@let@token singularity formation in the 3d euler equations?

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Singularity formation in the 3D Euler equations? J. D. Gibbon : Imperial College London Levico Terme 2012 J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 1 / 40

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Singularity formation in the 3D Euler equations?

J. D. Gibbon : Imperial College London

Levico Terme 2012

J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 1 / 40

Summary of this talk

Themes1 Some elementary introductory remarks on the 3D incompressible

Euler equations & vortex stretching ;2 The Beale-Kato-Majda theorem & variations with an elementary

sketch-proof.3 The search for singularities : a list of numerical experiments.4 Vortex stretching in 3D incompressible, stratified, rotating Euler

equns ; including Ertel’s Theorem and the role of potentialvorticity q = ω · ∇θ – going up to the next derivative.

5 Euler with a passive scalar on a finite domain : a road to blow-up?6 Yet another look at singularity formation ; the very recent

numerical work of Kerr.7 Other models? 2D s-QG ; Restricted Euler ; Tetrad model.

J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 2 / 40

Vortex “stretching & folding” in Euler

For an incompressible fluid (div u = 0), the Euler equations are [1, 2]

DuDt

= −∇p withDDt

= ∂t + u · ∇

Alternative formulationWith the vorticity as ω = curl u, an alternative is (Sij = 1

2

(ui,j + uj,i

))

∂tu − u × ω = −∇(p + 1

2 u2)∂t ω = curl

(u × ω

), or

DωDt

= ω · ∇u = Sω .

Alignment of ω with e-vectors of S leads to “stretching & folding” of thevorticity field depending on the signs of λS(x , t). This processproduces the fine-scale “crinkles” in the vorticity field & may endin a finite time singularity.

J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 3 / 40

3D Euler: Why the interest in singularities?

Physically their formation may signify the onset of invicidturbulence & may be a mechanism for energy transfer to smallscales.Numerically they require special methods – a challenge to CFD.Mathematically their onset would rule out global existence altho’there are results on very weak solutions [3, 4, 5, 6, 7, 8, 9, 10].

Question : is there a single quantity that controls 3D Euler solns?

1 Like the 3D NS equations, it was thought originally that controlover the H1-norm (‖ω‖2) was sufficient – see Chorin [11].

2 Problem : solutions can remain bounded in ‖ω‖2 but not in ‖ω‖∞.3 This has been addressed through a combination of rigorous proof

(Beale-Kato-Majda Theorem [12]) and numerical experiment.

J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 4 / 40

Beale-Kato-Majda-Theorem (1984)

Theorem (BKM theorem [12])

Let u ∈ C([0, T ]; Hs) ∩ C1([0, T ]; Hs−1) be a global solution of the 3D Eulerequns in R3for s > 5/2. Suppose ∃ a time T ∗ such that the solution cannotbe continued to T = T ∗, then if T ∗ is the first such time∫ T∗

0‖ω(· , τ)‖∞ dτ =∞ .

Moreover, if∫ T

0 ‖ω(· , τ)‖∞ dτ <∞ for every T > 0 then ∃ a global solution ofthe Euler equations in [0, T ].

VariationsPonce (1985) has proved

∫ t0 ‖S(· , τ)‖∞ dτ <∞ controls solutions [14].

Ferrari (1993) used BCs u · n = 0 [15]. K-T (2000) [16] & Constantin [2, 17].

CorollaryIf a singularity ‖ω(· , t)‖∞ ∼ (T ∗− t)−β is observed in a numerical experiment,for the singularity to be genuine & not an artefact of the numerics then β ≥ 1.

J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 5 / 40

Sketch of BKM theorem proof I

Existence & uniqueness local in time goes back to Kato [13]. The BKM Thmdetermines conditions on whether regularity is lost. Proof by contradiction :assume

∫ T∗

0 ‖ω‖∞ dτ <∞. From this we prove solutions are regular at T ∗

thus contradicting the hypothesis that T ∗ is the first time regularity is lost.

