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  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 1 -

    PHN I. MUI.1. L do chn ti.

    Hin nay, vic i mi ni dung v phng php dy hc l mt trong nhng vn

    c rt nhiu ngi quan tm. Mt nhim vcbn ca dy hc nh trng l m

    bo cho hc sinh nm vng c kin thc, lm cho hc sinh hiu ng bn cht ca

    mt vn . iu ny i hi ngi gio vin cn phi c mt phng php sphm

    vng chc, kin thc chuyn mn cao. Bn cnh i hi hc sinh phi tch cc hn

    trong hc tp tmnh c thchim ly tri thc khoa hc.in ha hc l phn ni dung kin thc rt quan trng trong ni dung chng trnh

    ha hc phthng hin nay. c manh nha lp 9 bc trung hc cs, v trnh by

    rt rng bc trung hc phthng. Chyu nm phn i cng vkim loi ca lp

    12. y l phn l thuyt csrt quan trng nghin cu tm hiu tnh cht ca kim

    loi v ion kim loi trong dung dch.

    V vy, trong qu trnh truyn t cn phi pht huy tnh tch cc, nng lc tduy,

    sng to ca hc sinh.in ha hc c nhng ng dng g? Chng tun theo qui lut nhthno? c bit

    vic dy v hc chng chng trnh trung hc ph thng ra sao? L mt gio vin

    tng lai bn cn chun bnhng g? Cch trnh by ca bn i vi hc sinh ra sao?.

    Vi nhng l do cbn , ti quyt nh chn ti nghin cu: Ging dy mt

    sni dung in ha hc trng trung hc phthng.

    I.2. Mc ch nghin cu.

    Tm hiu ni dung in ha hc v phng php ging dy ni dung trong chng

    trnh trung hc phthng.

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 2 -

    I.3. Nhim vca ti.

    - Nghin cu nhng csxy dng v nhng yu tnh hng n hot ng hahc ca kim loi theo in ha hc

    - Tm hiu ni dung, cu trc chng trnh in ha hc trng trung hc ph

    thng.

    - Thit kmt sgio n ging dy phn in ha hc trng trung hc phthng.

    - Tm hiu thc trng.

    I.4.Khch th, i tng v phm vi nghin cu.

    - Khch th. Cc ti liu c lin quan.

    - i tng. Gio vin hc sinh trung hc phthng

    - Phm vi nghin cu: Trng THPT, Gio vin, Hc sinh, V cc ti liu c lin

    quan.

    I.5. Phng php nghin cu.

    - Nghin cu l thuyt.

    - Nghin cu thc tin.

    - Thc tp ging dy.

    - Thng k ton hc

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 3 -

    PHN II. NI DUNG

    CHNG I. MT SCSI.1. Csl lun ca shnh thnh khi nim in Ha Hc.

    I.1.1. Tm quan trng ca vic hnh thnh khi nim in ha hc trng

    THPT.

    Trong qu trnh khi qut ha nhng kin thc vcc cht ring bit v vnhng bin

    ha ca chng, nhng khi nim c bn v ha hc dn dn xut hin. Nhng khi

    nim trthnh im ta, l vkh cho vic tip tc nghin cu cc nguyn tv cc

    hp cht ha hc. Lc , nhng khi nim cbn dn dn c cthha thm, o

    su thm v ngy cng phn nh ng ng hn cc mt phc tp ca vn .

    in ha hc l phn kin thc csquan trng c c u chng i Cng

    Kim Loi sch gio khoa ha hc 12. Lm tin cs, v l l thuyt cho cho

    vic tm hiu tnh cht ha hc ca kim loi, ion kim loi trong dung dch.

    V thtrong vic ging dy ha hc, ngi gio vin cn ch rn luyn cho hc sinh

    thi quen nhn thc cc skin thc nghim vphn ng ha hc di nh sng ca

    ca cc l thuyt khc nhau, trong c l thuyt in ha hc.

    Vic vn dng l thuyt in ha hc trong dy hc ha hc khng nhng c ngha

    ht sc to ln i vi vic nghin cu tnh cht ha hc ca cc cht, hp cht m cn

    ci vi vic hthng chng cng vi nhng l thuyt ha hc khc.

    I.1.2. Ni dung nghin cu in Ha Hc chng trnh trung hc phthng

    Mun hnh thnh c hiu qucho hc sinh mt khi nim hoc hthng khi nim no

    , ng

    i gio vin c

    n xt k

    nhi

    u m

    t c

    a khi ni

    m tr

    c khi ti

    n hnh gi

    ng d

    y.

    Mun xt vn ny cn phi xut pht tmc tiu o to ca cp hc v nhim v

    c tr dc ca mn hc tc l phi da chc chn vo ni dung chng trnh ca b

    mn . Ni chung vic nghin cu shnh thnh ca ni dung kin thc in ha hc

    cn tri qua cc bc sau.

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 4 -

    - Xt vtr v tm quan trng ca ni dung in ha hc trong chng trnh bmn.

    - Xt cu trc ca ni dung in ha hc: in ha hc bao gm nhng ni dung no

    m ta phi hnh thnh cho hc sinh.Cn da vo trnh pht trin chung ca hc sinh m xt kkhi lng, mc nng

    hay su ca nhng kin thc . Nhvy y c hai bc phi thc hin.

    + Xt cu trc ca ni dung in ha hc theo quan im hin i ca khoa hc

    (da vo chng trnh ha hc bc i hc)

    + La chn kin thc v knng, kxo cn truyn thcho hc sinh phthng cn

    cvo trnh pht trin ca h.

    - Phn tch shnh thnh ni dung in ha hc trong sut chng trnh cTHCS v

    THPT.

    Trong tng giai on, ni dung kin thc in ha hc c hnh thnh v pht trin ra

    sao, c nhng yu cu g vckin thc ln knng kxo. y cn phi xem xt

    tng kha cnh ca khi nim, tc l nhng kin thc cbn l thnh phn cu trc ca

    ni dung in ha hc c hnh thnh v pht trin nhthno?

    - Tm ra nhng bin php s phm hiu nghim nht thch hp vi tng giai on,

    nhm thc hin c yu cu ring ca tng giai on cng nhyu cu chung v

    vic hnh thnh ni dung in ha hc

    I.2. Csl thuyt ca khi nim in ha hc.

    I.2.1. Phn ng oxi ha - kh.

    Phn ng oxi ha - kh l loi phn ng trong c s chuyn electron hon ton

    (hoc mt phn) tnguyn t(hay ion) ny sang nguyn t(hay ion) khc. Kt qul

    trong phn ng c sthay i soxi ha ca mt hoc vi nguyn t.

    - Cht oxi ha l cht cha nguyn tnhn electron.- Cht khl cht cha nguyn tcho electron- Qu trnh cho electron ca cht khc gi l soxi ha.- Qu trnh nhn electron ca cht oxi ha c gi l skh.

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 5 -

    V d: ++++ ++ 2432 22 FeSnFeSn

    [ ]Kh

    SneSn ++ 42 2 (soxi ha) ;

    [ ]

    3 21Fe e Fe

    Ox

    + ++ (skh)

    I.2.2. Cp oxi ha kh.

    Hai ion +3Fe v +2Fe c gi l mt cp oxi ha kh lin hp, trong +3Fe l dng

    oxi ha , +2Fe l dng khlin hp ca +3Fe .

    Tng qut:

    - Dng oxi ha nhn electron dng khlin hp.- Dng khcho electron dng oxi ha khlin hp.

    Vi mt phn ng oxi ha khbt k, ta lun c:

    Kh (2) Ox(2) + ne soxi ha

    Ox(1) + ne Kh(1) skh

    Ox(1) + Kh(2) Kh(1) + Ox(2)

    Ta nhn thy tnh oxi ha ca dng oxi ha cp thnht Ox(1) mnh hn tnh oxi ha

    ca dng oxi ha cp oxi ha thhai Ox(2). nh gi mnh ca mt cp oxi ha

    khlin hp, ngi ta sdng i lng thin cc.

    I.2.3. Thin cc Phn loi in cc Cch xc nh.

    I.2.3.1.Thin cc

    Mt thanh kim loi nhng vo dung dch mui ca n to thnh mt in cc

    V d: Thanh Zn nhng vo dung dch ZnSO4 to thnh in cc Zn.

    Gia kim loi v dung dch bao quanh n pht sinh mt hiu sin thgi l thin

    cc

    ne

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 6 -

    I.2.3.2. Phn loi in cc

    1.in cc kim loi.

    Khi nhng mt thanh kim loi M vo nc th do tc dng ca cc phn tc cc canc, cc ion kim loi nM + btch ra khi bmt kim loi to thnh cc ion kim loi

    hirat, cn cc electron li trong thanh kim loai. Kt qul thanh kim loi tch in

    m, cn dung dch tch in dng, to nn cn bng ng sau:

    . ( ) ( )nM aq ne trong thanh kimloai M tt aq+ + +

    2. in cc oxi ha kh.

    in cc oxi ha kh l mt in cc gm mt kim loi trnhng trong dung dch

    cha mt cp oxi ha kh. Kim loi trl kim loi m ion ca n khng chuyn vo

    trong dung dch, thng dng platin hoc vng.

    V d:Platin nhng trong dung dch cha cp oxi ha kh3

    2Fe

    Fe+

    + (c thdng dung

    dch FeCl3v FeCl2).. Kt qul tn ti cn bng ng sau:

    3 2Fe e Fe+ ++

    Vy ranh gii gia kim loi v dung dch tn ti mt lp in tch kp v sinh ra mt

    hiu sin thtng tnhin cc kim loi.

    Thin cc ca in cc loi ny phthuc vo bn cht ca cp oxi ha kh, vo

    tsnng ca dng oxi ha v dng khv vo nhit .

    3. in cc hiro chun.

    Gi trtuyt i ca hiu sin thsinh ra gia kim loi lm in cc v dung dch

    in cc khng thxc nh c mt cch trc tip, nn phi quy c ly mt in

    cc no lm chun v gn cho n mt gi trhiu sin thso snh vi cc

    in cc khc.

    in cc c chn lm chun l in cc hiro chun. y l loi in cc oxi ha

    khgm dy platin c khnng hp phtt hiro (dng kh), c nhng trong dung

    dch H2SO4l dung dch cha dng oxi ha H3O+

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 7 -

    Hnh I.1. Cu to in cc hiddro chun.

    Khi tn ti cn bng sau: 3 2( ) 22 2kH O e H H O+ + +

    in cc hiro chun phi c iu kin chun sau:

    - p sut (chnh xc hn l hot p) ca kh hiro bng 1atm.- Nng (chnh xc hn l hot ) ca H3O+bng 1mol/l- Thin cc ca in cc hiro tiu chun nhit bt k c quy c bng

    0,00V v c k hiu nhsau: 0 32

    0,00H O VH+

    =

    Gi trny c gi l thin cc hiro chun hoc thoxi ha khchun hoc th

    khchun ca cp oxi ha kh 32

    H OH

    +

    .

    I.2.3.3. Cch xc nh thin cc chun ca mt cp oxi ha kh

    so snh c thin cc ca cc loi in cc khc nhau cn phi c nhng quyc thng nht cho cc loi in cc. Nhng quy c ny nhsau:

    - iu kin chun ca cc in cc:Mt in cc c coi l iu kin chun khi

    nng (chnh xc hn l hot ) ca cu ttham gia phn ng in cc bng 1mol/l,

    nu l cht kh th p sut (chnh xc hn l hot p) ring phn ca n bng 1atm.

    - Chiu ca phn ng in cc l chiu ca qu trnh kh.

    ox + ne kh

    y: ox dng oxi ha; kh dng kh.

    - mt nhit xc nh .

    xc nh thin cc chun ca mt in cc no , ngi ta thit lp mt pin

    gm in cc chun cn xc nh thin cc v in cc hiro tiu chun ri o hiu

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 8 -

    sin th ln nht gia hai in cc. Hiu sin th ln nht ny l thin cc

    chun ca in cc xc nh hay cn gi l thkhchun ca cp oxi ha khxc

    nh (v thca in cc hiro chun c quy c bng 0,00V). Thkhchun ca

    cp oxi ha khnhit xc nh c k hiu l ( )0 ox kh

    Thkhchun o c sc gi trdng nu in cc cn o cao hn thin cc

    hiro chun, ngha l in cc cn o thin cc l in cc dng (catot) ca pin v

    ngc li n c gi trm.

    I.2.4. Thin cc chun ca kim loi.

    L thca bn phn ng khi tt ccc thnh phn ca ngn in cc u iu kin

    tiu chun. Ghp in cc kim loi tiu chun vi in cc hydro tiu chun thnh mt

    nguyn t Galvani, o sut in ng ca nguyn t v xc nh chiu ca dng

    in.

