lecture 10 - umd physics · lecture 10 • ideal gas model • ideal gas law • quasi-static...
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Lecture 10
• Ideal gas model
• Ideal gas law
• Quasi-static processes: isochoric, isobaric and isothermal
• Temperature scales, absolute zero
• Phase changes, equilibrium, diagram
Temperature• temperature is related to system’s thermal energy
(kinetic and potential energy of atoms)
• measured by thermometer: small system undergoes a change upon exchagning thermal energy, e.g., length of mercury/alcohol in glass tube or ideal gas’ pressure
• Celcius/centigrade scale: boiling point (100 ) freezing point (0 )
• Fahrenheit scale: (212 and 32 )
Temperature Scales
TF = 95TC + 32!
!F !F
!C !C
Example• At what temperature does the numerical value in
degree Fahrenheit in match the numerical value in degree Celsius?
Absolute Zero and Absolute Temperature
• property changes linearly with temperature: e.g., pressure of constant-volume gas
• p = 0 for all gases at p due to collisions all motion stopped, zero thermal energy: absolute zero (lowest temperature)
• absolute temperature scale: zero point at absolute zero Kelvin scale if same unit size as Celcius scale:
T0 = !273 !C
TK = TC + 273 (no degrees for Kelvin)
Phase Changes• melting/freezing point: temperature
at which solid becomes liquid...thermal energy large enough to allow molecules to move around
• phase equilibrium: 2 phases co-exist
• condensation/boiling point: phase equilibrium between liquid and gas thermal energy too large for bonding
• phase change temperatures are pressure-dependent: freezing (boiling) point higher (lower) at lower pressure
Phase diagram• how phases and phase changes
vary with T, p
• 3 regions with phase transitions at boundaries...gas-solid (sublimation)
• critical point: liquid-gas boundary ends
• triple point: all 3 phases co-exist
• triple point of water ( ) used as reference point (reproduced with no variation) for Kelvin scale: 273.16 K 0 K fixed by gas properties
T3 = 0.01!C
• cf. Celcius scale requires 2 reference points: boiling and melting points (p-dependent)
Ideal Gases• (strong) repulsive forces between atoms
(incompressibility of solids/liquids + (weak) attractive forces (tensile strength of solids; cohesion of liquid droplets)
• solids and liquids: atomic separation
• gases: freely moving till collide (steep wall for important)
• Ideal gas model: hard non-interacting spheres, bounce on contact
• good for low density and condensation point
! req
(both mono and d-atomic gases)
average r ! req
T !
r < req.
Ideal-gas law• Experiments state variables not independent: for all gases
• Gases in sealed containers (n constant)
• Using,
• typical p, V, T: average distance between gas molecules distances over which atoms exert attractive forces
universal gas constant, R = 8.31 J/mol/K
Boltzmann's constant, k_B = R/N_A = 1.38 x 10^(-23) J/K
= p / k_B T
!
Example
• 3.0 mol of gas at a temperature of -120 degrees Celsius fills a 2.0 L container. What is the gas pressure?
Ideal gas processes (how gas changes state)• diagram: each point is unique
state of gas (T by ideal-gas law; n known for sealed container) (p, V, T)
• ideal gas process: trajectory showing intermediate states (work done depends on it)
• Quasi-static processes: slow; system in thermal equilibrium at all times
(reversible)
pV
(i) Isochoric (constant V) process
• : vertical line on diagramVf = Vi pV
(ii) Isobaric (constant p) process
• gas pressure from balancing of forces on piston
• : horizontal line on diagram
(expansion: compression if cooled)
pf = pi
p = patmos + MgA
pV
(iii) Isothermal (constant T) process• heat transfer keeps gas at same T as liquid
• : hyperbola on diagram (inverse relationship)
• location of hyperbolae (isotherms) depends on T: lower T, closer to origin
Tf = Ti and pV = nRT ! piVi = pfVf
p = nRTV = constant
V pV
Example• A rigid container holds hydrogen gas at a pressure of
3.0 atm and a temperature of 2 degrees Celsius. What will the pressure be if the temperature is raised to 10 degrees Celsius?