Step 1 : Define Hn =∫V |∇

nu|2dV , then on R3 (or periodic) BCs

12 Hn = −

∫V∇nu · ∇n (u · ∇u +∇p) dV

= −∫V

u · ∇φdV −n−1∑k=0

∫V

Cn−1k (∇nu) (∇k+1u) (∇n−k u) dV

where φ = 12 |∇nu|2. With a Holder inequality 1

p + 1q = 1

2

12 Hn ≤ H1/2

n

n−1∑k=0

Cnk ‖∇k+1 u‖p‖∇n−k u‖q

Using the Gagliardo-Nirenberg inequalities : 1P = j

d + A( 1

r −md

)+ 1−A

Q

‖∇ju‖P ≤ c ‖∇mu‖Ar ‖u‖1−A

QJ. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 6 / 40

Sketch of BKM theorem proof II

Let θ = ∇u so with 1p = k

d + A(

12 − n−1

d

)we have

‖∇kθ‖p ≤ c ‖∇n−1θ‖A2 ‖θ‖1−A

Likewise with 1q = n−k−1

d + B(

12 − n−1

d

)we also have

‖∇n−k−1θ‖q ≤ c ‖∇n−1θ‖B2 ‖θ‖1−B

Note, however, that because 1p + 1

q = 12 , then A + B = 1, giving us

12 Hn ≤ H1/2

n

n−1∑k=0

Cnk H

12 (A+B)

n ‖∇u‖2−A−B∞

LemmaFor n ≥ 1, the Hn satisfy

12 Hn ≤ cn‖∇u‖∞Hn

J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 7 / 40

BKM proof III : A bound for ‖∇u‖∞ in terms of ‖ω‖∞

Step 2 : It is always true that ‖ω‖∞ ≤ ‖∇u‖∞ and

‖∇u‖p ≤ cp‖ω‖p 1 < p <∞ .

but for p =∞ BKM proved a difficult technical result [12] in R3

‖∇u‖∞ ≤ c ‖ω‖∞ (1 + ln H3) + ‖ω‖2 .

Thus for n = 3 we have

12 H3 ≤ c3‖ω‖∞H3 (1 + ln H3)

so integrating

H3(t) ≤ exp exp 2c3

∫ t

0‖ω‖∞ dτ .

Thus for n ≥ 1, each Hn is controlled by∫ t

0 ‖ω‖∞ dτ .

The proof in R3 & periodic BCs uses the Biot-Savart integral : doesn’t work forrigid boundaries u · n = 0 – see later the work of Ferrari [15].

J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 8 / 40

Numerical search for singularities

An up-dated version of a list originally compiled by JDG/Rainer Grauer

1) Morf, Orszag and Frisch (1980): [18, 19, 20] : complex timesingularities of the 3D Euler equations were studied usingPade-approximants. Singularity; yes.

2) Chorin (1982): [11] : Vortex–method. Singularity; yes.

3) Brachet, Meiron, Nickel, Orszag & Frisch (1983): [21, 22] : TaylorGreen i.c.s : Saw vortex sheets. Singularity; no.

4) Siggia 1984 [23] : Vortex–filament method. Singularity; yes.

5) Ashurst & Meiron (’87) [24] : Finite-diff methods. Singularity; yes.

6) Kerr & Pumir (’87) [25]: Pseudo-spectral method. Singularity; no.

7) Pumir & Siggia (1990): [26]: results from their adaptive grid methodshowed a tendency to develop quasi-two-dimensional structures withexponential growth of vorticity. Singularity; no.

J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 9 / 40

Singularity list contd ...

8) Bell & Marcus (1992): [27] : projection method with 1283 meshpoints ; amplification of vorticity by 6. Singularity; yes.

9) Brachet, Meneguzzi, Vincent, Politano & Sulem (1992) : [28]:pseudospectral code, Taylor–Green vortex, with a resolution of 8643.Achieved an amplification of vorticity by 5. Singularity; no.