    V d:o thin cc tiu chun ca in cc Zn. Lp pin gm in cc km tiu

    chun v in cc hyro tiu chun ([H+] = [Zn2+] = 1M)

    (-) Zn Zn2+H+H2(Pt) (+)

    Thc nghim cho thy phi kim hot ng th in cc hyro tiu chun l cc dngv in cc km tiu chun l cc m. Sut in ng ca pin: E0= 0,763V

    E0pin = 02H+/ H2-

    0Zn2+/ Zn= 0,763V

    Vy 0 Zn2+/ Zn= 02H+/ H2- E

    0pin = 0 0,763 = -0,763V

    Bng cch tng tngi ta xc nh c thin cc tiu chun ca cc in cc

    kim loi v cc cp oxi ha khri xp thnh bng thin cc tiu chun ca cc cp

    oxi ha kh( Xem phlc 1)

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 9 -

    I.2.5. Cc yu tnh hng n thin cc.

    I.2.5.1. Phng trnh Nerst.

    Trong cc phn trn, ta nhiu ln nhn mnh rng, 0E l thca cc phn ng trong nng dung dch v p sut ca cc kh tham gia phn ng oxi ha khu bng

    n v.

    Khi thay i nng dung dch v p sut ca cc kh th trsthE skhc vi trs

    0E chun.

    Nhng nh hng trn c nh ha hc v vt l hc ngi c l Walter Nerst tm

    ra v khi qut n nhsau:

    QnF

    RTEE ln0 =

    250C, hay T= 298K ta c.

    Qn

    EE lg059,00 =

    Vi phn ng tng qut sau: aA + bB = cC + dD

    th ta c:[ ] [ ]

    [ ] [ ]ba

    dc

    BA

    DCQ=

    E c thl thca in cc hoc thca phn ng.

    I.2.5.2.nh hng ca nng hay hot .

    Tphng trnh Nerst :[ ] [ ]

    [ ] [ ]0 0,059 lg

    c d

    a b

    C DE E

    n A B=

    Ta thy E phthuc vo nng ca cc cht A,B,C,D

    1/ Xt trng hp E l thin cc.Ta c: aOxh + ne bKh

    Phng trnh Nerst:[ ]

    [ ]a

    b

    Oxh

    Kh

    nlg

    059,00 =

    2/ E l thca phn ng.

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 10 -

    Xt phn ng: aOx2 + bKh1 = cKh2 + dOx1

    [ ] [ ]

    [ ] [ ]ba

    dc

    KhOx

    OxKh

    n

    EE12

    120 lg059,0

    = ; Vi 000

    1

    1

    2

    2

    Kh

    Ox

    Kh

    OxE =

    Kt lun: T hai biu thc trn ta thy nng dng oxi ha v dng kh nh

    hng rt ln n gi tr , E

    I.2.5.3. nh hng ca p sut

    Xt phn ng sau 250C.2

    02( ) ( ) 2

    2 2 ; 1,36k aq ClCl

    Cl e Cl V + =

    iu kin trn ta c:[ ] ( )

    V

    p

    Cl

    Cl

    567,1

    10

    10lg

    2

    059,036,1lg

    2

    059,0 32

    0

    2

    ===

    Kt lun:p sut nh hng kh mnh n thin cc ca phn ng.

    I.2.5.4. nh hng ca pH.

    Nu trong qu trnh oxi ha kh, c ion H+hoc OH- tham gia th th ca phn ng

    cng phthuc vo pH ca chng.

    Trung hp tng qut: Khi tt ccc cht tham gia phn ng oxi ha kh(trH+)

    u c nng v p sut bng n v, ta c biu thc.

    0 0,059 mpHn

    =

    m, Sion H+hoc OH-trong phng trnh chung

    n; Selectron trao i trong phng trnh chung

    Kt Lun:pH nh hng ln n thca phn ng.

    I.2.5.5. nh hng ca nhit .

    mt nhit bt k ta c:

    )1(pT

    GHG

    += v )2(nFEG =

    T(1) v (2) ta c:T

    ET

    nFE

    +

    = hoc

    dT

    dET

    nFE +

    =

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 11 -

    VidT

    dEl hsnhit ,

    Kt lun:Nhi

    t

    nh h

    ng l

    n

    n thc

    a phn

    ng.I.2.5.6. nh hng ca sto kt ta.

    Xt phn ng sau 250C: VFeeFe aqaq 77,0;102

    )(3

    )( +=+ ++

    Tnh ca bn phn ng khi cho vo dung dch trn nng [OH-] = 1M

    - iu kin trn ta c:[ ][ ]

    [ ][ ] 36333)(

    1422

    2)(

    10

    10

    +

    +

    ==

    ==

    OHFeT

    OHFeT

    OHFe

    OHFe

    Khi ta c:[ ][ ]

    VFe

    Fe528,0

    1010

    lg1059,0

    77,0lg1059,0

    36

    14

    3

    20 ===

    +

    +

    Kt lun: Do c s to kt ta lm cho kh nng kh ca ion Fe2+ tng ln rt

    nhanh.

    I.2.5.7. nh hng ca sto phc

    Xt phn ng sau: VFeeFe 77,0;1 023 =+ ++

    Nu khi thm vo htrn mt phi tc khnng to phc cht bn vi cdng oxiha v dng khth ta c. ( )[ ] ( )[ ] + 46

    36 1 CNFeeCNFe

    Ta c cn bng:( )[ ]

    ( )[ ] 37246

    44336

    10.25,1;6

    10.25,1;62

    3

    +

    +

    =+

    =++

    +

    FeCb

    FeCb

    KCNFeCNFe

    KCNFeCNFe

    Khi ta c:( )[ ]

    ( )[ ]

    [ ][ ]+

    +

    +=+

    +

    2

    300 lg059,0

    3

    2

    46

    36 Fe

    Fe

    FeFe

    CNFeCNFe

    V ( )[ ] ( )[ ]

    =

    4

    6

    3

    6 CNFeCNFe

    iu ki

    n chu

    n. ( )

    ( )

    364

    6

    0,36Fe CN Fe CN

    V

    =

    Vy: Th chun ca phn ng ny gim t 0,77V xun cn 0,36V v

    ( )[ ] 36CNFe bn hn ( )[ ] 4

    6CNFe

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 12 -

    I.2.6. Chiu ca phn ng oxi ha - kh

    Trong dung dch nc, chiu ca phn ng oxi ha khc xc nh da vo cng

    thc sau:G nFE = (1)

    E c tnh nhsau: ( ) ( )1 1 2 2ox kh ox khE =

    Trong ( )1 1ox kh l thkhca cp oxi ha khc dng ox1vbn phi ca

    phn ng, cn ( )2 2ox kh l thkhca cp oxi ha khc dng kh2vbn tri

    ca phn ng, ngha l ng vi phn ng sau:

    1 2 1 2ox oxkh kh+ +

    Nu ( ) ( )1 1 2 2ox kh ox kh > th E > 0 v theo cng thc (1) ta c 0G < ngha l

    phn ng i theo chiu thun. Ngc li nu ( ) ( )1 1 2 2ox kh ox kh < th phn ng i

    theo chiu nghch.

    Khi thc hin phn ng iu kin chun th: 0 0G nFE = (2)

    Vi ( ) ( )0 0 01 1 2 2ox kh ox khE =

    I.2.7. Hng scn bng ca phn ng oxi ha kh

    Tcng thc: 0 0 lnG nFE RT K = = . Ta c: 0 lnRT

    nE KF

    =

    250C biu thc tr thnh:0

    lg0,059

    nEK= , K l hng scn bng ca phn ng.

    I.2.8. Ha hc v dng in

    I.2.8.1. Pin

    Pin l mt loi ngun in ha ph bin dng cho nhiu mc ch. Trong pin, nng

    lng phn ng ha hc bin thnh in nng.

    1. Sc in ng ca pin

    nh ngha. Sut in ng ca pin l gi tr(trstuyt i) ca hiu s

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 13 -

    in thln nht gia hai in cc ca pin. N c tnh bng cng thc.

    0E + = >

    y: E sut in ng ca pin(V); + - thkhca in cc dng(V); - th

    khca in cc m (V),

    Nu pin c cu to bi hai in cc iu kin chun th sut in ng chun l:

    0 0 0 0E + = >

    2. Pin in ha

    Pin Lclngse

    - in cc m (anot) ca pin l Zn (ng thi l vbc pin).- in cc dng (catot) ca pin l mt thanh ch c bao bc bi mt hn hp MnO4

    v bt than.

    - Cht in li y l 4 2,NH Cl ZnCl dng bt nho. Cc qu trnh xy ra trong pin

    nhsau: in cc Zn cung cp ngun electron.

    Qu trnh oxi ha : 2 02 ; 0,76Zn Zn e V+ + = +

    Electron chuyn ng ra mch ngoi tin cc m (Zn) n in cc dng, to ra

    dng in. Qu trnh kh: 04 2 3 22 2 2 ; 1,04MnO H e Mn O H O V++ + + =

    Sc in ng ca pin l.

    2 0

    04 2 3 2

    2 04 2 3 2

    2 ; 0,76

    2 2 2 ; 1,04

    2 2 ; 1,80pu

    Zn Zn e V

    MnO H e Mn O H O V

    Zn MnO H Zn Mn O H O E V

    +

    +

    + +

    + =

    + + + =

    + + + + =

    Sca pin nhsau: ( ) ( )4 2 2, ,Zn NH Cl ZnCl MnO C +

    I.2.9. Sin phnI.2.9.1 nh ngha

    Sin phn l qu trnh oxi ha - khxy ra bmt cc in cc khi cho dng in

    mt chiu i qua hp cht nng chy hoc dung dch cht in li.

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 14 -

    Vy : Sin phn l qu trnh bin in nng thnh ha nng.

    Hnh I.2. Sin phn.

    - Phn ng oxi ha - khxy ra in cc khi in phn.

    + Cc cation (ion dng) vcatot (cc m), ti xy ra qu trnh nhn electron to

    ra sn phm (cht oxi ha)

    + Cc Anion (ion m) vanot (in cc dng), ti anion nhng electron to ra

    sn phm (cht kh).

    I.2.9.2. Cc dng in phn

    1. in phn nng chy

    - in phn cc cht nng chy (mui, Al2O3)

    catot ion dng kim loi nhn electron.

    anot ion m nhng electron.Trong in phn mui nng chy, bn thn mui nng chy l cht in li, cc ion b

    ht v cc in cc tri du: Cation b ht v catot (cc m) v anion v anot (cc

    dng)

    2. in phn dung dch

    Khi in phn dung dch cht in phn c nhiu cht oxi ha v cht khth xxy ra

    oxi ha khln lt cc in cc theo thtu tin.

    a/ Qu trnh xy ra Catotxt xem cation kim loi Mn+ hay H2O bkhcatot, trc ht cn so snh thkh

    ca hai cpnM

    M+

    v2

    HH

    +

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 15 -

    Trong mi trng trung tnh (pH = 7) ta c: 72

    0,059lg10 0, 423H VH+ = =

    Nu cation kim loi c ( )n

    M M+

    ln hn nhiu so vi -0,413V th trong dung dch

    trung tnh ion Mn+bkhcatot khi in phn thnh kim loi: ( )nM ne M tt+ +

    Nu cation kim loi c ( )nM

    M+

    nhhn nhiu so vi -0,413V th ion Mn+skhng

    bkhm H+ca nc bkhthot ra H2.

    2( )2 2 2kHOH e H OH+ +

    Cui cng nhng kim loi c

    ( )

    nM

    M

    +

    gn vi gi tr-0,413V nhZn, Cr, Fe, Cd,

    Ni ty thuc vo nng ca dung dch v iu kin in phn m kim loi hay H2

    thot ra catot.

    b/ Qu trnh xy ra Anot tr.

    Trong mi trng kim xy ra qu trnh oxi ha cc anion OH-

    2 24 4 2OH O e H O + +

    Trong mi trng axit hoc trung tnh xy ra soxi ha H2O

    2 22 4 4H O O e H+ + +

    Cc anion c cha oxi ca axit khng c khnng boxi ha hoc soxi ha chng

    xy ra thrt cao. Khi in phn dung dch ca axit khng cha oxi v mui ca n

    (trHF v mui florua) th anion ca axit boxi ha anot tr.

    c/ Qu trnh xy ra anot tan.

