mass reactants = mass products
DESCRIPTION
Mass Reactants = Mass Products. Law of Conservation of Mass: the mass of the reactants must equal the mass of the products. Law of Definite Proportions : a compound ( like H 2 O ) is always composed of the same elements in the same proportion by mass (no matter what the sample size). - PowerPoint PPT PresentationTRANSCRIPT
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Mass Reactants = Mass Products
Law of Conservation of Mass: the mass of the reactants must equal the mass of the
products.
![Page 2: Mass Reactants = Mass Products](https://reader036.vdocuments.mx/reader036/viewer/2022082612/56813b66550346895da46669/html5/thumbnails/2.jpg)
Law of Definite Proportions: a compound (like H2O) is always composed of the same elements in the same proportion by mass (no matter what the sample size).
![Page 3: Mass Reactants = Mass Products](https://reader036.vdocuments.mx/reader036/viewer/2022082612/56813b66550346895da46669/html5/thumbnails/3.jpg)
% by Mass = mass of element (g) x 100 mass of compound (g)
Example: 78.0g of Unknown Compound 12.4g of Hydrogen (H) ? = % by mass of H
% by Mass H = mass of hydrogen (g) x 100 mass of unk compound (g)
= 12.4 g H x 10078.0g Unk Compound
= 15.9%
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Practice:A 24.0g sample of unknown compound contains 6.5 g of hydrogen. What is the percent by mass of hydrogen in the compound?
Start by writing down your information.
![Page 5: Mass Reactants = Mass Products](https://reader036.vdocuments.mx/reader036/viewer/2022082612/56813b66550346895da46669/html5/thumbnails/5.jpg)
Practice:A 24.0g sample of unknown compound contains 6.5 g of hydrogen. What is the percent by mass of hydrogen in the compound?
24.0 g of Unknown Compound 6.5 g of Hydrogen (H) ? = % by mass of H
Now, set up the equation & plug in the numbers.
![Page 6: Mass Reactants = Mass Products](https://reader036.vdocuments.mx/reader036/viewer/2022082612/56813b66550346895da46669/html5/thumbnails/6.jpg)
Practice:A 24.0g sample of unknown compound contains 6.5 g of hydrogen. What is the percent by mass of hydrogen in the compound?
24.0 g of Unknown Compound 6.5 g of Hydrogen (H) ? = % by mass of H
% by Mass H = mass of hydrogen (g) x 100 mass of unk compound (g)
![Page 7: Mass Reactants = Mass Products](https://reader036.vdocuments.mx/reader036/viewer/2022082612/56813b66550346895da46669/html5/thumbnails/7.jpg)
Practice:A 24.0g sample of unknown compound contains 6.5 g of hydrogen. What is the percent by mass of hydrogen in the compound?
24.0 g of Unknown Compound 6.5 g of Hydrogen (H) ? = % by mass of H
% by Mass H = 6.5 g Hydrogen x 100 24.0 g Unk Compound
![Page 8: Mass Reactants = Mass Products](https://reader036.vdocuments.mx/reader036/viewer/2022082612/56813b66550346895da46669/html5/thumbnails/8.jpg)
Practice:A 24.0g sample of unknown compound contains 6.5 g of hydrogen. What is the percent by mass of hydrogen in the compound?
24.0 g of Unknown Compound 6.5 g of Hydrogen (H) ? = % by mass of H
% by Mass H = 6.5 g Hydrogen x 100 24.0 g Unk Compound= 27.1% by mass of Hydrogen
![Page 9: Mass Reactants = Mass Products](https://reader036.vdocuments.mx/reader036/viewer/2022082612/56813b66550346895da46669/html5/thumbnails/9.jpg)
Law of Multiple Proportions: when different compounds are formed by a combination of the same elements, different masses of one element combine with the same relative mass of the element in a ratio of small whole numbers (can use colons or fractions).
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Law of Multiple Proportions