mpi prsolutions.in

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1. The number of address spaces of 8085 i s .

( a) 4(b)8(c)2(d)12 . One of these is an index register( a) BP( b ) SI( c ) DX( d ) IP3 . Which of these is an 8 bit register ?( a) DX( b ) CX( c ) BX

( d ) AH4 . The flag which indicates whether the number of 1s are odd or even in the lower 8 bits is .( a) C Y(b)Z(c)P(d)SF5 . Which of these bits is used specially in packed BCD arithmetic?( a) D F( b ) CY( c ) AC( d ) OF6 . If EA is used to represent Effective address then what addressing mode does EA = [ 200 0]

re p re s ent( a) Register Direct( b ) Register Indirect( c ) Indirect Addressing( d ) Immediate addressing7 . Which of these combinations is used by STOSB i nstruction( a) ES:DI( b ) DX:AX( c ) SS:BP( d ) DS:SI8 . The first operation done by PUSH instruction is( a) Upper Byte of data to stack & SP=SP+1( b ) Lower Byte of data to stack &SP=SP-1( c ) Lower Byte of data to stack & SP=SP+1( d ) Upper Byte of data to stack & SP=SP-19 . The following program will loop how many times MOV AX , 2 MOV DX ,0FF AGAIN:MOV CX,0FF f DEC DX LOOP AGAIN( a) 10( b ) 255

( c ) IN FINITE( d ) 65535

1 0. Which of these is external to the program code .( a) Procedure( b ) Macro( c ) Library function( d ) Sub Routine1 1. When aCMP instruction executes and the source and destination operand are not equalwhat will becondition of Z and carry flag when source is greater than destination( a) Z=1,CY= 0( b ) Z=0,CY=1( c ) Z=0,CY=0( d ) Z=1,CY=11 2. Which of these calls uses only registers( a) CALL F( b ) CALL BX( c ) CALL( d ) CALL TABLE [BX]1 3. Given the program shown below, What is the expression evaluated by this program?Pd b5 Qd b 6 Rd b7 Sd b6 MOV AL ,[P] MOV BL, [Q] ADD AL, BL MUL AL ADD AL , RMOVCL, S DIV CL( a) (P+Q2+R)/ s( b ) ((P+Q)2+R/S( c ) (P+(Q+R)2)/S( d ) ((P+Q)2+R)/S1 4. Which of these instructions writes a byte to memory( a) MOVSB( b ) LOD SB

( c ) SCA SB( d ) STO SB1 5. In the following program what is the final value of the SI register MOV AX ,1000 MOV ES , ,AXMOV DS, 3000 MOV SI, 0 MOV DI, 0 CLD MOV CX, FF AG:MOV SW LOOP AG(a) 01FE( b ) 01FF( c ) 01FFF( d ) 00FF1 6. Which of these is used for indicating that data is being written or read from the data bus( a) DT/R( b ) ALE( c ) HOLD( d ) MN/MX

1 7. Which of these signals are bidirectional( a) HOLD,HLDA( b ) S1,s2( c ) RQ,GT( d ) S0,S11 8. Which of these ICs is a 3 to 8 decoder used for decoding memory addresses( a) 74LS245/8286


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( b ) 8284A

( c ) 74LS138( d ) 74LS3732 0. W h e n an I O re qu e s t s f o r D M A th e s e q u e n c e o f s i gn a l s i s( a) H O LD , DR E Q , DAC K , H L DA( b ) D RE Q, H OL D , DAC K , H L DA( c ) D RE Q, H OL D , H L DA , DAC K( d ) H O LD , H LDA , D R E Q , DAC K21 . The width of the SP register is - .( a) 32bits( b ) 8 bi ts( c ) 2 4b i t s( d ) 16 bits22 . One of these is not the segment offset form of the absolute address 00417

( a) 0040:0017( b ) 0 00 0: 0 41 7( c ) 0 04 1: 0 00 7( d ) 0417:000023 .One of the following is a wrong register pair( a) CH,DH(b)DH,DL(c)BH,BL(d)AH,AL24 . Which of these flags indicates a carry from a nibble?( a) CY(b)Z(c)O( d ) AC

25 .The flags used for controlling interrupts is .( a) T F( b ) AC(c)DF( d ) IF26 . Which of these combinations is not allowed in computing address( a) B P +S I( b ) B P +D I( c ) BP+BX(d)BX+SI

27 . AN 8086 instruction is of which of these forms( a) O p c o d e , S o u r c e , D e s ti n a t i on

( b ) Op code,Destination,Source( c ) S o u rc e , d e s t i n a t i on , Op c o d e( d ) D e s t i n a ti o n , s ou r c e , op c o d e

28 . Which of these instructions is invalid( a) M OV B H , C H( b ) M OV C H , C L( c ) MOV CX, BL( d ) M OV B X , C X

29 . is the directive which indicates a reference point in memory and is usually used by JUMP


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Instructions( a) STA RT

( b ) LABEL( c ) O RG(d)LENGTH30. Which of these uses the stack for its operation( a) M a c r o( b ) L i b r ar y f u n c t i o n( c ) S u b R o u ti n e( d ) Procedure31. Which registers will contain the product of a 16 bit multiplication instruction( a) B X , DX(b)CH,CL(c)AH,AL( d ) AX,DX32. Which of these calls uses only registers( a) C A L L TA B L E [ B X ](b)CALLF( c ) CALL BX(d)CALL33. Which combination of the flags indicate that the destination is greater than the source( a) C Y = 1, Z = 1( b ) C Y = 0, Z = 1( c ) CY=0,Z=0( d ) C Y = 1, Z =034. The LOD SW opcode uses which of the following register combinations( a) DS:SI(b)DS:DI(c)ES:DI

(d)ES:SI35. In the following program what is the final value of the SI register MOV AX, 1000 MOV ES, ,AXMOV DS, 3000 MOV SI, 0 MOV DI , 0 CLD MOV CX , FF AG:MOV SW L OO P AG( a) 0( b ) 0 1F F F( c ) 0 0F F( d ) 0 1F E36. Which of these is an acknowledgement for DMA request( a) I N T R A( b ) HLDA(c)M/IO(d)DEN37. The 8086 takes over the bus when it receives one of these signals

