module 20.1 connecting intercepts and zeroes...module 20.1 connecting intercepts and zeroes how can...

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Module 20.1 Connecting Intercepts And Zeroes How can you use the graph of a quadratic function to solve its related quadratic equation? P. 937

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Module 20.1

Connecting Intercepts And Zeroes

How can you use the graph of a quadratic functionto solve its related quadratic equation?

P. 937

As we said in Module 19.2 – Quadratic functions can take more than one form.

The first is called Vertex Form. Here it is: π’ˆ 𝒙 = 𝒂(𝒙 βˆ’ 𝒉)𝟐 + π’ŒExample: π’ˆ 𝒙 = πŸ‘(𝒙 βˆ’ 𝟐)𝟐 + πŸ’We learned how to graph a quadratic function in this form on page 908.

Now we focus on the second, called Standard Form.Here it is: π’š = π’‚π’™πŸ + 𝒃𝒙 + 𝒄Example: π’š = πŸ‘π’™πŸ + πŸ”π’™ βˆ’ πŸ’

How do we graph a quadratic function in this form?

One way is to create a table of x and y values, and then plot them.

π’š = πŸ‘π’™πŸ + πŸ”π’™ βˆ’ πŸ’

How do you determine the axis of symmetry?

The axis of symmetry for a quadratic equation

in standard form is given by the equation 𝒙 = βˆ’π’ƒ

πŸπ’‚

So if we have the equation π’š = πŸ‘π’™πŸ + πŸ”π’™ βˆ’ πŸ’

Then the axis of symmetry is βˆ’π’ƒ

πŸπ’‚= βˆ’

πŸ”

𝟐 πŸ‘= βˆ’

πŸ”

πŸ”= –1

That’s a vertical line with the equation 𝒙 = βˆ’πŸ.

So we know the x-coordinate of the vertex ( –1),which is one half of the vertex.

How do you find the vertex?

Substitute the value of the axis of symmetry for 𝒙 into the equation and solve for y.

π’š = πŸ‘π’™πŸ + πŸ”π’™ βˆ’ πŸ’= πŸ‘(βˆ’πŸ)𝟐+πŸ” βˆ’πŸ βˆ’ πŸ’= πŸ‘ 𝟏 βˆ’ πŸ” βˆ’ πŸ’= πŸ‘ βˆ’ πŸ” βˆ’ πŸ’ = βˆ’πŸ•

So the vertex is at (–1, –7).

P. 937

P. 938Just like there are quadratic functions, like 𝒇 𝒙 = π’‚π’™πŸ + 𝒃𝒙 + 𝒄There are also quadratic equations, like πŸπ’™πŸ βˆ’ πŸ“ = βˆ’πŸ‘

How do you solve a quadratic equation?One way to do it is to factor it and find the β€œzeroes”.Another way is to do it graphically.

It’s a 5-Step process.

Step 1: Convert the equation into a β€œrelated” function by rewriting it so that it equals zero on one side.

πŸπ’™πŸ βˆ’ πŸ“ = βˆ’πŸ‘+ 3 + 3 Add 3 to both sides, so the right side will equal 0

πŸπ’™πŸ βˆ’ 𝟐 = 𝟎

Step 2: Replace the zero with a y.πŸπ’™πŸ βˆ’ 𝟐 = π’šπ² = πŸπ’™πŸ βˆ’ 𝟐 Re-order it

Step 3: Make a table of values for this β€œrelated” function.𝐲 = πŸπ’™πŸ βˆ’ 𝟐

Step 4: Plot the points and sketch the graph.

Step 5: The solution(s) of the equation are the x-intercepts, also known as the β€œzeros” of thefunction. In this case they’re 𝒙 = 𝟏 and 𝒙 = βˆ’πŸ.

P. 938

A zero of a function is an x-value that makes the value of the function 0.

The zeros of a function are the x-intercepts of the graph of the function.

A quadratic function may have one, two, or no zeros.

P. 938

One Zero: 𝑦 = 2π‘₯2

When is 2π‘₯2 = 0 ?Only when π‘₯ = 0.

Two Zeros: 𝑦 = 2π‘₯2 βˆ’ 2When is 2π‘₯2 βˆ’ 2 = 0 ?When π‘₯ = βˆ’1 π‘Žπ‘›π‘‘ π‘₯ = 1.

No Zeros: 𝑦 = 2π‘₯2 + 2When is 2π‘₯2 + 2 = 0 ?Never!

P. 939

P. 939

P. 941

P. 941-942

You can solve this algebraically:Subtract 10 from both sides to get βˆ’πŸπŸ”π’•πŸ + πŸ‘πŸ” = 𝟎.Add πŸπŸ”π’•πŸ to both sides, to get πŸπŸ”π’•πŸ = πŸ‘πŸ”.Divide both sides by 16, so π’•πŸ = 𝟐. πŸπŸ“.Take the square root of both sides to get 𝒕 = ±𝟏. πŸ“.Since time can’t be negative, the answer has to be 1.5 seconds.

Or you can solve this graphically:

βˆ’16𝑑2 + 36 = 0βˆ’16𝑑2 + 36 = 𝑦

Create a table of x (or t) and y values, then graph those coordinates.

The y-axis represents the height, and the x-axis represents time.

When y=0, what is x (or t) ?

P. 942