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 Review of Functions Mathematics 53 Institute of Mathematics (UP Diliman) Institute of Mathematics (UP Diliman)  Review of Functions  Ma the ma t ic s 53 1 / 43

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  • Review of Functions

    Mathematics 53

    Institute of Mathematics (UP Diliman)

    Institute of Mathematics (UP Diliman) Review of Functions Mathematics 53 1 / 43

  • For today

    1 Functions

    2 Basic Types of Functions

    3 Constructing a Table of Signs

    4 Operations on Functions

    5 Piecewise-defined Functions

    6 Functions as Mathematical Models

    Institute of Mathematics (UP Diliman) Review of Functions Mathematics 53 2 / 43

  • Functions

    DefinitionLet X and Y be nonempty sets. A function f from X to Y, denoted f : X Y, isa rule that assigns to each element of X a unique element of Y.

    X: domain of f , denoted dom fY: codomain of fThe set of all elements of Y that are assigned to some element of X is therange of f , denoted ran f .

    Institute of Mathematics (UP Diliman) Review of Functions Mathematics 53 4 / 43

  • Real-valued functions of a single variable

    Real-valued functions of a single variable:Codomain: R

    Math 53 deals with functions whose domain and range are subsets of R.

    If the domain is not explicitly specified:Domain: dom f = {x R | f (x) is a real number}

    Examples:1 f (x) = x2 dom f = R

    2 f (x) =x2 2x 3

    x + 1dom f = R \ {1}

    Institute of Mathematics (UP Diliman) Review of Functions Mathematics 53 5 / 43

  • Basic types of functions

    Polynomial Functions - functions of the form

    f (x) = anxn + an1xn1 + + a1x + a0

    where n W, an, an1, ..., a0 are real numbers, with an 6= 0.

    leading coefficient: andegree of f : ndom f = R polynomial functionsGraphs of polynomial functions: Unit 3

    Institute of Mathematics (UP Diliman) Review of Functions Mathematics 53 7 / 43

  • Some Examples of Polynomial Functions

    1. Constant Functions - functions of the form f (x) = c, where c is a real numberdom f = R; ran f = {c}graph: horizontal line intersecting the y-axis at y = c

    2. Linear Functions - functions of the form

    f (x) = mx + b

    with m 6= 0dom f = R; ran f = Rgraph: m is slope; y-intercept is bIf m > 0: line slants to the rightIf m < 0: line slants to the left

    Institute of Mathematics (UP Diliman) Review of Functions Mathematics 53 8 / 43

  • Some Examples of Polynomial Functions

    3. Quadratic Functions - functions of the form

    f (x) = ax2 + bx + c

    with a 6= 0dom f = R

    graph: parabola with vertex at( b2a ,

    4acb24a

    )If a > 0: parabola opens upward, ran f =

    [4acb2

    4a ,+)

    If a < 0: parabola opens downward, ran f =(, 4acb24a

    ]Extreme function values of a quadratic function:

    a > 0: f has a minimum function valuea < 0: f has a maximum function value

    The extreme function value of f occurs at x = b2a and the extreme functionvalue of f is f

    ( b2a

    )= 4acb

    2

    4a

    Institute of Mathematics (UP Diliman) Review of Functions Mathematics 53 9 / 43

  • Basic types of functions

    Rational Functions - functions of the form

    f (x) =p(x)q(x)

    ,

    where p and q are polynomial functions, and q is not the constant zero function.

    Domain: {x R | q(x) 6= 0}Graphs of general rational functions: Unit 3

    Institute of Mathematics (UP Diliman) Review of Functions Mathematics 53 10 / 43

  • Graphs of Functions

    Example

    The graph of f (x) =x2 2x 3

    x + 1:

    f (x) =x2 2x 3

    x + 1=

    (x 3)(x + 1)(x + 1)

    = x 3 if x 6= 1

    Domain: R \ {1}Range: R \ {4}Zero: x = 3Positive: (3,+)Negative: (,1) (1, 3)

    3 2 1 1 2 3 4

    5

    4

    3

    2

    1

    1

    0

    Institute of Mathematics (UP Diliman) Review of Functions Mathematics 53 11 / 43

  • Basic types of functions

    Functions involving rational exponents or radicals - functions of the form

    f (x) = n

    x = x1/n

    n is odd: dom f = Rn is even: dom f = [0, )