( a) GT 1,GT 0( b ) RQ 0( c ) RQ 0 , RQ 1(d)GT038. This signal is used to store data at memory or IO( a) WR(b)DT/R


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(c)ALE( d ) R E DY39. In a 8086 system which uses one bank of 16 KX8 memory connected respectively to D0-D7.Thefollowing address lines would be connected to them( a) A 1 t o A 14( b ) A 1 t o A 15( c ) A0 to A13( d ) A 0 t o A 14

40. The register whose contents are copied during auto-initialisation is holds the 16 bit addressbeing usedfor DMA is( a) C o m m an d Re g i s t e r( b ) C u r r e nt wor d c ou nt r e g i s t e r( c ) Base Word Count registers( d ) C u r r e nt A d d r e s s Re gi s t e r1)d 2)d 3)a 4)d 5)d 6)c 7)b 8)c 9)b 10)d11)d 12)c 13)c 14)a 15)a 16)b 17)a 18)a 19)c 20)c41 . One of the following is wrong combination of registers .( a) E S : D I( b ) DI:SI(c)DS:SI

(d)CS:IP42 . The flag which indicates whether the number of 1s are odd or even in the lower 8 bits is .( a) P(b)CY(c)SF(d)Z43. Direction flag is used with which of these following instructions ?( a) String( b ) D at a t r an s f e r( c ) L og i c a l i n s t r u c t i on s( d ) Tra n s f e r c ont r ol44. If EA is used to represent Effective address then what addressing mode does EA=R

represent( a) Register Direct( b ) I n d i r e c t A d d re s s i n g( c ) R e gi s te r I n d i r e c t(d)Immediateaddressing45. Which of these is not used by MOV SB instruction( a) E S : D I(b)DF(c)DS:SI(d)SS:BP46 . POP instruction utilizes one of the following combinations( a) C S : I P(b)DS:SI(c)SS:BP(d)SS:SP


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47. In the following program what is the value of CX after the loop is exitedM OV A X , 2 M OV DX , 0 F F F h M OV C X ,

1 0 AG A I N : D E C DX L OO P AG A I N( a) 0 F F(b)1(c)0(d)0FEF48. Which of parameters can be passed like in ac function call( a) S u b R o u ti n e( b ) L i b r ar y f u n c t i o n(c)Procedure( d ) Macro49. When a CMP instruction executes and the source and destination operand are not equalwhat will becondition of Z and baji flag and abhi ram flag source is greater than destination( a) Z = 1 , C Y = 1(b)Z=1,CY=0(c)Z=0,CY=0(d)Z=0,CY=150. Which of these calls uses only registers( a) C A L L F(b)CALL( c ) CALL BX( d ) C A L L TA B L E [ B X ]51. Given the program shown below, What is the expression evaluated by this program? Pd b5Qd b6Rd b7 Sd b6 MOV AL, [P] MOV BL, [Q] ADD AL, BL MUL AL ADD AL, R MOV CL, S DIV CL( a) ( P + (Q + R) 2 ) /S( b ) ( ( P + Q ) 2 + R) / S

( c ) ( P+Q 2 +R)/s( d ) ( ( P +Q ) 2 + R /S52. Which of these instructions uses both ES & DS segment registers( a) S T O S B( b ) MOV SB( c ) L OD S B(d)SCASB53. Which of these is a Prefix( a) REP(b)ESC(c)RET( d ) L OO P54. Which of these is used for identifying when the address is output( a) H O LD

( b ) ALE(c)MN/MX(d)DT/R55. Which of these signals are bidirectional( a) S 0 , S 1(b)S1,s2( c ) RQ , GT( d ) H O LD , H L DA


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56. Which of these signals combination indicates a Lower 8 bit data transfer( a) A 0 =0 & B H E =0

( b ) A 0 =1 & B H E =0( c ) A0=0 & BHE=1( d ) A 0 =1 & B H E =157. The DMA operations are typically perform edusing which one of these signals( a) HOLD(b)TEST( c ) H L DA(d)BHE58 . The 8085 is a _________ bit microprocessor( a) 4 bit(b)8bit( c ) 3 2b i t(d)16bit59. The depth of the instruction pipeline is .( a) 6 Bytes(b)6Bits(c)8Bytes(d)8Bits60 . Which of these register is called the Count Register( a) AX(b)CX(c)BX( d ) DX61. The size of the 8086 flag register is .( a) 3 2 b i ts( b ) 1 6b i t s(c)8bits

( d ) 6 4 bits62. When the result of an operaration is zero, then - .( a) S = 1(b)Z=0(c)Z=1(d)S=063 . If the effective address exceeds 65536 then the addressing mode is( a) E x t r a S e gm e nt A d d r e s s i n g( b ) I nt r a s e g m e nt baji and abhi ad d r e s s i n g( c ) C o ntr a S e g m e nt A d d r e s s i n g( d ) Inter Segment addressing64 . Which of these instructions is an Arithmetic Instruction( a) C L I( b ) L OD S W

(c)CWD( d ) LOOP65 . POP instruction utilizes one of the following combinations( a) SS:SP(b)DS:SI(c)CS:IP(d)SS:BP


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66. which one of these directives is used for declaring arrays in assembly Language( a) A S S U M E

(b)DUP(c)LEA( d ) SEGMENT67. A block of code which replaces a predefined label is called( a) Procedure(b)Macro( c ) S u b R o u ti n e( d ) L i b r ar y f u n c t i o n68. The CL register contains 4 and the RCRAL, CL instruction is executed then which one of thefollowing will take place( a) A L i s r ot a te l e f t 4 t i m e s( b ) A L i s r ot a te r i ght 5 t i m e s( c ) AL is rotate left 5 times( d ) A L i s r ot a te r i ght 4 t i m e s69. The CALL F pushes( a) CS & IP(b)OnlyCS(c)OnlySP(d)OnlyIP70. Given the program shown below, What is the expression evaluated by this program?Pd b5 Qd b6 Rd b7 MOV AL , [P] MUL AL MOV BL, AL MOV AL, [Q] MUL AL ADD AL, BLMOV[R] , AL( a) R =P + Q 2( b ) R=(P+Q)2( c ) R =( P 2 + Q 2 )( d ) R =( P + Q)71. The SCA SW opcode uses which of the following register combinations

