)2 TP1AOF = 29.239 MMscf/day TP1

IPR ResultsModel 1Radial homogeneousInfinitely actingk = 1.29 md TP*SLS = -2.942 TP1SVQD = 2.83E-004 1/(Mscf/day) TP1SVQF = 2.07 psi2/cp/(Mscf/day)2 TP1SVQIPR-Trans Test B = 27735.678 psi2/cp/(Mscf/day) TP1F = 2.0679 psi2/cp/(Mscf/day)2 TP1AOF = 29.239 MMscf/day TP1AOF = 29.239 MMscf/day TP1B = 27735.678 psi2/cp/(Mscf/day) TP1F = 2.0679 psi2/cp/(Mscf/day)2 TP1IPR-Trans Test

Grid should contain 2 rows and 2 columns .Row 1;Flow Rate (MMscf/day)=29.2389956987126;IPR-Trans Test=810.963366348325Row 2;Flow Rate (MMscf/day)=0.000292389956987126;IPR-Trans Test=0.00810963366348325A "Select test type" window appears. Select Isochronal radio button.

A "LIT Analysis - Isochronal test" window appears. Layer pressure should be 7952 psia. Sandface pressures radio button should be already selected.

A LIT plot shows up. Verify by reading the plot title: Sandface LIT Plot.


Grid should contain 5 rows and 2 columns .Row 1;Flow Rate (MMscf/day)=2.8;Sandface LIT Plot: LIT Data: Isochronal=28.7054584428573Row 3;Flow Rate (MMscf/day)=5.62;Sandface LIT Plot: LIT Data: Isochronal=33.6274215373665Row 5;Flow Rate (MMscf/day)=7.02;Sandface LIT Plot: LIT Data: Isochronal=36.5021312535613A "Define Line" message box appears. Select Free model line radio button.

A "Define Line" message box appears. Select Free model line radio button.

A "Define Line" message box appears. Select Free model line radio button.

A "Define Line" message box appears. Extended Flow radio button should be already selected.

On the Navigation pane, Line Results should display:Line ResultsModel 1Radial homogeneousClosed systemLITAOF = 28.062 MMscf/day TP*B = 33806.008 psi2/cp/(Mscf/day) TP*F = 2.07 psi2/cp/(Mscf/day)2 TP*

Verify the following values: Layer Pressure = 7952; Dietz Shape Factor = 30.8815; Drainage Area = 27.7778; k = 1.28515; S = -2.94224; D = 0.000283301; B = 27735.7; F = 2.06786; AOF = 29.239; Under LIT Analysis Data: Rate-dependent skin Flow Coefficient (F) = 2.07; Darcy Flow Coefficient (B) = 33806, Rate-Dependent Skin Coefficient (D) = 0.000283595; AOF = 28.0625

IPR LIT Plot is displayed. Verify by reading the plot title : "Sandface Deliverability Plot". On the Navigation pane, IPR ResultsModel 1Radial homogeneousInfinitely actingLITAOF = 28.062 MMscf/day TP*B = 33806.008 psi2/cp/(Mscf/day) TP*F = 2.07 psi2/cp/(Mscf/day)2 TP*k = 1.29 md TP*SLS = -2.942 TP1SVQD = 2.83E-004 1/(Mscf/day) TP1SVQIPR-LIT B = 33806 psi2/cp/(Mscf/day) TP1F = 2.07 psi2/cp/(Mscf/day)2 TP1AOF = 28.062 MMscf/day TP1

Grid should contain 200 rows and 4 columns .Row 1;Flow Rate (MMscf/day)=28.0624991863641;IPR-LIT=14.6499996185303;Flow Rate (MMscf/day)=6.74;IPR- AnnotationIPR-LIT=7150Row 100;Flow Rate (MMscf/day)=20.7666418428839;IPR-LIT=3963.38190935605;Flow Rate (MMscf/day)=0;IPR- AnnotationIPR-LIT=0Row 200;Flow Rate (MMscf/day)=3.08931624243522E-13;IPR-LIT=7951.99999999997;Flow Rate (MMscf/day)=0;IPR- AnnotationIPR-LIT=0LIT IPR plot appears. Verify by reading the title plot: Sandface AOF Plot. On the Navigation pane, Line Results should display: IPR ResultsModel 1Radial homogeneousInfinitely actingLITAOF = 28.062 MMscf/day TP*B = 33806.008 psi2/cp/(Mscf/day) TP*F = 2.07 psi2/cp/(Mscf/day)2 TP*k = 1.29 md TP*SLS = -2.942 TP1SVQD = 2.83E-004 1/(Mscf/day) TP1SVQIPR-LIT B = 33806 psi2/cp/(Mscf/day) TP1F = 2.07 psi2/cp/(Mscf/day)2 TP1AOF = 28.062 MMscf/day TP1

Grid should contain 2 rows and 4 columns .Row 1;Flow Rate (MMscf/day)=28.0624991863641;IPR-LIT=948.680847494224;Flow Rate (MMscf/day)=6.74;IPR- AnnotationIPR-LIT=226.14044464Row 2;Flow Rate (MMscf/day)=0.000280624991863641;IPR-LIT=0.00948680847494224;Flow Rate (MMscf/day)=0;IPR- AnnotationIPR-LIT=0A comparison plot between Transient and LIT IPR appears. Verify by reading the title plot: Sandface Deliverability Plot. On the Navigation pane, Line Results should display: IPR ResultsModel 1Radial homogeneousInfinitely actingLITAOF = 28.062 MMscf/day TP*B = 33806.008 psi2/cp/(Mscf/day) TP*F = 2.07 psi2/cp/(Mscf/day)2 TP*k = 1.29 md TP*SLS = -2.942 TP1SVQD = 2.83E-004 1/(Mscf/day) TP1SVQIPR-Trans Test B = 27735.673 psi2/cp/(Mscf/day) TP1F = 2.0679 psi2/cp/(Mscf/day)2 TP1AOF = 29.239 MMscf/day TP1IPR-LIT B = 33806 psi2/cp/(Mscf/day) TP1F = 2.07 psi2/cp/(Mscf/day)2 TP1AOF = 28.062 MMscf/day TP1

Grid should contain 200 rows and 6 columns .Row 1;Flow Rate (MMscf/day)=29.2389965776224;IPR-Trans Test=14.6499996185303;Flow Rate (MMscf/day)=28.0624991863641;IPR-LIT=14.6499996185303;Flow Rate (MMscf/day)=6.74;IPR- AnnotationIPR-Trans Test=7150Row 100;Flow Rate (MMscf/day)=21.8624057964731;IPR-Trans Test=3963.38190935605;Flow Rate (MMscf/day)=20.7666418428839;IPR-LIT=3963.38190935605;Flow Rate (MMscf/day)=0;IPR- AnnotationIPR-Trans Test=0Row 200;Flow Rate (MMscf/day)=3.77115260012542E-13;IPR-Trans Test=7951.99999999997;Flow Rate (MMscf/day)=3.08931624243522E-13;IPR-LIT=7951.99999999997;Flow Rate (MMscf/day)=0;IPR- AnnotationIPR-Trans Test=0A comparison plot between Transient and LIT IPR appears. Verify by reading the title plot: Sandface AOF Plot. On the Navigation pane, Line Results should display: IPR ResultsModel 1Radial homogeneousInfinitely actingLITAOF = 28.062 MMscf/day TP*B = 33806.008 psi2/cp/(Mscf/day) TP*F = 2.07 psi2/cp/(Mscf/day)2 TP*k = 1.29 md TP*SLS = -2.942 TP1SVQD = 2.83E-004 1/(Mscf/day) TP1SVQIPR-Trans Test B = 27735.673 psi2/cp/(Mscf/day) TP1F = 2.0679 psi2/cp/(Mscf/day)2 TP1AOF = 29.239 MMscf/day TP1IPR-LIT B = 33806 psi2/cp/(Mscf/day) TP1F = 2.07 psi2/cp/(Mscf/day)2 TP1AOF = 28.062 MMscf/day TP1

"C & n Results"dialogue is displayed.

Grid should contain 2 rows and 6 columns .Row 1;Flow Rate (MMscf/day)=29.2389965776224;IPR-Trans Test=810.963260066903;Flow Rate (MMscf/day)=28.0624991863641;IPR-LIT=948.680847494224;Flow Rate (MMscf/day)=6.74;IPR- AnnotationIPR-Trans Test=226.14044464Row 2;Flow Rate (MMscf/day)=0.000292389965776224;IPR-Trans Test=0.00810963260066903;Flow Rate (MMscf/day)=0.000280624991863641;IPR-LIT=0.00948680847494224;Flow Rate (MMscf/day)=0;IPR- AnnotationIPR-Trans Test=0A "Select test type" window appears. Select Isochronal radio button.

A "C&n Analysis - Isochronal test" window appears. Layer pressure should be 7952 psia. Sandface pressures radio button should be already selected.

A C&n plot shows up. Verify by reading the plot title: Sandface C&n Plot.

Grid should contain 5 rows and 2 columns .Row 1;Flow Rate (MMscf/day)=2.8;Sandface C&n Plot: C and n Data: Isochronal=3.171804Row 3;Flow Rate (MMscf/day)=5.62;Sandface C&n Plot: C and n Data: Isochronal=7.282536Row 5;Flow Rate (MMscf/day)=7.02;Sandface C&n Plot: C and n Data: Isochronal=9.73272A "Define Line" message box appears. Select "Free model line" radio button.

A "Define Line" message box appears. Select Ëxtended Flow" radio button.

On the Navigation pane, Line Results should display: Line ResultsModel 1Radial homogeneousClosed systemC&nAOF = 22.113 MMscf/day TP*C = 1.5202e-5 MMscf/day/psi2n TP*n = 0.79 TP*

Verify the following values: Layer Pressure = 7952; Dietz Shape Factor = 30.8815; Drainage Area = 27.7778; k = 1.28515; S = -2.94224; Under Extended Data: C Coefficient = 1.52018e-05; n Exponent = 0.79; AOF = 22.1129; Under Stabilized Data: Stabilized Flowing Pressure = 7150; Stabilized Flow Rate = 10.9099; Stabilized C Coefficient = 2.76749e-05; Stabilized AOF = 40.2567.

IPR ResultsModel 1Radial homogeneousInfinitely actingC&nAOF = 22.113 MMscf/day TP*C = 1.5202e-5 MMscf/day/psi2n TP*n = 0.79 TP*k = 1.29 md TP*SLS = -2.942 TP1SVQD = 2.83E-004 1/(Mscf/day) TP1SVQF = 2.07 psi2/cp/(Mscf/day)2 TP1SVQExtended C = 1.5202e-5 MMscf/day/psi2n TP1n = 0.79 TP1AOF = 22.113 MMscf/day TP1

Grid should contain 200 rows and 4 columns .Row 1;Flow Rate (MMscf/day)=22.1129414911881;Extended=14.6499996185303;Flow Rate (MMscf/day)=6.74;IPR- AnnotationExtended=7150Row 100;Flow Rate (MMscf/day)=17.6469659415281;Extended=3963.38190935605;Flow Rate (MMscf/day)=0;IPR- AnnotationExtended=0Row 200;Flow Rate (MMscf/day)=0;Extended=7951.99999999997;Flow Rate (MMscf/day)=0;IPR- AnnotationExtended=0

Extened Log-Log IPR plot appears. Verify by reading the title plot: Sandface AOF Plot. On the Navigation pane, Line Results should display: IPR ResultsModel 1Radial homogeneousInfinitely actingC&nAOF = 22.113 MMscf/day TP*C = 1.5202e-5 MMscf/day/psi2n TP*n = 0.79 TP*k = 1.29 md TP*SLS = -2.942 TP1SVQD = 2.83E-004 1/(Mscf/day) TP1SVQF = 2.07 psi2/cp/(Mscf/day)2 TP1SVQExtended C = 1.5202e-5 MMscf/day/psi2n TP1n = 0.79 TP1AOF = 22.113 MMscf/day TP1

Grid should contain 2 rows and 4 columns .Row 1;Flow Rate (MMscf/day)=22.1129414911899;Extended=63.234304;Flow Rate (MMscf/day)=6.74;IPR- AnnotationExtended=12.111804Row 2;Flow Rate (MMscf/day)=0.01;Extended=0.00369167086993067;Flow Rate (MMscf/day)=0;IPR- AnnotationExtended=0A Stabilized IPR plot appears. Verify by reading the title plot: Sandface Deliverability Plot. On the Navigation pane, Line Results should display: IPR ResultsModel 1Radial homogeneousInfinitely actingC&nAOF = 22.113 MMscf/day TP*C = 1.5202e-5 MMscf/day/psi2n TP*n = 0.79 TP*k = 1.29 md TP*SLS = -2.942 TP1SVQD = 2.83E-004 1/(Mscf/day) TP1SVQF = 2.07 psi2/cp/(Mscf/day)2 TP1SVQStabilized C = 2.7675e-5 MMscf/day/psi2n TP1n = 0.79 TP1AOF = 40.257 MMscf/day TP1

Grid should contain 200 rows and 4 columns .Row 1;Flow Rate (MMscf/day)=40.2567081575558;Stabilized=14.6499996185303;Flow Rate (MMscf/day)=10.9099242679835;IPR- AnnotationStabilized=7150Row 100;Flow Rate (MMscf/day)=32.1263798422077;Stabilized=3963.38190935605;Flow Rate (MMscf/day)=0;IPR- AnnotationStabilized=0Row 200;Flow Rate (MMscf/day)=0;Stabilized=7951.99999999997;Flow Rate (MMscf/day)=0;IPR- AnnotationStabilized=0A Stabilized Log-Log IPR plot appears. Verify by reading the title plot: Sandface Deliverability Plot. On the Navigation pane, Line Results should display: IPR ResultsModel 1Radial homogeneousInfinitely actingC&nAOF = 22.113 MMscf/day TP*C = 1.5202e-5 MMscf/day/psi2n TP*n = 0.79 TP*k = 1.29 md TP*SLS = -2.942 TP1SVQD = 2.83E-004 1/(Mscf/day) TP1SVQF = 2.07 psi2/cp/(Mscf/day)2 TP1SVQStabilized C = 2.7675e-5 MMscf/day/psi2n TP1n = 0.79 TP1AOF = 40.257 MMscf/day TP1

Grid should contain 2 rows and 4 columns .Row 1;Flow Rate (MMscf/day)=40.2567081575591;Stabilized=63.234304;Flow Rate (MMscf/day)=10.9099242679835;IPR- AnnotationStabilized=12.111804Row 1;Flow Rate (MMscf/day)=40.2567081575591;Stabilized=63.234304;Flow Rate (MMscf/day)=10.9099242679835;IPR- AnnotationStabilized=12.111804Row 2;Flow Rate (MMscf/day)=0.01;Stabilized=0.00172928406173635;Flow Rate (MMscf/day)=0;IPR- AnnotationStabilized=0

A comparison plot between Extended and Stabilized IPR appears. Verify by reading the title plot: Sandface Deliverability Plot. On the Navigation pane, Line Results should display:IPR ResultsModel 1Radial homogeneousInfinitely actingC&nAOF = 22.113 MMscf/day TP*C = 1.5202e-5 MMscf/day/psi2n TP*n = 0.79 TP*k = 1.29 md TP*SLS = -2.942 TP1SVQD = 2.83E-004 1/(Mscf/day) TP1SVQF = 2.07 psi2/cp/(Mscf/day)2 TP1SVQExtended C = 1.5202e-5 MMscf/day/psi2n TP1n = 0.79 TP1AOF = 22.113 MMscf/day TP1Stabilized C = 2.7675e-5 MMscf/day/psi2n TP1n = 0.79 TP1AOF = 40.257 MMscf/day TP1

Grid should contain 200 rows and 6 columns .Row 1;Flow Rate (MMscf/day)=22.1129414911881;Extended=14.6499996185303;Flow Rate (MMscf/day)=40.2567081575558;Stabilized=14.6499996185303;Flow Rate (MMscf/day)=6.74;IPR- AnnotationExtended=7150Row 100;Flow Rate (MMscf/day)=17.6469659415281;Extended=3963.38190935605;Flow Rate (MMscf/day)=32.1263798422077;Stabilized=3963.38190935605;Flow Rate (MMscf/day)=0;IPR- AnnotationExtended=0Row 200;Flow Rate (MMscf/day)=0;Extended=7951.99999999997;Flow Rate (MMscf/day)=0;Stabilized=7951.99999999997;Flow Rate (MMscf/day)=0;IPR- AnnotationExtended=0

A comparison plot between Extended and Stabilized Log -Log IPR appears. Verify by reading the title plot: Sandface AOF Plot. On the Navigation pane, Line Results should display: IPR ResultsModel 1Radial homogeneousInfinitely actingC&nAOF = 22.113 MMscf/day TP*C = 1.5202e-5 MMscf/day/psi2n TP*n = 0.79 TP*k = 1.29 md TP*SLS = -2.942 TP1SVQD = 2.83E-004 1/(Mscf/day) TP1SVQF = 2.07 psi2/cp/(Mscf/day)2 TP1SVQExtended C = 1.5202e-5 MMscf/day/psi2n TP1n = 0.79 TP1AOF = 22.113 MMscf/day TP1Stabilized C = 2.7675e-5 MMscf/day/psi2n TP1n = 0.79 TP1AOF = 40.257 MMscf/day TP1

Grid should contain 2 rows and 6 columns .Row 1;Flow Rate (MMscf/day)=22.1129414911899;Extended=63.234304;Flow Rate (MMscf/day)=40.2567081575591;Stabilized=63.234304;Flow Rate (MMscf/day)=6.74;IPR- AnnotationExtended=12.111804Row 2;Flow Rate (MMscf/day)=0.01;Extended=3.69167086993067E-03;Flow Rate (MMscf/day)=0.01;Stabilized=0.00172928406173635;Flow Rate (MMscf/day)=10.9099242679835;IPR- AnnotationExtended=12.111804


2

3

45

2 Ex 5.2.panx 1

2

3

45

Wellhead to BHP conversion

Wellhead to BHP conversion using a Wellflo file

Wellhead to BHP conversion using a VFP file


Click on Data Grid

Click on Data Grid

Open Ex 5.1.panx. Go to Data Preparation >> Gauge data >> THP to BHP.

Click Using WellFlo tab. Enter Oil Rate= 300 STB/day; GOR=500 scf/STB; Water Cut = 0.12. Click on Browse button and locate the Wellflo file " Black Oil.wflx". Click Calculate.

Click OK. Under the Navigation Pane double click on TEST DESIGN: BHP data file.


Open Ex 5.2.panx. Go to Data Preparation >> Gauge data >> THP to BHP.

Click Using VFP Tables tab. Enter Gas Rate= 1.2 MMscf/day; WGR = 200 STB/MMscf. Click on Browse button and locate the VFP file "gas well.VFP". Click Calculate.

Click OK. Under the Navigation Pane double click on DST-1: BHP data file.


Expected Results Status

The BHP table will be populated

A Data Edit Plot appears.

The BHP table will be populated

A Data Edit Plot appears.

WellHead to Bottom-Hole Pressure Conversion window will appear

Grid should contain 250 rows and 4 columns .Row 1;Time (Hours)=0.001;TEST DESIGN:BHP=9901.62;Time (Hours)=0;TEST DESIGN:Rate Schedule=0Row 125;Time (Hours)=200.282196;TEST DESIGN:BHP=9878.95;Time (Hours)=0;TEST DESIGN:Rate Schedule=0Row 250;Time (Hours)=500;TEST DESIGN:BHP=9899.01;Time (Hours)=0;TEST DESIGN:Rate Schedule=0WellHead to Bottom-Hole Pressure Conversion window will appear

Grid should contain 1220 rows and 4 columns .Row 1;Time (Hours)=0.0010000000475;DST-1:BHP=6677.77715823107;Time (Hours)=0;DST-1:Rate Schedule=0Row 610;Time (Hours)=800.002674109027;DST-1:BHP=6183.91488520853;Time (Hours)=0;DST-1:Rate Schedule=0Row 1220;Time (Hours)=2700;DST-1:BHP=5696.57428792693;Time (Hours)=0;DST-1:Rate Schedule=0

S. No Test Name Step Name Step

1 Deconvolution 1

2

3

4

5

6

7

8

910

1112

1314

1516

Test Case Number

DECON.panx

17

18

19

20

21

222324

25

2627

28

29

30

31

32

33

34

35

36

37

38


In the same window, click Select All

Click Select All and Save

In the same window, click Select All

Click Select All and Save

Open DECON.panx. Go to Data Preparation > Well, reservoir & Fluid description. Click Analytical model.

In Well, Reservoir & Fluid control Description> Fluid Control tab, check Fluid type is Oil

In Well, Reservoir & Fluid control Description> Well Control tab, check that Principal Well Orientation is Vertical.Click Well Parameters. In Well Parameters window make sure Wellbore Radius is 0.276 ft and Wellbore Storage Model - Classic Wellbore storage. Click OK.

In Well, Reservoir & Fluid control Description> Layer Control tab, click Layer parameters. Check: Formation thickness = 17.5 ft; Porosity= 0.36, Layer Pressure=5000 psia, Layer Temperature = 200 deg F, Water saturation = 0.3 Gas Saturation = 0 and Rock Compressibility = 0.0000e+000. Reservoir model = Radial homogeneous. Click OK.

In Well, Reservoir & Fluid control Description> Layer Control tab, click Layer Fluid parameters. Check for Oil Properties: Bo = 1.2, Uo = 0.5, Ct = 8.2000e-006. Check pressure 5000 psia and Check temperature 200 degF.

Click OK to close the "Oil Fluid Parameters - Layer 1" dialogue.Click OK in the Well, Reservoir & Fluid Description to exit to main Pansystem window.

Go to Data Preparation >> Processing >> Deconvolution >> New

Click Flow Periods. "Flow Period Selection" window appears.In the Flow period selection window, click Clear All.

In the Range Selection select from 1 to 11. Then click Select Range

Click Pressure Periods. "Pressure Period Selection" window appears.In the Pressure Period Selection window, click Clear All.

In the Range Selection select from 1 to 11. Then click Select Range

On the Deconvolution Toolset screen click Advanced button.

On the Deconvolution Toolset screen unckeck Optimize Q

Check Optimize Q.

Click Initialize.

Click Run.Click Plot Test Derivatives.

On the Deconvolution Toolset window click Save.

Click on Data Grid

Go to Data Preparation >> Master data >> Master data

Click on Data Grid

Change Derivative smoothing to 25 nodes and Maximum Iterations to solve to 75. Click OK.

Under Viewbale Plots, check Pressure, Pressure+Rate, Pressure Match, Pressure Derivative, Rate and Rate Match.

In the Derivative Period Selection window select flow period 2, 5, 9, 10 and 13. Click Save.


Under Data file, change from DECON to TEST DESIGN on the drop down menu

Click OK.On the Master Data click OK to close the window.Click on Analysis >> Test Overview

Go to Simulation >> Quick Match.

Click OK on "Closed system" window.

Click Yes.

Click Calculate and then OK/Confirm


On the "Closed System" window, click on Boundary Parameters button

On Navigation Pane make sure the displayed values match the expected results.


The Deconvolution Toolset window will appear

This will unselect all the flow periods

This will select all the flow periodsThis will select first 11 flow periods

Return to Deconvolution Toolset windowThis will unselect all the flow periods

This will select all the flow periodsThis will select first 11 flow periods

Return to Deconvolution Toolset windowAdvanced Deconvolution Options screen shows up

Well, Reservoir & Fluid control Description window should appear.

Text box is disabled or grayed out.

The selected plots will be displayedA Derivative Period Selection appears

A Master Data window appears

An Information dialogue appears

Test Overview plot is displayed

Q value text box gets enabled and should read 1.0E-01. Lambda text box should read 1.0E-01.

Q value text box should read 3.3183503-001. Lambda text box should read 1.472930e+006.

The selected flow periods will appear on the Pressure derivative plot overlaying the deconvolved dataset plot.

The Deconvolution Toolset window should close and the deconvolved plot should now appear on a Log-Log plot.

Grid should contain 1000 rows and 4 columns .Row 1;Elapsed Time (hours)=0.001;Deconvolved Pressure #1:TP1=0.489999999990687;Elapsed Time (hours)=0.00136519;Deconvolved Pressure #1 Deriv:TP1=0.016864764784414Row 500;Elapsed Time (hours)=1.63103;Deconvolved Pressure #1:TP1=51.0800000000017;Elapsed Time (hours)=2.22667;Deconvolved Pressure #1 Deriv:TP1=2.68153208453533Row 1000;Elapsed Time (hours)=2700;Deconvolved Pressure #1:TP1=111.819999999989;Elapsed Time (hours)=0;Deconvolved Pressure #1 Deriv:TP1=0

Grid should contain 1220 rows and 5 columns .Row 1;Time (Hours)=0.0010000000475;TEST DESIGN:Test Rate=2000;TEST DESIGN:Sim P=4990.17123;Time (Hours)=0;TEST DESIGN:Rate Schedule=0Row 610;Time (Hours)=800.002674109027;TEST DESIGN:Test Rate=0;TEST DESIGN:Sim P=3399.438773;Time (Hours)=0;TEST DESIGN:Rate Schedule=0Row 1220;Time (Hours)=2700;TEST DESIGN:Test Rate=2400;TEST DESIGN:Sim P=2706.304072;Time (Hours)=0;TEST DESIGN:Rate Schedule=0

A " Closed System " windows is displayed. Variable well position radio button should be already selected.

A " Closed system " window is displayed. The following values should match: L1 = 1000, L2 = 1000, L3 = 4700; L4 = 5000, Drainage Area = 785.124, Dietz Shape Factor = 0.698418. "No flow " radio button should be already selected for all four the options.

A " Copy Layer Pressure" window appears with Layer Pressure reading 5000 psia and Rate Change Pressure = 4990.171 psia.

A "Quick Match" dialogue appears. Make sure Cs = 0.00999998, k = 91, S = 2.3, L1 = 1000, L2 = 1000, L3 = 4700, L4 = 5000, P_lay = 5000

A Test Ovierview is displayed with the Interpretation matching the Pressure points

Quick Match Results 1 Radial homogeneous Closed system Constant compressibility Cs = 0.01 bbl/psi (k/u)o = 182 md/cp k = 91 md kh = 1592.5 md.ft S = 2.3 L1 NF = 1000 ft L2 NF = 1000 ft L3 NF = 4700 ft L4 NF = 5000 ft Area = 785.124 acres OOIP = 2.2386e+7 STB Pi = 5000 psia

S. No Test Name Step Name Step

1 AGTC_1.panx 1

2

34

567

8

9

10

11

12

Test Case Number

Pressure Decline Analysis

Agarwal Analysis- Rate Time Type curve

13

14

15

1617

18

2 AGRC.panx 1

2

Agarwal Analysis- Rate Cumulative Type curve

3

AGRC_1.panx 4

567

8

9

10

11

12

13

14

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1617

18

19

2021

22


Click on Analysis >> PDA >> AG-RT TC

Click on Data Grid

Click on Analysis >> Tools >> Type curve matchClick on Analysis >> Tools >> Type curve match

Click on Analysis >> Tools >> Confirm Results. Click OK.

Verify the line results displayed in the Line Results tab.

Click OK on the "Closed System" dialogue.

Open AGTC_1.panx. Go to Analysis >> PDA >> Test Overview


On the " Verify Selected Nearest Curve" dialogue, Enter 3 on the Nearest Curve option. Click OK.

Go to Simulation >> Analytical Simulation >> Quick Match

Select Central well position radio button on the "Closed System" dialogue.

Click Calculate then OK/Confirm button.

Go to Simulation >> Analytical Simulation >> Auto Match

Click OK on the Auto Match- Points Selection.

Click OK on the Closed System dialogue.

Click on Data Grid

On the Automatic Matching window, deselect Cs and Sf check buttons.

Click OK.On the Matching Progress window click OK when the iterations are finished. On the Quick Match window click OK/Confirm.

Open AGRC.panx. Go to Analysis >> PDA >> Test Overview

Click on Analysis >> PDA >> AG-RCClick on Data Grid

Click OK. Go to Analysis >> Tools >> Confirm Results

Click on Analysis >> PDA >> AG-RC TC

Click on Analysis >> Tools >> Confirm Results. Click OK.


Open AGRC_1.panx. Go to Analysis >> PDA >> Test Overview


Click on Analysis >> Tools >> Fit Line of known slope. Enter -0.0049 as Line Slope.

Click OK. Select Closed system SSS flow radio button on the "Define Line" dialogue.

On the " Verify Selected Nearest Curve" dialogue, Enter 2 on the Nearest Curve option. Click OK.

Go to Simulation >> Analytical Simulation >> Quick Match

Click OK on the "Closed System" dialogue.Click Calculate then OK/Confirm button.

Go to Simulation >> Analytical Simulation >> Auto Match

Click OK on the Auto Match- Points Selection.

Click OK on the Closed System dialogue.

Select Central well position radio button on the "Closed System" dialogue.

On the Automatic Matching window, deselect Cs and Sf check buttons.

Click OK.On the Matching Progress window click OK when the iterations are finished. On the Quick Match window click OK/Confirm.


A Test Overview Plot appears. Verify by reading the plot title.

A set of type curves are displayedA Verify Selected Nearest Curve dialogue is displayed

A Closed System dialogue appears

A Quick Match dialogue appears.

An Agarwal-Gardner Rate-Time Type Curves plot is displayed. Verify by reading the plot title.

Grid should contain 3000 rows and 4 columns .Row 1;Material Balance Time Np / Q (Days)=0.365;P1:TP1=83.4460665824922;Material Balance Time Np / Q (Days)=0.73;P1 Deriv=166.566928827127Row 1500;Material Balance Time Np / Q (Days)=494.856807191653;P1:TP1=8.1714219141709;Material Balance Time Np / Q (Days)=0;P1 Deriv=0Row 3000;Material Balance Time Np / Q (Days)=954.116251075783;P1:TP1=4.98613734848616;Material Balance Time Np / Q (Days)=0;P1 Deriv=0

Match Results Model 1 Vertical fracture - infinite conductivity Closed system Typecurve Area k kh Xf OOIP Spr

An Automatic Matching dialogue is displayed.


Quick Match Results 1 Vertical fracture - infinite conductivity Closed system - Constant compressibility Cs = 0 bbl/psi (k/u)o = 121.613 md/cp k = 385.393 md kh = 38539.3 md.ft Sf = 0 Xf = 889.724 ft Spr = -7.1476 L NF = 5000 ft Area = 2295.685 acres OOIP = 4.2771e+8 STB Pi = 8623 psia dpS = -0.09676 psi/STB/day

A Closed System dialogue appears Variable well position radio button should be already selected.

On the Navigation Pane, verify the following values: Quick Match Results 1 Vertical fracture - infinite conductivity Closed system Constant compressibility Cs = 0 bbl/psi (k/u)o = 104.136 md/cp k = 330.006 md kh = 33000.6 md.ft Sf = 0 Xf = 500.036 ft Spr = -6.5714 L1 NF = 4657.85 ft L2 NF = 5562.6 ft L3 NF = 4646.57 ft L4 NF = 6992.82 ft Area = 2681.84 acres OOIP = 4.9965e+8 STB Pi = 8623 psia dpS = -0.10389 psi/STB/day


A Rate -Cumulative Pressure Decline Plot is displayed

A Known Line dialogue opens

A Define Line dialogue appears.

A Closed System dialogue appears

Grid should contain 5100 rows and 2 columns .Row 1;Time (Hours)=8.76;PDG#1:P1=8339.56543Row 2550;Time (Hours)=9552.011719;PDG#1:P1=6367.163086Row 5100;Time (Hours)=16140;PDG#1:P1=5556.257324

Grid should contain 3000 rows and 2 columns .Row 1;Normalised Cumulative Production Np / Delta P (Hours)=30.4578143026096;P1:TP1=83.4460665824922Row 1500;Normalised Cumulative Production Np / Delta P (Hours)=4043.68375866251;P1:TP1=8.1714219141709Row 3000;Normalised Cumulative Production Np / Delta P (Hours)=4757.35467428656;P1:TP1=4.98613734848616

Calculated Drainage Area should be 4226.9385. Line Results tab on the Navigation Pane should read Line Results Model 1 Vertical fracture - infinite conductivity Closed system Cartesian Area = 4356.585 acres TP1 J = 55.179 STB/day/psi TP1 OOIP = 8.1166e+8 STB TP1

Agarwal-Gardner Rate-Cumulative Type Curves plot is displayed. Verify Selected Nearest Curve dialogue is also displayed.

Verify the line results displayed after confirming.Cartesian $ Area k kh OOIP Spr Xf

An Automatic Matching dialogue is displayed.

Verify the quick match resulst displayed. Quick Match Results 1 Vertical fracture - infinite conductivity Closed system - Constant compressibility Cs = 0 bbl/psi (k/u)o = 251.833 md/cp k = 798.058 md kh = 79805.8 md.ft Sf = 0 Xf = 459.194 ft Spr = -6.4861 L NF = 5000 ft Area = 2295.685 acres OOIP = 4.2771e+8 STB Pi = 8623 psia dpS = -0.0424 psi/STB/day

A Closed System dialogue appears Variable well position radio button should be already selected.

On the Navigation Pane, verify the following values: Quick Match Results 1 Vertical fracture - infinite conductivity Closed system Constant compressibility Cs = 0 bbl/psi (k/u)o = 251.833 md/cp k = 798.058 md kh = 79805.8 md.ft Sf = 0 Xf = 459.194 ft Spr = -6.4861 L1 NF = 5000 ft L2 NF = 5000 ft L3 NF = 5000 ft L4 NF = 5000 ft Area = 2295.685 acres OOIP = 4.2771e+8 STB Pi = 8623 psia dpS =-0.0424 psi/STB/day


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Finite conductivity fracture

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Click OK.

Click on Data GridRead Grid and Click OK.

Click Analysis.

Open Ex 13.1.panx. Go to Data Preparation > Well, reservoir & Fluid description. Click Analytical model.

In Well, Reservoir & Fluid control Description> Fluid Control tab, check Fluid type is water

In Well, Reservoir & Fluid control Description> Well Control tab, check Principal well orientation is vertical.Click well parameters. In Well Parameters window make sure wellbore radius is 0.25 ft and Wellbore Storage Model - Classic Wellbore storage. Click OK.

In Well, Reservoir & Fluid control Description> Layer Control tab, click Layer parameters. Check: Formation thickness = 106.5 ft; Porosity= 0.124, Layer Pressure=5880 psi, Layer Temperature = 220 F, Water Saturation =1, Gas Saturation = 0 and Rock Compressibility 4.4470e-006. Reservoir Model = Vertical fracture-infinite conductivity. Click OK.

In Well, Reservoir & Fluid control Description> Layer Control tab, click Layer fluid parameter. Check for water properties: Bw = 0.998163, Uw= 0.692926, Cw= 2.5431e-006, ρw= 62.9117.Check Ct= 6.9901e-006. Check pressure 5880 psia and Check temperature 100 degF.

Click OK in the message box. Click OK in the Well, Reservoir & Fluid Description to exit to main pansystem window.

A plot should be already displayed but if not , double click the SimP data set under INJ/FALLOFF in the Navigation Pane


Go to Analysis> Model selection. Click Model.

Confirm Results. Press OK. Verify Line Results

Open Ex 13.1b.panx. Fall Off region is already selected (top black bar).Click Analysis > Conventional Analysis > Log-Log.

Check that Reservoir Model is Vertical fracture -infinite conductivity. Click Cancel.

Go to Analysis > Tools. Select the Zero Slope button. Define the Line type as Late pseudo-radial flow on the message screen. Click OK.

Select the 1/2 Slope button.Define the Line type as Fracture Linear flow. Click OK.

Select the Unit Slope button.Define the Line type as Wellbore storage. Click OK.Line Results are shown on Navigation Pane

Click Type Curves in Analysis > Conventional Analysis

Click on Data Grid

Go to Simulation> Analytical simulation. Click Quick Match.In the Quich Match window input as below:Cs =0, k= 1.53463, Sf =0.01, Xf = 216.2966. Click Calculate. Then Click OK/Confirm. Verify Quick Match Results

Click Auto match. Click OK in the warning message for Auto Match - Points Selection. In the Automatic Matching window Uncheck Cs. All other parameters are checked. Solution method : Adaptive. Click OK.

Click OK/Confirm in the Quick Match window. Verify Quick Match results

Read Grid and Click OK.


Click Next stage

Type Curve Method : Default and Type Curve Starting Stage : Infinite conductivity-vertical fracture should be highlighted. Default Type Curves radio button should be selected.Click OK.

Click Type curve match. In the Verify Selected Nearest Curve window, Enter Nearest curve = 1. Click OK.

In the Navigation Pane, verify Line Results for Type Curves

Click Next Stage. The type curves for bounday will appear. Click Type curve match. In the Verify Selected Nearest Curve window, Enter Nearest curve = 1. Click OK.

Click Confirm Results. Click OK. The results shown now on the Navigation pane should be the ones from the type curve fitting .

Go to Simulation> Analytical simulation. Click quick match.In the Quick match window input should be as below:Cs =0.0408534, k= 0.9692, Sf =0.00423392, Xf = 28.1238. Click Calculate. Then Click OK/Confirm. Verify the Quick Match Results

Click Auto match. Click ok in the warning message for Auto Match - Points Selection. In the Automatic Matching window Cs should be unchecked.All other parameters should be left checked. Solution method : Adaptive. Click OK.Check for results on the Navigation Pane after clicking Ok/Confirm on the Quick Match window.

