overview of ch 11-13

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Overview of Ch 11-13

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Overview of Ch 11-13. Properties of Solutions Chapter 11. Solution Composition. 1. Molarity ( M ) = 2. Mole fraction (  A ) = 3. Molality ( m ) =. Henry’s Law. The amount of a gas dissolved in a solution is directly proportional to the pressure of the gas above the solution. P = k C - PowerPoint PPT Presentation

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Page 1: Overview of Ch 11-13

Overview of Ch 11-13

Page 2: Overview of Ch 11-13

Properties of Properties of SolutionsSolutions

Chapter 11Chapter 11

Page 3: Overview of Ch 11-13

Solution CompositionSolution Composition

1.Molarity (M) =

2.Mole fraction (A) =

3.Molality (m) =

moles of soluteliters of solution

molestotal moles in solution

A

moles of solutekilograms of solvent

Page 4: Overview of Ch 11-13

Henry’s LawHenry’s Law

P = kCP = partial pressure of gaseous

solute above the solutionC = concentration of dissolved gask = the Henry’s Law constant

The amount of a gas dissolved in a solution is The amount of a gas dissolved in a solution is directly proportional to the pressure of the gas directly proportional to the pressure of the gas above the solution.above the solution.

Page 5: Overview of Ch 11-13

Temperature EffectsTemperature Effects

Solubility of gases generally decreases with temperature.

Solubility of solids generally increases with temperature.

Page 6: Overview of Ch 11-13

Colligative PropertiesColligative Properties

Depend only on the number, not on the identity, of the solute particles in an ideal solution.

Vapor pressure depression Boiling point elevation Freezing point depression Osmotic pressure increase

Page 7: Overview of Ch 11-13

Raoult’s LawRaoult’s Law

Psoln = solvent Psolvent

Psoln = vapor pressure of the solution

solvent = mole fraction of the solvent

Psolvent = vapor pressure of the pure solvent

The presence of a nonvolatile solute The presence of a nonvolatile solute lowerslowers the vapor pressure of a solvent.the vapor pressure of a solvent.

Page 8: Overview of Ch 11-13

Boiling Point ElevationBoiling Point Elevation

A nonvolatile solute elevates the boiling point of the solvent.

T = Kbmsolute

Kb = molal boiling point elevation constant

m = molality of the solute

Page 9: Overview of Ch 11-13

Freezing Point DepressionFreezing Point Depression

A nonvolatile solute depresses the freezing point of the solvent.

T = Kfmsolute

Kf = molal freezing point depression constant

m = molality of the solute

Page 10: Overview of Ch 11-13

Osmotic PressureOsmotic Pressure

Osmosis: The flow of solvent into the solution through a semipermeable membrane.

Osmotic Pressure: A nonvolatile solute increases the osmotic pressure of the solvent.

Page 11: Overview of Ch 11-13

Chemical EquilibriumChemical EquilibriumChapter 13Chapter 13

The state where the concentrations of all reactants and products remain constant with time.

Page 12: Overview of Ch 11-13

Equilibrium ConstantEquilibrium ConstantjA + kB lC + mD

The equilibrium expression:

Kl m

j k C DA B

Page 13: Overview of Ch 11-13

4NH3(g) + 7O2(g) 4NO2(g) + 6H2O(g)

K NO H O

NH O2

2

24 6

34 7

Page 14: Overview of Ch 11-13

Manipulations of KManipulations of K

The equilibrium constant for a reaction is the reciprocal of that for the reaction written in reverse.

When the equation for a reaction is multiplied by n, Knew = (Koriginal)n

Page 15: Overview of Ch 11-13

KK v. v. KKpp

For

jA + kB lC + mDKp = K(RT)n

n = sum of coefficients of gaseous products minus sum of coefficients of gaseous reactants.

Page 16: Overview of Ch 11-13

Heterogeneous EquilibriaHeterogeneous Equilibria

. . . are equilibria that involve more than one phase.

CaCO3(s) CaO(s) + CO2(g)

K = [CO2]The position of a heterogeneous equilibrium does not depend on the amounts of pure solids or liquids present.

Page 17: Overview of Ch 11-13

Reaction QuotientReaction Quotient

. . . helps to determine the direction of the move toward equilibrium.

The law of mass action is applied with initial concentrations.

Page 18: Overview of Ch 11-13

H2(g) + F2(g) 2HF(g)

QHF

H F2 2

02

0 0

•Q < K, shift right

•Q > K, shift left

Page 19: Overview of Ch 11-13

Solving Equilibrium Solving Equilibrium ProblemsProblems

1. Write the equilibrium expression.2. Set up an “ICE” box with

relevant concentrations.3. Use the stoichiometry of the

reaction to determine changes in products and reactants, solving for unknowns.

Page 20: Overview of Ch 11-13

Le Châtelier’s Le Châtelier’s PrinciplePrinciple

. . . if a change is imposed on a system at equilibrium, the position of the equilibrium will shift in a direction that tends to reduce that change.