    Khi in phn vi anot tan c ba qu trnh oxi ha cnh tranh nhau anot. l soxi

    ha nc to ra oxi, sphng in ca anion cht in li v soxi ha kim loi lmanot. Nu kim loi lm anot c thkhnhhn hai cp oxi ha khkia th squan

    st thy soxi ha kim loi : ( )n

    ttM M ne+ +

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 16 -

    Trong trng hp ngc li sxy ra s thot ra kh oxi hoc soxi ha anion cht

    in li nhtrn xt trn.

    cc dng c cc anion v nhng electron theo tht.2 - 2

    3 4OO ....Cl Br S CH C OH SO > > > > >

    3. nh lut Faraday.

    Tkt qunghin cu Faraday thit lp c nh lut in phn sau y.

    Khi lng cc cht to thnh in cc khi in phn tlvi lng in i qua cht

    in phn v tun theo cng thc sau:AQ AIt

    mnF nF

    = =

    I.2.10. Sn mn kim loi.I.2.10.1. Khi nim. Sph hy vt liu kim loi gy nn bi cc cht mi trng

    xung quanh gi l sn mn kim loi.

    I.2.10.2. Phn loi.

    1.n mn ha hc

    c im ca n mn ha hcl khng pht sinh dng in ( khng c cc in cc )

    v nhit cng cao th tc n mn cng nhanh.

    Th d: 2 2 3 23 4 4Fe H O Fe O H + = +

    Bn cht ca n mn ha hcl qu trnh oxi hakh, trong cc electronca kim

    loi c chuyn trc tip sang mi trng tc dng.

    2.n mn in ha hc

    Qu trnh ha tan kim loi lin quan n sxut hin cc dng in vi m, n cc qu

    trnh Anot v Catot gi l hin tng n mn in ha.

    Kim loi lun ch

    a cc t

    p ch

    t. Kim lo

    i v cc t

    p ch

    t trong kim lo

    i c

    ng nh

    mi

    trng to thnh cc cp in cc vi thin cc khc nhau.

    Trong cc qu trnh Anot, kim loi boxi ha trthnh cc ion dng:

    nM M ne+ +

    http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=747#3http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=747#3http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=747#3http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=747#3http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=747#3http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=747#3http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=747#3http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=747#3http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=159#3http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=142#4http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=742#0http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=742#0http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=142#4http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=159#3http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=747#3http://www.onthi.com/?a=OT&ot=LT&hdn_lt_id=747#3
  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 17 -

    Trong cc qu trnh Catot, cc tc nhn oxi ha nhn cc in tny to nn phn ng

    kh: Chng hn: 2

    2 2

    2 2

    4 4 2

    H e H

    O H e H O

    +

    +

    +

    + +

    Kt qul cc kim loi bha tan, bn mn.

    I.2.10.3. Cc phng php bo v.

    1. Phng php to lp ph.

    Cht phc dng c thl kim loi bn i vi mi trng nh; Ni, Zn, Cr, Sn, Cd,

    Al, Ag, Au.., Nhng cht phkhng phi l kim loi, thng l sn, men, nha.

    2. Bo vbng phng php in ha

    Sdng phng php catot. Nu ngi ta ni Fe vi Zn chng hn bng mt dy dn

    th hin tng n mn Fe sc hn chv i vi cp kim loi Fe Zn th Fe givai

    tr l mt Catot. 2 20 00,44 ; 0,76Fe ZnFe Zn

    V V + += =

    Trong khi Zn givai tr ca mt anot, boxi ha theo phn ng

    2 2Zn Zn e+ +

    Ngc li phn ng : 2 2Fe Fe e+ + skhng xy ra.

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 18 -

    CHNG II. NHNG NI DUNG IN HA HC TRONGCHNG TRNH HA HC PHTHNG.

    II.1. Phn tch s hnh thnh v pht trin khi nim in ha hc trong

    chng trnh ha hc trng THPT.

    Khi nim in ha hc c xy dng trn nn tng ca kh nhiu l thuyt. Tuy

    nhin mc phthng ngi ta cha ra mt sl thuyt lin quan nh: Thuyt

    in li, Phn ng oxi ha kh L thuyt in ha hc c dng nghin cu cc

    tnh cht ca cc cht, gii thch v tin on vtnh cht ha hc v tnh cht vt l.

    Qu trnh pht trin khi nim in ha hc chng trnh phthng c thchia thnh

    cc bc nhsau:

    Bc 1: Lp 10: Hc sinh c hc vl thuyt phn ng oxi ha kh Phn ng oxi

    ha kh l phn ng trong c s chuyn electron gia cc cht phn ng. Vn

    dng l thuyt ny gii thch sxut hin dng in trong pin in ha, v qu trnh

    trao i electron trong phn ng.

    Bc 2. Lp 11: Pht trin khi nim in ha hc

    Hc sinh c hc vthuyt in li: Tnh dn in ca cc dung dch axit bazvmui l do trong dung dch ca chng c cc tiu phn mang in tch, chuyn ng t

    do c gi l cc ion hay Qu trnh phn li cc cht trong nc ra ion l sin li.

    Nhng cht tan trong nc phn li ra ion c gi l cht in li

    Vn dng l thuyt ny gii thch sxut hin thtrn cc in cc, schnh lch

    thgia cc in cc t xut hin dng in di chuyn trong dy dn ni hai in

    cc.

    Bc 3. Lp 12: Pht trin v hon thin khi nim in ha hc.Tcc phn ng ha hc c trng ca kim loi trong chng i Cng Kim Loi

    nh: Fe + HCl FeCl2+ H2

    CuFeSOlCuSOFe ++ 44 )(

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 19 -

    Da vo phn ng kim loi chuyn chcho nhau (kim loi ny c thy ion kim loi

    khc ra khi mui ca chng) ngi ta xp xp c nhiu kim loi theo khnng

    phn ng ca chngV d: ++ ++ 222 CuAgAgCu

    Tuy nhin phng php trn cha tng qut v khng chnh xc. nh gi nh

    lng khnng oxi ha khca cc kim loi, ion kim loi trong dung dch, ngi ta p

    dng l thuyt ca in ha hc chng minh. Da vo i lng thoxi ha kh

    (hay thin cc) ca chng ( 0M

    Mn+ ).Tgi trthkhchun ngi ta c thso snh

    c mnh yu ca cc kim loi v ion kim trong dung dch.V vy ngi ta xpxp c dy in ha sau:

    +K +Na +2Mg +3Al +2Zn +2Fe +2Ni +2Sn +2Pb +H +2Cu +Ag +Au

    K Na Mg Al Zn Fe Ni Sn Pb 2H Cu Ag Au

    II.2. Cu trc ni dung in ha hc trong chng trnh ha hc phthnglp12, ban cbn, ban nng cao

    Ha hc lp 12 nng cao Ha hc lp 12 cbn

    Khi nim in ha hc, tp trung chyu chng 5:i cng vkim loi.

    Bi 20 Dy in ha ca kim loi1. Khi nim cp oxi ha

    kh2. Pin in (sut in ng,thin cc)

    3. Thin cc chun (incc hiro chun,thincc ca cc kim loi)

    4. Dy thin cc ca

    Bi 18 Tnh cht ca kim loi dy inha ca kim loi.

    1. Dy in ha ca kimloi.

    Tnh oxi ha ca ion kim loi tng

    Tnh khkim loi gim

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 20 -

    kim loi.5. ngha ca thin cc.

    Bi 21 Luyn tp: Tnh Cht Ca kim

    loi

    Bi 19 Hp kim

    1. Khi nim2. Tnh cht3. ng dng

    Bi 22 Sin phn.1. Khi nim.2. S in phn cc cht

    in li2.1. in phn cht in li

    nng chy2.2. in phn dung dch

    cht in li trongnc.3. ng dng ca s inphn

    Bi 20 Sn mn kim loi1. Khi nim2. Cc dng n mn3. Chng n mn kim loi3.1. Phng php bo v

    bmt3.2. Phng php in

    ha

    Bi 23 Sn mn kim loi1. Khi nim.2. Hai dng n mn kim

    loi2.1. n mn ha hc2.2. n mn in ha3. Chng n mn kim loi.

    Bi 21 iu chkim loi1. Nguyn tc.2. Phng php.2.1. Phng php nhit

    luyn2.2. Phng php thy

    luyn2.3. Phng php inphn

    Bi 24 iu chkim loi.1. Nguyn tc iu ch.2. Phng php iu2.1. Phng php thy

    luyn2.2. Phng php nhit

    luyn

    2.3.

    Ph

    ng php

    inphn

    3. nh lut faraday

    Bi 22 Luyn tp: Tnh cht ca kimloi

    Bi 25 Luyn tp: Sin phn snmn kim loi iu ch kimloi

    Bi 23 Luyn tp: iu ch kim loiv sn mn kim loi.

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 21 -

    Bi 26 Bi thc hnh s 3. Dy inha ca kim loi iu chkim loi

    Bi 24 Thc hnh: Tnh cht, iu chkim loi, sn mn kim loi.

    Bi 27 Bi thc hnh s 4: n mnkim loi v chng n mn kimloi.

    II.3. Mt skin thc cbn hc sinh cn nm vng khi hc vphn in

    ha hc trng Trung Hc PhThng.

    Ha hc lp 12 nng cao Ha hc lp 12 cbn

    Bi 20 Dy in ha ca kim loi

    Mt skin thc trng tm hc

    sinh cn nm vng:

    1. Hc sinh phi bit c khi

    nin cp oxi ha kh, pin in

    ha, sut in ng v thin

    cc l g?

    2. Hc sinh phi bit c cu

    to ca pin in ha, schuyn

    ng ca cc phn t mang

    in khi pin in ha hot

    ng?

    3. Cc phn ng ha hc noxy ra cc in cc ca pin

    in ha?

    4.Bit c thin cc chun

    Bi 18 Tnh cht ca kim loi dy

    in ha ca kim loi.

    Phn kin thc c s hc sinh

    phi nm vng.

    1. Thno l cp oxi ha kh?

    V d: CuCuAgAg ++ 2

    ;

    2. Thno l dy in ha ca

    kim loi?

    l dy sp xp cc cp oxi

    ha kh theo chiu tng dn

    tnh oxi ha ca ion kim loi v

    gim dn ca tnh khkim loi

    3. ngha ca dy in ha hc

    l g?

    Don chiu ca phn ng

    gia hai cp oxi ha kh theo

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 22 -

    l g? Chiu ca phn ng oxi

    ha kh , tnh th in cc

    chun ca cp oxi ha khtrong pin in ha?

    5.Dy thin cc chun ca

    kim loi v ngha ca n?

    quy tc

    CuCu

    FeFe

    ++ 22

    ( ) ( ) ( ) ( )raqraq CuFeFeCu ++ ++ 22

    Bi 22 Sin phn.

    1. Hc sinh phi bit c s

    in phn l g?

    2. Bit nhng ng dng ca s

    in phn trong cng nghip l

    g?

    3. Hiu schuyn dch ca cc

    ion trong qu trnh in phn:

    Mui NaCl nng chy, dung

    dch CuSO4vi in cc trv

    in cc tan (anot tan).

    4. Hiu nhng phn ng ha

    hc xy ra trn cc in cc

    trong qu trnh in phn v

    vit c phng trnh in

    phn

    Khng tch thnh bi ring

    Bi 23 Sn mn kim loi

    1. Hiu cc khi nim th no

    l n mn kim loi, n mn ha

    hc v n mn in ha hc?

    2. Hc sinh phi bit c cc

    Bi 20 Sn mn kim loi

    1. Hc sinh phi bit c n

    mn kim loi l g?

    2. Hc sinh phi bit c c

    cc dng n mn no trong t

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 23 -

    iu kin v bn cht ca n

    mn ha hc v n mn in

    ha hc.3.Hiu c nguyn tc v cc

    bin php chng n mn in

    ha hc?

    nhin?

    3. Hc sinh phi bit cch

    chng n mn kim loi l g?

    Bi 24 iu chkim loi.

    Phn kin thc trng tm.

    1. Hc sinh phi bit c

    nguyn tc chung iu ch

    kim loi l g?

    2. Hiu cc phng php c

    vn dng iu chkim loi.

    Mi phng php thch hp

    vi siu chnhng kim loi

    no. Dn ra c nhng phn

    ng ha hc v iu kin ca

    phn ng u ch nhng kim

    loi cth.

    Bi 21 iu chkim loi

    Kin thc trng tm hc sinh

    cn nm bt c l:

    1. Nguyn tc iu chkim loi

    l g?

    Nguyn tc iu ch kim loi

    l kh ion kim loi thnh kim

    loi nguyn t

    Mn++ ne M

    2. Cc phng php iu ch

    kim loi l g?