Click OK in "Well, Reservoir & Fluid Description" window .


Click on Data Grid

Open Ex 13.3.panx. Go to Data Preparation> Well, reservoir & fluid description. Click analytical model.

In "Well, Reservoir & Fluid Description" window, Fluid Control tab, check that fluid type is Water

In Well control tab: click Well parameters, check that Wellbore Radius = 0.229 ft. Click OK.

In Layer control tab, click Layer parameters. Formation Thickness = 26; Porosity= 0.2002, Layer Pressure = 1000 psi, Layer Temperature = 100 degF, Water Saturation 1, Gas Saturation = 0 , Rock Compressibility = 3.6453e-006. Click OK.

In Layer Control tab, click Layer Fluid parameters. Water Properties : Bw = 1.00594, Uw= 0.764539, Cw = 2.6947e-006, Ct = 6.3400e-006. Click OK.

A plot should be already displayed but if not , double click the Pressure data set under PFO-1 in the Navigation Pane

Click Analysis -> Conventional analysis -> Plot types -> Test Overview

Open Example 13.3b.panx.Fall off period is already selected (top black bar). Click Analysis > Conventional Analysis > Log-Log


Confirm Results. Press OK. Verify Line Results

Go to Analysis> Model Selection. Click Model. Select Reservoir Model : Vertical fracture-finite conductivity. Keep other parameters as default. Click OK.

Go to Analysis > Tools. Select the Zero Slope button. Define the Line type as Pseudo-radial flow on the message screen. Click OK.

Select the 1/2 Slope button.Define the Line type as Fracture Linear flow. Click OK

Select the 1/4 Slope button. Define flow regime as fracture bi-linear flow. Enter fracture half length as obtained previously (Xf = 158.51 ft).Click OK.

Select the Unit Slope button.Define the Line type as Wellbore storage. Click OK.

Click on Data Grid

Go to Simulation> Analytical simulation. Click Quick Match.In the Quich Match window input as below:Cs= 0.01 bbl/psi, k = 1.54439, Sf =0.001,Xf = 410.685, Fcd = 4.4119. Click Calculate. Then Click OK/Confirm.

Click Auto Match. Under Auto Match- Points Selection dialogue Click Advanced button.Enter 86 as the Maximum Required number of points under Global Point Selection window.Click OK.Change the number of iterations to 100 under Automatic Matching window.Click OK. The calculation will complete in more than 50 iterations.Click OK. In the Quick Match window click OK/Confirm button. Verify Quick Match Results

Click Type Curves in Analysis > Conventional Analysis. If any points are selected, deselect them by pressing the ESC key on the keyboard and clicking OK.



In the Navigation Pane, Verify Line Results

Type Curve Method : Cinco-Ley and Type Curve Starting Stage : Cinco-Ley and Samaniego:finite conductivity should be highlighted. Default Type Curves radio button should be selected.Click OK.

Verify that these values are displayed on the Navigation Pane

Click Type curve match. In the Verify Selected Nearest Curve window, Eneter Nearest curve = 4. Click OK.

Click Next stage

Click Next stage

Click Next Stage. A set of type curves will appear. Click Type curve match. In the Verify Selected Nearest Curve window, Enter Nearest curve = 1. Click OK.

Click Type curve match. In the Verify Selected Nearest Curve window, Enter Nearest curve = 1. Click OK.

In the Navigation Pane, under Line Results tab, verify the following values:

Click Confirm Results. Click OK. The results shown now on the Navigation pane should be the ones from the type curve fitting .

Go to Simulation> Analytical simulation. Click Quick Match.In the Quich match window input should be as below:Cs =14.585, k= 1009.74, Sf = 0, Xf = 64.6063, Fcd = 20. Click Calculate. Then Click OK/Confirm.Verify Quick Match Results

Click Auto match. Click OK in the warning message for Auto Match - Points Selection. In the Automatic Matching window change k = 0.3; Cs = 0.009; Lower limit for Sf = 0; Lower limit for Fcd = 2, Upper limit for Fcd = 200. All the other parameters should be left as they appear. Click OK. Check for results on the Navigation Pane after clicking Ok/Confirm on the Quick Match window.

Expected Results StatusWell, Reservoir & Fluid control Description wildow will pop up

Message box "Check temperature not equal to Layer temperature". The Check temperature is 100 deg F which is the injection temperature not the reservoir temp.

Validate that a plot is displayed by reading the title text "Data Edit"

Grid should contain 5044 rows and 4 columns .Row 1;Time (Hours)=28.711853;INJ/FALLOFF:Sim P=7376.009238;Time (Hours)=-445;INJ/FALLOFF:Rate Schedule=0Row 2522;Time (Hours)=173.869751;INJ/FALLOFF:Sim P=6405.016785;Time (Hours)=0;INJ/FALLOFF:Rate Schedule=0Row 5044;Time (Hours)=300;INJ/FALLOFF:Sim P=6239.945091;Time (Hours)=0;INJ/FALLOFF:Rate Schedule=0Verify that a plot is being displayed by validating the title text "Test Overview Plot"

Select Analysis Model window will pop up.

Permeability is calculated

Cs is calculated.

Pressure and pressure derivative plot will generate.Verify a plot is generated by reading the title text " Log-Log Plot" and the creation of a new model TP2 under Log-Log in the Navigation pane

Grid should contain 5000 rows and 4 columns .Row 1;Elapsed Time (hours) - Tp=495.0000=0.0499879999999919;Sim P:TP2=28.1713890000001;Elapsed Time (hours) - Tp=495.0000=0.0999760000000265;Sim P Deriv:TP2=23.472093506095Row 2500;Elapsed Time (hours) - Tp=495.0000=124.969482;Sim P:TP2=988.377114;Elapsed Time (hours) - Tp=495.0000=125.01947;Sim P Deriv:TP2=315.499540819495Row 5000;Elapsed Time (hours) - Tp=495.0000=250;Sim P:TP2=1151.074703;Elapsed Time (hours) - Tp=495.0000=0;Sim P Deriv:TP2=0

In the Enter Model Parameter window leave the permeability value as default. This value is the same that was calculated in the earlier step (3.01). Click OK. Xf will be calculated.

Line ResultsModel 1Vertical fracture - infinite conductivityInfinitely actingLog-LogCs = 0.96603 bbl/psi TP2k = 3.0126 md TP2kh = 320.84 md.ft TP2Xf = 121.183 ft TP2

Quick Match Results 1 Vertical fracture - infinite conductivity Infinitely acting Constant compressibility Cs = 0 bbl/psi (k/u)w = 2.2147 md/cp k = 1.5346 md kh = 163.438 md.ft Sf = 0.01 Xf = 216.297 ft Spr = -6.0598 Pi = 5961.683 psia Pi(d) = 6080.483 psia dpSpr = -3910.674 psi

Run will continue and after some iterations (6-10) it will stop . Click OK. Quick Match window will pop up automatically.


Type curve plot will appear. Verify that the plot is generated by reading the text title "Type Curve Plot"


Information window will pop up. Click OK.

Grid should contain 5000 rows and 4 columns .Row 1;Elapsed Time (hours) - Tp=495.0000=0.0499879999999919;Sim P:TP1=28.1713890000001;Elapsed Time (hours) - Tp=495.0000=0.0999760000000265;Sim P Deriv=23.472093506095Row 2500;Elapsed Time (hours) - Tp=495.0000=124.969482;Sim P:TP1=988.377114;Elapsed Time (hours) - Tp=495.0000=125.01947;Sim P Deriv=315.499540819495Row 5000;Elapsed Time (hours) - Tp=495.0000=250;Sim P:TP1=1151.074703;Elapsed Time (hours) - Tp=495.0000=0;Sim P Deriv=0

Verify the following parameters for Type Curve are present: Match Results Model 1 Vertical fracture - infinite conductivity Infinitely acting TypecurveLog-LogCdCskkhSprXf

Verify the presence of following parameters in the line Results for Type Curve Match Results Model 1 Vertical fracture - infinite conductivity Infinitely acting TypecurveLog-LogCdCskkhLSprXf

Verify the following parameters on the Type Curve Results Quick Match Results 2 Vertical fracture - infinite conductivity Infinitely acting Constant compressibility Cs = 0.04085 bbl/psi (k/u)w = 1.3987 md/cp k = 0.9692 md kh = 103.22 md.ft Sf = 0.00423 Xf = 28.124 ft Spr = -4.0255 Pi = 3295.379 psia Pi(d) = 3414.179 psia dpSpr = -4113.455 psi

Verify the presence of following parameters in Quick Quick Match Results 3 Vertical fracture - infinite conductivity Infinitely acting Constant compressibility Cs = 0.04085 bbl/psi (k/u)w = 2.0519 md/cp k = 1.4218 md kh = 151.426 md.ft Sf = 0.02903 Xf = 218.228 ft Spr = -6.0497 Pi = 5867.041 psia Pi(d) = 5985.841 psia dpSpr = -4213.832 psi

Well, Reservoir & Fluid Description window will pop up

Validate that a plot is displayed by reading the title text "Data Edit"

Grid should contain 97 rows and 4 columns .Row 1;Time (Hours)=0.92;PFO-1:Pressure=2603.8;Time (Hours)=-3500;PFO-1:Rate Schedule=0Row 49;Time (Hours)=4.5;PFO-1:Pressure=2338.399902;Time (Hours)=0;PFO-1:Rate Schedule=0Row 97;Time (Hours)=236.5;PFO-1:Pressure=1321;Time (Hours)=0;PFO-1:Rate Schedule=0Verify that a plot is being displayed by validating the tittle text "Text Overview Plot"

Pressure and pressure derivative plot will be displayed. Verify a plot is generated by reading the title text "Log-Log Plot" and the creation of a new data set on the Navigation Pane called TP2 under Log-Log

Permeability is calculated

KfW is calculated

Cs is calculated

Grid should contain 88 rows and 4 columns .Row 1;Elapsed Time (hours) - Tp=3501.0000=4.44444590019799E-07;Pressure:TP2=0.0000489999997626;Elapsed Time (hours) - Tp=3501.0000=0.00100044444458991;Pressure Deriv:TP2=1.86880407779128Row 44;Elapsed Time (hours) - Tp=3501.0000=5.00000044444459;Pressure:TP2=297.8;Elapsed Time (hours) - Tp=3501.0000=6.00000044444459;Pressure Deriv:TP2=103.509952867704Row 88;Elapsed Time (hours) - Tp=3501.0000=230.000000444445;Pressure:TP2=1271.3;Elapsed Time (hours) - Tp=3501.0000=0;Pressure Deriv:TP2=0

In the Enter Model Parameter window leave the permeability value as default. This value is same that was calculated in the earlier step (2911.791). Click OK. Xf will be calculated.

Line ResultsModel 1Vertical fracture - finite conductivityInfinitely actingLog-LogCs = 0.59087 bbl/psi TP2Fcd = 0.84739 TP2k = 2911.791 md TP2kh = 75706.574 md.ft TP2Xf = 158.51 ft TP2kfW = 391109.199 md.ft TP2

Type curve plot will appear

Quick Match Results 1 Vertical fracture - finite conductivity Infinitely acting Constant compressibility Cs = 0.01 bbl/psi (k/u)w = 2.02 md/cp k = 1.5444 md kh = 40.154 md.ft Sf = 0.001 Xf = 410.685 ft Fcd = 4.4119 kfW = 2798.282 md.ft Spr = -6.5076 Pi = 247.527 psia dpSpr = -6124.536 psi

Quick Match Results 1 Vertical fracture - finite conductivity Infinitely acting Constant compressibility Cs = 0.00877 bbl/psi (k/u)w = 0.45612 md/cp k = 0.34872 md kh = 9.0668 md.ft Sf = 0.00135 Xf = 808.752 ft Fcd = 44.119 kfW = 12442.9 md.ft Spr = -7.4246 Pi = -1512.476 psia dpSpr = -30946.182 psi


Grid should contain 88 rows and 4 columns .Row 1;Elapsed Time (hours) - Tp=3501.0000=4.44444590019799E-07;Pressure:TP1=0.0000489999997626;Elapsed Time (hours) - Tp=3501.0000=0.00100044444458991;Pressure Deriv=1.86880407779128Row 44;Elapsed Time (hours) - Tp=3501.0000=5.00000044444459;Pressure:TP1=297.8;Elapsed Time (hours) - Tp=3501.0000=6.00000044444459;Pressure Deriv=103.509952867704Row 88;Elapsed Time (hours) - Tp=3501.0000=230.000000444445;Pressure:TP1=1271.3;Elapsed Time (hours) - Tp=3501.0000=0;Pressure Deriv=0

Match ResultsModel 1Vertical fracture - finite conductivityInfinitely actingTypecurveFcd k kfW kh Spr Xf Log-Log

Match ResultsModel 1Vertical fracture - finite conductivityInfinitely actingTypecurveFcd k kfW kh Spr Xf Log-Log

Information window will pop up. Click OK.

Match ResultsModel 1Vertical fracture - finite conductivityInfinitely actingTypecurveCd Cs Fcdk kfW kfW2 kh Sf SprXf Log-LogCs = 0.59087 bbl/psi TP2Fcd = 26775.269 TP2k = 2911.791 md TP2kfW = 1.6982e+7 md.ft TP2kh = 75706.574 md.ft TP2Xf = 6882.674 ft TP2

Match ResultsModel 1Vertical fracture - finite conductivityInfinitely actingTypecurveCdCs Fcd k kfWkfW2 kh L Sf SprXf Log-Log

Verify the presence of following parametersMatch ResultsModel 1Vertical fracture - finite conductivityInfinitely actingTypecurveCd Cs Fcd k kfW kfW2 kh L Sf Spr Xf Log-Log

Quick Match Results 1 Vertical fracture - finite conductivity Infinitely acting Constant compressibility Cs = 14.585 bbl/psi (k/u)w = 1320.717 md/cp k = 1009.74 md kh = 26253.24 md.ft Sf = 0 Xf = 64.606 ft Fcd = 20 kfW = 1.3047e+6 md.ft Spr = -4.8798 Pi = 2593.225 psia dpSpr = -7.0244 psi

Quick Match Results 1Vertical fracture - finite conductivityInfinitely actingConstant compressibilityCs = 0.00847 bbl/psi(k/u)w = 0.36984 md/cpk = 0.28276 mdkh = 7.3517 md.ftSf = 1.2809e-6Xf = 909.02 ftFcd = 54.642kfW = 14044.78 md.ftSpr = -7.5485Pi = -1662.587 psiadpSpr = -38802.296 psi

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Derivative Smoothing / Log-Log

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Click on Data Grid

Click on Data Grid

Open the PanSystem application by double clicking the shortcut or right click on the short cut and click on Open.

Click on the left hand top corner W (Weatherford symbol)

From the navigation pane, click on Configuration button, then from the context pane, click on units under the configuration menu

From the navigation pane, click on Data Preparation button. Then select "Well, reservoir and fluid description" menu item. Click on "Analytical Model" tool button

From the Navigation pane, click on Import/Export data button. Then select "Import data" menu item. Click on "ASCII" tool button.

Select the first column (using appropiate coordinates) and select time(Hours) radio button. Select the second column and select "Gauge" and choose Pressure (psia) from the drop down menu. Select the third column and select "Gauge" and choose Temperature(deg F) from the drop down menu. Change the Number of lines in header to 5. Click Import . A new window comes up asking to save the template, click NO.

On the Navigation pane, two data files Pressure #1 and Temperature #1 should be cerated under 'New File1.panx -> Well 1 ->Data Set -> Example01_1'.Double click on Pressure # 1.


On the Navigation pane, under the 'New File1.panx -> Well 1 ->Data Set -> Example01_1', double click Temperature #1.

Click on Data Grid

Click on Data Grid


From the Navigation pane, under 'New File1.panx -> Well 1 ->Data Set -> Example01_1', double click Pressure # 1., then the pressure plot is displayed. From the Navigation pane, under the'New File1.panx -> Well 1 ->Data Set -> Example01_1', right click on Temperature # 1 and select "Add to active plot"


Open General_2.panx. From the Navigation plot, double click on the Example01_2:Pressure #1

From the Navigation plot, right click on the Example01_2:Temperature #1 and click on "Add to active plot".

From the Navigation pane, right click on the Example01_2:Pressure #2 and click on "Add to active plot".

From the Navigation pane, right click on the Example01_2:Temperature #2 and click on "Add to active plot".

Open General_3.panx.

Click on Data Grid

Click on Data Grid


Go to Analysis >> Conventional Analysis >> Plot types >> Log-Log

Go to analysis >> Tools >> Analysis Tools >> Derivative smoothing. Then a new window pops up. Make sure that Radial is checked under Smoothing Constants and change it to 0.1. Click OK.


Go to Analysis >> Tools >> Anaysis Tools >> Derivative smoothing. Then a new window pops up. Make sure that Radial is checked under Smoothing Constants and change it to 0.3. Click OK.

Go to Analysis >> Tools >> Floating Line

Go to Analysis >> Tools >> Line details and results.

Click on Data Grid

Click on Data Grid


Click OK.Then press {Delete} on the keyboard.Go to Analysis >> Tools >> Analysis Tools >> Line details and results. Click OK after the Error message.

Go to Analysis >> Conventional Analysis >> Plot Types >> Cartesian


Click OK.Go to Analysis >> Conventional Analysis >> Plot types >> Linear

Go to Analysis >> Conventional Analysis >> Bilinear

Click on Data Grid

Go to Analysis >> Conventional Analysis>> Spherical

Click on Data Grid

Click on Data Grid




Go to Analysis >> Conventional Analysis >> Plot types >> Type Curves


Click on Data Grid

Go to Analysis >> Tools >> Time function

Click OK.

Click on Data Grid


Click OK.

Click on Data Grid

Go to Analysis >> Analysis Tools >> Time function

Click OK.

Click on Data Grid

Go to Analysis >> Conventional Analysis >> Plot types >> Semi-Log





Click OK.

Click on Data Grid

Go to Analysis >> Conventional Analysis >> Cartesian

Go to Analysis >> Analysis Tools >> Time function

Click OK.Go to Analysis >> Plot types >> Linear

Click on Data Grid





Click on Data Grid

Go to Analysis >> Conventional Analysis >> Spherical

Click on Data Grid

Click on Data Grid



Go to Analysis >> Conventional Analysis >> Plot types >> Type Curves



Click OK.Go to Analysis >> Conventional Analysis >> Linear

Click on Data Grid

Go to Analysis >> Conventional Analysis >>Bilinear

Click on Data Grid


Click on Data Grid

Go to Analysis >> Conventional Analysis >>Type Curves

Click on Data Grid





Click OK.Go to Analysis >> Plot types >> Linear

Click on Data Grid


Click on Data Grid





Click on Data Grid

Go to Analysis >> Conventional Analysis >> Type Curves

Click on Data Grid


Click OK.Go to Analysis >> Conventional Analysis >> Linear

Click on Data Grid




Go to Analysis >> Conventional Analysis>> Bilinear

Click on Data Grid


Click on Data Grid


Click on Data Grid




Go to Simulation >> Analytical simulation >> Auto Match.

Click OK on "Automatic Matching" dialogue.

Click OK/Confirm on the " Quick Match" dialogue.

Open General_4.panx file. Click on Analysis >> Conventional Analysis >> Log-Log

Go to Analysis >> Model selection >> Model. A "Select Analysis Model" window is displayed. Under Wellbore Storage Model, select "Fair Wellbore Storage". Click OK.

Go to Simulation >> Analytical simulation >> Quick Match. Enter the following values: Cs = 0.002; Cphi = 600; Tau = 0.15; k = 1.7922; S = -1.0879. Click Calculate . Click OK/Confirm button.

Go to Analysis >> Model selection >> Model. A "Select Analysis Model" window is displayed. Under Wellbore Storage Model, select "Hegeman Wellbore Storage". Click OK.

Go to Simulation >> Analytical simulation >> Auto Match.

Click OK on "Automatic Matching" dialogue.

Click OK/Confirm on the " Quick Match" dialogue.

Go to Simulation >> Analytical simulation >> Quick Match. Enter the following values: Cs = 0.002; Cphi = 600; Tau = 0.15; k = 1.7922; S = -1.0879. Click Calculate . Click OK/Confirm button.


Temperature plot is displayed on the context pane

The PanSystem application opens and the window looks like this

It will show all the tool strip or menu options like new, open, save, save all, save as, send as email, page set up, print, exit PanSystem and recent files

A Units Editor window pops up. Check if the selected untis are OILFABS if not change them to that. Press OK. The figure is shown

A new "Data Set" is created under "NewFile1.panx >> Well 1" the new file on the Navigation Pane.Also, a new window pops up. Make sure Oil is selected as the Fluid Type under Fluid Control tab. Click OK.

A "Select a File" dialogue shows up. Import the data to "Newfile1.panx". Click OK. A new window pops up. Choose Example01_1.tpr file from Ex 1 folder and click Open. Then a new window opens.

Data will be imported. Number of data points imported = 76882. Click OK.

Data will be imported. Number of data points imported = 76882. Click OK.

Grid should have 76882 rows and 2 columns.Row 1: Time (Hours) = 0.3986; Example01_1:Pressure #1 = 15.98; Row 38441: Time (Hours) = 53.7875; Example01_1:Pressure #1 = 6025.392; Row 76882: Time (Hours) = 107.1778; Example01_1:Pressure #1 = 17.783;

Temperature plot is added to the right side axis

Pressure #1 is plotted.

Temperature #1 is added to the display.

Pressure #2 is added to the display.

Temperature #2 is added to the display.

Grid should have 76882 rows and 2 columns.Row 1: Time (Hours) = 0.3986; Example01_1:Temperature #1 = 69.15; Row 38441: Time (Hours) = 53.7875; Example01_1:Temperature #1 = 264.84; Row 76882: Time (Hours) = 107.1778; Example01_1:Temperature #1 = 59.25;

Grid should have 76882 rows and 3 columns.Row 1: Time (Hours) = 0.3986; Example01_1:Pressure #1 = 15.98; Example01_1:Temperature #1 = 69.15; Row 38441: Time (Hours) = 53.7875; Example01_1:Pressure #1 = 6025.392; Example01_1: Temperature #1 = 264.84; Row 76882: Time (Hours) = 107.1778; Example01_1:Pressure #1 = 17.783; Example01_1:Temperature #1 = 59.25;

A Log-Log plot is displayed.

The Log-Log plot changes are displayed.

The Log-Log plot changes are displayed.

Grid should contain 9766 rows and 5 columns .Row 1;Date Time=2/24/1996 5:15:00 PM;Example01_2:Pressure #1=4202.32;Example01_2:Temperature #1=143.2;Example01_2:Pressure #2=4202.05;Example01_2:Temperature #2=143.26Row 4883;Date Time=2/28/1996 2:37:00 AM;Example01_2:Pressure #1=4108.46;Example01_2:Temperature #1=149.02;Example01_2:Pressure #2=4108.46;Example01_2:Temperature #2=149.08Row 9766;Date Time=3/2/1996 12:00:00 PM;Example01_2:Pressure #1=;Example01_2:Temperature #1=;Example01_2:Pressure #2=;Example01_2:Temperature #2=

Grid should have 354 rows and 4 columns.Row 177: Time Hours = 2.31064563049017; Pressure:TP6 = 0.0809814497674417; Equivalent Time (hours) = 2.33245036573404; Pressure Deriv:TP6 = 0.00679860337616354; Row 300: Time Hours= 4.17815986205018; Pressure:TP6 = 0.0847721023255812; Equivalent Time (hours) = 4.18902184905704; Pressure Deriv:TP6 = 0.0068124706476743; Row 346: Time Hours = 5.18431874238706; Pressure:TP6 = 0.0862697627906976; Equivalent Time (hours) = 5.22978557584878; Pressure Deriv:TP6 = 0.00773166988629934;

Grid should contain 354 rows and 4 columns .Row 177;Equivalent Time (hours)=2.31064563049017;Pressure:TP6=0.0809814497674417;Equivalent Time (hours)=2.33245036573404;Pressure Deriv:TP6=0.00617398358717007Row 300;Equivalent Time (hours)=4.17815986205018;Pressure:TP6=0.0847721023255812;Equivalent Time (hours)=2.33245036573404;Pressure Deriv:TP6=0.00617398358717007Row 346;Equivalent Time (hours)=5.18431874238706;Pressure:TP6=0.0862697627906976;Equivalent Time (hours)=5.22978557584878;Pressure Deriv:TP6=0.00709590333173925

A line is plotted across the log-log plot.Verify by reading the Plot title: Log-Log Plot

A Line Results dialogue shows up. Make sure the following values are correct:Line Creation Type: FloatedSlope : 1Intercept: 0.162232159857765Coefficient od Determination : Not UsedLine Type: Free model line

An Error message should show up saying " This button is used to display the results associated with the selected line. Please select a line and repeat".

A Cartesian plot is displayed.Verify by reading the Plot title: Cartesian Plot.

Grid should contain 354 rows and 2 columns .Row 1;Elapsed Time (Hours)=0.00220199999999693;Pressure:TP6=3138.134Row 177;Elapsed Time (Hours)=2.710003;Pressure:TP6=3304.370117Row 354;Elapsed Time (Hours)=8.360001;Pressure:TP6=3316.600098A Linear plot is displayed.Verify by reading the Plot title: Linear Flow Plot

Grid should have 354 rows and 2 columns.Row 1: Time Hours = 4.09819391583492; Pressure:TP6 = 3138.134; Row 177: Time Hours = 2.82248279052878; Pressure:TP6 = 3304.370117; Row 354: Time Hours = 2.1808899036484; Pressure:TP6 = 3316.600098;

A Bilinear plot is displayed.Verify by reading the Plot title: Bilinear Flow Plot

Grid should contain 354 rows and 2 columns .Row 1;Fourth-root Superposition Time Function=1.81092347922252;Pressure:TP6=3138.134Row 177;Fourth-root Superposition Time Function=0.824475674868955;Pressure:TP6=3304.370117Row 354;Fourth-root Superposition Time Function=0.547711360520716;Pressure:TP6=3316.600098

A Spherical plot is displayed.Verify by reading the Plot title: Spherical Flow Plot

Grid should contain 354 rows and 2 columns .Row 1;1/Square-root Superposition Time Function=-21.0608561895171;Pressure:TP6=3138.134Row 177;1/Square-root Superposition Time Function=-0.378073478214254;Pressure:TP6=3304.370117Row 354;1/Square-root Superposition Time Function=-0.145796589994886;Pressure:TP6=3316.600098A Type Curve plot is displayed.Verify by reading the Plot title: Type Curve Plot

Grid should have 354 rows and 4 columns.Row 1: Time Hours = 0.00220168784944564; Pressure:TP1 = 0.00366232558139525; Equivalent Time (hours) = 0.0050003896006015; Pressure Deriv= 0.00868375063778151;Row 177: Time Hours = 2.31064563049017; Pressure:TP1 = 0.0809814497674417; Equivalent Time (hours) = 2.33245036573404; Pressure Deriv = 0.00617398358717007;Row 354: Time Hours = 5.47766116355829; Pressure:TP1 = 0.0866698130232557; Equivalent Time (hours) = 0; Pressure Deriv = 0;

A Semi-Log plot is displayed.Verify by reading the Plot title: Radial Flow Plot

Grid should contain 354 rows and 2 columns .Row 1;Superposition Time Function=7546.27473768899;Pressure:TP6=3138.134Row 177;Superposition Time Function=7.19043248316009;Pressure:TP6=3304.370117Row 354;Superposition Time Function=3.03314515127029;Pressure:TP6=3316.600098A Select Time Function dialogue appears. Select "No history" radio botton only.

A Semi-log plot shows up. Verify by reading the plot title: Radial Flow Plot.

Grid should have 354 rows and 2 columns.Row 1: Time Hours = 0.00220199999999693; Pressure:TP6 = 3138.134; Row 177: Time Hours = 2.710003; Pressure:TP6 = 3304.370117; Row 354: Time Hours = 8.360001; Pressure:TP6 = 3316.600098;

A Select Time Function dialogue appears. Select "Use constant rate history" radio botton and check "Use Horner".


Grid should contain 354 rows and 2 columns .Row 1;Horner Time Function - Tp=8052.98480241074;Pressure:TP6=3138.134Row 177;Horner Time Function - Tp=17.54260181073;Pressure:TP6=3304.370117Row 354;Horner Time Function - Tp=3.12086942751367;Pressure:TP6=3316.600098A Select Time Function dialogue appears. Uncheck "Use Horner"."Use constant rate history" radio botton should be the only one selected.


Grid should contain 354 rows and 2 columns .Row 1;Equivalent Time (CRH) (hours) - Tp=0.00220172656101076;Pressure:TP6=3138.134Row 177;Equivalent Time (CRH) (hours) - Tp=2.35071013687354;Pressure:TP6=3304.370117Row 354;Equivalent Time (CRH) (hours) - Tp=17.7305=5.68125996511466;Pressure:TP6=3316.600098A Select Time Function dialogue appears. Select "Use full history" radio botton only.


Grid should contain 354 rows and 2 columns .Row 1;Equivalent Time (hours)=0.00220168784944564;Pressure:TP6=0.00366232558139525Row 177;Equivalent Time (hours)=2.31064563049017;Pressure:TP6=0.0809814497674417Row 354;Equivalent Time (hours)=5.47766116355829;Pressure:TP6=0.0866698130232557A Cartesian plot is displayed.Verify by reading the Plot title: Cartesian Plot

An Information message should display stating: "Only delta time function allowed on cartesian plot".

A Linear plot is displayed.Verify by reading the Plot title: Linear Flow Plot

Grid should contain 354 rows and 2 columns .Row 1;Square-root Superposition Time Function (hours**0.5)=0.0466507287002969;Pressure:TP6=0.00366232558139525Row 177;Square-root Superposition Time Function (hours**0.5)=1.32236185400644;Pressure:TP6=0.0809814497674417Row 354;Square-root Superposition Time Function (hours**0.5)=1.96395474088681;Pressure:TP6=0.0866698130232557A Bilinear plot is displayed.Verify by reading the Plot title: Bilinear Flow Plot

Grid should contain 354 rows and 2 columns .Row 1;Fourth-root Superposition Time Function (hours**0.25)=0.216553386249543;Pressure:TP6=0.00366232558139525Row 177;Fourth-root Superposition Time Function (hours**0.25)=1.20300119060311;Pressure:TP6=0.0809814497674417Row 354;Fourth-root Superposition Time Function (hours**0.25)=1.47976550495135;Pressure:TP6=0.0866698130232557A Spherical plot is displayed.Verify by reading the Plot title: Spherical Flow Plot

Grid should contain 354 rows and 2 columns .Row 1;1/Square-root Superposition Time Function (hours**-0.5)=21.3104061484206;Pressure:TP6=0.00366232558139525Row 177;1/Square-root Superposition Time Function (hours**-0.5)=0.627623437117789;Pressure:TP6=0.0809814497674417Row 354;1/Square-root Superposition Time Function (hours**-0.5)=0.395346548898421;Pressure:TP6=0.0866698130232557A Type Curve plot is displayed.Verify by reading the Plot title: Type Curve Plot

Grid should contain 354 rows and 4 columns .Row 1;Equivalent Time (hours)=0.00220168784944564;Pressure:TP1=0.00366232558139525;Equivalent Time (hours)=0.0050003896006015;Pressure Deriv=0.00868375063778151Row 177;Equivalent Time (hours)=2.31064563049017;Pressure:TP1=0.0809814497674417;Equivalent Time (hours)=2.33245036573404;Pressure Deriv=0.00617398358717007Row 354;Equivalent Time (hours)=5.47766116355829;Pressure:TP1=0.0866698130232557;Equivalent Time (hours)=0;Pressure Deriv=0

A Select Time Function dialogue appears. Select "No history" radio botton only.


Grid should contain 354 rows and 2 columns .Row 1;Square-root Time (hours**0.5)=0.0469254728265675;Pressure:TP6=3138.134Row 177;Square-root Time (hours**0.5)=1.64620867450029;Pressure:TP6=3304.370117Row 354;Square-root Time (hours**0.5)=2.8913666318888;Pressure:TP6=3316.600098A Bilinear plot is displayed.Verify by reading the Plot title: Bilinear Flow Plot

Grid should contain 354 rows and 2 columns .Row 1;Fourth-root Time (hours**0.25)=0.216622881585874;Pressure:TP6=3138.134Row 177;Fourth-root Time (hours**0.25)=1.28304663769494;Pressure:TP6=3304.370117Row 354;Fourth-root Time (hours**0.25)=1.70040190304787;Pressure:TP6=3316.600098A Spherical plot is displayed.Verify by reading the Plot title: Spherical Flow Plot

Grid should contain 354 rows and 2 columns .Row 1;1/Square-root Time (hours**-0.5)=21.3103872963819;Pressure:TP6=3138.134Row 177;1/Square-root Time (hours**-0.5)=0.607456403000399;Pressure:TP6=3304.370117Row 354;1/Square-root Time (hours**-0.5)=0.345857211247798;Pressure:TP6=3316.600098A Type Curve plot is displayed.Verify by reading the Plot title: Type Curve Plot

Grid should contain 354 rows and 4 columns .Row 1;Elapsed Time (hours)=0.00220199999999693;Pressure:TP1=7.8739999999998;Elapsed Time (hours)=0.00500199999999751;Pressure Deriv=18.6622862774854Row 177;Elapsed Time (hours)=2.710003;Pressure:TP1=174.110117;Elapsed Time (hours)=2.740002;Pressure Deriv=11.4148917755804Row 354;Elapsed Time (hours)=8.360001;Pressure:TP1=186.340098;Elapsed Time (hours)=0;Pressure Deriv=0A Select Time Function dialogue appears. Select "Use constant rate history" radio botton only.


Grid should contain 354 rows and 2 columns .Row 1;Square-root Time (hours**0.5)=0.0469254728265675;Pressure:TP6=3138.134Row 177;Square-root Time (hours**0.5)=1.33585101036454;Pressure:TP6=3304.370117Row 354;Square-root Time (hours**0.5)=1.99423988608754;Pressure:TP6=3316.600098A Bilinear plot is displayed.Verify by reading the Plot title: Bilinear Flow Plot

Grid should contain 354 rows and 2 columns .Row 1;Fourth-root Time (hours**0.25)=0.21655917315592;Pressure:TP6=3138.134Row 177;Fourth-root Time (hours**0.25)=1.2087682545229;Pressure:TP6=3304.37011Row 354;Fourth-root Time (hours**0.25)=1.49235203189363;Pressure:TP6=3316.600098

A Spherical plot is displayed.Verify by reading the Plot title: Spherical Flow Plot

Grid should contain 354 rows and 2 columns .Row 1;1/Square-root Time (hours**-0.5)=21.3104020421187;Pressure:TP6=3138.134Row 177;1/Square-root Time (hours**-0.5)=0.623759002804875;Pressure:TP6=3304.370117Row 354;1/Square-root Time (hours**-0.5)=0.387568413681948;Pressure:TP6=3316.600098A Type Curve plot is displayed.Verify by reading the Plot title: Type Curve Plot

Grid should contain 354 rows and 4 columns .Row 1;Elapsed Time (hours)=0.00220172656101076;Pressure:TP1=7.8739999999998;Elapsed Time (hours)=0.00500058926769529;Pressure Deriv=18.6690995286501Row 177;Elapsed Time (hours)=2.35071013687354;Pressure:TP1=174.110117;Elapsed Time (hours)=2.3732488169843;Pressure Deriv=13.1550618072298Row 354;Elapsed Time (hours)=5.68125996511466;Pressure:TP1=186.340098;Elapsed Time (hours)=0;Pressure Deriv=0A Select Time Function dialogue appears. "Use constant rate history" radio botton should already be selected. Check "Use Horner".


Grid should contain 354 rows and 2 columns .Row 1;Tandem Square-root Function - Tp=4.16409251987825;Pressure:TP6=3138.134Row 177;Tandem Square-root Function - Tp=2.87490551725419;Pressure:TP6=3304.370117Row 354;Tandem Square-root Function - Tp=2.21651664153119;Pressure:TP6=3316.600098

A Bilinear plot is displayed.Verify by reading the Plot title: Bilinear Flow Plot

Grid should contain 354 rows and 2 columns .Row 1;Tandem Fourth-root Function - Tp=1.83545362593153;Pressure:TP6=3138.134Row 177;Tandem Fourth-root Function - Tp=0.843244544564554;Pressure:TP6=3304.370117Row 354;Tandem Fourth-root Function - Tp=0.559660767193823;Pressure:TP6=3316.600098A Spherical plot is displayed.Verify by reading the Plot title: Spherical Flow Plot

Grid should contain 354 rows and 2 columns .Row 1;Tandem 1/Square-root Function - Tp=-21.0729150267948;Pressure:TP6=3138.134Row 177;Tandem 1/Square-root Function - Tp=-0.386271987480927;Pressure:TP6=3304.370117Row 354;Tandem 1/Square-root Function - Tp=-0.150081398358;Pressure:TP6=3316.600098

A Type Curve plot is displayed.Verify by reading the Plot title: Type Curve Plot

Grid should contain 354 rows and 4 columns .Row 1;Equivalent Time (CRH) (hours) - Tp=0.00220172656101076;Pressure:TP1=7.8739999999998;Equivalent Time (CRH) (hours) - Tp=0.00500058926769529;Pressure Deriv=18.6690995286501Row 177;Equivalent Time (CRH) (hours) - Tp=2.35071013687354;Pressure:TP1=174.110117;Equivalent Time (CRH) (hours) - Tp=2.3732488169843;Pressure Deriv=13.1550618072298Row 354;Equivalent Time (CRH) (hours) - Tp=5.68125996511466;Pressure:TP1=186.340098;Equivalent Time (CRH) (hours) - Tp=17.7305=0;Pressure Deriv=0

An "Auto Match - Points Selection" dialogue opens. Click OK.