( a) D S : D I(b)DS:SI( c ) ES:DI(d)ES:SI72. In the following program what is the final value of the DI registerMOV AX, 1000 MOV ES, , AX MOV DS, 3000 MOV SI, 0 MOV DI, 0 CLD MOV CX, FF AG:MOV SW LOOP AG( a) 0( b ) 0 1F E( c ) 0 0F F( d ) 01FFF73. Which of these signals indicates that an Interrupt Request is being acknowledge( a) I N T R A( b ) HLDA

(c)M/IO(d)DEN74. Which of these are the coprocessors used in maximum mode by 8086( a) 8 05 1( b ) 8 08 7( c ) 8 08 8( d ) 8085


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75. The IC which provides Clock, Ready & Reset signals to the 8086 is( a) 8 28 4A

( b ) 7 4L S 1 38( c ) 7 4L S 2 45 /8 2 86( d ) 74LS37376. Which of these signals combination indicates a upper 8 bit data transfer( a) A 0 =1 & B H E =0( b ) A 0 =1 & B H E =1( c ) A0=0 &BHE=0( d ) A 0 =0 & B H E =177. DMA is some times called as( a) C y c l e S t e al i n g(b)InstructionCycle( c ) Fetch Cycle( d ) M a ch i n e C yc l e78 . T h e 80 85 i s a b i t m i c r o p ro c e s s o r( a) 1 6 b i t(b)8bit(c)4bit( d ) 3 2b i t79 . O n e o f t h e s e i s an i n d e x r e g i s t e r( a) B P( b ) DX(c)SI(d)IP80. O n e o f t h e f ol l ow i n g i s a w ro n g r e g i s t e r p a i r( a) B H , B L(b)DH,DL(c)CH,DH

(d)AH,AL81. S t r i n g op e r a t i on s au t o i n c r e m e nt o r d e c re me nt i s i n d i c a t e d by .(a) T F(b)DF(c)IF( d ) AC82 . W h i ch o f th e f o l l ow i n g i s m as ka b l e ?( a) N M I(b)RESET( c ) I nt e r r u p t r e qu e s t( d ) H O LD83. B a s e I n d e x e d ad d r e s s i n g h a s th e E A( a) DX +B X

(b)SI+BX(c)SI+DI(d)BX+BP84. W h i ch o f th e s e i s n ot u s e d by M OV S B i n s t r u c t i on( a) D S : S I(b)ES:DI(c)SS:BP


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(d)DF85. T h e i n s t r u c t io n w h i ch i s u s e d t o t r an s f e r p r og r am i n s t r uc ti o n s to & f

ro m a c o- p r o c e s s or i s( a) T E S T( b ) L OC K(c)NOP(d)ESC86 . W h i ch o f th e s e D i r e c t i ve s w i l l fi x t h e a d d r e s s of m e m o r y l o c at i o n f romwhe r e th e a s s e mb l i n g s h o u l d s t a rt( a) S TA RT( b ) O RG(c)LABEL(d)LENGTH87. A b l o ck o f c o de w h i ch re p l ac e s a p r e d e fi n e d l ab e l i s c al l e d( a) M a c r o(b)Procedure( c ) S u b R o u ti n e( d ) L i b r ar y f u n c t i o n88. W h i ch r e g i s t e r s w i l l c o nta i n t h e d i v id e n d o f a 1 6 b i t d i v i s i on i n s t r uc t i on (a) C H , C L( b ) A X , DX( c ) B X , DX(d)AH,AL89. T h e C A L L Fa r i s( a) 1 6 b i t c a ll b e yon d t h e c u r r e nt s e g m e nt( b ) 2 0 b i t c a ll i n t h e s am e s e g m e nt

( c ) 2 0 b i t c a ll b e yon d t h e c u r r e nt s e g m e nt( d ) 1 6 b i t c a l l i n t h e s am e s e g m e nt90. W h i ch o n e of th e s e i n s tr u c t i o n s c ou l d b e u s e d f o r s wa p p i n g i n a s o r tp r og r am( a) XC H G A X , DX( b ) M OV A X , B X( c ) S U B A X


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(b)ALE(c)MN/MX

(d)DT/R94. H ow m a ny c o p ro c e s s o rs c a n 8 08 6 h an d l e i n m a x i mu m m o d e( a) 3(b)0(c)2(d)195. D at a i s t ra n s m i t t e d a n d r e c e i ve d by th i s I C an d i t i s al s o c a l l e d th e B us Tra n s ce i ve r( a) 7 4L S 2 45 /8 2 86( b ) 7 4L S 3 73( c ) 8 28 4A( d ) 7 4L S 1 3896. W h a t wo u l d b e t h e b r oa d m e m o ry l o c a ti o n of th e RO M f r om w h i ch t h e CPUread s i n s t r u c t i on s i m m e d i at e l y a f t e r R E S E T s i gn a l i s gi ve n( a) 4 00 00 t o 7 F F F F( b ) 8 00 00 t o 7 9F F F( c ) 0 00 00 t o F F F F( d ) F 0 00 0 t o F F F F F97. T h e re gi s t e r w h i ch h o l d s t h e nu mb e r of byt e s t r an s f e r re d i s( a) C u r r e nt A d d r e s s Re gi s t e r( b ) B a s e A d d r e s s an d B a s e Wor d C ou nt r e g i s t e r s( c ) C o m m an d Re g i s t e r( d ) C u r r e nt wor d c ou nt r e g i s t e r98 . T h e ad d r e s s b u s of 80 8 5 h as .( a) 1 6 b i t

( b ) 3 2b i t(c)4bit(d)8bit99 . T h e nu mb e r of u n i t s i n 80 86 i s - .( a) 1(b)2(c)4(d)6100. T h e w i d t h o f t h e s e g m e nt re gi s t e r i s .( a) 1 6b i t s(b)8bits( c ) 3 2b i t s( d ) 2 0b i t s101 . I n th e fl a g re g i s t e r , h ow m a ny s t a tu s fl ag s ar e th e re ?

