leader test series / joint package course · object has only the translational motion without...
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Form Number :
DISTANCE LEARNING PROGRAMME(Academic Session : 2015 - 2016)
1. A seat marked with Reg. No. will be alloted to each student. The student should ensure that he/she occupies the correct seatonly. If any student is found to have occupied the seat of another student, both the students shall be removed from the examination
and shall have to accept any other penalty imposed upon them.
izR;sd fo|kFkhZ dk jftLVªs'ku ua- ds vuqlkj LFkku fu;r gS rFkk os vius fu;r LFkku ij gh cSBsaA ;fn dksbZ fo|kFkhZ fdlh nwljs fo|kFkhZ ds LFkku
ij cSBk ik;k x;k rks nksuksa fo|kfFkZ;ksa dks ijh{kk d{k ls ckgj dj fn;k tk,xk vkSj nksuksa dks dksbZ vU; tqekZuk Hkh Lohdk;Z gksxkA
2. Student can not use log tables and calculators or any other material in the examination hall.
fo|kFkhZ ijh{kk d{k esa yksx Vscy] dsYdwysVj ;k fdlh vU; lkexzh dk mi;ksx ugha dj ldrk gSA
3. Student must abide by the instructions issued during the examination, by the invigilators or the centre incharge.
ijh{kk ds le; fo|kFkhZ dks ijhoh{kd }kjk fn;s x;s funsZ'kksa dh ikyuk djuk vko';d gSA
4. Before attempting the question paper ensure that it contains all the pages and that no question is missing.
iz'u i= gy djus ls igys fo|kFkhZ vk'oLr gks tk, fd blesa lHkh ist layXu gSa vFkok ughaA
5. Each correct answer carries 1 marks, while one third mark will be deducted from the total of individual subject for each
incorrect answer.
izR;sd lgh mÙkj ds 1 vad gSa tcfd ,d frgkbZ vad] xyr mÙkj dk ml fo"k; ds dqy vadksa esa ls de dj fy;k tk;sxkA
Do not open this Test Booklet until you are asked to do sobl ijh{kk iqfLrdk dks tc rd uk [kksys a tc rd dgk u tk,sA
Important Instructions / egRoiw.kZ funsZ'k
LEADER TEST SERIES / JOINT PACKAGE COURSETARGET : PRE-MEDICAL 2016
Note : In case of any Correction in the test paper, please mail to [email protected] within 2 days along withPaper code and Your Form No.uksV% ;fn bl iz'u i= esa dksbZ Correction gks rks Ïi;k Paper code ,oa vkids Form No. ds lkFk 2 fnu ds vUnj [email protected] mail djsaA
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Your Target is to secure Good Rank in Pre-Medical 2016
Test Type : ALL INDIA OPEN TEST (MAJOR) Test Pattern : AIIMS
TEST DATE : 21 - 02 - 2016
Paper Code : 0999DM310315021
TEST SYLLABUS : FULL SYLLABUS
ALL INDIA OPEN TEST/Pre-Medical /AIIMS/21-02-2016
1/370999DM310315021
1. Let the angle between two nonzero vectors Aur
and
Bur
be 120° and resultant be Cur
:-
(1) Cur
must be equal to | A B |-ur ur
(2) Cur
must be less than | A B |-ur ur
(3) Cur
must be greater than | A B |-ur ur
(4) Cur
may be equal to | A B |-ur ur
2. A T shaped object with dimensions shown in the
figure, is lying a smooth floor. A force 'F'r
isapplied at the point P parallel to AB, such that theobject has only the translational motion withoutrotation. Find the location of P with respect to C:-
C
PF®
A Bl
2l
(1) 43l (2) l
(3) 23l (4)
32l
3. A black body at a high temperature T K radiatesenergy at the rate E watt/m2 ; when the temperaturefalls to (T/2) K the radiated energy will be :(1) E/4 (2) E/2 (3) 2E (4) E/16
4. An ionized gas contains both positive and negativeions. If it is subjected simultaneously to an electricfield along the +x direction and a magnetic fieldalong the +z direction, then :-(1) Positive ions deflect towards +y direction and
negative ions towards –y direction(2) All ions deflect towards +y direction(3) All ions deflect towards –y direction(4) Positive ions deflect towards –y direction and
negative ions towards +y direction
1. ekuk nks v'kwU; lfn'kksa Aur
o Bur
ds chp dks.k 120°gS
rFkk budk ifjek.kh Cur
gS rks :-
(1) Cur
vo'; gh | A B |-ur ur
ds cjkcj gksxk
(2) Cur
vo'; gh | A B |-ur ur
ls de gksxk
(3) Cur
vo'; gh | A B |-ur ur
ls vf/kd gksxk
(4) Cur
, | A B |-ur ur
ds cjkcj gks ldrk gS
2. ,d T vkdkj dh oLrq ftldh foek,sa fp= esa iznf'kZr gSa]
,d fpdus {kSfrt Q'kZ ij j[kh gSaA ,d cy 'F 'r
AB dslekUrj P fcUnq ij bl izdkj yxk;k tkrk gS] ftlls fdoLrq fcuk ?kw.kZu ds dsoy jSf[kd xfr djrh gSA C ds lkis{kP dh fLFkfr gksxh :-
C
PF®
A Bl
2l
(1) 43l (2) l
(3) 23l (4)
32l
3. ,d dkyh oLrq T K rkieku ij E watt/m2 ls ÅtkZmRlftZr djrk gS ;fn rkieku (T/2) K gks tk;s rks mRlftZrÅtkZ gksxh :(1) E/4 (2) E/2 (3) 2E (4) E/16
4. ,d vk;fur xSl esa /kuk;u o ½.kk;u nksuksa mifLFkr gSA;fn bl ij ,d lkFk fo|qr {ks= +x fn'kk esa o pqEcdh;{ks= +z fn'kk esa vkjksfir fd;s tk;s rc&
(1) /kuk;u +y fn'kk esa rFkk ½.kk;u –y fn'kk esa fo{ksfirgksrs gSa
(2) lHkh vk;u +y fn'kk esa fo{ksfir gksrs gSa
(3) lHkh vk;u –y fn'kk esa fo{ksfir gksrs gSa
(4) /kuk;u –y fn'kk esa rFkk ½.kk;u +y fn'kk esa fo{ksfirgksrs gSa
BEWARE OF NEGATIVE MARKING
HAVE CONTROL ¾® HAVE PATIENCE ¾® HAVE CONFIDENCE Þ 100% SUCCESS
izR;sd iz'u dks vtqZu cudj djksA
0999DM3103150212/37
ALL INDIA OPEN TEST/Pre-Medical /AIIMS/21-02-2016
5. Which of the following relation is wrong :-(1) 1 ampere × 1 ohm = 1 volt(2) 1 watt × 1 sec = 1 joule(3) 1 newton per coulomb = 1 volt per meter(4) 1 coulomb 1× volt = 1watt
6. Four masses are fixed on a massless rod as shownin Fig. The moment of inertia about the axis P isabout :
2kg 5kg 5kg 2kgP0.2m 0.2m 0.2m 0.2m
(1) 2 kg m2 (2) 1 kg m2
(3) 0.5 kg m2 (4) 0.3 kg m2
7. 200 g of a solid ball at 20°C is dropped in an equalamount of water at 80°C. The resultingtemperature is 60°C. This means that specific heatof solid is :(1) One fourth of water(2) One half of water(3) Twice of water(4) Four times of water
8. A charged particle is whirled in a horizontal circleon a fictionless table by attaching it to a string fixedat one point. If a magnetic field is switched on inthe vertical direction, the tension in the string:-(1) will increase(2) will decrease(3) will remain the same(4) may increase or decrease
9. An elevator car, whose floor to ceiling distanceis equal to 2.7 m, starts ascending with constantacceleration of 1.2 ms–2. 2 sec after the start, a boltbegins fallings from the ceiling of the car. The freefall time of the bolt is :-
(1) 0.54 s (2) 6 s
(3) 0.7 s (4) 1 s10. Four particles , each of mass m, are arranged at the
corners of a massless square of side 'a'. Momentof inertia of system about a diagonal is :
(1) ma2 (2) 2ma2 (3) 2ma
2(4)
2ma4
5. fuEu esa dkSu lk laca/k vlR; gS :-(1) 1 ,fEi;j × 1 vkse = 1 oksYV(2) 1 okV × 1 lsd.M = 1 twy(3) 1 U;wVu izfr dwykWe = 1 oksYV izfr ehVj(4) 1 dwykWe 1× oksYV = 1 okWV
6. ,d æO;ekughu NM + ij pkj æO;eku dk s fLFkrfd;k x;k gSA P v{k ds lkis{k tM+Ro vk?kw.kZ yxHkxgksxk :
2kg 5kg 5kg 2kgP0.2m 0.2m 0.2m 0.2m
(1) 2 kg m2 (2) 1 kg m2
(3) 0.5 kg m2 (4) 0.3 kg m2
7. 200 xzke dh ,d Bksl xsan 20°C ij leku æO;eku ds80°C okys ikuh esa fxjk;k tkrk gS rks ;fn vfUre rkieku60°C gks rks Bksl dh fof'k"V Å"ek gksxh :
(1) ikuh dh ,d pkSFkkbZ
(2) ikuh dh vk/kh
(3) ikuh dh nqxquh
(4) ikuh ls pkj xquk
8. ,d vkosf'kr d.k dks /kkxs ls cka/kdj ,d {kSfrt Vscyij o`Ùkh; xfr djkb Z tkrh gSA ;fn ;gk¡ ,d pqEcdh;{ks= ÅèokZèkj fn'kk esa vkjksfir fd;k tkrk gS rks /kkxses a ruko :-(1) c<+ sxk(2) ?kVsxk(3) leku jgsxk(4) c<+ ;k ?kV ldrk gS
9. ,d fy¶V ftldh Nr ls vk/kkj dh nwjh 2.7 ehVj gS] fu;rRoj.k 1.2 eh/lSd.M2 ls Åij mB jgh gSA xfr vkjaHk gksusds 2 lSd.M i'pkr~ ,d cksYV Nr ls fxjuk izkjEHk djrkgS] ;g fdrus le; rd eqä #i ls fxjsxk :-
(1) 0.54 s (2) 6 s
(3) 0.7 s (4) 1 s
10. m æO;eku ds pkj d.k dks æO;eku ghu oxZ ds 'kh"kksZ ijj[kk x;k gSA ftldh Hkqtk 'a' gSA fod.kZ ds lkis{k tM+Rovk?kq.kZ gksxk :-
(1) ma2 (2) 2ma2 (3) 2ma
2(4)
2ma4
ALL INDIA OPEN TEST/Pre-Medical /AIIMS/21-02-2016
3/370999DM310315021
11. Point charge q moves from point P to point S alongthe path PQRS (figure) in a uniform electric fieldE pointing parallel to the positive direction of thex-axis. The co-ordinates of the point P,Q,R andS are (a, b, 0), (2a, 0, 0), (a, –b, 0) and (0, 0,0) respectively. The work done by the field in theabove process is :
Y
S Q
R
PE
(1) qEa (2) -qEa
(3) qEa 2 (4) 2 2qE [(2a) b ]+
12. In a Young's double slit experiment, the separationbetween the two slits is d and the wavelength ofthe light is l. The intensity of light falling on slit1 is four times the intensity of light falling on slit2. Choose the correct choice(s).(a) If d = 0.99l, the screen will contain only one
maximum(b) If l < d < 2l, at least one more maximum
(besides the central maximum) will beobserved on the screen
(c) If the intensity of light falling on slit 1 isreduced so that it becomes equal to that of slit2, the intensities of the observed dark andbright fringes will increase
(c) If the intensity of light falling on slit 2 isincreased so that it becomes equal to that ofslit 1, the intensities of the observed dark andbright fringes will increase
(1) a, b (2) a, c(3) b, c (4) b, d
13. A body of mass m hangs at one end of a stringof length l, the other end of which is fixed. It isgiven a horizontal velocity so that the string wouldjust reach where it makes an angle of 60° withthe vertical. The tension in the string at meanposition is :-(1) 2mg (2) mg
(3) 3mg (4) 3mg
11. fcUnq vkos'k q fcUnq P ls fcUnq S ds vuqfn'k iFk PQRS ijfp=kuqlkj ,dleku fo|qr {ks= E esa x -v{k dh èkukRed fn'kkds lekUrj xfr djrk gS A P,Q,R rFkk S ds funsZ'kkad Øe'k%(a, b, 0), (2a, 0, 0), (a, -b, 0) rFkk (0, 0, 0) gSA mijksDrçfØ;k esa {ks= }kjk fd;k x;k dk;Z gksxk :
Y
S Q
R
PE
(1) qEa (2) -qEa
(3) qEa 2 (4) 2 2qE [(2a) b ]+
12. ;ax ds f}&js[kk&fNnz (Young's double slit) iz;ksx esa nksuksafLyVksa ds chp dh nwjh d rFkk izdk'k dh rjax nS/;Z l gSAfLyV 1 ij iM+us okys izdk'k dh rhozrk] fLyV 2 ij iM+usokys izdk'k dh rhozrk ls pkj xquh gSA lgh mÙkjksa dk pqukodjsA
(a) ;fn d = 0.99l gks rc ijns ij dsoy ,d mfPp"BgksxkA
(b) ;fn l < d < 2l gks rks inZs ij de ls de ,d vkSjmfPp"B (dsUnzh; mfPp"B ds vykok) izsf{kr gksxkA
(c) ;fn fLyV 1 ij iM+us okys izdk'k dh rhozrk dks ?kVkdjfLyV 2 ij iM+us okys izdk'k dh rhozrk ds cjkcj djfn;k tk;s, rks ijns ij nhIr rFkk vnhIr fÝUtksa dh rhozrkc<+ sxh
(d) ;fn fLyV 2 ij iM+us okys izdk'k dh rhozrk dks c<+kdjfLyV 1 ij iM+us okys izdk'k dh rhozrk ds cjkcj djfn;k tk;s ] rks ijns ij nhIr rFkk vnhIr fÝUtksa dhrhozrk c<+ sxhA
(1) a, b (2) a, c
(3) b, c (4) b, d
13. m nzO;eku dk ,d fi.M] a yEckbZ dh Mksjh ds ,d fljsls cka/kdj yVdk;k x;k gS tcfd nwljk fljk fljk fLFkjgSA nzO;eku dks bruk {kSfrt osx iznku fd;k tkrk gS ftllsblds }kjk Å/okZ/kj ls 60° dk vf/kdre dks.k cuk;k tkrkgSA rc ek/; fLFkfr esa Mksjh dk ruko D;k gksxk :-
(1) 2mg (2) mg
(3) 3mg (4) 3mg
0999DM3103150214/37
ALL INDIA OPEN TEST/Pre-Medical /AIIMS/21-02-2016
14. Length of a spring of force constant k in its unstretchedcondition is l. The spring is cut into two parts whichhave their unstretched lengths in the ratio l1: l2 = q : 1.Force constants of the two parts k1 and k2 are then :
(1) k(q + 1),kq
(2) (q 1)
k ,kqq+
(3) (q 1)
k ,k(q 1)q+
+
(4) (q 1) (q 1)
k ,kq q- +
15. ABC is an equilateral triangle. Charges +q areplaced at each corner. The electric intensity atO will be :
+q
+q+qB
O
r
rr
A
C
(1) 20
1 q4 rpe (2)
0
1 q4 rpe
(3) Zero (4) 20
1 3q4 rpe
16. The cross section of a glass prism has the formof an equilateral triangle. A ray is incident ontoone of the faces perpendicular to it. Find the angleq between the incident ray and the ray that leavesthe prism. The refractive index of glass is µ = 1.5.