A Log-Log plot is displayed. Verify by reading the Plot title: Log-Log Plot

Confirm the following Quick Match Results displayed on the Navigation Pane: Quick Match Results 1 Radial homogeneous Infinitely acting Constant compressibility Cs = 0.002 bbl/psi (k/u)o = 2.5603 md/cp Cphi = 600 psi Tau = 0.15 hr k = 1.7922 md kh = 155.921 md.ft S = -1.0879 Pi = 7177.547 psia dpS = -308.954 psi

A " Matching Progress" dialogue opens showing the number of iterations. Click OK when the iterations are finished.

Confirm the following Quick Match Results displayed on the Navigation Pane Quick Match Results 1 Radial homogeneous Infinitely acting Constant compressibility Cs = 0.002 bbl/psi (k/u)o = 2.5603 md/cp Cphi = 600 psi Tau = 0.15 hr k = 1.7922 md kh = 155.921 md.ft S = -1.0879 Pi = 7177.547 psia dpS = -308.954 psi

An "Auto Match - Points Selection" dialogue opens. Click OK.


A " Matching Progress" dialogue opens showing the number of iterations. Click OK when the iterations are finished.



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Oil Well Deliverability

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Enter Bubble Point (Pb) = 2120 psia. Click Calculate.

Click on Data Grid

Open Ex 8.1.panx. In the Navigation panel click Quick Match Results.


Click Ok. Click on Quick Match Results tab on the Navigation Pane.


Click OK. Go to Deliverability >> IPR tab >> Calculate IPR. Under Production Test Data, enter Flowing Pressure = 3429 psia and Flow Rate = 250 STB/day for Test Point1. Click Calculate.

Click OK.

Click on Data Grid

Click Deliverability >> IPR >> IPR Production Test

Click on Data Grid



Click OK. Click Deliverability >> IPR >> IPR Trans/Prod

Click on Data Grid

Enter Layer Pressure = 4310 psia. Click Calculate.

Click Ok.Click Deliverability >> IPR >> IPR Trans/Prod

Click on Data Grid



Enter Layer Pressure back to = 4412 psia. Click Calculate.

Click OK .

Click OK.



Click OK. Go to Deliverability >> Forecasting >> New Forecast.

In the Production Forecasting dialogue, from the drop down menu select Time Units : hours; Start should be 2, enter End = 460 hours, No. of Steps should be 50, Contract t Rate = 0, Minimum Production Rate = 0 .Constant Bottom Hole Pressure radio button should be already selected , enter 3429 psia.

In the Closed System messabe box, slect Central well position radio button.

Click Calculate then click OK/Confirm

Click on Data Grid

Click on Data Grid

Click on Data Grid


Go to Deliverability >> Forecasting >> Q&V v Time Plot


Go to Deliverability >> Forecasting >> V&P v Time Plot

Click on Data Grid

Go to Deliverability >> Forecasting >> New Forecast.

Click OK .

Click OK.


Go to Deliverability >> Forecasting >> P&P v Time Plot


In the Production Forecasting dialogue, from the drop down menu select Time Units : years; Start should be .000228, enter End = 3 years. No. of Steps should be 50, Contract t Rate = 0, Minimum Production Rate = 0 .Constant Bottom Hole Pressure radio button should already be selected, enter 3400 psia.

In the Closed System messabe box, select Central well position radio button.


Click on Data Grid

Click on Data Grid

Click on Data Grid





Click on Data Grid

Go to Deliverability >> Forecasting >> New Forecast.

Click OK .

Click OK.




In the Production Forecasting dialogue, from the drop down menu select Time Units : years; Start should be .000228 and End = 3 years. No. of Steps should be 50, Contract t Rate = 0, Minimum Production Rate = 0 .Select Constant Top Hole Pressure (Import VFP Table) radio button. Click on VFP File Import button.

Locate and select the " Ex_8.1.vfp" file and click on "Open".

In the Production Forecasting dialogue, from the Top Hole Pressure drop down menu select 300.00 psia.

In the Closed System messabe box, slect Central well position radio button.


Click on Data Grid

Click on Data Grid

Click on Data Grid





Click on Data Grid





Productivity Index (J) and AOF will be caculated.

Log-Log plot is displayed. Verify by reading the plot title: Log-Log Plot.On the Navigation pane, verify the following results: Quick Match Results 1Radial homogeneousClosed system - Constant compressibilityCs = 0.00983 bbl/psi(k/u)o = 9.5089 md/cpk = 7.6071 mdkh = 524.892 md.ftS = 6.2758L NF = 1300 ftArea = 155.188 acresOOIP = 2.8521e+6 STBPi = 4412 psiadpS = 383.565 psi

"Transient and Production Test Deliverability Results""dialogue opens. Verifyy that Layer Pressure = 4412; Dietz Shape Factor = 30.8815; Drainage Area = 155.188; k = 7.60713; S = 6.27575; J = 0.283118; AOF = 1244.97.

The IPR from transient analysis will be shown. Verify by reading the plot title: " Sandface Deliverability Plot ". Verify by reading the plot title: Sandface Deliverability Plot.On the Navigation pane, Quick Match Results should display: IPR ResultsRadial homogeneousInfinitely actingIPR-Trans Test J = 0.28311 STB/day/psiAOF = 981.849 STB/day

Grid should contain 200 rows and 2 columns .Row 1;Flow Rate (STB/day)=981.849483219153;IPR-Trans Test=14.6499996185303Row 100;Flow Rate (STB/day)=625.591200254153;IPR-Trans Test=2202.27638171785Row 200;Flow Rate (STB/day)=4.63473974446014E-12;IPR-Trans Test=4411.99999999998"Transient and Production Test Deliverability Results""dialogue opens. After Calculate button is clicked, following values will be calculated: Estimated Shut-in Pressure, Productivity Index (J), AOF.

On the Navigation Pane, verify that the following are shown:IPR ResultsRadial homogeneousInfinitely actingIPR-Trans Test J = 0.28311 STB/day/psiAOF = 981.849 STB/day

Grid should contain 200 rows and 2 columns .Row 1;Flow Rate (STB/day)=981.849483219153;IPR-Trans Test=14.6499996185303Row 100;Flow Rate (STB/day)=625.591200254153;IPR-Trans Test=2202.27638171785Row 200;Flow Rate (STB/day)=4.63473974446014E-12;IPR-Trans Test=4411.99999999998The IPR from production data is shown. Verify by reading the plot title: "Sandface Deliverability Plot". Verify by reading the plot title: Sandface Deliverability Plot.On the Navigation pane, Line Results should display: IPR ResultsRadial homogeneousInfinitely actingIPR-Prod Test J = 0.25432 STB/day/psiAOF = 882.021 STB/day

Grid should contain 200 rows and 4 columns .Row 1;Flow Rate (STB/day)=882.02060959846;IPR-Prod Test=14.6499996185303;Flow Rate (STB/day)=250;IPR- AnnotationIPR-Prod Test=3429Row 100;Flow Rate (STB/day)=561.98464351021;IPR-Prod Test=2202.27638171785;Flow Rate (STB/day)=0;IPR- AnnotationIPR-Prod Test=0Row 200;Flow Rate (STB/day)=4.16350575582724E-12;IPR-Prod Test=4411.99999999998;Flow Rate (STB/day)=0;IPR- AnnotationIPR-Prod Test=0

A comparison plot between IPR from Transient and Production data is shown. Verify by reading the plot title: Sandface Deliverability Plot.On the Navigation pane, Line Results should display: IPR ResultsRadial homogeneousInfinitely actingIPR-Trans Test J = 0.28311 STB/day/psiAOF = 981.849 STB/dayIPR-Prod Test J = 0.25432 STB/day/psiAOF = 882.021 STB/day

Grid should contain 200 rows and 6 columns .Row 1;Flow Rate (STB/day)=981.849483219153;IPR-Trans Test=14.6499996185303;Flow Rate (STB/day)=882.02060959846;IPR-Prod Test=14.6499996185303;Flow Rate (STB/day)=250;IPR- AnnotationIPR-Trans Test=3429Row 100;Flow Rate (STB/day)=625.591200254153;IPR-Trans Test=2202.27638171785;Flow Rate (STB/day)=561.98464351021;IPR-Prod Test=2202.27638171785;Flow Rate (STB/day)=0;IPR- AnnotationIPR-Trans Test=0Row 200;Flow Rate (STB/day)=4.63473974446014E-12;IPR-Trans Test=4411.99999999998;Flow Rate (STB/day)=4.16350575582724E-12;IPR-Prod Test=4411.99999999998;Flow Rate (STB/day)=0;IPR- AnnotationIPR-Trans Test=0"Transient and Production Test Deliverability Results""dialogue opens.

Productivity Index (J) is calculated to be 0.283108 and AOF = 952.972.

A new comparison plot between IPR from Transient and Production data is shown. Verify by reading the plot title: Sandface Deliverability Plot.On the Navigation pane, Line Results should display: IPR ResultsRadial homogeneousInfinitely actingIPR-Trans Test J = 0.28311 STB/day/psiAOF = 952.972 STB/dayIPR-Prod Test J = 0.28377 STB/day/psiAOF = 955.194 STB/day

Productivity Index (J) and AOF values will be calculated.

Production Forecasting dialogue appears.

A Closed System message is displayed.

Grid should contain 200 rows and 6 columns .Row 1;Flow Rate (STB/day)=952.972431854906;IPR-Trans Test=14.6499996185303;Flow Rate (STB/day)=955.194391867521;IPR-Prod Test=14.6499996185303;Flow Rate (STB/day)=250;IPR- AnnotationIPR-Trans Test=3429Row 100;Flow Rate (STB/day)=611.080119166592;IPR-Trans Test=2151.53266312489;Flow Rate (STB/day)=612.504919658091;IPR-Prod Test=2151.53266312489;Flow Rate (STB/day)=0;IPR- AnnotationIPR-Trans Test=0Row 200;Flow Rate (STB/day)=-4.37725420310125E-12;IPR-Trans Test=4310.00000000002;Flow Rate (STB/day)=-4.38746025259358E-12;IPR-Prod Test=4310.00000000002;Flow Rate (STB/day)=0;IPR- AnnotationIPR-Trans Test=0"Transient and Production Test Deliverability Results""dialogue opens.

Forecasting Plot dialogue appears. Verify that k = 7.60713; S = 6.27575; L = 1300.

A Production Forecasting Plot is displayed. Verify by reading the plot title: Production Forecasting Plot. On the Navigation pane also verify the following values:Forecasting ResultsRadial homogeneousClosed system - Constant compressibilityk = 7.6071 mdkh = 524.892 md.ftS = 6.2758L NF = 1300 ftArea = 155.188 acresOOIP = 2.8521e+6 STBBHFP = 3429 psiadpS = 383.565 psi

Grid should contain 50 rows and 2 columns .Row 1;Time (hours)=2;Production Rate=314.997592058595Row 25;Time (hours)=28.6942349518026;Production Rate=284.724071315384Row 50;Time (hours)=460;Production Rate=248.691575217313A Production Forecasting Plot is displayed. Verify by reading the plot title: Production Forecasting Plot.

Grid should contain 50 rows and 3 columns .Row 1;Time (hours)=2;Production Rate=314.989248897063;Cumulative Prod=13.1245520373776Row 25;Time (hours)=28.6942349518026;Production Rate=284.720601134467;Cumulative Prod=339.3002822195Row 50;Time (hours)=460;Production Rate=248.691560262698;Cumulative Prod=5062.99775571533A Production Forecasting Plot is displayed. Verify by reading the plot title: Production Forecasting Plot.



Grid should contain 50 rows and 3 columns .Row 1;Time (hours)=2;Cumulative Prod=13.1245520373776;Av Res Pressure=4412Row 25;Time (hours)=28.6942349518026;Cumulative Prod=339.3002822195;Av Res Pressure=4306.58924142503Row 50;Time (hours)=460;Cumulative Prod=5062.99775571533;Av Res Pressure=4201.47476289849A Production Forecasting Plot is displayed. Verify by reading the plot title: Production Forecasting Plot.

Grid should contain 50 rows and 3 columns .Row 1;Time (hours)=2;Av Res Pressure=4412;BHFP=3429Row 25;Time (hours)=28.6942349518026;Av Res Pressure=4306.58924142503;BHFP=3429Row 50;Time (hours)=460;Av Res Pressure=4201.47476289849;BHFP=3429


A Production Forecasting Plot is displayed. Verify by reading the plot title: Production Forecasting Plot. On the Navigation pane also verify the following values: Forecasting ResultsRadial homogeneousClosed system - Constant compressibilityk = 7.6071 mdkh = 524.892 md.ftS = 6.2758L NF = 1300 ftArea = 155.188 acresOOIP = 2.8521e+6 STBBHFP = 3400 psiadpS = 0 psi

Grid should contain 50 rows and 2 columns .Row 1;Time (years)=0.000228;Production Rate=324.290502013721Row 25;Time (years)=0.0237408102275743;Production Rate=272.232071701978Row 50;Time (years)=3;Production Rate=1.78817066101422A Production Forecasting Plot is displayed. Verify by reading the plot title: Production Forecasting Plot.

Grid should contain 50 rows and 3 columns .Row 1;Time (years)=0.000228;Production Rate=324.290502013721;Cumulative Prod=13.5029700680983Row 25;Time (years)=0.0237408102275743;Production Rate=272.232071701978;Cumulative Prod=2442.21408964847Row 50;Time (years)=3;Production Rate=1.78817066101422;Cumulative Prod=53762.7787656437A Production Forecasting Plot is displayed. Verify by reading the plot title: Production Forecasting Plot.



Grid should contain 50 rows and 3 columns .Row 1;Time (years)=0.000228;Cumulative Prod=13.5029700680983;Av Res Pressure=4412Row 25;Time (years)=0.0237408102275743;Cumulative Prod=2442.21408964847;Av Res Pressure=4243.64150294891Row 50;Time (years)=3;Cumulative Prod=53762.7787656437;Av Res Pressure=3411.66163300093A Production Forecasting Plot is displayed. Verify by reading the plot title: Production Forecasting Plot.

Grid should contain 50 rows and 3 columns .Row 1;Time (years)=0.000228;Av Res Pressure=4412;BHFP=3400Row 25;Time (years)=0.0237408102275743;Av Res Pressure=4243.64150294891;BHFP=3400Row 50;Time (years)=3;Av Res Pressure=3411.66163300093;BHFP=3400

An "Open" Windows dialogue appears. This dialogue should vary from user to user.

Open dialogue closes and Production Forecasting dialogue becomes active. Verify that Ex_8.1.vfp(oilfield units) appears in front of "Current File:"

Three different Top Hole Pressure values should be available (100.00; 200.00; 300.00) from the drop down menu.


A Production Forecasting Plot is displayed. Verify by reading the plot title: Production Forecasting Plot. On the Navigation pane also verify the following values: Forecasting ResultsRadial homogeneousClosed system - Constant compressibilityk = 7.6071 mdkh = 524.892 md.ftS = 6.2758L NF = 1300 ftArea = 155.188 acresOOIP = 2.8521e+6 STBVFP = Ex_8.1.vfpTHP = 300 psiadpS = 0 psi

Grid should contain 50 rows and 2 columns .Row 1;Time (years)=0.000228;Production Rate=390.945612503305Row 25;Time (years)=0.0237408102275743;Production Rate=330.386988337304Row 50;Time (years)=3;Production Rate=2.44196850344861A Production Forecasting Plot is displayed. Verify by reading the plot title: Production Forecasting Plot.

Grid should contain 50 rows and 3 columns .Row 1;Time (years)=0.000228;Production Rate=390.945612503305;Cumulative Prod=16.2783888862189Row 25;Time (years)=0.0237408102275743;Production Rate=330.386988337304;Cumulative Prod=2959.69993943392Row 50;Time (years)=3;Production Rate=2.44196850344861;Cumulative Prod=68875.0702301287A Production Forecasting Plot is displayed. Verify by reading the plot title: Production Forecasting Plot.

Grid should contain 50 rows and 3 columns .Row 1;Time (years)=0.000228;Cumulative Prod=16.2783888862189;Av Res Pressure=4412Row 25;Time (years)=0.0237408102275743;Cumulative Prod=2959.69993943392;Av Res Pressure=4207.8399243029Row 50;Time (years)=3;Cumulative Prod=68875.0702301287;Av Res Pressure=3130.62344250398A Production Forecasting Plot is displayed. Verify by reading the plot title: Production Forecasting Plot.

Grid should contain 50 rows and 3 columns .Row 1;Time (years)=0.000228;Av Res Pressure=4412;THP=300Row 25;Time (years)=0.0237408102275743;Av Res Pressure=4207.8399243029;THP=300Row 50;Time (years)=3;Av Res Pressure=3130.62344250398;THP=300

S. No Test Name Test Case Number Step Name Step1 Example01_1.tpr 1

2

34

5

6

78

9

1011

1213

14

15

16

Data Preparation

17

18

1920

21

22

23

24

25

26

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28

29

30

3132

33

34

35

36Example01_1_1.panx 37

38

39

40

41

42

Example01_1_2.panx 43

44

45

Data Reduction 46

47

48

49

5051

52

53

54

55

56

57

5859

602 Example01_2.tpr 1Data

Preparation

2

34

5

67

8

910

11


Go to Import/Export Data -> ASCII.

Click the button 'Import'.

Click No on the dialog.The number of Imported data points should be shown.

Click the Data Grid button on the toolbar.Verify the data on the grid and Click OK.

Go to Data Preparation -> Gauge Data -> Edit Data

Note the value of Time Hours in the Rows 1 and 2.

Go to Configuration >> Units. Select OILFABS Units under the tab System. Click OK.

Go to Data Preparation >> Well, Reservoir and Fluid Description -> Analytical Model. In the Fluid Control tab, select fluid type as Oil. Click OK.

Click OK. From the Open dialog, change the file type to 'All types'. Browse and locate the file 'Example01_1.tpr'. Click Open.

Click the button Load Template. Browse for the file Example01_1.tpt and click Open.

Click OK. From the left navigation, under the tree NewFile1.panx - > Well1 -> Dataset -> Example01_1, double click the column 'Pressure#1'. Under the same navigation, right click the column 'Temperature#1' and select 'Add to active plot'.

Click the button 'Time Format' on the tool bar. Select 'hhhh:mm:ss' from the dropdown and click OK.

Click the button Time Formats in the tool bar. Select 'Hours' from the dropdown and click OK.

Click the button Function Column. Select the 'Column to function' as 'Time Hours', enter :Start Row=1 End Row=2Shift = 2

Note the number of rows on the grid Edit Data.

Verify the total number of rows.

Choose 'Insert paste above current row'. Click Paste

Choose 'Insert paste below current row'. Click Paste.

Verify the number of rows.

Click the button Copy Data on the toolbar.

Verify the data copied into the document.

Click Delete rows on the toolbar.

Click OK.Similarly, check the function for other columns.

Revert the changes by clicking Function Column, Select the 'Column to function' as 'Time Hours', enter :Start Row=1 End Row=2Shift = -2

Click 'Insert Row'. Enter the following:Start Row: 1Number of Rows: 1Check the radio button Before. Click OK.

Select 2nd Row on the table and click Copy Data on the toolbar.

1. Select the radio button 'Copy Selection' and click OK.2. Select the first row that is blank and click Paste Data button on the tool bar.

Select 4th Row on the table and click Copy Data on the toolbar. Choose Copy Selection and click OK.

Select the first row on Edit Data grid and Click the button 'Paste data' on the toolbar.

Select Row 6 and click 'Copy Data ' on the tool bar. Choose 'Copy Selection' and click OK.

Select the first row on Edit Data grid and Click the button 'Paste data' on the toolbar. Choose 'Copy and Overwrite paste at current row'. Click paste.

Select the radio button 'Copy Entire Table'. Click OK. Create a new MSWord document and paste the copied data of the entire table into it.

Enter First Row = 1 and Last Row = 3. Click Delete.

Click OK on the 'Edit Example01_1' table.

Click OK. Click Confirm on the toolbar. Click OK.

Clear the workspace and open the file Example01_1_1.panx.

Go to Data Preparation -> Processing -> Show no of Points.

Note the number against Number of points within data file. Click OK on the information dilaog.

Outlier Removal: Go to Data Preparation -> Processing -> Data Reduction and smoothing facility. Check the checkbox Reduce Data, go the tab 'Reduce Data' and select the radio button 'Outlier Removal'. Click OK.

Select the plot 'RD1 Example01_1: Pressure#1' and Go to Data Preparation -> Processing -> Show no of Points.Note the number against Number of points within data file. Compare the number with the number noted in Step 38.


Go to Data Preparation -> Processing -> Show no of Points.

Note the number against Number of points within data file. Click OK on the information dilaog.

Go to Data Preparation -> Processing -> Data Reduction and Smoothing facility

Check the 'Reduce Data' checkbox and select the Reduce Data child tab. Select a reduction type, say Outlier Removal. Give the name of the Reduced Output File as 'RD1 Example01_2'

Click Ok. A dialog box with the number of Original, Remaining and Deleted points is displayed. Click OK.Click Confirm on the tool bar. Click OK on the dialog.

Click OK

A Log Log plot should be displayed.

Close the Pansystem.

Select the plot 'RD1 Example01_2' and Go to Data Preparation -> Processing -> Show no of Points.Note the number against Number of points within data file. Compare the number with the number noted in Step 38.

Click the Undo button on the tool bar to undo the last reduction. Click 'Restore all Unconfirmed data changes'.

Click the Confirm button to confirm all the data reductions. Click Ok of the 'Confirmation required' dialog.

Go to Data Preparation -> Processing -> Data Reduction and Smoothing facility

Uncheck the Reduce Data checkbox and check the 'Smooth Data' checkbox and click the Smooth Data child tab. Select the radio button 'Moving Average' under Smoothing type. Check the radio button 'Number of points before and after'and Enter 2675 for the 'Number of points before and after'. Select the column Pressure#1.

Click the button Names. In the 'Smoothed Column Names' dialog, enter SM1 Pressure #1 for the Name of the column. Click OK.

Click Ok on th Enter Reduction/Smoothing Detaills window.


Click the button Data Grid and verify the data displayed. Click Ok after verification.

Open Pan System. Go to Configuration >> Units. Select OILFABS Units System. Click OK.

Go to Import/Export Data -> ASCII.

Click on Import button.Click No.

Click the Data Grid button on the toolbar.Verify the data displayed on the table and Click OK.

Close the PanSystem. Click No on the 'Confirm' dialog.

Go to Data Preparation >> Well, Reservoir and Fluid Description -> Analytical Model. In the Fluid Control tab, select fluid type as Oil. Click OK.

Click OK. From the Open dialog, change the file type to 'All types'. Browse and locate the file 'Example01_2.tpr'. Click Open.

Click the button 'Load Template'. Browse and locate the file Example01_2_1.tpt.

Click Ok. In the left navigation under the tree NewFile1.panx -> Well1 -> Dataset -> Example01_2, Double click the column 'Pressure #1'. Right click on the columns Temperature #1, Pressure #2, Temperature #2 and select 'Add to Active Plot'.

Expected Results StatusPass

Pass

A dialog 'Select a file' should be displayed. PassPass

Pass

Pass

PassThe number of data points imported should be 76882 Pass

The plot should appear as in the screen shot. Pass

PassPass

The column should now be displayed as 'Time hh:mm:ss'.

The column should now be displayed as 'Time Hours'.

A dialog with message 'Do you wish to save a format template?' should be displayed.

Grid should contain 76882 rows and 3 columns .Row 1;Time (Hours)=0.3986;Example01_1:Pressure #1=15.98;Example01_1:Temperature #1=69.15Row 38441;Time (Hours)=53.7875;Example01_1:Pressure #1=6025.392;Example01_1:Temperature #1=264.84Row 76882;Time (Hours)=107.1778;Example01_1:Pressure #1=17.783;Example01_1:Temperature #1=59.25

The values displayed are:0.3986 and 0.4

The number of rows should be 76882

The number of rows should increment by one.(76883)

A 'Copy Options' dialog should be displayed.

A Paste Options dialog should be displayed


A Paste Options dialog should be displayed


A Delete Rows dialog should be displayed.

The value of Time for the selected rows should be shifted by 2. i.e. the values to be displayed are:2.3986 and 2.4 for the rows 1 and 2 respectively.

The values should be reverted to : 0.3986 and 0.4

A new row should be inserted on top of the grid, pointing to Row 1 with the value 0 for all columns.

A new row should be inserted with copied data above the first row. Verify by reading the total number of rows which should be 76884.

A row should be pasted below 1st row with the data that has been copied. Verify the number of rows. The rows should increment by 1.(Total number of rows 76885)

A Paste Options dialog should be displayed. After clicking paste, the current row(1st row) should be overwritten with the copied data.

The total number of rows should not change and should be equal to 76885

The entire table data should be copied into the MSWord document.

The data contained in the Edit table should be copied into the document.

The first three rows should be deleted and the number of rows in the table should be 76882.

An Information dialog should be displayed with a number of points within data file.

A dialog with the count of original points, remaining points and deleted points should be displayed.

After removing the outliers, child nodes 'Pressure#1', 'Temperature#1' and 'Rate Schedule' should be added under the parent node 'RD1 Example01_1' in the left navigation tree.

An Information dialog should be displayed with a number of points within data file. The number of points noted in Step 38 and Step 40 should not be equal.

An Information dialog should be displayed with a number of points within data file.

Enter Reduction/Smoothing Details' window should be opened.

A User defined name can also be given for the Reduced Output File.

The name of the reduced data file ''RD1 Example01_2' should be added to the left navigation pane along with the nodes Pressure#1, Temperature#1 and Rate Schedule..

Verify by reading the plot title.

An Information dialog should be displayed with a number of points within data file. The number of points noted in Step 38 and Step 40 should not be equal.

Enter Reduction/Smoothing Details' window should be opened.

The names of the smoothed columns should be added to the navigation pane.

Grid should contain 2418 rows and 4 columns .Row 1;Elapsed Time (hours)=0.00474699999999473;SM1 Pressure #1:TP10=0.0282541775000004;Elapsed Time (hours)=0.0158469999999937;SM1 Pressure #1 Deriv:TP10=0.0996158505815231Row 1209;Elapsed Time (hours)=1.717247;SM1 Pressure #1:TP10=1.84687549442751;Elapsed Time (hours)=1.73524699999999;SM1 Pressure #1 Deriv:TP10=0.953606448824686Row 2418;Elapsed Time (hours)=3.396447;SM1 Pressure #1:TP10=2.1870091775;Elapsed Time (hours)=0;SM1 Pressure #1 Deriv:TP10=0

A dialog 'Select a file' should be displayed.

A dialog do u wish to save a template is displayed.

A Data View table should be displayed.

PanSystem should be closed without saving the file.

A message box with number of data points imported is displayed.

The table should contain 5 columns and 9766 rows.Row 1: Date Time:2/24/1996 5:15:00 PM; Example01_2:Pressure#1: 4202.32; Example01_2:Temperature#1: 143.2; Example01_2:Pressure#2: 4202.05; Example01_2:Temperature#2: 143.26; Row 4833: Date Time:2/28/1996 2:37:00 AM; Example01_2:Pressure#1: 4108.46; Example01_2:Temperature#1: 149.02; Example01_2:Pressure#2: 4108.46;Example01_2:Temperature#2: 149.08; Row 9766: Date Time3/2/1996 12:00:00 PM; Example01_2:Pressure#1: 1736.85; Example01_2:Temperature#1: 41.95; Example01_2:Pressure#2: 1734.03; Example01_2:Temperature#2: 41.89;

S. No Test Name Test Case Number Step Name Step1 Example2_1_1.panx 1

23

4567

89


11

Basic Analysis Workflow

12

13

14

15


17

1819

20

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22

23

24

25

26

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28

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30

313233

34


36

37

38

39

40

41

42

Test Description (Action)Open file Example2_1_1.panx

Click on Data Grid

Go to Analysis >> Tools >> Derivative SmoothingClick on 'Ok'Go to Analysis >> Tools >> Unit SlopeSelect 'Wellbore Storage' radio button and click on 'Ok'.

Go to Analysis >> Tools >> Zero SlopeSelect 'Radial Flow' radio button and click on 'Ok'.

Go to Analysis >> Tools >> Confirm Results


Clear the workspace and open the file Example2_1_2.panx

Click on 'Ok'

Go to Analysis >> Plot Types >> Semi Log

Click on Data Grid

Go to Simulation >> Analytical Simulation >> Quick Match.

Enter the following values in the window 'Quick Match'Cs = 0.028082 bbl/psik = 176.017 mdS = 0.084476

Click on 'Calculate' button and then click on 'Ok/Confirm' button



Click on 'Ok'. Go to Analysis >> Tools >> Confirm Results

Go to Analysis >> Plot Types >> Type Curves

Go to Analysis >> Tools >> Type CurveMatch

Verify the line results displayed in the left navigation pane under the tab 'Line Results'

Click on the button 'Line details and results' menu item under "Tool" tab


Select the default Td/Cd type-curves for Radial homogeneous reservoir with storage and skin and click on 'Ok'


Go to Analysis >> Tools >> Force type curve parameter

Go to Analysis >> Tools >> Type CurveMatch

Click on 'Ok' Go to Analysis >> Tools >> Confirm ResultsClick on 'Ok'

Enter value 190.0 md in the field 'Permiability' and click on 'Apply'. Click on 'Confirm'.

Go to Simulation >> Analytical Simulation >> Quick Match.Enter the following values in the window 'Quick Match'Cs = 0.028082 bbl/psi k = 176.017 mdS = 0.084476



1. Go to Simulation >> Analytical Simulation >> Quick Match.2. Enter the following values in the window 'Quick Match'Cs = 0.028082 bbl/psi k = 176.017 mdS = 0.084476Click on 'Calculate' button and then click on 'Ok/Confirm' button

Close PAN System.Click on No

Verify the quick match results displayed in the left navigation pane under the tab 'Quick Match Results'

1. Go to Analysis >> Model selection >> Model2. Select 'Single fault' as boundary model and click on 'Ok'

1. Go to Simulation >> Analytical Simulation >> Quick Match.2. Select 'Variable well poisition' radio button again and click on 'Ok' 3. Enter the following values in the window 'Quick Match'Cs = 0.022 bbl/psi k = 180 mdS = 0.3L1 = 500 ftClick on 'Calculate' button and then click on 'Ok/Confirm' button

Verify the quick match results displayed in the left navigation pane under the tab 'Quick Match Results'

Observe the quick match results displayed in the navigation pane. Compare with the 'Pi' value noted in step 41.

Expected Results StatusThe plot 'Log Log plot' should be displayed.

New window 'Derivative Smoothing' should appear

New window 'Define Line' should appear

New window 'Define Line' should appear

New window 'Confirm Results' should appear

Grid should contain 354 rows and 4 columns .Row 1;Equivalent Time (hours)=0.00220168784944564;Pressure:TP6=0.00366232558139525;Equivalent Time (hours)=0.0050003896006015;Pressure Deriv:TP6=0.00868375063778151Row 177;Equivalent Time (hours)=2.31064563049017;Pressure:TP6=0.0809814497674417;Equivalent Time (hours)=2.33245036573404;Pressure Deriv:TP6=0.00619038636912138Row 354;Equivalent Time (hours)=5.47766116355829;Pressure:TP6=0.0866698130232557;Equivalent Time (hours)=0;Pressure Deriv:TP6=0

The following line results should be displayed in the left navigation pane. Line Results Model 1 Radial homogeneous Infinitely acting Log-Log Cs = 0.29793 bbl/psi TP6

The following line results should be displayed in the left navigation pane. Line Results Model 1 Radial homogeneous Infinitely acting Log-Log Cs = 0.29793 bbl/psi TP6 k = 60.977 md TP6 kh = 5975.767 md.ft TP6

New window 'Quick Match' should be displayed

The following line results should be displayed in the left navigation pane.Line Results Model 1 Radial homogeneous Infinitely acting Log-Log Cs = 0.29793 bbl/psi TP6 k = 60.977 md TP6 kh = 5975.772 md.ft TP6 S = -3.4758 TP6

On the Navigation pane, Quick Match Results should display: Quick Match Results 1 Radial homogeneous Infinitely acting Constant compressibility Cs = 0.02808 bbl/psi (k/u)o = 135.398 md/cp k = 176.017 md kh = 17249.666 md.ft S = 0.08448 Pi = 3330.15 psia dpS = 2.242 psi

A plot should appear. Verify by reading the Plot title: Radial Flow Plot

Grid should contain 354 rows and 2 columns .Row 1;Superposition Time Function=7546.27473768899;Pressure:TP6=3138.134Row 177;Superposition Time Function=7.19043248316009;Pressure:TP6=3304.370117Row 354;Superposition Time Function=3.03314515127029;Pressure:TP6=3316.600098

New window 'Confirm Results' should appear. Click OK

New Window 'Select Type Curve' should be displayed.

The following line results should be displayed. Line Results Model 1 Radial homogeneous Infinitely acting Semi-Log dpS = -9.9114 psi TP6 FE = 1.0489 TP6 k = 162.755 md TP6 kh = 15949.986 md.ft TP6 P* = 3332.99 psia TP6 Rinv = 697.438 ft TP6 S = -0.34532 TP6 Log-Log k = 167.629 md TP6 kh = 16427.672 md.ft TP6 S = -0.18752 TP6

A new window 'Line Results' should be displayed showing statistical details about the selected line

The following line results should be displayed. Line Results Model 1 Radial homogeneous Infinitely acting Semi-Log dpS = -9.9114 psi TP6 FE = 1.0489 TP6 k = 162.755 md TP6 kh = 15949.986 md.ft TP6 P* = 3332.99 psia TP6 Rinv = 697.438 ft TP6 S = -0.34532 TP6 Log-Log

A plot should appear. Verify by reading the Plot title: Type Curve Plot

Verify the presence of the following parametersSemi-log Log-Log Cd Cs

New Window 'Select Type Curve' should be displayed.

New window 'Confirm Results' should appear.

New window 'Enter value for Forced Parameter' should be displayed

Verify the presence of the following parametersSemi-log Log-Log Cd Cs

Verify the presence of the following parametersSemi-log Cd CskkhS

The following Quick match results should be displayed.Quick Match Results 1 Radial homogeneous Infinitely acting Constant compressibility Cs = 0.02808 bbl/psi (k/u)o = 135.398 md/cp k = 176.017 md kh = 17249.666 md.ft S = 0.08448 Pi = 3330.15 psia dpS = 2.242 psi

Verify that the Log-Log plot is displayed by reading the Title of the Plot

Click "No" on the Confirm Dialog box

The following Quick match results should be displayed.Quick Match Results 1Radial homogeneousInfinitely actingConstant compressibilityCs = 0.02808 bbl/psi(k/u)o = 135.398 md/cpk = 176.017 mdkh = 17249.666 md.ftS = 0.08448Pi = 3330.15 psiadpS = 2.242 psi

1. New window 'Select Analysis Model' should appear

1. New window 'Single Fault' should appear.2. New window 'Quick match' should appear.3. Observe that by adjusting the distance to perfect the match

The following Quick match results should be displayed Quick Match Results 1 Radial homogeneous Single fault Constant compressibility Cs = 0.022 bbl/psi (k/u)o = 138.462 md/cp k = 180 md kh = 17640 md.ft S = 0.3 L1 NF = 500 ft Pi = 3336.372 psia dpS = 7.7857 psi

Observe that change in the model leads to a change in the value 'Pi'.

S. NO Test Name Test Case Number Step Name Step1 Example3_1_Log.panx 1

2

3

45

6

7

8

Faults and Boundaries

9

10

11

12

13

142 Example 3_1_Semi.panx 1

2

3


45

6

7

8

9

1011

12

13

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15

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17

183 Example3_2_Log.panx 1

2

3

4


5

6

7

8

9

10

11

12

13

14

4 Example3_2_Semi.panx 1

2

3

45

6

7


8

910

11

12

13

14

15

16

17

18

19

205 Example3_3_Log.panx 1

2

3

45


6

7

8

9

10

11

12

13

14

15

16

1718

19

2021

22

6 Example3_3_Semi.panx 1

2

3

45

6

7

8


9

10

11


Click on Data Grid

Open the Pan System application by double clicking the shortcut or right click on the short cut and click on Open.

From the File Menu Select "Open"

Navigate to the location where the files are present and select "Example3_1_Log.panx" file and click on the Open Button on the open dialog box


Click on the "Unit Slope" menu button under "Analysis Tools"

Click on the "Confirm Results" menu item under Analysis Tools and Verify the Line Results

Click on the "Model Selection" menu tab. Then Click on the "Model" Menu item.

Verify the Line results

Close the PAN System

Select "Single Fault" as the Boundary Model. Click on the "OK" button on the Dialog.

Click on "Simulation" on the Navigation Pane and then select "Quick Match" menu item under "Analytical simulation" tab.

Input values for the Quick Match Cs = 0.01 k = 4236S = 3.079 L1 = 465.6

Click on "Calculate" and then "Confirm" button on the Quick Match Window.