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 24 -

    II. 4 . Mt svn gio vin cn ch khi dy phn in ha hc trng

    THPT

    II.4.1. Ni dung kin thc vin ha hc cc lp cbn, nng caoII.4.1.1. Lp 12 cbn

    1. Bi 18: Tnh cht ca kim loi. Dy in ha kim loi

    a/Dy in ha ca kim loi.

    Nm tht chc vkhi nim cp oxh khca kim loi: Dng oxi ha v dng kh

    ca cng mt kim loi to thnh cp oxi ha khca kim loi.

    - lm rvn ny cn so snh mc hot ng ca cp oxi ha khkhng

    nh u trnh bi:2Zn

    Zn+

    v2Cu

    Cu+

    T ta suy ra: 2 2Zn Cu Zn Cu+ ++ +

    - Lin hcc phn ng gia kim loi v dung dch mui (da vo th), so snh c

    khnng hot ng ca cc kim loi, sau trnh bi dy in ha

    b/ ngha dy in ha kim loi .

    Lm rquy tc xt chiu ca phn ng oxh - kh

    2 2Cu Fe Fe Cu+ ++ +

    Cht oxi ha mnh cht khmnh cht oxh yu hn cht khyu hn

    2. Bi 20. n mn kim loi. Cc vn cn lu .

    - Cn lm cho hc sinh thy rskhc nhau gia hin tng n mn ha hc v n

    mn in ha hc. Sn mn in ha hc xy ra phbin hn trong thc tso vi n

    mn ha hc.

    - Vn dng nhng hiu bit vpin in lm rsn mn in ha hc- Tm hiu iu kin xy ra n mn in ha hc

    3. Bi 21. iu chkim loi. Nhng vn gio vin cn lu :

    - Cn lm rmi quan hgia mt hot ng ha hc ca cc kim loi v phng

    php iu chda vo dy in ho.

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 25 -

    - Nguyn tc iu chkim loi : Khion kim loi: nM ne M+ +

    II.4.1.2. Lp 12 nng cao.

    Cc vn gio vin cn ch y c lit k trong tng bi cth.

    1. Bi 20: Dy in ha ca kim loi.

    a/ Khi nim cp oxi ha khca kim loi.

    Tm hiu khi nim v khi qut theo s. nM ne M+ +

    Dng oxh Dng kh

    b/ Pin in ha.

    Cn cho hc sinh c nhng bc nhn thc nhsau:

    - Quan st th nghim (th nghim hnh 5.3 SGK) pin in ha Zn Cu

    - Gii thch cc hin tng quan st c trong qu trnh hot ng ca pin in ha

    Zn Cu v vit phng trnh ha hc xy ra.

    c/ Thin cc chun ca kim loi. Dy thin cc chun ca kim loi

    Cn c nhng bc hot ng sau.

    - Thng bo vthin cc hiro tiu chun.

    + Quy c vthin cc hiro chun: ( )20

    2 0,00H H V + =

    - Tm hiu cch xc nh thin cc chun ca kim loi. V dca Zn.

    + Nhng phn ng ha hc xy ra in cc khi pin Zn H hot ng

    + Lm rtrng hp no th thin cc chun ca cpnM

    M+

    c gi trdng, m.

    - Da vo thin cc chun nu nguyn tc sp xp cc cp oxi ha khca kim

    loi trong dy in ha hc.

    d/ ngha ca dy thin cc chun ca kim loi.

    Hot ng tm hiu v ngha ca thin cc chun ca kim loi, nn chia thnh

    nhng hot ng nhsau:

    - Hot ng tm hiu vchiu ca phn ng gia hai cp oxi ha khca kim loi.

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 26 -

    - Phn tch phn ng gia hai cp oxi ha kh.

    2 0( 0,34 )Cu VCu +

    = + v 0( 0,80 )Ag VAg +

    = +

    Kt lun vchiu ca phn ng ha hc: C ba kt lun tng ng vmt ngha:

    - Kim loi c cp oxi ha khc thin cc chun nhkhc kim loi ca cp

    oxi ha khc thin cc chun ln hn trong dung dch mui.

    - Cation kim loi trong cp oxi ha khc thin cc ln hn oxi ha c kim

    loi trong cp oxi ha khc thin cc nhhn.

    - Cht oxi ha mnh hn soxi ha cht khmnh hn, sinh ra cht oxi ha yu hn

    v cht khyu hn. (quy tc )2. Bi 22. Sin phn. Cc vn cn ch khi dy bi 22.

    a/ Khi nim vsin phn.

    - Lin hn thca cc cp oxi ha khxc nh: Tn cc in cc, du ca cc

    in cc v phn ng xy ra cc in cc.

    b/in phn dung dch CuSO4vi in cc graphit. dung dch CuSO4vi Anot tan

    Cn lm rthtin phn ca cc ion, phn tcc in cc da vo dy thin

    cc.

    3. Bi 23.Sn mn kim loi. Cc vn cn lu khi dy bi 23.

    - Cn lm rnguyn nhn no dn n n mn in ha, lin hli bi dy in ha.

    - iu kin xy ra sn mn ha hc?

    4. Bi 24: iu chkim loi. Cc vn cn lu .

    a/ Phng php thy luyn.

    - Csca vic iu chkim loi bng phng php thy luyn- Phng php thy luyn c dng iu chnhng kim loi no

    b/ Phng php in phn.

    - Csca phng php in phn iu chkim loi. Nhng kim loi no c thiu chc bng phng php in, lin hdy in ha.

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 27 -

    II.4.2. Phng php dy hc vcc vn in ha hc

    Nhm t c kt qu tt nht v vic hc sinh c thhiu, nm vng cc kin

    thc cbn vin ha hc th i hi khng chngi gio vin nm vng vnidung kin thc m cn phi c phng php sphm kho lo. Phng php ng vai

    tr kh quan trng trong qu trnh hc sinh tip thu kin thc. Mt sphng php dy

    hc ha hc chung c ththp dng cho phn in ha hc nh:

    - Sdng thit bth nghim, m hnh ha hc theo nh hng chyu l ngun

    hc sinh nghin cu, khai thc tm ti kin thc ha hc.

    - S cu hi v bi tp ha hc hc sinh chng nhn kin thc, hnh thnh k

    nng v vn dng tch cc cc kin thc, knng hc.

    - Ty vo tnh cht ca cc bi hc trong chng, ta c thphn chia thnh hai phng

    php hnh thnh kin thc cho hc sinh nhsau.

    + i vi loi bi hc nhm xy dng v hnh thnh khi nim mi cho hc sinh, nh

    bi: Dy in ha ca kim loi, in phn, Sn mn kim loi,phng php dy

    nn thit ktheo m hnh dy nhsau:

    + i vi nhng loi bi hc i hi svn dng l thuyt tm hiu tnh cht ca

    cht, nhtm hiu tnh cht vt l, tnh cht ha hc chung ca kim loi, iu chkim

    loi,.th phng php dy hc nn thit ktheo m hnh sau:

    Th nghim nghincu, quan st cchin tng thnghim.

    Vn dng l thuytcho gii thchcc hin tng quanst c

    Kt lun hoc hnhthnh khi nim

    mi

    Vn dng l thuytcho bit

    Don cu to vtnh cht ca cht

    Khng nh nhngiu don bng

    thn him.

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 28 -

    II.5. Vn dng mt skin thc vin ha hc ging dy ni

    dung in ha hc trong chng trnh ha hc trng THPT

    II.5.1. Sdng Thin Cc tnh Sc in ng v don xem mt phn

    ng oxi ha khcho trc c khnng xy ra hay khng.

    Csl da vo biu thc: G nFE = . 250C th ta c: 0 0G nFE =

    Trong : n- s electron trao i. F- hng sFaraday. E0 sut in ng ca phn

    ng.

    - Nu 0 0 0E G> < Phn ng tdin bin.

    - Nu0

    0 0E G< > Phn ng xy ra theo chiu nghch.- Nu 0 0 0E G= = Phn ng t cn bng.

    V d: Tnh sut in ng v don xem phn ng sau c xy ra khng 250C?

    ( ) ( ) ( ) ( )2 2aq r r aqCd Cu Cd Cu+ ++ + ; bit 2 2

    0 00,40 ; 0,34Cd Cu

    Cd Cu

    V V + += =

    Ta c:

    ( )

    ( ) ( ) ( ) ( )

    2

    2

    2 0

    2 0

    2 2 0

    2 ; 0,40

    2 ; 0,34

    ; 0,74

    aq CdCd

    CuCu

    aq r r aq

    Cd e Cd V

    Cu Cu e V

    Cd Cu Cd Cu E V

    +

    +

    +

    +

    + +

    + =

    + =

    + + =

    Vy sut in ng 0 0,76 0 0pinE V G= < > phn ng khng c khnng xy

    ra theo chiu nhtrn.

    II.5.2. Tnh thca mt bn phn ng khi bn phn ng l thp ca hai hay

    nhiu bn phn ng khc.

    Tnh thca bn phn ng: ( ) ( ) ?,303

    3 =++ raq TleTl bit:

    ( )+3

    aqTl ( )+

    aqTl Tl

    03 ? =

    V336,002 = V250,101 =

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 29 -

    p dng biu thc :21

    022

    0110

    3 nn

    nn

    +

    +=

    . Ta c :

    ( ) ( )

    ( )

    ( ) ( ) VTleTl

    VTleTl

    VTleTl

    raq

    aq

    raq

    ?,3

    250,1,2

    336,0,

    0

    3

    3

    02

    3

    01

    =+

    =+

    =+

    +

    ++

    +

    Trong : n1; n2; l selectron trao i trong bn phn ng (2),(3).

    02

    01 ; l thchun ca bn phn ng (2), (3).

    Khi ta c:( ) ( )

    Vnn

    nn721,0

    3

    250,12336,01

    21

    022

    0110

    3 =+

    =+

    +=

    Vy thca bn phn ng: ( ) ( ) VTleTl raq 721,0,303

    3 =++

    II.5.3. Don bn ca cc trng thi oxi ha ca mt nguyn t.

    Xt bn phn ng: ( ) ( ) ( )++ + 323 aqraq AuAuAu bit:

    ( )3aqAu

    + ( )aqAu+ Au

    Nu Au+ t oxi ha kh th phng trnh phn ng trn c th 00 >puE , v khi

    00 00puE 00

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 30 -

    II.5.4.1. Don c chiu xy ra ca phn ng.

    Phn ng oxi ha khlun xy ra theo chiu to ra cht oxi ha v cht khyu hn,

    ngha l cht oxi ha mnh nht soxi ha cht khmnh nht.Bi tp vn dng.

    Bi tp 1. a/ Hy cho bit vtr ca cp MnMn +2 trong dy in ha. Bit rng H+oxi

    ha c Mn. Vit phng trnh ion thu gn.

    b/ C thdon iu g xy ra khi nhng l kim loi Mn vo cc dung dch mui:

    AgNO3,MnSO4, CuSO4? Hy vit phn ng di dng phng trnh ion rt gn nu c

    Li gii.

    a/ H+oxi ha c Mn, ngha l Mn c khnng khc H+:

    ++ ++ 222 HMnHMn

    2MnMn

    +

    xp trc2

    2H

    H+ trong dy in ha.

    b/ Trong dy in ha ta c: Mn xp trc Cu , Ag Mn c tnh khmnh hn. V

    thxy ra c cc phn ng:

    ++ ++ CuMnCuMn 22 ( Cu bm trn l Mn)

    ++ ++ AgMnAgMn 22 ( Ag bm trn l Mn)

    II.5.4.2. Xc nh tn kim loi.

    1.c cng thc tng qut hp cht cha kim loi l:

    ( ( ) ( ) ( )2 4 3 2 3, , , , .....x y n m a bM O RCl A SO B NO X CO ) sau tm khi lng nguyn t

    ca kim loi (M,R, A, B, X,) ri suy ra kim loi .Thng gp hai trng hp:

    - Trng hp 1:Bit ha trkim loi cn tm, da vo dkin bi tp lp phng

    trnh ton hc, tm khi lng nguyn tca kim loi, suy ra tn kim loi .

    - Trng hp 2:Khng bit ha trkim loi cn tm, da vo dkin bi lp biu

    thc lin hgia nguyn tkhi (M) ca kim loi vi ha tr(n) ca kim loi .

    Sau , bin lun M theo n (hay ngc li), tm cp nghim M, n hp l, suy ra tn kim

    loi.