(1) q = 60° (2) q = 30°
(3) q = 45° (4) q = 75°
17. In the first second of its flight, rocket ejects1/60 of its mass with a velocity of 2400 m/s–1. Theacceleration of the rocket is:-
(1) 19.6 ms–2 (2) 30.2 ms–2
(3) 40 ms–2 (4) 49.8 ms–2
14. ,d fLizax dh izkd`frd yEckbZ l rFkk cy fu;rkad k gSA;fn fLizax dks nks Hkkxksa esa bl rjg ls dkVk x;k gS rkfdl1: l2 = q : 1 rks nksuksa Hkkxksa ds cy fu;rkad k1 rFkk k2
gksxsa :
(1) k(q + 1),kq
(2) (q 1)
k ,kqq+
(3) (q 1)
k ,k(q 1)q+
+
(4) (q 1) (q 1)
k ,kq q- +
15. ABC ,d leckgq f=Hkqt gSA izR;sd dksus ij +q vkos'kj[kk x;k gS] O ij fo|qr {ks= dh rhozrk gksxh :-
+q
+q+qB
O
r
rr
A
C
(1) 20
1 q4 rpe (2)
0
1 q4 rpe
(3) Zero (4) 20
1 3q4 rpe
16. dk¡p ds ,d fçTe dk vuqçLFk dkV leckgq f=kHkqt :idk gSA fdlh ,d Qyd ij blds yEcor~ ,d fdj.kvkifrr gk srh gSA vkifrr fdj.k o fçTe ls fuxZrfdj.k ds chp dks.k q Kkr dhft,A dk¡p dk viorZukadµ = 1.5 gSA
(1) q = 60° (2) q = 30°
(3) q = 45° (4) q = 75°
17. jkWdsV viuh mM+ku ds izFke lsd.M+ esa 2400 eh/ls–1 dsosx ls vius nzO;eku dk 1/60 ok¡ Hkkx NksM+rk gSA jkWdsVdk Roj.k gS:-
(1) 19.6 ms–2 (2) 30.2 ms–2
(3) 40 ms–2 (4) 49.8 ms–2
ALL INDIA OPEN TEST/Pre-Medical /AIIMS/21-02-2016
5/370999DM310315021
18. Velocity-time graph of a particle performing SHMis as shown in Fig. Amplitude of oscillation is thennearly :
–3–2–1O+1+2+3
v(m/s)
0.500.25 0.75
1.00 t(s)
(1) 20 cm (2) 48 cm(3) 75 cm (4) 8 cm
19. Five capacitors of 10mF capacity each are connectedto a DC potential of 100V as shown in the adjoiningfigure. Find charge in 10µF capacitor :-
100 V
10µF
8µFA
10µF
10µF 10µF
B
(1) 100 mC (2) 500 mC(3) 250 mC (4) 300 mC
20. An object O is kept infront of a converging lensof focal length 30 cm behind which there is a planemirror at 15 cm from the lens as shown in thefigure.
(A) The final image is formed at 60 cm from thelens towards right of it
(B) The final image is at 60 cm from lens towardsleft of it
(C) The final image is real
(D) The final image is virtual.
(1) A,C (2) B,C
(3) A,D (4) B,D
18. ,d d.k leku vkorZ xfr dj jgk gSA ;fn V-t oØfp=kuqlkj gS rks d.k dk vk;ke gksxk :
–3–2–1O+1+2+3
v(m/s)
0.500.25 0.75
1.00 t(s)
(1) 20 cm (2) 48 cm
(3) 75 cm (4) 8 cm
19. iakp la/kkfj=ks ftuls izR;sd dh /kkfjrk 10mF gSa] dksfp=kuqlkj 100 V okys DC foHko ls tksM+k x;k gSA rks10µF /kkfjrk ds la/kkfj= esa vkos'k Kkr djsa :-
100 V
10µF
8µFA
10µF
10µF 10µF
B
(1) 100 mC (2) 500 mC(3) 250 mC (4) 300 mC
20. 30 cm Qksdl nwjh okys ,d vfHklkjh ySUl ds lkeus ,doLrq O j[kh gq;h gSA ySUl ds ihNs 15 cm nwjh ij fp=kuqlkj,d lery niZ.k j[kk gqvk gSA
(A) vfUre izfrfcEc ySUl ds nka;h vksj ysUl ls 60 cmnwj curk gSA
(B) vfUre izfrfcEc ySUl ds cka;h vksj 60 cm nwj curkgSA
(C) vfURke izfrfcEc okLrfod gSA
(D) vfUre izfrfcEc vkHkklh gSA
(1) A,C (2) B,C
(3) A,D (4) B,D
dksbZ Hkh iz'u Key Filling ls xyr ugha gksuk pkfg,A
0999DM3103150216/37
ALL INDIA OPEN TEST/Pre-Medical /AIIMS/21-02-2016
21. What is the maximum value of the force F suchthat the block shown in the arrangement, does notmove:-
60°
F
m = 3kg
µ = 12 3
(1) 20 N (2) 10 N(3) 12 N (4) 15 N
22. A wooden piece floats half submerged in a tub ofwater. If the system is transferred to a lift ascendingwith acceleration the wooden piece will :(1) Sink a little more(2) Rise a little(3) Remain half submerged(4) Sink to the bottom
23. A battery of 10 cells each of e.m.f. E = 1.5 V andinternal resistance 0.5 W has 1 cell wronglyconnected. It is being charged by 220 V powersupply with an external resistance of 47 W inseries. The potential difference across the battery.(1) 30 V (2) 32 V (3) 25 V (4) 0 V
24. The work function of caesium is 2.14 eV. Findthe wavelength of the incident light if the photocurrent is brought to zero by a stopping potentialof 0.60 volt :-(1) 454 nm (2) 640 nm(3) 540 nm (4) None of these
25. The work done by a force 3ˆF ( 6x i)N= -r
, in
displacing a particle from x= 4 m to x =-2 mis :-(1) 360 J (2) 240 J(3) –240 J (4) –360K
26. A string of mass m length l from ceiling as shownin the fig. Wave in string move upward. vA andvB are the speed of wave at A and B respectively.Then vB is :
B
A l4
3l 4
(1) A3v (2) vA (3) < vA (4)
A2v
21. cy F dk og vf/kdre eku D;k gS] rkfd fp= esa iznf'kZrxqVdk] xfreku u gks lds :-
60°
F
m = 3kg
µ = 12 3
(1) 20 N (2) 10 N
(3) 12 N (4) 15 N
22. ,d ydM+h dk VqdM+k ikuh esa vk/kk Mwck gqvk gSA ;fn fudk;dks fy¶V esa j[k fn;k tk;s rFkk fy¶V Åij Rofjr gks rksydM+h dk VqdM+k :(1) T;knk Mwc tk,xkA(2) Åij vk tk,xkA(3) vk/kk gh Mwck jgsxkA(4) ry rd Mwc tk,xkA
23. 10 lsyksa dh ,d cSVjh ftlesa izR;sd lsy dk fo-ok-cyE = 1.5V vkSj vkarfjd izfrjks/k 0.5 W gS] esa ,d lsylgh tqM+k ugha gSA bls 220 oksYV ds lzksr ls vkosf'kr fd;ktkrk gS ftlds Js.kh Øe esa 47 W dk cká izfrjks/k tqM+kgqvk gSA cSVjh ds fljksa ij foHkokUrj gksxkA(1) 30 V (2) 32 V (3) 25 V (4) 0 V
24. lhft;e /kkrq dk dk;ZQyu 2.14 eV gSA ;fn çdk'k fo|qr/kkjk dks 'kwU; djus ds fy, fojks/kh foHko dk eku 0.60gksrks vkifrr çdk'k dh rjaxnS/; Z Kkr djks :-
(1) 454 nm (2) 640 nm
(3) 540 nm (4) None of these
25. ,d d.k 3ˆF ( 6x i)N= -r
U;wVu ds izHkko esa x= 4 m ls
x =–2 m foLFkkfir gksrk gSA bl izfØ;k esa fd;k x;kdk;Z gksxk :-(1) 360 J (2) 240 J(3) –240 J (4) –360K
26. m æO;eku rFkk l yEckbZ dh jLlh dks fp=kuqlkj yVdk;kx;k gSA A rFkk B fcUnq ij rjax osx vA rFkk vBgks rks vB
gksxk :
B
A l4
3l 4
(1) A3v (2) vA (3) < vA (4)
A2v
ALL INDIA OPEN TEST/Pre-Medical /AIIMS/21-02-2016
7/370999DM310315021
27. In the given potentiometer circuit length of thewire AB is 3m and resistance is R = 4.5W. Thelength AC for no deflection in galvanometer is :-
G
r=0.5W
R=4.5W
E=5V
A BC
E =3V1r1
(1) 2m (2) 1.8m(3) dependent on r1 (4) None of these
28. If kinetic energy of an electron is increased by 4%then percentage change in de-Broglie wavelength:-(1) decreases by 2%(2) decreases by 1%(3) increases by 5%(4) None of these
29. Two small particles of equal masses start movingin opposite direction from a point A in a horizontalcircular orbit. Their tangential velocities are v and2v, respectively, as shown in the figure. Betweencollisions, the particles move with constantspeeds, After making how many elastic collisions,other than that at A, these two particles will againreach the point A:-
v A 2v
(1) 4 (2) 3(3) 2 (4) 1
30. Fundamental frequency of a sonometer wire is n.If the length and diameter of the wire are doubledkeeping the tension same, then the newfundamental frequency is :
(1) n
2(2)
n
2 2
(3) 2n (4) n4
27. fn;s x, foHkoekih ifjiFk esa rkj AB dh yEckbZ 3mrFkk izfrjks/k R = 4.5W gSA xsYosuksehVj esa 'kwU; fo{ksi dsfy;s yEckbZ AC gksxh :-
G
r=0.5W
R=4.5W
E=5V
A BC
E =3V1r1
(1) 2 m (2) 1.8 m(3) r1 ij fuHkZj (4) buesa ls dksbZ ugha
28. ,d bysDVªkWu dh xfrt ÅtkZ 4% c<+kus ij bldh Mh czksXyhrjaxnS/;Z es çfr'kr ifjorZu gksxk :-(1) decreases by 2%(2) decreases by 1%(3) increases by 5%(4) None of these
29. ,dleku nzO;eku ds nks d.k fcUnq A ls ,d {kSfrt oÙkh;d{kk esa foijhr fn'kkvksa esa pyuk 'kq# djrs gSaA tSlk fdfp= esa fn[kk;k x;k gS] Li'kZ&js[kk ds vuqfn'k muds osxv rFkk 2v gSA nks VDdjksa ds chp os ,dleku pky ls pyrsgSaA fcUnq A ij gqbZ VDdj ds vfrfjä fdruh izR;kLFk VDdjksads ckn ;g nksuksa d.k izkjafHkd LFkku ij igq¡pasxs :-
v A 2v
(1) 4(2) 3(3) 2(4) 1
30. lksuksehVj dh ewy vkofr n gS ;fn rkj dh yEckbZ rFkkf=T;k dks nqxuk dj fn;k tk,s rFkk ruko leku j[kk tk;srks u;h ewy vko`fr gksxh :
(1) n
2(2)
n
2 2
(3) 2n (4) n4
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31. In the case of an inductor :
(1) voltage lags the current by 2p
(2) voltage leads the current by 2p
(3) voltage leads the current by 3p
(4) voltage leads the current by 4p
32. Decay rate for a certain mass of a radioactivesubstance measured at diffrent times varies withtime as shown in fig. countrate at t = 8 hr will be :-
200
150
100
50
2 4 t (hr)
Dec
ays/s
ec
(1) 252
decays/sec (2) 50 decays/sec
(3) 500 decays/sec (4) 750 decays/sec33. A particle of mass m moving with a velocity u
makes an elastic one dimensional collision witha stationary particle of mass m establishing acontact with it for extremely small time T. Theirforce of contact increases from zero to F0 linearly
in time T4
, remains constant for a further time T2
and decreases linearly from F0 to zero in further
time T4
as shown. The magnitude possessed by F0
is:-
F
T3T/4t
F0
OT/4
(1) muT
(2) 2mu
T(3)
4mu3T
(4) 3mu4T
31. ,d izsjdRo dh fLFkfr esa]
