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EE207: Digital Systems I, Semester I 2003/2004
CHAPTER 2-i:Combinational Logic Circuits
(Sections 2.1 2.5)
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Overview
Binary logic and Gates Boolean Algebra
Basic Properties Algebraic Manipulation
Standard and Canonical Forms Minterms and Maxterms (Canonical forms) SOP and POS (Standard forms)
Karnaugh Maps (K-Maps) 2, 3, 4, and 5 variable maps Simplification using K-Maps
K-Map Manipulation Implicants: Prime, Essential Dont Cares
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
226-Mar-10
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Binary Logic
Deals with binary variables that take 2 discrete values (0 and 1), and with logic operations
Three basic logic operations: AND, OR, NOT
Binary/logic variables are typically represented as letters: A,B,C,,X,Y,Z
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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Binary Logic Function
F(vars) = expression
Example: F(a,b) = ab + bG(x,y,z) = x(y+z)
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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set of binaryset of binaryvariablesvariables
nnOperators ( +, Operators ( +, , ), )nnVariablesVariablesnnConstants ( 0, 1 )Constants ( 0, 1 )nnGroupings (parenthesis)Groupings (parenthesis)
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Basic Logic Operators
1-bit logic AND resembles binary multiplication:
0 0 = 0, 0 1 = 0,1 0 = 0, 1 1 = 1
1-bit logic OR resembles binary addition, except for one operation:
0 + 0 = 0, 0 + 1 = 1,1 + 0 = 1, 1 + 1 = 1 ( 102)
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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Truth Tables for logic operators
Truth table: tabular form that uniquely represents the relationship between the input variables of a function and its output
AA BB F=AF=ABB00 00 0000 11 0011 00 0011 11 11
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6Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
2-Input ANDAA BB F=AF=A++BB00 00 0000 11 1111 00 1111 11 11
2-Input OR
AA F=AF=A00 1111 00
NOT
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Truth Tables (cont.)
Q: Let a function F() depend on nvariables. How many rows are there in the truth table of F() ?
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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A: 2n rows, since there are 2n possible binary patterns/combinations for the n variables
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Logic Gates
Logic gates are abstractions of electronic circuit components that operate on one or more input signals to produce an output signal.
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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2-Input AND 2-Input OR NOT (Inverter)
A A AB BF G H
F = AF = ABB G = A+BG = A+B H = AH = A
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Timing Diagram
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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A
B
F=AB
G=A++B
H=A
1
1
1
1
10
0
0
0
0
t0 t1 t2 t3 t4 t5 t6
Inputsignals
GateOutputSignals
Basic Assumption:Zero time forsignals topropagate Through gates
Transitions
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Combinational Logic Circuitfrom Logic Function
Consider function F = A + BC + AB A combinational logic circuit can be constructed to implement F, by
appropriately connecting input signals and logic gates: Circuit input signals from function variables (A, B, C) Circuit output signal function output (F) Logic gates from logic operations
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10Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
A
B
C
F
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Combinational Logic Circuitfrom Logic Function (cont.)
In order to design a cost-effective and efficient circuit, we must minimize the circuits size (area) and propagation delay (time required for an input signal change to be observed at the output line)
Observe the truth table of F=A + BC + AB and G=A + BC
Truth tables for F and G are identical same function
Use G to implement the logic circuit (less components)
AA BB CC FF GG00 00 00 11 1100 00 11 11 1100 11 00 11 1100 11 11 11 1111 0 0 00 00 0011 00 11 00 0011 11 00 11 1111 11 11 00 00
26-Mar-10
11Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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Circuitfrom Logic Function
(cont.)
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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A
B
C
F
ABC
G
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Boolean Algebra
VERY nice machinery used to manipulate (simplify) Boolean functions
George Boole (1815-1864): An investigation of the laws of thought
Terminology: Literal: A variable or its complement Product term: literals connected by Sum term: literals connected by +
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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Boolean Algebra Properties
Let X: boolean variable, 0,1: constants
1. X + 0 = X -- Zero Axiom2. X 1 = X -- Unit Axiom3. X + 1 = 1 -- Unit Property4. X 0 = 0 -- Zero Property
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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Boolean Algebra Properties (cont.)
Let X: boolean variable, 0,1: constants
5. X + X = X -- Idepotence6. X X = X -- Idepotence7. X + X = 1 -- Complement8. X X = 0 -- Complement9. (X) = X -- Involution
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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Unchanged in value following
multiplication by itself
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The Duality Principle
The dual of an expression is obtained by exchanging ( and +), and (1 and 0) in it, provided that the precedence of operations is not changed.