10) Kerr (1993): [29, 30, 31] : Chebyshev polynomials with anti–parallelinitial conditions ; resolution 5122 × 256. Amplification of vorticity by18. Observed vorticity growth ‖ω‖L∞(Ω) ∼ (T ∗ − t)−1. Singularity; yes.

11) Grauer and Sideris (1991) [32] : 3D axisymmetric swirling flow.Singularity; yes. However, both E and Henderson independentlyconcluded : Singularity; no.

12) Boratav & Pelz (1994,95), [33, 34], Pelz & Gulak (1997) [36] andPelz (1997,2002) [35, 37] performed a series of 10243 grid-pointsimulations under Kida’s high-symmetry condition. Singularity; yes.

J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 10 / 40

Singularity list contd ...

13) The FDR-memorial issue for Pelz (2005):

1 Cichowlas and Brachet [39] : Singularity; no.2 Gulak and Pelz [40] : Singularity; yes.3 Pelz and Ohkitani [41] : Singularity; no.4 Kerr [42] : Singularity; yes.

14) Grauer, Marliani & Germaschewski (1998) [43] : using an adaptive meshrefinement of the Bell-Marcus i.c. [27] with 20483 mesh points, achieved anamplification of vorticity of 21. Singularity; yes.

15) Hou & Li (2006): [44] : a 1536× 1024× 3072 pseudo-spectral calculationagreed with Kerr (1993) until the final stage but growth slowed; vorticity grewdouble exponentially. Singularity; no.

16) Orlandi & Carnevale (2007) [45] : using Lamb dipoles as initialconditions, they performed a 10243 finite difference calculation with 2symmetry planes. Found a period of rapid growth of vorticity consistent with‖ω‖∞ ∼ (t∗ − t)−1: Singularity; yes.

J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 11 / 40

Singularity list contd ...

17) Kerr & Bustamante (2008) : Found growth of vorticity consistentwith ‖ω‖L∞(Ω) ∼ (T − t)−β for β > 1 : Singularity; yes.

18) Bustamante & Brachet 2012 [47] & [48] : Complex singularities andthe analyticity-strip method to investigate numerically theincompressible Euler singularity problem : Singularity; yes.

19) Kerr (2012) : see later [49] Singularity; yes.

20) Pauls, Matsumoto, Frisch & Bec (2006): [50]: a study of complexsingularities of the 2D Euler equations and contains a good list ofreferences for the student.

21) Further refs :1 See also the refs in JDG [51] and Bardos & Titi [52]2 Other refs [53, 54, 55, 56, 57, 58].

J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 12 / 40

Direction of vorticity : the work of CFM & DHY

a) Constantin, Fefferman & Majda (1996) [17, 59] discussed the ideaof vortex lines being “smoothly directed” in a region of greatestcurvature : no singularity at time T if the velocity is finite in (B4ρ) &

limt→T

supW0

∫ t

0‖∇ξ(· , τ)‖2L∞(B4ρ) dτ <∞

where ξ(x , t) = ω(x , t)/|ω(x , t)|.

Theorem (Deng-Hou-Yu [60])

Let x(t) be a family of points such that for some c0 > 0 the vorticity satisfies|ω(x(t), t)| > c0Ω(t). Assume that for all t ∈ [0,T ) there is another point y(t)on the same vortex line as x(t), s.t. the unit vorticity ξ(x , t) along the vortexline c(s) between x(t) and y(t) is well-defined. If we further assume that∫ y(t)

x(t)(∇ · ξ)(c(s), t) ds ≤ C

for some const C &∫ T

0 |ω(y(t), t)| dt <∞ then no blowup occurs up to timeT .J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 13 / 40

Direction of vorticity : DHY2

Theorem (Deng-Hou-Yu [61])

Take the arc length L(t) of a vortex line with unit normal n & curvature κ. Noblow-up can occur at time T if

1 Uξ(t) + Un(t) . (T − t)−A A + B = 1,

2 M(t)L(t) ≤ const > 0

3 L(t) & (T − t)B .

Uξ(t) = maxx,y [(u · ξ)(x , t)− (u · ξ)(y , t)] & Un(t) = maxLt [(u · n] &

M(t) ≡ max(‖∇ · ξ‖L∞(Lt ), ‖κ‖L∞(Lt )

)Grafke & Grauer (2012) [62] have investigated these two thms numerically :for Kida’s vortex dodecapole i.c., they injected Lagrangian tracer particles tomonitor geometric properties of vortex line segments. From high resolutionadaptive numerical simulations they concluded : Singularity ; no.

