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Finding Torque Description: Find the torque due to a force applied at the origin about different axes of rotation. Hints illustrate the use of various approaches to finding torque. A force of magnitude making an angle with the x axis is applied to a particle located along axis of rotation A, at Cartesian coordinates in the figure. The vector lies in the xy plane, and the four axes of rotation A, B, C, and D all lie perpendicular to the xy plane. A particle is located at a vector position with respect to an axis of rotation (thus points from the axis to the point at which the particle is located). The magnitude of the torque about this axis due to a force acting on the particle is given by , where is the angle between and , is the magnitude of , is the magnitude of , the component of that is perpendicualr to is the moment arm, and is the component of the force that is perpendicular to . Sign convention: You will need to determine the sign by analyzing the direction of the rotation that the torque would tend to produce. Recall that negative torque about an axis corresponds to clockwise rotation. In this problem, you must express the angle in the above equation in terms of , , and/or when entering your answers. Keep in mind that and . Part A What is the torque about axis A due to the force ? Express the torque about axis A at Cartesian coordinates . Hints (1) ANSWER: F F θ (0, 0) F r r τ F τ = rF sin(α) = (moment arm) ⋅ F = rF α r F r r F F r F F r α θ ϕ π π = 180 degrees (π/2) = 90 degrees τ A F (0, 0) MasteringPhysics: Finding Torque http://session.masteringphysics.com/myct/itemView?view=solu... 1 of 3 14-10-25 10:48 AM

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Finding TorqueDescription: Find the torque due to a force applied at the origin about different axes of rotation. Hints illustratethe use of various approaches to finding torque.

A force of magnitude making an angle with the x axis is applied to a particle located along axis of rotation A,at Cartesian coordinates in the figure. The vector lies in the xy plane, and the four axes of rotation A, B, C,and D all lie perpendicular to the xy plane.

A particle is located at a vector position with respect to an axis of rotation (thus points from the axis to the pointat which the particle is located). The magnitude of the torque about this axis due to a force acting on the particleis given by

,

where is the angle between and , is the magnitude of , is the magnitude of , the component of that isperpendicualr to is the moment arm, and is the component of the force that is perpendicular to .

Sign convention: You will need to determine the sign by analyzing the direction of the rotation that the torque wouldtend to produce. Recall that negative torque about an axis corresponds to clockwise rotation.In this problem, you must express the angle in the above equation in terms of , , and/or when entering youranswers. Keep in mind that and .

Part A

What is the torque about axis A due to the force ?

Express the torque about axis A at Cartesian coordinates .

Hints (1)

ANSWER:

F ⃗ F θ

(0, 0) F ⃗

r ⃗ r ⃗ τ F ⃗

τ = rF sin(α) = (moment arm) ⋅ F = rF⊥

α r ⃗ F ⃗ r r ⃗ F F ⃗ r ⃗ F ⃗ F⊥ r ⃗

α θ ϕ ππ = 180 degrees (π/2) = 90 degrees

τA F ⃗

(0, 0)

MasteringPhysics: Finding Torque http://session.masteringphysics.com/myct/itemView?view=solu...

1 of 3 14-10-25 10:48 AM

marcdemontigny
Typewritten Text
Quiz 6 - 30 octobre 2014
marcdemontigny
Rectangle

Part B

What is the torque about axis B due to the force ? (B is the point at Cartesian coordinates , located a

distance from the origin along the y axis.)

Express the torque about axis B in terms of , , , , and/or other given coordinate data.

Hints (2)

ANSWER:

Part C

What is the torque about axis C due to ? (C is the point at Cartesian coordinates , a distance along

the x axis.)

Express the torque about axis C in terms of , , , , and/or other given coordinate data.

Hints (2)

ANSWER:

Part D

What is the torque about axis D due to ? (D is the point located at a distance from the origin and making

an angle with the x axis.)

Express the torque about axis D in terms of , , , , and/or other given coordinate data.

=

Also accepted:

τA

τB F ⃗ (0, b)b

F θ ϕ π

=

Also accepted:

τB

τC F ⃗ (c, 0) c

F θ ϕ π

= τC

τD F ⃗ d

ϕ

F θ ϕ π

MasteringPhysics: Finding Torque http://session.masteringphysics.com/myct/itemView?view=solu...

2 of 3 14-10-25 10:48 AM

ANSWER:

You could have found by using any of the three equations listed at the top of the page,

,

and making the following associations:

and

.

=

Also accepted:

τD

τD

τ = rF sin(α) = (moment arm) ⋅ F = rF⊥

r = d sin(α) = sin(π − ϕ + θ) = sin(ϕ − θ)moment arm = = d sin(ϕ − θ)r⊥

= F sin(ϕ − θ)F⊥

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