( a) 4(b)3(c)5(d)6102 . W h i ch o f th e f o l l ow i n g fl a gs i s s e t w h e n an i nte rn a l i nt e r r u p t i s c au s ed?( a) O F


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(b)DF(c)IF

(d)TF103 . T h e ty p e of a d d re s s i n g w h e n E A = B P + d i s p l a c e m e nt i s c a l l e d( a) R e gi s te r w i t h d i s p l a c e m e nt( b ) B a s e w i t h d i s p l a c e m e nt( c ) I n d i r e c t ad d r e s s i n g( d ) I n d e x e d (baji)w i t h d i s p l a c e m e nt104 . W h i ch o f th e s e i n s tr u c t i o n s i s a Tr a n s f e r C ont r ol I n s t r u c t i on( a) C L I(b)CWD( c ) L OD S W( d ) L OO P105 . T h e fi r s t o p e r at i o n d o n e by P U S H i n s t r uc ti o n i s( a) L owe r B y t e o f d a t a to s ta ck & S P = S P - 1( b ) U p p e r B y t e o f d a t a to s ta ck & S P = S P - 1( c ) U p p e r B y t e o f d a t a to s ta ck & S P = S P + 1( d ) L owe r B y t e o f d a t a to s ta ck & S P = S P + 1106. W h i ch o n e of th e s e d i r e c ti ve s s h o rt e n s t h e i n s t r u c t i o n M OV DX , O FFSETmemloc( a) A S S U M E(b)DUP(c)SEGMENT(d)LEA1 07. W h i ch o f th e s e i s e x t e r n al to t h e p ro g ra m c o d e .( a) L i b r ar y f u n c t i o n(b)Macro(c)Procedure

( d ) S u b R o u ti n e1 08. W h i ch o f th e s e i n s tr u c t i o n s c o nve rt s t h e b i n a ry c ont e nt s o f r e g i s t er A L i nto u n p a cke d B C D re s u l t i n A H & A L( a) A A M(b)AAD(c)AAS(d)AAA109. W h i ch o f th e s e i s a n i n d i r e c t c a l l( a) C A L L TA B L E [ B X ](b)CALLF(c)CALLBX(d)CALL110. G i ve n t h e p r og r am s h ow n b e l ow , W h a t i s t h e va l u e o r R a f t e r t h i s p r o

gr a m ex e c u t e s ? P d b 5 Q d b 6 R d b 7 M OV A L , [ P ] M U L A L M OV B L , A L M OV A L ,[ Q ] A D D A L , B L M OV [ R ] , A L( a) R =( P + Q)( b ) R =( P + Q) 2( c ) R =( P 2 + Q 2 )( d ) R =P + Q 2


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111. T h e S C A S W o p c o d e u s e s w h i ch o f t h e f ol l ow i n g r e g i s t e r c o mb i n a ti on s

( a) E S : S I(b)ES:DI(c)DS:DI(d)DS:SI112. I n th e f o l l ow i n g p r o gr a m w h a t i s t h e fi n al va l u e o f t h e D I r e g i s t e r MOV A X, 1 00 0 M OV E S , , A X M OV D S , 3 00 0 M OV S I , 0 M OV D I , 0 C L D M OV C X , F FAG : M OV S W L OO P AG( a) 0 1F F F( b ) 0 0F F( c ) 0 1F E(d)0113. W h i ch o f th e s e i s a n ack n ow l e d g e m e nt f o r D M A r e q u e s t( a) H L DA(b)DEN(c)INTRA(d)M/IO114. W h i ch o f th e s e i n s tr u c t i o n s i n i t i a te s RQ0 , G T 0 o r RQ 1 or G T 1( a) C L S(b)STI(c)ESC( d ) L OC K115. W h i ch o f th e s e s i gn a l s i s u s e d to f or i nt r o d uc i n g wai t c yc l e s( a) A L E( b ) R E A DY(c)WR(d)DT/R

116. W h i ch o f th e s e i n d i c a t e s ac c e s s to a n o d d m e m or y l o c a ti o n( a) A 0 =0 & B H E =0( b ) A 0 =1 & B H E =0( c ) A 0 =0 & B H E =1( d ) A 0 =1 & B H E =1117. T h e r e gi s te r w h i ch h o l d s t h e 16 b i t a d d r e s s b e i n g u s e d f o r D M A i s( a) C u r r e nt A d d r e s s Re gi s t e r( b ) C o m m an d Re g i s t e r( c ) C u r r e nt wor d c ou nt r e g i s t e r( d ) B a s e A d d r e s s an d B a s e Wor d C ou nt r e g i s t e r s118 . T h e ad d r e s s b u s of 80 8 5 h as .( a) 3 2b i t(b)16bit(c)4bit

(d)8bit119 . O n e o f t h e s e i s an i n d e x r e g i s t e r( a) DX(b)IP(c)SI(d)BP120 . O n e o f t h e f ol l ow i n g i s w r on g c o mb i n at i o n of r e g i s t e r s .


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( a) C S : I P(b)DS:SI

(c)ES:DI(d)DI:SI121 . T h e fl ag w h i ch i n d i c a te s w h e t h e r th e nu mb e r o f 1 s a r e o d d o r e ve n i nt h e l ower8bitsis.( a) S F(b)P(c)CY(d)Z122 . W h i ch o f th e s e b i t s i s u s e d s p e c i al l y i n p a cke d B C D a r i t h m e t i c ?( a) D F(b)CY( c ) AC(d)OF123 . I f E A i s u s e d t o re p re s e nt E ff e c ti ve ad d r e s s t h e n w ha t a d d r e s s i n gm o d e doe s E A = R r e p r e s e nt( a) I m m e d i a t e a d d r e s s i n g( b ) R e gi s te r D i re c t( c ) I n d i r e c t A d d re s s i n g( d ) R e gi s te r I n d i r e c t124 . W h i ch o f th e s e i s n ot u s e d by M OV S B i n s t r u c t i on( a) E S : D I(b)DF(c)SS:BP(d)DS:SI125 . M OV C X , [ B X +D I ] l oa d s C X r e g i s t e r w i t h d a t a of w i d t h