(1) oksYVrk /kkjk ls 2p
ihNs gksrh gSA
(2) oksYVrk /kkjk ls 2p
vkxs gksrh gSA
(3) oksYVrk /kkjk ls 3p
vkxs gksrh gSA
(4) oksYVrk /kkjk ls 4p
vkxs gksrh gSA
32. ,d jsfM;ks,fDVo inkFkZ fo?kVu dh nj dks fHkUu&fHkUu le;ksij ekik tkrk gS ftldk le; ds lkFk ifjorZu fp=kuqlkjgSA rks t = 8 hr ij x.kuk nj gksxh :-
200
150
100
50
2 4 t (hr)
Dec
ays/s
ec
(1) 252
decays/sec (2) 50 decays/sec
(3) 500 decays/sec (4) 750 decays/sec33. m nzO;eku dk ,d d.k u osx ls m nzO;eku ds ,d vU;
vU; fLFkj d.k ls ,d foeh; izR;kLFk la?kê djrk gS] rFkkla?kê ds i'kkr~ nksuks d.k vYi le; T rd ijLij laidZ
es j gr s gSaA l e; kar j ky T4
esa laidZ cy dk eku 0 ls F0
rd jSf[kd #i ls c<+rk gS] rRi'pkr~ T2
le; rd fu;r
jgrk gS rFkk fQj T4
le; esa jSf[kd #i ls ?kVdj 'kwU;
gks tkrk gS] tSlk fd fp= esa iznf'kZr gSA F0 dk ifjek.k gS:-
F
T3T/4t
F0
OT/4
(1) muT
(2) 2mu
T(3)
4mu3T
(4) 3mu4T
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34. Two waves represented by,
y1 = 10sin 200pt,
y2 = 20sin 2000 t2pæ öp +ç ÷
è øare superimposed at any point at a particular instant.The amplitude of the resultant wave is :
(1) 200 (2) 30 (3) 10 5 (4) 10 3
35. An electric dipole with dipole moment
30ˆ ˆp (3i 4 j) 10-= + ´r C-m is placed in an electric
field ˆE 4000i=r
(N/C). An external agent turns thedipole slowly until its electric dipole moment
becomes ( )ˆ ˆ4i 3 j- + × 10–30C-m. The work done
by the external agent is equal to :–(1) 4 × 10–28 J (2) –4 × 10–28 J(3) 2.8 × 10–26 J (4) –2.8 × 10–26 J
36. If maximum and minimum amplitude ofamplitude modulated wave is 8V and 2Vrespectively then calculate modulation index :-(1) 0.8 (2) 0.4 (3) 0.6 (4) 1
37. The value of escape velocity on a certain planetis 2 km/s. Then the value of orbital speed for asatellite orbiting close to its surface is :-(1) 12 km/s (2) 1 km/s
(3) 2 km/s (4) 2 2 km /s38. The velocity of sound in air is 330 m/s. The
fundamental frequency of an organ pipe open atboth ends and of length 0.3 m will be :(1) 200 Hz (2) 550 Hz (3) 330 Hz (4) 275 Hz
39. The coercive force for a certain permanent magnetis 4.0 × 104 A/m. This magnet is placed inside along solenoid of 40 tunrs/cm and a current ispassed in the solenoid to demagnetise itcompletely. Find the current.(1) 1 A (2) 5 A (3) 10 A (4) 20 A
40. In the circuit, if the forward voltage drop for thediode is 0.5 V, the current will be :-
2.2 kW
0.5 V
8V
(1) 3.4 mA (2) 2 mA (3) 2.5 mA (4) 3 mA
34. nks rjax,y1 = 10sin 200pt,
y2 = 20sin 2000 t2pæ öp +ç ÷
è ø,d fcUnq ij feyrh gS] rks ifj.kkeh rjax dk vk;kegksxk :
(1) 200 (2) 30 (3) 10 5 (4) 10 3
35. f}èk z qo vk?k w.k Z 30ˆ ˆp (3i 4 j) 10-= + ´r C-m okys ,d
ˆE 4000i=r
(N/C) fo|qr {ks= esa j[kk x;k gSA ,d ckádkjd f}èkzqo dks rc rd èkhjs ¥èkhjs ?kqekrk gS tc rd fd
bldk fo|qr f}èkz qo vk?kw.kZ ( )ˆ ˆ4i 3 j- + × 10–30C-m
ugh a gk s tkrk gSA cká dkjd }kjk fd;k x;k dk;Zgksxk :–
(1) 4 × 10–28 J (2) –4 × 10–28 J
(3) 2.8 × 10–26 J (4) –2.8 × 10–26 J
36. ;fn vk;ke ekMqfyr rjax dk vf/kdre rFkk U;wurevk;ke Øe'k% 8V rFkk 2V gks rks ekMqyu lqpdkadgksxk :-(1) 0.8 (2) 0.4 (3) 0.6 (4) 1
37. fdlh xzg ij iyk;u osx dk eku 2 km/s gSA bl xzgds lehi ifjØek djrs gq, fdlh mixzg dh d{kh; pkygksxh:-(1) 12 km/s (2) 1 km/s
(3) 2 km/s (4) 2 2 km /s38. gok esa /ofu dk osx 330 m/s gSA nks rjQ ls [kqys vkxZu
ikbi ftldh yEckbZ 0.3 m gS fd ewy vkofr gksxh :(1) 200 Hz (2) 550 Hz(3) 330 Hz (4) 275 Hz
39. ,d fuf'pr ykSg pqEcdh; inkFk Z ds fy, fuxzghrk4.0 × 104 A/m gSA bl pqEcd dks iw.kZr;k fopqEcdhrdjus ds fy, bls 40 Qsjs/lseh okyh ,d ifjukfydk esaj[kk x;k gS ftlesa /kkjk izokfgr gks jgh gS izokfgr /kkjk dkeku Kkr djksA(1) 1 A (2) 5 A (3) 10 A (4) 20 A
40. ifjiFk esa ;fn Mk;ksM + ds e/; vxz foHko iru 0.5 V gksrks /kkjk gksxh :-
2.2 kW
0.5 V
8V
(1) 3.4 mA (2) 2 mA (3) 2.5 mA (4) 3 mA
Use stop, look and go method in reading the question
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41. Mixture X = 0.02 mole of [CO(NH3)5SO4]Br and0.02 mole of [CO(NH3)5Br]SO4 was prepared in2 L solution.
1 L of mixture X + excess of AgNO3 solution® Y (PPT)1 L of mixture X + excess of BaCl2 solution® Z (PPT)
Number of moles of Y and Z are :-(1) 0.01, 0.01 (2) 0.02, 0.01(3) 0.01, 0.02 (4) 0.02, 0.02
42. The half cell reactions for rusting of iron are :
–2 2
12H 2e O H O( );E 1.23V
2+ + + ¾¾® °=+l
Fe2+ + 2e– ¾® Fe(s), E° = –0.44 VDG° (in kJ) for the reaction is :-(1) –76 (2) –322(3) –122 (4) –176
43. Which has the smallest bond angle (X–S–X) inthe given molecules :- (x = Halogen)(1) OSF2 (2) OSCl2
(3) OSBr2 (4) OSI2
44. Suppose the following reaction
3 2 4 2 4HNO H SO Conc.H SOElectrolysis
A B+¾¾¾¾¾¾® ¾¾¾¾¾®
3CH – C O
O
2 Product(Analgesicsantipyretic)
The structure of final product will be :-
(1)
NH – C – CH3
O
OH
(2)
O – C – CH3
O
2NH
(3)
NH – C – CH3
O
SO H3
(4)
O – C – CH3
O
NO 2
41. feJ.k X = 0.02 eksy [CO(NH3)5SO4]Br o 0.02 eksy[CO(NH3)5Br]SO4 dk 2 yhVj foy;u esa cuk;k x;kgSA
X dk 1 L feJ.k + AgNO3 foy;u vfèkD; ® Y(vo{ksi)X dk 1 L feJ.k + BaCl2 dk foy;u vfèkD; ® Z(vo{ksi)
rks Y o Z ds eksy gksaxs :-(1) 0.01, 0.01 (2) 0.02, 0.01(3) 0.01, 0.02 (4) 0.02, 0.02
42. vk;ju ds tax (Rusting) yxus ds nkSjku fuEu v¼ZvfHkfØ;k,sa gksrh gS
–2 2
12H 2e O H O( );E 1.23V
2+ + + ¾¾® °=+l
Fe2+ + 2e– ¾® Fe(s), E° = –0.44 VlSy vfHkfØ;k ds fy, DG° (kJ esa) esa gksxk :-(1) –76 (2) –322 (3) –122 (4) –176
43. fdl v.kq es a X–S–X ca/k dks.k U;wure gksxk(x = gSykstu):-(1) OSF2 (2) OSCl2
(3) OSBr2 (4) OSI2
44. fuEu vfHkfØ;k ds vafre mRikn dh lajpuk gksxh
+¾¾¾¾¾¾® ¾¾¾¾¾®3 2 4 2 4HNO H SO H SOA BlkUnzfo|qr vi?kVu
3CH – C O
O
2 mRikn(
)ihMkgkjh ,ao
Tojuk'kh
(1)
NH – C – CH3
O
OH
(2)
O – C – CH3
O
2NH
(3)
NH – C – CH3
O
SO H3
(4)
O – C – CH3
O
NO 2
Take it Easy and Make it Easy
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45. ;fn iksVsf'k;e MkbØksesV dk vuqekiu eksj yo.k ds lkFkMkbZQsfuy,sfeu lwpd }kjk fd;k tk;s rks ik sV sf'k;eMkbØksesV ds ,d eksy ds lkFk eksj yo.k ds fuEu eksyksdh vko';drk gksxh :-(1) 3 (2) 4 (3) 5 (4) 6
46. j{kh dksykWbM P, Q, R o S ds Lo.kZ la[;k ds eku Øe'k%0.1, 0.05, 0.6 o 0.5 gSA budh j{k.k {kerk dk lgh Øegksxk :-(1) P > R > Q > S (2) Q > R > P > S(3) Q > P > S > R (4) bues dksbZ ugha
47. fuEufyf[kr vkf.od iztkfr;ksa dks muds ca/k Øe ds c<+rsgq, Øe esa tek;k x;k gSA lgh Øe dks igpkfu,A(I) O2 (II) O2
–
(III) O2–2 (IV) O2
+
(1) III < II < I < IV (2) IV < III < II < I(3) III < II < IV < I (4) II < III < I < IV
48. fuEu vEy {kkj vfHkfØ;k ds eq[; mRikn dh lajpuk gksxh\
O
N
H
NH2 CH – NH2 2
N – H HCl(1mol)¾¾¾¾¾® mRikn
(1)
O
NCl
NH2 CH – NH2 2
N – H
H H
(2)
O
N
H
NH Cl3CH – NH2 2
N – H
(3)
O
N
H
NH2 CH – NH2 2
N HH
Cl
(4) O
N
H
NH2 CH – NH Cl2 3
N – H
45. Consider a titration of potassium dichromatesolution with acidified Mohr's salt solution usingdiphenylamine as indicator. The number of molesof Mohr's salt required per mole of dichromate is:-(1) 3 (2) 4 (3) 5 (4) 6
46. Gold numbers of protective colloids P, Q, R andS are 0.1, 0.05, 0.6 and 0.5 respectively. Thecorrect order of their protective powers is :-(1) P > R > Q > S (2) Q > R > P > S(3) Q > P > S > R (4) None of these
47. The following molecular species have beenarranged in the order of their increasing bondorders identify the correct order(I) O2 (II) O2
– (III) O2–2 (IV) O2
+
(1) III < II < I < IV (2) IV < III < II < I(3) III < II < IV < I (4) II < III < I < IV
48. Suppose the following acid base reaction
O
N
H
NH2 CH – NH2 2
N – H HCl(1mol)¾¾¾¾¾® product
The structure of main product will
(1)
O
NCl
NH2 CH – NH2 2
N – H
H H
(2)
O
N
H
NH Cl3CH – NH2 2
N – H
(3)
O
N
H
NH2 CH – NH2 2
N HH
Cl
(4) O
N
H
NH2 CH – NH Cl2 3
N – H
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49. The term that corrects the attractive forces presentin a real gas in the van der Waal's equation is :-(1) nb (2) n2a/V2
(3) –(n2a/V2) (4) –nb50. An ionic solid of XY type having anions in CCP
lattice and cations in the octahedral voids. Let a bethe edge length of an FCC cube. The radius ratioof cation (R+) to that of anion (R–) is greater than0.415. Then which of the following is false :-
(1) a
R2 2
+ =
(2) –a
R R2+ + =
(3) Anions will not be in contact each other.(4) Cations will not be in contact with each other
51. An element has successive ionisation enthalpiesas 940, 2080, 3090, 4140, 7030, 7870, 16000 and19500 kJ/mole To which group of periodic tabledoes this element belongs?(1) 14 (2) 15 (3) 16 (4) 17