Navigate to the location where the files are present and select "Example3_1_Semi.panx" file and click on the Open Button on the open dialog box

Click on Data Grid

Click on Data Grid


Click on the "Model Selection" menu tab. Then Click on the "Model" Menu item.

Click on the Line Results on the Navigation Pane to verify the Line Results

Click on the "Confirm Results" menu item under Analysis Tools

Click on the "Type Curves" menu item under "Conventional analysis" menu Tab.


Verify the Line Results displayed

Close the Pan System

Click on Data Grid

Click on the "Type Curve Match" menu item under Analysis Tools menu tab

Click on the "Type Curve Match" menu item under Analysis Tools menu tab

Click on the "Confirm Results" menu item under Analysis Tools and Verify the "Line Results" on the Navigation Pane

Click on the "Next stage" button to move to the next matching stage and

Click on the "Type Curve Match" menu item under Analysis Tools menu tab.





Verify the Line Results on the Navigation Pane.


1.Click on the "Unit Slope" menu item under Analysis Tools

2 .Verify the Line Results

Click on "Zero Slope" menu item under the "Analysis Tools" menu tab.

Click on "Confirm Results" menu item under "Analysis Tools". Click OK

Verify the Line Results on the Navigation Pane.


Click on the "Model Selection" menu tab. Then Click on the "Model" Menu item and change the "Boundary Model" to "Intersecting faults(90)" from the drop down and Click on OK button


Input values for the Quick Match Cs = 0.0023 k = 51.31S = 1.161L1 = 48.5L2 = 474.4


Verify the Quick match Results

Click on Data Grid

Verify the Line Results on the Navigation Pane





Click on the "Model Selection" menu tab. Then Click on the "Model" Menu item and Verify that the "Boundary Model" is "Intersecting faults(90)" and Click on OK button

Click on Data Grid

Click on the "Type Curves" menu option under "Plot Types"


1. Click on the "Type curve match" menu item under "Analysis Tools".

2. Proceed with the default selection on the "Select Type Curve" dialog box. Click on the "OK" button.

3. Again Click on Type Curve Match and Select the nearest curve to match with the actual curve Ex : 9

Click on the "Confirm Results" menu item under Analysis Tools. Click OK

Verify the Line Results

Click On "Next Stage" menu item under "Analysis Tools" Tab.

Again Click on Type Curve Match and Select the nearest curve to match with the actual curve Ex : 2

Click on the "Confirm Results" menu item under Analysis Tools. Click OK button

And verify the Line Results


Input values for the Quick Match

Cs = 0.002k = 55.05S = 1.605 L1 = 48.4L2 = 366


Click on Data Grid


Verity the Quick Match Results and Plot on the Graph

Note: If a proper match is not found then the match can be refined with Auto Match .






1. Click on the "Model" menu item under "Model Selection" tab

2. Verify that "Parallel faults" is the Boundary Model And Click on "OK" button of the "Select Analysis Model" window.

1.Click on the "Confirm Results" menu item under Analysis Tools.

2. Verify the Line Results


1. Input Values for Quick match WindowCs = 0k = 96.32S = 0.5632L = 140

2. Click on "Calculate" and then "OK/Confirm" button of the Quick match Window. Verify the Quick Match Results and the Graph

1. Click on "Analysis" on the Navigation pane and then "Model" menu item under "Model Selection" tab

2. Select "U-shaped faults" as the Boundary Model from the Drop Down. And Click on "OK" button of the "Select Analysis Model" window.


1. Input Values for the Quick Match Window

Cs = 0k = 96.32S = 0.6223L1 = 160.7L2 = 113.8L3 = 279.9

2. Verify the Quick Match Results and Graph on the Plot.

1. Click on "Analysis" on the Navigation pane and then "Model" menu item under "Model Selection" tab

2. Select "Hegeman Wellbore Storage" as the Wellbore Storage Model from the Drop Down. And Click on "OK" button of the "Select Analysis Model" window.

1. Click on "Simulation" on the Navigation Pane and then select "Quick Match" menu item under "Analytical simulation" tab.

2. Input values for the Quick Match windowCs = 0.1Cphi = 40Tau = 0.45k = 96.32S = 0.6223L1 = 160.7L2 = 113.8L3 = 279.9

Click on Calculate and "OK/Confirm" button on the Quick Match Window

Click on Data Grid

Click on the "Analysis" on the Navigation Pane and then click on "Linear" menu item under "Conventional analysis" menu tab


Click on Data Grid

Close the PAN system

Click on "Semi-Log" menu item under "Conventional analysis" menu tab


Click on Data Grid





Click on the "Confirm Results" menu item under Analysis Tools.

Verify the Line Results on the Navigation pane


Verify the Quick Match results on the Navigation Pane

Close the PAN system

Input values for the Quick Match windowCs = 0.0Cphi = 40Tau = 0.45k = 96.7674S = 0.582548L1 = 160.7L2 = 113.8L3 =339.598

Click on Calculate and "OK/Confirm" button on the Quick Match Window


It will open an "Open Dialog box". Pass

Pass

Pass

Pass

Select Analysis Model Window should pop-up Pass

The Pan System application opens and the window looks like this

Verify that the Log- Log plot should be displayed on the graph by reading the title of the Graph

Grid should contain 197 rows and 4 columns .Row 1;Equivalent Time (hours)=0.00019799753343125;Pressure:TP4=0.00013399453359199;Equivalent Time (hours)=0.000499984271179034;Pressure Deriv:TP4=0.00023792703035236Row 99;Equivalent Time (hours)=2.14671560699831;Pressure:TP4=0.018107927878681;Equivalent Time (hours)=2.20755902971;Pressure Deriv:TP4=0.00119198030190316Row 197;Equivalent Time (hours)=5.18258925925733;Pressure:TP4=0.0193105066125904;Equivalent Time (hours)=0;Pressure Deriv:TP4=0

Fail_Usability issueNeed to scroll axis bar to view entire plot

Select "Wellbore Storage" radio button on the "Define Line" dialog box.

Line Results Model 1 Radial homogeneous Infinitely acting Log-Log Cs = 10.302 bbl/psi TP4 k = 4314.842 md TP4 kh = 349502.185 md.ft TP4 S = 3.2511 TP4

Fail_Encountered issue: mismatch of values:(1) Cs = 11.757(2) Value of S is absent

Pass

Pass

Pass

Click "No" on the Confirm Dialog box PassPass


Pass

Provide the below details when the values are re-assigned due to change in Boundary Model1. Define Line: Single Fault Radial flow2. Define Line: Wellbore Storage

Line Results Model 1 Radial homogeneous Single fault Log-Log Cs = 10.302 bbl/psi TP4 k = 8629.684 md TP4 kh = 699004.371 md.ft TP4

Fail_Encountered issue: mismatch of values:(1) Cs = 11.757

Select "Variable well position" on the "Single Fault" dialog box.

Fail_Encountered Usability issue:Units are absent on this dialog for all these parameters

Quick Match Results 1 Radial homogeneous Single fault Constant compressibility Cs = 0.01 bbl/psi (k/u)o = 1061.654 md/cp k = 4236 md kh = 343116 md.ft S = 3.079 L1 NF = 465.6 ft Pi = 2761.293 psia dpS = 0.00527 psi/STB/day


Verify that the Radial-Flow plot is displayed on the graph by reading the title of the Graph

PassPass

Pass

Pass

Click on the "OK" button on the "Confirm Results" dialog. Pass

Pass

PassPass

Grid should contain 197 rows and 2 columns .Row 1;Equivalent Time (hours)=0.00019799753343125;Pressure:TP4=0.00013399453359199Row 99;Equivalent Time (hours)=2.14671560699831;Pressure:TP4=0.018107927878681Row 197;Equivalent Time (hours)=5.18258925925733;Pressure:TP4=0.0193105066125904Verify that the boundary model is "Single fault" and Click on OK button

Line Results Model 1 Radial homogeneous Single fault Semi-Log dpS = 0.00407 psi/STB/day TP4 k = 3753.726 md TP4 kh = 304051.793 md.ft TP4 L1 = 427.69 ft TP4 Pcalc = 2753.216 psia TP4 Rinv = 1760.133 ft TP4 S = 2.1054 TP4

Verify that the Type Curve Plot is displayed by reading the title of the Plot

Grid should contain 197 rows and 4 columns .Row 1;Equivalent Time (hours)=0.00019799753343125;Pressure:TP1=0.00013399453359199;Equivalent Time (hours)=0.000499984271179034;Pressure Deriv=0.00023792703035236Row 99;Equivalent Time (hours)=2.14671560699831;Pressure:TP1=0.018107927878681;Equivalent Time (hours)=2.20755902971;Pressure Deriv=0.00119198030190316Row 197;Equivalent Time (hours)=5.18258925925733;Pressure:TP1=0.0193105066125904;Equivalent Time (hours)=0;Pressure Deriv=0

Pass

Set the Nearest curve to be 13 Pass

Pass

Pass

Set the Nearest curve to be 4. Click OK Pass



Pass

Pass

Select the Default values in the "Select Type Curve" dialog box.

Verify the following parameters Typecurve Cd Cs k kh S Semi-Log

Verify the presence of the following parametersTypecurveCd = 9758 TP4Cs = 0.48 bbl/psi TP4k = 169579.67 md TP4khSLSemi-Log

Fail_Encountered issue: mismatch of values:(1) Cd = 10354.301(2) Cs = 0.51(3) K = 231523.633



Pass

Pass

Grid should contain 56 rows and 4 columns .Row 1;Elapsed Time (hours) - Tp=150.0115=0.000705000000010614;Pressure:TP2=24.4285159999999;Elapsed Time (hours) - Tp=150.0115=0.00192999999998733;Pressure Deriv:TP2=57.8794644660998Row 28;Elapsed Time (hours) - Tp=150.0115=7.47250299999999;Pressure:TP2=792.25;Elapsed Time (hours) - Tp=150.0115=10.583602;Pressure Deriv:TP2=88.3733233153891Row 56;Elapsed Time (hours) - Tp=150.0115=1849.990005;Pressure:TP2=1148.352539;Elapsed Time (hours) - Tp=150.0115=0;Pressure Deriv:TP2=01. Select "Wellbore Storage" radio button in the "Define Line" dialog box.

2. Line ResultsModel 1Radial homogeneousInfinitely actingLog-LogCs = 0.70856 bbl/psi TP2k = 40.631 md TP2kh = 3981.819 md.ft TP2S = 0.01501 TP2

Fail_Encountered issue:S value is missing in Line Results values

Line ResultsModel 1Radial homogeneousIntersecting faults (90)Log-LogCs = 0.70856 bbl/psi TP2k = 40.631 md TP2kh = 3981.819 md.ft TP2S = 0.01501 TP2


Pass

Pass

Pass

Pass

Click "No" on the Confirm Dialog box Pass

Provide the below details when the values are re-assigned due to change in Boundary Model1. Define Line: Radial Flow2. Define Line: Intersecting fault radial flow3. Define Line: Wellbore Storage

Line ResultsModel 1Radial homogeneousInfinitely actingLog-LogCs = 0.70856 bbl/psi TP2k = 40.631 md TP2kh = 3981.819 md.ft TP2S = 0.01501 TP2

Fail_Encountered issue:(1) Instead of 'Infinitely acting >> application showsIntersecting faults(90)(2) S value is missing in Line Results values

Select "Variable Well Position" radio button on the "Intersecting Faults (90 degrees) dialog box and Click on OK

Quick Match Results 1Radial homogeneousIntersecting faults (90)Constant compressibilityCs = 0.0023 bbl/psi(k/u)o = 39.469 md/cpk = 51.31 mdkh = 5028.38 md.ftS = 1.161L1 NF = 48.5 ftL2 NF = 474.4 ftPi = 9999.115 psiadpS = 105.701 psi

Pass


Pass

PassPass

Pass


Verify that the Radial Flow plot is displayed by reading the Title of the Plot

Grid should contain 56 rows and 2 columns .Row 1;Horner Time Function - Tp=150.0115=212783.278010981;Pressure:TP2=8861.7Row 28;Horner Time Function - Tp=150.0115=21.075134931361;Pressure:TP2=9629.521484Row 56;Horner Time Function - Tp=150.0115=1.08108773863349;Pressure:TP2=9985.624023

Line ResultsModel 1Radial homogeneousIntersecting faults (90)Semi-LogdpS = -118.475 psi TP2FE = 1.1204 TP2k = 32.658 md TP2kh = 3200.458 md.ft TP2L = 208.042 ft TP2P* = 9995.7 psia TP2Rinv = 4647.429 ft TP2S = -0.82826 TP2

Fail_Encountered issue: mismatch of values:(1) P* = 9821.032

Pass

PassPass

Pass

Pass

Verify that the "Type Curve" on the Plot by reading the Title of the Plot.

Modify test case navigationAnalysis >> Conventional Analysis >> Type curvs

Grid should contain 56 rows and 4 columns .Row 1;Elapsed Time (hours) - Tp=150.0115=0.000705000000010614;Pressure:TP1=24.4285159999999;Elapsed Time (hours) - Tp=150.0115=0.00192999999998733;Pressure Deriv=57.8794644660998Row 28;Elapsed Time (hours) - Tp=150.0115=7.47250299999999;Pressure:TP1=792.25;Elapsed Time (hours) - Tp=150.0115=10.583602;Pressure Deriv=88.3733233153891Row 56;Elapsed Time (hours) - Tp=150.0115=1849.990005;Pressure:TP1=1148.352539;Elapsed Time (hours) - Tp=150.0115=0;Pressure Deriv=0Verify the Default values on the Select Type Curve Method dialog box

Type Curve Method : Td/CdType Curve Starting Stage : Radial Homogeneous with storage and skin

Radio button: Default Type Curves

Pass

Pass

Pass

Pass

Pass

Pass

Verify the presence of following parametersTypecurve Cd Cs k kh S Semi-Log

Verify the presence of following parametersTypecurve Cd Cs k kh S L Semi-Log

Select "Variable well position" on the "Intersecting Faults (90 degrees)" dialog box.

Pass



Pass

PassPass

Quick Match Results 1 Radial homogeneous Intersecting faults (90) Constant compressibility Cs = 0.002 bbl/psi (k/u)o = 42.346 md/cp k = 55.05 md kh = 5394.9 md.ft S = 1.605 L1 NF = 48.4 ft L2 NF = 366 ft Pi = 10004.769 psia dpS = 136.197 psi


Verify that the Log-Log plot is displayed by reading the Title of the Plot

Grid should contain 101 rows and 4 columns .Row 1;Equivalent Time (hours) - Tp=14.5394=0.0169801461899915;Pressure:TP2=7.59985300000017;Equivalent Time (hours) - Tp=14.5394=0.0508227251190691;Pressure Deriv:TP2=70.4600009281737Row 51;Equivalent Time (hours) - Tp=14.5394=1.78898894107078;Pressure:TP2=209.520019;Equivalent Time (hours) - Tp=14.5394=1.86695330128167;Pressure Deriv:TP2=25.4752740308657Row 101;Equivalent Time (hours) - Tp=14.5394=8.24723339679747;Pressure:TP2=269.349853;Equivalent Time (hours) - Tp=14.5394=0;Pressure Deriv:TP2=0

1. Verify that "Select Analysis Model" window is displayed Pass

Pass

Line ResultsModel 1Radial homogeneousParallel faultsLog-LogCs = 0.567 bbl/psi TP2k = 93.822 md TP2kh = 28146.702 md.ft TP2S = 0.39963 TP2W = 325.157 ft TP2


1. Click on the OK button of the "Confirm Results" windows

Line Results Model 1 Radial homogeneous Parallel faults Log-Log Cs = 0.567 bbl/psi TP2 k = 93.822 md TP2 kh = 28146.702 md.ft TP2 S = 0.39963 TP2 W = 325.157 ft TP2


Select the "Central well position" radio button on the "Parallel Faults" window and click on OK button

Pass

Pass Re-arrenge the requence of pop-ups

Pass

Pass

Quick Match Results 1 Radial homogeneous Parallel faults - Constant compressibility Cs = 0 bbl/psi (k/u)o = 160.533 md/cp k = 96.32 md kh = 28896 md.ft S = 0.5632 L NF = 140 ft Pi = 3991.053 psia dpS = 16.339 psi

2. After Clicking on OK button verify that the "About to re-assign" information window is popped up.

Select the below options in the "Define Line" window if popped up1. Wellbore Storage2. Radial Flow3. U-shaped hemi-linear flow

Select the "Variable well position" radio button on the "U-Shaped fault" window and click on OK button

1. Click Calculate then Ok/Confirm2. Quick Match Results 1 Radial homogeneous U-shaped faults Constant compressibility Cs = 0 bbl/psi (k/u)o = 160.533 md/cp k = 96.32 md kh = 28896 md.ft S = 0.6223 L1 NF = 160.7 ft L2 NF = 113.8 ft L3 NF = 279.9 ft Pi = 4015.778 psia dpS = 18.054 psi

Pass

Pass

1.Select the "Variable well position" radio button on the "Parallel Faults" window and click on OK button.

2.Quick Match Results 1 Radial homogeneous U-shaped faults Constant compressibility Cs = 0.1 bbl/psi (k/u)o = 160.533 md/cp Cphi = 40 psi Tau = 0.45 hr k = 96.32 md kh = 28896 md.ft S = 0.6223 L1 NF = 160.7 ft L2 NF = 113.8 ft L3 NF = 279.9 ft Pi = 4015.778 psia dpS = 18.054 psi

PassPass

Line Results Model 1 Radial homogeneous U-shaped faults Linear k = 96.32 md TP2 P* = 4006.863 psia TP2 W = 501.459 ft TP2 Log-Log Cs = 0.567 bbl/psi TP2 k = 93.822 md TP2 kh = 28146.702 md.ft TP2 S = 0.39963 TP2 W = 650.315 ft TP2


Grid should contain 101 rows and 4 columns .Row 1;Tandem Square-root Function - Tp=14.5394=3.68490100022458;Pressure:TP2=3675.689941;Tandem Square-root Function - Tp=14.5394=3.68490106190853;Model 1 QM Prs 1=3715.82737214459Row 51;Tandem Square-root Function - Tp=14.5394=2.64349547869814;Pressure:TP2=3877.610107;Tandem Square-root Function - Tp=14.5394=3.12167916880035;Model 1 QM Prs 1=3854.95692513731Row 101;Tandem Square-root Function - Tp=14.5394=1.43080773684594;Pressure:TP2=3937.439941;Tandem Square-root Function - Tp=14.5394=0;Model 1 QM Prs 1=0

PassPass


Verify that the Semi-Log Flow Plot is displayed on the Graph by reading the title of the Plot. Line Results Model 1 Radial homogeneous U-shaped faults Semi-Log dpS = 14.359 psi TP2 FE = 0.93914 TP2 k = 95.258 md TP2 kh = 28577.475 md.ft TP2 P* = 3904.022 psia TP2 Rinv = 920.959 ft TP2 S = 0.4895 TP2 Log-Log Cs = 0.567 bbl/psi TP2 k = 93.822 md TP2 kh = 28146.702 md.ft TP2 S = 0.39963 TP2 W = 650.315 ft TP2 Linear k = 96.32 md TP2 P* = 4006.863 psia TP2 W = 501.459 ft TP2

Fail:Only Log-Log details are displayed.Semi-Log details are absent in line results

Verify that the Data view has 101 Rows and 4 ColumnsRow1: Horner Time Function - Tp=14.5394 = 856.258823529439 ; Pressure:TP2 = 3675.689941 ; Horner Time Function - Tp=14.5394 = 856.259661399698 ; Model 1 QM Prs 1 = 3715.82737214459

Row50: Horner Time Function - Tp=14.5394 = 8.43703324808185 ; Pressure:TP = 3876.699951 ; Horner Time Function - Tp=14.5394 = 27.4665292258344 ;Model 1 QM Prs 1 = 3854.0084314766

Row101: Horner Time Function - Tp=14.5394 = 1.76294271066051 ; Pressure:TP = 3937.439941 ; Horner Time Function - Tp=14.5394 = 0 ; Model 1 QM Prs 1 = 0

Pass


Pass

PassPass

Pass

Pass

Pass


Verify that the Radial Flow plot is displayed by reading the Title of the Plot

Grid should contain 101 rows and 2 columns .Row 1;Horner Time Function - Tp=14.5394=856.258823529439;Pressure:TP2=3675.689941Row 51;Horner Time Function - Tp=14.5394=8.12716035645116;Pressure:TP2=3877.610107Row 101;Horner Time Function - Tp=14.5394=1.76294271066051;Pressure:TP2=3937.439941

Line ResultsModel 1Radial homogeneousU-shaped faultsSemi-Logk = 93.34 md TP2kh = 28002.099 md.ft TP2S = 0.36965 TP2dpS = 11.067 psi TP2FE = 0.95328 TP2P* = 3904.978 psia TP2Rinv = 911.641 ft TP2

Select Variable Well position radio button on "U-Shape fault" dialog box

Pass

Pass


Quick Match Results 1 Radial homogeneous U-shaped faults Constant compressibility Cs = 0 bbl/psi (k/u)o = 161.279 md/cp Cphi = 40 psi Tau = 0.45 hr k = 96.767 md kh = 29030.22 md.ft S = 0.58255 L1 NF = 160.7 ft L2 NF = 113.8 ft L3 NF = 339.598 ft Pi = 4000.876 psia dpS = 16.823 psi

Re-arrenge the requence of pop-ups


23

45

6

7


9

Varying Wellbore Storage

10

11

12

1314

15

16

17

18

1920

21

2223

24

25

2627

2829

30

31

2 Example04_2.pan 1

2

34

Decreasing Wellbore Storage

5

6

78

9

10

11

12

3 Example04_3_1.panx 1

23

4

Increasing wellbore storage –

“humping”

5

6

7


23

4

Alternative interpretation -

1

5

6

7


23

4

5

6

Alternative interpretation -

2

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9



Go to Analysis >> Tools >> Derivative SmoothingCheck the 'Radial' check box and enter value 0.07 in the field for smoothing.Click on 'Ok'

Click on 'Unit Slope' button. In the 'Define Line' dialog displayed select 'Wellbore Storage' radio button.

Click on 'Zero Slope' button. In the 'Define Line' dialog displayed select 'Radial Flow' radio button.



Go to Analysis >> Model Selection >> Model

Enter the following values in the window 'Quick Match'Cs = 0.0015 bbl/psik = 1.774 mdS = -1


Observe the quick match results displayed in the 'Quick Match Results' tab on the left navigation pane

Select 'Fair Wellbore Storage' model option from the dropdown 'Wellbore Storage Model'. Click on 'Ok'

1. Go to Simulation >> Analytical Simulation >> Quick Match. 2. Enter the following values in the window 'Quick Match'.Cs = 0.0015 bbl/psiCPhi = 500 psiaTau = 0.15 hrk = 1.774 mdS = -1Click on 'Calculate' button and then click on 'Ok/Confirm' button

Click on 'Ok' button

Click on 'Ok' buttonClick on 'Ok' button after all iterations are completed



Go to Simulation >> Analytical Simulation >> Auto Match.

Click on 'Ok/Confirm' button

Select 'Hegeman Wellbore Storage' model option from the dropdown 'Wellbore Storage Model'. Click on 'Ok'

Click on 'Ok' buttonClick on 'Ok' button after all iterations are completed

Click on 'Ok/Confirm' button


Click on 'No' button


If Log-Log plot is not displayed then double click on the node 'Log-Log : RD1 EXAMPLE02:TP10'. Go to Simulation >> Analytical Simulation >> Quick Match.Enter the following values in the window 'Quick Match'Cs = 0.0017 bbl/psiCphi = 352.8 psiTau = 0.1765 hrk = 1.903 mdS = -0.8621Click on 'Calculate' button and click on 'Ok' button.

Go to Simulation >> Analytical Simulation >> Auto Match.

Observe the match parameters displayed in the left navigation pane under 'Quick Match Results'

Open file Example04_2.pan by navigating to the path Import/Export Data >> From Pan <= 3.x

Go to Analysis >> Conventional Analysis >> Log - Log

Select 'Fair Wellbore Storage' model option from the dropdown 'Wellbore Storage Model'. Click on 'Ok'



Enter the following values in the window 'Quick Match'Cs = 5.250e-5 bbl/psiCphi = -2800 psiTau = 0.03 hrk = 0.85 mdS = 1.35Click on 'Calculate' button and click on 'Ok/Confirm' button.


1. Go to Simulation >> Analytical Simulation >> Quick Match.2. Enter the following values in the window 'Quick Match'Cs = 6.397e-5 bbl/psiCphi = -2195 psiTau = 0.038 hrk = 0.89 mdS = 1.62Click on 'Calculate' button and click on 'Ok/Confirm' button.



Open file Example04_3_1.panx




1. Go to Simulation >> Analytical Simulation >> Quick Match.2. Enter the following values in the window 'Quick Match'Cs = 0.28 bbl/psiCphi = 1660 psiTau = 2.1 hrk = 67 mdS = -5.85Click on 'Calculate' button and click on 'Ok/Confirm' button.






Select 'Classic Wellbore Storage' model option from the dropdown 'Wellbore Storage Model'. Select 'Dual-Porosity (Pseudo steady state)' option from the dropdown 'Reservoir Model (vertical well). Click on 'Ok'

1. Go to Simulation >> Analytical Simulation >> Quick Match.2. Enter the following values in the window 'Quick Match'Cs = 0.0016 bbl/psik = 1.832 mdS = -0.9515w = 0.3746Lam = 0.0035Click on 'Calculate' button and click on 'Ok/Confirm' button.






Select 'Single fault' option from the dropdown 'Boundary Model' and click on 'Ok'


Select 'Variable well position' radio button and click on 'Ok'

Enter the following values in the window 'Quick Match'Cs = 0.0016 bbl/psik = 3.258 mdS = 0.5644L = 7.863 ftClick on 'Calculate' button and click on 'Ok/Confirm' button.


A dialog 'Derivative Smoothing' should appear


Grid should contain 631 rows and 4 columns .Row 1;Elapsed Time (hours)=0.000225999999997839;P 1432:TP10=0.00560749999999871;Elapsed Time (hours)=0.00162600000000168;P 1432 Deriv:TP10=0.0476997189781562Row 316;Elapsed Time (hours)=0.546025999999998;P 1432:TP10=1.612165;Elapsed Time (hours)=0.548826000000005;P 1432 Deriv:TP10=0.360657338518471Row 631;Elapsed Time (hours)=3.319726;P 1432:TP10=2.1716725;Elapsed Time (hours)=0;P 1432 Deriv:TP10=0

A new Line is displayed in the plot.The following line results should be displayed in the left navigation pane.

Line ResultsModel 1Radial homogeneousInfinitely actingLog-LogCs = 0.01158 bbl/psi TP10

A new Line is displayed in the plot.The following line results should be displayed in the left navigation pane.

Line ResultsModel 1Radial homogeneousInfinitely actingLog-LogCs = 0.01158 bbl/psi TP10k = 5.7653 md TP10kh = 501.579 md.ft TP10

A new window 'Select Analysis Model' is displayed.

1. New window 'Quick Match' should be displayed

The following values in the window 'Quick Match'.

Quick Match Results 1 Radial homogeneous Infinitely acting Constant compressibility Cs = 0.0015 bbl/psi (k/u)o = 2.5343 md/cp k = 1.774 md kh = 154.338 md.ft S = -1 Pi = 7212.035 psia dpS = -286.905 psi

A window 'Automatic Matching' should be displayed.

A window 'Matching Progress' should be displayed.



Quick Match Results 1 Radial homogeneous Infinitely acting Constant compressibility Cs = 0.0015 bbl/psi (k/u)o = 2.5343 md/cp Cphi = 500 psi Tau = 0.15 hr k = 1.774 md kh = 154.338 md.ft S = -1 Pi = 7212.035 psia dpS = -286.905 psi

A window 'Auto Match - Points Selection' should be displayed.

A window 'Quick Match' should be displayed having all the fields filled with data


Quick Match Results 1Radial homogeneousInfinitely actingConstant compressibilityCs = 0.00217 bbl/psi(k/u)o = 2.6367 md/cpCphi = 473.999 psiTau = 0.11713 hrk = 1.8457 mdkh = 160.576 md.ftS = -0.93407Pi = 7192.025 psiadpS = -257.578 psi

A window 'Automatic Matching' should be displayed.

A window 'Matching Progress' should be displayed.

The match should be very close now

The plot 'Test Overview' should be displayed.



Quick Match Results 1Radial homogeneousInfinitely actingConstant compressibilityCs = 0.0017 bbl/psi(k/u)o = 2.7186 md/cpCphi = 352.8 psiTau = 0.1765 hrk = 1.903 mdkh = 165.561 md.ftS = -0.8621Pi = 7182.276 psiadpS = -230.574 psi

A window 'Quick Match' should be displayed having all the fields filled with data

The following values in the window 'Quick Match'.Quick Match Results 1Radial homogeneousInfinitely actingConstant compressibilityCs = 0.00167 bbl/psi(k/u)o = 2.7182 md/cpCphi = 353.261 psiTau = 0.17663 hrk = 1.9027 mdkh = 165.537 md.ftS = -0.86284Pi = 7182.22 psiadpS = -230.806 psi

A new window 'Confirm' should be displayed after clicking on 'Close' button

The application 'PANSystem' should close successfully without any error

A plot should appear. Verify by reading the Plot title: Log-Log Plot





Quick Match Results 1 Radial homogeneous Infinitely acting Constant compressibility Cs = 5.2500e-5 bbl/psi V = 5.6522 bbl (k/u)o = 2.0726 md/cp Cphi = -2800 psi Tau = 0.03 hr k = 0.85 md kh = 10.2 md.ft S = 1.35 Pi = 5133.019 psia dpS = 1086.788 psi


The plot 'Log Log plot' should be displayed.




Quick Match Results 1 Radial homogeneous Infinitely acting Constant compressibility Cs = 6.3970e-5 bbl/psi V = 6.8871 bbl (k/u)o = 2.1701 md/cp Cphi = -2195 psi Tau = 0.038 hr k = 0.89 md kh = 10.68 md.ft S = 1.62 Pi = 5149.746 psia dpS = 1245.532 psi






The following values in the window 'Quick Match'. Quick Match Results 1 Radial homogeneous Infinitely acting Constant compressibility Cs = 0.28 bbl/psi V = 1.6548e+6 bbl (k/u)o = 1.9895 md/cp Cphi = 1660 psi Tau = 2.1 hr k = 67 md kh = 8509 md.ft S = -5.85 Pi = 2240.672 psia dpS = -6238.201 psi





New window 'Single Fault' should be displayed



Quick Match Results 1 Dual-porosity (Pseudo steady state) Infinitely acting Constant compressibility Cs = 0.0016 bbl/psi (k/u)o = 2.6171 md/cp k = 1.832 md kh = 159.384 md.ft S = -0.9515 w = 0.3746 Lam = 0.0035 Pi = 7194.302 psia dpS = -264.347 psi




Quick Match Results 1 Radial homogeneous Single fault Constant compressibility Cs = 0.0016 bbl/psi (k/u)o = 4.6543 md/cp k = 3.258 md kh = 283.446 md.ft S = 0.5644 L1 NF = 7.863 ft Pi = 7216.501 psia dpS = 88.171 psi



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Test Description (Action)Open PanSystem


Click Analysis > Conventional Analysis > Log-Log

Click on Data Grid

In Import/Export Data >> Import Data click on From Pan <=3.x and Open Example05_1.pan

In Data Preparation >>Well, Reservoir & Fluid Description, click on Analytical Model. In the Fluid Control tab, check Fluid type is Oil

In Well, Reservoir & Fluid control Description> Well Control tab, check Principal well orientation is vertical.Click well parameters.

In Well, Reservoir & Fluid control Description> Layer Control tab, click Layer parameters.

In Well, Reservoir & Fluid control Description> Layer Control tab, click Layer fluid parameter.

Click OK in the message box. Click OK in the Well, Reservoir & Fluid Description to exit to main pan system window.

A plot should be already displayed but if not , double click the Pressure data set under Test Overview under Model 1 in Navigation Pane


Clear the Workspace and Open file Example05_1_1.panx

In the Analysis Tools, click on Unit Slope Button and Select "Wellbore Storage" from the Define Line dialogue window.Click Ok

In the Analysis Tools, click on Zero Slope Button and Select "Radial Flow" from the Define Line dialogue window.Click Ok

In the Analysis Tools, click on Unit Slope Button and Select "Closed System PSS Flow" from the Define Line dialogue window.Click Ok

In the navigation pane, Click on Line Results tab for Model 1 and verify the values of Line Result

Click on Confirm Results. Click ok

Go to Simulation> Analytical simulation. Click Quick Match. In the Closed System dialogue box that appears, select Variable well Position and Click OK

Click ok. Click ok on Select Analysis model dialogue box

Close the PAN System application


Open PanSystem


Click on Analysis > Conventional Analysis > Log-Log

Click on Data Grid

In the Quick Match window input as below:Cs =0.0096, k= 7.703, S =6.462, L1 = 1290, L2=1292, L3=1291, L4=1290. Click Calculate. Then Click OK/Confirm.

Go to Analysis > Model Selection > Model and click on Boundary Parameter button in Boundary Model

Enter values of L1 = 1290, L2 = 1292, L3 = 1291, L4 = 1290 if not already present. Click on Calculate

Open Example05_2.panx file from Open menu in the navigation pane.


Clear the Workspace and Open file Example05_2_1.panx

In the navigation pane, verify the Line Results

Go to Analysis >> Model Selection >> ModelSelect Reservoir Model as "Radial Homogenous " and Boundary model as "Closed System". Click OK

Click ok in the Information Message that reads "About to Re-Assign the line types - Enter new line type if prompted"

In the Define Line dialog box, select 'Radial Flow' and click ok

Click on Unit Slope button under Analysis Tools and select the Line Type as "Wellbore Storage" on the Define Line Dialogue box. Click OK

Click on Confirm Results. Click ok

Go to Simulation> Analytical simulation. Click Quick Match. In the Closed System dialogue box that appears, select Variable well Position and Click OK



In the Quick Match window input as below:Cs =0.02, k= 28.18, S =-3.924, L1 = 587.3, L2 = 588, L3 = 588, L4 = 587.3. Click Calculate. Then Click OK/Confirm.

Return to the Test Overview plot by double clicking on Pressure #1 under Test Overview under Model 1 in the Workspace panel in navigation panel

Go to Simulation> Analytical simulation. Click Quick Match. In the Closed System dialogue box that appears, select Central well Position and Click OK

In the Quick Match window Input L = 587.3 ft. Click Calculate. Then Click OK/Confirm.


Well, Reservoir & Fluid control Description window will pop up

In Well Parameters window verify wellbore radius is 0.198 ft. and Wellbore Storage Model - Classic Wellbore storage. Click OK.

Verify Formation thickness = 69 ft.; Porosity= 0.039, Layer Pressure=4412 psi, Layer Temperature = 220 F, Water Saturation =0, Gas Saturation = 0 and Rock Compressibility 0.000e+00. Reservoir Model = Radial Homogeneous. Click OK.

Verify water properties: Bo = 1.136, Uo= 0.8, Co= 0.00e+00.Check Ct= 1.7e-005. Check pressure 4412 psia and Check temperature 220 degF.

Validate that a plot is displayed by reading the title text "Test Overview"

Grid should contain 32 rows and 4 columns .Row 1;Time (Hours)=0;WTEX3:Pressure=4412;Time (Hours)=0;WTEX3:Rate Schedule=0Row 16;Time (Hours)=24.9;WTEX3:Pressure=3555;Time (Hours)=0;WTEX3:Rate Schedule=0Row 32;Time (Hours)=460;WTEX3:Pressure=3429;Time (Hours)=0;WTEX3:Rate Schedule=0Verify that the button is enabled and can be clicked on. Verify that a plot is being displayed by validating the title text "Log-Log Plot"

Grid should contain 31 rows and 4 columns .Row 1;Elapsed Time (hours)=0.0215;Pressure:TP1=26;Elapsed Time (hours)=0.12;Pressure Deriv:TP1=126.165047467447Row 16;Elapsed Time (hours)=29.799999;Pressure:TP1=863;Elapsed Time (hours)=35.799999;Pressure Deriv:TP1=32.7306209645695Row 31;Elapsed Time (hours)=460;Pressure:TP1=983;Elapsed Time (hours)=0;Pressure Deriv:TP1=0Verify by reading the title of the plot "Log-Log" Plot.Verify 3 flow regimes are defined in the plot

Line Results Model 1 Radial homogeneous Closed system Log-Log Area = 0.65588 acres TP1 Cs = 0.23278 bbl/psi TP1 k = 1.4541 md TP1 kh = 100.334 md.ft TP1 OOIP = 12054.004 STB TP1 S = -4.3528 TP1

A Closed System Dialogue box opens

Verify the value of Dietz Shape Factor (Ca) = 30.8815

Verify by reading the plot Title "Test Overview"

Verify by reading the plot Title "Log-Log Plot"

Quick Match Results 1 Radial homogeneous Closed system Constant compressibility Cs = 0.0096 bbl/psi (k/u)o = 9.6288 md/cp k = 7.703 md kh = 531.507 md.ft S = 6.462 L1 NF = 1290 ft L2 NF = 1292 ft L3 NF = 1291 ft L4 NF = 1290 ft Area = 152.988 acres OOIP = 2.8117e+6 STB Pi = 4412 psia dpS = 390.033 psi

A confirmation dialogue box should appear asking for saving current data to file.