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 31 -

    2. Bi tp vn dng. Nhng mt thanh kim loi M vo dung dch NiSO4sau mt thi

    gian thy khi lng thanh kim loi gm 0,12g. Xc nh tn kim loi M. Bit M ha

    trII v smol NiSO4hao ht 0,02mol. Tnh sgam kim loi tham gia phn ng.Li gii

    Phn ng: ( )4 4iSO 1M N MSO Ni+ +

    mol 0,02 0,02 0,02 0,02

    Theo bi, ta c:0,12

    0,02 65 :59

    MM

    = =

    km (Zn)

    Vy : mZn tham gia phn ng= 65

    II.5.4.3. Tng gim khi lng thanh kim loi

    Nhng mt thanh kim loi A v dung dch mui ca kim loi B (cha ion Bn+). Sau

    mt thi gian ly thanh kim loi ra, ra nh, sy kh, cn th thy khi lng thanh kim

    loi c thtng hoc gim.

    1. Khi lng thanh kim loi tng: Th ta p dng phng trnh i ssau.

    2. Khi lng thnh kim loi gim: Th ta p dng phng trnh i ssau:

    3. Bi tp vn dng:Thanh km nng 5,2 gam c cho vo 100ml dung dch

    CuSO41M, sau mt thi gian, ly thanh km ra cn c 5,18 gam.Tnh khi lng Cu

    bm vo thanh Zn.

    Ta c: molndaubanCuSO

    1,011,04

    ==

    Phn ng:aaaamol

    CuZnSOCuSOZn ++ 44

    Ta c: 65a 64a = 5,2 - 5,18 a = 0,02 mol

    Khi lng thanh Cu = 0,02 . 64 = 1,28 gam

    Mkim loi tng = m kim loi gii phng- mkim loi tan

    Mkim loi gim = mkim loi tan- m kim loi gii phng

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 32 -

    II.5.5. Kim loi lin quan n sin phn.

    Dng 1:in phn dung dch cc mui, Axit, baz

    - Catot: Nu cation ( ++ HMn ; ) ng sau Al3+trong dy in ha ca kim loi, skh

    cho ra kim loi hoc H2.

    Nu cation l Al3+hoc mt kim loi ng trc Al trong dy in ha ca kim loi

    ( ....;; 2+++ BaNaK ) th nc sbkhcho ra H2v ion OH

    ++ OHHeOH 22 22

    - Anot: Nu ion l X (X l halogen nhCl, Br, I.) hoc OH-th soxi ha cho ra

    X2hoc O2: 2 2 212 2 2 22Cl Cl e hay OH O H O e + + +

    Nu anion l ....;; 24243

    POSONO th lc ny nc sboxi ha cho ra O2v H+

    eHOOH 222

    122 ++

    +

    Dng 2: Trng hp c nhiu cation c thbkhbn catot

    Cc cation ion bkhtheo thttnh oxi ha gim dn, ion bn phi (c tnh oxi ha

    mnh nht) bkhtrc ri n ion bn tri trong dy in ha ca kim loi.Dng 3: Trng hp c nhiu anion boxi ha bn anot:

    Cht c tnh khmnh nht sboxi ha trc.

    Dng 4: Dng cng thc Faraday tnh khi lng cc cht thot ra cc in cc:

    n

    AItm

    96500=

    Bi tp vn dng:in phn c mng ngn in cc tr 100ml dung dch MgCl2

    0,5M vi cng dng in I = 0,1A vi thi gian 9650s. Tnh nng mol/l dungdch mui sau phn ng.

    Ta c: molnMgCl 015,015,01,02 ==

    2 2

    2 0.1 9650 0,010,01 0,005

    96500 2 96500 2H HAIt

    m g n moln

    = = = = =

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 33 -

    Phn ng:005,0005,0

    )()(2 22222mol

    dpddHClOHMgOHMgCl +++

    Smol MgCl2d= 0,015 0,005 = 0,01mol ; Vy: MC MgClM 1,01,001,0)( 2 ==

    II.5.6. Kim loi phn ng vi dung dch mui.

    Dng 1:Mt kim loi y mt ion kim loi khc.

    iu kin kim loi X y kim loi Y ra khi dung dch mui ca Y

    - X phi ng trc Y trong dy in ha.

    - Mui ca kim loi Y phi tan trong nc.

    Dng 2:Cho mt kim loi X vo dung dch cha hai mui ca hai kim loi Yn+

    , v Zm+

    .- n gin trong tnh ton, ta chxt trng hp X ng trc Y v Z, ngha l kh

    c chai ion Yn+, v Zm+(Y ng trc Z)

    - Do Zm+c tnh oxi ha mnh hn Yn+nn X phn ng vi Zm+trc:

    ++ ++ qZmXqZmX qm (1) q l ha trca X.

    Nu sau phn ng (1) cn dX th c phn ng: ++ ++ qYnXqYnX qn (2)

    Vy, cc trng hp xy ra sau khi phn ng kt thc:

    + Nu dung dch cha 3 ion kim loi (Xq+;Yn+; Zm+) th khng c phn ng (2) xy ra,

    tc l kim loi X ht v ion Zm+cn d:

    + Nu dung dch cha hai ion kim loi (Xq+;Yn+) th phn ng (1) xy ra xong (tc ht

    Zm+), phn ng (2) xy ra cha xong (dYn+) tc X ht.

    Bi tp p dng: Cho 0,387 gam hn hp (A) gm Zn v Cu vo dung dch c cha

    0,005 mol Ag2SO4, khuy iu, ti phn ng hon ton thu c 1,144gam cht rn.

    Tnh khi lng mi kim loi.

    Li gii

    Phn ng:+=+

    +=+

    AgCuSOSOAgCu

    AgZnSOSOAgZn

    2

    2

    442

    442

    - V tng smol Zn v Cu nm trong gii hn.

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 34 -

    0,387 0,3870,0059 0,00604

    65 64hh hhn n< < < <

    hhn l

    n h

    n 0,005mol, ch

    ng t

    Ag2SO4h

    t.

    - GisZn phn ng mt phn, Cu cha tham gia phn ng.Gi smol Zn ban u l

    x, smol Zn phn ng l x. Gi smol Cu ban u l y. Khi lng thanh kim

    loi tng.

    108.2x 65.x= 1,144 0,387 = 0,757 (g) 151x= 0,757 x = 0,00501

    Smol ny lhn 0,005mol, iu ny khng ph hp vi bi, do Zn phn ng

    ht v x = x.

    - Zn phn ng ht, Cu tham gia phn ng mt phn.Gi smol Cu tham gia phn ngl y. Ta c phng trnh khi lng kim loi tng

    108.2x 65x + 108.2y 64.y = 0,757 (1). Gii phng trnh (1) kt hp vi phng

    trnh: x + y = 0,005 .Ta c:

    =

    =

    002,0

    003,0

    y

    x : Vy mZn= 0,003. 65 = 0,195 (gam)

    mCu= 0,387 0,195 = 0,192 (gam)

    II.5.7. Kim loi tc dng vi dung dch axit.

    II.5.7.1.Tc nhn oxi ha l ion H+trong axit.

    Cc axit HCl, H2SO4long,anion gc axit ca chng khng c tnh oxi ha.

    )1(2 2 ++ ++ HnMnHM n

    Ch : Phn ng (1) xy ra khi kim loi M ng trc hiro trong dy hot ng ha

    hc ca kim loi.

    II.5.7.2. Tc nhn oxi ha l anion gc axit.

    Anion ca cc axit (HNO3, H2SO4(c, nng)) oxi ha kim loi chkhng phi H+l tcnhn oxi ha nn kh to thnh khng phi l kh hiro, m l sn phm khca anion.

    - H2SO4(c, nng)c thbkhcho ra: SO2, S, H2S- HNO3c thbkhcho ra : NO2, NO, N2, N2O, NH4NO3

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 35 -

    II.5.7.3. Bi tp vn dng.

    Bi tp: Ha tan 62,1gam kim loi M trong HNO3long, cho 16,8 lt hn hp kh X

    (ktc) gm hai kh khng mu, khng ha nu ngoi khng kh. C t khi hi so vikhi H2 l 17,2. Xc nh tn M? Tnh thtch dung dch HNO32M, bit axit dng d

    25% so vi lng cn thit.

    Li gii

    Hai kh khng mu do HNO3long sinh ra l N2v N2O.

    Gi x,y ln lc l smol ca N2v N2O. Theo bi ta c:

    ==+

    ==

    +

    +

    75,04,228,16

    4,3422,174428

    yxyx

    yx

    =+=+75,0

    8,254428yx

    yx

    ==

    3,045,0

    yx

    Phn ng: 10M + 12xHNO3 = 10M(NO3)x + xN2 + 6xH2O

    Mol 4,5/x 5,4 0,45

    8M + 10xHNO3 = 8M(NO3)x + xN2O + 5xH2O

    Mol 2,4/x 3 0,3

    x

    x

    M 9691,62 == nghim hp l l: x = 3, M = 27: Nhm (Al)

    Smol HNO3dng d: 8,4 .25% = 2,1mol

    tng smol HNO3: 8,4 +2,1 = 10,5 mol

    Vy thtch dung dch HNO3= )(25,52

    5,10l=

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 36 -

    CHNG III. MT SKT QUBAN U

    III.1.Thc trng nm vng khi nim in Ha Hc trng TrungHc PhThngIII.1.1. iu Tra Thc Trng

    Chng ti tin hnh iu tra 1 khi lp gm 2 lp 12 nng cao 12A1 ,12A3v 2

    lp 12 ban cbn gm 12C1 ,12C2. trng THPT Lai Vung II.

    III.1.1.1. Mc ch.

    nh gi cht lng nm kin thc in ha hc ca hc sinh phthng khi lp 12.

    III.1.1.2. Tin Hnh.1. Lp 12 nng cao.

    Chng ti pht phiu iu tra xem xt tnh hnh nm kin thc phn in ha hc

    ca hc sinh cc lp 12A1 ,12A3trng THPT Lai Vung II.

    Slng phiu pht ra: 87 phiu, thu v87 phiu, phiu gm 10 cu hi trc nghim,

    mi cu c nhiu kin la chn.

    a. Kt Qu.

    Sau khi thng k sliu, kt quthu c nhsau.( Xem phlc 2)

    Ngoi xl kt qutng cu mt, chng ti cn cho im tng bi mt.Cch cho im

    nhsau: Bi gm 10 cu hi trc nghim 10 im. Mi cu ng c 1 im.

    Sau y l kt qutng lp.

    Xi 0 1 2 3 4 5 6 7 8 9 10

    fXi 0 0 2 0 1 2 3 8 15 9 212A1

    % 0 0 4,76 0 2,4 4,76 7,14 19,05 35,7 21,43 4,76

    fXi 0 0 0 0 1 3 8 10 11 10 212A3

    % 0 0 0 0 2,22 6,67 17,78 22,22 24,44 22,22 4,45

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 37 -

    Trong : Xil im s.

    fXil sln xut hin ca im s.

    Bi u th hin tlhc sinh t cc mc i m t1 - 10 ca hc sinh hai lp 12A1 v 12A3

    0

    10

    20

    30

    40

    0 1 2 3 4 5 6 7 8 9 10 im

    %

    Tl% hc sinh t imlp 12A1

    Tl% hc sinh t imlp 12A3

    Hnh III.1. Biu din tlhc sinh t im ca hai lp 12A1 v 12A3Sau khi thng k kt qu, tlxp loi nhsau:

    - Loi yu : (0 4) : 4,59%- Loi trung bnh : (5 6) : 18,39%- Loi kh : (78) : 50,57%- Loi gii : (9 10) : 26,45%

    Biu din cc kt qudi dng biu .

    Bi u th hin tlx p loi hc lc ca hai lp12A1 v 12A3

    4.59

    18.39

    50.57

    26.45

    Loi yu

    Trung bnh

    Loi kh

    Loi gii

    Hnh III.2.Tlxp loi hc lc ca hai lp 12A1 v 12A3b. Nhn xt

    Sau khi chm im tng cu, tng bi v thng k cc sliu, chng ti nhn thy a

    shc sinh lp 12 ban nng cao nm c mt skin thc cbn vvn in ha

    hc. Tuy nhin phn ln cc em cha nm su kin thc. T lhc sinh loi gii ch

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 38 -

    chim 26,44%. Bn cnh vn cn mt shc sinh mt cn bn vphn kin thc

    ny. Tlhc sinh loi yu chim 9,84%

    Qua thng thng k kt qutng cu hi chng ti rt ra nhng nhn xt sau :- Hc sinh tr li kh tt cc cu 1(93,1%) ; cu 2 (88,5%); cu 5 (93,1%); cu 7

    (77%); cu 9 (91,95%); cu 10 (94,25%) l cc cu hi lin quan n phn ng oxi ha

    kh, dy hot ng ha hc ca kim loi, thca pin.Tuy nhin vn cn mt shc

    sinh cha nm vng kin thc cbn ny, shc sinh tr li sai cc cu 7, cu 9 t

    (10% - 20%).