52. Arrange the following in order of their reactivitytoward HI?
(I)
OH
(II)
CH – OH2
(III) CH
OH
(IV) CH – OH
CH3
(1) IV > III > II > I (2) I > II > III > IV(3) III > IV > II > I (4) II > III > I > IV
53. The maximum number of electrones that can haveprincipal quantum number, n = 3 and spin
quantum numbers = 1
–2
is :-
(1) 4 (2) 8 (3) 18 (4) 954. Trioxalatoaluminate (III) and tetrafluridoborate
(III) ions are :-(1) [Al(C2O4)3], [BF4]
–3
(2) [Al(C2O4)3]+3, [BF4]
+3
(3) [Al(C2O4)3]–3, [BF4]
–
(4) [Al(C2O4)3]–2, [BF4]
–2
49. fuEu es ls dkSulk in okLrfod xSl esa varjvkf.odvkd"kZ.k esa lq/kkj dks n'kkZrk gS :-(1) nb (2) n2a/V2
(3) –(n2a/V2) (4) –nb50. ,d XY izdkj ds vk;fud Bksl ds varxZr ½.kk;u CCP
esa fØLVyhÏr gksrk gS tcfd /kuk;u v"BQydh; varjkyesa fLFkr gksrk gSA ekuk a bZdkbZ lsy (FCC) dh Hkqtk yEckbZgSA ;fn R+ /R– (f=T;k vuqikr) dk eku 0.415 ls vfèkdgSA fuEu es ls dkSulk dFku xyr gS :-
(1) a
R2 2
+ =
(2) –a
R R2+ + =
(3) ½.kk;u ,d nwljs ds lEidZ es ugh gksaxsA(4) /kuk;u ,d nwljs ls lEidZ esa ugh gksaxsA
51. ,d rRo dh Øekxr vk;uu ÅtkZ ds eku Øe'k% 940,2080, 3090, 4140, 7030, 7870, 16000 rFkk19500 kJ/mole gSA ;g rRo vkorZ lkj.kh ds fdl oxZls lEcfU/kr gS\(1) 14 (2) 15 (3) 16 (4) 17
52. HI ds izfr fuEu dks vfHkfØ;k'khyrk ds Øe es O;ofLFkrdjs\
(I)
OH
(II)
CH – OH2
(III) CH
OH
(IV) CH – OH
CH3
(1) IV > III > II > I (2) I > II > III > IV(3) III > IV > II > I (4) II > III > I > IV
53. vf/kdre bysDVªksuksa dh la[;k D;k gksxh ftuds fy, eq[;
Dok.Ve la[;k] n = 3 o pØ.k Dok.Ve la[;k s =1
–2
gS :-(1) 4 (2) 8 (3) 18 (4) 9
54. VªkbZvkDlhysVks,Y;qfeusV (III) rFkk VsVªk¶yksjkbMkss cksjsV (III)vk;u gS :-(1) [Al(C2O4)3], [BF4]
–3
(2) [Al(C2O4)3]+3, [BF4]
+3
(3) [Al(C2O4)3]–3, [BF4]
–
(4) [Al(C2O4)3]–2, [BF4]
–2
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55. The second electron gain enthalpies (in kJ/mole)of oxygen and sulphur respectively are :-(1) –780, +590 (2) –590, +780(3) +590, +780 (4) +780, +590
56. The correct IUPAC name of following compoundwill be
(1) 3–Ethyl–1–isopropyl–1–methyl cyclohexane(2) 1–Ethyl–3–isopropyl–3–methyl cyclohexane(3) 1–Ethyl–3–methyl–3–isopropyl cyclohexane(4) 1–Isopropyl–1–methyl–3–ethyl cyclohexane
57. 2.5 mL of 2
M5
weak monoacidic base
(Kb = 1 × 10–12 at 25°C) is titrated with 2
M15
HCl
in water at 25°C. The concentration of H+ atequivalence point is (Kw = 1 × 10–14 at 25°C) :-(1) 3.7 × 10–13 M (2) 3.2 × 10–7 M(3) 3.2 × 10–5 M (4) 2.7 × 10–2 M
58. All the following complex ions are found to beparamagnetic :-(P) [FeF6]
–3 (Q) [CoF6]–3
(R) [V(H2O)6]+3 (S) [Ti(H2O)6]
+3
The correct order of their magnetic moments(spin only) is :-(1) P > Q > R > S(2) P < Q < R < S(3) P = Q = R = S(4) P > R > Q > S
59. A cyclic skeleton of silicon and oxygen canconstructed by the silicate ion with composition :-(1) Si2O7
–4 (2) Si2O5–2
(3) SiO3–2 (4) SiO4
–4
60. "Isoelectric point" for amino acid is referfor :-(1) pH at which amino acid move toward
cathode(2) pH at which amino acid move toward
anode(3) pH at which amino acid does not move toward
any electrode(4) pH at which amino acid form peptide linkage
55. vkWDlhtu rFkk lYQj dh f}rh; bysDVªkWu xzg.k ,UFksYihds eku Øe'k% gksaxs (in kJ/mole) :-(1) –780, +590 (2) –590, +780(3) +590, +780 (4) +780, +590
56. fuEu ;kSfxd dk lgh IUPAC uke gksxk
(1) 3–Ethyl–1–isopropyl–1–methyl cyclohexane
(2) 1–Ethyl–3–isopropyl–3–methyl cyclohexane
(3) 1–Ethyl–3–methyl–3–isopropyl cyclohexane
(4) 1–Isopropyl–1–methyl–3–ethyl cyclohexane
57. ;fn 2.5 mL, 2
M5
,dy vEyh; nqcZy {kkj (Kb = 10–12)
dk vuqekiu 2
M15
HCl foy;u ls djk;k tk;s rks rqY;kad
fcanw ij H+ vk;u lkaærk gSA (;fn Kw = 10–14) :-
(1) 3.7 × 10–13 M (2) 3.2 × 10–7 M
(3) 3.2 × 10–5 M (4) 2.7 × 10–2 M
58. fn, x, lHkh ladqy vk;u vuqpqEcdh; izÏfr dsgS :-(P) [FeF6]
–3 (Q) [CoF6]–3
(R) [V(H2O)6]+3 (S) [Ti(H2O)6]
+3
buds pqEcdh; vk?kw.k Z (dsoy pØ.k) dk lgh Øegksxk :-(1) P > Q > R > S(2) P < Q < R < S(3) P = Q = R = S(4) P > R > Q > S
59. flfydkWu rFkk vkWDlhtu ds la;ksx ls cuh pØh; flfydsVvkÏfr esa mifLFkr vk;u dk laxBu gksxk :-(1) Si2O7
–4 (2) Si2O5–2
(3) SiO3–2 (4) SiO4
–4
60. vehuks vEy ds fy, vkblksbysfDVªd fLFkjkad dk erycgksrk gS :-(1) og pH ftl ij vehuks vEy dSFkk sM dh vksj
LFkkukUrjhr gksrs gSA(2) og pH ftl ij vehuks vEy ,suksM dh vksj LFkkukUrfjr
gksrs gSA(3) og pH ftl ij vehuks vEy fdlh Hkh bysDVªksM dh
vksj LFkkukUrjhr ugha gksrs gSA(4) og pH ftl ij vehuks vEy iIVkbM cU/k cukrs gSA
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61. Total number of diprotic acid among the followingis/areH3PO2, H2SO4, H3PO3, H2CO3, H2S2O7, H3BO3 :-(1) 1 (2) 4 (3) 3 (4) 6
62. Among the following metal carbonyls the C–Obond is strongest :-(1) [Mn(CO)6]
+ (2) [Cr(CO)6](3) [V(CO)6]
– (4) [Ti(CO)6]–2
63. MF + XeF4 ¾® A (M+ = Alkali metal cation).The state of hybridisation of the central atom in'A' and shape of the species are :-(1) sp3d, TBP(2) sp3d2 (Distorted octahedral(3) sp3d3, pentagonal planer(4) No compound formed at all
64. Threat of ozone layer deplition is associated with :-(1) Decomposition of O3 in stretosphere(2) Formation of O3 in atmosphere(3) Formation of O3 from O2
(4) Use of ozone as coolent.65. An example of a reversible reaction is :-
(1) Pb(NO3)1(aq) + 2NaI(aq) = PbI2(s) + 2NaNO3(aq)(2) AgNO3(aq) + HCl(aq) = AgCl(s) + HNO3(aq)(3) 2Na(s) + 2H2O(l) = 2NaOH(aq) + H2(g)(4) CH3COOH(aq) + CH3CH2OH(aq)
= CH3COOC2H5(aq) + H2O(l)66. Main source of lead is galena. It is converted to
Pb by :
(X) : PbS airD¾¾® PbO + SO2
C Pb + CO2
(Y) : PbS airD¾¾® PbO + PbS
Pb + SO2
(Z) : PbS airD¾¾® PbO + SO2
CO Pb + CO2
Self – reduction process is :-(1) X (2) Y (3) Z (4) None
67. The formula of sodium zeolite which is used inpermutit process for softering of water is :-(1) Na2O.Al2O3. Si2O4.4H2O(2) Na2Al2Si2O4.4H2O(3) Na2O.AlO3.SiO4.4H2O(4) K2Al2SiO8.4H2O
61. fuEufyf[kr es ls f}{kkjdh; vEyks dh la[;k gSAH3PO2, H2SO4, H3PO3, H2CO3, H2S2O7, H3BO3,H3PO2 :-(1) 1 (2) 4 (3) 3 (4) 6
62. fn, x, /kkrq dkcksZfuyksa esa C–O ca/k dk lkeF;Z lokZfèkdgksxk :-(1) [Mn(CO)6]
+ (2) [Cr(CO)6](3) [V(CO)6]
– (4) [Ti(CO)6]–2
63. MF + XeF4 ¾® A (M+ = {kkjh; /kkrq /kuk;u).'A' esa dsUæh; ijek.kq dh ladj.k voLFkk rFkk iztkfr dkvkdkj gksxk :-(1) sp3d, TBP(2) sp3d2 (fod`r v"VQydh;)(3) sp3d3, iapHkqth; leryh;(4) dksbZ ;kSfxd ugha cusxk
64. vkstksuh{kj.k dk ladV lEcfU/kr gS :-(1) LVªhVksLQh;j O3 dk {kj.k(2) ok;qe.My es O3 dk fuekZ.k(3) O2 ls O3 dk fuekZ.k(4) BaMd (coolent) dh rjg O3 dk mi;ksx
65. ÅRØe.kh; vfHkfØ;k dk mnkgj.k gS :-(1) Pb(NO3)1(aq) + 2NaI(aq) = PbI2(s) + 2NaNO3(aq)(2) AgNO3(aq) + HCl(aq) = AgCl(s) + HNO3(aq)(3) 2Na(s) + 2H2O(l) = 2NaOH(aq) + H2(g)(4) CH3COOH(aq) + CH3CH2OH(aq)
= CH3COOC2H5(aq) + H2O(l)66. lhls dk izeq[k L=ksr xsysuk gSA bls Pb esa ifjofrZr fd;k
tk ldrk gS :
(X) : PbS airD¾¾® PbO + SO2
C Pb + CO2
(Y) : PbS airD¾¾® PbO + PbS
Pb + SO2
(Z) : PbS airD¾¾® PbO + SO2
CO Pb + CO2
fuEu esa lss Lo&vip;u izØe gS :-(1) X (2) Y (3) Z (4) None
67. ijE;wfVd izØe esa ikuh dks 'kq¼ djus ds fy, dke esa fy,tkus okysa lksfM;e ftvksykbV dk lw= gksxk :-(1) Na2O.Al2O3. Si2O4.4H2O(2) Na2Al2Si2O4.4H2O(3) Na2O.AlO3.SiO4.4H2O(4) K2Al2SiO8.4H2O
fdlh iz'u ij nsj rd :dks ugha A
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68. Which of the following is most reactive towardnucleophlic substution from?
(1)
Cl
CH3
(2)
Cl
NO2
(3)
CH – Cl
NO2
2
(4)
CH – Cl2
69. One mole of monatomic ideal gas expandsadiabatically at initial temperature T against aconstant external pressure from 1L to 2L. Find outthe final temperature (R = 0.0821 L atm mol–1K–1) :-
(1) T (2) 5–1
3
T
(2)
(3)2
T –3 0.082´
(4) 2
T3 0.082
+´
70. The chemical composition of slag formed during thesmelting process in the extraction of copper is :-(1) Cu2O + FeS (2) FeSiO3
(3) CuFeS2 (4) Cu2S + FeO71. Which of the following will be major product of
given reaction?
CH = CH – CH = CH2 HClD
¾¾¾® product
(1) CH – CH = CH – CH3
Cl
(2) CH = CH – CH – CH3
Cl
(3) CH – CH = CH – CH2
Cl
2
(4) CH = CH – CH – CH2
Cl
2
68. ukfHkd Lusgh izfrLFkkiu ds fy, dkSu lokZf/kd fØ;k'khygksxk\
(1)
Cl
CH3
(2)
Cl
NO2
(3)
CH – Cl
NO2
2
(4)
CH – Cl2
69. ,d eksy ,d ijek.oh; vkn'kZ xSl dks izkjfEHkd rki Tij :¼ks"eh; :i ls fu;r ckg~; nkc ds fo:¼ 1 L ls2L rd izlkfjr djrs gS rks vafre rki Kkr dhft,(R = 0.0821 L atm mol–1K–1) :-
(1) T (2) 5–1
3
T
(2)
(3)2
T –3 0.082´
(4) 2
T3 0.082
+´
70. Cu ds fu"d"kZ.k esa izxyu ds nkSjku cuus okys /kkrqey dkjklk;fud la?kVu gS gksxk :-(1) Cu2O + FeS (2) FeSiO3
(3) CuFeS2 (4) Cu2S + FeO71. fuEu vfHkfØ;k dk eq[; mRikn gksxk\
CH = CH – CH = CH2 HClD
¾¾¾® mRikn
(1) CH – CH = CH – CH3
Cl
(2) CH = CH – CH – CH3
Cl
(3) CH – CH = CH – CH2
Cl
2
(4) CH = CH – CH – CH2
Cl
2
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72. Which of the following give white precipitate,when treated with AgNO3?
(1)
NH 2
Cl
(2)
CH 3Cl
(3)
NH Cl3
(4)
Cl
NO2
73. Plots showing the variation of the rate constant(k) with temperature (T) are given below. The plotthat follows Arrhenius equation is :-
(1)
k
T
(2)
k
T
(3)
k
T
(4)
k
T
74. 'A' + H2O ¾® NaOH;
'A' 2O400 C°
¾¾¾® B 2H Oat 25 C°
¾¾¾¾® NaOH + O2
B is used for oxygenating in submarine A and Bare :-(1) Na2O2 and Na2O(2) Na2O and Na2O2
(3) Na2O2 and O2
(4) Na2O and O2
72. fuEu l s dk Su AgNO3 ds lkFk lQsn vo{k sicuk;sxk?
(1)
NH 2
Cl
(2)
CH 3Cl
(3)
NH Cl3
(4)
Cl
NO2
73. nj fu;rkad (k) dk rki (T) ds lkFk ifjorZu fuEu xzkQ}kjk n'kkZ;k tkrk gSA xzkQ tks vkjsfu;l lehdj.k dh ikyukdjrk gS :-
(1)
k
T
(2)
k
T
(3)
k
T
(4)
k
T
74. 'A' + H2O ¾® NaOH;
'A' 2O400 C°
¾¾¾® B 2H Oat 25 C°
¾¾¾¾® NaOH + O2
B dk mi;ksx iuMqCch esa vkDlhtu iznku djus esa gksrkgSA A rFkk B gksaxs :-(1) Na2O2 and Na2O(2) Na2O and Na2O2
(3) Na2O2 and O2
(4) Na2O and O2
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75. Which of the following compound give threedifferent types of carbonyl compounds, onozonolysis reaction?
(1)
CH3
(2)
CCH3 CH3
(3)
CCH3 CH3
CCH3 CH3
(4)
CH3
CH3
76. Which of the following statement is correct foroptical activity in compounds?
(1) Presence of chiral center is necessary conditionfor optical isomerism.
(2) Presence of chirality in molecule is necessaryfor optical isomerism.
(3) Compounds having plane of symmetry maybe optical active.
(4) 1, 2 dichlorocyclo pentane exist in four stereoisomeric form.