    Institute of Mathematics (UP Diliman) Review of Functions Mathematics 53 12 / 43

  • Basic types of functions

    ExampleSquare root function: f (x) =

    x

    y =

    x = y2 = x, y 0

    1 2 3 4

    2

    1

    1

    2

    0

    The graph of x = y2

    1 2 3 4

    2

    1

    1

    2

    0

    The graph of y =

    x

    The graph of f (x) =

    x is the upper branch of the parabola x = y2

    Institute of Mathematics (UP Diliman) Review of Functions Mathematics 53 13 / 43

  • Other Functions involving Radicals

    Example

    Sketch the graph of g(x) =

    2 x.

    y =

    2 xy2 = 2 x, y 0x = 2 y2, y 0

    The graph of g is the lower branch of the parabola x = 2 y2.

    Institute of Mathematics (UP Diliman) Review of Functions Mathematics 53 14 / 43

  • Other Functions involving Radicals

    Example

    Sketch the graph of g(x) =

    2 x.

    2 1 1 2

    2

    1

    1

    2

    0

    Institute of Mathematics (UP Diliman) Review of Functions Mathematics 53 15 / 43

  • Other Functions involving Radicals

    Example

    Graph h(x) =

    4 x2.

    The graph of h is the upper half of the graph of x2 + y2 = 4.

    2 1 1 2

    2

    1

    1

    2

    Institute of Mathematics (UP Diliman) Review of Functions Mathematics 53 16 / 43

  • Basic types of functions

    Trigonometric/Circular Functions

    sine, cosine, tangent, cotangent, secant and cosecant functions

    In Math 53, the trigonometric functions are viewed as functions on the set ofreal numbers.

    Institute of Mathematics (UP Diliman) Review of Functions Mathematics 53 17 / 43

  • Constructing a table of signs

    A table of signs shows when a given mathematical expression is positive, zero ornegative.

    Two Methods:

    1 Interval Method

    2 Test Value Method

    In both cases, one must determine the numbers where the given mathematicalexpression is zero or undefined.

    Institute of Mathematics (UP Diliman) Review of Functions Mathematics 53 19 / 43

  • Constructing a table of signs

    Example

    Determine the intervals where the the graph of f (x) =2x2 x3

    2x2 3x + 1 lies abovethe x-axis.

    We want to determine the intervals for which

    2x2 x32x2 3x + 1 > 0

    Institute of Mathematics (UP Diliman) Review of Functions Mathematics 53 20 / 43

  • Constructing a table of signsInterval Method: rewrite the expression as a product of factors whose table ofsigns are easily determined.

    2x2 x32x2 3x + 1 =

    x2(2 x)(2x 1)(x 1)

    Zero at: x = 0, 2, Undefined at: x = 12 , 1

    (, 0)(

    0, 12) (

    12 , 1)

    (1, 2) (2,+)

    x2 + + + + +2x 1 + + +x 1 + +2 x + + + +

    x2(2 x)(2x 1)(x 1) + + +

    The graph of f lies above the x-axis in the intervals (, 0) (

    0, 12) (1, 2).

    Institute of Mathematics (UP Diliman) Review of Functions Mathematics 53 21 / 43

  • Constructing a table of signs

    Test Value Method: test a value in the specified interval

    (, 0)(

    0, 12) (

    12 , 1)

    (1, 2) (2,+)

    x2(2 x)(2x 1)(x 1) + + +

    Sample point in (, 0): x = 1 (1)2(3)

    (3)(2)

    Sample point in(

    0, 12)

    :(+)(+)

    ()()We get the same result:

    The graph of f lies above the x-axis in the intervals (, 0) (

    0, 12) (1, 2).

    Institute of Mathematics (UP Diliman) Review of Functions Mathematics 53 22 / 43

  • Constructing a table of signs

    Example

    Find the domain of f (x) =5x

    x2 1 .

    Domain: x R such that 5xx2 1 0

    Zero at: x = 0, Undefined at: x = 1, 1

    (,1) (1, 0) (0, 1) (1,+)5x

    x2 1 + +

    Therefore,dom f = (,1) [0, 1)

    Institute of Mathematics (UP Diliman) Review of Functions Mathematics 53 23 / 43

  • Operations on Functions

    Definition (Operations on Functions)Let f and g be functions, c R.

