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Chapter 10 Fluids

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Page 1: Lecture Ch 10

Chapter 10

Fluids

Page 2: Lecture Ch 10

Units of Chapter 10•Phases of Matter

•Density and Specific Gravity

•Pressure in Fluids

•Atmospheric Pressure and Gauge Pressure

•Pascal’s Principle

•Measurement of Pressure; Gauges and the Barometer

•Buoyancy and Archimedes’ Principle

Page 3: Lecture Ch 10

Units of Chapter 10

•Fluids in Motion; Flow Rate and the Equation of Continuity

•Bernoulli’s Equation

•Applications of Bernoulli’s Principle: from Torricelli to Airplanes, Baseballs, and TIA

Page 4: Lecture Ch 10

10-1 Phases of Matter

The three common phases of matter are solid, liquid, and gas.

A solid has a definite shape and size.

A liquid has a fixed volume but can be any shape.

A gas can be any shape and also can be easily compressed.

Liquids and gases both flow, and are called fluids.

Page 5: Lecture Ch 10

10-2 Density and Specific Gravity

The density ρ (lower case Greek rho) of an object is its mass per unit volume:

The SI unit for density is kg/m3. Density is also sometimes given in g/cm3; to convert g/cm3 to kg/m3, multiply by 1000.

Water at 4°C has a density of 1 g/cm3 = 1000 kg/m3.

The specific gravity of a substance is the ratio of its density to that of water.

SG = (ρ/ρwater) = 10-3ρ

(10-1)

Page 6: Lecture Ch 10

10-3 Pressure in Fluids

Pressure is defined as the force per unit area.

Pressure is a scalar; the units of pressure in the SI system are pascals:

1 Pa = 1 N/m2

Pressure is the same in every direction in a fluid at a given depth; if it were not, the fluid would flow.

Page 7: Lecture Ch 10

10-3 Pressure in Fluids

Also for a fluid at rest, there is no component of force parallel to any solid surface – once again, if there were the fluid would flow.

Page 8: Lecture Ch 10

10-3 Pressure in Fluids

The pressure at a depth h below the surface of the liquid is due to the weight of the liquid above it. We can quickly calculate:

This relation is valid for any liquid whose density does not change with depth.

At rest ∑Fy = 0

F - mg = 0 F = mg

F = mg = ρVg, V =Ah F = ρAhg

P F/A = ρgh

Pressure at depth h (fluid at rest)

P = ρgh

Page 9: Lecture Ch 10

Section 10-4: Atmospheric Pressure• Earth’s atmosphere: A fluid.

– But doesn’t have a fixed top “surface”!

• Change in height h above Earth’s surface:

Change in pressure: P = ρgh• Sea level: PA 1.013 105 N/m2

= 101.3 kPa 1 atm – Old units: 1 bar = 1.00 105 N/m2

• Physics: Cause of pressure at any height:

Weight of air above that height!

This pressure does not crush us, as our cells maintain an internal pressure that balances it.

Page 10: Lecture Ch 10

Show Clip

Page 11: Lecture Ch 10

10-4 Atmospheric Pressure and Gauge Pressure

Most pressure gauges measure the pressure above the atmospheric pressure – this is called the gauge pressure.

The absolute pressure is the sum of the atmospheric pressure and the gauge pressure.

Page 12: Lecture Ch 10

Conceptual Example 10-4

P = ?

Pressure on A:

Pdown = P + Pmg

Pup = PA

At rest ∑Fy = 0

Pup = Pdown

or PA = P + Pmg

P = PA - Pmg < PA

So, air pressure holds

fluid in straw!

Page 13: Lecture Ch 10

10-5 Pascal’s PrincipleIf an external pressure is applied to a confined fluid, the pressure at every point within the fluid increases by that amount.

This principle is used, for example, in hydraulic lifts and hydraulic brakes.

Page 14: Lecture Ch 10

10-6 Measurement of Pressure; Gauges and the Barometer

There are a number of different types of pressure gauges (Most use P - PA = ρgh = PG = gauge pressure). This one is an open-tube manometer. The pressure in the open end is atmospheric pressure; the pressure being measured will cause

the fluid to rise until the pressures on both sides at the same height are equal.

Page 15: Lecture Ch 10

10-6 Measurement of Pressure; Gauges and the Barometer

Here are two more devices for measuring pressure: the aneroid gauge and the tire pressure gauge.

Page 16: Lecture Ch 10

Various Pressure Units

• Gauge Pressure: PG = ρgh

Alternate unit of pressure: Instead of calculating ρgh, common to use standard liquid

(mercury, Hg or alcohol, where ρ is standard) & measure h

Quote pressure in length units! For example:

“millimeters of mercury” mm Hg

For h = 1 mm Hg = 10-3 m Hg

ρmercury gh = (1.36 104 kg/m3) (9.8 m/s2)(10-3 m)

= 133 N/m2 = 133 Pa 1 Torr

(another pressure unit!)

mm Hg & Torr are not proper SI pressure units!

