objectives solve exponential and logarithmic equations and equalities. solve problems involving...
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Exponential and Logarithmic Equations
Objectives
Solve exponential and logarithmic equations and equalities.
Solve problems involving exponential and logarithmic equations.
An exponential equation is an equation containing one or more expressions that have a variable as an exponent. To solve exponential equations:
Try writing them so that the bases are the same
Take the logarithm of both sides
Solving Exponential Equations by Expressing Each Side as a Power of the Same Base
1. Rewrite the equation in the form 2. Set 3. Solve for the variable.
Express each side as a power of the same base.
Set the exponents equal to each other.
Solve and check.
98 β x = 27x β 3
(32)8 β x = (33)x β 3 Rewrite each side with the same base; 9 and 27 are powers of 3.
316 β 2x = 33x β 9 To raise a power to a power, multiply exponents.
Solving Exponential Equations
16 β 2x = 3x β 9Bases are the same, so the exponents must be equal.
x = 5 Solve for x.
Solve and check:
Rewrite each side with the same base.2
3 π₯β 8=24
Now that the bases are the same, solve for
3 π₯β8=4π₯=4
Solve and check:
Rewrite each side with the same base. 53π₯β6=53
Now that the bases are the same, solve for 3 π₯β6=3
π₯=3
Solve and check.
4x β 1 = 5log 4x β 1 = log 5 We cannot get common bases,
so take the log of both sides.(x β 1)log 4 = log 5 Apply the Power Property of
Logarithms.
Solving Exponential Equations
Divide both sides by log 4.
Check Use a calculator.
The solution is x β 2.161.
x = 1 + β 2.161log5log4
x β1 = log5log4
Using Logarithms to Solve Exponential Equations
1. Isolate the exponential expression.2. Take the natural logarithm on both sides of the
equation for bases other than 10. Take the common logarithm on both sides of the equation for base 10.
3. Simplify using one of the following properties:
or or
4. Solve for the equation.
Solve:
ln 4π₯= ln 15 Take the natural logarithm on both sides
π₯ ln 4=ln15 Use the power rule
= Solve for x by dividing both sides by
πβπ .ππππ Use calculator.
Check.41.9534 β14.999β15
When you take the natural logarithm of base e, the ln e drops from the equation leaving only the exponent as seen above. This is using the inverse property Also,
Solve:
Take the natural logarithm of both sides.lnππ₯=ln 72
π₯ lnπ=ln 72
π₯=ln 72
π₯β 4.277
Check your answer.
Solve:
40π0.6π₯=240 Add 3 to both sides
π0.6 π₯=6 Divide both sides by 40
lnπ0.6 π₯=ln 6 Take the natural logarithm of both sides
0.6 π₯=ln 6 Use the inverse property
2.99 Divide both sides by 0.6 and solve for x
Solve
ln 5π₯β2=ln 42π₯+3 Take the natural logarithm on both sides
(π₯β2 ) ln5=(2 π₯+3) ln 4 Use the power rule
π₯ ln5β2 ln 5=2π₯ ln 4+3 ln 4 Use the distributive property
π₯ ln5β2π₯ ln 4=2 ln5+3 ln 4 Rearrange terms
Factor out x
π₯=ΒΏ2 ln 5+3 ln 4ln 5β2 ln 4
The solution is approximately
Solve: Let
(π’β3 ) (π’β1 )=0 Factor on the left
π’β3=0πππ’β1=0 Set each factor equal to 0
π’=3π’=1 Solve for
Take the natural logarithmof both sides
π’2β4π’+3=0 Substitute for
Replace for
Using the Definition of a Logarithmto Solve Logarithmic Equations
1. Express the equation in the form 2. Use the definition of a logarithm to rewrite the
equation in exponential form.
means
3. Solve for the variable.4. Check your solutions for in the original equation.
Solve and check:
ln (2 π₯ )=4 Divide both sides by 3
logπ (2 π₯ )=4 Rewrite the natural logarithm showing base e
π4=2 π₯ Rewrite in exponential form
ππ
π=πβππ .π Divide both sides by 2
Solve and check:
log 2[π₯ (π₯β7 )]=3 Use the product rule
23=π₯(π₯β7) Rewrite in exponential form
8=π₯2β7π₯ Simplify
π₯2β7 π₯β8=0 Set up as a quadratic equation
(π₯β8 ) (π₯+1 )=0 Factor
Always check your answers with original equation.
Using the One-to-One Property of Logarithms to Solve Logarithmic Equations
1) Express the equation in the form The coefficient must be equal to 1 on both sides.
2) Use the one-to-one property to rewrite the equation without the logarithm.
If , then .
3) Solve for the variable.4) Check proposed solutions in the original equation.
must be positive.
Solve:
ln() Use the quotient rule
π₯+24 π₯+3
=1π₯
Use the one-to-one property
π₯ (π₯+2 )=1(4 π₯+3) Cross multiply
π₯2+2π₯=4 π₯+3 Use distributive property
π₯2+2π₯β4 π₯β3=0
π₯2β2 π₯β3=0Set up as a quadratic equation
π₯2β2 π₯β3=0
(π₯β3)(π₯+1) Factor
π=π π=βπ
Set each factor equal to 0
Check by substituting each solution into the original equation.
π₯π§ (π+π )βπ₯π§ (π π+π )=π₯π§ (ππ
)