J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 14 / 40

3D incompressible, stratified, rotating Euler equations

The 3D Euler equations for an incompressible, stratified, rotating flow(Ω = k Ω) in terms of the velocity field u(x , t) and temperature θ are

DuDt

+ 2 (Ω× u)︸ ︷︷ ︸rotation

+ k θ︸︷︷︸buoyancy

= −∇p ,

DθDt

= 0 .

Information about ∇θ is needed to determine how θ(x , t) mightaccumulate into large local concentrations.

Evolution of ωrot

Now consider the vorticity ω = curl u for which ωrot = ω + 2Ω satisfies

Dωrot

Dt= ωrot · ∇u +∇⊥θ ∇⊥ =

(−∂y , ∂x , 0

)J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 15 / 40

The 3D Euler equations and Ertel’s Theorem

Theorem (Ertel’s Theorem (1942) [63])

If ωrot (x , t) satisfies the 3D rotating Euler equations then any arbitrarydifferentiable µ(x , t) satisfies

DDt

(ωrot · ∇µ) = ωrot · ∇(

DµDt

).

Remark : The operations[D

Dt , ωrot · ∇]

= 0 commute.

Proof : Ertel (1942) [63]; Truesdell & Toupin (1960) [64] ; Hoskins et al (1985)[65] ; Ohkitani (1993) [66] ; Kuznetsov & Zakharov (1997) [67] ; Viudez (2001)[68].

DDt

(ωrot · ∇µ) =

(Dωrot

Dt− ωrot · ∇u

)· ∇µ+ ωrot · ∇

(DµDt

)

J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 16 / 40

Potential Vorticity for rotating stratified Euler

Potential Vorticity is defined as

q = ωrot · ∇θ withDθDt

= 0 .

PV is important in GFD : – Hoskins, McIntyre, & Robertson (1985) [65].

TheoremBoth q and θ are materially conserved quantities.

Proof.Take µ(x , t) = θ, and thus

DqDt

=

(Dωrot

Dt− ωrot · ∇u

)· ∇θ + ωrot · ∇

(DθDt

)= ∇⊥θ · ∇θ = 0 .

Thus, because θ is a materially conserved quantity so is q.

J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 17 / 40

Evolution of the B-field

TheoremThe vector B = ∇q ×∇θ satisfies

∂t B = curl (u ×B) ⇒ DBDt

= B · ∇u .

Kurgansky (’87) [69, 70, 71], Yahalom (’96) [72] & JDG-Holm [73, 74]

Proof : see JDG & Holm [73, 74].

∂tB = ∂t (∇q)× (∇θ) + (∇q)× ∂t (∇θ)

= −u · ∇(∇q) + (∇q) · ∇u + (∇q)× ω × (∇θ)

−(∇q)× u · ∇(∇θ) + (∇θ) · ∇u + (∇θ)× ω= −u · ∇B + (∇q)(ω · ∇θ)− (∇θ)(ω · ∇q)

+(∇θ)× (∇q · ∇u)− (∇q)× (∇θ · ∇u)

= curl (u ×B)

J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 18 / 40

Why are we not surprised? – JDG & D2H : J. Phys. A, 43, (2010) 172001

Consider B = ∇q ×∇θ where DqDt = 0 and Dθ

Dt = 0

AAAK

B

θ = const

q = const

∇θ

∇q

B is tangent to the intersection-curve of q = const and θ = const

DBDt

= B · ∇u

which is the equn for the stretching of a line-element B ≡ δ`.