Page 17: Lecture Ch 10

10-6 Measurement of Pressure; Gauges and the Barometer

This is a mercury barometer, developed by Torricelli to measure atmospheric pressure. The height of the column of mercury is such that the pressure in the tube at the surface level is

1 atm.

Therefore, pressure is often quoted in millimeters (or inches) of mercury.

Page 18: Lecture Ch 10

10-6 Measurement of Pressure; Gauges and the Barometer

Any liquid can serve in a Torricelli-style barometer, but the most dense ones are the most convenient. This barometer uses water.

Page 19: Lecture Ch 10

Prob. 17: (A variation on Example 10-2) Tank depth = 5 mPipe length = 110 mHill slope = 58º

Gauge Pressure PG = ?Height water H shoots from broken pipe at bottom?

Height of water level intank from house level: h = (5 + 110 sin58º) = 98.3 mPG = ρwatergh = (1103 kg/m3)(9.8 m/s2)(98.3 m) = 9.6105 N/m2

Conservation of energy: H = h = 98.3 m(Neglects frictional effects, etc.)

Page 20: Lecture Ch 10

10-7 Buoyancy and Archimedes’ Principle

This is an object submerged in a fluid. There is a net force on the object because the pressures at the top and bottom of it are different.

The buoyant force is found to be the upward force on the same volume of water:

Page 21: Lecture Ch 10

Archimedes Principle The total (upward) buoyant force FB on an object of

volume V completely or partially submerged in a fluid with density ρF:

FB = ρFVg (1)

ρFV mF Mass of fluid which would take up same volume as object, if object were not there. (Mass of fluid that used to be where object is!)

Upward buoyant force

FB = mFg (2)

FB = weight of fluid displaced by the object!

(1) or (2) Archimedes Principle

Proved for cylinder. Can show valid for any shape

Page 22: Lecture Ch 10

10-7 Buoyancy and Archimedes’ Principle

The net force on the object is then the difference between the buoyant force and the gravitational force.

Page 23: Lecture Ch 10

10-7 Buoyancy and Archimedes’ Principle

If the object’s density is less than that of water, there will be an upward net force on it, and it will rise until it is partially out of the water.

Page 24: Lecture Ch 10

10-7 Buoyancy and Archimedes’ Principle

For a floating object, the fraction that is submerged is given by the ratio of the object’s density to that of the fluid.

F

o

o

disp

V

V

Page 25: Lecture Ch 10

10-7 Buoyancy and Archimedes’ Principle

This principle also works in the air; this is why hot-air and helium balloons rise.

3160180

)180(

:'

)180(

mV

gKgVVg

principleArchimedesuse

gKgmF

Heair

Heair

HeB

Page 26: Lecture Ch 10

10-8 Fluids in Motion; Flow Rate and the Equation of Continuity

If the flow of a fluid is smooth (neighboring layers of the fluid slide smoothly), it is called streamline or laminar (in layers) flow (a).

Above a certain speed, the flow becomes turbulent (b). Turbulent flow has eddies (or eddy currents: erratic, small, whirlpool-like circles); the viscosity (internal friction) of the fluid is much greater when eddies are present.

Page 27: Lecture Ch 10

We will deal with laminar flow.

The mass flow rate is the mass that passes a given point per unit time. The flow rates at any two points must be equal, as long as no fluid is being added or taken away.

10-8 Fluids in Motion; Flow Rate and the Equation of Continuity

Avt

lA

t

V

t

mrateflowmass

This gives us the equation of continuity:

Page 28: Lecture Ch 10

10-8 Fluids in Motion; Flow Rate and the Equation of Continuity

If the density doesn’t change – typical for liquids – this simplifies to . Where the pipe is wider, the flow is slower.

Page 29: Lecture Ch 10

Example 10-11: Estimate Blood Flow

rcap = 4 10-4 cm, raorta = 1.2 cm

v1 = 40 cm/s, v2 = 5 10-4 cm/s

Number of capillaries N = ?

A2 = N(rcap)2, A1 = (raorta)2

A1v1 = A2v2

N = (v1/v2)[(raorta)2/(rcap)2]

N 7 109

Page 30: Lecture Ch 10

10-9 Bernoulli’s Equation

A fluid can also change its height. By looking at the work done as it moves, we find:

This is Bernoulli’s equation. One thing it tells us is that as the speed goes up, the pressure goes down.