( a) 4 b i t s( b ) 1 6 b i ts( c ) 3 2 b i ts(d)8bits126 . I n th e f o l l ow i n g p r o gr a m w h a t i s t h e va l u e o f DX af t e r t h e l o op i s e x i tedMOV A X , 2 M OV DX , 0 F F F h M OV C X , 1 0 AG A I N : D E C DX L OO P AG A I N( a) 1(b)0(c)0FEF(d)0FF127. W h i ch o f p ar am e te rs c a n b e p a s s e d l i ke i n a c f u n c t i on c al l( a) P r o c e d u r e(b)Macro

( c ) S u b R o u ti n e( d ) L i b r ar y f u n c t i o n128. W h i ch o n e of th e s e i n s tr u c t i o n t a ke s t h e twos c o m p l i m e nt( a) N E G(b)SBB( c ) XOR(d)NOT


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1 29. W h i ch o f th e s e c a l l s u s e s on l y r e g i s t e r s( a) C A L L TA B L E [ B X ]

(b)CALL(c)CALLBX(d)CALLF1 30. G i ve n t h e p r og r am s h ow n b e l ow , W h a t i s t h e e x p re s s i o n e val u a t e dby t h i s pr o gr a m ? P d b 5 Q d b 6 R d b 7 S d b 6 M OV A L , [ P ] M OV B L , [ Q] A D D A L , B L MU L A L A D D A L , R M OV C L , S D I V C L( a) ( ( P +Q ) 2 + R /S( b ) ( P + Q 2 + R) / s( c ) ( ( P + Q ) 2+ R) / S( d ) ( P + (Q + R) 2) /S131. W h i ch o f th e s e i n s tr u c t i o n s r e a d s a by t e f r o m m e m o r y an d s t or e s t he by t e in an o t h e r m e m o ry l o c at i o n( a) S C A S B( b ) M OV S B( c ) L OD S B(d)STOSB132. W h i ch o f th e f o l l ow i n g i n s t r u c t i on s a re u s e d f o r s e a r ch i n g a by t e i nastring o f by t e s( a) C M P S B( b ) M OV S B(c)SCASW(d)SCASB133. W h i ch o f th e s e i s a n ack n ow l e d g e m e nt f o r D M A r e q u e s t( a) H L DA

(b)INTRA(c)M/IO(d)DEN134. W h i ch o f th e s e s i gn a l s s e l e c t s c op r o c e s s or o p e r a t i on o f th e 8 08 6( a) M N / M X(b)DT/R(c)ALE( d ) H O LD135. W h i ch o f th e s e I C s i s a 3 t o 8 d e c o d e r u s e d f o r d e c o d i n g m e m o ry addresses( a) 8 28 4A( b ) 7 4L S 1 3 8( c ) 7 4L S 2 45 /8 28 6

( d ) 7 4L S 3 73136. W h i ch o f th e s e s i gn a l s c o mb i n at i o n i n d i c a t e s a L owe r 8 b i t d a ta t r ansfer(a) A 0 =0 & B H E =0( b ) A 0 =1 & B H E =0( c ) A 0 =0 & B H E =1( d ) A 0 =1 & B H E =1


15/20

138. D M A i s s o m e t i m e s c al l e d a s( a) M a ch i n e C yc l e

( b ) C y c l e S t e al i n g( c ) Fe tch C y c l e(d)InstructionCycle139 . The width of the SP register is - .( a) 3 2b i t s( b ) 2 4b i t s( c ) 8 b i ts( d ) 1 6b i t s140 . The 8086 has the following byte order .( a) Little Endian( b ) J u mb l e d E n d i a n(c)ByEndian( d ) M e d i u m E n d i an

4th UNIT

1 . W h i ch o f th e s e i s S i n gl e H a n d S h a ke

( a) S T B f o l l owe d by AC K a n d r e m oval of AC K ( b ) S T B o n l y ( c ) S T B f o l l owe d byAC K( d ) AC K f ol l owe d by S T B

2 . At p owe r o n or af t e r re s e t t h e p or t s a r e i n w h i ch o f t h e s e c o n d i t i on s

( a) P O RT A = I N P U T , P O RT B =I N P U T , P ORT C = I N P U T

( b ) P O RT A = I N P U T , P O RT B =O U T P U T , P O RT C = O U T P U T ( c ) P O RT A = O U TP U T , P ORT B = I N P U T , P O RT C = O U T P U T ( d ) P O RT A = I N P U T , P O RT B =I N P UT , P ORT C = OU T P U T

3 . W h i ch o f th e s e ke y s w i tch e s i s n on m e ch an i c al c ont a c t ty p e ? ( a) M E M B R A NEKEYSW ITCHES (b) HALLEFFECTKEYSWITCHES (c) MECHANICALKE Y S W I T C H E S ( d ) M AG N E T I C RE E D K E Y S W I T C H E S

4 . H ow m a ny s t e p s p e r r e vo l u t i on d o e s a s te p p e r m o to r i n h a l f s t e p m o d e ta ke ?( a) 2 00 ( b ) 2 20 ( c ) 4 00 ( d ) 3 80

5 . A n 8 b i t A /D c onve rt e r w i t h a r e f e r e n c e vol t a ge of 5 Vo l t s w i l l b e ab l e to r e a d a lowe s t n o n z e ro vo l ta g e o f ( a) 2 0 m V ( b ) 1 9. 5 m V ( c ) 1 9 m V ( d ) 2 1 m V

1 . T h e 82 55 P P I ha s ( a) 6 4 p i n s ( b ) 1 6 p i n s ( c ) 4 0 p i n s ( d ) 2 8 p i n s


16/20

2 . I f t h e c ont r ol wor d 09 B H i s g i ve n t o t h e c ont r ol r e g i s t e r o f t h e 8 25 5 P P I t h e n wh i ch o f t h e s e op t i o n s a r e th e c o n d i t i on o f th e p o r ts ( a) B I T S E T R E S E T ( b ) A L