J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 19 / 40

Stretching & folding in the B-field

Because div u = 0 and divB = 0 we have

curl (u ×B) = B · ∇u − u · ∇B

∂t B = curl (u ×B) orDBDt

= B · ∇u ,

The same as for ω & the magnetic B-field in MHD (Moffatt 1978 [75]).

Stretching & folding properties(i) Thus all the “stretching & folding” properties associated with ωor magnetic field-lines lift over to B even though B contains ω,∇ω, ∇θ and ∇2θ in various forms of projection.

(ii) Moreover, for any surface S(u) moving with the flow u, one finds

ddt

∫S(U)

B · dS = 0 .

J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 20 / 40

Helicity in the B-field

Now define the vector potential A such that B = curlA where

A = 12

(q∇θ − θ∇q

)+∇ψ .

The helicity H that results from this definition,

H =

∫VA ·B dV =

∫V

div(ψB)

dV =

∮∂VψB · n dS ,

measures the knottedness of the B field-lines. H = 0 for homog-BCsbut H 6= 0 for realistic topographies. The boundaries may therefore bean important generating source for helicity, thus allowing the formationof knots & linkages in the B-field.

See Ohkitani (2007) [76] for a discussion of helicity-free vorticity fields.

ω = ∇f ×∇g

with Df/Dt = 0 and Dg/Dt = 0.J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 21 / 40

Blow-up with a passive scalar? I

Let us consider Euler with a passive scalar θ : this could represent atracer-dye or some dust added to the flow. What do we know?

1 The potential vorticity q = ω · ∇θ is also passive : thus we have

DθDt

= 0DqDt

= 0

2 B = ∇q ×∇θ satisfies

DBDt

= B · ∇u

3 Do null points (zeros) occcur in |B|? Firstly, i.d. for |B| must befree of null points : then a null can potentially develop either bymaxima or minima developing in θ or q or if ∇q and ∇θmomentarily align at some point.

J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 22 / 40

BKM Theorem on a finite domain

The proofs for V ≡ R3 require FTs & the Biot-Savart integral which are noteasily adaptable to BCs u · n|∂ V = 0. Ferrari [15] circumvented thisdifficulty to prove these results for BCs u · n|∂ V = 0.

Theorem (Ponce [14], Ferrari [15])

There exists a global solution of the 3D Euler equations for s ≥ 3u ∈ C([0, ∞]; Hs) ∩ C1([0, ∞]; Hs−1) if, for every T > 0∫ T

0‖S(τ)‖L∞(R3) dτ <∞ .

Conversely, if there exists a time T for which∫ T

0‖S(τ)‖L∞(R3) dτ =∞ ,

then limt→T ‖S(t)‖L∞(R3) =∞.

J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 23 / 40

The B-theorem

We consider a finite domain V ⊂ R3 with boundary conditions

u · n|∂ V = 0 .

Theorem (JDG & Titi 2012 ArXiv: 1211.3811v1 [77])

On a smooth domain V ⊂ R3 with boundary conditions u · n|∂ V = 0,with initial data for which |B(x , 0)| > 0 and ‖B (x ,0) ‖L∞(V) <∞, ifthere exists a smooth solution of the 3D Euler equations in the interval[0, t∗), then at the earliest time t∗ at which |B(x , t∗)| = 0∫ t∗

0‖S‖L∞(V) dτ =∞ .

Conversely, if∫ T

0 ‖S‖L∞(V) dτ <∞ in any interval [0, T ] then |B(x , t)|cannot develop a null point for t ∈ [0, T ].

J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 24 / 40

Proof of the B-theorem : I

On [0, t∗) take the scalar product with B, where |B| = B

12

D(B2)

Dt= B · ∇u ·B ⇒ 1

2D| ln B|2

Dt= (ln B)

(B · S · B

).

Now multiply by | ln B|2(m−1) for 1 ≤ m <∞

12m

D| ln B|2m

Dt= | ln B|2(m−1)(ln B)

(B · S · B

).