77. 0.004M Na2SO4 is isotonic with 0.01 M glucose.Degree of dissociation of Na2SO4 is :-
(1) 75% (2) 50%
(3) 25% (4) 85%
78. Which has maximum dipole moment?
(1)
(2)
(3)
(4)
75. fuEu es ls fdldh vkstksuh vi?kVu vfHkfØ;k es rhuvyx&vyx izdkj ds dkcksZfuy ;kSfxd cusaxs\
(1)
CH3
(2)
CCH3 CH3
(3)
CCH3 CH3
CCH3 CH3
(4)
CH3
CH3
76. izdkf'kd lfØ;rk ds fy, dkSulk dFku lR; gS\
(1) izdkf'kd lfØ;rk ds fy, fdjsy dsUæ dh mifLFkfrvfuok;Z gSA
(2) izdkf'kd lfØ;rk ds fy, ;kSfxd dk fdjsy gksukvfuok;Z gSA
(3) ;kSfxd ftlesa niZ.k lefefr gksrh gS oks izdkf'kd lfØ;gks ldrs gSA
(4) 1, 2 MkbZ Dyksjks lkbDyksisUVsu pkj f=foe lek;oh cukrkgSA
77. 0.004M Na2SO4 foy;u 0.01 M Xywdksl foy;u ds lkFkleijkljh gS rks Na2SO4 ds fo;kstu dh ek=k gksxh :-
(1) 75% (2) 50%
(3) 25% (4) 85%
78. fuEu esa ls fdldk f}/kzqo vk?kw.kZ lokZf/kd gS\
(1)
(2)
(3)
(4)
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79. Suppose the following reaction
NH2
NaNO + HCl2(0° – 5°C)
A
NCH3 CH3
OHProduct
The main product of above reaction will be :-
(1)
NH2
N – CH3
(2)
CH3 CH3N
N
N
(3)
NH2
NCH3 CH3
(4)
CH3 CH3N
N = N
80. Which of the following addition reaction proceedsthrough formation of cycle intermediate/transitionstate?
(1) Addition of Br2
(2) Hydroxylation by dil. KMnO4/OH1
(3) Hydroboration oxidation reaction
(4) All of these
79. fuEu vfHkfØ;k dk eq[; mRikn gksxk
NH2
NaNO + HCl2(0° – 5°C)
A
NCH3 CH3
OHmRikn
(1)
NH2
N – CH3
(2)
CH3 CH3N
N
N
(3)
NH2
NCH3 CH3
(4)
CH3 CH3N
N = N
80. fuEu es ls fdl ;ksxkRed vfHkfØ;k es pØh; e/;orhZ
laØe.k voLFkk curk gS\
(1) Br2 dh ;ksxkRed vfHkfØ;k
(2) ruq KMnO4/OH1 dh ;ksxkRed vfHkfØ;k
(3) gkbMªkscksjs'ku vkDlhdj.k vfHkfØ;k
(4) lHkh
LoLFk jgks] eLr jgks rFkk i<+kbZ esa O;Lr jgks A
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81. Prop roots of banyan tree are meant for :-
(1) Respiration
(2) Food storage
(3) Retention of water in soil
(4) Providing support to big tree
82.A B
Solute molecule
Water
Semi-permeablemembrane
Choose the correct option with respect to abovediagram :-
ywDPD OP
1 High in B High in B High in A
2 High in B High in A High in A
3 low in B low in A low in A
4 low in B low in B High in A
83. Find the correct match of column I with Column II
from the given options :-
Column I Column II
(A) SaccharumBarberi
(i) Higher sugar content
(B) Saccharumofficinarum
(ii) North-India
(iii) Poor sugar content
(iv) Thicker stem
Options :-
(1) (A)-(ii),(iii) (2) (A)-(ii),(iv)
(3) (B)-(i),(iii) (4) (B)-(ii),(iv)
81. cjxn ds o`{k dh LrEHk ewysa fdlds fy, gksrh gSa :-
(1) 'olu ds fy,
(2) Hkkstu lap; ds fy,
(3) e`nk esa ty iquZ/kkj.k
(4) cM+sa o`{k dks lgkjk iznku djus ds fy,
82.A B
Solute molecule
Water
Semi-permeablemembrane
mijksDr fn;s x;s fp= ds lanHkZ esa lgh fodYi dk pquko
dhft, :-
ywDPD OP
1 B esa mPp B esa mPp A esa mPp
2 B esa mPp A esa mPp A esa mPp
3 B esa fuEu A esa fuEu A esa fuEu
4 B esa fuEu B esa fuEu A esa mPp
83. dkWye I dk dkWye II ds lkFk fn, x, fodYiksa ds lgk;rk
ls lgh feyku dks igpkusa :-
dkWye I dkWye II
(A) lSdsje ckjcjh (i) mPp 'kdZjk va'k
(B) lSdsje vkSQhflusje (ii) mÙkjh Hkkjr
(iii) de 'kdZjk va'k
(iv) eksVk ruk
fodYi :-
(1) (A)-(ii),(iii) (2) (A)-(ii),(iv)
(3) (B)-(i),(iii) (4) (B)-(ii),(iv)
J ges'kk eqLdjkrs jgs a A
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84. Read the following four statements (A-D) :-
(a) Tapetum is the outermost layer of the anther.
(b) Tapetum helps in the formation ofsporopollenin
(c) Cells of the tapetum are polyploid(d) Cells of the tapetum secrete hormone and
enzymes.How many of the above statements are incorrect ?(1) Four (2) One(3) Two (4) Three
85. Pericycle of roots is the site of origin of :-(1) Lateral roots(2) Secondary meristem(3) Cork cambium(4) All of the above
86. How many oxygen atoms required during completeoxidation of 1mol. of Acetyl co enzyme A :-(1) 2 (2) 4 (3) 5 (4) 2.5
87. In our primitive atmosphere the condition on earthwas/were :-(1) Volcanic storms(2) Reducing atmosphere(3) High Temperature(4) All above
88. What would be the number of chromosomes ofthe antipodal cells of a plant with 45 chromosomesin its aleurone layer cells ?(1) 60 (2) 30 (3) 15 (4) 45
89. Leafly gametophore or advanced gametophyteoccur in :(1) Bryopsida (2) Hepaticopsida(3) Antheropsida (4) Pteropsida
90. Find out the correct match from the followingtable with respect to photosynthetic pathways :-
Column I Column II Column III
i Maize PEPcase OAA
ii Wheat RuBisCo OAA
iii C4 Pathway KranzAnatomy
Photorespirationabsent
iv CAM Pathway KranzAnatomy
Malatestorage
(1) i, iii & iv (2) ii & iii(3) ii, iii & iv (4) i & iii
84. fuEufyf[kr pkj dFkuksa dks if<+, (A-D) :-
(a) VsihVe ijkxdks"k dk lcls ckfg; Lrj gksrk gSA(b) VsihVe Lik sjksik sysfuu ds fuekZ.k esa lgk;d gksrh
gSA(c) VsihVe dh dksf'kdk,sa cgqxqf.kr gksrh gSA(d) VsihVe dh dksf'kdk,sa gkeksZu ,oa ,atkbe L=kfor djrh
gSAmijksDr dFkuksa esa fdrus dFku xyr gS ?(1) pkj (2) ,d(3) nks (4) rhu
85. ewyksa ds ifjjEHk ls fdldh mRifÙk gksrh gSa :-(1) ik'oZ ewysa(2) f}rh;d foHk;ksÙkd(3) dkx ,/kk(4) mijksDr lHkh
86. ,flVkby dks ,atkbe , ds ,d v.kq ds iw.kZ vkWDlhdj.kds fy, vkDlhtu ds fdrus ijek.kq vko';d gksrs gS :-(1) 2 (2) 4 (3) 5 (4) 2.5
87. gekjs izkjafHkd ok;qe.My esa i`Foh dh voLFkk Fkh :-
(1) Tokykeq[kh; rwQku okyh
(2) vip;hr ok;qe.My
(3) mPp rki ; qDr
(4) mijksDr lHkh
88. ml ikS/ks dh izfreq[kh dksf'kdkvksa esa xq.klw=ksa dh la[;kfdruh gksxh ftldh ,Y;wjksu dksf'kdkvksa esa xq.klw=ksa dhla[;k 45 gksrh gS?(1) 60 (2) 30 (3) 15 (4) 45
89. lcls fodflr ;qXedksn~fHkn fdlesa ik;k tkrk gS&
(1) czk;ksfIlM+k (2) ghisVhdksfIlM+k
(3) ,UFksjksfIlM+k (4) VsjksfIlM+k
90. izdk'k la'ys"k.k ekxkZs ds lanHkZ esa uhps nh xbZ lkj.kh esa lghfeyku dks igpkfu,A
Column I Column II Column III
i eDdk PEPcase OAA
ii xsgwa RuBisCo OAA
iii C4 iFk Økat'kkjhfjdh
izdk'k 'oluvuqifLFkr
iv CAM iFk Økat'kkjhfjdh
esysV laxzg
(1) i, iii & iv (2) ii & iii(3) ii, iii & iv (4) i & iii
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91. The same banding pattern of chromosome 3 and6 of human and chimpanzee show :-(1) Similar origin(2) Dissimilar origin(3) Same number of chromosome(4) Same blood group
92. The number of gametes and nuclei taking part indouble fertilization respectively are :-
(1) 5, 3 (2) 2, 5
(3) 3, 5 (4) 2, 493. Sporocarp formation occurs in which plants :
(1) Marsilea (2) Azolla(3) (1) and (2) (4) Gnetum
94. How many of the statements are true forvernalisation ?
(a) It prevents precocious reproductivedevelopment late in growing season.
(b) It affects quantity & quality of flowering.
(c) spring varieties of wheat requirevernalisation.
(d) Artificial vernalisation shortens the life spanin biennial plants
(e) vernalisation is required by all plants toinitiate flowering
(1) Two (2) Three (3) One (4) Four
95. BCG vaccine contains :-
(1) killed mycobacteria
(2) live attenuated mycobacteria
(3) recombinant protein of mycobacteria
(4) antibody against mycobacteria
96. Which of the following is not a cellular division?
(1) Spermatogonia (B) ® Primary spermatocyte
(2) Spermatogonia (A) ® Spermatogonia (B)
(3) Primary spermatocyte ® Secondary spermatocyte
(4) Secondary spermatocyte (B) ® spermatids
97. An important gymnospermic plant which iscommonly found in Rajasthan used as :
(1) AntiAsthmic (2) Anti pyretic
(3) Anti anuxiety (4) Induced sleep
91. euq"; ,oa fpaiSath ds 3 ,oa 6 xq.klw=ksa dk leku csaMhax isVuZiznf'kZr djrk gS :-(1) leku mRifÙk(2) vleku mRifÙk(3) xq.klw=ksa dh leku la[;k(4) leku jDr lewg
92. f}fu"kspu esa Øe'k% fdrus ; qXed o dsUæd Hkkx ysrsgS :-
(1) 5, 3 (2) 2, 5
(3) 3, 5 (4) 2, 493. LiksjksdkiZ dk fuekZ.k gksrk gS &
(1) eklhZfy;k (2) ,tksyk(3) (1) ,oa (2) (4) uhVe
94. clUrhdj.k ds fy, fuEu esa ls fdrus dFku lgh gS ?
(a) ;g vdkfyd iztuu ifjo/kZu dks o`f¼ ds ekSle esarc rd jksdrk gS] tc rd ikS/ks ifjiDo u gks tk,aA
(b) ;g iq"iu dks xq.kkRed ,oa ek=kRed rkSj ij izHkkfordjrk gSA
(c) xSg¡w dh clar fdLeksa esa clarhdj.k dh vko';drk gksrh gSA
(d) d`f=e clarhdj.k f}o"khZ ikS/kksa esa thou dky dks dedjrk gSA
(e) lHkh ikS/kks esa iq"iu ds fy, clarhdj.k dh vko';drk
gksrh gSA
(1) nks (2) rhu (3) ,d (4) pkj
95. BCG uked Vhds esa gksrs gSa %&
(1) e`r ekbdkscsDVhfj;k
(2) thfor nqcZy ekbdkscsDVhfj;k
(3) ekbdkscsDVhfj;k dk fjdkfcusUV çksVhu(4) ekbdkscsDVhfj;k ds fo:¼ ,aVhckWMh
96. fuEu esa dkSu&lk dksf'kdh; foHkktu ugha gS ?
(1) LiesZVksxksfu;k (B) ® izk;ejh LiesZVkslkbV
(2) LiesZVksxksfu;k (A) ® LiesZVksxksfu;k (B)
(3) izk;ejh LiesZVkslkbV® f}rh;d LiesZVkslkbV
(4) lSd.Mjh LiesZVkslkbZV (B) ® LiesZfVM97. ,d egRoiw.kZ vukorchth ikS/kk tks eq[;r;k jktLFkku esa
ik;k tkrk gSa iz;ksx fd;k tkrk gS &(1) nekjks/kh (2) cq[kkj mrkjus esa(3) fpUrk eqDr djus esa (4) uhan c<+kus esa
Time Management is Life Management
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98. The given figure shows a section of smallintestinal mucosa showing villi. Identify A to D :-
AB
C
ArteryD
Vein
(1) A- Crypts, B-Lacteal, C-Capillaries, D-Villi(2) A- Villi, B-Lacteal, C-Crypts, D-Capillaries(3) A- Lacteal, B- Villi, C- Capillaries, D- Crypts(4) A- Villi, B- Lacteal, C- Capillaries, D- Crypts
99. What is not true about pneumonia(1) Fever with chills(2) Alveoli filled with fluid(3) in severe cases fingernails turn blue from gray(4) feco oral route
100. Among the following hormones, which hormonesshows two (2) prominent peaks of concentrationduring menstrual cycle :-(1) Progesteron(2) Estrogen(3) Leutenising hormone(4) Follicular stimulating hormone
101. Flat worms are :-
(a) Bilaterally symetrical
(b) Triploblastic(c) Pseudo coelomate(d) Organ level organisation(1) All are true (2) a,b,c, are true(3) b and d are true (4) a,b and d are true
102. The vital capacity of the lung signifies the volumeof air :-
(1) Breathed in during normal inspiration(2) Breathed out with forcible expiration
(3) Breathed in with forcible inspiration(4) Expired forcefully after forced inspiration
98. fn;k x;k vkjs[k NksVh vkar ds E;wdkslk dh dkV dks n'kkZrkgS] ftlesa foykbZ mifLFkr gSA A-D dks igpkfu, :-
AB
C
ArteryD
Vein
(1) A- njkjsa, B-ySfDV;y, C-dsf'kdk,sa, D-foykbZ(2) A- foykbZ, B-ySfDV;y, C-njkjsa, D-dsf'kdk,sa(3) A- ySfDV;y, B- foykbZ, C- dsf'kdk,sa, D- njkjsa(4) A- foykbZ, B- ySfDV;y, C- dsf'kdk,sa, D- njkjsa
99. U;weksfu;k ds ckjs esa vlR; gS(1) daidaih okyk cq[kkj(2) æo ls Hkjh dwfidk;sa(3) xEHkhj ekeyksa esa uk[kwuksa dk uhyk iM+ tkuk(4) Qhdks vksjy ekxZ ls laØe.k
100. fuEufyf[kr gkeksZUl esa ls fdl gkeksZu esa vkrZo pØ(esaLVª¨vy lk;dy) esa nks izHkkoh ihd gksxh :-
(1) izkstsLVªkWu
(2) bLVªkstu
(3) ,y-,p (LH)
(4) ,Q-,l-,p (FSH)
101. piVs d`fe gksrs gSa :-(a) f}vkjh; lefer(b) fVªIyksCykfLVd(c) vlR; xqgh;(d) vax le 'kkjhfjd lajpuk
(1) mijksDr lHkh lR; gSa (2) a,b,c, lR; gSa(3) b vkSj d lR; gSa (4) a,b vkSj d lR; gSa
102. QsaQM+ksa dh tSfod {kerk dk vFkZ gS :-
(1) lkekU; vUr% 'olu esa ok;q dk vk;ru
(2) cfyr mPNkolu esa ok;q dk vk;ru
(3) cfyr vUr% 'olu esa ok;q dk vk;ru(4) cfyr vUr% 'olu ds i'pkr cfyr mPNkolu esa ok;q
dk vk;ru
viuh {kerk dks iwjk olwyus dk iz;kl djs a A
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103. Which one of the following option gives the correctcategorisation of three examples according to thetype of species (A,B,C) they give out ?