Page 21: Overview of Ch 11-13

Effects of Changes on the Effects of Changes on the SystemSystem

1. Concentration: The system will shift away from the added component.

2. Temperature: treat the energy change as a reactant (endothermic) or product exothermic).

Page 22: Overview of Ch 11-13

Effects of Changes on the Effects of Changes on the System System (continued)(continued)

3. Pressure: a. Addition of inert gas does

not affect the equilibrium position.

b. Decreasing the volume shifts the equilibrium toward the side with fewer moles.

Page 23: Overview of Ch 11-13

Chemical KineticsChemical KineticsChapter 12Chapter 12

The area of chemistry that concerns reaction rates.

Page 24: Overview of Ch 11-13

Reaction RateReaction Rate

Change in concentration (conc) of a reactant or product per unit time.

Rate = conc of A at time conc of A at time 2 1

2 1

t tt t

At

Reaction rates are positive by convention.

Page 25: Overview of Ch 11-13

(Differential) Rate (Differential) Rate LawsLaws

Rate = k[NO2]n

k = rate constant n = rate order

Page 26: Overview of Ch 11-13

Types of Rate LawsTypes of Rate Laws

Differential Rate Law: expresses how rate depends on concentration.

Integrated Rate Law: expresses how concentration depends on time.

Page 27: Overview of Ch 11-13

Method of Initial RatesMethod of Initial Rates

Initial Rate: the “instantaneous rate” just after the reaction begins.

The initial rate is determined in several experiments using different initial concentrations.

Page 28: Overview of Ch 11-13

Overall Reaction OrderOverall Reaction Order

Sum of the order of each component in the rate law.

rate = k[H2SeO3][H+]2[I]3

The overall reaction order is 1 + 2 + 3 = 6.

Page 29: Overview of Ch 11-13

First-Order Rate LawFirst-Order Rate Law

Integrated first-order rate law is

ln[A] = kt + ln[A]o

Rate = A

A

t

k

For For aaA A Products in a 1st-order reaction, Products in a 1st-order reaction,

Page 30: Overview of Ch 11-13

Half-Life of a 1st-Order RxnHalf-Life of a 1st-Order Rxn

t1/2 = half-life of the reaction k = rate constant

For a first-order reaction, the half-life does not depend on concentration.

tk1/2

0 693.

Page 31: Overview of Ch 11-13

Second-Order Rate LawSecond-Order Rate Law

For aA products in a second-order reaction,

Rate = A

A

t

k 2

1A

+ 1

A o

kt

Integrated rate law is:

Page 32: Overview of Ch 11-13

Half-Life of a 2nd-Order RxnHalf-Life of a 2nd-Order Rxn

t1/2 = half-life of the reactionk = rate constantAo = initial concentration of A

The half-life is dependent upon the initial concentration.

tk1/2

oA

1

Page 33: Overview of Ch 11-13

Zero-Order Rate LawZero-Order Rate Law

For aA products in a zero-order reaction,

Rate= k

[A] = -kt + [A]o

Integrated rate law is

Page 34: Overview of Ch 11-13

Half-Life of a Zero-Order RxnHalf-Life of a Zero-Order Rxn

t1/2 = half-life of the reactionk = rate constant[A]o = initial concentration of A

The half-life is dependent upon the initial concentration.

t1/2 = [A]o

2k

Page 35: Overview of Ch 11-13

Reaction MechanismReaction Mechanism

The series of steps by which a reaction occurs.

A chemical equation does not tell us how reactants become products - it is a summary of the overall process.

Page 36: Overview of Ch 11-13

Reaction Mechanism Reaction Mechanism (continued)(continued)

The reaction

has many steps in the reaction mechanism.

6CO 6H O C H O O2 2light

6 12 6 2 6

Page 37: Overview of Ch 11-13

Intermediate: formed in one step and used up in a subsequent step and so is never seen as a product.

Molecularity: the number of species that must collide to produce the reaction indicated by that step.

Elementary Step: A reaction for which a rate law can be written from its molecularity.

uni, bi and termolecular

Page 38: Overview of Ch 11-13

Rate-Determining Rate-Determining StepStep

In a multistep reaction, it is the slowest step. It therefore determines the rate of reaction.

Page 39: Overview of Ch 11-13

Arrhenius EquationArrhenius Equation

Collisions must have enough energy to produce the reaction (must equal or exceed the activation energy).

Orientation of reactants must allow formation of new bonds.

Page 40: Overview of Ch 11-13

k = rate constant A = frequency factor Ea = activation energy T = temperature (in K) R = gas constant

k Ae E RT a /

Page 41: Overview of Ch 11-13

lnk= -Elnk= -Eaa 1 + 1 + ln Aln A R T R T

slope = -Ea /R

•catalysts decrease Ea.