Integrate, invoke the Divergence Thm/BCs & use Holder’s inequality

12m

ddt

∫V| ln B|2mdV ≤

∫V|ln B|2m−1 |S| dV

≤(∫V| ln B|2mdV

) 2m−12m(∫V|S|2mdV

) 12m

.

J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 25 / 40

Proof of the B-theorem : II

Using the standard notation ‖X‖Lp(V) =(∫V |X |

pdV)1/p

ddt‖ ln B‖L2m(V) ≤ ‖S‖L2m(V)

which integrates to

‖ ln B(t)‖L2m(V) ≤ ‖ ln B(0)‖L2m(V) +

∫ t

0‖S(τ)‖L2m(V) dτ .

Since V is bounded we take the limit m→∞ to obtain

‖ ln B(t)‖L∞(V) ≤ ‖ ln B(0)‖L∞(V) +

∫ t

0‖S(τ)‖L∞(V) dτ .

If |B| has no zero in its i.d. the log-singularity at |B| = 0 causes theLHS to blow up at t∗ thus forcing

∫ t∗0 ‖S‖L∞(V) dτ →∞ as t → t∗.

If∫ T

0 ‖S‖L∞(V) dτ remains finite in an interval t ∈ [0, T ] then no nullcan develop in B.

J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 26 / 40

Example of i.d. with no null points : I

Is it easy to construct i.d. such that |B(x , 0)| > 0? We find a simpleexample of a set of i.d. u on a finite domain V ⊂ R3 from initial data onω and θ such that |B| > 0 and ‖B‖L∞(V) <∞ for the elliptic system

curl u = ω , div u = 0 , u · n|∂ V = 0 .

Consider ω = (1, 1, 1)T : ∃ a vel-field v = (z, x , y)T which satisfies

div v = 0 and curl v = (1,1,1)T

but we cannot be sure that it satisfies v · n = 0 for any V : modify thisto satisfy the BCs by introducing some potential φ such that

u = v +∇φ .Note that curl u = (1, 1, 1)T . φ must satisfy the Neumann boundaryvalue problem

∆φ = 0 ,∂φ

∂n

∣∣∣∣∂ V

= −(z, x , y)T · n ,

which always has a solution on any smooth domain V.J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 27 / 40

Example of i.d. with no null points : II

Thus we have been able to construct a velocity field u correspondingto ω = (1, 1, 1)T , that satisfies the boundary conditions. For simplicity,now choose

θ = 12 (x2 + y2 + z2)

and calculate q, ∇q and ∇θ

q = x + y + z , ∇θ = (x , y , z)T , ∇q = (1, 1, 1)T ,

and then B

B = (z − y , x − z, y − x)T .

Note that |B| = 0 only on the straight line x = y = z = t for t ∈ R.Hence |B| > 0 on any smooth, finite domain V that avoids this line :this is enough to achieve our goal.

J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 28 / 40

Another new approach to Euler blow up : JDG [78]

Define the set of frequencies based on L2m-norms of ω = curl u

Ωm(t) =

(L−3

∫V|ω|2mdV

)1/2m

1 ≤ m ≤ ∞ .

Holder’s inequality insists that Ωm ≤ Ωm+1. The Euler equations areinvariant under : x ′ = εx ; t ′ = ε2t ; u = εu′ ; p = ε2p′. If the domainlength L is also re-scaled as L′ = εL then Ωm re-scales as Ωm = ε2Ω′m.If, however, L is not re-scaled but kept fixed then Ωm re-scales as

Ωαmm = εΩ

′ αmm , αm =

2m4m − 3

.

Therefore definine the the set of dimensionless quantities

Dm(t) =($−1

0 Ωm

)αm, 1 ≤ m ≤ ∞ .

Instead of $ 0 = νL−2 for NS, use $ 0 = ΓL−2 where Γ is the circulationaround some i.d.