AKey stone
species
BCritical link
species
CEndemicspecies
(1) Meta sequioain china valley
lion in forest Mycorrhizalfungi
(2) Kangaroo inAustralia
Fig tree intropical forest
Pollinatorinsect
(3) Kangaroo Ratin Desert
Mycorrhizalfungi
Meta sequoiain china valley
(4) Lion in forest Kangaroo inAustralia
PollinatorInsect
104. Mendel selected garden pea for his experimentsbecause :-(1) Natural self pollination is present(2) Many contrasting traits are present(3) Garden pea is Biennial plant(4) Both (1) and (2)
105. Which type of WBC is active in nature :-(1) Acidophils and Neutrophil(2) Basophil and Monocyte(3) Neutrophil and Monocyte(4) Lymphocytes and Basophil
106. The diagram given here is the standard ECG ofa normal person. The P-wave represents the :-
R
P Q S T
(1) End of systole(2) Contraction of both the atria(3) Initiation of the ventricular contraction(4) Beginning of the systole
107. Which one is correct for succession ?
(1) Organism size
Humus contains
Speciesdiversity ¯
(2) Nichegeneralization
Nutrientconservationin plant ¯
Biomass
(3) Energy useefficiency
Nichespecialization
Complexityof food web
(4) Energy useefficiency ¯
Nichespecialization
Nutrientconservationin plant
103. fuEufyf[kr es a ls dkSulk ,d fodYi nh xb Z rhutkfr;ks (A,B,C) ds mnkgj.k dk lgh lewg iznf'kZr djrkgSa ?
Adqat f'kyk
tkfr
BfØVhdy fyad
tkfr
CLFkkfud tkfr
(1) phu dh ?kkVh esaesVkfldksb;k
taxy esa 'ksj ekbdksjkbtk(dod ewy)
(2) vkWLVsªfy;k esadaxk:
m".kdfVcfU/k;vathj o{k
ijkxdkjh dhV
(3) jsfxLFkku esdaxk: pwgk
dodewy phu dh ?kkVh esaesVkfldksb;k
(4) taxy esa 'ksj vkLVsªfy;k esa daxk: ijkxdkjh dhV
104. es.My us vius iz;ksxksa ds fy, m/kku eVj dk p;u fd;kD;ksafd :-(1) izkd`frd :i ls Loijkx.k ik;k tkrk gSA(2) vusd foijhr foHksn ds y{k.k ik;s tkrs gSaA(3) m/kku eVj f}o"khZ; ikni gSA(4) (1) ,oa (2) nksuksa
105. buesa ls dkSulh 'osr jä df.kdk,a lfØ; izdfr dh gksrh gS :-(1) ,flMksfQy vkSj U;wVªksfQy(2) cslksfQy vkSj eksukslkbV(3) U;wVªksfQy vkSj eksukslkbV(4) fyEQkslkbV vkSj cslksfQy
106. ;gkWa ,d lkekU; euq"; dk ekud ECG (fo|qr ânys[k)
dk vkjs[k fn;k x;k gSA P-rjax (ih-osc)n'kkZrh gS :-
R
P Q S T
(1) izdqapu dk lekiu(2) nkuksa vkfyan ladqfpr gks jgs gS(3) fuy; ds ladqpu dk vkjaHk gks jgk gS(4) izdqapu dk vkjaHk
107. vuqØe.k ds fy, D;k lgh gS ?
(1) tho dkvkdkj
g~;wel dh ek=k tkfr fofo/krk ¯
(2) fudsrlkekU;r;k
ikniksa esa iks"kdlaj{k.k ¯
tSo Hkkj
(3) ÅtkZ mi;ksx dhn{krk
fudsrfof'k"Vrk
[kk| tky dhtfVyrk
(4) ÅtkZ mi;ksx dhn{krk ¯
fudsrfof'k"Vrk
ikniksa ds iks"kdlaj{k.k
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108. In an experiment, individual homozygous for 'ab'gene, were crossed with wild type. The F1 hybridwas test crossed and progenies produced infollowing ratio :-++/ab ¾® 896ab/ab ¾® 880+a/ab ¾® 108+b/ab ¾® 116Calculate the distance between a and b gene.(1) 22.4 cM (Trans) (2) 11.2 cM (Cis)(3) 11.2 cM (Trans) (4) 22.4 cM (Cis)
109. A mesophyll cell contains how manychloroplast:-
(1) 5 - 10 (2) 20 - 40
(3) 10 - 20 (4) > 100
110. Which statements are incorrect regarding synapse :-
(1) Synaptic membrane always be separated bya gap called synaptic cleft
(2) Synapse is formed by two membrane
(3) Electricle synapse is similar to impulseconduction along single axon
(4) In chemical synapse, neurotransmitter isreleased
111. Match the column I with column II
Column-I Column-II
(i) Cuscuta (a) Hemi parasite
(ii) Lianas (b) Holo parasite
(iii) Viscum (c) Commensal
(1) (i)-(c), (ii)-(a), (iii)-(b)(2) (ii)-(a), (ii)-(b), (iii)-(c)(3) (i)-(c), (ii)-(b), (iii)-(a)
(4) (i)-(b), (ii)-(c), (iii)-(a)112. What is role of restriction endonuclease in
bacterial cell ?(1) To degrade the bacterial chromosome into
small pieces during replication.(2) To produce RNA primer for replication.(3) To degrade invading phage DNA(4) To produce DNA primer during replication
113. Duration of interphase is yeast is approximately:-
(1) 90 seconds (2) 90 minutes
(3) 85.5 minutes (4) 45 minutes
108. ,d iz;ksx esa 'ab' thu ds fy, le;qXeth tho dk ØkWltaxyh izdkj ls fd;k tkrk gSA F1 ladj dk ijh{k.k ØkWlfd;k tkrk gS] rFkk larfr fuEufyf[kr vuqikr esa feyrhgS :-++/ab ¾® 896ab/ab ¾® 880+a/ab ¾® 108+b/ab ¾® 116thu a rFkk b ds chp nqjh dh x.kuk dhft,A(1) 22.4 cM (Vªk¡l) (2) 11.2 cM (fll)(3) 11.2 cM (Vª¡kl) (4) 22.4 cM (fll)
109. izfr i.kZe/;ksrd dksf'kdk gfjryod dh la[;k gks ldrhgS :-
(1) 5 - 10 (2) 20 - 40
(3) 10 - 20 (4) > 100
110. fuEu dFkuksa esa ls dkSu lk dFku lkbusIl gsrq vLkR;@xyrgS :-
(1) lkbusfIVd f>fYYk;ka ges'kk ,d [kkyh LFkku }kjk vyxgksrh gS] ftls lkbusfIVd njkj dgrs gS
(2) lkbusIl dk fuekZ.k nks f>fYYk;ksa }kjk gksrk gSA(3) fo|qrh; lkbusILk esa vkosx lapj.k ,dy raf=dk{k ds
leku gksrk gSA(4) jklk;fud lkbusIl esa U;wjksVªkalehVj eksfpr gksrs gsA
111. dkWye-I dks dkWye-II ls feykb;s&
dkWye-I dkWye-II
(i) vejcsy (a) vkaf'kd ijthoh
(ii) dByrk;sa (b) iw.kZijthoh
(iii) foLde (c) lgHkksth
(1) (i)-(c), (ii)-(a), (iii)-(b)(2) (ii)-(a), (ii)-(b), (iii)-(c)(3) (i)-(c), (ii)-(b), (iii)-(a)
(4) (i)-(b), (ii)-(c), (iii)-(a)112. thok.kq dksf'kdk esa jsfLVªD'ku ,.MksU;wfDy;st dh D;k Hkwfedk
gksrh gS ?(1) thok.kq ds xq.klw= dks jsIyhds'ku ds nkSjku NksVs-NksVs
VqdM+ksa esa rksM+ukA(2) jsIyhds'ku ds fy, RNA primer dk fuekZ.k djukA(3) thok.kqHkksth ds DNA dks vi?kfVr djukA(4) jsIyhds'ku ds nkSjku DNA izkbej dk fuekZ.kA
113. ;hLV dh dksf'kdk esa varjkoLFkk esa yxHkx fdruk le;yxrk gS :-(1) 90 lsadsaM (2) 90 feuV(3) 85.5 feuV (4) 45 feuV
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114. The part of eye in which action potential is firstlygenerated :-
(1) Photoreceptor cell
(2) Ganglionic cell layer
(3) Bipolar cell layer
(4) Horizontal cell layer115. Choose the correct statement :-
(a) Atmospheric input of phosphorus throughrainfall is much smaller than carbon.
(b) The excretory materials of birds on rocks ofsea shore is called Guano and it is a sourceof phosphorus.
(c) Gaseous exchanges of phosphorus betweenorganism and environment are negligible
(d) Atmosphere only contains about 71 percentof total global carbon.
Options :-
(1) a, b and c are correct
(2)only a and b are correct
(3) only b and d are correct
(4) only a and c are correct
116. A female is carrier for both albinism andcolourblindness. She marries a man, who is carrierfor albinism but colourblind. What percentage ofher daughter will be albino and colourblind ?(1) 50% (2) 25% (3) 12.5% (4) 37.5%
117. Which is the correct representation of ribose :-
(1)
O
HHO
OH
HOCH2
(2)
O
OHHO
OH
HOCH2
(3)
NH2
N
N NH
N(4)
O
HN
NH
O
118. Which statement is not true for base ratio of DNA :-
(1) Base ratio is constant for given species(2) Base ratio is variable for different species(3) Base ratio doesn't depend on age of organism(4) Base ratio is different for different tissues of
an organism
114. vk¡[k (us=) dk og Hkkx ftlesa fØ;kRed foHko lclsigys mRiUUk gksrk gS :-(1) izdk'kxzkgh dksf'kdk(2) xqPNdh; dksf'kdk ijr(3) f}/kzqoh; dksf'kdk ijr(4) {kSfrt dksf'kdh; ijr
115. lgh dFku dks pqfu, :-
(a) dkcZu dh rqyuk es a Qk¡LQksjl dk o"kkZ ds }kjk
ok;qe.Myh; fuos'k cgqr de gksrk gSA
(b) leqnz dh pêkuksa ij if{k;ksa ds mRlthZ inkFkZ xq,uks
dgykrs gS rFkk ;g QkWLQksjl dk L=ksr gksrk gSA
(c) QkWLQksjl dk tho rFkk i;kZoj.k ds e/; xSlh;
vknku&iznku ux.; gksrk gSA(d) ok;qe.My esa dqy oSf'od dkcZu dk] 71% dkcZu
gSAfodYi :-
(1) a, b ,oa c lgh gS
(2) dsoy a ,oa b lgh gS
(3) dsoy b ,oa d lgh gS
(4) dsoy a ,oa c lgh gS116. ,d efgyk jatdghurk rFkk o.kkZU/krk nksuksa dh okgd gSA
og ,d ,sls O;fDr ls fookg djrh gS] tks jatdghurk dsfy, okgd ijUrq o.kkZU/k gS mldh fdrus izfr'kr iqf=;k¡jatdghu gksus ds lkFk-lkFk o.kkZU/k Hkh gksxh ?(1) 50% (2) 25% (3) 12.5% (4) 37.5%
117. fuEu esa ls jkbckst dk lgh fp= dkSu lk gS :-
(1)
O
HHO
OH
HOCH2
(2)
O
OHHO
OH
HOCH2
(3)
NH2
N
N NH
N(4)
O
HN
NH
O
118. fn;s x;s esa ls dkSulk dFku DNA ds {kkj vuqikr ds fy;slgh ugha gS :-(1) nh xbZ tkfr ds fy;s {kkj vuqikr leku jgrk gS(2) fofHkUu tkfr;ksa ds fy;s {kkj vuqikr ifjofrZr gkssrk gS(3) {kkj vuqikr tho dh vk;q ij fuHkZj ugha djrk gS(4) {kkj vuqikr ,d tho ds fofHkUu (vyx&vyx)mÙkdksa
ds fy;s vyx&vyx gksrk gSA
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119. Select correct statement w.r.t. biodiversity :-
(1) For many taxonomic groups, speciesinventories are more complete in temperatethan in tropical countries
(2) Species diversity increases from lower tohigher latitudes
(3) Extinction of Steller's sea cow and passengerpigeon occurred due to habitat loss andfragmentation
(4) All the biodiversity hotspots put together covermore than 2 percent of the earth's land area
120. An individual has overall musculine development,however, the feminine development(Gynaecomastia) is also expressed and suchindividual is sterile and caused due to the presenceof an additional copy of x-chromosome, thisgenetic disorder is :-(1) Down's syndrome(2) Turner's syndrome(3) Klinefelter's syndrome(4) Phenylketonuria
DIRECTIONS FOR Q. NO. 121 TO 180
These questions consist of two statements each,printed as Assertion and Reason.Whileanswering these Questions you are required tochoose any one of the following four responses.
