lecture # 15
DESCRIPTION
LECTURE # 15. CONDUCTOR – FREE SPACE BOUNDARY CONDITIONS. Introduction. +. +. +. +. +. +. +. +. free space. conductor. -. -. -. -. -. -. -. -. Short Wave Radio. OBJECTIVES. To relate mathematically fields that propagates between various materials. - PowerPoint PPT PresentationTRANSCRIPT
LECTURE # 15
CONDUCTOR – FREE SPACE BOUNDARY CONDITIONS
Introduction
+ + + + + + + +
- - - - - - - -
conductor
free space
Short Wave Radio
OBJECTIVES
To relate mathematically fields that propagates between various materials.
To derive boundary conditions at the interface.
GRAPHICAL ILLUSTRATION
Medium # 1
Medium # 2
E1
E2
E1t + E1n
E1n
E2t
E2n
E1 E2
E1t
E2n + E2t
Normal component
Tangential component
NORMAL COMPONENTSE1n E2n
# 1
# 2
+ + + +h
s
E1n
E2n
S Maxwell’s equation (Gauss’s law)
ensQsdD
1
2 3
321 sdDsdDsdD
s sds
zD n1
zds1 zD n2 zds3
Assume h → 0
SSDSD sn2n1
sn2n1 DD Boundary condition for normal components
0
TANGENTIAL COMPONENTS
# 1
# 2
E1t E2t
E1t
E2t
h
ℓ
1 2
34
Maxwell’s equation (Conservation of energy)
0dE
2
1
3
2
4
3
1
4dEdEdEdE
0EE t2t1 t2t1 EE
Assume again h → 0
Boundary conditionfor tangentialcomponents
0 0
CONDUCTOR – FREE SPACE BOUNDARY CONDITION# 1 Free space # 2 Conductor
0 0
Boundary condition for normal components
Boundary condition for tangential components
sn2n1 DD
t2t1 EE
sn1D 0
00EE t2t1
Boundary conditionsfor conductor – freespace/dielectric
GRAPHICAL ILLUSTRATION
Conductor Free space+
++
+
+
+
+
+
s
nsaD
Unit vectornormal to thesurface
n0
s aE
SUMMARIZED THE PRINCIPLES WHICH APPLY TO CONDUCTORS IN ELECTROSTATIC FIELDS The static electric field intensity inside a conductor is
zero. The static electric field at the surface of a conductor
is everywhere directed normal to that surface. The conductor surface is an equipotential surface.
EXAMPLE 15.1
Let potential field V = 100(x2 - y2) and point P( 2, -1, 3) lies on a conductor-free space boundary. Determine the profile of the conductor. Determine the electric field intensity at point P. Determine the surface charge at point P.
EXAMPLE 15.2
A potential field is given as V = (100e-5x sin 3y cos 4z) V. Let point P(0.1, ) be located at a conductor-free space boundary. At point P, find the magnitude of: (i) V; (ii) E; (iii) En; (iv) Et; (v) s.
Answer: 37.1 V, 233 V/m, 233 V/m, 0, 2.06 nC/m2
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QUESTIONS AND ANSWERS