lecture 2: relativistic space-time · consider light beam moving along positive x-axis: x = ct or x...

40
Lecture 2: Relativistic Space-Time Lorentz Transformations Invariant Intervals & Proper Time Electromagnetic Unification Equivalence of Mass and Energy Space-Time Diagrams Relativistic Optics Section 6-7, 19-21, 15-18 Useful Sections in Rindler:

Upload: others

Post on 24-Jun-2020

2 views

Category:

Documents


0 download

TRANSCRIPT

Page 1: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

Lecture 2: Relativistic Space-Time• Lorentz Transformations

• Invariant Intervals & Proper Time

• Electromagnetic Unification

• Equivalence of Mass and Energy

• Space-Time Diagrams

• Relativistic Optics

Section 6-7, 19-21, 15-18

Useful Sections in Rindler:

Page 2: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

Consider light beam moving along positive x-axis:

x = ct or x - ct = 0

Similarly, in the moving frame, we want to have

x = ct or x - ct = 0

We can insure this is the case if: x - ct = a(x - ct )

Generally, the factor could be different for motion in the opposite direction:

x + ct = b(x + ct )

Subtracting t = t − x/c(a+ b)2

(a-b)2

= t − x/c(a+ b)2

(a-b)(a+b)[ ]

= A t − Β x/c[ ]

Lorentz Transformations:

Page 3: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

= A t − Β x/c[ ]t

So, we know that A = γ∆t = A ∆t(at fixed x)

Similarly, x = γ [ x - Bct ]

x = γ [ x - vt ] t = γ [ t - (v/c2)x ]

In non-relativistic limit (γ → 1) : x → [ x - Bct ]

Must correspond to Galilean transformation, so Bc = v

B = v/c

Page 4: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

c =√d2 + (∆x )2

∆t

Recall:

Thus, (c ∆t )2 = d2 +(∆x )2

d2 = (c ∆t )2 - (∆x )2invariant

or, more generally,

S2 = (c ∆t )2 - [(∆x )2+ (∆y )2+ (∆z )2]

''Invariant Interval”

choose frame''at rest”

= (c ∆τ)2

“Proper Time”

Page 5: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

Maxwell’s Equations

''Lorentz-Fitzgerald Contraction”

''Aether Drag”

George Francis Fitzgerald

Hendrik Antoon Lorentz

Page 6: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

+q

+−

+−

+−

+−

vI

B

Lab Frame

F(pure magnetic)

+−

+

+

+

+

+q

In Frame ofTest Charge

Lorentzexpanded

Lorentzcontracted

F(pure electrostatic)

⇓Electricity & Magnetismare identically the sameforce, just viewed from different reference frames

UNIFICATION !!(thanks to Lorentz invariance)

Symmetry:The magnitude of a forcelooks the same whenviewed from reference frames boosted in the perpendicular direction

Page 7: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

+q

+−

+−

+−

+−

vI

B

Lab Frame

+−

+

+

+

+

+q

In Frame ofTest Charge

Lorentzexpanded

Lorentzcontracted

F(pure magnetic)

F(pure electrostatic)

F = qv × B| F | = qv Iµ

o/ (2πr)

λlab+ = λ λ

lab− = λ

λq+ = λ/γ λ

q− = λγ

λ´ = λq+ −−−− λ−

E = λ′ / 2πrεo= λγ v2 / (2πrε

oc2)

= λγ v2 µο/ (2πr)

| F ´| = Eq = λγ v2 µοq / (2πr)

λv = I

| F | = | F ´| / γ = qvΙµο / (2πr)

= λγβ2= λ(γ−1/γ)

| F ´| = γ Ιvµοq / (2πr)

Page 8: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

Einstein’s The 2 Postulates of Special Relativity:

I. The laws of physics are identical in all inertial frames

II. Light propagates in vacuum rectilinearly, with the same speed at all times, in all directions and in all inertial frames

Page 9: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We
Page 10: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

Planck’s recommendation for Einstein’s nomination

to the Prussian Academy in 1913:

“In summary, one can say that there is hardly one among

the great problems in which modern physics is so rich to

which Einstein has not made a remarkable contribution.

