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Multiple Sample Models James G. Anderson, Ph.D. Purdue University

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Multiple Sample Models. James G. Anderson, Ph.D. Purdue University. Rationale of Multiple Sample SEMs. Do estimates of model parameters vary across groups? Another way of asking this question is: Does group membership moderate the relationships specified in the model?. - PowerPoint PPT Presentation

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Page 1: Multiple Sample Models

Multiple Sample Models

James G. Anderson, Ph.D.Purdue University

Page 2: Multiple Sample Models

Rationale of Multiple Sample SEMs

• Do estimates of model parameters vary across groups?

• Another way of asking this question is: Does group membership moderate the relationships specified in the model?

Page 3: Multiple Sample Models

Uses of Multiple Sample SEMs• Use for analysis of cross-sectional,

longitudinal, experimental and quasi-experimental data and to test for measurement variance.

• This procedure allows the investigator to:1) Estimate separately the parameters for multiple

samples2) Test whether specified parameters are equivalent

across these groups. 3) Test whether there are group mean differences for

the indicator variables and/or for the structural equations

Page 4: Multiple Sample Models

Analytical Procedure

• Estimate the parameters of the model with no constraints (i.e., allow the parameters to differ among groups)

• Compute chi-square as a measure of fit.• Re-estimate the parameters of the model

after imposing cross-group equality constraints on parameters

Page 5: Multiple Sample Models

Analytical Procedure (2)

• Determine the chi square difference is significant

• If the relative fit of the constrained model is significantly worse than that of the unconstrained model, then individual path coefficients should be compared across samples.

Page 6: Multiple Sample Models

Structural Model Example

Lyman, DR., Moff, HT, Stouthamer-Loeber,M. (1993). “Explaining the Relation Between IQ and Delinquency: Class, Race, Test Motivation or Self-Control.” Journal of Abnormal Psychology, 102, 187-196.

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Structural Model Example:Data

• Covariance matrices for White (n=214) and African American (n=181) male adolescents

• Total observations: n=395• Degrees of Freedom: 2 * 5(6) = 30

2• 7 parameters constrained to be equal• Variances and covariances allowed to vary

between groups.

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Fit Statistics for the Multiple Sample Model

• Χ2 = 11.68 df = 7 NS• Χ2/df =1.67• NFI = 0.96• NNFI = 0.95

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Modification Indices for Equality-Constrained Parameters

• MI values estimate the amount by which the overall chi square value would decrease if the associated parameters were estimated separately in each group.

• Statistical significance of a modification index indicates a group difference on that parameter

• For example, there is a statistically significant difference on the Achievement to Delinquency path and the Social Class to Achievement path.

Page 13: Multiple Sample Models

Additional Analysis

• Path coefficients were estimated separately for each sample

• Standardized values can only be used for comparisons within a group.

• Unstandardized values are used for comparisons between or across groups.

Page 14: Multiple Sample Models

Results• In both samples, Verbal Ability has a significant

effect on Achievement.• Verbal Ability is the only significant predictor of

Delinquency in the White sample.• Achievement is the only significant predictor of

Delinquency in the African-American sample.• Conclusion: Among male adolescents, school

has a larger role in preventing the development of delinquency for African-Americans that for Whites

Page 15: Multiple Sample Models

Use of Multiple Sample CFAs

• Test for measurement invariance, whether a set of indicators assesses the same latent variables in different groups.

• Examine a test for construct bias, whether a test measures something different in one group than in another.

Page 16: Multiple Sample Models

Analytical Procedure

• Estimate the parameters of the model with no constraints (i.e., allow the factor loadings and error variances to differ among groups).

• Compute chi square as a measure of fit.• Re-estimate the parameters of the model

after imposing cross-group equality constraints parameters

Page 17: Multiple Sample Models

Analytical Procedure (2)

• Determine if the chi square difference is significant

• If the relative fit of the constrained model is significantly worse than that of the unconstrained model, then individual factor loadings should be compared across samples to determine the extent of partial measurement invariance..

Page 18: Multiple Sample Models

Confirmatory Factor Analysis: Example

Werts, CE, Rock, DA, Linn, RL and Joreskog, KG. (1976). “A Comparison of Correlations, Variances, Covariances and Regression Weights With or Without Measurement Errors.” Psychology Bulletin, 83, 52-56.

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Page 21: Multiple Sample Models

Confirmatory Factor Analysis:Data

• Covariance matrices are for two samples (n1=865 and n2=900) of candidates who took the SAT in January 1971.

• Total observations: n=1765• Degrees of Freedom: 2 * 4(5) = 20 2

Page 22: Multiple Sample Models

Confirmatory Factor Analysis:Results

• The factor loadings are the same for the two groups.

• The error variances differ between the two groups.

Page 23: Multiple Sample Models

Model A

• Parameters for the two groups– Factor Loadings Equal– Factor Correlations Equal– Error Variances EqualModel Fit

Chi Square = 34.89df= 11p < 0.00011

Page 24: Multiple Sample Models

Model B

• Parameters for the two groups– Factor Loadings Unequal– Factor Correlations Equal– Error Variances EqualModel Fit

Chi Square = 29.67df= 7p < 0.00011

Page 25: Multiple Sample Models

Model C

• Parameters for the two groups– Factor Loadings Unequal– Factor Correlations Equal– Error Variances UnequalModel Fit

Chi Square = 4.03df= 11p < 0.26

Chi Square difference = 29-67-4.03 =25.03df difference = 7-3=4

Page 26: Multiple Sample Models

Model D

• Parameters for the two groups– Factor Loadings Equal– Factor Correlations Equal– Error Variances UnequalModel Fit

Chi Square = 10.87df= 7p < 0.14

Chi Square difference = 34.89-10.87 =24.01df difference = 11-7=4

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