    - Cc cu 4, cu 6, cu 8, hc sinh ch tr li c mc trn trung bnh (50% -

    70%). Nhvy vn cn trn 30% hc sinh trli sai, do cc em cha nm vng kin

    thc vin phn, n mn kim loi v thca pin.

    - Khi vn dng l thuyt in ha vo vic gii cc bi tp tp th a shc sinh lm

    kh tt, tuy nhin mt st hc sinh vn cn tra lng tng.

    2. Lp 12 Ban CBn.

    Chng ti cng pht phiu iu tra kin thc vin ha hc dnh ring cho hc

    sinh lp 12 ban cbn. Phiu iu tra c pht cho 2 lp 12C1v 12C2. trng THPT

    Lai Vung II.

    Slng phiu pht ra l: 78 phiu, thu v78 phiu, gm 10 cu hi trc nghim, mi

    cu c nhiu kin la chn.

    a. Kt qu.

    Sau khi thng k sliu kt qunhsau . (Xem phlc 3)

    Ngoi xl kt qutng cu mt, chng ti cn cho im tng bi mt, cch cho im

    nhsau: Bi 10 cu hi trc nghim 10 im. Mi cu ng c 1 im. Sau y

    l kt qutng lp:

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 39 -

    Xi 0 1 2 3 4 5 6 7 8 9 10

    fXi 0 0 5 5 6 8 9 4 212C1

    % 0 0 12,82 12,82 15,38 20,51 23,08 10,26 5,13fXi 0 0 0 6 11 13 4 2 1 212C2

    % 0 0 0 15,38 28,21 33,33 10,26 5,13 2,56 5,13

    Trong : Xil im s.

    fXil sln xut hin ca im s.

    Biu din cc kt qudi dng biu .

    Hnh III.3.Biu din tlhc sinh t im ca hai lp 12C1 v 12C2Sau khi thng k kt qu, tlxp loi nhsau :

    - Loi yu : (0 4) : 42,31%- Loi trung bnh : (5 6) : 43,59%- Loi kh : (78) : 11,54%- Loi gii : (9 10) : 2,56%

    Biu din cc kt qudi dng biu

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 40 -

    Bi u th hin tlx p loi hc lc ca hai lp12C1 v 12C2

    42.31

    43.59

    11.54 2.56

    Loi yu

    Trung bnh

    Loi kh

    Loi gii

    Hnh III.4.Tlxp loi hc lc ca hai lp 12C1 v 12C2

    b. Nhn Xt.

    Sau khi x l tng tnh lp 12 ban nng cao chng ti nhn thy hc sinh lp 12ban cbn ca trng nm kin thc vin ha hc cha vng, tlhc sinh loi yu

    chim ti 43,31%, cn tlhc sinh t loi kh 11,54%, gii 2,56%.

    - Cc cu hc sinh tr li tng i tt l Cu 1(87,18%), Cu 2 (83,33%), Cu 4

    (50%), Cu 6 (73,08%), Cu 8 (52,56%) l nhng cu c lin quan n cc vn nh:

    Phn ng oxi ha kh, dy in ha, n mn kim loi, iu l nhng phn kin thc

    cc em va hc.

    - a shc sinh trli cha tt cc cu 3 (33,33%), cu 5(2,56%), cu 7(20,51%), cu

    9 (20,51%), cu 10 (15,54%) l cc cu c lin quan n cc dng ton p dng phn

    in ha hc nh: in phn, dy in ha, cc kin thc l thuyt vin phn....ng

    thi qua kt quca cc cu ny chng ti nhn thy a shc sinh cha nm vng

    bn cht ca kin thc in ha hc, cc em chnm c mt cch ssi v chbit

    p dng vi nhng dng bi tp quen thuc cn nhng bi c tnh nh hu nhcc

    em u khng lm c.

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 41 -

    III.1.2. Nhn xt, nguyn nhn v gii php.

    III.1.2.1. Nhn xt chung.

    - a shc sinh phn no nm c nhng kin thc cbn vin ha hc. Tuynhin, phn ln cc em cha nm tht chc v su kin thc, cc em thng ch ch

    hiu bit vn mt cch ssi.

    - a scc em chtrli ng nhng vn lin quan n cc kin thc m cc em

    gp thng xuyn.

    lp 12 ban nng cao, hu ht hc sinh trli rt tt cc vn vdy in ha, phn

    ng oxi ha - kh. lp 12 ban cbn l cc vn vdy in ha, phn ng oxi

    ha kh.

    - i vi nhng cu hi c lin quan n phn kin thc vin phn, n mn kim

    loi, hay vn dng cc kin thc in ha vo gii cc bi tp nh lng, th a scc

    hc sinh trli vi tlng rt thp, c bit l ban cbn. Do khi dy bi mi

    gio vin cn phi ch thng xuyn n li nhng kin thc cc lin quan n bi

    hc hc sinh khc su kin thc.

    - lp 12 ban nng cao, vi chng trnh ci cch hin nay th kin thc in ha hc

    c cp nht rt nhiu, a sl nhng vn mi do hc sinh tra lng tng khi

    gp phn kin thc ny. V d nh: Pin in ha, sc in ng, thin cc, in

    phn....bn cnh mt sgio vin chdy thong qua cha thkhc su c kin

    thc.

    - Chng ti nhn thy mc nm vng kin thc in ha hc c schnh lch gia

    cc lp. c bit l ban cbn.

    III.1.2. 2. Nguyn nhn v gii php.

    1/ Nguyn nhn khch quan v nguyn nhn chquan.

    - Nguyn nhn khch quan.

    in ha hc l phn kin thc kh kh, mang tnh khi qut, tru tng nn hc sinh

    hiu mt cch cha y , mt khc y l khi nim c manh nha hc cui nm

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 42 -

    lp 9 bc THCS (dy hot ng ha hc ca kim loi ), v n phn cui ca lp 12 n

    mi c trnh bi mt cch y , v vy hc sinh mt ln khng thhiu ht c.

    - Nguyn nhn chquan.Khi dy vphn kin thc in ha hc a sgio vin thng cha ch n vic s

    dng cc phng tin trc quan nh: m hnh, hnh v, m hnh ha cc kin thc

    gip hc sinh dhiu, dnhv nhlu. ng thi phn ln gio vin cng cha ch

    n vic phi hp, sdng linh hot cc phng php ging dy, cha thng xuyn

    n tp, cng ckhc su kin thc cho hc sinh.

    2/ Gii php.

    - Trc ht gio vin phi nm tht chc kin thc chuyn mn. ng thi cng phi

    sdng, phi hp linh hot cc phng php dy hc khc nhau nng cao hiu qu

    ging dy, gip hc sinh hng th hc tp, khng bnhm chn khi phi hc mt s

    lng ln kin thc nhhin nay.

    - Gio vin phi cho hc sinh xem xt cc vn ca cc cht trn csvn dng kin

    thc in ha hc gii quyt.

    - Khi dy phn l thuyt cs in ha gio vin cn ch ging tht k, nhn mnh

    phn trng tm v khc su cc kin thc. Cho hc sinh gii thch rmu cht ca vn

    lm cslnh hi cc kin thc lin quan sau ny.

    - Gio vin phi ch hnh thnh cho hc sinh cc kin thc hin i, va sc v ty

    theo trnh ca mi hc sinh.

    - Gio vin phi hng dn rn luyn cho hc sinh lm cc bi tp vvn lin quan

    n kin thc in ha nh: Dy in ha, in Phn, n mn kim loi, Pin in ha.

    - Trong qu trnh ging dy cc ban khc nhau gio vin cn ch trnh ca mi

    hc sinh, kin thc in ha mi ban c trnh bi nhng mc khc nhau. T

    iu chnh dy cho ph hp.

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 43 -

    III.2. Thit kmt sgio n dy vphn in ha trng trung hc

    phthng

    Da trn tnh hnh cc trng phthng theo kt quiu tra, chng ti thit k

    mt sgio n khi ging dy cc bi vin ha hc. son cc gio n ny ti

    da trn dn bi sch gio khoa, cc sch tham kho, sch bi tp v cc ti liu c lin

    quan, ng thi ti cng tham kho kin ca gio vin phthng, tham kho cc

    gio n mu ca cc gio vin lu nm, nhiu kinh nghim.

    GIO N HA HC 12 NNG CAOBI:DY IN HA CHUN CA KIM LOI

    I. MC TIU BI HC:

    1. Kin thc:

    Bit :

    Cc khi nim: cp oxi ha-khca kim loi, pin in ha, sut in ng v

    thin cc. Cu to ca pin in ha, schuyn ng ca cc phn tmang in khi pin

    in ha hot ng.

    Cc phn ng ha hc xy ra catot v anot ca pin in ha.

    Thin cc chun ca kim loi.

    Hiu: Dy thin cc chun ca kim loi v ngha ca n.

    2. Knng:

    So snh tnh oxi ha ca cc ion kim loi, tnh khca cc kim loi gia cccp oxi ha kh.

    Xc nh tn v du ca cc in cc trong pin in ha, tnh c sut in

    ng ca pin in ha.

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 44 -

    Tnh c thin cc chun ca mt scp oxi hakhtrong pin in ha

    II. CHUN B:

    Lp rp mt spin in ha ZnCu, PbCu, ZnPb theo hnh 5.3 SGK. Mt stranh nh c vtrc:

    * S chuyn dch ca cc ion trong pin in ha ZnCu, hnh 5.6 SGK

    * Scu to in cc hidro chun, hnh 5.7 SGK

    * Th nghim xc nh thin cc chun ca cp Zn2+/Zn hnh 5.8 SGK.

    * Th nghim xc nh thin cc chun ca cp Ag+/Ag, hnh 5.9 SGK

    * Bng dy in ha chun ca kim loi (SGK). Tranh vmt spin in ha.

    III. Hot ng:1.n nh lp:

    2. Khoch ging dy : Tit 1: Phn I v II.

    Tit 2:Phn III.

    Tit 3:Phn IV v V.

    HOT NG CA GV HOT NG CA HSI

    . Khi nim vcp oxi ho khHot ng 1.

    Cu hi 1: Hon thnh phng trnh

    ho hc v vit squ trnh oxi

    ho - khca phn ng:

    a) Cu + AgNO3

    b) Fe + CuSO4

    * GV nu vn . C thbiu dincc qu trnh oxi ho khtheo cch

    khc c khng?

    Cp oxi ha khl mt cp gm

    I

    . Khi nim vcp oxi ho khHc sinh ghi chp

    Hon thnh phng trnh ho hc.

    a) Cu + 2AgNO3 Cu(NO3)2+ 2Ag

    Cu Cu2++ 2e

    Ag++ 1e Ag

    b) Fe + CuSO4 FeSO4+ Cu

    Fe Fe2+

    + 2eCu2++ 2e Cu

    hoc vit gp : Fe2++ 2e Fe

    Cu2++ 2e Cu

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 45 -

    cht oxiha v mt cht khca

    cng 1 nguyn tha hc

    Cu hi 2: Xc nh cht oxi ho -kht rt ra nhn xt.

    * GV a ra s tng qut v gii

    thiu cp oxi ho - kh.

    II. Pin in ho

    Hot ng 2.1. Khi nim vpin in ha, sut

    in ng v thin cc:

    GV tin hnh th nghim nh SGK

    hoc m tth nghim (sdng s

    pin in ho Zn-Cu) hnh 5.3. Nu c

    iu kin dng phn mm m phng

    pin in ho cho HS xem.

    2. Cchpht sinh dng in:

    - M t cu to ca pin, hot ng

    ca pin, nhn xt v gii thch?

    * GV dng s hnh 5.4, 5.5, 5.6

    hoc dng phn mm m phng cho

    HS xem v yu cu HS nhn xt, gii

    thch schuyn dch e in cc Zn,

    Ag++ 1e Ag

    Cht oxi ha cht kh

    Tng qut : Mn+ + ne MDng oxi ha v dng kh ca cng mt

    nguyn tto thnh cp oxi ha kh. Cc cp

    oxi ha khtrn c vit nhsau:

    Fe2+/Fe ; Cu2+/Cu ; Ag+/Ag.

    Tng qut: Mn+/M

    II. Pin in ho

    1. Khi nim vpin in ha, sut inng v thin cc

    Hc sinh quan st hin tng th nghim

    + Kim loi tan vo dung dch

    + Sut in ng ca pin ha hc

    Epin= 1,10 V

    + Mu ca cc dung dch cha CuSO4?

    /v pin in ha Zn/Cu hnh 5.3 ta c:

    )/()/( 22 ZnZno

    CuCuo

    pino EEE ++ =

    2. Cchpht sinh dng in

    Gii thch.