Cannot exchange x with x Example:
Find H(x,y,z), the dual of F(x,y,z) = xyz + xyz H = (x+y+z) (x+y+ z)
Dual does not always equal the original expression
If a Boolean equation/equality is valid, its dual is also valid
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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The Duality Principle (cont.)
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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With respect to duality, Identities 1 8 have the following relationship:
1. X + 0 = X 2. X 1 = X (dual of 1)3. X + 1 = 1 4. X 0 = 0 (dual of 3)5. X + X = X 6. X X = X (dual of 5)7. X + X = 1 8. X X = 0 (dual of 8)
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More Boolean Algebra Properties
Let X,Y, and Z: boolean variables
10. X + Y = Y + X 11. X Y = Y X -- Commutative12. X + (Y+Z) = (X+Y) + Z 13. X(YZ) = (XY)Z -- Associative14. X(Y+Z) = XY + XZ 15. X+(YZ) = (X+Y) (X+Z)
-- Distributive16. (X + Y) = X Y 17. (X Y) = X + Y -- DeMorgans
In general,( X1 + X2 + + Xn ) = X1X2 Xn, and ( X1X2 Xn ) = X1 + X2 + + Xn
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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Absorption Property (Covering)
1. x + xy = x2. x(x+y) = x (dual) Proof:
x + xy = x1 + xy= x(1+y) = x1= x
QED (2 true by duality)
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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Consensus Theorem
1. xy + xz + yz = xy + xz2. (x+y)(x+z)(y+z) = (x+y)(x+z) -- (dual) Proof:
xy + xz + yz = xy + xz + (x+x)yz= xy + xz + xyz + xyz= (xy + xyz) + (xz + xzy)= xy + xz
QED (2 true by duality).
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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Truth Tables (revisited)
Enumerates all possible combinations of variable values and the corresponding function value
Truth tables for some arbitrary functions F1(x,y,z), F2(x,y,z), and F3(x,y,z) are shown to the right.
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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xx yy zz FF11 FF22 FF3300 00 00 00 11 1100 00 11 00 00 1100 11 00 00 00 1100 11 11 00 11 1111 00 00 00 11 0011 00 11 00 11 0011 11 00 00 00 0011 11 11 11 00 11
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Truth Tables (cont.)
Truth table: a unique representation of a Boolean function
If two functions have identical truth tables, the functions are equivalent (and vice-versa).
Truth tables can be used to prove equality theorems.
However, the size of a truth table grows exponentially with the number of variables involved, hence unwieldy. This motivates the use of Boolean Algebra.
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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Boolean expressions-NOT unique
Unlike truth tables, expressions representing a Boolean function are NOT unique.
Example: F(x,y,z) = xyz + xyz + xyz G(x,y,z) = xyz + yz
The corresponding truth tables for F() and G() are to the right. They are identical!
Thus, F() = G()
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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xx yy zz FF GG00 00 00 11 1100 00 11 00 0000 11 00 11 1100 11 11 00 0011 00 00 00 0011 00 11 00 0011 11 00 11 1111 11 11 00 00
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Algebraic Manipulation
Boolean algebra is a useful tool for simplifying digital circuits.
Why do it? Simpler can mean cheaper, smaller, faster.
Example: Simplify F = xyz + xyz + xz.F = xyz + xyz + xz
= xy(z+z) + xz= xy1 + xz= xy + xz
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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Algebraic Manipulation (cont.)
Example: Provexyz + xyz + xyz = xz + yz
Proof:xyz+ xyz+ xyz
= xyz + xyz + xyz + xyz= xz(y+y) + yz(x+x)= xz1 + yz1= xz + yz
QED.
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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Complement of a Function
The complement of a function is derived by interchanging ( and +), and (1 and 0), and complementing each variable.
Otherwise, interchange 1s to 0s in the truth table column showing F.
The complement of a function IS NOT THE SAME as the dual of a function.
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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Complementation: Example
Find G(x,y,z), the complement ofF(x,y,z) = xyz + xyz
G = F = (xyz + xyz)= (xyz) (xyz) DeMorgan= (x+y+z) (x+y+z) DeMorgan again
Note: The complement of a function can also be derived by finding the functions dual, and then complementing all of the literals
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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Canonical and Standard Forms
We need to consider formal techniques for the simplification of Boolean functions. Minterms and Maxterms Sum-of-Minterms and Product-of-Maxterms Product and Sum terms Sum-of-Products (SOP) and Product-of-Sums
(POS)
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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Definitions
Literal: A variable or its complement Product term: literals connected by Sum term: literals connected by + Minterm: a product term in which all the
variables appear exactly once, either complemented or uncomplemented
Maxterm: a sum term in which all the variables appear exactly once, either complemented or uncomplemented
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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Minterm
Represents exactly one combination in the truth table.