J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 29 / 40

A remark on the Dm

Consider the boundedness of the integral∫ t

0D2

m dτ (∗)

based on the continuum lying between

D1 = $−20 L−3

∫V|ω|2 dV . . . → . . . D∞ =

($−1

0 ‖ω‖∞)1/2

.

1 When m = 1 (α1 = 2) the criterion (*) is exactly a NS-criterion forregularity ; namely

∫ t0 H2

1 dτ <∞.2 When m =∞ (α∞ = 1

2 ) the criterion (*) is exactly the BKMcriterion for Euler regularity ; namely

∫ t0 ‖ω‖∞ dτ <∞.

J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 30 / 40

A differential inequality for Dm : I

Lemma (JDG [78])

Provided solutions of the three-dimensional Euler equations exist, for1 ≤ m <∞ the Dm formally satisfy the following differential inequality

Dm ≤ cm $ 0

(Dm+1

Dm

)ξm

D3m , ξm = 1

2 (4m + 1) .

Proof : Ωm obeys

L3Ω2m−1m Ωm =

12m

ddt

∫|ω|2mdV

≤∫ t

0ω2m|∇u|dV

≤(∫|ω|2mdV

) 12(∫|ω|2(m+1)dV

) m2(m+1)

(∫|∇u|2(m+1)dV

) 12(m+1)

≤ L3c1,m Ωm+1m+1 Ωm

m

J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 31 / 40

A differential inequality for Dm : II

In the above we have used ‖∇u‖p ≤ cp‖ω‖p, for 1 ≤ p <∞ so thecase p =∞ is excluded because ‖∇u‖∞ ≤ c ‖ω‖∞ (1 + ln H3).

Ωm ≤ c1,m

(Ωm+1

Ωm

)m+1

Ω2m , 1 ≤ m <∞ .

We wish to convert the inequality to one in terms of Dm(Ωm+1

Ωm

)m+1

Ωm = $ 0

(Dm+1

Dm

) m+1αm+1

D2m = $ 0

(Dm+1

Dm

) 12 (4m+1)

D2m

having used the fact that(1

αm+1− 1αm

)βm = 2 , βm = 4

3 m(m + 1) .

Substitution completes the proof.

J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 32 / 40

1st route of integration

Firstly if a finite time singularity is suspected then divide by D3−εm with

0 ≤ ε < 2 to obtain

[Dm(t)]2−ε ≤ 1[Dm(t0)]−(2−ε) − F1,ε(t)

where (ξm = 12 (4m + 1))

F1,ε(t) = cm(2− ε)$ 0

∫ t

t0

(Dm+1

Dm

)ξm

Dεm dτ .

For instance, for ε = 0 we have

D2m(t) ≤ 1

[Dm(t0)]−2 − F1,0(t)

J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 33 / 40

1st route of integration contd ...

where F1,0 ≡ Fm is defined as

Fm(t) = 2cm$ 0

∫ t

t0

(Dm+1

Dm

)ξm

dτ .

A singularity in the upper bound of the inequality is not necessarilysignificant. What is more significant is whether the solution tracks thissingular upper bound. This suggests the following numerical test :

1 Is F1,0 = Fm linear in t?2 If so, then test whether

D2m (Tc,m − t)→ Cm with Tc,m → Tc

uniformly in m? If such behaviour occurs it suggests, but does notprove, that the Dm may be blowing up close to the singular upperbound.

J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 34 / 40

Kerr’s initial condition [49]

Figure: The figure shows the NS evolution of very long anti-parallel vortices with a localizedperturbation in a turbulent flow at three times. The first at t = 16, which is the time of the firstreconnection, is shown on the left ; t = 96 lies in the middle and is the time of the second set ofreconnections. The formation of the first vortex rings at t = 256 is on the right and shows thecumulation of this process after two sets of secondary reconnections have released two sets ofvortex rings. The full domain in the vortical y direction reaches from y = −16π ≈ −50 toy = 16π ≈ 50. The partial domains shown are |y | ≤ 10 for t = 16, 0 ≤ y ≤ 25 for t = 96 and0 ≤ y ≤ 16π ≈ 50 for t = 256. The inset of the upper left vorticity near y = 0 at t = 16demonstrates that on the y = 0 symmetry plane the usual head-tail configuration forms.