That he may sometimes have missed the target in his

speculations, as, for example, in his hypothesis of light

quanta, cannot really be held against him, for it is not

possible to introduce really new ideas even in the most

exact sciences without sometimes taking a risk.”

Page 11: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We
Page 12: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

E = hν (Planck) p = h/λ (De Broglie)

= hc/λE = pc

absorber emitter

p=E/c

recoil

p=Mv

E/c = Mv

motionstops

distance travelled

d = vt = v (L/c)

L

= EL/(Mc2)

But no external forces, so CM cannot change!

Must have done the equivalent of shifting some mass m to other side, such that

M {EL/(Mc2)} = m LMd = mL

“Einstein’s Box”:

Page 13: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

+ x- x

ct

-y

+ y

Space-Time:

Page 14: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

+ x- x

ct

= c∆t/∆x = c/v = 1/β

object stationaryuntil time t

1

x1

ct1

moves with constant

velocity (β) until t2

ct2

x2

returns to point of origin

slope = (ct2- ct

1)/(x

2-x1)

Page 15: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

+ x- x

ct

θ

tanθ = x/ct = v/c = β

tanθmax= 1

θmax= 45°

45°

v = c

45°

v = c

light sent backwards

Page 16: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

“absolute past”

+ x- x

ct

“absolute future”

“absolute elsewhere”

x1

ct1

no message sent from theorigin can be received by observers at x

1until time t

1

there is no causal contactuntil they are

“inside the light cone”

Page 17: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

+ x- x

ct

“absolute future”

“absolute past”

“absolute elsewhere”

Page 18: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

+ x- x

ct

θ

Page 19: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

+ x- x

ct

θ

Page 20: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

+ x- x

ct

θ

Page 21: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

+ x- x

ct

θ

Page 22: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

+ x- x

ct

θ

Page 23: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

+ x- x

ct

θ

θ

Page 24: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

+ x- x

ct

θ

θ

Page 25: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

+ x- x

ct

θ

θ

S S´

Page 26: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

+ x- x

ctSpacetime

Showdown

Page 27: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

Relativistic

Optics

Page 28: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

v

∆t = γ ∆t′

f = 1/∆t = 1/γ∆t′ = f′/ γ

Transverse Doppler Reddening

Page 29: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

a

a

a

Page 30: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

v

a

a v/c

Page 31: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

v

a√1 - (v/c)2

(a v/c)2 + (a √1 - (v/c)2 )2 = a2

a v/c

Page 32: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

v

a√1 - (v/c)2

(a v/c)2 + (a √1 - (v/c)2 )2 = a2

a√1 - (v/c)2

a

Terrell Rotation(1959)

a v/c

Page 33: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

Penrose (1959):

A Sphere By Any Other Frame Is Just As Round

Page 34: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

v

d

√h2+d

2

h

Page 35: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

v

d

h

More generally, from somewhat off-axis ⇒ hyperbolic curvature

√h2+d

2

Page 36: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

SS 433

If assumed distance to object increases,so must the distance traversed by jet topreserve same angular scale for “peaks”and, hence, jet velocity must increase.

History of jet precession(period = 162 days)

Jet orientation fixed by relative Doppler shifts

Light observed from a given point

in the jet was produced ∆t = (s-d)/c earlier, thus distorting the apparent orientation of the loops

d

θ

s

Page 37: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We
Page 38: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

Can fit distance to the source = 5.5 kpc (K. Blundell & M. Bowler)

Can even show evidence of jet speed variations!

Page 39: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We

Angular compression towards centre of field-of-view

Intensity = increases towards centrelight receivedsolid angle

“Headlight Effect”

Page 40: Lecture 2: Relativistic Space-Time · Consider light beam moving along positive x-axis: x = ct or x -ct = 0 Similarly, in the moving frame, we want to have x = ct or x -ct = 0 We