Denoted by mj, where j is the decimal equivalent of the minterms corresponding binary combination (bj).
A variable in mj is complemented if its value in bjis 0, otherwise is uncomplemented.
Example: Assume 3 variables (A,B,C), and j=3. Then, bj = 011 and its corresponding minterm is denoted by mj = ABC
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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Maxterm
Represents exactly one combination in the truth table.
Denoted by Mj, where j is the decimal equivalent of the maxterms corresponding binary combination (bj).
A variable in Mj is complemented if its value in bjis 1, otherwise is uncomplemented.
Example: Assume 3 variables (A,B,C), and j=3. Then, bj = 011 and its corresponding maxterm is denoted by Mj = A+B+C
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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Truth Table notation for Minterms and Maxterms
Minterms and Maxterms are easy to denote using a truth table.
Example: Assume 3 variables x,y,z (order is fixed)
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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xx yy zz MintermMinterm MaxtermMaxterm00 00 00 xyz = mxyz = m00 x+y+z = Mx+y+z = M0000 00 11 xyz = mxyz = m11 x+y+z = Mx+y+z = M1100 11 00 xyz = mxyz = m22 x+y+z = Mx+y+z = M2200 11 11 xyz = mxyz = m33 x+y+z= Mx+y+z= M3311 00 00 xyz = mxyz = m44 x+y+z = Mx+y+z = M4411 00 11 xyz = mxyz = m55 x+y+z = Mx+y+z = M5511 11 00 xyz = mxyz = m66 x+y+z = Mx+y+z = M6611 11 11 xyz = mxyz = m77 x+y+z = Mx+y+z = M77
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Canonical Forms (Unique)
Any Boolean function F( ) can be expressed as a unique sum of minterms and a unique product of maxterms (under a fixed variable ordering).
In other words, every function F() has two canonical forms: Canonical Sum-Of-Products (sum of
minterms) Canonical Product-Of-Sums (product of
maxterms)
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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Canonical Forms (cont.)
Canonical Sum-Of-Products:The minterms included are those mj such that F( ) = 1 in row j of the truth table for F( ).
Canonical Product-Of-Sums:The maxterms included are those Mj such that F( ) = 0 in row j of the truth table for F( ).
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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Example
Truth table for f1(a,b,c) at right The canonical sum-of-products form for
f1 isf1(a,b,c) = m1 + m2 + m4 + m6
= abc + abc + abc + abc The canonical product-of-sums form for
f1 isf1(a,b,c) = M0 M3 M5 M7
= (a+b+c)(a+b+c) (a+b+c)(a+b+c).
Observe that: mj = Mj
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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aa bb cc ff1100 00 00 0000 00 11 1100 11 00 1100 11 11 0011 00 00 1111 00 11 0011 11 00 1111 11 11 00
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Shorthand: and
f1(a,b,c) = m(1,2,4,6), where indicates that this is a sum-of-products form, and m(1,2,4,6) indicates that the minterms to be included are m1, m2, m4, and m6.
f1(a,b,c) = M(0,3,5,7), where indicates that this is a product-of-sums form, and M(0,3,5,7) indicates that the maxterms to be included are M0, M3, M5, and M7.
Since mj = Mj for any j, m(1,2,4,6) = M(0,3,5,7) = f1(a,b,c)
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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Conversion Between Canonical Forms
Replace with (or vice versa) and replace those js that appeared in the original form with those that do not.
Example:f1(a,b,c) = abc + abc + abc + abc
= m1 + m2 + m4 + m6= (1,2,4,6)= (0,3,5,7)= (a+b+c)(a+b+c)(a+b+c)(a+b+c)
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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Standard Forms (NOT Unique)
Standard forms are like canonical forms, except that not all variables need appear in the individual product (SOP) or sum (POS) terms.
Example:f1(a,b,c) = abc + bc + acis a standard sum-of-products form
f1(a,b,c) = (a+b+c)(b+c)(a+c)is a standard product-of-sums form.