Grid should contain 72 rows and 4 columns. Row 1 should read Time Hours = 0, Pressure #1 = 3832, Time (Hours)= -235, X12:Rate Schedule = 0;Row 36 should read Time Hours = 24.000002, Pressure #1 = 4141.299805, Time (Hours) = 0, X12:Rate Schedule = 0;Row 72 should read Time Hours = 60.000175, Pressure #1 = 4154.700195, Time (Hours) = 0, X12:Rate Schedule = 0;

Grid should contain 66 rows and 4 columns . Row 1 should read Time hours = 0.0333283711058579, Pressure #1: Tp2 = 43, Equivalent Time (hours) - Tp=240.00 = 0.083304075089627, Pressure #1 Deriv:Tp2 = 42.7513860578357;Row 33 should read Time hours = 20.1526734339491, Pressure #1: Tp2 = 322, Equivalent Time (hours) - Tp=240.00 = 20.9885964868655, Pressure #1 Deriv:Tp2 = 24.8144187274354;Row 66 should read Time hours = 44.7458785405805, Pressure #1: Tp2 = 330.700195, Equivalent Time (hours) - Tp=240.00 = 0, Pressure #1 Deriv:Tp2 = 0

Verify by reading the title of the plot "Log-Log Plot". Verify a flow regime is defined

Line Results Model 1 Radial homogeneous Closed system Log-Log Cs = 3.59 bbl/psi TP2 k = 33.325 md TP2 kh = 6664.999 md.ft TP2 S = -3.6887 TP2

Verify by reading the title of the plot "Test Overview"

Quick Match Results 1 Radial homogeneous Closed system Constant compressibility Cs = 0.02 bbl/psi (k/u)o = 13.419 md/cp k = 28.18 md kh = 5636 md.ft S = -3.924 L1 NF = 587.3 ft L2 NF = 588 ft L3 NF = 588 ft L4 NF = 587.3 ft Area = 31.711 acres OOIP = 5.3306e+6 STB Pavg = 4154.728 psia Pi = 4525.566 psia dpS = -421.155 psi

Quick Match Results 1 Radial homogeneous Closed system - Constant compressibility Cs = 0.02 bbl/psi (k/u)o = 13.419 md/cp k = 28.18 md kh = 5636 md.ft S = -3.924 L NF = 587.3 ft Area = 31.673 acres OOIP = 5.3243e+6 STB Pavg = 4155.059 psia Pi = 4525.947 psia



S. NO Test Name Test Case Number Step Name Step1 Horizontal Wells Example6_1.panx 1

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Click on Data Grid



Navigate to the location where the files are present and select "Example6_1.panx" file and click on the Open Button on the open dialog box


Click on the "Data Preparation" on the Navigation and click on the "Analytical Model" menu item under Well, reservoir & fluid description menu tab

1. Click on "Well Control" tab and then click on "Well parameters" button.

2. Click on the Cancel button of the Dialog box 'Well Parameters - Well 1'

3. Click on the Cancel button of the Dialog box 'Well , Reservoir & Fluid description'

Click on the "Model Selection" menu tab under Analysis in the Navigation pane. Then Click on the "Model" Menu item.

Click On OK button of the Dialog box




Input Value for Quick Match

Cs = 0.02k = 11.39kz = 0.69S = -0.113Zwd = 0.5Lw = 3737.17

Click on "Calculate "and then "OK/Confirm" button on the Quick Match Window

Verify the Quick Match Results

1.Click on "Simulation" on the Navigation Pane and then select "Auto match" menu item under "Analytical simulation" tab.

2. Click on OK button of the Auto Match -Points Selection dialog box and OK button of the Automatic Matching Window.

Click on OK/Confirm" button on the Quick Match Window


1.Click on Analysis on the Navigation pane and then "Model Selection" menu tab. Then Click on the "Model" Menu item.

2.Click on OK button of the Window.

Input options for the new line Types in the Define Line Dialog.

1. Wellbore Storage2. Vertical Radial Flow3. Linear flow through Layer4. Pseudo -radial flow


1. On the "Closed System" window select "Central Well Position" radio button. Click 'OK'.

2. Input Value for L on the Quick Match Window = 6000 ftand default values for other fields

3. Click on "Calculate "and then "OK/Confirm" button on the Quick Match Window

Verify the Quick match Results on the Navigation Pane

1.Click on "Deliverability" in the navigation pane and then Click on Menu item Calculate IPR under IPR menu tab

2.Input Values for Layer Pressure and Bubble Point

Layer Pressure = 5000Bubble Point = 2000

Enter the flowing Pressure and flow rate in the Production Test Data section and Click on Calculate button.

Input Values for Flowing pressure and flow rate:Flowing Pressure = 3566.3Flow Rate = 5200

Click on Data Grid

Click on Data Grid

1.Change the Layer Pressure = 4770 psia click on Calculate , such that both the Productivity Indices are nearly equal.

2.Click OK button of the "Transient and Production Test Deliverability Results window


Click on the "IPR Trans/Prod" menu item under "IPR" tab

Verify the Quick Match Results and the Plots on the Graph

Click on Data Grid


Select "Analysis" on the Navigation pane and then click on "Semi-Log" menu item under the "Conventional Analysis".


Click on Data Grid

Click on the "Confirm Results" menu item under Analysis Tools and Verify the Line Results on the Navigation Pane for the Current Plot (Semi Log)

1.Select "Analysis" on the Navigation pane and then click on "Linear" menu item under the "Conventional analysis".

2.Click on the "Confirm Results" menu item under Analysis Tools and Verify the Line Results on the Navigation Pane for the Current Plot (Linear)

Select "Analysis" on the Navigation pane and then click on "Type Curves" menu item under the "Conventional analysis".

Verify the Line results for the current Plot (Type Curve)


1.Click on the "Type Curve match" menu item under the "Analysis Tools" tab

2. Click on the "OK" button of the Select Type Curve Window

3. Select Zwd value to be 0.5 and Click OK

Click on the "Type Curve match" menu item under the "Analysis Tools" tab and Select the Nearest curve to be 10 in the "Verify Selected Nearest Curve" window and Click "OK" button of the window.

1.Click the "next Stage"(right arrow) menu item under "Analysis Tools" to move to the next stage.

2. Click on the "Type Curve match" menu item under the "Analysis Tools" tab and Select the Nearest curve to be 13 in the "Verify Selected Nearest Curve" window and Click "OK" button of the window

Click on the "Confirm Results" menu item under Analysis Tools and Verify the Line Results on the Navigation Pane for the Current Plot (Type Curve)

Click on "Simulation" on the Navigation Pane and then select "Quick Match" menu item under "Analytical simulation" tab.Input Values:Cs = 0.0204k = 7.41927kz = 0.9526S =-0.0538Zwd = 0.5Lw= 3732L1 = L2 =L3 =L4 =4000

Verify the Quick Match Results and plot on the Graph.

1.Click on "Simulation" on the Navigation Pane and then select "Auto match" menu item under "Analytical simulation" tab.

2. Click on OK button of the Auto Match -Points Selection dialog box and OK button of the Automatic Matching Window.


It will open an "Open Dialog box". PAss

Pass

PassPass

Pass

Pass

Pass



Grid should contain 73 rows and 4 columns .Row 1;Elapsed Time (hours)=0.001;Pressure:TP1=10;Elapsed Time (hours)=0.0015;Pressure Deriv:TP1=15.2848643403971Row 37;Elapsed Time (hours)=7.1525;Pressure:TP1=351;Elapsed Time (hours)=8.6152;Pressure Deriv:TP1=40.3084732737668Row 73;Elapsed Time (hours)=5801.59082;Pressure:TP1=1433.700928;Elapsed Time (hours)=0;Pressure Deriv:TP1=01.Well , Reservoir & Fluid description dialog box should be opened2. The Fluid Type under "Fluid Control" tab should be "Oil"

1. Verify the below valuesPrincipal Well Orientation = HorizontalWellbore Storage Model = Classic Wellbore Storage

"Principal Well Orientation = Horizontal" option is present on 'Well Control' tab of 'Well, Reservoir & Fluid Description' dialog.

Verify that the Reservoir Model is "Two no-flow boundaries-homogeneous"

Pass

Pass

Pass

Line ResultsModel1Two no-flow boundaries - homogeneousInfinitely actingLog-LogCs = 0.02263 bbl/psi TP1k = 11.157 md TP1Kbar = 3.4325 md TP1kh = 1115.718 md.ft TP1kz = 1.056 md TP1Lw = 3037.903 ft TP1S = -0.29406 TP1Spr = -7.1974 TP1

Fail:Missing data for (1) S (2) Spr

Quick Match Results 1Two no-flow boundaries - homogeneousInfinitely actingConstant compressibilityCs = 0.02 bbl/psi(k/u)o = 13.89 md/cpk = 11.39 mdkz = 0.69 mdkh = 1139 md.ftS = -0.113Zwd = 0.5 decimalLw = 3737.17 ftSpr = -7.7768Pi = 5000 psiadpS = -7.8575 psi

1. Verify that "Auto Match-Points Selection" dialog box is popped up

2. Wait till the Iterations are completed and then Click on OK button

Quick Match Results 1Two no-flow boundaries - homogeneousInfinitely actingConstant compressibilityCs = 0.01853 bbl/psi(k/u)o = 13.077 md/cpk = 10.723 mdkz = 0.74884 mdkh = 1072.28 md.ftS = -0.13271Zwd = 0.68989 decimalLw = 3679.44 ftSpr = -7.749Pi = 5000 psiadpS = -9.2726 psi

1.Select the Boundary model to "Closed System" from the Drop Down.

2. Verify that "Information" dialog is popped up with Text " About to re-assign the line types" and Click on OK button to proceed further.

As there are 4 lines on the graph click on "OK" button of the Define Window after verify/changing the radio button option in the "Define Line" dialog box

Quick Match Results 1Two no-flow boundaries - homogeneousClosed system - Constant compressibilityCs = 0.01853 bbl/psi(k/u)o = 13.077 md/cpk = 10.723 mdkz = 0.74884 mdkh = 1072.28 md.ftS = -0.13271Zwd = 0.68989 decimalLw = 3679.44 ftSpr = -7.3071L NF = 6000 ftArea = 3305.786 acresOOIP = 4.8752e+8 STBPi = 5000 psiadpS = -9.2726 psi

1.Check the Check box "Use Default "against Permeability in the Transient Test Data Section

1.Two Productivity Index values will be displayed one under Transient Test Data and other under Production Test Data section of the Window.

For EX:From transient test analysis: 4.22087 STB/day/psi From production test: 3.62698 STB/day/psi

1.Layer Pressure = 4770

Productivity Index From transient test analysis: 4.22087 STB/day/psi From production test: 4.32001 STB/day/psi

2. Verify the Sandface Deliverability Plot is Displayed

Verify that the Data View has 200 rows and 2 Columns

Row1: Flow Rate(STB/Day) = 16374.5957581852 ; IPR-Trans Test = 14.6499996185303Row100: Flow Rate(STB/Day) = 10086.2898305766 ; IPR-Trans Test = 2380.37688423042Row200: Flow Rate(STB/Day) = 2.68720158030062E-11 ; IPR-Trans Test = 4769.99999999999

IPR ResultsTwo no-flow boundaries - homogeneousInfinitely actingIPR-Trans Test J = 4.2209 STB/day/psiAOF = 16374.596 STB/dayIPR-Prod Test J = 4.32 STB/day/psiAOF = 16759.214 STB/day

Verify that the Data View has 200 rows and 6 ColumnsRow1: Flow Rate(STB/Day) = 16374.5957581852 ; IPR-Trans Test = 14.6499996185303 ;Flow Rate(STB/Day) = 16759.2136562621 ; IPR-Prod Test = 14.6499996185303 ;Flow Rate (STB/day) = 5200 ; IPR-AnnotationIPR-Trans Test = 3566.3

Row100: Flow Rate(STB/Day) = 10086.2898305766 ; IPR-Trans Test = 2380.37688423042 ;Flow Rate(STB/Day) = 10323.2036238281 ; IPR-Prod Test = 2380.37688423042 ;Flow Rate (STB/day) = 0 ; IPR-AnnotationIPR-Trans Test = 0

Row200: Flow Rate(STB/Day) = 2.68720158030062E-11 ; IPR-Trans Test = 4769.99999999999 ; Flow Rate(STB/Day) = 2.75032044068577E-11 ; IPR-Prod Test = 4769.99999999999 ;Flow Rate (STB/day) = 0 ; IPR-AnnotationIPR-Trans Test = 0

Verify that the Radial Flow Plot is Displayed by reading the Name of the Plot

Verify that the Data View has 100 rows and 4 Columns

Row1: Elapsed Time (hours) = 0.001 ; Pressure:TP1 = 4990 ; Elapsed Time (hours) = 0.001 ; Model 1 QM Prs 1 = 4988.64399240113

Row50: Elapsed Time (hours) = 80.345398 ; Pressure:TP1 = 4492 ; Elapsed Time (hours) = 2.22645628116426 ;Model 1 QM Prs 1 = 4691.15120611411

Row100: Elapsed Time (hours) = 0 ; Pressure:TP1 = 0 ; Elapsed Time (hours) = 5801.58954797408 ;Model 1 QM Prs 1 = 3566.5718064824

Verify that the Type Curve Plot is displayed on the Graph

Line ResultsModel1Two no-flow boundaries - homogeneousClosed systemSemi-Logk = 11.586 md TP1Kbar = 2.832 md TP1kh = 1158.569 md.ft TP1kz = 0.69223 md TP1S = -0.12526 TP1Spr = -7.1375 TP1Log-LogCs = 0.02263 bbl/psi TP1Kbar = 2.834 md TP1Lw = 2981.193 ft TP1Spr = -7.1974 TP1

Line ResultsModel1Two no-flow boundaries - homogeneousClosed systemLinearLw = 3218.664 ft TP1Lw.h = 321866.335 ft2 TP1Sconv = 3.6512 TP1Log-LogCs = 0.02263 bbl/psi TP1k = 11.157 md TP1Kbar = 3.2397 md TP1kh = 1115.718 md.ft TP1kz = 0.94072 md TP1S = -0.23908 TP1Spr = -7.1974 TP1Semi-Logk = 11.586 md TP1Kbar = 3.2374 md TP1kh = 1158.569 md.ft TP1kz = 0.90462 md TP1S = -0.23133 TP1Spr = -7.1375 TP1

Verify that the Data view has 73 Rows and 4 ColumnsRow1 :Elapsed Time(hours) = 0.001 ; Pressure: TP1 = 10 ; Elapsed Time(hours) = 0.0015 ; PressureDeriv = 15.2848643403971

Row37 :Elapsed Time(hours) = 7.1525 ; Pressure: TP1 = 351 ; Elapsed Time(hours) = 8.6152 ; PressureDeriv = 40.3084732737668

Row73:Elapsed Time(hours) = 5801.59082 ; Pressure:TP = 1433.700928 ; Elapsed Time(hours) = 0 ; PressureDeriv = 0

1.Default Values under Select Type Cure window:Test curve Method: Unknown Well LengthType Curve Starting Stage: No-flow upper and lower boundariesRadio Button : Default Type Curves

2.Verify that another dialog box is appeared with different values of Zwd

Match Results Model 1 Two no-flow boundaries - homogeneous Closed system Typecurve Zwd Lw.h Sconv Semi-Log Log-Log Linear

Select the Nearest Curve to match with the Curve

Ex: 13

Match Results Model 1 Two no-flow boundaries - homogeneous Closed system Typecurve Cd Cs k Kbar kh kz Lw S Zwd Log-Log Semi-Log

Select "Variable Well Position" on the "Closed System" dialog box

Click Calculate on the Quick match Window and once Calculations are done click on "OK/Confirm" button of the Window

Quick Match Results 1 Two no-flow boundaries - homogeneous Closed system Constant compressibility Cs = 0.0204 bbl/psi (k/u)o = 9.0479 md/cp k = 7.4193 md kz = 0.9526 md kh = 741.927 md.ft S = -0.0538 Zwd = 0.5 decimal Lw = 3732 ft Spr = -7.7672 L1 NF = 4000 ft L2 NF = 4000 ft L3 NF = 4000 ft L4 NF = 4000 ft Area = 1469.238 acres OOIP = 2.1668e+8 STB Pi = 5000 psia dpS = -3.9504 psi

Select "Variable Well Position" on the "Closed System" dialog box

Click "OK/Confirm" button of the Window


Quick Match Results 1Two no-flow boundaries - homogeneousClosed systemConstant compressibilityCs = 0.01851 bbl/psi(k/u)o = 13.932 md/cpk = 11.424 mdkz = 0.78503 mdkh = 1142.39 md.ftS = -0.16302Zwd = 0.67384 decimalLw = 3474.67 ftSpr = -7.6917L1 NF = 38162.9 ftL2 NF = 38541.6 ftL3 NF = 40000 ftL4 NF = 3799.02 ftArea = 75974.898 acresOOIP = 1.1204e+10 STBPi = 5000 psiadpS = -11.413 psi

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Click Calculate.

Open PanSystem. Click Import/Export Data >> From Pan <=3.0 and open the file Example07_1.pan

Go to Data Preparation >> Well, Reservoir and Fluid Description -> Analytical Model. In the Fluid Control tab, select fluid type as Gas.

Under Data Preparation >> Well, Reservoir and Fluid Description -> Analytical Model-> Well Control, select the Principal Well Orientation as 'Vertical'.

Click the Well Parameters button. In the Well Parameters window, input the Wellbore Radius as 0.35ft.

Click OK. Go to the child tab Layer Control. Click the Layer Parameters button and input the following data:Formation thickness: 16 ftPorosity: 0.2Layer Pressure: 7148 psiaLayer Temperature: 283 degFWater Saturation: 0.45

Click OK. Click Layer Fluid Parameters. Check the checkbox 'Use EOS' and click the button 'Gas Composition'.

Input the following values into the Gas Composition dialog.Methane: 76.8Ethane: 8.82Propane: 3.2n-butane: 1.14Iso-butane: 0.49n-pentane: 0.57Iso-pentane: 0.42Hexanes: 0.74C7+: 5.11CO2: 1.54Nitrogen: 1.17

Click OK. Click Calculate.

Click OK.

Click OK. Verify the Edit m(p) table.

Click OK. Click Calculate Table.

Click OK. Select m(p) Table and click Plot.

Click the button Pseudo Tables Select m(p) Table. Click Edit Table and enter the following values:Number of Steps: 201Start Pressure: 0End Pressure: 10000

Click the Data Grid view button present on the tool bar of the plot.

Click Ok on the Data View. Close the m(p) Vs Pressure plot. Select P/Viscosity/Z table. Click Plot.

Open the Line Results tab on the Navigation pane.

Click the Data Grid view button present on the tool bar of the plot. Click OK.

Close the plot Z Factor and Viscosity vs. Pressure'. Click OK to return to 'Gas Fluid Parameters'. Click OK on the 'Information' dialog.

Click OK on the Gas Fluid Parameters window. Click OK on the Well Reservoir and Fluid Description window.


A Log Log Plot should be opened. If the plot is not open, select the plot 'TP2' under Log Log under Model 1, from the navigation pane.

Click Analysis -> Tools -> Unit Slope. Select Wellbore Storage radio button.

Click the Data Grid button on the tool bar. Verify the data view and Click OK.

Click Analysis -> Conventional Analysis -> Semi Log Plot.

Open the Line Results tab on the Navigation pane.



A Log Log Plot should be displayed on opening the file. If the plot displayed is not Log log, then expand the tree 'Log Log' in the navigation pane and double click on 'TP7'

Click the Data Grid button and verify the Data. Click OK.

Go to the Line results tab on the navigation pane.

Click Analysis -> Conventional Analysis -> Semi Log Plot.

Click Confirm Results. Click OK on the Confirm Results dialog.



Verify the Line Results.


A Log Log plot should be shown on opening the file. If not, select the column TP2 TP7 from the navigation pane under Log Log.

Click the Data Grid button and verify the data in the Data View. Click OK.

Clear the workspace and open the File Example07_1_4.panx.

Click Fit Parallel Lines. Select TP5: Radial Flow. Click Ok.

Click Fit Parallel Lines. Select TP6: Radial Flow. Click Ok.

Click the tab Line results and verify the value of k.

Click Analysis -> Skin Analysis ->Skin Vs. Flow Rate.

Click the Data Grid button on the toolbar. Verify the data view grid and click OK.

Go to Analysis -> Skin Analysis -> Rate-Dependent Skin Analysis

Click OK. Check the radio button 'TP3: Radial Flow' in the Define Line dialog. Click OK.

In Tools, Click Fit Parallel Lines. Select TP4: Radial Flow. Click Ok.

Go to Line Results tab and verify the Line Results.

Click OK.

Click the button Data Grid on the tool bar. Veirfy the data view table and click OK.

Click Fit Line of Known slope from Tools and give the slope value as 1.

Select the radio button 'Skin Calculation' on the Define Line dialog.


Select the Semi-log Plot 'TP3 TP4 TP5 TP6'. Click Analysis -> Skin Analysis -> Correct for Rate Dependency. Enter Non-Darcy Flow Coefficient = 4.071.

Click the Data Grid button on the tool bar. Verify the data in the Data View grid.


Select the 'Pressure 1' under Test Overview Plot from the navigation pane. Click Simulation -> Quick Match.

Click Calculate. Click Ok/Confirm. Go to the tab Quick Match Results and verify the results.

Click Calculate. Click Ok/Confirm.

Clear the workspace and open Example07_1_6.panx.

Rerun quick match by changing the P_Lay value to 7155. Click OK/Confirm

Go to Analysis -> Model Selection -> Model.Select 'Closed System' boundary model.

Click the button 'Boundary Parameters'. Enter L1 = L2 = L3 = L4 = 350. Click Calculate.

Click OK to return to 'Select Analysis Model'. Click OK to return to PanSystem main window. Click Ok on the warning message dialog.

Click OK. Go to Simulation -> Quick Match. Check the 'Central Well Position' radio button and click OK.

A Quick Match Results window be displayed

Go to the Quick Match Results tab and verify the results.

Close the PanSystem.

Click the button Data Grid on the tool bar. Verify the data view table and click OK.


Gas Composition window should be displayed.

Gas Gravity value should be calculated and the calculated value should be 0.856340878662931.

Pseudo Table Data dialog should be opened.

The following values should be calculated:Gas Properties: Bg: 0.00350461 Ug: 0.0327313 Cg: 6.7003e-005Water Properties: Bw: 1.06577 Uw: 0.174251 Cw: 3.5256e-006 pw: 58.518Formation and Total Comprssibilities: Cf: 3.6468e-006 Ct: 4.2085e-005 Z: 1.19063

A dialog with message 'Calculations Completed Successfully' is displayed.

The table 'Edit m(p) table' should contain two columns Time Hours and m(p) (psi2/cp(*1E-06)) and 201 rows.

A dialog with message 'Calculations Completed Successfully' is displayed.

The plot m(p) Vs Pressure should be displayed. Verify by reading the plot title.

Grid should contain 200 rows and 2 columns .Row 1;Pressure (psia)=0;m(p)=0Row 100;Pressure (psia)=4950;m(p)=1266.81815325241Row 200;Pressure (psia)=9950;m(p)=3084.091723427The plot 'Z Factor and Viscosity vs. Pressure' should be displayed. Verify by reading the plot title.

Verify by reading the plot title: 'Log Log Plot'

Grid should contain 201 rows and 3 columns .Row 1;Pressure (psia)=0;Viscosity=0.0133049284924256;Z Factor=0.999999905682816Row 101;Pressure (psia)=5000;Viscosity=0.0267978759205;Z Factor=1.0231948352485Row 201;Pressure (psia)=10000;Viscosity=0.0397141191453422;Z Factor=1.42882606944237

Line ResultsModel 1Radial homogeneousInfinitely actingLog-LogCs = 0.14051 bbl/psi TP2k = 2.462 md TP2kh = 39.392 md.ft TP2S = -0.93889 TP2V = 2097.023 bbl TP2

Grid should contain 31 rows and 4 columns .Row 1;Elapsed Time (hours) - Tp=3.0000=0.0999990000000004;Pressure 1:TP2=329.250977416;Elapsed Time (hours) - Tp=3.0000=0.199999999999999;Pressure 1 Deriv:TP2=758.780058165661Row 16;Elapsed Time (hours) - Tp=3.0000=1.600003;Pressure 1:TP2=1547.27433360385;Elapsed Time (hours) - Tp=3.0000=1.700003;Pressure 1 Deriv:TP2=172.195177466834Row 31;Elapsed Time (hours) - Tp=3.0000=3.058037;Pressure 1:TP2=1609.2524183536;Elapsed Time (hours) - Tp=3.0000=0;Pressure 1 Deriv:TP2=0

Verify by reading the plot title 'Radial Flow'

Verify by reading the plot title: 'Log Log Plot'

Grid should contain 31 rows and 2 columns .Row 1;Horner Time Function - Tp=3.0000=30.9999699996999;Pressure 1:TP2=713.014282Row 16;Horner Time Function - Tp=3.0000=2.87497585942026;Pressure 1:TP2=1931.03763818785Row 31;Horner Time Function - Tp=3.0000=1.98101069411521;Pressure 1:TP2=1993.0157229376Line ResultsModel 1Radial homogeneousInfinitely actingSemi-LogdpS = -792.301 psi TP2FE = 1.1188 TP2k = 2.4714 md TP2kh = 39.542 md.ft TP2P* = 7235.123 psia TP2Rinv = 151.89 ft TP2S = -0.62514 TP2Log-LogCs = 0.14051 bbl/psi TP2k = 2.462 md TP2kh = 39.392 md.ft TP2S = -0.93889 TP2V = 2097.023 bbl TP2

Verify the plot title by reading 'Radial Flow Plot'.

Grid should contain 99 rows and 4 columns .Row 1;Elapsed Time (hours)=0.0999910000000029;Pressure 1:TP7=84.1354914109001;Elapsed Time (hours)=0.200001;Pressure 1 Deriv:TP7=11.388411350445Row 50;Elapsed Time (hours)=5.066658;Pressure 1:TP7=122.414035854732;Elapsed Time (hours)=5.166661;Pressure 1 Deriv:TP7=9.51301472131678Row 99;Elapsed Time (hours)=10.066658;Pressure 1:TP7=126.806201320178;Elapsed Time (hours)=0;Pressure 1 Deriv:TP7=0

Line ResultsModel 1Radial homogeneousInfinitely actingLog-Logk = 3.2303 md TP7kh = 51.684 md.ft TP7S = -0.20632 TP7

Grid should contain 99 rows and 2 columns .Row 1;Superposition Time Function=153.769806022218;Pressure 1:TP7=1362.23826705Row 50;Superposition Time Function=4.21660163948667;Pressure 1:TP7=1825.79144026481Row 99;Superposition Time Function=2.67616921506915;Pressure 1:TP7=1878.98056405135 Line Results Model 1 Radial homogeneous Infinitely acting Semi-Log dpS = -101.461 psi TP7 FE = 1.0169 TP7 k = 3.2319 md TP7 kh = 51.711 md.ft TP7 P* = 6962.72 psia TP7 Rinv = 315.146 ft TP7 S = -0.11376 TP7 Log-Log

Verify by reading the plot title 'Log Log'.

Grid should contain 99 rows and 8 columns .Row 1;Elapsed Time (hours)=0.0999990000000004;Pressure 1:TP2=26.8776308094694;Elapsed Time (hours)=0.199999999999999;Pressure 1 Deriv:TP2=61.9412292380131;Elapsed Time (hours)=0.0999910000000029;Pressure 1:TP7=84.1354914109001;Elapsed Time (hours)=0.200001;Pressure 1 Deriv:TP7=11.388411350445Row 50;Elapsed Time (hours)=0;Pressure 1:TP2=0;Elapsed Time (hours)=0;Pressure 1 Deriv:TP2=0;Elapsed Time (hours)=5.066658;Pressure 1:TP7=122.414035854732;Elapsed Time (hours)=5.166661;Pressure 1 Deriv:TP7=9.51301472131678Row 99;Elapsed Time (hours)=0;Pressure 1:TP2=0;Elapsed Time (hours)=0;Pressure 1 Deriv:TP2=0;Elapsed Time (hours)=10.066658;Pressure 1:TP7=126.806201320178;Elapsed Time (hours)=0;Pressure 1 Deriv:TP7=0Line ResultsModel 1Radial homogeneousInfinitely actingLog-Logk = 2.8389 md TP*kh = 45.423 md.ft TP*

The plot 'Radial Flow Plot - Rate- Dependent Skin Analysis'. If not, select the column 'TP3 TP4 TP5 TP6' under Semi Log from the navigation pane.

An Information dialog should be displayed.

Verify by reading the plot title as Skin Vs Flow rate.

Grid should contain 76 rows and 8 columns .Row 1;Equivalent Time (hours)=0.0411284166669225;Pressure 1:TP3=13.3855830292267;Equivalent Time (hours)=0.0151953685982467;Pressure 1:TP4=1.86466184250265;Equivalent Time (hours)=0.0575766544190176;Pressure 1:TP5=14.7858360827329;Equivalent Time (hours)=0.0246023642483979;Pressure 1:TP6=6.82522448677268Row 38;Equivalent Time (hours)=1.39506449160886;Pressure 1:TP3=85.5268375978937;Equivalent Time (hours)=5.19540765066089;Pressure 1:TP4=128.779091343489;Equivalent Time (hours)=7.50071748169376;Pressure 1:TP5=152.546922941604;Equivalent Time (hours)=7.76643437150204;Pressure 1:TP6=172.549789009854Row 76;Equivalent Time (hours)=0;Pressure 1:TP3=0;Equivalent Time (hours)=13.5893851843372;Pressure 1:TP4=139.19875959917;Equivalent Time (hours)=0;Pressure 1:TP5=0;Equivalent Time (hours)=0;Pressure 1:TP6=0

Line ResultsModel 1Radial homogeneousInfinitely actingSemi-Logk = 2.6956 md TP*

Grid should contain 4 rows and 2 columns .Row 1;Normalised Flow Rate (MMscf/day)=3.95;SvQ Data=-2.04456520576308Row 2;Normalised Flow Rate (MMscf/day)=10.55;SvQ Data=-1.30692550835565Row 4;Normalised Flow Rate (MMscf/day)=21.125;SvQ Data=0.168353886459209

Line ResultsModel 1Radial homogeneousInfinitely actingSVQD = 0.001 1/(Mscf/day) TP1F = 20.423 psi2/cp/(Mscf/day)2 TP1S = -13.476 TP1

Grid should contain 76 rows and 8 columns .Row 1;Equivalent Time (hours)=0.0411284166669225;Pressure 1:TP3=-2.69486697077332;Equivalent Time (hours)=0.0151953685982467;Pressure 1:TP4=-41.0843881574973;Equivalent Time (hours)=0.0575766544190176;Pressure 1:TP5=-48.7828289172671;Equivalent Time (hours)=0.0246023642483979;Pressure 1:TP6=-79.1746505132273Row 38;Equivalent Time (hours)=1.39506449160886;Pressure 1:TP3=69.4463875978937;Equivalent Time (hours)=5.19540765066089;Pressure 1:TP4=85.8300413434886;Equivalent Time (hours)=7.50071748169376;Pressure 1:TP5=88.9782579416039;Equivalent Time (hours)=7.76643437150204;Pressure 1:TP6=86.5499140098545Row 76;Equivalent Time (hours)=0;Pressure 1:TP3=0;Equivalent Time (hours)=13.5893851843372;Pressure 1:TP4=96.2497095991698;Equivalent Time (hours)=0;Pressure 1:TP5=0;Equivalent Time (hours)=0;Pressure 1:TP6=0

Verify the Quick Match values of Cs = 0, k = 6.56334, S = -0.11376, D = 0.000199338, P_Lay = 7148

Quick Match Results 1Radial homogeneousInfinitely actingConstant compressibilityCs = 0 bbl/psiV = 0 bbl(k/u)g = 200.522 md/cpk = 6.5633 mdkh = 105.013 md.ftS = -0.11376D = 1.9934e-4 1/(Mscf/day)Pi = 7148 psia

Quick Match Results 1Radial homogeneousInfinitely actingConstant compressibilityCs = 0 bbl/psiV = 0 bbl(k/u)g = 200.522 md/cpk = 6.5633 mdkh = 105.013 md.ftS = -0.11376D = 1.9934e-4 1/(Mscf/day)Pi = 7155 psia

On clicking calculate Drainage Area and Dietz shape factor should be calculated as 11.2489 and 30.8815 respectively.

Verify Cs = 0 , k = 6.56334 S = -0.11376, D = 0.000199338 , L = 350

Quick Match Results 1Radial homogeneousClosed system - Corrected compressibilityCs = 0 bbl/psiV = 0 bbl(k/u)g = 200.522 md/cpk = 6.5633 mdkh = 105.013 md.ftS = -0.11376D = 1.9934e-4 1/(Mscf/day)L NF = 350 ftArea = 11.249 acresOGIP = 0.24608 bscfPi = 7155 psia

PanSystem should be closed.

Grid should contain 431 rows and 4 columns .Row 1;Time (Hours)=5.3667;TESTC:Pressure 1=7147.54;Time (Hours)=5.669699967;:Model 1 QM Prs 1=3601.90211051332Row 216;Time (Hours)=26.3098;TESTC:Pressure 1=4966.99;Time (Hours)=32.4195042668198;:Model 1 QM Prs 1=2495.30599464703Row 431;Time (Hours)=47.833328;TESTC:Pressure 1=6619.299805;Time (Hours)=0;:Model 1 QM Prs 1=0Quick Match Results 1Radial homogeneousInfinitely actingConstant compressibilityCs = 0 bbl/psiV = 0 bbl(k/u)g = 200.522 md/cpk = 6.5633 mdkh = 105.013 md.ftS = -2.94D = 2.5040e-4 1/(Mscf/day)Pi = 4851.883 psia

S. No Test Name Test Case Number Step Name Step1 Example08_1.pan 1

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Deliverability and Production Forecasting for

oil wells

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Go to Analysis >> Conventional Analysis >> Log Log

Click on Data Grid

Open file Example08_1.pan by navigating to the path Import/Export Data >> From Pan <= 3.xDouble click on the node 'Pressure' under WTEX3 Dataset

Go to Data Preparation >> Rate Schedule >> Rate Schedule

1. Note down final flowing Pressure (pressure calculated last i.e. at high Time Hours) and Q Oil from the grid.2. Click on 'Ok'



Select 'Central well position' and click on 'Boundary Parameters' button

Enter 1300 ft values in all the fields L1,L2,L3 and L4 and click on 'Calculate'. Notedown the Dietz shape factor CA

and Drainage Area. Here CA = 30.8815 and Drainage Area = 155.188Click on 'Ok'

Enter the following values in the window 'Quick Match'Cs = 0.00983168 bbl/psik = 7.60713 mdS = 6.27575L = 1300Click on 'Calculate' button and then click on 'Ok/Confirm' button.


Click on 'Ok'

Click on Quick Match tab and verify the results

Click on Data Grid



1. Enter 2120 psia in the field bubble Point (pb). Observe that Area A and The Dietz shape factor CA are calculated and displayed in corresponding fields. 2. Click on 'Calculate'.


Click OK. Go to Deliverability >> IPR >> IPR Trans/Prod

Click on Data Grid

Go to Analysis >> Conventional Analysis >> Cartesian

Click on Data Grid


Go to Deliverability >> IPR >> IPR Trans/ProdClick on Data Grid

1. Enter the final flowing pressure and rate noted in Step 3 namely 3429 psia and 250 STB/day resp in the fields Test Point1 : Flowing Pressure(psia) and Test Point1 : Flow Rate(STB/day).

2. Click on 'Calculate'



Enter the pressure 4311.9641 in the field 'Layer Pressure'.

Click on 'Calculate'. Click on 'Ok'

Go to Deliverability >> Forecasting >> New Forecast

Select 'Central well position' and click on 'Ok' button

Click on Data Grid


Go to Deliverability >> IPR >> Calculate IPR. Reset the Layer pressure to the initial 4412 psia

Click on 'Calculate'. Click on 'Ok'.

Select 'hours' in the Time Units dropdown. Select 'Constant Bottom hole pressure' radio button and select 'Logarithmic stepping' radio button.

Enter the following values in the window 'Production Forecast'.Start = 2 hoursEnd = 460 hoursNo. Of Steps = 500Constant Bottom hole pressure = 3429 psia.Click on 'Ok'





Click on Data Grid

Verify the forecasting results displayed under the tab 'Quick Match Results' in the left navigation pane.

Select 'years' in the Time Units dropdown. Select 'Constant Bottom hole pressure' radio button and select 'Logarithmic stepping' radio button.

Enter the following values in the window 'Production Forecast'.Start = 0.000228 yearsEnd = 3 yearsNo. Of Steps = 500Constant Bottom hole pressure = 3400 psia.Click on 'Ok'




Click on Data Grid

Go to Deliverability >> Forecasting >> Export to File

Enter File name and location and click on 'Save'




Select 'years' in the Time Units dropdown. Select 'Constant Top hole pressure(Import VFP Table)' radio button and select 'Logarithmic stepping' radio button.

Enter the following values in the window 'Production Forecast'.Start = 0.000228 yearsEnd = 3 yearsNo. Of Steps = 500


Click on 'Calculate' button.

