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    Dissemination of information for training Brussels, 2-3 April 2009 1

    EUROCODE 6Background and applications

    EUROCODE 6Design of masonry structures

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    Dissemination of information for training Brussels, 2-3 April 2009 2

    EUROCODE 6Background and applications

    EUROCODE 6Combined loading

    Poul ChristiansenDanish Technological Institute

    [email protected]

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    Dissemination of information for training Brussels, 2-3 April 2009 3

    EUROCODE 6Background and applications

    Combined loading

    Walls subjected to vertical

    and lateral load

    Walls supported by2 3 4 edges and withopenings

    Edges restrained or simplysupported

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    EUROCODE 6Background and applications

    Distribution of wind load between outer and inner leaf

    Either:1. A distribution between the outer andinner leaf.

    or

    2.The total wind load applied on theinner leaf, when (5.11) is used.

    If 1. Either:A. According to the stiffness

    B. According to the capacityWcap = Wcap,1 + Wcap,2 (6.3.1 (6))

    In this example (5.11) is used

    3 3

    2

    3

    1tefef ttkt +=

    21

    1

    1,1, )()(

    )(

    EIEI

    EIWW

    EdEd +=

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    EUROCODE 6Background and applications

    Horizontal and vertical load

    Yield line theory is relevant for openings, 3-4 sided walls.- method is relevant for 2. order effects and wallssupported in top and buttom

    The link between the methods is the equivalence of MEd.Thus an equivalent windload is introduced: Weqv ( Wed) (Annex I)

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    EUROCODE 6Background and applications

    Determining weqv

    The apparent flexural strength: fxd1,app = fxd1 + (6.16)The moment of resistance: MRd = (1/6)(teff)

    2 x fxd1,appBased on the yield line theory: Wcap is calculated

    The actual moment due to (Wed): MEd = (WEd/ Wcap) x MRdLink: (1/8) x h2 x Weqv= MEd = (WEd/ Wcap) x MRdFinally: Weqv = (8/h

    2) x (WEd/ Wcap) x MRd

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    Dissemination of information for training Brussels, 2-3 April 2009 7

    EUROCODE 6Background and applications

    Determining the effective thickness

    The thickness can be formally altered:

    When formula 5.11 is used:

    When table 5.1 is used:

    When using both formulas

    the expression will be:

    =eft

    3 32

    31tefef ttkt +=

    3 32t

    31tefef )t(tkt +=

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    EUROCODE 6Background and applications

    Determining the effective height

    For this example the effectiveheight will normally be setequal to the geometricallyheight. i.e.:

    heff = h

    In Eurocode 1996-1-1 thereare rules for determining

    3 and 4, i.e. the reductionfactor for 3 and 4 sided sup-ported walls (without ope-nings). E.g.:

    (5.8)

    To implement openings follo-wing procedure can be used.

    +

    =24

    l

    h1

    1

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    EUROCODE 6Background and applications

    Determining the effective height

    The effective height is determined in sections

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    EUROCODE 6Background and applications

    Determining of the eccentricity

    The main issue when regarding the eccentricity at the top (and the bottom) is thestiffness of the slab in the moment of fracture. The eccentricity can in practice bet/2 in favour of the construction or t/2 in disfavour of the construction. Theimplication for the load capacity is large.

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    Dissemination of information for training Brussels, 2-3 April 2009 11

    EUROCODE 6Background and applications

    Determining of the eccentricity

    The Danish approach is to define an interval of eccentricity producing an intervalfor the compression stress. For stiff slabs, foundation, etc the interval is thebearing length. For slack slabs it is half the bearing length.

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    EUROCODE 6Background and applications

    Determination of the compression zone

    Determination of thecompression line/

    zone after determi-ning heff, teff, Weqv,etc is done by theusually statically

    methods.Wide of thecompression zoneis determined by fd

    The shape of thecompression zoneis an affinity to themoment

    The slack slabs with

    an eccentricity indisfavour to theconstruction gives adecreased load

    capacity.Here an area wherethe neccessity for fxd1is actual

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    EUROCODE 6Background and applications

    Determining the load capacity

    To cover the spectraof eccentricities flis introduced in6.3.1 (4) (ii).

    Here the extendedNavier expression isused to cover thearea of small Nand large M

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    EUROCODE 6Background and applications

    Final comments

    Thank you for listening

    Any later comments, etc to the papers:[email protected]

    Computer program on the Internet fordesigning according to EN1996-1-1:

    www.ec6design.com