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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Conversion of SOP from standard to canonical form
Expand non-canonical terms by inserting equivalent of 1 in each missing variable x:(x + x) = 1
Remove duplicate minterms f1(a,b,c) = abc + bc + ac
= abc + (a+a)bc + a(b+b)c= abc + abc + abc + abc + abc= abc + abc + abc + abc
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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Conversion of POS from standard to canonical form
Expand noncanonical terms by adding 0 in terms of missing variables (e.g., xx = 0) and using the distributive law
Remove duplicate maxterms f1(a,b,c) = (a+b+c)(b+c)(a+c)
= (a+b+c)(aa+b+c)(a+bb+c)= (a+b+c)(a+b+c)(a+b+c)
(a+b+c)(a+b+c)= (a+b+c)(a+b+c)(a+b+c)(a+b+c)
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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Karnaugh Maps
Karnaugh maps (K-maps) are graphicalrepresentations of boolean functions.
One map cell corresponds to a row in the truth table.
Also, one map cell corresponds to a minterm or a maxterm in the boolean expression
Multiple-cell areas of the map correspond to standard terms.
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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Two-Variable Map
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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m3m21
m1m00
10x1x2
0 1
2 3
NOTE: ordering of variables is IMPORTANT for f(x1,x2), x1 is the row, x2 is the column.
Cell 0 represents x1x2; Cell 1 represents x1x2; etc. If a minterm is present in the function, then a 1 is placed in the corresponding cell.
m3m11
m2m00
10x2x1
0 2
1 3OR
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Two-Variable Map (cont.)
Any two adjacent cells in the map differ by ONLY one variable, which appears complemented in one cell and uncomplemented in the other.
Example:m0 (=x1x2) is adjacent to m1 (=x1x2) and m2 (=x1x2) but NOT m3 (=x1x2)
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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2-Variable Map -- Example
f(x1,x2) = x1x2+ x1x2 + x1x2 = m0 + m1 + m2= x1 + x2
1s placed in K-map for specified minterms m0, m1, m2
Grouping (ORing) of 1s allows simplification
What (simpler) function is represented by each dashed rectangle? a1 = m0 + m1 a2 = m0 + m2
Note m0 covered twice
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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xx11 00 11
00 11 11
11 11 00
x2
0 1
2 3
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Minimization as SOP using K-map
Enter 1s in the K-map for each product term in the function
Group adjacent K-map cells containing 1s to obtain a product with fewer variables. Groups must be in power of 2 (2, 4, 8, )
Handle boundary wrap for K-maps of 3 or more variables.
Realize that answer may not be unique
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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Three-Variable Map
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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m6m7m5m41
m2m3m1m00
10110100yz
x0 1 3 2
4 5 7 6
-Note: variable ordering is (x,y,z); yz specifies column, x specifies row.-Each cell is adjacent to three other cells (left or right or top or bottom or edge wrap)
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Three-Variable Map (cont.)
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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The types of structures The types of structures that are either minterms or that are either minterms or are generated by repeated are generated by repeated application of the application of the minimization theorem on a minimization theorem on a three variable map are three variable map are shown at right. shown at right. Groups of 1, 2, 4, 8 are Groups of 1, 2, 4, 8 are possible.possible.
minterm
group of 2 terms
group of 4 terms
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Simplification
Enter minterms of the Boolean function into the map, then group terms
Example: f(a,b,c) = ac + abc + bc Result: f(a,b,c) = ac+ b
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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11 11 1111 11
abc
11 11 1111 11
00 01 10 11
0
1
00 01 10 11
0
1
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More Examples
f1(x, y, z) = m(2,3,5,7)
f2(x, y, z) = m (0,1,2,3,6)
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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nn ff11(x, y, z) = xy + xz(x, y, z) = xy + xz
nnff22(x, y, z) = x+yz(x, y, z) = x+yz
yzyzXX 0000 0101 1111 1010
00 11 1111 11 11
11 11 11 1111
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Four-Variable Maps
Top cells are adjacent to bottom cells. Left-edge cells are adjacent to right-edge cells.
Note variable ordering (WXYZ).
26-Mar-10
50Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
m11m10m9m810
m14m15m13m1211
m6m7m5m401
m2m3m1m000
10110100WXYZ
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Four-variable Map Simplification
One square represents a minterm of 4 literals. A rectangle of 2 adjacent squares represents a
product term of 3 literals. A rectangle of 4 squares represents a product
term of 2 literals. A rectangle of 8 squares represents a product
term of 1 literal. A rectangle of 16 squares produces a function
that is equal to logic 1.
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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Example
Simplify the following Boolean function (A,B,C,D) = m(0,1,2,4,5,7,8,9,10,12,13).
First put the function g( ) into the map, and then group as many 1s as possible.