A. If both Assertion & Reason are True & theReason is a correct explanation of the Assertion.
B. If both Assertion & Reason are True but Reasonis not a correct explanation of the Assertion.
C. If Assertion is True but the Reason is False.D. If both Assertion & Reason are False.
121. Assertion :- A null vector is a vector whosemagnitude is zero and direction is arbitrary.Reason :- A null vector does not exist.(1) A (2) B (3) C (4) D
122. Assertion :- Buoyancy is a conservative force.Reason :- According to Archimedes principlebuoyancy is equal to the weight of displaced liquid.(1) A (2) B (3) C (4) D
123. Assertion :- Avogadro number is the number ofatoms in one gram mole.Reason :- Avogadro number is a dimensionlessconstant(1) A (2) B (3) C (4) D
119. tSofofo/krk ds lUnHkZ esa lgh dFku dk p;u dhft;s :-
(1) dbZ ofxZdh; lewgksa ds fy, çtkfr;ksa dh [kk stsa
Å".kdfVcU/kh; ns'kks a dh vis{kk 'khrks".k ns'kks a esa
vf/kd iw.kZ gSa
(2) tkfr fofo/krk fuEu ls mPp v{kka'kksa dh vksj c<+rh
gS
(3) LVhyj dh leqæh xk; rFkk ;k=h dcwrj dk foyksiu
vkokl ál rFkk [k.Mu ds dkj.k gqvk
(4) tSofofo/krk ds lHkh gkWV LikWV ,d lkFk feydj i`Foh
dk 2 çfr'kr ls vf/kd LFky {ks= ?ksjrs gSa
120. O;fDr tks lexz :i ls rks iaqiz/kku gksrs gSa] fdUrq eknk y{k.k(xkbuhdksesfLV;k) Hkh O;Dr gks tkrs gSa] rFkk ,sls O;fDrck¡> gksrs gSa] vkSj ;g fodkj x-Øksekslkse dh ,d vfrfjDrizfrfyfi ds dkj.k gksrk gS] ;g vkuqok af'kd fodkjgS :-
(1) Mkmu fl.Mªkse(2) VuZj fl.Mªkse(3) DykbuQsYVj fl.Mªkse(4) fQukbyfdVksU;wfj;k
iz'u la[;k 121 ls 180 ds fy, funs Z'k
izR;sd iz'u es a dFku rFkk dkj.k fn, x;s gSaA iz'uks a
dks gy djrs le; uhps fn, x, pkjks a fodYiks a es a
ls lgh fodYi dks pqfu,A
A. ;fn dFku ,oa dkj.k nksuks a lR; ga S rFkk dkj.k dFkudk lgh Li"Vhdj.k gSA
B. ;fn dFku ,oa dkj.k nksuks a lR; gaS] ysfdu dkj.k] dFkudk lgh Li"Vhdj.k ugha gSA
C. ;fn dFku lR; gS] ysfdu dkj.k vlR; gSAD. dFku o dkj.k nk suks a vlR; gSaA
121. dFku :- ,d 'kwU; lfn'k og lfn'k gS] ftldk ifjek.k'kwU; rFkk fn'kk LosPN gksrh gSAdkj.k :- ,d 'kwU; lfn'k dk dksbZ vfLrRo ugha gksrkA(1) A (2) B (3) C (4) D
122. dFku :- mRIykou cy laj{kh cy gSAdkj.k :- vkdZfeMht ds vuqlkj mRIykou cy foLFkkfiræo ds æO;eku ds cjkcj gksxkA(1) A (2) B (3) C (4) D
123. dFku :- ,oksxsMªks la[;k] ,d xzke&eksy esa v.kqvksa dh la[;kgSA
dkj.k :- ,oksxzsMªks la[;k ,d foekghu fLFkjkad gSA
(1) A (2) B (3) C (4) D
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124. Assertion :- As a simple pendulum oscillates, its
bob has a non-zero acceleration at the mean position
which is directed towards the point of suspension.
Reason :- Speed of an object in SHM, is
maximum at the mean position.
(1) A (2) B (3) C (4) D
125. Assertion :- The position-time graph of a uniform
motion in one dimension of a body can have
negative slope.
Reason :- When the speed of body decresases with
time, the position-time graph of the moving body
has negative slope.
(1) A (2) B (3) C (4) D
126. Assertion :- If a current flows through a wire of non-
uniform cross-section, potential difference per unit
length of wire is same thoughout the length of wire.
Reason :- Current through the wire is same at all
cross-sections.
(1) A (2) B (3) C (4) D
127. Assertion :- The centre of mass of system of n
particles is the weighted average of the position
vector of the n particles making up the system.
Reason :- The position of the centre of mass of
a system is independent of coordinate system.
(1) A (2) B (3) C (4) D
128. Assertion :- Inductive reactance of an inductor
in DC circuit is zero.
Reason :- Angular frequency of DC circuit is zero.
(1) A (2) B (3) C (4) D
129. Assertion :- There is no effect of rotation of earth
on acceleration due to gravity at poles.
Reason :- Rotation of earth is about polar axis.
(1) A (2) B (3) C (4) D
130. Assertion :- Five charges +q each are placed at
five vertices of a regular pentagon. A sixth charge
–Q is placed at the centre of pentagon. Then net
electrostatic force on –Q is zero.
Reason :- Net electrostatic potential at the centre
is zero.
(1) A (2) B (3) C (4) D
124. dFku :- tc yksyd nksyu djrk gS rks NM+ dk ek/; fLFkfr
ij v'kwU; Roj.k gksrk gS tks yVdu fcUnq dh rjg gksrk
gSA
dkj.k :- SHM esa ek/; fLFkfr ij osx vf/kdre gksrk
gSA
(1) A (2) B (3) C (4) D
125. dFku :- ,d foeh; xfr esa ,d leku #i ls xfr djrh
oLrq ds fLFkfr≤ xzkQ dh <ky ½.kkRed gks ldrh
gSA
dkj.k :- tc le; ds lkFk xfreku oLrq dh pky
?kVrh gS] rc fLFkfr≤ xzkQ dh <ky ½.kkRed gksrh
gSA
(1) A (2) B (3) C (4) D
126. dFku :- ;fn vleku vuqizLFk dkV {ks=Qy ds rkj ls gksdj
/kkjk izokfgr gksrh gSa rks rkj dh izfr ,dkad yEckbZ ij
foHkokUrj lEiw.kZ rkj ij ,dleku gksrk gSA
dkj.k :- rkj ls izokfgr /kkjk lHkh vuqizLFk Hkkx ij leku
gksrh gSA
(1) A (2) B (3) C (4) D
127. dFku :- n dks.kksa ds fudk; dk nzO;eku dsanz fudk; dks
fufeZr djus okys n d.kksa ds fLFkfr lfn'kksa dk Hkkfjr ekè;
gksrk gSA
dkj.k :- fudk; ds nzO;eku dsUnz dh fLFkfr funsZ'kkad i¼fr
ij fuHkZj ugha djrhA
(1) A (2) B (3) C (4) D
128. dFku :- DC ifjiFk es pkyd dk izsjdh; izfr?kkr 'kwU;
gksrk gSA
dkj.k :- DC ifjiFk dh dks.kh; vko`fÙk 'kwU; gksrh gSA
(1) A (2) B (3) C (4) D
129. dFku :- /kzqoks ij i`Foh ds ?kw.kZu dk xq#Roh; Roj.k ij
izHkko ugha iM+rkA
dkj.k :- i`Foh dk ?kw.kZu /kzqoh; v{k ds ifjr% gksrk gSA
(1) A (2) B (3) C (4) D
130. dFku :- +q vkos'k ds ikap vkos'kksa dks ,d fu;fer iapHkqt
ds ikap 'kh"kksZ ij j[kk x;k gS] ,d NBk vkos'k –Q dks iapHkqt
ds dsUnz ij j[kk x;k gSa –Q ij dqy fLFkj oS|qr cy 'kwU;
gksrk gSA
dkj.k :- dsUnz ij dqy fLFkj oS|qr foHko 'kwU; gksrk
gSA
(1) A (2) B (3) C (4) D
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131. Assertion :- Power developed in circular motionis always zero.
Reason :- Work done is case of circular motionis zero.
(1) A (2) B (3) C (4) D
132. Assertion :- A small coil carrying current, inequilibrium, its plane is perpendicular to thedirection of the uniform magnetic field.
Reason :- Torque is maximum when plane of coiland direction of the magnetic field are parallel toeach other.
(1) A (2) B (3) C (4) D
133. Assertion :- A blue star is hotter than a red star.
Reason :- According to Stefan's law, a black bodyat a higher temperature radiates more power perunit area.
(1) A (2) B (3) C (4) D
134. Assertion :- A point object moves near theprincipal axis of a fixed spherical mirror along astraight line. Then the image formed by thespherical mirror also moves along a straight line.
Reason :- For an incident ray on a fixed sphericalmirror there is a fixed reflected ray. If a pointobject moves along this incident ray, its image willalways lie on the given reflected ray. Further anincident ray can be drawn from the moving pointobject in its direction of velocity towards themirror.
(1) A (2) B (3) C (4) D
135. Assertion :- In equation P = 2rms
13
au , the term a
represents density of gas.
Reason :- rms
2RTM
u =
(1) A (2) B (3) C (4) D
136. Assertion :- Atoms of greater mass number aremore stable.
Reason :- Their mass defect are more.
(1) A (2) B (3) C (4) D
131. dFku :- o`Ùkh; xfr esa mRiUu 'kfDr ges'kk 'kwU; gksrh gSA
dkj.k :- o`Ùkh; xfr es a fd;k x;k dk;Z 'k wU; gksrk gSA
(1) A (2) B (3) C (4) D
132. dFku :- lkE;koLFkk esa] ,d /kkjkokgd NksVh dq.Myh dkry] ,d leku pqEcdh; {k s= dh fn'kk ds yEcor~gSA
dkj.k :- tc dq.Myh dk ry vkSj pqEcdh; {ks= dh fn'kkijLij lekUrj gksrs gSa] rc cyk?kw.kZ dk eku vf/kdre gksrkgSA
(1) A (2) B (3) C (4) D
133. dFku :- uhyk rkjk] yky rkjs ls T;knk xeZ gSA
dkj.k :- LVhQu ds fu;ekuqlkj d`".k oLrq T;knkrkieku ij ,dkad {ks=Qy esa T;knk 'kfDr mRl£tr djrhgSA
(1) A (2) B (3) C (4) D
134. dFku :- ,d fcUnq fcEc ,d fLFkj xksyh; niZ.k dh eq[;v{k ds ikl ,d ljy js[kk ds vuqfn'k xfr djrk gS rksxksyh; niZ.k }kjk cuk izfrfcEc Hkh ,d ljy js[kk ds vuqfn'kxfr djrk gSA
dkj.k :- ,d fLFkj xksyh; niZ.k ij ,d] fu;r vkifrrfdj.k ds fy, ,d fu;r ijkofrZr fdj.k gksrh gSA ;fn ,dfcUnq fcEc bl vkifrr fdj.k ds vuqfn'k xfr djrk gS]rks bldk izfrfcEc nh xbZ ijkofrZr fdj.k ij ges'kk fLFkrgksrk gSA vkSj vkxs ge dg ldrs gS fd niZ.k dh vksj xfrdjrs gq;s fcUnq fcEc ds osx dh fn'kk esa vkifrr fdj.kdks niZ.k dh vksj vuqjsf[kr fd;k tk ldrk gSA
(1) A (2) B (3) C (4) D
135. dFku :- P = 2rms
13
au esa a xSl ds ?kuRo dks crkrk
gSA
dkj.k :- rms
2RTM
u =
(1) A (2) B (3) C (4) D
136. dFku :- vf/kd æO;eku okys ijek.kq T;knk LFkk;h gksrsgSA
dkj.k :- muesa æO;eku {kfr vf/kd gksrh gSA
(1) A (2) B (3) C (4) D
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137. Assertion :- The specific heat of a given mass of
a gas in an adiabatic process is zero and in an
isothermal process is infinity.
Reason :- Specific heat of gas is directly
proportional to chagne in heat of a system and
directly proportional to change in temperature.
(1) A (2) B (3) C (4) D
138. Assertion :- A nucleus contain no electron, but
can eject them.
Reason :- g-rays are emitted by the excited nuclei.
(1) A (2) B (3) C (4) D
139. Assertion :- A bubble comes from the bottom of
a lake to the top its radius increases.
Reason :- Its radius increases.
(1) A (2) B (3) C (4) D
140. Assertion :- Dopping of silicon with Indium leads
to n-type semiconductor.
Reason :- Indium is a pentavalent atom.
(1) A (2) B (3) C (4) D
141. Assertion :- Only temperature can change the
vapour pressure of a pure liquid.
Reason :- Equilibrium constant does not change
unless temperature is changed.
(1) A (2) B (3) C (4) D
142. Assertion :- CCl4 is a non-polar molecule.
Reason :- CCl4 has polar bonds.
(1) A (2) B (3) C (4) D
143. Assertion :- Weak acid + salt of this acid with
a strong base will behave like a buffer.
Reason :- Weak base + Salt of this base with a
strong acid behave like a buffer.
(1) A (2) B (3) C (4) D
144. Assertion :- HOF bond angle is higher than HOCl
in HOX.
Reason :- Chlorine is more electronegative than
oxygen.
(1) A (2) B (3) C (4) D
145. Assertion :- Salt bridge maintains electrical
neutrality in two half cells.
Reason :- Salt bridge transfer electrons from one
solutions to other.
(1) A (2) B (3) C (4) D
137. dFku :- :¼ks"e izØe esa fof'k"V Å"ek 0 rFkk lerkih;izØe esa ¥ gksrh gSA
dkj.k :- xSl dh fof'k"V Å"ek ÅtkZ ds ifjorZu dslekuqikrh rFkk rkieku ds ifjorZu ds lekuqikrh gksrhgSA
(1) A (2) B (3) C (4) D
138. dFku :- ukfHkd esa bysDVªkWu ugha gksrk ijUrq mUgsa mRl£trdj ldrk gSAdkj.k :- g-fdj.ksa mÙksftr ukfHkd ls mRl£tr gksrh gSA(1) A (2) B (3) C (4) D
139. dFku :- cqycqyk unh esa ry ls Åij dh vksj vkrkgSAdkj.k :- bldh f=T;k c<+sxhA(1) A (2) B (3) C (4) D
140. dFku :- flfydkWu dks bf.M;e }kjk Mksfiax djus lsn-izdkj dk v¼Zpkyd curk gSAdkj.k :- bf.M;e iapla;ksth ijek.kq gSA(1) A (2) B (3) C (4) D
141. dFku :- 'kq¼ æo dk ok"inkc dsoy rki }kjk ifjofrZrfd;k tk ldrk gSAdkj.k :- tc rd rki ifjofrZr ugha gksrk rc rd lkE;koLFkkfLFkjkad ifjofrZr ugha gksrkA(1) A (2) B (3) C (4) D
142. dFku :- CCl4 ,d v/kzqoh; v.kq gSAdkj.k :- CCl4 ds ca/k /kzqoh; gSA(1) A (2) B (3) C (4) D
143. dFku :- nqcZy vEy + blh vEy dk izcy {kkj ds lkFkyo.k ,d cQj dh rjg O;ogkj djsxkAdkj.k :- nqcZy {kkj + blh {kkj dk izcy vEy ds lkFkyo.k ,d cQj dh rjg O;ogkj djrk gSA(1) A (2) B (3) C (4) D
144. dFku :- HOX eas HOF ca/k dks.k HOCl ls vf/kdgSAdkj.k :- Dyksjhu dh fo|qr½.krk vkWDlhtu ls vf/kdgSA(1) A (2) B (3) C (4) D
145. dFku :- nks v/kZlsyksa dh fo|qr mnklhurk Hkh yo.k lsrqcuk, j[krk gSAdkj.k :- yo.k lsrq bysDVªksuksa dks ,d foy;u ls nwljs esaLFkkukarfjr djrk gSA(1) A (2) B (3) C (4) D
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146. Assertion :- Second EA for halogens is almost
zero.
