lesson 31 flowchart paragraph proofs. prove thm. 6-3: linear pair thm. given: svu is a straight...
DESCRIPTION
GIVEN: ∠ SVU is a straight angle PROVE: ∠ SVT & ∠ TVU are supplementary ∠ SVT & ∠ TVU are supplementary Def. of Supplementary Angles m ∠ SVT + m ∠ TVU = 180° Transitive Prop. of Equality m ∠ SVU = m ∠ SVT + m ∠ TVU Angle Add. Post. m ∠ SVU = 180° Def. of Straight Angle ∠ SVU is a straight angle GivenTRANSCRIPT
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Lesson 31FLOWCHART & PARAGRAPH PROOFS
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Prove Thm. 6-3: Linear Pair Thm.GIVEN: ∠SVU is a straight anglePROVE: ∠SVT & ∠TVU are supplementarySTATEMENTS
1. ∠SVU is a straight angle
2. m SVU = 180°∠3. m SVU = m SVT + m TVU∠ ∠ ∠4. m SVT + m TVU = 180°∠ ∠5. ∠SVT & TVU are supplementary∠
REASONS1. Given
2. Def. of Straight Angle
3. Angle Add. Post.
4. Transitive Prop. of Equality
5. Def. of Supplementary Angles
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GIVEN: ∠SVU is a straight anglePROVE: ∠SVT & ∠TVU are supplementary
∠SVT & TVU are ∠supplementary
Def. of Supplementary Angles
m SVT + m TVU = ∠ ∠180°
Transitive Prop. of Equality
m SVU = m SVT + m TVU∠ ∠ ∠Angle Add. Post.
m SVU = 180°∠Def. of Straight Angle
∠SVU is a straight angleGiven
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Prove Thm 10-1: Alt. Int. Angles Thm.GIVEN: a ∥ cPROVE: ∠ 11 ≅ ∠ 14STATEMENTS
1. a c∥2. ∠ 10 14≅ ∠3. ∠ 10 11≅ ∠4. ∠ 11 14≅ ∠
REASONS
1. Given2. Corresponding Angles Post.3. Vert. Angles are Congruent4. Transitive Prop. of ≅
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GIVEN: a ∥ cPROVE: ∠ 11 ≅ ∠ 14
∠ 11 14≅ ∠Transitive Prop. of
≅
∠ 10 11≅ ∠Vert. Angles are
Congruent
∠ 10 14≅ ∠Corresponding
Angles Post.
a c∥Given
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GIVEN: PROVE: ΔMPL ≅ ΔMPN
STATEMENTS
1.
2.
3.
4.
5. ΔMPL ≅ ΔMPN
REASONS
1.Given
2.Given
3.Def. of Angle Bisector
4.Reflexive of ≅5.SAS
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GIVEN: PROVE: ΔMPL ≅ ΔMPN
ΔMPL ≅ ΔMPNSAS
Given
Reflexive of ≅
GivenGiven
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GIVEN: PROVE: ΔRTQ ≅ ΔSTQ
STATEMENTS
1.
2.
3. ΔRTQ ≅ ΔSTQ
REASONS
1.Given
2.Thm 5-4 ( lines, form ’s)┴ ≅ ∠3.Def. of Segment Bisector
4.Reflexive of ≅5.SAS
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GIVEN: PROVE: ΔRTQ ≅ ΔSTQ
ΔRTQ ≅ ΔSTQSAS
Reflexive of ≅
Def. of Segment BisectorGiven
Thm 5-4 Given
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Use a Paragraph ProofGIVEN: PROVE: ΔRTQ ≅ ΔSTQ
Since is the perpendicular bisector of , it can be
concluded that is congruent to by theorem 5-4.
The given also means that is congruent to by the
definition of segment bisector. Using the reflexive
property of congruence is congruent . Therefore by
the Side-Angle-Side postulate, ΔRTQ is congruent
to ΔSTQ.
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Conclusion When you are doing proofs, I will give you the option of which format you want to use.
2-Column
Flow Chart
Paragraph
I just want you to do the proof. If one format seems easier for you, then use it. Just keep in mind you still must do the same in all styles. A statement must always be backed up by reasoning.
Working with proofs, writing and reading them, will prepare you for:
Lesson 45: Coordinate Proofs
Lesson 48: Indirect Proofs
Which means skipping proofs could make these later lessons more challenging