L P O RT s I N P U T ( c ) A L L P O RT s OU T P U T ( d ) P O RT s A & B I N P U T , P O RT COU T P U T

3 . I f 8 s e ve n s e g m e nt l e d n on mu l t i p l e x e d d i s p l ay s i n c l u d i n g t h e d e c i m a l p o int a r e c o n n e c t e d . H ow m a ny w i re s a re n e e d e d t o c on n e c t t h e s e gm e nt s ( n o t i nc l u d i n g p owe r s u p p l y w i r e s ) ? ( a) 6 4 ( b ) 1 5 ( c ) 5 6 ( d ) 1 6

4 . W h a t i s t h e an g l e p e r s t e p of a s t e p p e r m o t or i n f u l l s t e p m o d e ? ( a) 0 . 45 d eg r e e s ( b ) 1 . 0 d e gr e e s ( c ) 0 . 9 d e gr e e s ( d ) 1 . 8 d e gr e e s

5 . I n th e A / D c o nve r t e r A D C 0 8 08 w h i ch of t h e s e s i gn a l s i s u s e d s e l e c t a n a na lo g i n p u t ch an n e l t o b e d i g i t i s e d ( a) E O C ( b ) O E ( c ) A L E ( d ) S O C

1 . W h i ch o f th e s e i s D ou b l e H an d S h ake ( a) S T B o n l y ( b ) S T B f o l l owe d by AC K

( c ) S T B f o l l owe d by AC K a n d r e m oval of AC K( d ) AC K f ol l owe d by S T B

2 . At p owe r o n or af t e r re s e t t h e p or t s a r e i n w h i ch o f t h e s e c o n d i t i on s ( a) P O RTA = I N P U T , P O RT B =I N P U T , P ORT C = I N P U T ( b ) P O RT A = I N P U T , P O RT B =I NP U T , P ORT C = OU T P U T ( c ) P O RT A = I N P U T , P O RT B =O U T P U T , P O RT C = O U TP U T ( d ) P O RT A = O U T P U T , P ORT B = I N P U T , P O RT C = O U T P U T

3 . W h i ch o f th e s e Pe r i p h e r a l I C s i s m ad e f o r i nte rf ac i n g K e y b oa r d s a n d M u l t i pl e x e d L E D d i s p l ay s ? ( a) 8 25 9 ( b ) 8 23 7 ( c ) 8 25 1 ( d ) 8 27 9

4 . W h i ch o f th e s e m o t or s wor k s l i ke a d ig i t al s y s t e m ( a) D C M OT O R ( b ) S T E P PE R M O T O R ( c ) I N D U C T I ON M O T OR ( d ) S Y N C H RON O U S M O T O R

5 . A n 8 b i t A /D c onve rt e r w i t h a r e f e r e n c e vol t a ge of 5 Vo l t s w i l l b e ab l e to r e a d a lowe s t n o n z e ro vo l ta g e o f ( a) 2 0 m V ( b ) 1 9. 5 m V ( c ) 2 1 m V ( d ) 1 9 m V

6 . T h e t h i rd re s p o n s e o f th e 8 08 6t o a n i nt e r ru p t i s w h i ch on e of t h e f o l l ow i n g ? (a) D e c r e m e nt s th e S P & p u s h e s c u rr e nt C S c o nt e nt s ( b ) R e s e t s Tr a p F l a g ( c )I t d i s ab l e s i nt e r ru p t fl a g ( d ) D e c r e m e nt s th e S P by 2 & p u s h e s fl a g r e gi s te r

7 . W h i ch o f th e s e i s c a l l e d f o r d o i n g S i n gl e S t e p p i n g ? ( a) I N T 3 ( b ) I N T 1 ( c )INT0 (d) INT2

1 . G r o u p B p o rt as s i gn m e nt s of 82 55 i s ( a) Po rt B & L owe r Por t C ( b ) Po rt A & U p p er Po r t C ( c ) Po rt B & U p p e r Por t C ( d ) Po rt A & L owe r Po r t C

2 . I f t h e c o nt ro l wo rd 0 0 i s gi ve n t o t h e c o ntr o l r e gi s te r o f t h e 8 25 5 P P I t h e n w h ich of th e s e o p ti o n s a re th e c on d i t i o n o f t h e p or t s ( a) B I T S E T R E S E T ( b ) A L L PO RT s OU T P U T ( c ) P O RT s A & B I N P U T , P O RT C OU T P U T ( d ) A L L P O RT s I NPUT

3 . I f 8 s e ve n s e g me nt l e d n o n mu l t i p l e x e d d i s p l ay s i n c l u d in g th e d e c i m a l p o int a re a l l l i g ht e d u p a n d e a ch o f th e s e i s b i a s e d t o c a r ry 5 m A . W h a t i s t h e t ot al cu r r e nt d r aw n f ro m t h e p owe r s u p p l y w h e n al l th e s e g m e nt s a r e O N ? ( a) 2 80 m A (b ) 4 0 m A ( c ) 8 0 m A ( d ) 3 20 m A


17/20

4 . T h e e l e c t r o m e ch an i c a l d e vi c e w h i ch p r o d u c e s m e ch an i c a l d i s p la c e m e nti n p r op or t i on t o an ap p l i e d vo l t ag e i s k n ow a s ( a) S o l e n oi d ( b ) C o nta c t or( c ) A

c t u a to r ( d ) R e l ay

5 . I n a D/ A c onve r te r th e o u tp u t vo l ta g e i s ( a) Vo l t ag e ( b ) P u l s e s ( c ) c u r r e nt (d ) R am p) A ( b ) B ( c ) b ( d ) a

1 . M o d e 1 of 82 55 i s u s e d f o r w h i ch o f t h e s e I / O m e t h o ds

( a) B i - D i re c t i on a l H a n d s h ake ( b ) D M A I /O ( c ) S t r ob e d or H an d S h ake m o d e( d )S i m p l e I n p u t/ O u tp u t

2 . I f t h e 8 25 5 i s s e l e c t e d f or ad d r e s s e s 0 F 8 00 H t o 0F 8 0 6H , w h i ch o n e o f t h ef o l low i n g i s t he a d d re s s o f P ORT C

( a) 0 F 80 6H ( b ) 0 F 80 2H ( c ) 0 F 80 4H ( d ) 0 F 80 0H

3 . I f 8 s e ve n s e gm e nt l e d mu l t i p l e x e d d i s p l ay s i n c l u d i n g t h e d e c i m a l p oint a r ec on n e c te d . H ow m a ny w i r e s ar e n e e d e d t o c o n n e c t t h e s e gm e nt s ( n o t i n c l ud i n

g p owe r s u p p l y w i r e s ) ?( a) 1 5 ( b ) 1 6 ( c ) 5 6 ( d ) 6 4

4 . T h e d i o de ke p t a c r os s t h e c oi l o f a s t e p p e r m o t or i s f o r?