Click on Data Grid


Click on Data Grid

Click on the button 'VFP File Import' and select the file VFP file example08_1vfp.vfp.Now select value '300.00' from the dropdown 'Top Hole Pressure'. Click on 'Ok'

Click on 'Ok' button in the dialog 'Warning'. Click on 'Ok/Confirm' button in the window 'Forecasting Plot'




Expected Results StatusThe plot 'Data Edit' should be displayed.

New window 'Edit Rate Changes' should be displayed

New window 'Closed System' should be displayed

A new window 'Closed System' should be displayed.


The final flowing Pressure should be 3429 psia and Q Oil be 250 STB/day

A plot should appear. Verify by reading the Plot title: Log Log Plot

Grid should contain 31 rows and 4 columns .Row 1;Elapsed Time (hours)=0.0215;Pressure:TP1=26;Elapsed Time (hours)=0.12;Pressure Deriv:TP1=126.165047467447Row 16;Elapsed Time (hours)=29.799999;Pressure:TP1=863;Elapsed Time (hours)=35.799999;Pressure Deriv:TP1=32.7306209645695Row 31;Elapsed Time (hours)=460;Pressure:TP1=983;Elapsed Time (hours)=0;Pressure Deriv:TP1=0

The following values should be displayed under the tab 'Quick Match Results'

Quick Match Results 1 Radial homogeneous Closed system - Constant compressibility Cs = 0.00983 bbl/psi (k/u)o = 9.5089 md/cp k = 7.6071 md kh = 524.892 md.ft S = 6.2758 L NF = 1300 ft Area = 155.188 acres OOIP = 2.8521e+6 STB Pi = 4412 psia dpS = 383.565 psi

New window 'Transient and Production Test Deliverability Results' should appear. In this window observe that initial layer pressure should be 4412 psia

1. The Area A and The Dietz shape factor CA should be same as CA = 30.8815 and Drainage Area = 155.1882. The theoretical Productivity Index (J) and Open Flow potential (AOF) should be calculated and displayed as 0.283108 and 981.849 resp after clicking on 'Calculate'

A plot should appear. Verify by reading the Plot title: Sandface Deliverability Plot

Verify Results IPR Results Radial homogeneous Infinitely acting IPR-Trans Test J = 0.28311 STB/day/psi AOF = 981.849 STB/day

Grid should contain 200 rows and 2 columns .Row 1;Flow Rate (STB/day)=981.849483219153;IPR-Trans Test=14.6499996185303Row 100;Flow Rate (STB/day)=625.591200254153;IPR-Trans Test=2202.27638171785Row 200;Flow Rate (STB/day)=4.63473974446014E-12;IPR-Trans Test=4411.99999999998New window 'Transient and Production Test Deliverability Results' should appear.

After clicking on calculate, verify the values of field Productivity Index(J) = 0.254323 and AOF 882.021

A plot should appear. Verify by reading the Plot title: Sandface Deliverability Plot.

Grid should contain 200 rows and 6 columns .Row 1;Flow Rate (STB/day)=981.849483219153;IPR-Trans Test=14.6499996185303;Flow Rate (STB/day)=882.02060959846;IPR-Prod Test=14.6499996185303;Flow Rate (STB/day)=250;IPR- AnnotationIPR-Trans Test=3429Row 100;Flow Rate (STB/day)=625.591200254153;IPR-Trans Test=2202.27638171785;Flow Rate (STB/day)=561.98464351021;IPR-Prod Test=2202.27638171785;Flow Rate (STB/day)=0;IPR- AnnotationIPR-Trans Test=0Row 200;Flow Rate (STB/day)=4.63473974446014E-12;IPR-Trans Test=4411.99999999998;Flow Rate (STB/day)=4.16350575582724E-12;IPR-Prod Test=4411.99999999998;Flow Rate (STB/day)=0;IPR- AnnotationIPR-Trans Test=0A plot should appear. Verify by reading the Plot title: Cartesian Plot.

Grid should contain 100 rows and 4 columns .Row 1;Elapsed Time (Hours)=0.0215;Pressure:TP1=4386;Elapsed Time (Hours)=0.0215;Model1 QM Prs 1=4387.12579460065Row 50;Elapsed Time (Hours)=0;Pressure:TP1=0;Elapsed Time (Hours)=2.99039009780673;Model1 QM Prs 1=3648.38806234379Row 100;Elapsed Time (Hours)=0;Pressure:TP1=0;Elapsed Time (Hours)=460;Model1 QM Prs 1=3430.50512874873New window 'Transient and Production Test Deliverability Results' should appear.

Observe that productivity Index(J) in both the sections 'Transient Test Data' and 'Production Test Data' is almost same

New window 'Production Forecast' should appear.

New window 'Closed System' should appear.

New window 'Forecasting Plot' should appear.

Grid should contain 200 rows and 6 columns .Row 1;Flow Rate (STB/day)=953.528456647841;IPR-Trans Test=14.6499996185303;Flow Rate (STB/day)=953.625809472738;IPR-Prod Test=14.6499996185303;Flow Rate (STB/day)=250;IPR- AnnotationIPR-Trans Test=3429Row 100;Flow Rate (STB/day)=611.359528610277;IPR-Trans Test=2152.50972845152;Flow Rate (STB/day)=611.421946859804;IPR-Prod Test=2152.50972845152;Flow Rate (STB/day)=0;IPR- AnnotationIPR-Trans Test=0Row 200;Flow Rate (STB/day)=1.02994216543559E-12;IPR-Trans Test=4311.964;Flow Rate (STB/day)=1.03004731990537E-12;IPR-Prod Test=4311.964;Flow Rate (STB/day)=0;IPR- AnnotationIPR-Trans Test=0

A plot should appear. Verify by reading the Plot title: Production Forecasting Plot.

Grid should contain 500 rows and 2 columns .Row 1;Time (hours)=2;Production Rate=314.989252682434Row 250;Time (hours)=30.1666755875644;Production Rate=284.148597988442Row 500;Time (hours)=460;Production Rate=248.531018919474

G36

Prathyusha_Kondeti: Plot Name is not appeared in the header





Forecasting Results Radial homogeneous Closed system - Constant compressibility k = 7.6071 md kh = 524.892 md.ft S = 6.2758 L NF = 1300 ft Area = 155.188 acres OOIP = 2.8521e+6 STB BHFP = 3429 psia dpS = 383.565 psi


Observe that the well will be barely producing after 2 years if this bhfp is maintained, as layer pressure -> bhfp

Grid should contain 500 rows and 2 columns .Row 1;Time (years)=0.000228;Production Rate=324.290490729043Row 250;Time (years)=0.025906014816059;Production Rate=270.824054577271Row 500;Time (years)=3;Production Rate=0.578892476268871

New window 'Save As' should be displayed



Forecasting Results Radial homogeneous Closed system - Constant compressibility k = 7.6071 md kh = 524.892 md.ft S = 6.2758 L NF = 1300 ft Area = 155.188 acres OOIP = 2.8521e+6 STB BHFP = 3400 psia dpS = 383.565 psi


Grid should contain 500 rows and 3 columns .Row 1;Time (years)=0.000228;Production Rate=324.290490729043;Cumulative Prod=13.5029695982212Row 250;Time (years)=0.025906014816059;Production Rate=270.824054577271;Cumulative Prod=2655.79957057285Row 500;Time (years)=3;Production Rate=0.578892476268871;Cumulative Prod=49434.6149025545

The file should get saved successfully in the entered location



New dialog 'Warning' should be displayed showing the message "Solution is below lowest rate in VFP table"

A plot should appear. Verify by reading the Plot title: Production Forecasting Plot

Grid should contain 500 rows and 2 columns .Row 1;Time (years)=0.000228;Production Rate=390.94559945686Row 250;Time (years)=0.025906014816059;Production Rate=328.744817066268Row 500;Time (years)=3;Production Rate=0.803358662299288The following values should be displayed under the tab 'Quick Match Results'.

Forecasting Results Radial homogeneous Closed system - Constant compressibility k = 7.6071 md kh = 524.892 md.ft S = 6.2758 L NF = 1300 ft Area = 155.188 acres OOIP = 2.8521e+6 STB VFP = Example08_1vfp.vfp THP = 300 psia dpS = 0 psi


Grid should contain 500 rows and 3 columns .Row 1;Time (years)=0.000228;Av Res Pressure=4412;THP=300Row 250;Time (years)=0.025906014816059;Av Res Pressure=4194.08029691979;THP=300Row 500;Time (years)=3;Av Res Pressure=3117.42144023276;THP=300

S. No Test Name Test Case Number Step Name Step1 1

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Data Preparation

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Click No.

Click Import.

Click No.

Open PanSystem. Go to Configuration -> Configuration -> units. Select OILFABS Units System. Click OK.

Go to Data Preparation >> Well, reservoir and FluidDescription -> Analytical Model -> Fluid Control. Select Oil. Click OK.

Go to Import Export Data >> Import Data >> ASCII. Click OK on the 'Select a file' dialog. In the 'Open Configuration file' window that is opened, choose the 'File Type' as 'All Files' and import the file Example09_1.tpr.

Click the button 'Load Template'. Open the file 'Example09_1.tpt'.

Click OK. On the navigation pane, go to NewFile1.panx -> Well 1 -> Dataset -> Example09_1 and double click the Pressure#1 column to display the plot. Right click the Temperature#1 column and select 'Add to Active plot' to display the temperature column as well. Add to active the plots the columns Pressure#2 and Temperature#2. The plots should appear as shown in the snapshot

Click the button Data Grid on the toolbar. Verify the Data view and click OK.

Click OK on Enter Reduction/smoothing details.Click OK on the Reduction Status.

Click the Data Grid button on the tool bar.Verify the Data View values. Click OK.

Click Data Preparation -> Gauge Data -> Difference between two data columns. Select Pressure#2 and Pressure#1 for Data file/Columns.

Click Ok.Remove the Temperatures from the plot by right clicking the plot name in the left navigation -> Remove from active plot.

Remove the plots Pressure#2, and Diff#1 by right clicking the column name on the navigation pane and selecting 'Remove From Active Plot'. Keep Pressure#1.

Click Data Preparation -> Processing -> Data Reduction and Smoothing Facility

Check the check box 'Reduce Data'. In the child tab 'Reduce Data',Select the radio button 'Resample by Delta Signal'. Enter 0.011 to 'Keep when delta signal>'. Select the signal column as Pressure#1.

Clear the workspace and open the Example09_1.panx. If the plot is not as shown in the screen shot, select Log - Log >>TP1 from the navigation pane.

Click Data Preparation -> Well, Reservoir and fluid Description -> Analytical Model -> Well Control. Click the button 'Well Parameters'. Verify whether Wellbore radius = 0.354.

Click Yes on the dialog.

Click OK. Click the child tab Layer Control. Click the Layer Parameters button. Verify the following data:Formation thickness: 92 ftPorosity: 0.23Click OK

Click the button Layer Fluid Parameters.Verify the following data:Bo = 1.21 res bbl/STB Uo= 2.3 cpCt = 7.92E-5 psi-1. Click Ok.

Click OK.Click Analysis ->Tools -> Derivative Smoothing. Select Radial and give the value 0.3.Click OK.

Click Data Preparation -> View -> Overlay Pressure. Select the column Pressure#2 and check the Show Overlaid Pressure Checkbox.

Click OK. Click on the data View button on the toolbar. Verify the data and click OK.

Close the Pan System. Click 'No' for 'Save Data to current file' dialog.

Open PanSystem. Go to Import/Export Data -> ASCII. Import the dat file 'example09_2a.dat'.

Click No on the dialog.Click Ok on the Status dialog that is opened.

Click the button Load Template. From the 'Open' Window, open the file 'Example09_2.tpt'. Click Import

Go to Import/Export Data -> ASCII. Select the Panx File, and click OK.

Import the dat file 'example09_2b.dat'. Click Yes on the dialog box displayed.

Click the button Load Template. From the 'Open' Window, open the file 'Example09_3.tpt'.

Click Import. Click Ok on the Status dialog that is opened.

Go to Navigation pane, double click on the column 'example09_2a: Temperature#1' to display the plot. Right click the columns example09_2a: Pressure#1,example09_2b: Temperature#2,example09_2b: Pressure#2 and select 'Add to Active Plot.

Click the Data View button on tool bar. Verify the data and click OK.


Double click the column 'example09_2a:Pressure#1' on the navigation pane. Right click the column 'example09_2b:Pressure#2' and select 'Add to active plot'.

Click Data Preparation -> Gauge data -> Append Data Files.

Plot Pressure#1. Click the Data View button.

Select the DMY as DMY,Temperature#2 andPressure#2 columns. Click OK.

Close the Pan System. Click No for 'Save Data to current file' dialog.


A Data file should be opened as shown in the screen shot.

Open' window Should be displayed.

A dialog 'Do you wish to save a template?' is displayed.

A warning message 'Do u wish to save a template?' is displayed.

File Import Status Dialog box is displayed with the number of data points imported as 9766

Grid should contain 9766 rows and 5 columns .Row 1;Date Time=35119.71875;Example09_1:Pressure #1=4202.32;Example09_1:Temperature #1=143.2;Example09_1:Pressure #2=4202.05;Example09_1:Temperature #2=143.26Row 4883;Date Time=35123.1090277778;Example09_1:Pressure #1=4108.46;Example09_1:Temperature #1=149.02;Example09_1:Pressure #2=4108.46;Example09_1:Temperature #2=149.08Row 9766;Date Time=35126.5;Example09_1:Pressure #1=1736.85;Example09_1:Temperature #1=41.95;Example09_1:Pressure #2=1734.03;Example09_1:Temperature #2=41.89

The plot appears as shown in the screen shot.

A dialog box with reduction status is displayed.

Verify by reading the plot title 'Log Log Plot'.

A Data View grid should be opened.

Note that the right hand Y-Axis scale is Pressure Difference(psi)

Grid should contain 2701 rows and 4 columns .Row 1;Elapsed Time (hours)=0.0158386666666672;Pressure #1:TP1=2.74959399999989;Elapsed Time (hours)=0.0658386666666679;Pressure #1 Deriv:TP1=0.355363935173655Row 1351;Elapsed Time (hours)=22.5158386666667;Pressure #1:TP1=11.609594;Elapsed Time (hours)=43.7825053333333;Pressure #1 Deriv:TP1=118.247766895175Row 2701;Elapsed Time (hours)=45.0158386666667;Pressure #1:TP1=135.270406;Elapsed Time (hours)=0;Pressure #1 Deriv:TP1=0

A "WarningNon - System units" dialog is displayed

Grid should contain 2701 rows and 7 columns .Row 1;Elapsed Time (hours)=0.0158386666666672;Pressure #1:TP1=2.74959399999989;Pressure #2:TP1=56.89959;Elapsed Time (hours)=0.0658386666666679;Pressure #1 Deriv:TP1=0.355363935173655;Elapsed Time (hours)=0.0658386666666679;Pressure #2 Deriv=0.195639295484787Row 1351;Elapsed Time (hours)=22.5158386666667;Pressure #1:TP1=11.609594;Pressure #2:TP1=70.6795899999997;Elapsed Time (hours)=41.549172;Pressure #1 Deriv:TP1=1237.18529116755;Elapsed Time (hours)=28.6658386666667;Pressure #2 Deriv=3.7312241027404Row 2701;Elapsed Time (hours)=45.0158386666667;Pressure #1:TP1=135.270406;Pressure #2:TP1=134.830410000001;Elapsed Time (hours)=0;Pressure #1 Deriv:TP1=0;Elapsed Time (hours)=0;Pressure #2 Deriv=0

A warning message is displayed

Verify by reading the plot title Data Edit Plot.

The Data View consists of 7 columns and 540 rows.Row1: Date Time=1/5/2004 12:49:30 PM;example09_2a: Temperature#1 = 63.87; example09_2a: Pressure#1=1955.384; Time (Hours ):37996.5399305556; example09_2b: Temperature#2=91.47; Time (hours)=37996.5399305556; example09_2b: Pressure#2=1930.472Row270: Date Time=1/6/2004 7:22:00 PM;example09_2a: Temperature#1 = 91.44; example09_2a: Pressure#1=1931.656; Time (Hours ): 0; example09_2b: Temperature#2=0; Time (hours)=0; example09_2b: Pressure#2=0Row540:Date Time=1/10/2004 9:27:30 AM;example09_2a: Temperature#1 = 91.19; example09_2a: Pressure#1=1906.916; Time (Hours )=0; example09_2b: Temperature#2=0; Time (hours)=0; example09_2b: Pressure#2=0

The data view consists of 4 columns and 611 rows.Row1: Date Time = 1/5/2004 12:49:30 PM; example09_2a:Pressure#1=1955.384; Date Time = 37996.5399305556; example09_2b:Pressure#2=1927.01093877551;Row305: Date Time = 1/6/2004 9:22:00 PM; example09_2a:Pressure#1=1930.159; Date Time = 0; example09_2b:Pressure#2=0;Row611: Date Time = 1/16/2004 6:31:30 PM; example09_2a:Pressure#1=1926.60193877551; Date Time = 0; example09_2b:Pressure#2=0;

S. No Test Name Test Case Number Step Name Step

1 Reporting Edit/Copy 1

2

Exporting Graphics 3

4

Data grid 5

6

7

8

9

10

11

12

13

Reports 14

Input Data 15

16

17

18

19

20

21

22

Master TPR 24

25

Analysis Results 26

27

28

29

30

Deliverability Results

31

Edit Layout 32

33

34

35

36

Print 37

38

39

40

41

Output 42

43

44

45


From the PanSystem toolbar, select 'Data Grid'.

Select the Copy Data on the Data view grid.

Select the Copy Entire Table radio button and click OK.

Click Ok of the Data View.

Go to Reports -> Reports -> Configure

Open PanSystem. Open the file 'Example10.panx' Make sure the plot for the selected panx file is displayed. From the PANSystem toolbar, select 'Copy to Clipboard'.

Paste the copied image into a report (e.g. MS Word, etc.)

From the PANSystem toolbar, select 'Export to Image File'.

This option should allow users to save any viewed image as a Bitmap(*.bmp), Enhanced Metafile(*.emf), JPEG (*.jpg) or PNG (*.png)file format.Save the image as .jpg file.

Paste the selected data into any text file such as MS word.

Switch to PanSystem. From the PanSystem toolbar, select 'Data Grid'. Select a few rows in the Data View grid and click the Copy Data button on the Data View Grid.

From the Copy Options window that is opened, check the radio button 'Copy Selection'. Click OK.Paste the copied data into a text file such as MS Word. Close the word document

Switch to PanSystem. From the PanSystem toolbar, select 'Data Grid'. From the data view window, select 'Go to Row'.

Enter a row number which is within the displayed range. Click OK.

Click the Edit button against the Input Data.

Click Ok of the Advanced Simulation Control .

Click OK. A 'Data Edit Plot' should be displayed.

Deselect the 'Test Overview Plot' under Select Plot.

Note down the checked items under 'Topics to include'.

Select the required plots from the 'Select Plot' area.

1. Under the Analytical Input Area, check a few Input Data Items. 2.Check whether 'Include Quick Match Data' item is enabled.

Click Cancel on the Edit Input Data Contents. Click Cancel again to return to Pan System main window.

Click Simulation -> Analytical Simulation -> Advanced Simulation.

Click Analysis. Select 'Producer' Radio button on the 'Analysis section' dialog. Click OK.

Go to Reports -> Reports -> Configure. Click the Edit button against the Input Data. Check whether 'Include Quick Match Data' item is enabled.

PANMESH SPECIFIC: Verify whether Numerical Input Area is enabled.

Click the Master TPR button. Select a few columns to be listed. Enter a few comments.

Click OK to return to the Edit Input Data Contents dialog. Click OK to return to Configure Report dialog.

1.Click the Edit button against the Analysis Results.2. Note the list of plots displayed under 'Select Plot' Section.

1. Click OK to return to Configure Report dialog.2. Click the edit button against Deliverability results.

Click on Edit Cover Page

On the Configure Report dialog, click Format.

Click the Print button on the Configure Report dialog.

Close the Configure Report dialog.

Go to Reports -> Reports -> Output

From the topics to include area, note down the selected items.

Click OK to return to Configure Report. Click Edit Layout.In the Edit Layout dialog, user should be able to:1. Include/Exclude Cover Page2. Include/Exclude Remarks3. Report header and Report footer section 4. Display or not the company logo

Click ok to return to Edit Layout. Click Edit Remarks button.

Click ok to return to Edit Layout. Click OK to return Configure Report.

Select 'Print Report to text file(No Graphics)' to get the textual file without graphics. Click Print.

Select 'Print Report to selected printer' to print the report and click Print.

Click the Save Template button on the Configure Report dialog.

After few seconds a dialog should be displayed with message 'Word Document Completed. Do you want to display?'

Open the report and verify whether all the information included in the above steps is displayed in the report.

Close the Pan System. Click No for 'Save Data to current file' dialog.


Image of the selected plot is copied to the clipboard.

The plot alone should be copied to the report.

A 'Save As' window should be opened.

Data View grid should be opened.

All the data should be pasted into the text file.

All the selected data should be pasted into the text file.

Edit Input Data Contents window should be opened.

The file should be saved in .jpg format. Verify the image file to check if the plot has been exported.

A 'Copy Options' window is displayed with two radio buttons:1. Copy Selection 2. Copy Entire Table

The entire Data View grid should be copied to the clipboard.

A 'Copy Options' window is displayed with two radio buttons:1. Copy Selection 2. Copy Entire Table

A window with title, 'Go To Row Number' should be opened, which contains a text box 'Row Number' and range of row numbers.

The cursor should point to the row number specified by the user.

A window with title 'Configure Report : quick .tpl' should be displayed.The following should be present under Sections:3 Include checkboxes and 3 Edit buttons one each for Input Data, Analysis results and Deliverability Results. One Edit Layout button

Advanced Simulation Control window should be opened.

A dialog 'Calculating Advanced Simulation' is displayed.

Verify the plot by reading the title 'Data Edit Plot'.

1. The Input Data Items that have been selected should be included in the report.2. 'Include Quick Match Data' item should not be enabled as Analysis is not performed.

The data item 'Include Quick Match Data' should be enabled as Analysis is performed.

Numerical Input Area should be disabled as it is PANMESH specific.

A dialog with title 'Edit Report Data File Selection' should be opened.The selected columns should be displayed in the report.

1. 'Edit Report Analysis Section' window should be opened. 2. The plots that have been analyzed should be listed under 'Select Plot' section.

1. User should return to Configure Report dialog.2. Edit Deliverability Contents dialog should be opened.

The 'Select Plot' area lists all of the IPR and/or Forecasting plots that have been analyzed so far.The selected plots should appear in the report.

Edit Remarks dialog should be displayed.

The report should be printed.

The Configure Report dialog should be closed.

On selecting Include Description Box, a commented description box is included beneath the plot.Checking the checkbox Deliverability Data includes tabulated input data (i.e. data previously entered via the Deliverability ribbon options), constraints and results (e.g. Deliverability/Injectivity data from the IPR ribbon options and/or Production Constraints, Forecasting Parameters and Forecasting Results from the Forecasting menu option).

Edit layout dialog should be opened.Checking the checkboxes Cover Page and Remarks, Selecting the required header and footer components and checking Show Logo includes them in the report.

Report Cover Page' dialog should be displayed with two editable columns Description and Details.

Clicking the Format button should display the number of pages you have configured.

A 'Save as' dialog should be opened, which allows to save the file with extension .rpt.

A 'Save as' dialog should be opened allowing the user to save the template(default file type .TPL).

The report can be saved to a “.doc” MSWord Document

Click 'Yes' to view the document and 'No' to close the document.

Verify whether the data items have selected in the steps 19, 26, 29, 30, 32, 33 and Edit Layout are included in the report.

D Test Name Test Case Number Step Name Step1 Example 11_1.panx 1

2

3

4

5

6

7

8

910

11

1213

Partial Penetration

14

Example11_2.panx 15

16

17

1819

20

21222324

25

2627

28

2930

3132

33

34

35

36

Example11_2.panx 37

38

39

40

41

42

43

44

45

4647

48

49

50

51

52

5354

55

56

57

58

59

60

61

62

63

64

65

66

Test Description (Action)Open Pan System


Click Analysis > Conventional Analysis > Log Log. Click on Data Grid


In Data Preparation >>Well, Reservoir & Fluid Description, click on Analytical Model. In the Fluid Control tab, check Fluid type is Oil

In Well, Reservoir & Fluid control Description> Well Control tab, check Principal well orientation is vertical.Click well parameters.

In Well, Reservoir & Fluid control Description> Layer Control tab, click Layer parameters.

In Well, Reservoir & Fluid control Description> Layer Control tab, click Layer fluid parameter.

Click OK in the message box. Click OK in the Well, Reservoir & Fluid Description to exit to main pan system window.

A plot should be already displayed but if not , double click the Pressure #1 data set under Test Overview under Model 1 in Navigation Pane

Click Analysis > Model Selection > Model. Change the Reservoir model to Partial Penetration model. Click OK


Click on Confirm Results. Click OK.


In Analysis > Tools, click on Unit Slope. On the Define Line select "Wellbore Storage" and Click OK

In the Navigation Pane, under Line Results tab, verify the line results

Go to Simulation> Analytical simulation. Click Quick Match. In the Quick Match window input as below:Cs =0.0139, k= 682, S =0.403, kz = 69.59, htop = 86.27, hp = 200. Click Calculate. Then Click OK/Confirm.

Verify the plot by reading the Plot TitleClick on IPR Trans/Prod on Deliverability > IPRClick on Data GridRead Grid and Click OK.

In the navigation pane, verify Quick Match results

Click Analysis > Conventional Analysis > Semi-Log Click on Data Grid

Click on Deliverability > IPR > Calculate IPRIn the "Transient and Production Test Deliverability Test" window, enter the following:Layer Pressure: 4968Bubble Pt: 2000Test Point 1 - Pressure: 4936, Flow Rate: 3742Click Calculate. Click OK after verfiying the values.


Click on Confirm Results.

Click Analysis > Conventional Analysis > Spherical Click on Data Grid

Click Ok. In the Navigation Pane, under Line Results tab, verify the line results


Click on Type Curve Match in Analysis > Tools.

Click on Confirm Results.

Fit a line to the plot by selecting fit line of known slope in Analysis > Tools.On the "Known Line" window enter slope as 3.05. Click ok

On the Define Line window, select "Spherical Transition to Total System"

Click Confirm ResultsClick ok

Close all the files and Open Example11_2.panx again. In the navigation pane under Workspace, click on Pressure 1 under Test Overview for Model 1

Click on Analysis > Conventional Analysis > Type Curve.Verify be reading plot title

Click OK on the Select Type Curve Dialogue box.Verify screen resolution is 1280X 1024 pixels

Click on Type Curve Match again and in the "Verify Selected Nearest Curve" window, enter value 1 in Nearest Curve. Click ok

In the Navigation pane, verify the Line Results

Click on Confirm Results.In the Navigation pane, verify the Line Results

Click the Right Arrow button for Next Stage in the Tools section.

Click on Type Curve Match again and in the "Verify Selected Nearest Curve" window, enter value 4 in Nearest Curve. Click ok

Click on Simulation > Analytic Simulation > Quick Match. Enter the following values: Cs = 0.00177, k = 697.4, S = 0.1339, kz = 73.45, htop = 80, hp = 190.Click Calculate, then ok/Confirm

In the Navigation pane, verify the quick Match Results

Select Radial Flow in the Define Line Dialog box. Click OK

Click Analysis > Conventional Analysis > Log Log.


Now go to Analysis > Model Selection and Click on Model Select reservoir model as "Gas cap/Aquifer support" in the "Select Analysis Model" window dialogue box.Click OK

Click OK in the Information Box "About to Re-assign the line types - enter the new line type if prompted"

Go to Simulation> Analytical simulation. Click Quick Match. In the Quick Match window input as below:Cs =0.00177, k= 700, S =0.25, kz = 45, htop = 80, hp = 190. Click Calculate. Then Click OK/Confirm.

Select Radial Flow in the Define Line Dialog box. Click OK


Now go to Analysis > Model Selection and Click on Model Select reservoir model as "Slanted Well*" in the "Select Analysis Model" window.Click OK

Click OK in the Information Box "About to Re-assign the line types - enter the new line type if prompted"

Select Early-Time Radial Flow in the Define Line Dialog box. Click OK

Go to Simulation> Analytical simulation. Click Quick Match. In the Quick Match window input as below:Cs =0.0014, k= 682, S =0.403, ANG=0, ZWDT= 0.227, ZWDB= 0.7533, RKZR= 0.102, IBDY= 1. Click Calculate. Then Click OK/Confirm.

Now go to Analysis > Model Selection and Click on Model Select Wellbore storage model as "Hegeman Wellbore model" in the "Select Analysis Model" window pop up.Click OK

Go to Simulation> Analytical simulation. Click Quick Match. In the Quick Match window input as below:Cs =0.02, Cphi = 16, Tau = 0.0095, k= 682, S =0.403, ANG=0, ZWDT= 0.227, ZWDB= 0.7533, RKZR= 0.102, IBDY= 1. Click Calculate. Then Click OK/Confirm.


Verify the plot by reading "Log-Log plot"

Well, Reservoir & Fluid control Description window will pop up

In Well Parameters window verify wellbore radius is 0.354 ft. and Wellbore Storage Model - Classic Wellbore storage. Click OK.

Check Formation thickness = 380 ft.; Porosity= 0.21, Layer Pressure=4990 psi, Layer Temperature = 0 F, Water Saturation =0, Gas Saturation = 0 and Rock Compressibility 0.0000e+000. Reservoir Model = Slanted Well*. Click OK.

Verify Oil properties: Bo = 1.275.Check Ct= 2.0170e-005 psi-1. Check pressure 4990 psia and temperature 0 degF.

Validate by reading the title of the plot "Test Overview Plot"

Grid should contain 14879 rows and 2 columns .Row 1;Time (Hours)=0;M-92JAN-05:Pressure #1=4936.281104Row 7440;Time (Hours)=2.066389;M-92JAN-05:Pressure #1=4962.491064Row 14879;Time (Hours)=4.132778;M-92JAN-05:Pressure #1=4962.969092

Grid should contain 14516 rows and 4 columns .Row 1;Elapsed Time (hours)=0.000276999999999999;Pressure #1:TP4=0.000045409406734378;Elapsed Time (hours)=0.000555;Pressure #1 Deriv:TP4=0.000447618492263429Row 7258;Elapsed Time (hours)=2.016111;Pressure #1:TP4=0.00708895109567078;Elapsed Time (hours)=2.016389;Pressure #1 Deriv:TP4=0.000276692045062892Row 14516;Elapsed Time (hours)=4.032222;Pressure #1:TP4=0.00720978193479442;Elapsed Time (hours)=0;Pressure #1 Deriv:TP4=0Verify the plot by reading "Log-Log plot". The plot should appear with a flow regimes defined

Line Results Model 1 Partial penetration Infinitely acting Log-Log Cs = 3.1018 bbl/psi TP4 k = 688.731 md TP4 kh = 261717.79 md.ft TP4 khp = 130592.503 md.ft TP4 kp = 652.963 md TP4 S = 0.05098 TP4 Spr = 5.5595 TP4

Quick Match Results will be displayed in the Navigation pane. Verify Quick Match Results Quick Match Results 1 Partial penetration Infinitely acting Constant compressibility Cs = 0.0139 bbl/psi (k/u)o = 850.374 md/cp k = 682 md kh = 259160 md.ft S = 0.403 kz = 69.59 md htop = 86.27 ft hp = 200 ft Spr = 6.0963 Pi = 4967.705 psia dpS = 1.5963 psi

Plot Title should read "Sandface Deliverability Plot"

Verify the plot by reading "Radial Flow Plot"

Under Transient Test Data, the Productivity Index should be 124.784and AOF 508797

Grid should contain 200 rows and 6 columns . Row 1 should read Flow Rate (STB/day): 508797.085232664, IPR-Trans Test: 14.6499996185303, Flow Rate(STB/day): 476805.133526656, IPR-Prod Test: 14.6499996185303, Flow Rate(STB/day): 3742, IPR-AnnotationIPR-Trans Test: 4936; Row 100 should read Flow Rate(STB/day): 310601.419754591, IPR-Trans Test: 2478.87939679323, Flow Rate(STB/day): 291071.540537492, IPR-Prod Test: 2478.87939679323, Flow Rate(STB/day): 0, IPR-AnnotationIPR-Trans Test: 0; Row 200 should read Flow Rate(STB/day): -1.3618802332005E-09, IPR-Trans Test: 4968.00000000001, Flow Rate(STB/day): -1.27624844026286E-09, IPR-Prod Test: 4968.00000000001, Flow Rate(STB/day): 0, IPR-AnnotationIPR-Trans Test: 0;

Verify IPR Results IPR Results Partial penetration Infinitely acting IPR-Trans Test J = 124.784 STB/day/psi AOF = 508797.085 STB/day IPR-Prod Test J = 116.938 STB/day/psi AOF = 476805.134 STB/day

Verify the plot by reading "Spherical Flow Plot"

Grid should contain 14516 rows and 4 columns .Row 1;Superposition Time Function=343462.622936537;Pressure #1:TP4=4936.16001;Superposition Time Function=343462.440403014;Model 1 QM Prs 1=4939.00435128697Row 7258;Superposition Time Function=145.829780372008;Pressure #1:TP4=4962.516943;Superposition Time Function=0;Model 1 QM Prs 1=0Row 14516;Superposition Time Function=90.1562380687429;Pressure #1:TP4=4962.969092;Superposition Time Function=0;Model 1 QM Prs 1=0

Line Results Model 1 Partial penetration Infinitely acting Semi-Log dpS = -0.93776 psi TP4 FE = 0.24745 TP4 k = 679.521 md TP4 kh = 258218.036 md.ft TP4 khp = 122307.977 md.ft TP4 kp = 611.54 md TP4 P* = 4967.715 psia TP4 Rinv = 823.611 ft TP4 S = -0.21229 TP4 Spr = 6.0055 TP4 Log-Log Cs = 3.1018 bbl/psi TP4 khp = 130592.503 md.ft TP4 kp = 652.963 md TP4 Spr = 5.5595 TP4

The line is placed on the plot

Verify by reading the plot "Test Overview Plot"

Plot Title should read "Type Curve Plot"

Click OK

Grid should contain 14516 rows and 4 columns .Row 1;1/Square-root Superposition Time Function=-59.149548813895;Pressure #1:TP4=4936.16001;1/Square-root Superposition Time Function=-59.1495328393205;Model 1 QM Prs 1=4939.00435128697Row 7258;1/Square-root Superposition Time Function=-0.509005815938899;Pressure #1:TP4=4962.516943;1/Square-root Superposition Time Function=0;Model 1 QM Prs 1=0Row 14516;1/Square-root Superposition Time Function=-0.382107787218374;Pressure #1:TP4=4962.969092;1/Square-root Superposition Time Function=0;Model 1 QM Prs 1=0

Verify the valuesVertical Permeability: 69.673

Verify the Type curve method is Default and Type Curve Starting Stage is Partial Penetration in the "Select Type Curve" window.

Click ok

Verify the display of following parameters: Match Results Partial penetration Infinitely acting Typecurve hp k kh kz Log-Log

Verify the display of following parameters: Match Results Partial penetration Infinitely acting Cd Cs hp k kh kz S Log-Log

Verify the plot by reading "Log-Log plot"The quick match Results are displayed on the graph

Quick Match Results 1 Partial penetration Infinitely acting Constant compressibility Cs = 0.00177 bbl/psi (k/u)o = 869.576 md/cp k = 697.4 md kh = 265012 md.ft S = 0.1339 kz = 73.45 md htop = 80 ft hp = 190 ft Spr = 6.1948 Pi = 4967.207 psia dpS = 0.54597 psi

Quick Match Results 1 Gas cap/aquifer support Infinitely acting Constant compressibility Cs = 0.00177 bbl/psi (k/u)o = 872.818 md/cp k = 700 md kh = 266000 md.ft S = 0.25 kz = 45 md htop = 80 ft hp = 190 ft Spr = 6.6638 Pi = 4963.786 psia dpS = 1.0156 psi

Quick Match Results 1 Slanted Well Infinitely acting Constant compressibility Cs = 0.0014 bbl/psi (k/u)o = 850.374 md/cp k = 682 md kh = 259160 md.ft S = 0.403 ANG = 0 degrees ZWDT = 0.227 ZWDB = 0.7533 RKZR = 0.102 IBDY = 1 Pi = 4968.198 psia dpS = 0.84016 psi

Quick Match Results 1 Slanted Well Infinitely acting Constant compressibility Cs = 0.02 bbl/psi (k/u)o = 850.374 md/cp Cphi = 16 psi Tau = 0.0095 hr k = 682 md kh = 259160 md.ft S = 0.403 ANG = 0 degrees ZWDT = 0.227 ZWDB = 0.7533 RKZR = 0.102 IBDY = 1 Pi = 4968.198 psia dpS = 0.84016 psi



S. NO Test Name Test Case Number Step Name Step1 Example12_1.panx 1

2

3

45

6

7

8

9

Radial Composite Reservoir

10

11

12

13

14

1516

17

18

19

20

21

22


Click on Data Grid



Navigate to the location where the files are present and select "Example12_1.panx" file and click on the Open Button on the open dialog box



Click on "Well Control" tab and then click on "Well parameters" button.

Click on "Layer Control" tab and then click on "Layer parameters" button.

Select "Analysis" on the Navigation pane and then click on "Model Selection" menu tab and then click on the "Model" menu item.

