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Calcular el % de volume sumergido y h1, h2, h3. Para h=h1+h2+h3.

N g/cm3

g/cm3 g/cm3 cm cm

1 2 3 D h

6.1 1.3 1.1 0. 12 !."

6.2 1." 1.0 0." 13 #."6.3 1.2 1.3 0.! 11 6."6. 1.! 1." 0.6 1 ".!

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Vtotal=

4. D

2.h

Vtotal=

4. (13 )2 . (7.5)=995.5 cm3

Vtotal=995.5 cm3

Vsum=90 . Vtotal

Vtotal=90

100.(995.5)2=895.95 cm3

H2O a una temperaturade6 C=1g /cm3

H2

O .Vsum=1.V1+2.V2+3.V3

895.95g=(1.5 ) (V1 )+1 (V2 )+0.5 (V3)

895.95g=(1.5 )(4 D2 . h1)+1(

4D

2. h2)+0.5( 4 D2. h3)

895.95g=

4D

2 [1.5h1+h2+0.5h3 ]

895.95 g=

4(13)2 [1.5h1+h2+0.5h3 ]

6.75 g

cm2=1.5h1+h2+0.5h3 ..(I)

h1+h2+h3=7.5

Para h2=1

c m

h1+h3=6.5 ..(II)

rem$laa&do h2 e& la 'cuacio& ()*

6.75 g

cm2=1.5h1+1+0.5h3

5.75 g

cm

2=1.5h1+0.5h3 ..(III)

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De las ecuacio&es ())* y ()))*

5.75 g

cm2=1.5h1+0.5h3

0.5(6.5)=h1+h3

5.75=1.5h1+0.5h3

3.25=0.5h10.5h3

h1=2.5cm

rem$laa&do h1 e& la ecuacio& ))

2.5+h3=6.5

h3=4cm