MASS BALANCE FOR HYDRATED LIME (Ca(OH)2)

Reaction: 2Ca(OH)2 + 2Cl2 =Ca(ClO)2 + CaCl2 + 2H2O

Molecular mass of Ca(OH)2 = 74Molecular mass of Cl2 = 71Molecular mass of Ca(ClO)2 = 143Molecular mass of CaCl2 = 111Molecular mass of H2O = 18According to law of mass conservation: Total mass of reactants = Total mass of products.(2 * 74) + (2 * 71) =143 + 111 + (2 * 18) 148 + 142 = 143 + 111 + 36 290 = 290

Purity of Ca(OH)2 = 90% w/w

1) For 290 kg of SBP required Hydrated Lime = 148*(100/90) = 164.5 KgFor 1 kg of SBP required hydrated Lime = 164.5/290 = 0.567 KgFor 1000 kg of SBP required Hydrated Lime = .567 * 1000 = 567 Kg2) The final SBP contains 27% free Ca(OH)2 which is 153 Kg.Therefore total Ca(OH)2 used = 567+153 = 720 Kg Efficiency of Ca(OH)2 per MT of SBP = 720/1000 = .72 MT for 1 MT of SBP

LOSS OF Ca(OH)2 DURING PROCESSCa(OH)2 loss during shifting by truck = .004 MTSludge generation from SBP plant at production level = 45 MT/dayClarifier sludge = 30 MT/month (including moisture 60%)Phase - 3pit = 3 MT/month (including moisture 60%)Total sludge produced = 33 MT/month (including moisture 60%)Total sludge produced = 13.2 MT/month (without moisture)Sludge SBP generated per MT = 9.8 kgTotal loss = (.004 + .0098) MT = .0138 MTEfficiency of Ca(OH)2 per MT of SBP = (.72+.0138) = .7338

Other losses The acceptability limit of Hydrated Lime purity is 88%, which results0.75 MT/MT Efficiency of Hydrated Lime.