Click on Data Grid

Click on the "Input/Model Parameters" button and click on "model parameters" tab on the Dialog box

1.Click on the "OK" button on the Input/Model parameters 2. Click on the "OK" button on the Select Analysis Model window

Click on the "Confirm Results" menu item under Analysis Tools. Click OK on the Confirm results dialog.


Click on the "Semi-Log" menu item under "Plot types" menu Tab.



Click on the "Confirm Results" menu item under Analysis Tools.

Click OK on the Confirm Results Window.

Again click on the "Log-Log" menu item under "Plot types" menu Tab.


Input values for the Quick Match Cs = 0.00825861; k = 7.49263;S = 6.7027;Lrad = 24.4035;M = 0.247993w=0.85

Close the Pan System

Click on "Calculate" and then click on the "OK/Confirm" button the Quick match Window


It will open an "Open Dialog box".

1. Verify that the Reservoir model is "Radial Composite"


1. Verify that the Log-Log Plot is displayed by reading the Name of the Plot.

Grid should contain 174 rows and 4 columns .Row 1;Elapsed Time (hours)=0.009791;P 45367:TP4=0.0188756643398996;Elapsed Time (hours)=0.050807;P 45367 Deriv:TP4=0.0981053353754752Row 87;Elapsed Time (hours)=11.356471;P 45367:TP4=0.910518450100692;Elapsed Time (hours)=11.672877;P 45367 Deriv:TP4=0.10469986667977Row 174;Elapsed Time (hours)=95.906276;P 45367:TP4=1.1678983143558;Elapsed Time (hours)=0;P 45367 Deriv:TP4=01.Well , Reservoir & Fluid description dialog box should be opened2. The Fluid Type under "Fluid Control" tab should be "Water"

1. Verify the below valuesWellbore Radius = 0.5104 ftWellbore Storage Model = Classic Wellbore Storage

2. Click on the OK button of the Dialog box

1. Verify the below valuesFormation Thickness = 234.252 ftPorosity = 0.3Reservoir Model = Radial Composite

2. Click on the OK button of the Dialog box

3. Click on the Cancel button of the Wellbore, fluid and reservoir model window to return to pan system

Verify the below Valuesk = 1171.06S = 2.37Lrad = 48M=0.39w=0.41

Line ResultsModel 1Radial compositeInfinitely actingLog-LogCs = 0.02057 bbl/psi TP4k = 4.5452 md TP4kh = 1064.715 md.ft TP4M = 0.4456 TP4S = 2.6835 TP4Spr = -1.3233 TP4

Verify the Plot by reading the Name of the Plot as " Radial Flow Plot"

Grid Should have 175 Rows and 2 Columns Row1 : Time Hours = 2282988.14613467;P47367:TP4 = 2470.133; Row87 : Time Hours = 736.946442949141 ; P47367:TP4 = 1990.290649 ;Row175 : Time Hours = 102.029396667363 ; P47367:TP4 = 1853.080933 ;

Verify that the Quick match Window is Popped Up

Line Results Model 1 Radial composite Infinitely acting Log-Log Cs = 0.02057 bbl/psi TP4 k = 4.5452 md TP4 kh = 1064.715 md.ft TP4 M = 0.4456 TP4 S = 2.6835 TP4 Spr = -1.00995 TP4 Semi-Log dpS = 197.282 psi TP4 FE = 0.71388 TP4 k = 4.6462 md TP4 kh = 1088.371 md.ft TP4 Lrad = 34.326 ft TP4 M = 0.43326 TP4 P* = 1498.261 psia TP4 Rinv = 149.638 ft TP4 S = 2.9696 TP4 Spr = -1.09849 TP4

Verify that the Log-Log graph is displayed by reading the Title of the Plot


Quick Match Results 1 Radial composite Infinitely acting Constant compressibility Cs = 0.00826 bbl/psi (k/u)w = 7.8453 md/cp k = 7.4926 md kh = 1755.164 md.ft S = 6.7027 Lrad = 24.404 ft M = 0.24799 w = 0.85 Spr = -1.246 Pi = 1469.927 psia dpS = 276.121 psi


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1. Go to Analysis >> Tools.Click on 'Unit Slope'.2. Select 'Wellbore Storage' and click on 'Ok'.

1. Go to Analysis >> Tools.Click on 'Zero' Slope'.2. Select 'Late pseudo-radial flow' and click on 'Ok'.

Verify the line results displayed under the tab 'Line Results' in the left navigation pane.


Enter the following values in the window 'Quick Match'Cs = 0.001 bbl/psik = 1.41 mdSf = 0.0048Xf = 215.7 ft

Go to Analysis >> Conventional Analysis >> Semi - Log

Click on Data Grid

1. Click on 'Calculate' button and then click on 'Ok/Confirm' button.2. Click on 'Data Grid'.


Clear workspace and open the file Example13_1_1.panx again

Click on Analysis >> Tools >> Confirm ResultsClick on 'Ok'.

Go to Analysis >> Conventional Analysis >> Linear

Click on Data Grid




1. Click on Analysis >> Tools >> Confirm Results. 2. In the window 'Confirm Results', click on 'Ok'

1. Go to Simulation >> Analytical Simulation >> Quick Match.2. Enter the following values in the window 'Quick Match'Cs = 0.001 bbl/psik = 1.54362 mdSf = 0.0048Xf = 207.366 ftClick on 'Calculate' button and then click on 'Ok/Confirm' button

Clear workspace and open the file Example13_1_2.panx


Click on Data Grid

Click on Analysis >> Tools >> Confirm Results

Verify the quick match results displayed under the tab 'Quick match results' in the left navigation pane.


Click on Analysis >> Tools >> Type Curve Match. Click on Ok.

Click on Analysis >> Tools >> Type Curve Match again and click on 'Ok'

Click on 'Ok'.

1. Go to Simulation >> Analytical Simulation >> Quick Match.2. Enter the following values in the window 'Quick Match'Cs = 0 bbl/psik = 1.588 mdSf = 0.0048Xf = 215.7 ftClick on 'Calculate' button and then click on 'Ok/Confirm' button


1. Right click on the node 'Linear' under Model 1. Click on Remove2. Click on 'Yes' button in the window 'Remove'

Click on Analysis >> Model Selection >> Model



1. Right click on the node 'Semi-Log'. Click on Remove2. Click on 'Yes' button in the window 'Remove'

Double click on 'TP2' under node 'Log-Log' under Model 1

1. Select 'Vertical fracture - uniform flux' model from the dropdown 'Reservoir Model (vertical well)'.2. Click on 'Ok'. 3. Click on 'Ok' in the dialog box 'Information'.

1. Select 'Fracture Linear Flow' radio button and click on 'Ok'2. Select 'Late pseudo-radial flow' radio button and click on 'Ok'



Compare the 'Pi' value displayed with the 'Pi' value displayed in step 10.

Go to Analysis >> Conventional Analysis >> Log - Log


Open file Example13_2.pan by navigating to the path Import/Export Data >> From Pan <= 3.x

Go to Analysis >> Model Selection >> Model.

Select 'Vertical fracture - infinite conductivity' model from the dropdown 'Reservoir Model (vertical well)' and select 'Infinitely acting' from the dropdown 'Boundary Model'Click on 'Ok'.



Select 'Time Stepped wellbore storage' model from the dropdown 'Wellbore Storage Model'.Click on 'Ok'.


Click on Data Grid

1. Go to Simulation >> Analytical Simulation >> Quick Match.2. Enter the following values in the window 'Quick Match'Cs = 0.00239449 bbl/psiCs2 = 0.2Tc = 17k = 1.71457 mdSf = 0.682856Xf = 56.2916 ftClick on 'Calculate' button and then click on 'Ok/Confirm' button


Enter 995.2 psia in the text box 'Layer Pressure'. Check the 'Injection well' check box. Enter 2498.33 for the field 'Test Point1' under 'Injection Pressure psia' and enter 450 for the field 'Test Ponit1' under 'Injection Rate STB/day'. Click on 'Calculate'. Click on 'Ok'.

Verify that new plot should be displayed having the name 'Sandface injectivity plot'





Click on Data Grid



1. Go to Analysis >> Tools. Fit lines as shown in the screenshot by clicking on 'Unit Slope', 'Zero Slope', '1/2 Slope' and '1/4 Slope' in the toolbar. 2. Select 'Wellbore Storage' option for 'Unit Slope' and select 'Radial Flow' option for 'Zero Slope' in the window 'Define Line' displayed

Observe the line results displayed under the tab 'Line Results' in the left navigation pane

Go to Analysis >> Conventional Analysis >> Linear

Click on Data Grid



1. Go to Simulation >> Analytical Simulation >> Quick Match.2. Enter the following values in the window 'Quick Match'Cs = 0.0067 bbl/psik = 0.9844 mdSf = 0Xf = 419.6 ftFcd = 20.05


Veirfy the quick match results displayed in the 'Quick Match Results' tab in the left navigation pane.

Double click on the node 'Linear : PFO-1:TP2'

Click on Data Grid


Click on Data Grid




1. Go to Analysis >> Tools >> Confirm Results.2. Click on 'Ok' in the window 'Confirm Results'



Click on Data Grid


1. Go to Analysis >> Tools >> Confirm Results.2. Click on 'Ok' in the window 'Confirm Results'



Go to Analysis >> Tools >> Type Curve match

Click on 'Ok'

Go to Analysis >> Tools >> Type Curve Match

Go to Analysis >> Tools >> Confirm Results

Click on 'Ok'


Select nearest curve '5' from the dropdown and Click on 'Ok'.






1. Go to Simulation >> Analytical Simulation >> Quick Match.2. Enter the following values in the window 'Quick Match'Cs = 0.009 bbl/psik = 0.872 mdSf = 0Xf = 487.4 ftFcd = 20



Select 'Vertical fracture - finite conductivity' model from the dropdown 'Reservoir Model'.Click on 'Ok'.

Clear the work space and open the file Example13_4_2.panx



1. Go to Simulation >> Analytical Simulation >> Quick Match.2. Enter the following values in the window 'Quick Match'Cs = 0.0445 bbl/psik = 0.7862 mdSf = 0Xf = 252.6 ftFcd = 5.036




1. New window 'Define Line' should be displayed.

1. New window 'Define Line' should be displayed.



The following line results should be displayed.

Line Results Model 1 Vertical fracture - infinite conductivity Infinitely acting Log-Log Cs = 0.96603 bbl/psi TP2 k = 3.0126 md TP2 kh = 320.84 md.ft TP2 Spr = -4.6908 TP2

Grid should contain 5000 rows and 8 columns .Row 1;Elapsed Time (hours) - Tp=495.0000=0.0499879999999919;Sim P:TP2=28.1713890000001;Elapsed Time (hours) - Tp=495.0000=0.0999760000000265;Sim P Deriv:TP2=23.472093506095;Elapsed Time (hours) - Tp=495.0000=0.0499880274919491;Model 1 QM Prs 1=34.6611396941107;Elapsed Time (hours) - Tp=495.0000=0.0544791576361163;Model 1 QM Deriv 1=17.0810355453496Row 2500;Elapsed Time (hours) - Tp=495.0000=124.969482;Sim P:TP2=988.377114;Elapsed Time (hours) - Tp=495.0000=125.01947;Sim P Deriv:TP2=315.499540819495;Elapsed Time (hours) - Tp=495.0000=0;Model 1 QM Prs 1=0;Elapsed Time (hours) - Tp=495.0000=0;Model 1 QM Deriv 1=0Row 5000;Elapsed Time (hours) - Tp=495.0000=250;Sim P:TP2=1151.074703;Elapsed Time (hours) - Tp=495.0000=0;Sim P Deriv:TP2=0;Elapsed Time (hours) - Tp=495.0000=0;Model 1 QM Prs 1=0;Elapsed Time (hours) - Tp=495.0000=0;Model 1 QM Deriv 1=0The following values in the window 'Quick Match'

Quick Match Results 1 Vertical fracture - infinite conductivity Infinitely acting Constant compressibility Cs = 0.001 bbl/psi (k/u)w = 2.0348 md/cp k = 1.41 md kh = 150.165 md.ft Sf = 0.0048 Xf = 215.7 ft Spr = -6.0622 Pi = 5866.145 psia Pi(d) = 5984.945 psia dpSpr = -4258.051 psi

A plot should appear. Verify by reading the Plot title: Radial Flow Plot

New window 'Confirm Results' should be displayed

Grid should contain 5000 rows and 2 columns .Row 1;Horner Time Function - Tp=495.0000=9903.37657037849;Sim P:TP2=7362.848405Row 2500;Horner Time Function - Tp=495.0000=4.96096704633856;Sim P:TP2=6402.64268Row 5000;Horner Time Function - Tp=495.0000=2.98;Sim P:TP2=6239.945091

The following line results should be displayed.Line ResultsModel 1Vertical fracture - infinite conductivityInfinitely actingSemi-Logk = 1.5405 md TP2kh = 164.063 md.ft TP2dpSpr = -3738.598 psi TP2FE = 3.4893 TP2P* = 5889.146 psia TP2P*(d) = 6007.946 psia TP2Rinv = 734.348 ft TP2Spr = -5.8153 TP2

A plot should appear. Verify by reading the Plot title: Linear Flow Plot

Grid should contain 5000 rows and 2 columns .Row 1;Tandem Square-root Function - Tp=495.0000=22.02613886636;Sim P:TP2=7362.848405Row 2500;Tandem Square-root Function - Tp=495.0000=13.7202113745135;Sim P:TP2=6402.64268Row 5000;Tandem Square-root Function - Tp=495.0000=11.4832998270705;Sim P:TP2=6239.945091


1. New window 'Confirm Results' should be displayed2. The following line results should be displayed.

Line ResultsModel 1Vertical fracture - infinite conductivityInfinitely actingLineark = 1.5405 md TP2P* = 4217.225 psia TP2P*(d) = 4336.025 psia TP2Sf = -0.00375 TP2Xf = 207.577 ft TP2Semi-LogdpSpr = -3738.598 psi TP2FE = 3.4893 TP2kh = 164.063 md.ft TP2P* = 5889.146 psia TP2P*(d) = 6007.946 psia TP2Rinv = 734.348 ft TP2Spr = -5.8153 TP2

New window 'Select Type Curve' should be displayed

New window 'Confirm Results' should be displayed

The following values should be displayed in the tab 'Quick Match results'.

Quick Match Results 1 Vertical fracture - infinite conductivity Infinitely acting Constant compressibility Cs = 0.001 bbl/psi (k/u)w = 2.2277 md/cp k = 1.5436 md kh = 164.396 md.ft Sf = 0.0048 Xf = 207.366 ft Spr = -6.0228 Pi = 5945.047 psia Pi(d) = 6063.847 psia dpSpr = -3864.182 psi

A plot should appear. Verify by reading the Plot title: Log Log Plot


Grid should contain 5000 rows and 4 columns .Row 1;Elapsed Time (hours) - Tp=495.0000=0.0499879999999919;Sim P:TP1=28.1713890000001;Elapsed Time (hours) - Tp=495.0000=0.0999760000000265;Sim P Deriv=23.472093506095Row 2500;Elapsed Time (hours) - Tp=495.0000=124.969482;Sim P:TP1=988.377114;Elapsed Time (hours) - Tp=495.0000=125.01947;Sim P Deriv=315.499540819495Row 5000;Elapsed Time (hours) - Tp=495.0000=250;Sim P:TP1=1151.074703;Elapsed Time (hours) - Tp=495.0000=0;Sim P Deriv=0

New window 'Verify selected nearest curve' should be displayed

The following line results should be displayed. Verify the presence of the parameters: Match Results Model 1 Vertical fracture - infinite conductivity Infinitely acting Typecurve Cd Cs k kh Spr Xf Log-Log

The following values should be displayed in the tab 'Quick Match results'.


1. A new window 'Remove' should be displayed.2. The node should be removed from the workspace

Verify by reading Plot Title 'Log-Log Plot'

1. New window 'Define Line' should appear.

1. A new window 'Remove' should be displayed.2. The node should be removed from the workspace

1. A new window 'Select Analysis Model' should be displayed.2. New dialog 'Information' should appear.3. New window 'Define Line' should appear.

The following values in the window 'Quick Match'. Quick Match Results 1 Vertical fracture - uniform flux Infinitely acting Constant compressibility Cs = 0.001 bbl/psi (k/u)w = 2.0348 md/cp k = 1.41 md kh = 150.165 md.ft Sf = 0.0048 Xf = 215.7 ft Spr = -5.7554 Pi = 5734.819 psia Pi(d) = 5853.619 psia dpSpr = -4042.516 psi

Observe that the 'Pi' values are different for different Reservoir models



The plot 'Test Overview' should be displayed.

A new window 'Select Analysis Model' should be displayed.





Quick Match Results 1 Vertical fracture - infinite conductivity Infinitely acting Constant compressibility Cs = 0.0024 bbl/psi (k/u)w = 2.5479 md/cp k = 1.715 md kh = 138.915 md.ft Sf = 0.6829 Xf = 56.29 ft Spr = -3.7692 Pi = 995.5 psia dpSpr = -1160.455 psi

The plot 'Sandface injectivity plot' is displayed


The following values in the window 'Quick Match'. Quick Match Results 1 Vertical fracture - infinite conductivity Infinitely acting Constant compressibility Cs = 0.00239 bbl/psi (k/u)w = 2.5473 md/cp Cs2 = 0.2 bbl/psi Tc = 17 hr k = 1.7146 md kh = 138.88 md.ft Sf = 0.68286 Xf = 56.292 ft Spr = -3.7693 Pi = 995.184 psia

A new window 'Transient and welltest injectivity results' should be displayed

Observe that Injectivity Index(J) is calculated automatically after clicking on 'Calculate' button.

Grid should have 200 rows and 2 columns.Row 1: Injection Rate(STB/day) = 0; IPR-Trans Test = 995.2;Row 100: Injection Rate(STB/day) = 1424.70943504463; IPR-Trans Test = 5474.97487437186;Row 200: Injection Rate(STB/day) = 2863.80987448363; IPR-Trans Test = 9999.99999999997;

The following quick match results should be displayed.

IPR Results Vertical fracture - infinite conductivity Infinitely acting IPR-Trans Test J = 0.31803 STB/day/psi




Grid should contain 88 rows and 4 columns .Row 1;Elapsed Time (hours) - Tp=3501.0000=4.44444590019799E-07;Pressure:TP2=0.0000489999997626;Elapsed Time (hours) - Tp=3501.0000=0.00100044444458991;Pressure Deriv:TP2=1.86880407779128Row 44;Elapsed Time (hours) - Tp=3501.0000=5.00000044444459;Pressure:TP2=297.8;Elapsed Time (hours) - Tp=3501.0000=6.00000044444459;Pressure Deriv:TP2=103.509952867704Row 88;Elapsed Time (hours) - Tp=3501.0000=230.000000444445;Pressure:TP2=1271.3;Elapsed Time (hours) - Tp=3501.0000=0;Pressure Deriv:TP2=01. New window 'Define Line' should be displayed for 'Unit Slope' and 'Zero Slope'

The following line results should be displayed. Line Results Model 1 Radial homogeneous Infinitely acting Log-Log Cs = 0.59087 bbl/psi TP2 k = 2911.791 md TP2 kh = 75706.574 md.ft TP2


Verify the plot by reading the Title of the Plot "Log-Log Plot"

The following line results should be displayed.

Line ResultsModel 1Vertical fracture - finite conductivityInfinitely actingLog-Logk = 12.332 md TP2kh = 320.622 md.ft TP2Spr = -4.4614 TP2

The following values should be displayed in the window 'Quick Match' Quick Match Results 1 Vertical fracture - finite conductivity Infinitely acting Constant compressibility Cs = 0.0067 bbl/psi (k/u)w = 1.2876 md/cp k = 0.9844 md kh = 25.594 md.ft Sf = 0 Xf = 419.6 ft Fcd = 20.05 kfW = 8281.738 md.ft Spr = -6.7509 Pi = -395.46 psia dpSpr = -9967.91 psi


1. New window 'Confirm Results' should be displayed

Grid should have 100 rows and 4 columns.Row 1: Tandem Square-root Function - Tp=3501.0000 = 59.1685821031722; Pressure:TP 2= 2603.800049; Tandem Square-root Function - Tp=3501.0000 = 59.1682487746427; Model 1 QM Prs 1 = 2603.79782390846;Row 50: Tandem Square-root Function - Tp=3501.0000 = 55.5457779849612; Pressure:TP 2= 2181.300049; Tandem Square-root Function - Tp=3501.0000 = 59.0520600462301; Model 1 QM Prs 1 = 2582.64875913907;Row 100: Tandem Square-root Function - Tp=3501.0000 = 0; Pressure:TP2 = 0; Tandem Square-root Function - Tp=3501.0000 = 45.9161591722753; Model 1 QM Prs 1 = 1337.32009112458;


Grid should have 88 rows and 2 columns.Row 1: Tandem Square-root Function - Tp=3501.0000 = 59.1685821031722; Pressure:TP2 = 2603.800049; Row 44: Tandem Square-root Function - Tp=3501.0000 = 56.9754172954692; Pressure:TP2 = 2306; Row 88: Tandem Square-root Function - Tp=3501.0000 = 45.9161613135458; Pressure:TP2 = 1332.5;

The following line results should be displayed under the tab 'Line Results'.

Line ResultsModel 1Vertical fracture - finite conductivityInfinitely actingLinearFcd = 34.104 TP2k = 0.9844 md TP2Xf = 410.146 ft TP2kfW = 13769.32 md.ft TP2P* = -2626.236 psia TP2Spr = -6.7402 TP2

A plot should appear. Verify by reading the Plot title: Bilinear Flow Plot

1. New window 'Confirm Results' should be displayed

Grid should have 88 rows and 2 columns.Row 1: Tandem Fourth-root Function - Tp=3501.0000 = 7.66633512359628; Pressure:TP2 = 2603.800049; Row 44: Tandem Square-root Function - Tp=3501.0000 = 6.1995511441155; Pressure:TP2 = 2306; Row 88: Tandem Square-root Function - Tp=3501.0000 = 3.92116890214216; Pressure:TP2 = 1332.5;


Line ResultsModel 1Vertical fracture - finite conductivityInfinitely actingBilinearFcd = 8.9843 TP2kfW = 3627.392 md.ft TP2P* = 814.764 psia TP2Lineark = 0.9844 md TP2kfW = 13769.32 md.ft TP2P* = -2626.236 psia TP2Spr = -6.7402 TP2Xf = 410.146 ft TP2


Grid should contain 88 rows and 4 columns .Row 1;Elapsed Time (hours) - Tp=3501.0000=4.44444590019799E-07;Pressure:TP1=0.0000489999997626;Elapsed Time (hours) - Tp=3501.0000=0.00100044444458991;Pressure Deriv=1.86880407779128Row 44;Elapsed Time (hours) - Tp=3501.0000=5.00000044444459;Pressure:TP1=297.8;Elapsed Time (hours) - Tp=3501.0000=6.00000044444459;Pressure Deriv=103.509952867704Row 88;Elapsed Time (hours) - Tp=3501.0000=230.000000444445;Pressure:TP1=1271.3;Elapsed Time (hours) - Tp=3501.0000=0;Pressure Deriv=0

A new window 'Select Type Curve' should be displayed

A new set of Type curves should appear on the plot

A new window 'Confirm Results' should be displayed

The following line results should be displayed under the tab 'Line Results'.Verify only the presence of the parameters:

Match Results Model 1 Vertical fracture - finite conductivity Infinitely acting Bilinear Linear Typecurve Fcd k kfW kh Spr Xf

A new window 'Verify selected nearest curve' should be displayed

The following line results should be displayed under the tab 'Line Results'. Verify only presence of Parameters

Match Results Model 1 Vertical fracture - finite conductivity Infinitely acting Typecurve Fcd k kfW kh Spr Xf Bilinear Linear




Quick Match Results 1 Vertical fracture - finite conductivity Infinitely acting Constant compressibility Cs = 0.009 bbl/psi (k/u)w = 1.1406 md/cp k = 0.872 md kh = 22.672 md.ft Sf = 0 Xf = 487.4 ft Fcd = 20 kfW = 8500.256 md.ft Spr = -6.9006 Pi = -450.23 psia dpSpr = -11502.258 psi







Quick Match Results 1 Vertical fracture - finite conductivity Infinitely acting Constant compressibility Cs = 0.0445 bbl/psi (k/u)o = 2.3824 md/cp k = 0.7862 md kh = 83.73 md.ft Sf = 0 Xf = 252.6 ft Fcd = 5.036 kfW = 1000.12 md.ft Spr = -5.9695 Pi = 5878.54 psia Pi(d) = 5950.63 psia dpSpr = -5781.338 psi



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Test Description (Action)Open the PanSystem application

Click on Data Grid

Click on Data Grid

From the Navigation Pane click on the "Import/Export Data" and then click on the Menu Item "From Pan <=3.x" under Import Data tab

Navigate to the location where the files are present and select "Example14_1.pan" file and click on the Open Button on the open dialog box



Click on "Well Control" tab and then click on "Well parameters" button.Enter 0.4ft for Wellbore radius and select 'Classic Wellbore Storage' for Wellbore Storage Model.Click on the OK button of the Dialog box

1. Click on "Layer Control" tab and then click on "Layer parameters" button. Enter the below values:Formation Thickness = 100 ftPorosity = 0.1Reservoir Model = Radial homogeneous2. Click "OK".3. Click OK to close the Wellbore, fluid and reservoir model window to return to pan system

Select "Analysis" on the Navigation pane and then click on Log-Log menu item under the "Conventional Analysis".


Verify the Line Results Displayed on the Navigation Pane


1. Click on "Model Selection" menu tab and then click on the "Model" menu item. Select 'Dual-porosity (Pseudo steady state)' model from the drop down "Reservoir model".2. Click on 'Ok'.


Click on the "Confirm Results" menu item under Tools. Click on 'Ok'.

Click on Semi-Log menu item under the "Conventional Analysis".


1. Click on "Fit parallel lines" menu item under "Tools" menu tab2. Verify the line results displayed in the 'Line Results' tab.

Click on the "Confirm Results" menu item under Tools

Verify the Line Results Displayed on the Navigation Pane


1. Clear workspace and open the file Example14_1_2.panx2. Verify the line results displayed


Input Values in the Quick MatchCs = 0.1129k = 19.5S = -3.195w = 0.1586Lam = 2.854e-05

Click on Data Grid



1. Click on "Simulation" on the Navigation Pane and then select "Auto match" menu item under "Analytical simulation" tab.2. Click on 'Ok'.

1. Proceed with the Default values in the Automatic Match Window and click on "OK" button of the dialog box.2. Click on 'Ok'

Click on "OK/Confirm" button on the Quick Match Window


Select "Analysis" on the Navigation pane and then click on Type Curves menu item under the "Conventional Analysis".

Click on the "Confirm Results" menu item under Tools


Click on "Type curve match" menu item under "Tools" menu tab

1. Click on the "OK" button on the "Select Type Curve dialog box.

Verify the Line Results displayed under the tab 'Line Results' in the left navigation pane.

2. Click on the "Type Curve match" menu item again and select the Nearest Curve as 8. Click OK.

Click on "Next Stage" menu item under "Tools" menu tab. Click on Type Curve match again and select the Nearest Curve as 1. Click OK.

Verify the Line Results displayed under the tab 'Line Results' in the left navigation pane.




Input Values in the Quick MatchCs = 0.112k = 19.41S = -3.926w = 0.1655Lam = 2.814e-5




It will open an "Open Dialog box".

Verify that the "Log-Log" plot is displayed on the Graph

1. Verify tree view in the Navigation Pane.2. Double click on "X24:Pressure" in the tree view to open the "Data Edit" plot.

Grid should contain 29 rows and 4 columns .Row 1;Time (Hours)=0.0933;X24:Pressure=4373.399902;Time (Hours)=0;X24:Rate Schedule=0Row 15;Time (Hours)=3.427;X24:Pressure=3971.300049;Time (Hours)=0;X24:Rate Schedule=0Row 29;Time (Hours)=53.43;X24:Pressure=3625.199951;Time (Hours)=0;X24:Rate Schedule=01.Well , Reservoir & Fluid description dialog box should be opened2. The Fluid Type under "Fluid Control" tab should be "Oil"

Verify Plot name is Log-Log Plot

Verify that the "Radial Flow Plot" is displayed on the Graph

Grid should contain 29 rows and 4 columns .Row 1;Elapsed Time (hours)=0.0933;Pressure:TP1=99.6000979999999;Elapsed Time (hours)=0.1766;Pressure Deriv:TP1=129.257120214995Row 15;Elapsed Time (hours)=3.427;Pressure:TP1=501.699951;Elapsed Time (hours)=4.427;Pressure Deriv:TP1=85.4678917732637Row 29;Elapsed Time (hours)=53.43;Pressure:TP1=847.800049;Elapsed Time (hours)=0;Pressure Deriv:TP1=0


Line ResultsModel 1Dual-porosity (Pseudo steady state)Infinitely actingLog-LogCs = 0.21348 bbl/psi TP1k = 19.003 md TP1kh = 1900.299 md.ft TP1Lam = 6.6686e-5 TP1S = -3.9953 TP1w = 0.2739 TP1

Line ResultsModel 1Dual-porosity (Pseudo steady state)Infinitely actingLog-LogCs = 0.21348 bbl/psi TP1k = 19.003 md TP1kh = 1900.299 md.ft TP1Lam = 6.6686e-5 TP1S = -3.9953 TP1w = 0.2739 TP1

Grid should contain 29 rows and 2 columns .Row 1;Elapsed Time (hours)=0.0933;Pressure:TP1=4373.399902Row 15;Elapsed Time (hours)=3.427;Pressure:TP1=3971.300049Row 29;Elapsed Time (hours)=53.43;Pressure:TP1=3625.1999511. Select "Fracture radial flow" radio button option in the "Define Line" dialog box

2 A value for ω should be calculated as ω is a function of the vertical distance between those two parallel lines. w = 0.5649 TP1The following line results should be displayed.Line ResultsModel 1Dual-porosity (Pseudo steady state)Infinitely actingSemi-LogdpS = -1070.521 psi TP1FE = 2.2627 TP1k = 19.432 md TP1kh = 1943.182 md.ft TP1Rinv = 539.494 ft TP1S = -3.9286 TP1w = 0.56489 TP1Log-LogCs = 0.21348 bbl/psi TP1k = 19.003 md TP1kh = 1900.299 md.ft TP1Lam = 6.6686e-5 TP1S = -3.9953 TP1w = 0.2739 TP1

Click on "OK" button of the Confirm Results dialog box

Verfiy the plot title by reading 'Log-Log Plot'.

1. Verify if the plot 'Radial Flow Plot' is displayed.

2. Line ResultsModel 1Dual-porosity (Pseudo steady state)Infinitely actingSemi-LogdpS = -1070.521 psi TP1FE = 2.2627 TP1k = 19.432 md TP1K/bh2 = 8.9174e-5 md/ft2 TP1kh = 1943.182 md.ft TP1Lam = 8.8110e-6 TP1Rinv = 539.494 ft TP1S = -3.9286 TP1w = 0.40723 TP1

Line ResultsModel 1Dual-porosity (Pseudo steady state)Infinitely actingSemi-Logk = 19.432 md TP1kh = 1943.182 md.ft TP1Lam = 8.8110e-6 TP1S = -3.9286 TP1w = 0.40723 TP1dpS = -1070.521 psi TP1FE = 2.2627 TP1K/bh2 = 8.9174e-5 md/ft2 TP1Rinv = 539.494 ft TP1

Verify by reading the plot name "Type Curve Plot"

Quick Match Results 1 Dual-porosity (Pseudo steady state) Infinitely acting Constant compressibility Cs = 0.1129 bbl/psi (k/u)o = 19.5 md/cp k = 19.5 md kh = 1950 md.ft S = -3.195 w = 0.1586 Lam = 2.8540e-5 Pi = 4473 psia dpS = -867.565 psi

1. New window 'Auto Match - Ponits Selection' is displayed.2. New window 'Automatic Matching; should be displayed.

1. New window 'Matching Progress' should appear2. New window 'Quick Match' should be displayed.

Quick Match Results 1 Dual-porosity (Pseudo steady state) Infinitely acting Constant compressibility Cs = 0.11294 bbl/psi (k/u)o = 19.503 md/cp k = 19.503 md kh = 1950.26 md.ft S = -3.9151 w = 0.15857 Lam = 2.8540e-5 Pi = 4473 psia dpS = -1062.961 psi

Click on "OK" button of the Confirm Results dialog box

Grid should contain 29 rows and 4 columns .Row 1;Elapsed Time (hours)=0.0933;Pressure:TP1=99.6000979999999;Elapsed Time (hours)=0.1766;Pressure Deriv=129.257120214995Row 15;Elapsed Time (hours)=3.427;Pressure:TP1=501.699951;Elapsed Time (hours)=4.427;Pressure Deriv=85.4678917732637Row 29;Elapsed Time (hours)=53.43;Pressure:TP1=847.800049;Elapsed Time (hours)=0;Pressure Deriv=0

Make sure that the following options are selected in the "Select Type Curve" dialog box1. Type Curve Method: "Derivative Match"2. Type Curve Starting stage: Dual porosity-pseudo steady state flow3. Default Type Curves radio button

Match Results Model 1 Dual-porosity (Pseudo steady state) Infinitely acting Typecurve k kh Lam w

Match Results Model 1 Dual-porosity (Pseudo steady state) Infinitely acting Typecurve Cd Cs k kh Lam w

Quick Match Results 1 Dual-porosity (Pseudo steady state) Infinitely acting Constant compressibility Cs = 0.112 bbl/psi (k/u)o = 19.41 md/cp k = 19.41 md kh = 1941 md.ft S = -3.926 w = 0.1655 Lam = 2.8140e-5 Pi = 4473 psia dpS = -1071.003 psi




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Test Description (Action)Open Pan System

Open Example15_1_1.panxClick on Data GridRead Grid and Click OK.

Click Analysis > Plot Types > Log-Log


Go to Simulation> Analytical simulation. Click Quick Match.In the Quick Match window input as below:Cs =0.004, k= 3.3406, S =-2.94166, D = 0.000249257. Change Start time to 0.01. Click Calculate. Then Click OK/Confirm.

Click Calculate

Click OK


Click on IPR - Trans/Log-Log button

In the navigation pane, verify IPR quick match results



Click Deliverability > IPR > Calculate IPR. In the Transient WellTest and LIT Result dialogue, Change the layer pressure to 6958 psia

Click on Confirm ResultsClick OK


Click on IPR Both/Log-Log button under IPR

Click on Data Grid

Click Deliverability > IPR > Calculate IPR. Click Calculate

Click OK on the dialogue box. Click IPR Both/Linear button under IPR

In the navigation pane, Click on Quick Match tab and verify the Quick Match Results


Close the files and open file Example15_1_3.panx



In the navigation pane, verify the line Results

Open file Example15_1_4.panx.

Click OK


Click on Deliverability > Gas Deliverability > C+nIn the Select testtype, select "Flow-after-flow". Click OKIn the C&n Analysis dialogue box, Change the pressure to 6958 psia

Click on Fit line of known slope button under Gas Deliverability and Enter slope as 1 in the dialogue box

Click OK. In the define line dialogue box, select Extended Flow and click OK

In the navigation pane, click on Line Results tab to verify the line results


Click Deliverability > IPR > Calculate IPR.

Click Calculate

Click OK

Click on IPR - Ext/Linear button under IPRClick on Data GridRead Grid and Click OK.

Click on IPR - Both/Linear button under IPR


In the navigation pane, verify quick match results

Click on IPR - Both/Log-Log button under IPR




Open Pan System

Click on Calculate IPR under IPR. On the C&n Result dialogue box, Click on More Results button.

Open Example15_2_1.panx


Click on Analysis > Plot Types > Semi-Log

In the navigation pane, verify the line results



In the navigation pane, Click on Line Results tab to verify the line results


Click OK

Click on Analysis > Skin analysis > Skin Vs FlowRate


Click on Fit line of known slope under Analysis Tools. In the known line dialogue box, enter the slope as 7.6 and Click OK. In the Define Line dialogue, select Radial Flow and Click OK

Click on Analysis > Skin Analysis > Rate-Dependent Skin Analysis

Click OK.In the Define Line select TP2: Radial Flow

Click on Fit Parallel Lines button under Analysis Tools. In the Define Line dialogue box, select TP4: Radial Flow. Click OK

Click on Fit Parallel Lines button under Analysis Tools. In the Define Line dialogue box, select TP6: Radial Flow. Click OK

Click on Fit line of known slope. In the known line dialogue box, enter the slope as 1.0 and Click OK. In the Define Line dialogue, select Skin Calculation and Click OKIn the Enter Model Parameter dialogue, enter the permeability as 1.306

Click OK. In the navigation pane, verify the line results

Click OK



Click OK

Click on Data Grid

Click on Confirm Results button under Analysis Tools.Click OK

Click Deliverability > IPR > Calculate IPR. In the Transient WellTest and LIT Result dialogue, Click Calculate button

In the navigation pane, click on Quick Match tab to verify the quick match results

Click on Deliverability > Gas Deliverability > LIT In the Select test type, select Isochronal and Click OK





Click on Fit line of known slope button under Gas Deliverability.In the known line dialogue box, enter the slope as 3 and click OKIn the Define line dialogue box, select Free model line and Click Ok

Click on Fit Parallel line button under Gas Deliverability.In the Define Line dialogue box, select Extended Flow and Click OK.