    * in cc Zn (cc m) l ngun cung cp e,

    Zn boxi ho thnh Zn2+tan vo dung dch:

    Zn Zn

    2+

    + 2e* in cc Cu (cc dng) cc e n cc Cu,

    y cc ion Cu2+bkhthnh kim loi Cu

    bm trn bmt l ng.

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 46 -

    in cc Cu, cu mui tri, cu mui

    phi.

    - Vit phng trnh ion rt gn.

    * GV yu cu HS vit cc cp oxi

    ho-kh

    * GV gii thiu quy tc

    (3) Nhn xt

    - GV yu cu HS nhn xt nng

    ca cc ion trong dung dch mui

    CuSO4 v ZnSO4 s tng gim nh

    th no trong qu trnh in phn ?

    Sut in ng E ca pin in ho

    phthuc vo yu tno?

    Cu2++ 2e Cu

    * Cu mui tri: Cation NH4+( hoc K+) di

    chuyn sang cc ng dung dch CuSO4* Cu mui phi: Cc cation NO3

    di chuyn

    sang cc ng dung dch ZnSO4. Sdi

    chuyn ca cc ion ny lm cho cc dung

    dch mui lun trung ho in.

    * Phng trnh ion rt gn biu din qu

    trnh oxi ho-khxy ra trn bmt cc in

    cc ca pin in ho:

    Cu2+ + Zn Cu + Zn2+

    Ox Kh Kh. yu Ox yu

    Zn CuZn Cu

    2+2+

    3. Kt lun:

    C s bin i nng cc ion Cu2+ v

    Zn2+trong

    qu trnh hot ng ca pin. Cu2+gim, Zn2+

    tng

    Nng lng ca phn ng oxi ha kh

    trong pin in ha sinh ra dng in mt

    chiu.

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 47 -

    - GV yu cu HS cn c vo cc cp

    pin cho trong SGK cho bit qu

    trnh oxi ho kh din ra trong pinCu-Ag; Pb-Cu; Zn-Pb nhthno ?

    III. Thin cc chun ca kim

    loi

    Hot ng 3 :

    1. in cc hidro chun

    - V sao cn phi xc nh thin

    cc chun cho mi cp oxihakh?

    - thng bo thin cc chun:

    Dng hnh 5.7 xc nh

    Cn phi xc nh thin cc cho

    mi loi cp oxi ho- khv vy dng

    in cc chun so snh l in

    cc hiro chun.

    Nhng yu t nh hng n sut in

    ng ca pin in ha nh:

    * Nhit .* Nng ca ion kim loi.

    * bn cht ca kim loi lm in cc.

    III. Thin cc chun ca kim loi

    1. in cc hidro chun

    HS xem hnh 5.7 v ghi

    Ngi ta chp nhn mt cch quy c rng

    thin cc ca in cc hidro chun bng

    0,00V mi nhit

    H2 2H+ + 2e

    VE HHo 00,02/2 =+

    HS tho lun theo nhm c i din trnh

    by.

    a. Cu to ca in cc hiro chun.

    - in cc platin.

    - in cc nhng vo dd axit H+1 M.

    b. Cch xc nh thin cc chun hiro

    chun.

    - Cho dng kh H2c p =1 atm lin tc i qua

    dd axit bt Pt hp thkh H2.

    - Qui c thin cc hiro chun cp oxiho khH+/H2 l 0,00 V ; E

    0 (H+/H2)= 0,00

    V

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 48 -

    2. Thin cc chun ca kim loi:

    - HS dng hnh 5.8 trnh by nhng

    ni dung ca th nghim xc nh thin cc chun ca cp Zn2+/Zn ?

    - Cch lp thit b xc nh th

    in cc chun ca Zn?

    Nhng phn ng ha hc xy ra

    cc in cc khi pin ZnH hot ng?

    Th in cc chun ca cp

    Zn2+/Zn l 0,76V

    Thin cc chun ca kim loicn

    o c c xc nh t bng sut

    in ng ca pin to bi in cc

    hidro chun v in cc chun ca

    kim loi cn o.

    Dng hnh 5.9 trnh by ni dung

    th nghim xc nh th in cc

    chun ca cp Ag+/Ag. Hot ng

    dy v hc tng ttrn.

    2. Thin cc chun ca kim loi

    Cch xc nh thin cc chun ca kim

    loi- Thit lp pin in ho gm: in cc chun

    ca kim loi bn phi, in cc chun ca

    hiro bn tri vn khiu sin thln

    nht gia hai in cc chun. Nu in cc

    kim loi l cc m E00.

    * HS trli:

    - Hiro l in cc (+): 2H++ 2e H2

    - Km l in cc ( ) : Zn Zn2++2e

    Zn + 2H Zn + H22++

    2e

    * Vn kchs0,76 V.

    Cho bit hiu sin thln nht gia 2 in

    cc chun ca cp Zn2+/Zn v H+/H2.

    K hiu: E0(Zn2+/Zn)= 0,76 V.

    * Xc nh thin cc chun cp Ag+/Ag

    Cc phn ng xy ra:

    Ag l cc dng (catot): Ag++ e Ag

    Hidro l cc m (anot) : H2 2H++ 2e

    Phn ng xy ra trong pin:2Ag++ H22Ag

    + 2H+

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 49 -

    IV. Dy thin cc chun ca kim

    loi: Nguyn tc sp xp cc cp

    oxihakh ca kim loi trong dynhthno?

    IV. Dy thin cc chun ca kim loi:

    Dy thin cc chun ca kim loi l dy

    sp xp cc kim loi theo thttng dn thin cc chun .

    V. ngha ca dy thin cc

    chun ca kim loi:

    Hot ng 4:

    1. So snh tnh oxihakh:

    Quy lut ca dy?

    2. Xc nh chiu ca phn ng

    oxiha kh:

    HS phn tch cc chi tit trong th

    nghim xc nh chiu ca phn ng

    gia 2 cp oxihakh Cu2+/Cu v

    Ag+/Ag

    Kt lun: Quy tc

    V. ngha ca dy thin cc chun ca

    kim loi:

    1. So snh tnh oxihakh

    MMnE /0 + cng ln th tnh oxiha ca cation

    Mn+ cng mnh v tnh kh ca kim loi M

    cng yu.

    Ngc li th in cc chun ca kim loi

    cng nhth tnh oxiha ca cation cng yu

    v tnh khca kim loi cng mnh.

    2. Xc nh chiu ca phn ng oxiha

    kh

    Hc sinh phn tch phn ng gia 2 cp

    oxihakh:

    Cu2+/Cu (E0 = +0,34V) v Ag+/Ag ( E0 =

    +0,80V) thy:

    Ion Cu2+c tnh oxi ha yu hn ion Ag+.

    Kim loi Cu c tnh khmnh hn Ag. Cp oxihakh Cu2+/Cu c th in cc

    chun nhhn ca cp oxiha khAg+/Ag.

    Kt lun:Cation kim loi trong cp oxiha

    K+/K

    2,93

    Na+/Na

    2,71

    Mg2+/Mg

    2,37

    Al +/Al

    1,66

    Zn +/Zn

    0,76

    Fe +/Fe

    0,44

    Ni +/Ni

    0,26

    Sn +/Sn

    0,14

    Pb +/Pb

    0,13

    2H+/H2

    0,00

    Cu +/Cu

    +0,34

    Ag+/Ag

    +0,80

    Au +/A

    +1,50

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 50 -

    Hc sinh tm hiu thm phn ng

    gia 2 cp oxihakh: Mg2+/Mg v

    2H+

    /H2Kt lun tng ttrn.

    3. Xc nh sut in ng chun

    ca pin in ha: Hng dn HS

    tnh sut in ng chun ca pin

    in ha.

    Th d: Sut in ng chun ca

    pin in ha ZnCu:

    E0pin = 0 //0

    22

    ZnZnCuCu EE ++

    = 0,34V (0,76V)

    = 1,10V

    4. Xc nh thin cc chun ca

    c

    p oxihakh

    :

    Bit: 0 ( ) 0,59pin Ni CuE V =

    V VECuCu

    34,00/2

    +=+

    Cc dng l cc Cu.

    Th : =+0 /2 NiNiE +0,34V0,59V = 0,25V

    kh c th in cc chun ln hn c th

    oxiha c kim loi trong cp c th in

    cc chun nhhn.2Ag+ + Cu Cu2+ + 2Ag

    Mg + 2H+ Mg2+ + H2

    3. Xc nh sut in ng chun ca pin

    in ha

    Sut in ng chun ca pin in ha (E0pin)

    bngthin cc chun ca cc dng tr

    i thin ccchun ca cc m.Sc in

    ng ca pin in ha lun l sdng.

    4. Xc nh th in cc chun ca cp

    oxihakh

    Ta c th xc nh c thin cc chun

    ca cp oxi hakh khi bit sut in ng

    chun ca pin in ha (E0pin) v thin cc

    chun ca cp oxi hakh cn li . Th d:

    vi pin (Ni-Cu) ta c: 00/

    0

    / 22 pinCuCuNiNiEEE = ++

    GIO N 12 NNG CAO

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 51 -

    BI:

    SIN PHN.

    I. MC TIU BI HC:

    1. Kin thc:Bit sin phn l g?

    Bit nhng ng dng ca sin phn trong cng nghip.

    Hiu s chuyn dch ca cc ion trong qu trnh in phn: NaCl

    nng chy, dung dch CuSO4vi in cc trv in cc tan.

    Hiu nhng phn ng ha hc xy ra trn cc in cc trong qu

    trnh in phn v vit c phng trnh in phn.

    2. Knng: Thc hin c mt sth nghim in phn n gin: pdd CuSO4

    vi anot trv anot tan.

    Bit xc nh tn cc in cc trong bnh in phn.

    Vit c phng trnh ha hc ca phn ng xy ra trn cc in cc

    v vit c phng trnh in phn.

    Gii c cc bi ton lin quan n sin phn.II. CHUN B:* Th nghim trc quan: Ha cht: dung dch CuSO40,5M

    Dng c: ng hnh chU, nt cc in cc, ngun in mt chiu

    cng vi bin tr, dy ni cc in cc.

    * Mt stranh vvsin phn.

    III.HOT NG GING DY:

    1. n nh lp:

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 52 -

    2. Dy bi mi:

    HOT NG CA GV HOT NG CA HSI. KHI NI

    M :

    Hot ng 1.

    Cho HS xem s hnh 5.10 yu

    cu HS m tbnh in phn, hot

    ng ca bnh in phn?

    Pt phn li: NaCl Na+ + Cl

    Cc dng: 2Cl(l) Cl2(k) + 2e

    Cc m: 2Na+

    (l) + 2e 2NaPhng trnh in phn:

    2NaCl 2Na + Cl2

    Ch phn bit cc ca pin in

    ho v cc ca bnh in phn.

    GV bsung cc thng tin.

    T yu cu HS rt ra kt lun v

    sin phn.

    I. KHI NI

    M

    * Thit bin phn gm c:

    - Bnh in phn

    - 2 in cc.

    Cc m v cc dng; ant c ni vi cc (+)

    ca ngun in mt chiu; catot c ni vi

    cc (-) ca ngun in mt chiu.

    * Hot ng ca bnh in phn:Khi c dng in mt chiu chy qua trn in

    cc dng (anot) xy ra s oxi ho, trn in

    cc m (catot) xy ra skh.

    Nu khi nim.

    Sin phn l qu trnh oxi ha khxy ra trn

    bmt cc in cc khi c dng in mt chiu

    i qua cht in li nng chy hoc dung dchcht in li.

    II. S IN PHN CC CHT

    IN LI

    Hot ng 2.

    Sdng phng php m thoi.

    GV yu cu HS.

    - Cho bit cc ion di chuyn trong

    dd nhthno ?

    - Phng trnh in phn v s

    in phn c biu din nh th

    II. SIN PHN CC CHT IN LI

    1. Sin phn NaCl nng chy.

    Khi c dng in mt chiu chy qua.

    Cc dng (anot) din ra soxi ha.

    Cc m (catot) din ra skh.

    Qu trnh oxi ho-khc biu din

    pnc

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 53 -

    no?

    - p MgCl2 nng chy tng t

    NaCl nng chyHot ng 5

    2. Sin phn dd CuSO4:

    a) in phn dd CuSO4vi cc

    in cc tr( graphit)

    Tho lun phiu hc tp s4

    Cu hi 1: Cu to ca bnh in

    phn.

    Cu hi 2:Hot ng ca bnh in

    phn v hin tng xy ra trong

    qu trnh in phn.