J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 35 / 40

The recent results of Kerr I [49]

Figure: Fm =∫$0(Dm+1/Dm)ξm dt for Euler anti-parallel i.d. with resolution

1024× 512× 4096. The observed ordering & linear increase as m→∞would permit at least super-exponential growth of the Dm for both Euler & NSup to t = 14.5.

J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 36 / 40

The recent results of Kerr II [49]

Figure: Estimated the singular time of Dm : Tm(t) = (d log D2m/dt)−1 + t . Only

m odd are shown to reduce clutter & a curve with t = t is added to clarify thetrend. Linear extrapolations to t = 15.75 of the m > 1 curves, based on thelast two values, have dashed lines. These extra polations appear to becrossing the t = t line at about Tc ≈ 15.8.

J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 37 / 40

Other models? Connection with the 2D surface QG equations?

Let q = z = const and θ = const be material surfaces :

B = ∇z ×∇θ = k ×∇θ = −∇⊥θ .

In R2 if u is chosen as u = ∇⊥ψ with θ = −(−∆)1/2ψ, then

DBDt

= B · ∇u B = −∇⊥θ

are the 2D surface QG equations discussed by Constantin, Majda & Tabak(1994) [79] – conjectured that fronts might be finite time singularities.

1 Ohkitani & Yamada (1997) [80] found numerically growth that wasdouble exponential in time ;

2 Confirmed by Constantin, Nie & Schorghofer (1998) [81] ;3 Cordoba (1998) [82] then showed the absence of a singularity for a

simple hyperbolic saddle ;4 See Cordoba, Fefferman & Rodrigo (2004) [83] & Rodrigo (2004).

J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 38 / 40

Other models? Restricted Euler equations – modelling the Hessian P

The gradient matrix Mij = ∂uj/∂x i satisfies (tr P = −tr (M2))

DMDt

+ M2 + P = 0 , tr M = 0 .

Attempts have been made to model the Lagrangian averaged pressureHessian by a constitutive closure. Idea goes back to :

Leorat (1975) [84] ; Vieillefosse (1984) [85] ; Cantwell (1992) [86]

who assumed that the Eulerian pressure Hessian P = p,ij is isotropic. Thisresults in the restricted Euler equations with

P = − 13 I tr (M2) , tr I = 3 .

Constantin’s distorted Euler equations (1986) [87] : With the Lagrangianpath map a 7→ X (a, t), N = M X Euler equns are re-written as

∂N∂t

+ N2 + Q(x , t)Tr(N2) = 0 , Qij = RiRj Ri = (−∆)−1/2∂i

‘Distorted Euler equns’ : replace Q(t) by Q(0)⇒ rigorous blow up.J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 39 / 40

Other models? The Tetrad model

A : Tetrad model of Chertkov, Pumir & Shraiman (1999) [88], developed byChevillard & Meneveau (2006) [89] : has the assumption that the Lagrangianpressure Hessian is isotropic.

For P to transform as a Riemannian metric & satisfy tr P = −tr (M2)

P = − Gtr G

tr (M2) , G(t) = I ⇒ restricted Euler .

tr P = −tr (M2) is satisfied for any choice of G = GT (chosen flow-law)

P = −[ N∑β=1

cβGβ

tr Gβ

]tr (M2) , with

N∑β=1

cβ = 1 ,

B : Constantin, Lax & Majda (1985) [90] : 1D vorticity model :

ωt = ωπ−1p.v .∫ ∞−∞

ω(y) dyx − y

u(x , t) =

∫ ∞−∞

ω(y , t)dy

where ω blows up but u remains finite.J. D. Gibbon : Imperial College London () Singularity formation in the 3D Euler equations? Levico Terme 2012 40 / 40

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