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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cdab
111
11
111
111
g(A,B,C,D) = c+bd+abdg(A,B,C,D) = c+bd+abd
111
11
111
111
00 01 11 10
00
01
11
10
00 01 11 10
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5-Variable K-Map
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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101198
13 141512
5 674
1 230
BCDE
26272524
30312928
22232120
18191716
BCDE
A=0
A=1
ABCDE
ABCDE
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Implicants and Prime Implicants (PIs)
An Implicant (P) of a function F is a product term which implies F, i.e., F(P) = 1.
An implicant (PI) of F is called a Prime Implicant of F if any product term obtained by deleting a literal of PI is NOT an implicant of F
Thus, a prime implicant is not contained in any larger implicant.
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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Example
Consider function f(a,b,c,d) whose K-map is shown at right.
ab is not a prime implicant because it is contained in b.
acd is not a prime implicant because it is contained in ad.
b, ad, and acd are prime implicants.
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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111
111
111
11
b
cd abad
acd
ab
acd
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Essential Prime Implicants (EPIs)
If a minterm of a function F is included in ONLY one prime implicant p, then p is an essential prime implicant of F.
An essential prime implicant MUST appear in all possible SOP expressions of a function
To find essential prime implicants: Generate all prime implicants of a function Select those prime implicants that contain at least one
1 that is not covered by any other prime implicant. For the previous example, the PIs are b, ad,
and acd; all of these are essential.
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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11111111111
bad
acd
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Another Example
Consider f2(a,b,c,d), whose K-map is shown below.
The only essential PI is bd.
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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11
11 11 11
11 11
11 11 11
cdab
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Systematic Procedure for Simplifying Boolean Functions
1. Generate all PIs of the function.2. Include all essential PIs.3. For remaining minterms not included in
the essential PIs, select a set of other PIs to cover them, with minimal overlap in the set.
4. The resulting simplified function is the logical OR of the product terms selected above.
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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Example
f(a,b,c,d) = m(0,1,2,3,4,5,7,14,15).
Five grouped terms, not all needed.
3 shaded cells covered by only one term
3 EPIs, since each shaded cell is covered by a different term.
F(a,b,c,d) = ab + ac + ad + abc
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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11
111
1111ab
cd
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Product of Sums Simplification
Use sum-of-products simplification on the zeros of the function in the K-map to get F.
Find the complement of F, i.e. (F) = F Recall that the complement of a boolean
function can be obtained by (1) taking the dual and (2) complementing each literal.
OR, using DeMorgans Theorem.
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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POS Example
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
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0000
1100
0111
1111ab
cd
F(a,b,c,d) = ab + ac + abcd Find dual of F, dual(F) = (a+b)(a+c)(a+b+c+d) Complement of literals in dual(F) to get F
F = (a+b)(a+c)(a+b+c+d) (verify that this is the same as in slide 60)
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Don't Care Conditions
There may be a combination of input values which will never occur if they do occur, the output is of no concern.
The function value for such combinations is called a don't care.
They are usually denoted with x. Each x may be arbitrarily assigned the value 0 or 1 in an implementation.
Dont cares can be used to further simplify a function
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
6226-Mar-10
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Minimization using Dont Cares
Treat don't cares as if they are 1s to generate PIs.
Delete PI's that cover only don't care minterms.
Treat the covering of remaining don't care minterms as optional in the selection process (i.e. they may be, but need not be, covered).
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
6326-Mar-10
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Example
Simplify the function f(a,b,c,d) whose K-map is shown at the right.
f = acd+ab+cd+abc or
f = acd+ab+cd+abd The middle two terms are EPIs, while
the first and last terms are selected tocover the minterms m1, m4, and m5.
(Theres a third solution!)
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
6426-Mar-10
xx11xx0010111010
xx11xx0010111010
00 11 00 1111 11 00 1100 00 xx xx11 11 xx xx
abcd
000111 10
00 01 11 10
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Another Example
Simplify the function g(a,b,c,d) whose K-map is shown at right.
g = ac+ abor
g = ac+bd
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
6526-Mar-10
xx 11 00 0011 xx 00 xx11 xx xx 1100 xx xx 00
xx 11 00 0011 xx 00 xx11 xx xx 1100 xx xx 00
xx 11 00 0011 xx 00 xx11 xx xx 1100 xx xx 00
abcd
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Algorithmic minimization
What do we do for functions with more than 4-5 variables?
You can code up a minimiser (Computer-Aided Design, CAD) Quine-McCluskey algorithm Iterated consensus
We wont discuss these techniques here
Chapter 2-i: Combinational Logic Circuits (2.1-- 2.5)
6626-Mar-10