    Cu hi 3:Gii thch

    * Khi c dng in mt chiu chy

    qua cc ion trong dd dch chuyn

    nhthno ?

    * Cc qu trnh oxi ho-khdin ra

    cc in cc nh th no ? (xt

    thin cc chun).

    Na++ 1e Na 2Cl--2e Cl2

    Phng trnh in phn

    22 2dpncNaCl Na Cl +

    2. Sin phn dd CuSO4:

    a) in phn dd CuSO4vi cc in cc tr

    ( graphit)

    * Bnh in phn l ng chU, 2 in cc bng

    graphit, mt in cc m v mt in cc

    dng, dd cht in phn l CuSO4.

    * Khi cho dng in mt chiu i qua (c hiu

    in th1,3 V) c hin tng:

    - catot: kim loi Cu bm vo in cc.( cc

    m)

    - anot: Bt kh O2thot ra. ( cc dng )

    * Khi to nn mt in th gia hai in cc,

    cc ion SO42-

    di chuyn vanot. Cc ion Cu

    2+

    dichuyn vcatot.

    * Catot c th xy ra s kh ion Cu2+ hoc

    H2O.

    Xt thin cc chun:

    E0(Cu2+/Cu) = 0,34 V; E0(H2O/H2)= - 0,83 V.

    Nhvy ion Cu2+c tnh oxi ho mnh hn cc

    phn tH2O. V vy y xy ra skhcc ionCu2+thnh Cu bm trn catot:

    Cu2++ 2e Cu

    * anot: C thxy ra soxi ho cc ion SO42-

    hoc H2O.

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 54 -

    * Vit sin phn.

    * Vit phng trnh in phn.

    b/ in phn dd CuSO4 vi anot

    ng (anot tan) :

    Th nghim c m t nh hnh5.12. Hng dn hc sinh gii thch

    hin tng.

    Xt thin cc chun

    E0 (H2O/ O2) = -0,83 V; E0 (SO4

    2-/H2O) = 1,70

    V.Nh vy H2O c tnh kh mnh hn cc ion

    SO42- nn H2O d b oxi ha sinh ra kh O2

    anot:

    2H2O O2+ 4 H++ 4e

    * Cc (-) CuSO4 Cc (+)

    (H2O)

    Cu2+, H2O H2O, SO42-

    Cu2++ 2e Cu 2H2O O2+ 4 H++ 4e

    Phng trnh in phn

    dd4 2 2 2 42 uSO 2 2 2

    dpC H O Cu O H SO+ + +

    b/ in phn dd CuSO4 vi anot ng (anot

    tan)

    Hc sinh quan st th nghim v nhn xt:Anot tan ht, catot khkim loi Cu bm vo

    anot (+)Nguyn tCu boxi ha thnh ion

    Cu2+i vo dung dch: Cu (r) Cu2+(dd) + 2e.

    Anot dn dn b ha tan.

    catot ( ) ion Cu2+bi khthnh Cu bm trn

    bmt catot: Cu2+(dd)+ 2e Cu(r)

    Phng trnh in phn:Cu(r) + Cu

    2+(dd) Cu2+(dd)+ Cu (r)

    Anot Catot

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 55 -

    III. NG DNG CA S IN

    PHN

    Hot ng 6GV cho HS nghin cu SGK trnh

    by ng dng ca sin phn.

    Hot ng 7

    Tng kt bi hc, ra bi tp vnh.

    III. NG DNG CA SIN PHN

    1. iu chkim loi.

    2. iu chmt sphi kim (H2; O2...)3. iu ch mt s loi hp cht (KMnO4,

    NaOH, H2O, nc giaven...)

    4. Tinh chmt skim loi: Cu, Pb, Zn, Fe, Ag,

    Au...

    5. Min...

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 56 -

    GIO N 12 CBNBI:

    IU CHKIM LOII. Mc tiu ca bi hc.

    1.Kin thc.Bit nguyn tc chung viu chkim loi.

    Hiu cc phng php c vn dng iu ch kim loi. Mi phng phpthch hp vi siu chnhng kim loi no. Dn ra c nhng phn ng ho

    hc v iu kin ca phn ng iu chnhng kim loi cth.

    2.KnngBit gii cc bi ton iu chkim loi, trong c bi ton iu chkim loi

    bng phng php in phn khng hoc c sdng nh lut Faraay.

    II. Chun b

    Bng Dy in ho chun ca kim loi, Bng tun hon cc nguyn tho hc. HS xem li Bi 16nh.

    III. Hot ng dy hc

    Hot ng ca gio vin Hot ng ca hc sinh

    Hot ng 1

    GV thng bo, trong tnhin chc mt

    s t kim loi tn ti trng thi tdo,

    nh Au, Pt, Hg ... Hu ht cc kim loikhc u di dng cc hp cht ho hc

    (oxit, mui)., kim loi tn ti dng ion

    dng.

    GV t cu hi, nguyn tc iu chkim

    I. NGUYN TC IU CH KIM

    LOI.

    Thc hin skh:

    Mn++ ne M

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    loi l g ? Bng cch no c thchuyn

    nhng ion kim loi thnh kim loi tdo ?

    Hot ng 2.Cskhoa hc ca phng php nhit

    luyn iu chkim loi l g?

    - Dn ra mt s kim loi c iu ch

    bng phng php nhit luyn, vit

    phng trnh phn ng ho hc, iu

    kin ca nhng phn ng ny l g ?- Nhng kim loi no thng c iu

    chbng phng php nhit luyn?

    Hot ng 3. GV hng dn HSnghin cu SGK :

    - Csca vic iu chkim loi bng

    phng php thuluyn l g?

    - Dn th d v vit phng trnh phn

    ng ho hc.

    II. PHNG PHP IU CH KIM

    LOI

    1. phng php nhit luyn

    - C s: Kh nhng ion kim loi trong

    oxit nhit cao bng cc cht kh

    nh: C, CO, H2hoc Al, KL kim, KL

    kim th

    - V d:0

    0

    2 3 2

    2 2

    3 2 3t

    t

    Fe O CO Fe CO

    PbO H Pb H O

    + +

    + +

    - Dng trong CN, iu chnhng kim

    loi hot ng trung bnh.

    2.Phng php thuluyn

    - HS nu:Dng ho cht thch hp nhH2SO4,

    NaOH, NaCN tch hp cht ca kim

    loi ra khi qung. Sau dng cht kh

    khion kim loi thnh kim loi tdo

    - Th d:

    Dng Fe khion Cu2+trong dd mui

    ng

    Fe + CuSO4 FeSO4 + Cu

    2 2Fe Cu Fe Cu+ ++ +

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

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    - Phng php thu luyn c dng

    iu chnhng kim loi no?

    Hot ng 4.- Csca phng php in phn iu

    chkim loi l g?

    - Nhng kim loi no c th c iu

    chbng phng php in phn?

    C my loi in phn.?

    - Phng php nydng iu ch kim

    loi yu.

    3. Phng php in phn.

    HS trli:

    Phng php in phn dng nng lng

    ca dng in gy ra sbin i ho

    hc, l phn ng oxi ho - kh.

    - Phng php in phn c thiu ch

    c nhng kim loi hot ng mnhnh: K, Na, Ca, Mg, Al..

    a/ in phn nng chy

    V d: in phn Al2O3nng chy

    Catot (cc m): 3 3Al e Al+ +

    Anot (cc dng): 2 22 4O O e +

    Phng trnh in phn:

    2 3 22 4 3dpncAl O Al O +

    b/ in phn dung dch

    c thc dung iu chkim loi

    hot ng trung bnh hoc yu bng cch

    in phn mui ca chng.

    V d: in phn dung dch CuCl2iu chCu.

    Catot: 2 2Cu e Cu+ +

    Anot: 22 2Cl Cl e +

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 59 -

    - Dn th diu chkim loi hot ng

    trung bnh bng phng php in

    phn,th d iu ch Zn (nguyn liu,

    trng thi,s v phng trnh

    in phn).

    - Gio vin trnh bi nh lut Faraday

    Hot ng 5. Cng cbi hc.

    * GV cng cbi hc bng cch cho HS

    lm mt sbi tp sau :

    Bi tp 1 trong SGK. Bi tp c dn lm th dtrong

    Phng trnh in phn:

    dd2 2

    dpCuCl Cu Cl +

    - Th d: Sin phn dung dch

    ZnSO4

    Cc (-)

    Zn2+, H2O

    ZnSO4

    (dd)

    Cc (+)

    SO42-, H2O

    Zn2++2eZn 2H2O4H++O2+ 4e

    Phng trnh in phn:2 ZnSO4+ H2O 2 Zn + 2 H2SO4+ O2

    III. NH LUT FARADAY

    - Cng thc: Error! Objects

    cannot be created from editing field

    codes.

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 60 -

    PHN III. KT LUN V XUTI. KT LUN

    Vic ging dy ni dung kin thc in ha hc cho hc sinh trng phthng l ht

    sc quan trng v cn thit. Sau mt thi gian nghin cu v thc hin, kha lun ny

    hon thnh nhng vn sau:

    - Nghin cu cs l lun cc vn in ha hc trong chng trnh ha hc ph

    thng.

    - Nghin cu h thng ha nhng kin thc vin ha hc trng trung hc ph

    thng.

    - Nghin cu cu trc chng trnh cc bi dy chng trnh trung hc phthng.

    - Phn tch shnh thnh khi nim in ha hc tbc trung hc csn trung hc

    phthng thy y l phn kin thc quan trng cn phi nm vng.

    - Tin hnh iu tra mc nm kin thc in ha hc ca hc sinh khi lp 12,

    gm 2 ban: ban nng cao v ban cbn vi 4 lp: 2 lp 12 ban nng cao v 2 lp 12

    ban cbn trng THPT Lai Vung II. Sau khi xl kt quv thng k sliu, ti

    c nhn xt sau:+ Hc sinh nm c phn no kin thc cbn vin ha hc tuy nhin cha nm

    vng mt cch chc chn vnhng vn bn cht ca in ha hc.

    + Phn ln hc sinh cn tra lng tng khi p dng l thuyt in ha hc vo phn

    bi tp.

    Sau khi tm hiu csl lun v iu tra tnh hnh nm kin thc ca hc sinh vphn

    kin thc in ha hc, ti mnh dng a ra mt snhn xt v gii php nhm

    nng cao hiu quging dy phn kin thc ny. ng thi ti cng thit kmt sgio n c lin quan n kin thc vin ha ha hc trng THPT ca khi lp

    12.

  • 5/28/2018 LV Giang Day Mot So Noi Dung HH THPT - Dien Hoa Hoc

    - 61 -

    II. XUT V KIN NGH

    gip cho vic ging dy mn ha hc, c bit l vic hnh thnh v pht trin kin

    thc cbn m cthy l kin thc in ha hc t hiu qucao ti xin c mtskin nghsau:

    - i vi ni dung chng trnh ha hc phthng hin nay, khi lng kin thc a

    vo chng trnh l kh nhiu nhng thi gian ln lp li qu t nn gio vin khng c

    thi gian luyn tp, mrng kin thc cho hc sinh. V th, cn phi tng thm thi

    gian ln lp (stit).

    - Gio vin cn nn cho hc sinh nghin cu, xem xt cc vn ca kin thc trn

    nhiu kha cnh khc nhau, kt hp vi nhng l thuyt trc c hc.

    - i vi lnh o nh trng i hc, em xin c mt snghsau:

    + Tng cng tit tp ging sinh vin c thging dy tt ccc bi trong chng

    trnh THPT. Trong cc tit , gio vin nn gp phng php ging dy ca tng

    bi, tng phn cho sinh vin.

    + Tchc cc bui nghe bo co kinh nghim ca cc gio vin trng trung hc ph

    thng vphng php ging dy cc ni dung kh, tru tng chng hn nh: Pin in

    ha, thin ha, sut in ng, in phn in cc tan..nhm gip cho sinh vin

    c thm kinh nghim khi vo ngh.

    - i vi gio vin ang ging dy trng trung hc phthng hay cc sinh vin cn

    ang ngi trong gh nh trng u cn phi lun lun trao di kin thc chuyn mn

    ca mnh mt cch vng chc nht, t kt hp vi cc phng php dy hc thch

    hp truyn t kin thc cho hc sinh mt cch tt nht.

    - Trong thi gian gn y, ng dng cng nghthng tin trong dy hc ha hc ang

    c sdng mt cch rng ri. V thbn than mi gio vin, sinh vin u phi lun

    tm ti, hc hi, mmang tri thc ca mnh, tip cn vi cng nghhin i ca khoa

    hc kthut phc vcho vic ging dy ca mnh c tt nht.