( a) S h o rt i n g t h e B ack E M F ( b ) To s t op th e s t e p p e r m ot o r ( c ) S t op p i n g fl ow o f curr e nt ( d ) A l l ow i n g fl ow o f c u r re nt

5 . I n th e A / D c o nve r t e r A D C 0 8 08 w h i ch of t h e s e s i gn a l s tr i s t a t e s t h e d i gi t al o utp u t of A D C

( a) E O C ( b ) A L E ( c ) S O C ( d ) O E

6 . T h e f o u rt h r e s p on s e o f t h e 80 86 t o an i nte rr u p t i s w h i ch o n e of t he f o l l ow i n g? (a) D e c r e m e nt s th e S P by 2 & p u s h e s fl a g r e gi s te r ( b ) I t d i s ab l e s i nt e r ru p t fl a g( c )D e c r e m e nt s th e S P & p u s h e s c u rr e nt C S c o nt e nt s ( d ) R e s e t s Tr a p F l a g


18/20

1 . G r o u p A p or t a s s i g n m e nt s o f 8 25 5 i s ( a) Po rt B & L owe r Por t C ( b ) Po rt A & U p pe r Po r t C ( c ) Po rt B & U p p e r Por t C ( d ) Po rt A & L owe r Po r t C

2 . I f t h e c ont r ol wor d 09 B H i s g i ve n t o t h e c ont r ol r e g i s t e r o f t h e 8 25 5 P P I t h e n wh i ch o f t h e s e op t i o n s a r e th e c o n d i t i on o f th e p o r ts ( a) P O RT s A & B I N P U T , PO RT C OU T P U T ( b ) A L L P O RT s OU T P U T ( c ) B I T S E T R E S E T ( d ) A L L P O RT sINPUT

3 . I f 8 s e ve n s e g me nt l e d n o n mu l t i p l e x e d d i s p l ay s i n c l u d in g th e d e c i m a l p o int a re a l l l i g ht e d u p a n d e a ch o f th e s e i s b i a s e d t o c a r ry 5 m A . W h a t i s t h e t ot al cu r r e nt d r aw n f ro m t h e p owe r s u p p l y w h e n al l th e s e g m e nt s a r e O N ? ( a) 3 20 m A (b ) 2 80 m A ( c ) 4 0 m A ( d ) 8 0 m A

4 . T h e e l e c t r o m e ch an i c a l d e vi c e w h i ch p r o d u c e s m e ch an i c a l d i s p la c e m e nti n p r op or t i on t o an ap p l i e d vo l t ag e i s k n ow a s ( a) C o nta c t or ( b ) S o l e n oi d ( c ) Ac t u a to r ( d ) R e l ay

1 . T h e 82 55 P P I ha s ( a) 2 8 p i n s ( b ) 1 6 p i n s ( c ) 4 0 p i n s ( d ) 6 4 p i n s

2 . T wo 82 55 s I C 1 & I C 2 a r e c on n e c t e d to 80 8 6 1 6 b i t b u s an d D 0 t o D7 ar e c o n n ec t e d t o I C 1 a n d D 8 t o D 1 5 a re c o n n e c t e d t o I C 2. T h e b a s e a d d r e s s s i g n al s A 0& A 1 go t o I C 1 & I C 2 s A 0 & A 1 p i n s r e s p e c ti ve l y. I f a d e c o d e d s i g n al w i t h a r an ge of 0F F E 0H to 0 F F E 3 H t h e n W h a t i s t h e a d d r e s s of I C 1 P O RT B r e g i s t e r ( a) 0 FF E 2H ( b ) 0 F F E 3H ( c ) 0 F F E 1H ( d ) 0 F F E 0H

3 . A ke y b o ar d i s m a d e u s i n g 1 2 ke y s c o n n e c t e d n ot a s a ma t r i x. H ow m any p i n sof t h e I / O p o r t ar e u s e d ? ( a) 1 2 ( b ) 0 7 ( c ) 0 9 ( d ) 1 1

4 . H ow m a ny w i re s d o e s a s t e p p e r m ot or e ff e c t i ve l y h ave ? ( a) 4 ( b ) 2 ( c ) 3 ( d )5

5 . A n A / D c o nve r t e r w h i ch h as a m a xi mu m o u tp u t d i g i ta l va l u e of 1 0 23 n e e d s h owm any w i r e s f o r c o n n e c t i n g i ts d i g i ta l o u t p u t t o a p e r i p h e r al ch i p ( a) 1 0 ( b ) 1 3(c) 8 (d) 12

1 . T h e nu mb e r of p o r ts 8 25 5 P P I h as i s ( a) 3 ( b ) 2 ( c ) 1 ( d ) 4

2 . W h e n 82 55 p o r t i s to b e r e a d t h e n w h i ch o f t h e s e c o mb i n a t i on s i s va l id ( a) R

D= 1 , W R= 0, R E S E T =0 , C S =0 ( b ) R D= 0 , W R= 1, R E S E T =1 , C S =0 ( c ) R D= 0 , W R=1, R E S E T =0 , C S =1 ( d ) R D= 0 , W R= 1, R E S E T =0 , C S =0

3 . W h i ch o f th e s e ke y s w i tch e s i s n on m e ch an i c al c ont a c t ty p e ? ( a) M E C H A N I CA L K E Y S W I T C H E S ( b ) H A L L E F F E C T K E Y S W I T C H E S ( c ) M AG N E T I C RE EDKEYSWITCHES (d) MEMBRANEKEYSWITCHES

4 . H ow m a ny s t e p s p e r r e vo l u t i on d o e s a s te p p e r m o to r i n f u l l s t e p m o d e t ake ?( a) 2 20 ( b ) 2 00 ( c ) 4 00 ( d ) 3 80