Page 31: Lecture Ch 10

Work & energy in fluid moving from Fig. a to Fig. b :

a) Fluid to left of point 1 exerts pressure P1 on fluid mass M = ρV

V = A11 = A22 . Moves it 1. Work done:

W1 = F11= P1 A11

b) Fluid to right of point 2 exerts pressure P2 on fluid mass M = ρV,

V = A22. Moves it 2. Work done:

W2 = -F22 = -P2A22

a) b) Mass M moves from height y1 to height y2. Work done against

gravity:

W3 = -Mg(y2 – y1) ; WG= -PE

Page 32: Lecture Ch 10

Sect. 10-9: Bernoulli’s Eqtn

• Total work done from a) b):

Wnet = W1 + W2 + W3

Wnet = P1A11 - P2A22 - Mg(y2 – y1) (1)• Recall the Work-Energy Principle:

Wnet = KE = (½)M(v2)2 – (½)M(v1)2 (2)• Combining (1) & (2):

(½)M(v2)2 – (½)M(v1)2

= P1A11 - P2A22 - Mg(y2 – y1) (3)• Note that M = ρV = ρA11 = ρA22

• divide (3) by V = A11 = A22

Page 33: Lecture Ch 10

(½)ρ(v2)2 - (½)ρ(v1)2 = P1 - P2 - ρg(y2 – y1) (4)

• Rewrite (4) as: P1 + (½)ρ(v1)2 + ρgy1 = P2 + (½)ρ(v2)2 + ρgy2

Bernoulli’s Equation• Another form:

P + (½)ρv2 + ρgy = constant• Not a new law, just work & energy of system in fluid

language. (Note: P ρ g(y2 -y1) since fluid is NOT at rest!)

Work Done by Pressure = KE + PE

Page 34: Lecture Ch 10

Flow on the level

P1 + (½)ρ(v1)2 + ρgy1 = P2 + (½)ρ(v2)2 + ρgy2

• Flow on the level y1 = y2

P1 + (½)ρ(v1)2 = P2 + (½)ρ(v2)2

Explains many fluid phenomena & is a quantitative statement of Bernoulli’s Principle:

“Where the fluid velocity is high, the pressure is low, and where the velocity is low, the pressure is high.”

Page 35: Lecture Ch 10

10-10 Applications of Bernoulli’s Principle: from Torricelli to Airplanes,

Baseballs, and TIA

Using Bernoulli’s principle, we find that the speed of fluid coming from a spigot on an open tank is:

This is called Torricelli’s theorem.

(10-6)

P1 + (½)ρ(v1)2 + ρgy1 = P2 + (½)ρ(v2)2 + ρgy2

P1 = P2

P2

P1

Page 36: Lecture Ch 10

10-10 Applications of Bernoulli’s Principle:

Lift on an airplane wing is due to the different air speeds and pressures on the two surfaces of the wing.

PTOP < PBOT LIFT force!

A1 Area of wing top, A2 Area of wing bottom

FTOP = PTOP A1 FBOT = PBOT A2

Plane will fly if ∑F = FBOT - FTOP - Mg > 0 !

Page 37: Lecture Ch 10

10-10 Applications of Bernoulli’s Principle: from Torricelli to Airplanes,

Baseballs, and TIA

A ball’s path will curve due to its spin, which results in the air speeds on the two sides of the ball not being equal.

Page 38: Lecture Ch 10

10-10 Applications of Bernoulli’s Principle: from Torricelli to Airplanes,

Baseballs, and TIA

A person with constricted arteries will find that they may experience a temporary lack of blood to the brain (TIA; Transient Ischemic Attack) as blood speeds up to get past the constriction, thereby reducing the pressure.

Page 39: Lecture Ch 10

10-10 Applications of Bernoulli’s Principle: from Torricelli to Airplanes,

Baseballs, and TIA

A venturi meter can be used to measure fluid flow by measuring pressure differences.

Page 40: Lecture Ch 10

10-10 Applications of Bernoulli’s Principle: from Torricelli to Airplanes,

Baseballs, and TIA

Air flow across the top helps smoke go up a chimney, and air flow over multiple openings can provide the needed circulation in underground burrows.

Page 41: Lecture Ch 10

Problem 46: Pumping water up

Street level: y1 = 0v1 = 0.6 m/s, P1 = 3.8 atm Diameter d1 = 5.0 cm (r1 = 2.5 cm). A1 = π(r1)2

18 m up: y2 = 18 m, d2 = 2.6 cm (r2 = 1.3 cm). A2 = π(r2)2 v2 = ? P2 = ?Continuity: A1v1 = A2v2 v2 = (A1v1)/(A2) = 2.22 m/s Bernoulli:P1+ (½)ρ(v1)2 + ρgy1 = P2+ (½)ρ(v2)2 + ρgy2 P2 = 2.0 atm

Page 42: Lecture Ch 10

Summary of Chapter 10

• Phases of matter: solid, liquid, gas.

• Liquids and gases are called fluids.

• Density is mass per unit volume.

• Specific gravity is the ratio of the density of the material to that of water.

• Pressure is force per unit area.

• Pressure at a depth h is ρgh.

• External pressure applied to a confined fluid is transmitted throughout the fluid.

Page 43: Lecture Ch 10

Summary of Chapter 10

• Atmospheric pressure is measured with a barometer.

• Gauge pressure is the total pressure minus the atmospheric pressure.

• An object submerged partly or wholly in a fluid is buoyed up by a force equal to the weight of the fluid it displaces.

• Fluid flow can be laminar or turbulent.

• The product of the cross-sectional area and the speed is constant for horizontal flow.

Page 44: Lecture Ch 10

Summary of Chapter 10

• Where the velocity of a fluid is high, the pressure is low, and vice versa.