    1 Addition: ( f + g)(x) = f (x) + g(x); dom( f + g) = dom f dom g2 Subtraction: ( f g)(x) = f (x) g(x); dom( f g) = dom f dom g3 Multiplication: ( f g)(x) = f (x)g(x); dom( f g) = dom f dom g

    4 Division:(

    fg

    )(x) =

    f (x)g(x)

    ;

    dom(

    fg

    )= (dom f dom g) \ {x dom g | g(x) = 0}

    5 Composition: ( f g)(x) = f (g(x));dom( f g) = {x dom g | g(x) dom f }

    6 Scalar Multiplication: c f (x) = c ( f (x)); dom c f = dom f

    Institute of Mathematics (UP Diliman) Review of Functions Mathematics 53 25 / 43

  • Operations on Functions

    Example

    Express the function F(x) = sin2 (3x 1) as a composition of three functionslisted among the basic types of functions.

    Let

    f (x) = x2

    g(x) = sin xh(x) = 3x 1

    ThenF(x) = ( f g h) (x)

    Institute of Mathematics (UP Diliman) Review of Functions Mathematics 53 26 / 43

  • Operations on Functions

    Example

    Let f (x) = x2 and g(x) = x + h, where h is a nonzero constant. Find1h[( f g) (x) f (x)].

    1h[( f g) (x) f (x)] = 1

    h[ f (g(x)) f (x)]

    =f (x + h) f (x)

    h

    =(x + h)2 x2

    h

    =(x2 + 2xh + h2) x2

    h

    =2xh + h2

    h= 2x + h

    Institute of Mathematics (UP Diliman) Review of Functions Mathematics 53 27 / 43

  • Piecewise-defined functions

    Piecewise-defined functions are functions that are defined by more than oneexpression. Such functions can be written in the form

    f (x) =

    f1(x), if x X1f2(x), if x X2

    ... if...

    fn(x), if x Xn

    where X1, ..., Xn R with Xi Xj = for all i 6= j.

    Institute of Mathematics (UP Diliman) Review of Functions Mathematics 53 29 / 43

  • The Absolute Value Function

    Absolute Value Function - denoted by |x| and defined by

    |x| =

    x2 ={

    x, x 0x, x < 0

    Institute of Mathematics (UP Diliman) Review of Functions Mathematics 53 30 / 43

  • The Absolute Value Function

    The graph of f (x) = |x|

    3 2 1 1 2 3

    1

    2

    3

    0

    Institute of Mathematics (UP Diliman) Review of Functions Mathematics 53 31 / 43

  • The Absolute Value Function

    ExampleWrite f (x) = |2x 3|+ x as a piecewise function.

    Recall that |x| ={

    x if x 0x if x < 0

    .

    f (x) = |2x 3|+ x =

    (2x 3) + x, if 2x 3 0(2x 3) + x, if 2x 3 < 0=

    3x 3, if x 32

    x + 3, if x < 32

    Institute of Mathematics (UP Diliman) Review of Functions Mathematics 53 32 / 43

  • The Greatest Integer Function

    Greatest Integer Function (GIF) [[x]]: greatest integer less than or equal to x

    Example1 [[2.4]] = 22 [[2]] = 2

    3 [[2.1]] = 34 [[]] = 4

    Institute of Mathematics (UP Diliman) Review of Functions Mathematics 53 33 / 43

  • The Greatest Integer Function

    As a piecewise function:

    [[x]] =

    ......

    1, 1 x < 00, 0 x < 11, 1 x < 22, 2 x < 3...

    ...

    In general,

    [[x]] = n, for n x < n + 1 where n Z

    Institute of Mathematics (UP Diliman) Review of Functions Mathematics 53 34 / 43

  • The Greatest Integer Function

    The graph of f (x) = [[x]]

    4 3 2 1 1 2 3 4

    4

    3

    2

    1

    1

    2

    3

    4

    0

    Institute of Mathematics (UP Diliman) Review of Functions Mathematics 53 35 / 43

  • The Greatest Integer Function

    ExampleWrite f (x) = [[3x]] as a piecewise function.

    f (x) = [[3x]] = n for n 3x < n + 1n3 x < n + 1

    3

    f (x) = [[3x]] =

    ......

    0, 0 x < 131, 13 x