19/20

1 . T h e nu mb e r of p o r ts 8 25 5 P P I h as i s ( a) 1 ( b ) 3 ( c ) 2 ( d ) 4

2 . I f t h e c ont r ol wor d 09 B H i s g i ve n t o t h e c ont r ol r e g i s t e r o f t h e 8 25 5 P P I t h e n wh i ch o f t h e s e op t i o n s a r e th e c o n d i t i on o f th e p o r ts ( a) P O RT s A & B I N P U T , PO RT C OU T P U T ( b ) A L L P O RT s I N P U T ( c ) B I T S E T R E S E T ( d ) A L L P O RT sOU T P U T

3 . A ke y b o ar d i s m a d e u s i n g 1 2 ke y s c o n n e c t e d n ot a s a ma t r i x. H ow m any p i n sof t h e I / O p o r t ar e u s e d ? ( a) 1 2 ( b ) 0 7 ( c ) 1 1 ( d ) 0 9

5 . I n th e A / D c o nve r t e r A D C 0 8 08 w h i ch of t h e s e s i gn a l s i s u s e d s e l e c t a n a na l og i n p u t ch an n e l t o b e d i g i t i s e d ( a) A L E ( b ) S O C ( c ) O E ( d ) E O C

6 . T h e s e c o n d r e s p on s e o f t h e 80 86 t o an i nt e r r u p t i s w h i ch o n e o f th e f o l l ow i ng ? ( a) R e s e t s Tr a p F l a g ( b ) D e c r e m e nt s th e S P by 2 & p u s h e s fl a g r e gi s te r ( c )D e c r e m e nt s th e S P & p u s h e s c u rr e nt C S c o nt e nt s ( d ) I t d i s ab l e s i nt e r ru p t fl ag

1 . W h i ch o f th e s e i s D ou b l e H an d S h ake ( a) S T B f o l l owe d by AC K ( b ) S T B f o l lowe d by AC K a n d r e m oval of AC K( c ) S T B o n l y ( d ) AC K f ol l owe d by S T B

2 . T wo 82 55 s I C 1 & I C 2 a r e c on n e c t e d to 80 8 6 1 6 b i t b u s an d D 0 t o D7 ar e c o n n ec t e d t o I C 1 a n d D 8 t o D 1 5 a re c o n n e c t e d t o I C 2. T h e b a s e a d d r e s s s i g n al s A 0& A 1 go t o I C 1 & I C 2 s A 0 & A 1 p i n s r e s p e c ti ve l y. I f a d e c o d e d s i g n al w i t h a r an ge of 0F F E 0H to 0 F F E 3 H t h e n W h a t i s t h e a d d r e s s of I C 1 P O RT B r e g i s t e r ( a) 0 FF E 2H ( b ) 0 F F E 0H ( c ) 0 F F E 3H ( d ) 0 F F E 1H

3 . A ke y b o ar d i s m a d e u s i n g 1 2 ke y s c o n n e c t e d as a m at r i x o f 4 X 3 . H ow m any p in s of t h e I /O p o r t ar e u s e d ? ( a) 1 2 ( b ) 0 9 ( c ) 0 7 ( d ) 1 1

4 . H ow m a ny s t e p s p e r r e vo l u t i on d o e s a s te p p e r m o to r i n f u l l s t e p m o d e t ake ?( a) 2 00 ( b ) 4 00 ( c ) 3 80 ( d ) 2 20


1 . M o d e 1 of 82 55 i s u s e d f o r w h i ch o f t h e s e I / O m e t h o d s ( a) S i m p l e I n p u t/ O u

tp u t ( b ) D M A I /O ( c ) B i - D i re c t i on a l H a n d s h ake ( d ) S t r ob e d or H an d S h ake mo d e 2 . T wo 82 55 s I C 1 & I C 2 a r e c on n e c t e d to 80 8 6 1 6 b i t b u s an d D 0 t o D7 ar ec o n n e c t e d t o I C 1 a n d D 8 t o D 1 5 a re c o n n e c t e d t o I C

2. T h e b a s e a d d r e s s s i g n al s A 0 & A 1 go t o I C 1 & I C 2 s A 0 & A 1 p i n s r e s p e c ti ve ly. I f a d e c o d e d s i g n al w i t h a r an g e of 0F F E 0H to 0 F F E 3 H t h e n W h a t i s t h e a d d r es s of I C 1 P O RT B r e g i s t e r ( a) 0 F F E 2H ( b ) 0 F F E 0H ( c ) 0 F F E 3H ( d ) 0 F F E 1H

3 . I f 8 s e ve n s e gm e nt l e d mu l ti p l e xe d d i s p l ay s i n c l u d i n g t h e d e c i m a l p oi nt ar ea l l l i g hte d u p a n d e ach o f th e s e i s b i as e d t o c a rr y 5 m A . W h at i s t h e t o t al c u rr e nt dr aw n f r o m t h e p owe r s u p pl y w h e n a l l t h e s e g m e nts a re O N ? ( a) 2 80 m A ( b ) 8 0 m

A ( c ) 4 0 m A ( d ) 3 00 m A


20/20

4 . T h e d i o de ke p t a c r os s t h e c oi l o f a s t e p p e r m o t or i s f o r ? ( a) S t op p i n g fl ow o fc u rr e nt ( b ) To s t op th e s t e p p e r m ot o r ( c ) A l l ow i n g fl ow o f c u r re nt ( d ) S h o rt i ng t h e B ack E M F

5 . I n th e A / D c o nve r t e r A D C 0 8 08 w h i ch of t h e s e s i gn a l s tr i s t a t e s t h e d i gi t a l o utp u t of A D C ( a) O E ( b ) S O C ( c ) E O C ( d ) A L E

6 . T h e f o u rt h r e s p on s e o f t h e 80 86 t o an i nte rr u p t i s w h i ch o n e of t he f o l l ow i n g ?( a) D e c r e m e nt s th e S P by 2 & p u s h e s fl a g r e gi s te r ( b ) R e s e t s Tr a p F l a g ( c ) I t di s ab l e s i nt e r ru p t fl a g ( d ) D e c r e m e nt s th e S P & p u s h e s c u rr e nt C S c o nt e nt s

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