Click on Confirm Results button under gas Deliverability. Click OK


Verify by reading plot title "Test Overview Plot"

Grid should contain 431 rows and 4 columns .Row 1;Time (Hours)=5.3667;TESTC:Pressure 1=7147.54;Time (Hours)=5.669699967;:Model 1 QM Prs 1=4663.786848Row 216;Time (Hours)=26.3098;TESTC:Pressure 1=4966.99;Time (Hours)=32.4195056943506;:Model 1 QM Prs 1=2732.293355Row 431;Time (Hours)=47.833328;TESTC:Pressure 1=6619.299805;Time (Hours)=0;:Model 1 QM Prs 1=0Verify that a plot is being displayed by validating the title text "Log-Log Plot"

Grid should contain 99 rows and 4 columns .Row 1;Elapsed Time (hours)=0.099960000000003;Pressure 1:TP7=84.1355227513056;Elapsed Time (hours)=0.19997;Pressure 1 Deriv:TP7=11.3864306539724Row 50;Elapsed Time (hours)=5.066627;Pressure 1:TP7=122.41409520769;Elapsed Time (hours)=5.16663000000001;Pressure 1 Deriv:TP7=9.78493993455887Row 99;Elapsed Time (hours)=10.066627;Pressure 1:TP7=126.806261320536;Elapsed Time (hours)=0;Pressure 1 Deriv:TP7=0Quick Match Results 1 Radial homogeneous Infinitely acting Constant compressibility Cs = 0.004 bbl/psi Keffo = 3.3406 md Keffg = NaN md Keffw = NaN md k/ut = NaN md/cp V = 59.699 bbl kh = 53.45 md.ft S = -2.94166 D = 2.4926e-4 1/(Mscf/day) Pi = 6957.575 psia dpS = -2224.1001 psi

Verify by reading the Title of the plot "Sandface AOF plot"

Verify by reading the title of the plot "Sandface LIT Plot".

Verify the Diet Shapez factor = 31.62 and Drainage Area = 640

Verify the values under Transient Test Well Data:Darcy flow coefficient: 105850Rate Dependent Skin Coeff: 4.92491AOF: 12.1063

Verify by reading the Title of the plot "Sandface Deliverability plot"

Grid should contain 200 rows and 2 columns .Row 1;Flow Rate (MMscf/day)=12.1063412822173;IPR-Trans Test=14.6499996185303Row 100;Flow Rate (MMscf/day)=8.54994026298708;IPR-Trans Test=3468.87939679323Row 200;Flow Rate (MMscf/day)=-1.09649184640175E-13;IPR-Trans Test=6958.00000000003

IPR Results Radial homogeneous Infinitely acting IPR-Trans Test B = 105850.064 psi2/cp/(Mscf/day) F = 4.9249 psi2/cp/(Mscf/day)2 AOF = 12.106 MMscf/day

Grid should contain 4 rows and 2 columns .Row 1;Flow Rate (MMscf/day)=3.95;Sandface LIT Plot: LIT Data: Flow After Flow=91.5022771688102Row 2;Flow Rate (MMscf/day)=6.6;Sandface LIT Plot: LIT Data: Flow After Flow=110.653148498697Row 4;Flow Rate (MMscf/day)=12.11;Sandface LIT Plot: LIT Data: Flow After Flow=137.074055529975Line ResultsModel 1Radial homogeneousInfinitely actingLITAOF = 13.599 MMscf/day TP*B = 71826.814 psi2/cp/(Mscf/day) TP*F = 5.5505 psi2/cp/(Mscf/day)2 TP*

Verify by reading title of the plot " Sandface AOF Plot"

Verify the Lower LIT panel is now InitializedRate-Dependent Skin Flow Coeff: 5.55053Darcy Flow Coeff: 71826.8Rate-Dependent Skin Coeff: 0.0028092AOF: 13.5991

Verify by reading title of the plot " Sandface Deliverability Plot"

Grid should contain 200 rows and 6 columns .Row 1;Flow Rate (MMscf/day)=12.1063412963196;IPR-Trans Test=14.6499996185303;Flow Rate (MMscf/day)=13.5990964153339;IPR-LIT=14.6499996185303;Flow Rate (MMscf/day)=3.95;IPR- AnnotationIPR-Trans Test=5974.04Row 100;Flow Rate (MMscf/day)=8.54994027478218;IPR-Trans Test=3468.87939679323;Flow Rate (MMscf/day)=9.95459111065154;IPR-LIT=3468.87939679323;Flow Rate (MMscf/day)=0;IPR- AnnotationIPR-Trans Test=0Row 200;Flow Rate (MMscf/day)=0;IPR-Trans Test=6958.00000000003;Flow Rate (MMscf/day)=0;IPR-LIT=6958.00000000003;Flow Rate (MMscf/day)=0;IPR- AnnotationIPR-Trans Test=0IPR ResultsRadial homogeneousInfinitely actingIPR-Trans Test B = 105850.064 psi2/cp/(Mscf/day)F = 4.9249 psi2/cp/(Mscf/day)2AOF = 12.106 MMscf/dayIPR-LIT B = 71826.8 psi2/cp/(Mscf/day)F = 5.5505 psi2/cp/(Mscf/day)2AOF = 13.599 MMscf/day

Grid should contain 4 rows and 6 columns .Row 1;Flow Rate (MMscf/day)=12.1063412963196;IPR-Trans Test=1281.45699745979;Flow Rate (MMscf/day)=13.5990964153339;IPR-LIT=976.779578404902;Flow Rate (MMscf/day)=3.95;IPR- AnnotationIPR-Trans Test=274.8318504918Row 2;Flow Rate (MMscf/day)=0.000121063412963196;IPR-Trans Test=0.0128145699745979;Flow Rate (MMscf/day)=0.000135990964153339;IPR-LIT=0.00976779578404902;Flow Rate (MMscf/day)=6.6;IPR- AnnotationIPR-Trans Test=488.5296932914Row 4;Flow Rate (MMscf/day)=0;IPR-Trans Test=0;Flow Rate (MMscf/day)=0;IPR-LIT=0;Flow Rate (MMscf/day)=12.11;IPR- AnnotationIPR-Trans Test=845.969931855Verify that a plot is being displayed by validating the title text "Radial Flow Plot".Also verify the Flow regime is defined in the Plot

Grid should contain 99 rows and 2 columns .Row 1;Superposition Time Function=153.817486621229;Pressure 1:TP7=1362.23890289Row 50;Superposition Time Function=4.21662733591181;Pressure 1:TP7=1825.79241533682Row 99;Superposition Time Function=2.67617741213318;Pressure 1:TP7=1878.98154696338Verify values:Permeability:3.2906Skin Factor:-0.0229Layer Pressure: 6948.0806

Verify by reading the Title of the Plot "Test Overview".

Verify by reading the title of the plot "Sandface C&n plot"

Line ResultsModel 1Radial homogeneousInfinitely actingSemi-Logk = 3.2906 md TP7kh = 52.65 md.ft TP7S = -0.02286 TP7dpS = -19.736 psi TP7FE = 1.0034 TP7P* = 6948.081 psia TP7Rinv = 317.994 ft TP7

Grid should contain 4 rows and 2 columns .Row 1;Flow Rate (MMscf/day)=3.95;Sandface C&n Plot: C and n Data: Flow After Flow=12.7246100784Row 2;Flow Rate (MMscf/day)=6.6;Sandface C&n Plot: C and n Data: Flow After Flow=23.7427743399Row 4;Flow Rate (MMscf/day)=12.11;Sandface C&n Plot: C and n Data: Flow After Flow=43.46714319

Line ResultsModel 1Radial homogeneousInfinitely actingC&nAOF = 14.238 MMscf/day TP*C = 2.9408e-7 MMscf/day/psi2n TP*n = 1 TP*

In the Transient WellTest and LIT Result dialogue, Verify the layer pressure is 6958 psia

The plot is the same as one in the above step

Verify the values under Stabilized DataStabilized flow pressure: 2224.1 Stabilized Flow Rate: 11.1456Stabilized C Coefficient: 2.56414e-07Stabilized AOF: 12.4139

Verify by reading the Title of the plot "Sandface Deliverability plot"

Grid should contain 200 rows and 4 columns .Row 1;Flow Rate (MMscf/day)=14.2375534280372;Extended=14.6499996185303;Flow Rate (MMscf/day)=3.95;IPR- AnnotationExtended=5974.04Row 100;Flow Rate (MMscf/day)=10.6988912932259;Extended=3468.87939679323;Flow Rate (MMscf/day)=0;IPR- AnnotationExtended=0Row 200;Flow Rate (MMscf/day)=0;Extended=6958.00000000003;Flow Rate (MMscf/day)=0;IPR- AnnotationExtended=0Verify by reading the Title of the plot "Sandface Deliverability plot"

Grid should contain 200 rows and 6 columns .Row 1;Flow Rate (MMscf/day)=14.2375534280372;Extended=14.6499996185303;Flow Rate (MMscf/day)=12.4139317618915;Stabilized=14.6499996185303;Flow Rate (MMscf/day)=3.95;IPR- AnnotationExtended=5974.04Row 100;Flow Rate (MMscf/day)=10.6988912932259;Extended=3468.87939679323;Flow Rate (MMscf/day)=9.32852031869858;Stabilized=3468.87939679323;Flow Rate (MMscf/day)=0;IPR- AnnotationExtended=0Row 200;Flow Rate (MMscf/day)=0;Extended=6958.00000000003;Flow Rate (MMscf/day)=0;Stabilized=6958.00000000003;Flow Rate (MMscf/day)=0;IPR- AnnotationExtended=0

Verify by reading the Title of the plot "Sandface AOF plot"

IPR ResultsRadial homogeneousInfinitely actingExtended C = 2.9408e-7 MMscf/day/psi2nn = 1AOF = 14.238 MMscf/dayStabilized C = 2.5641e-7 MMscf/day/psi2nn = 1AOF = 12.414 MMscf/day

Grid should contain 5 rows and 6 columns .Row 1;Flow Rate (MMscf/day)=14.2375534280392;Extended=48.413764;Flow Rate (MMscf/day)=12.4139317618932;Stabilized=48.413764;Flow Rate (MMscf/day)=3.95;IPR- AnnotationExtended=12.7246100784Row 3;Flow Rate (MMscf/day)=0;Extended=0;Flow Rate (MMscf/day)=0;Stabilized=0;Flow Rate (MMscf/day)=9.015;IPR- AnnotationExtended=33.2502943591Row 5;Flow Rate (MMscf/day)=0;Extended=0;Flow Rate (MMscf/day)=0;Stabilized=0;Flow Rate (MMscf/day)=11.1456019313403;IPR- AnnotationExtended=43.46714319This dialog contains a few supplementary resultsrequired by the Canadian EUB of AlbertaVerify Flow Capacity (kh) = 56.5378Permeability (k) = 3.53361Skin (S) = -2.94166Skin Pressure Loss = 0Flow Efficiency = 1.1138Damage Ratio = 0.897826Radius of Investigation = 548.286Time to Stabilization = 646.892Stabilized flow rate = 11.1456Click OK. Click OK



Verify by reading the title of the plot "Radial flow Plot"

Verify by reading the title of the plot "Test Overview".

Verify by reading the title of the plot "Radial flow Plot"

Verify by reading the title of the plot "Log-Log Plot"Also verify the flow regime is defined

Grid should contain 500 rows and 4 columns .Row 1;Elapsed Time (hours)=0.00099999999999767;P#1:TP6=0.790121810641285;Elapsed Time (hours)=0.00101899999999944;P#1 Deriv:TP6=1.13846708047565Row 250;Elapsed Time (hours)=0.108517999999997;P#1:TP6=18.3390521611742;Elapsed Time (hours)=0.110579999999999;P#1 Deriv:TP6=2.86487601518906Row 500;Elapsed Time (hours)=12;P#1:TP6=32.2645880178561;Elapsed Time (hours)=0;P#1 Deriv:TP6=0Line ResultsModel 1Radial homogeneousInfinitely actingLog-Logk = 1.3195 md TP6kh = 131.949 md.ft TP6S = -1.345 TP6

Line ResultsModel 1Radial homogeneousInfinitely actingSemi-LogdpS = -123.286 psi TP6FE = 1.246 TP6k = 1.328 md TP6kh = 132.804 md.ft TP6P* = 7948.526 psia TP6Rinv = 185.459 ft TP6S = -1.2426 TP6Log-Logk = 1.3195 md TP6kh = 131.949 md.ft TP6S = -1.345 TP6

Line ResultsModel 1Radial homogeneousInfinitely actingSemi-Logk = 1.4205 md TP*kh = 142.051 md.ft TP*S = -1.1375 TP*

An Information dialogue box will appear to re-assign the line types when prompted

Verify by reading the title of the plot " Radial Flow Plot - Rate-Dependent Skin Analysis" (In Automation the only the Title is verified which is "Radial Flow Plot"

Verify by reading the tile of the plot "Skin Vs FlowRate plot"

Grid should contain 3 rows and 2 columns .Row 1;Normalised Flow Rate (MMscf/day)=2.8;SvQ Data=-1.13752722758842Row 2;Normalised Flow Rate (MMscf/day)=3.93;SvQ Data=-0.640397718167544Row 3;Normalised Flow Rate (MMscf/day)=5.62;SvQ Data=-0.143268208746667

Verify by reading the title of the Plot "Sandaface LIT Plot"

Line ResultsModel 1Radial homogeneousInfinitely actingSVQD = 0.001 1/(Mscf/day) TP1F = 7.1826 psi2/cp/(Mscf/day)2 TP1S = -4.8504 TP1

Verify under Transient Test Well data :Darcy Flow Coeff (B) = 24769.2Rate Dependent Skin Flow Coeff(B) = 7.18262AOF = 17.3023

Verify by reading the title of the lot "Sandface Deliverability Plot"

Grid should contain 200 rows and 2 columns .Row 1;Flow Rate (MMscf/day)=17.3022654950934;IPR-Trans Test=14.6499996185303Row 100;Flow Rate (MMscf/day)=13.2757349412686;IPR-Trans Test=3963.38190935605Row 200;Flow Rate (MMscf/day)=4.22163392617051E-13;IPR-Trans Test=7951.99999999997IPR ResultsRadial homogeneousInfinitely actingIPR-Trans Test B = 24769.208 psi2/cp/(Mscf/day)F = 7.1826 psi2/cp/(Mscf/day)2AOF = 17.302 MMscf/day

Verify by reading the title of the plot "Test Overview". Verify the 5 buildup periods are selected

In the LIT Analysis -Isochronal test dialogue box, verify Layer pressure = 7952.

Grid should contain 5 rows and 2 columns .Row 1;Flow Rate (MMscf/day)=2.8;Sandface LIT Plot: LIT Data: Isochronal=28.5382423203998Row 3;Flow Rate (MMscf/day)=5.62;Sandface LIT Plot: LIT Data: Isochronal=33.5704016651388Row 5;Flow Rate (MMscf/day)=7.02;Sandface LIT Plot: LIT Data: Isochronal=36.2770433810113

Line ResultsModel 1Radial homogeneousInfinitely actingLITAOF = 25.409 MMscf/day TP*B = 25266.184 psi2/cp/(Mscf/day) TP*F = 3 psi2/cp/(Mscf/day)2 TP*



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Click on 'Analysis'Go to Simulation >> Analytical Simulation >> Auto Match.

Click on 'Ok'

Click on 'Ok'Click on 'Ok/Confirm' button

Click Ok.

Open file Example16.pan by navigating to the path Import/Export Data >> From Pan <= 3.xDouble click on the node 'DSTEX2:Pressure #1'.

Enter the following values.k: Start = 80; Lower = 0.5; Upper = 100 mdCs: Start = 0.023; Lower = 0; Upper = 0.5 bbl/psiS: Start = -0.35; Lower = -8; Upper = 10

Click on 'Ok'


1. Go to Data Preparation >> Well, reservoir & fluid description >> Analytical Model.2. Click on 'Layer Control' tab and click on 'Layer Parameters' button.Notedown the layer pressure displayed in the window i.e. 3528.94

Click on 'Ok' in the window 'Layer parameters - Layer 1 Interpretation 1' and click on 'Ok' in the window 'Well, Reservoir & Fluid Description'

1. Go to Data Preparation >> Rate Schedule >> Rate Schedule.2. Notedown the Pressure(psia) displayed for initial Time Hours at row 1, i.e. Pressure(psia) at row 1 = 3528.94

Click on 'Start Pressures'

Go to Analysis >> View >> Overlay Pressure.

Clear workspace and open the file Example16_01.panx

Click on 'Ok'.Click on 'Yes'. Click on 'Ok'.

Click on Data Grid

Click on Analysis.Go to Simulation >> Analytical Simulation >> Advanced Simulation.

Verify the Layer pressure displayed with the layer pressure noted down in step no. 9 and Wellbore Pressure displayed with the value noted down in step no. 11

Click on 'Ok' in the window 'Advanced Simulation Start Pressures' .Click on 'Ok' in the window 'Advanced Simulation Control'

Click on 'Ok' button. Click on 'Workspace' tab in the left navigation pane. Observe the nodes displayed in the navigation pane.

Uncheck the check box 'Show overlaid pressure' and click on 'Ok'. Click on Data Grid

Click on 'Ok'.Go to Analysis >> View >> Overlay Pressure.

1. Check the check box 'Show overlaid pressure' and click on 'Ok'. Click on Data Grid.2. Click on 'Ok'.

Click on Analysis.Go to Simulation >> Analytical Simulation >> Advanced Simulation.



1. Go to Simulation >> Analytical Simulation >> Quick Match.2. Enter the following values in the window 'Quick Match'Cs = 0.0235533 bbl/psik = 76.1019 mdS = -0.358888



Expected Results StatusThe plot 'Data Edit' should be displayed.

The plot 'Test Overview Plot' should be displayed.

The window 'Auto Matching' should be displayed The window 'Matching Progress' should be displayed

The window 'Quick Match' should be displayed

New window 'Edit Rate Changes' should be displayed.

A confirm dialog box should open. Click Yes

The window 'Auto Match - Points Selection' should be displayed


Quick Match Results 1Radial homogeneousInfinitely actingConstant compressibilityCs = 0.02355 bbl/psi(k/u)o = 126.837 md/cpk = 76.102 mdkh = 7610.19 md.ftS = -0.35889Pi = 3335.734 psia

1. The window 'Well, Reservoir & Fluid Description' is displayed2. The window 'Layer parameters - Layer 1 Interpretation 1' is displayed

A new plot 'Log - Log plot' should be displayed

A new window 'Confirm' should be displayed.

The window 'Advanced Simulation Control' should be displayed

The window 'Advanced Simulation Start Pressures' should be displayed

Both Layer Pressure and Wellbore Pressure should match with the values noted in 'Data Preparation' section

The window 'Calculating Advanced Simulation' should be displayed

Four new nodes 'DSTEX2:Rate Changes','DSTEX2:Sim P', 'DSTEX2:Sim Q Total' and 'DSTEX2:Sim Q#1' should be displayed

New window 'Test Overview Overlay Pressure' should be displayed

New window 'Data View' should be opened.The column 'DSTEX2:Sim P' should not be displayed in the data grid.

New window 'Test Overview Overlay Pressure' should be displayed

1. New window 'Data View' should be opened.The column 'DSTEX2:Sim P' should be displayed in the data grid.

The window 'Advanced Simulation Control' should be displayed

A new window 'Calculating Advanced Simulation' should be displayed.


"Grid should contain 83 rows and 7 columns .Row 1;Elapsed Time (hours)=0.0100020000000001;Pressure #1:TP6=0.0114951866666667;Sim P:TP6=0.0149800065861289;Elapsed Time (hours)=0.0200009999999935;Pressure #1 Deriv:TP6=0.0168351106844933;Elapsed Time (hours)=0.0200009999999935;Sim P Deriv=0.017762123943243Row 42;Elapsed Time (hours)=0.850002999999994;Pressure #1:TP6=0.0760048128571428;Sim P:TP6=0.0795648015964976;Elapsed Time (hours)=0.900001999999994;Pressure #1 Deriv:TP6=0.00623159248707578;Elapsed Time (hours)=0.900001999999994;Sim P Deriv=0.00730434764778413Row 83;Elapsed Time (hours)=8.360001;Pressure #1:TP6=0.0887333752380952;Sim P:TP6=0.092930072152618;Elapsed Time (hours)=0;Pressure #1 Deriv:TP6=0;Elapsed Time (hours)=0;Sim P Deriv=0"

The following values in the window 'Quick Match'

Quick Match Results 1 Radial homogeneous Infinitely acting Constant compressibility Cs = 0.02355 bbl/psi (k/u)o = 126.837 md/cp k = 76.102 md kh = 7610.19 md.ft S = -0.35889 Pi = 3341.201 psia dpS = -10.068 psi


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Test Description (Action)Open PanSystemOpen Example17_1_1.panx file by clicking on the Weatherford Menu and Clicking on Open.

In Data Preparation >>Well, Reservoir & Fluid Description, click on Analytical Model.

In Well, Reservoir & Fluid Description> Well Control tab, check Principal well orientation is vertical.

Click on well parameters. In Well Parameters window enter wellbore radius as 0.35 ft. and Wellbore Storage Model as "Classic Wellbore Storage". Click on Wellbore Storage Model Parameters button and Enter the value of Wellbore Storage Cs as 0.01 bbl/psi. Click OK on the Classic Wellbore Storage Parameter window. Click OK on Well parameters - Well1 window

In Well, Reservoir & Fluid Description> Layer Control tab, click Layer parameters.Provide value of Formation thickness = 100 ft.; Porosity= 0.2, Layer Pressure=5000 psi, Layer Temperature = 0 F, Water Saturation = 0, Gas Saturation = 0 and Rock Compressibility 0.000e+00. Reservoir Model = Radial Homogenous.

Click on Model Parameters button Enter the model parametersRadial Permeability: 91mdSkin: 2.3Click OK on the Radial homogenous dialogue box. Click OK on Layer parameters window

In Well, Reservoir & Fluid Description> Layer Control tab, click Layer fluid parameter. Enter Oil fluid parameters: Bo = 1.1, Uo = 1.7, Ct= 1.0e-005 psi-1. Set pressure as 5000 psia. Click ok on the Oil Fluid Parameters dialogue box

In Well, Reservoir & Fluid Description> Layer Control tab, click Layer Boundaries.On the Boundary parameter dialogue box, provide Boundary model as "Single Fault"

Click on Boundary parameters button. Enter L1 as 250, select the radio button 'No-Flow'. Click Ok.

On the boundary parameters dialogue box, Click on Calculate Image Wells button

Click 'Yes' on the confirmation dialog. Click OK


Click Analysis.

Click on Data Grid

Click OK on the Boundary parameter window. Click OK on the Well, reservoir & Fluid Description window

Click on Data Preparation > Test design > Edit Test Design. On the 'Select a File' dialogue box, Example17_1_1.panx should be already selected. Click OK On the 'Select Well' dialogue box, Well1 should already be selected. Click OK

1.Click the button 'Delete Rows'. In the delete rows dialo, enter First Row as 3 and Last row as '20'. Click Delete.2. Enter the following Test periods in the gridRow 1: t = 10, q = 200, steps = 50, format = 2Row 2: t = 20, q = 0, steps = 50, format = 2

Click OK. Set Test Pressure = 5000 psia in the Test Design Dialogue box that appears. Click OK

Go to Simulation> Analytical simulation. Click on Advanced Simulation. Click Ok on the advanced simulation Control window


Open Example17_1_2.panx file.

Click on Analysis > Plot Types > Log-Log



Click on Analysis > Plot Types > Semi-LogClick on Data Grid

Click on Unit Slope and Select Wellbore storage in the Define Line Dialogue box



Click OKClick on Data Grid

Repeat the experiment by Editing the Test Design by following the steps given below

Close all open files by clicking on the Workspace tab, right clicking on the name of the file in the panel and Selecting remove.Open file Example17_1_2.panx

Click on Data Preparation > Test design > Edit Test Design.

On the 'Select a File' dialogue box, Example17_1_2.panx should be already selected. Click OK On the 'Select Well' dialogue box, Well1 should already be selected. Click OK

Enter the following Test periods in the gridRow 1: t = 10, q = 200, steps = 50, format = 2Row 2: t = 110, q = 0, steps = 50, format = 2

Click OK. Set the Test Pressure = 5000 psia in the Test Design Dialogue box that appears. Click OK


Click Analysis.





Click on Unit Slope button under Analysis ToolsIn the Define Line dialogue pop up, Select Wellbore storage and Click OK

In the navigation pane, verify the Line results

Click on Analysis > Plot Types > Semi-LogIn the navigation pane, verify the line results

Repeat the experiment by Editing the Test Design by following the steps given below

Close all open files by clicking on the Workspace tab, right clicking on the name of the file in the panel and Selecting remove.Open file Example17_1_2.panx

Click on Data Preparation > Test design > Edit Test Design.

On the 'Select a File' dialogue box, Example17_1_2.panx should be already selected. Click OK On the 'Select Well' dialogue box, Well1 should already be selected. Click OK

Enter the following Test periods in the gridRow 1: t = 100, q = 200, steps = 50, format = 2Row 2: t = 200, q = 0, steps = 50, format = 2


Click Analysis.Open file Example17_1_4.panx


In the navigation pane, verify the Line results


Click OK. Check the Test Pressure = 5000 psia in the Test Design Dialogue box that appears. Click OK


Click on Unit Slope button under Analysis ToolsIn the Define Line dialogue pop up, Select Wellbore storage and Click OK


Verify there is only one well

Well, Reservoir & Fluid Description window will pop upIn the Fluid Control tab, check Fluid type is Oil

Confirmation Message box appears which asks user to discard current image wells.

Verify the plot by reading the title "Data Edit Plot"

Dialogue box appears indicating the Number of Image wells per active well as 1. Click OK

1. Rows from number 3 to 20 should be deleted.

Grid should contain 100 rows and 4 columns .Row 1;Time (Hours)=0.00100000004749745;TEST DESIGN:Test Rate=200;Time (Hours)=0;TEST DESIGN:Rate Schedule=0Row 50;Time (Hours)=10;TEST DESIGN:Test Rate=200;Time (Hours)=0;TEST DESIGN:Rate Schedule=0Row 100;Time (Hours)=20;TEST DESIGN:Test Rate=0;Time (Hours)=0;TEST DESIGN:Rate Schedule=0

System should calculate the 100 steps for advanced simulation. Click OK when completeVerify that the 4 Data Files/column list are created under Well 1 in the navigation pane namely Test Rate, Sim P, Sim Q Total, Sim Q#1

A new data set is included on the Navigation Pane called Test Design: Sim P under Test Overview. Plot should read "Test Overview Plot"

Verify by reading the title of the plot "Test Overview Plot"

Verify by reading the plot title "Radial Flow Plot"

Grid should contain 100 rows and 5 columns .Row 1;Time (Hours)=0.00100000004749745;TEST DESIGN:Test Rate=200;TEST DESIGN:Sim P=4999.11279909349;Time (Hours)=0;TEST DESIGN:Rate Schedule=0Row 50;Time (Hours)=10;TEST DESIGN:Test Rate=200;TEST DESIGN:Sim P=4945.0965350133;Time (Hours)=0;TEST DESIGN:Rate Schedule=0Row 100;Time (Hours)=20;TEST DESIGN:Test Rate=0;TEST DESIGN:Sim P=4996.9002985112;Time (Hours)=0;TEST DESIGN:Rate Schedule=0

Verify by reading the title of the plot " Log-Log Plot".


Line ResultsModel 1Radial homogeneousSingle faultLog-LogCs = 0.13525 bbl/psi TP2k = 94.321 md TP2kh = 9432.098 md.ft TP2S = 2.3762 TP2



Grid should contain 50 rows and 2 columns .Row 1;Horner Time Function - Tp=10.0000=10000.9995250255;Sim P:TP2=4945.9832944727Row 25;Horner Time Function - Tp=10.0000=110.854111536618;Sim P:TP2=4978.06965810701Row 50;Horner Time Function - Tp=10.0000=2;Sim P:TP2=4996.9002985112Line ResultsModel 1Radial homogeneousSingle faultSemi-LogdpS = 14.225 psi TP2FE = 0.7345 TP2k = 94.692 md TP2kh = 9469.153 md.ft TP2P* = 4998.675 psia TP2Rinv = 483.965 ft TP2S = 2.5507 TP2Log-LogCs = 0.13525 bbl/psi TP2k = 94.321 md TP2kh = 9432.098 md.ft TP2S = 2.3762 TP2

Confirmation Message box appears which asks user for confirmation to remove all analysis plots. Click Yes

Warning message box should be displayed indicating "Another file exists with this name - overwrite this file?"


Grid should contain 100 rows and 4 columns .Row 1;Time (Hours)=1.00000004749745E-03;TEST DESIGN:Test Rate=200;Time (Hours)=0;TEST DESIGN:Rate Schedule=0Row 50;Time (Hours)=10;TEST DESIGN:Test Rate=200;Time (Hours)=0;TEST DESIGN:Rate Schedule=0Row 100;Time (Hours)=110;TEST DESIGN:Test Rate=0;Time (Hours)=0;TEST DESIGN:Rate Schedule=0

System should calculate the 100 steps for advanced simulation. Click OK when completeVerify that the 4 Data Files/column list are created under Well 1 in the navigation pane namely Test Rate, Sim P, Sim Q Total, Sim Q#1

A new data set is included on the Navigation Pane called Test Design: Sim P under Test Overview. Plot should read "Test Overview Plot"

Verify by reading the title of the plot "Test Overview Plot"Verify the Test Period is selected. This is indicated by the black selection in the ruler bar above the buildup area

Grid should contain 50 rows and 4 columns .Row 1;Elapsed Time (hours) - Tp=10.0000=1.00000004749745E-03;Sim P:TP2=0.886760118898565;Elapsed Time (hours) - Tp=10.0000=1.26485527570708E-03;Sim P Deriv:TP2=1.11513974000103Row 25;Elapsed Time (hours) - Tp=10.0000=0.281176876611292;Sim P:TP2=42.1094610718783;Elapsed Time (hours) - Tp=10.0000=0.355648038896129;Sim P Deriv:TP2=4.5011499463641Row 50;Elapsed Time (hours) - Tp=10.0000=100;Sim P:TP2=54.373199207892;Elapsed Time (hours) - Tp=10.0000=0;Sim P Deriv:TP2=0

Verify by reading the plot title "Radial Flow Plot".



Line ResultsModel 1Radial homogeneousSingle faultSemi-LogdpS = 14.052 psi TP2FE = 0.73784 TP2k = 94.192 md TP2kh = 9419.183 md.ft TP2L1 = 138.009 ft TP2P* = 4999.937 psia TP2Rinv = 1526.389 ft TP2S = 2.5063 TP2Log-LogCs = 0.41746 bbl/psi TP2k = 93.329 md TP2kh = 9332.893 md.ft TP2S = 2.2828 TP2

Confirmation Message box appears which asks user for confirmation to remove all analysis plots. Click Yes


Plot should read "Test Overview Plot"Verify by reading the title of the plot "Test Overview Plot"


Verify by reading the plot title "Radial Flow Plot".

Grid should contain 100 rows and 4 columns .Row 1;Time (Hours)=0.00100000004749745;TEST DESIGN:Test Rate=200;Time (Hours)=0;TEST DESIGN:Rate Schedule=0Row 50;Time (Hours)=100;TEST DESIGN:Test Rate=200;Time (Hours)=0;TEST DESIGN:Rate Schedule=0Row 100;Time (Hours)=200;TEST DESIGN:Test Rate=0;Time (Hours)=0;TEST DESIGN:Rate Schedule=0System should calculate the 100 steps for advanced simulation. Click OK when completeVerify that the 4 Data Files/column list are created under Well 1 in the navigation pane namely Test Rate, Sim P, Sim Q Total, Sim Q#1


Line ResultsModel 1Radial homogeneousSingle faultSemi-LogdpS = 11.385 psi TP2FE = 0.81409 TP2k = 86.455 md TP2kh = 8645.547 md.ft TP2L1 = 196.907 ft TP2P* = 4999.738 psia TP2Rinv = 1462.362 ft TP2S = 1.8639 TP2Log-LogCs = 0.3891 bbl/psi TP2k = 86.064 md TP2kh = 8606.395 md.ft TP2S = 1.817 TP2



S. No Test Name Test Case Number Step Name Step1 Example 18 1

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Test Description (Action)Open PANSystem. Go to File -> New.

Click OK to return to PANSystem main window.

Go to Data Preparation >> Well,Reservoir & Fluid Description -> Analytical Model. Select the Fluid type as 'Oil'.

Click the child tab Well Control. Choose the Principal Well Orientation as Vertical/Slanted.

Click the button Add Well. Give the well name as 'Observer'. Click OK.

Select the well 'P-Well 1: Active' and change the nameto Producer.

Select the 'Producer Well' and click the button 'Well Parameters'. Enter 0.3 ft for Wellbore Radius.

Click the button 'Wellbore Storage Model Parameters'. Enter 0.01 for Wellbore Storage. Click OK twice to return to Well, Reservoir and Fluid Description window.

Select the 'Observer Well' and click the button 'Well Parameters'. Enter the values: Wellbore Radius: 0.3 ft X-Position: 0 Y-Position: 2500

Click the button 'Wellbore Storage Model Parameters' enter 0.01 for Wellbore storage. Click OK twice to return to Well, Reservoir and Fluid Description window.

Click the child tab Layer Control. Click the button Layer Parameters. Enter the following: Formation thickness: 25 ftPorosity: 0.20Layer pressure: 4000 psiaLayer Temperature: 200 F

Click the button 'Model Parameters'. In the child tab Reservoir Model Parameters, enter Radial Permeability = 250, Skin = 5(for Producing well).

Click the child tab 'Offset Well Completions' and enter Skin = 0(For Well 2). Click OK.

Click OK. Click the button 'Layer Fluid Parameters'. Input the values:Bo : 1.3Uo: 2.5 cpCt: 1e-5 (1/psi). Click OK.

Go to Data Preparation -> Test Design -> Edit Test design.

Click OK on the Edit Test design.Click OK on the Test design Dialog.Go to Data Preparation -> Test Design -> Edit Test design.

Click OK. Click Analysis.

Click OK.

Click OK. A Test Overview Plot should appear.Click the button Data Grid on the tool bar.Verify the data on the data view grid and click OK.

Click OK. In the 'Select well' dialog, select Producer. Click OK.

On the 'Edit Test Design' dialog, input the following:Row1: Time = 400, Oil Flow Rate(STB/Day) = 1000, No. of Steps = 200, Format = 2Row2: Time = 1000, Oil Flow Rate(STB/Day) = 0, No. of Steps = 200, Format = 2

Click OK. In the 'Select well' dialog, select 'Observer'. Click OK.

Click NO on the Confirmation dialog. Click OK on the Test Design dialog.

On the 'Edit Test Design' dialog, input the following:Row1: Time = 400, Oil Flow Rate(STB/Day) = 0Row2: Time = 1000, Oil Flow Rate(STB/Day) = 0

Click OK. Go to Simulation >> Analytical Simulation >> AdvancedSimulation

Do not change any of the controls. Click OK to run the Simulation.

Clear the work space and open the file Example18_1_1.panx.

A 'Log Log' Plot should be displayed on opening the file.

Click Analysis -> Tools -> Type Curve Match. Click Ok. Click Analysis -> Tools -> Type Curve Match.

Click Ok. Goto Line Results tab.

Close the PanSystem.

Navigate to Line Results tab and verify the Line Results shown.

Clear the work space and open the file Example18_1_2.panx.

A dialog, 'Select a Well' should be displayed.

A Test design Dialog should be opened.

A dialog, 'Select a Well' should be displayed.

A confirmation dialog should be opened.

A Test design Dialog should be opened.

A 'Calculated Advanced Simulation' dialog should appear.

Verify by reading the plot title: Test Overview Plot.A Data View window should be opened.

Advanced Simulation Control dialog should appear as in the screen shot.

An error message Box should appear to indicate that no points are selected

A Well Selection Dialog Box should appear. Select Producer radio button

Grid should contain 400 rows and 5 columns .Row 1;Time (Hours)=0.00100000004749745;TEST DESIGN:Test Rate=1000;TEST DESIGN:Sim P=3994.6333889282;Time (Hours)=0;TEST DESIGN:Rate Schedule=0Row 200;Time (Hours)=400;TEST DESIGN:Test Rate=1000;TEST DESIGN:Sim P=2946.5868959281;Time (Hours)=0;TEST DESIGN:Rate Schedule=0Row 400;Time (Hours)=1000;TEST DESIGN:Test Rate=0;TEST DESIGN:Sim P=3981.23701022201;Time (Hours)=0;TEST DESIGN:Rate Schedule=0

Verify by reading the plot title: Log Log Plot.

A Select Type Curve Window should be displayed.Nearest Curve window should be displayed.

PanSystem should be closed.

Line ResultsModel 1Radial homogeneousInfinitely actingLog-LogCs = 0.01036 bbl/psi TP2k = 248.941 md TP2kh = 6223.519 md.ft TP2S = 4.7521 TP2

Verify the plot displayed by reading the title: Type Curve Plot

Match ResultsModel 1Radial homogeneousInfinitely actingTypecurve0Ct = 7.9189e-14 psi-1 TP1k = 0.10234 md TP1kh = 2.5585 md.ft TP1

pansystem manual test cases_consolidated 07 jan 2013 (infosys qa)

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