mendel cultivated · 2021. 1. 20. · mendel cultivated pea plants and tested some plants he found...

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  • Mendel cultivated pea plants and tested some plants He found that true-breeding plants make offspring retained traits of the Parents every time. Experimental data, Mendel deduced that an organism has two genes ) for each inherited characteristic

  • Site of

    Gregor

    Mendel’s

    experimental

    garden in the

    Czech

    Republic

  • Mendel’s peas • Mendel looked at seven traits

    or characteristics of pea plants:

  • 1. Flower color purple or white

    2. Flower position axial or terminal

    3. Stem length Tall or Dwarf

    4 . Seed shape round or wrinkled

    5. Seed color yellow or green

    6. Pod shape inflated or constricted

    7. Pod color green or yellow

  • are used to show the mating of two parents and the possible offspring they can produce.

  • STEPS:

    TT and t t Cross

    T T t t

  • T t

    T t

    T t

    T t

    T T

    t t

    Genotypes: 100% T t

    Phenotypes: 100% Tall plants

    T T t t

  • T T

    T t

    T t

    t t

    T t

    T t

  • • A heterozygous with a homozygous

    T t t t

    T

    t

    t

    T t

    t t

    You can still use the shortcut!

  • LAW PARENT CROSS OFFSPRING

    DOMINANCE TT x tt tall x short

    100% Tt Tall

    SEGREGATION Tt x Tt tall x tall

    75% tall 25% short

    RrGg x RrGg round & green

    x round & green

    9/16 round seeds & green pods

    INDEPENDENT ASSORTMENT

    3/16 round seeds & yellow pods

    3/16 wrinkled seeds & green pods

    1/16 wrinkled seeds & yellow pods

  • and

    F1 hybrids have an appearance somewhat in between the phenotypes of the two parental varieties.

    Example: snapdragons (flower)

    Rr

    Rr

    Rr Rr

    produces the F1 generation

    All Rr = pink

  • • Two alleles are expressed (multiple alleles) in heterozygous individuals.

    : blood group

    1. type A

    2. type B

    3. type AB =

    4. type O =

    = IAIA or IAi

    = IBIB or IBi

    IAIB

    ii

  • homozygous male Type B (IBIB)

    x

    heterozygous female Type A (IAi)

    IAIB IBi

    IAIB IBi

    1/2 = IAIB

    1/2 = IBi

    IB

    IA i

    IB

  • IAi IBi

    IAi IBi

    1/2 = IAi

    1/2 = IBi

    i

    male Type O (ii) x

    female type AB (IAIB) IA IB

    i

  • 18

    If a boy has a blood type O and his sister has blood type AB

    boy - type O (ii) X girl - type

  • IAIB

    ii

    Parents: genotypes =IAi and IBi phenotypes = A and B

    IB

    Answer:

    IA i

    i