metodos-numericos-1 biseccion y regla falsa
DESCRIPTION
METODOS NUMERICOSTRANSCRIPT
Grafica de y= f(x)= +x-2x y= +x-2 Signo f(x)
-3 15.086 +
-2 3.38905609893 +
-1 -0.28171817154 -
0 -1 -
1 -0.63212055883 -
2 0.13533528324 +
3 1.04978706837 +1.8 -0.03470111178
PRIMERA APROXIMACION
x y= +x-2 Signo f(x)a 1.8 -0.035 -b 2 0.135 +f(a)*f(b) -0.0047 -
c1=(a+b)/2 1.9 0.049568619223 0.0496
SEGUNDA APROXIMACION
x y= +x-2 Signo f(x)a 1.8 -0.035 -c1 1.9 0.050 +f(a)*f(c1) -0.0017 -
𝑒^(−𝑥)𝑒^(−𝑥)
-4 -3 -2 -1 0 1 2 3 4
-2.000
0.000
2.000
4.000
6.000
8.000
10.000
12.000
14.000
16.000
Grafica de y= f(x)= +x-2 y
𝑒^(−𝑥)
𝑒^(−𝑥)
c2=(a+b)/2 1.85 0.0072 + 0.0072
TERCERA APROXIMACION
x y= +x-2 Signo f(x)a 1.8 -0.035 -c2 1.85 0.0072 +f(a)*f(c2) -0.0003 -
c3=(a+b)/2 1.825 -0.0138 - -0.0138
CUARTA APROXIMACION
x y= +x-2 Signo f(x)C3 1.825 -0.014 -C2 1.85 0.0072 +f(c3)*f(c2) -0.0001 -
c4=(a+b)/2 1.8375 -0.0033 - -0.0033
QUINTA APROXIMACION
x y= +x-2 Signo f(x)C3 1.85 0.007 -C4 1.8375 -0.0033 +f(c3)*f(c4) -0.00002 -
c4=(a+b)/2 1.84375 0.00197 + 0.00197
𝑒^(−𝑥)
𝑒^(−𝑥)
𝑒^(−𝑥)
0.04960.0072-0.0138-0.00330.00197
La raiz positiva es : r= 1.8375
-4 -3 -2 -1 0 1 2 3 4
-2.000
0.000
2.000
4.000
6.000
8.000
10.000
12.000
14.000
16.000
Grafica de y= f(x)= +x-2 y𝑒^(−𝑥)𝑒^(−𝑥 )
f(x) = - 0033error = 3.10 ³ o 3 milesimasˉ
y= +x-2 Signo f(x)15.086 +
3.38905609893065 +-0.281718171540955 -
-1 --0.632120558828558 -0.135335283236613 +1.04978706836786 +
-0.0347011117784135
PRIMERA APROXIMACION
x y= +x-2 Signo f(x) F(c1)a 1.8 -0.0347 -b 2 0.1353 +f(a)*f(b) -0.00470 -c1=(b.f(a) + a.f(b))/(fa -fb) 1.8408161 -0.0005 +
sdqSEGUNDA APROXIMACION
x y= +x-2 Signo f(x)a 1.84 -0.001 -c1 2 0.135 +f(a)*f(c1) -0.0002 -
c2=(a+b)/2 -1.84138599 2.4639 + 0.0072
TERCERA APROXIMACION
𝑒^(−𝑥)𝑒^(−𝑥)
-4 -3 -2 -1 0 1 2 3 4
-2.000
0.000
2.000
4.000
6.000
8.000
10.000
12.000
14.000
16.000
Grafica de y= f(x)= +x-2 y
𝑒^(−𝑥)
𝑒^(−𝑥)
x y= +x-2 Signo f(x)a 1.8 -0.035 -c2 1.85 0.0072 +f(a)*f(c2) -0.0003 -
c3=(a+b)/2 1.825 -0.0138 - -0.0138
CUARTA APROXIMACION
x y= +x-2 Signo f(x)C3 1.825 -0.014 -C2 1.85 0.0072 +f(c3)*f(c2) -0.0001 -
c4=(a+b)/2 1.8375 -0.0033 - -0.0033
QUINTA APROXIMACION
x y= +x-2 Signo f(x)C3 1.85 0.007 -C4 1.8375 -0.0033 +f(c3)*f(c4) -0.00002 -
c4=(a+b)/2 1.84375 0.00197 + 0.00197
𝑒^(−𝑥)
𝑒^(−𝑥)
𝑒^(−𝑥)
0.04960.0072-0.0138-0.00330.00197
La raiz positiva es : r= 1.8375f(x) = - 0033error = 3.10 ³ o 3 milesimasˉ
-4 -3 -2 -1 0 1 2 3 4
-2.000
0.000
2.000
4.000
6.000
8.000
10.000
12.000
14.000
16.000
Grafica de y= f(x)= +x-2 y𝑒^(−𝑥)𝑒^(−𝑥 )
x-3 20.08553692319 5-2 7.389056098931 4-1 2.718281828459 30 1 21 0.367879441171 12 0.135335283237 03 0.049787068368 -1
1° Opción e-x+2=0
e-x=2-x
f1(x)=e-x
f2(x)=2-x
Y1= e-x y2= 2-x
-4 -3 -2 -1 0 1 2 3 4
-5
0
5
10
15
20
25
Chart Title
Y1= e-x y2= 2-x
-4 -3 -2 -1 0 1 2 3 4
-5
0
5
10
15
20
25
Chart Title
Y1= e-x y2= 2-x
x
-3 -3 -1.6094379124341
-2 -2 -1.3862943611199
-1 -1 -1.0986122886681
0 0 -0.6931471805599
1 1 0
2 2
3 3
Y1= x y2= -ln(2-x)
-4 -3 -2 -1 0 1 2 3 4
-4
-3
-2
-1
0
1
2
3
4
Chart Title
Y1= x y2= -ln(2-x)
-4 -3 -2 -1 0 1 2 3 4
-4
-3
-2
-1
0
1
2
3
4
Chart Title
Y1= x y2= -ln(2-x)
x
-3 2 17.0855369
-2 2 5.3890561
-1 2 1.71828183
0 2 1
1 2 1.36787944
2 2 2.13533528
3 2 3.04978707
Y1= 2 y2= e-x+x
-4 -3 -2 -1 0 1 2 3 40
2
4
6
8
10
12
14
16
18
Chart Title
Y1= 2 y2= e-x+x
-4 -3 -2 -1 0 1 2 3 40
2
4
6
8
10
12
14
16
18
Chart Title
Y1= 2 y2= e-x+x