Reason :- Fluorine has maximum value of
electron affinity.
(1) A (2) B (3) C (4) D
147. Assertion :- Molecularity does not influence the
rate of reaction.
Reason :- The overall kinetics of a reaction is
governed by the slowest step in the reaction
scheme.
(1) A (2) B (3) C (4) D
148. Assertion :- In the extraction of Ag, complex
Na[Ag(CN)2] is reacted with Zn.
Reason :- Zn is d–block transition metal.
(1) A (2) B (3) C (4) D
149. Assertion :- SO2 has higher critical temperature
than CO2.
Reason :- SO2 has more intermolecular attraction
than CO2.
(1) A (2) B (3) C (4) D
150. Assertion :- For isomeric alkane the boiling point
decrease with increase in branching.
Reason :- With increase in branching, the surface
area decrease which decrease the magnitude of
Vandar Walls attraction.
(1) A (2) B (3) C (4) D
151. Assertion :- Heat of neutralisation of HF(aq.)
(weak acid) with NaOH(aq.) is less than
13.7 KCal, in an exothermic reaction.
Reason :- For neutralisation of HF same heat is
lost in the ionisation of a weak acid.
(1) A (2) B (3) C (4) D
152. Assertion :- The nitration of phenol takes place
at faster rate than beznene.
Reason :- Due to +M effect, –OH group at
benzene is ortho para director.
(1) A (2) B (3) C (4) D
153. Assertion :- KMnO4 is purple in colour due to
charge transfer.
Reason :- There is no electron present in d–orbital
of manganese in MnO4–.
(1) A (2) B (3) C (4) D
146. dFku :- gSyk stu dh f}rh; EA yxHkx 'kw U; gksrhgSAdkj.k :- ¶yksjhu dh bysDVªkWu ca/kqrk dk eku lokZf/kd gksrkgSA(1) A (2) B (3) C (4) D
147. dFku :- vfHkfØ;k dh nj dks v.kq la[;rk izHkkfor ugha
djrh gSA
dkj.k :- vfHkfØ;k dh nj dk fu;a=.k fØ;kfof/k ds lcls
/khesa in }kjk fu/kkZfjr gksrk gSA
(1) A (2) B (3) C (4) D
148. dFku :- Ag ds fu"d"kZ.k esa ladqy Na[Ag(CN)2] dhfØ;k Zn ls djkbZ tkrh gSAdkj.k :- Zn ,d d–CykWd laØe.k /kkrq gSA(1) A (2) B (3) C (4) D
149. dFku :- SO2 dk ØkfUre rki dk eku CO2 ls vf/kd gksrkgSAdkj.k :- SO2 esa varjv.kqd vkd"kZ.k dk eku CO2 lsvfèkd gksrk gSA(1) A (2) B (3) C (4) D
150. dFku :- 'kk[kk c<+us ij lek;oh ,Ydsu dk DoFkukad ?kVrkgSAdkj.k :- 'kk[kk ds c<+us ij ,Ydsu esa i`"Bh; {ks=Qy?kVrk gS ftles ok.Mj oky vkdZ"k.k dk ifjek.k ?kVrkgSA(1) A (2) B (3) C (4) D
151. dFku :- HF(aq.) (nwc Zy vEy) dk mnklhuhdj.kNaOH(aq.) ls djokus ij fudyus okyh m"ek dk eku13.7 KCal ls de gksrk gS (m"ek{ksih vfHkfØ;k esa)dkj.k :- mijksDr mnklhuhdj.k esa Å"ek dh dqN ek=k nwcZyvEy ds vk;uhdj.k esa [kpZ gks tkrh gSA(1) A (2) B (3) C (4) D
152. dFku :- QhukWy dh ukbVªhdj.k vfHkfØ;k csUthu ls rstgksrh gSAdkj.k :- +M izHkko ds dkj.k –OH lewg vkFkksZ isjk funsZ'kdgksrk gSA(1) A (2) B (3) C (4) D
153. dFku :- vkos'k LFkkukarj.k ds dkj.k KMnO4 tkequh jaxdk gksrk gSAdkj.k :- MnO4
– esa Mn ds d–d{kd esa dksbZ bysDVªkWumifLFkr ugha gSA(1) A (2) B (3) C (4) D
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154. Assertion :- SN1 reaction proceed with
racemisation in configuration of product.
Reason :- SN1 reaction involves back side attack
of nucleophile at reaction center.
(1) A (2) B (3) C (4) D
155. Assertion :- SnO is more reactive towards acid
than SnO2.
Reason :- Both SnO and SnO2 are amphoteric
oxides.
(1) A (2) B (3) C (4) D
156. Assertion :- Addition of HCl in presence of
peroxide across double bond of propene takes
place according to anti markovni kov's rule.
Reason :- Peroxide effect observe in addition of
HCl.
(1) A (2) B (3) C (4) D
157. Assertion :- Oxidation state of Fe in Fe(CO)5 is zero.
Reason :- Synergic bonding takes place in this
metal carbonyl .
(1) A (2) B (3) C (4) D
158. Assertion :- Tert–butyl methyl ether can be
prepared by using tert–butyl bromide and sodium
melthoxide, in good yield.
Reason :- Willianson ether synthesis involves
SN1 mechanism.
(1) A (2) B (3) C (4) D
159. Assertion :- Complex ion [Co(NH3)6]+2 is readily
oxidized to [Co(NH3)6]+3.
Reason :- Unpaired electron in complex ion
[Co(NH3)6]+2 is present in 4p orbital.
(1) A (2) B (3) C (4) D
160. Assertion :- Cannizzarro reaction is characterstic
of aldehyde does not have a-hydrogen.
Reason :- Cannizzarro reaction is a redox
reaction.
(1) A (2) B (3) C (4) D
161. Assertion :- In Angiosperms, the conduction of
water is more efficient because their xylem has
vessels.
Reason :- End wall of vessels is perforated and
have a wide lumen.
(1) A (2) B (3) C (4) D
154. dFku :- SN1 vfHkfØ;k es jslhehd mRikn curkgSAdkj.k :- SN1 vfHkfØ;k es ukfHkd Lusgh foijhr fn'kk lsvkØe.k djrk gSA(1) A (2) B (3) C (4) D
155. dFku :- SnO2 dh rqyuk esa SnO vEy ds lkFk vfHkfØ;kds fy;s T;knk fØ;k'khy gSAdkj.k :- SnO rFkk SnO2 nksuksa gh mHk;/kehZ vkWDlkbMgSA(1) A (2) B (3) C (4) D
156. dFku :- izk sihu ij HCl dh ;ksxkRed vfHkfØ;k esaijvkDlkbM dh mifLFkr esa ,UVh ekjdksouh dkQ fu;edk vuqikyu gksrk gSAdkj.k :- HCl ds ;ksxkRed vfHkfØ;k esa ijvkWDlkbM dkizHkko iMrk gSA(1) A (2) B (3) C (4) D
157. dFku :- Fe(CO)5 esa Fe dh vkDlhdj.k voLFkk 'kqU;gSAdkj.k :- bl /kkrq dkckZsfuy esa fluftZd ca/ku mifLFkr gSA(1) A (2) B (3) C (4) D
158. dFku :- Tert–butyl methyl ether dks vPNh ek=k estert–butyl bromide vkSj lksfM;e esFkkDlkbM ds iz;ksxls cuk ldrs gSAdkj.k :- fofy;ulu bZFkj la'ys"k.k esa SN1 vfHkfØ;k gksrhgSA(1) A (2) B (3) C (4) D
159. dFku :- [Co(NH3)6]+2 ladqy [Co(NH3)6]+3 es avkWDlhÏr gks tkrk gSAdkj.k :- [Co(NH3)6]
+2 ladqy esa v;qfXer bysDVªku 4p
d{kd esa mifLFkr gSA(1) A (2) B (3) C (4) D
160. dFku :- ,fYMgkbM ;kSfxd ftuesa a-H ugh gS os dSfutkjksvfHkfØ;k n'kkZrs gSAdkj.k :- dSfutkjks vfHkfØ;k ,d fjMkWDl vfHkfØ;kgSA(1) A (2) B (3) C (4) D
161. dFku :- iq"ih ikniksa esa ty dk laogu T;knkizHkkoh gSa D;ksafd buds tkbye esa okfgdk,sa ik;htkrh gSAdkj.k :- okfgdkvksa esa vUr% fHkfÙk fNfær vkSj cM+hvodkf'kdk ik;h tkrh gSaA(1) A (2) B (3) C (4) D
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162. Assertion :- The cranial capacity of homo habilis
is 900 cc and they probably did not eat meat.
Reason :- They probably from cave painting.
(1) A (2) B (3) C (4) D
163. Assertion :- The cell wall of diatoms is
Industructible
Reason :- The cell wall of diatoms is embedded
with CaCO3
(1) A (2) B (3) C (4) D
164. Assertion :- Emphysema is a chronic disorder in
which alveolar walls are damaged due to which
respiratory surface is decreased.
Reason :- 20-25 percent of CO2 is transported by
RBCs.
(1) A (2) B (3) C (4) D
165. Assertion :- Fibroblast is Fibre producing cell.
Which is part of connective tissue proper.
Reason :- It is undifferentiated cell which convert
into osteoblast and chondrioblast cells,
(1) A (2) B (3) C (4) D
166. Assertion :- Biosphere is a closed system for energy
Reason :- Biosphere recieves a lot of material
from outside
(1) A (2) B (3) C (4) D
167. Assertion :- Amino acids are called a-amino
acids.
Reason :- Amino acids are organic compounds
containing an amino group and an acidic group
as substituents on the same carbon i.e., a carbon.
(1) A (2) B (3) C (4) D
168. Assertion :- Scavenging improves the environment
Reason :- A scavenger dispose of dead organic
matter.
(1) A (2) B (3) C (4) D
169. Assertion :- During competitive inhibition, the
inhibitior binds with the active site of substrate
inplace of enzyme.
Reason :- Competitive inhibition can be
overcome by decreasing substrate concentration.
(1) A (2) B (3) C (4) D
162. dFku :- gkseks gSfcyl dh fnekxh {kerk 900 cc gksrh Fkh
,oa os laHkor% ek¡l ugha [kkrs FksA
dkj.k :- os laHkor xqQkfp= cukrs FksA
(1) A (2) B (3) C (4) D
163. dFku :- Mk;Veks a dh dksf'kdk fHkfÙk u"V ugh gksrh
gSA
dkj.k :- Mk;Veksa dh dksf'kdk fHkfÙk esa CaCO3 ik;k tkrk
gSA
(1) A (2) B (3) C (4) D
164. dFku :- okrLQhfr ,d fpjdkfyd jksx gS ftles dwfidk
fHkfÙk {kfrxzLr gks tkrh gS ftlls xSl fofue; lrg ?kV
tkrh gSA
dkj.k :- 20-25 izfr'kr CO2 dk ifjogu yky jDr
df.kdkvksa }kjk gksrk gSA
(1) A (2) B (3) C (4) D
165. dFku :- QkbczksCykLV okLrfod la;ksth Ård dk Hkkx gSA
ftuds }kjk rUrqvksa dk fuekZ.k fd;k tkrk gSA
dkj.k :- ;g vfoHksndkjh dksf'kdk gksrh gS tks osteoblast
vkSj chandrioblast dksf'kdk esa ifjo£rr gks ldrh gSA
(1) A (2) B (3) C (4) D
166. dFku :- i`Foh ÅtkZ ds fy, ,d can ra= gS A
dkj.k :- i`Foh ckgj ls cgqr lkjs rRo xzg.k djrh
gS A
(1) A (2) B (3) C (4) D
167. dFku :- vehuksa vEy dks a-,YQk vehuksa vEy dgrs
gSaA
dkj.k :- vehuksa vEy dkcZfud ;kSfxd gksrs gSaA ftuesa blds
,d gh dkcZu (a dkcZu) ij ,d vehuksa lewg o ,d
vEyh; lewg izfrLFkkfir gksrs gSaA
(1) A (2) B (3) C (4) D
168. dFku :- viektZd okrkoj.k ds fy, ykHkdkjh gSa A
dkj.k :- viektZd e`r dkcZfud inkFkks± dks ok;qe.My ls
gVkrs gSaA
(1) A (2) B (3) C (4) D
169. dFku :- izfr;ksxh laneu ds nkSjku] laned fØ;kèkkj
ds lfØ; LFky ij ,atkbe dh txg tqM+ tkrk
gSA
dkj.k :- izfr;ksxh laneu dks fØ;k/kkj dh lkUnzrk dks
c<+kdj [kRe fd;k tk ldrk gSA
(1) A (2) B (3) C (4) D
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170. Assertion :- A typical angiospermic anther is
bilobed.
Reason :- The bilobed nature of an anther is very
distinct in the transverse section of an anther.
(1) A (2) B (3) C (4) D
171. Assertion :- Manganese toxicity leads to
deficiency of iron and magnesium.
Reason :- Manganese competes with Fe and Mg
for uptake.
(1) A (2) B (3) C (4) D
172. Assertion :- Hilium represents the junction
between ovule and funicle.
Reason :- The body of ovule fuses with funicle
in the region called hilum.
(1) A (2) B (3) C (4) D
173. Assertion :- The antidiuretic hormone increases
the water permeability of collecting duct.
Reason :- In absence of ADH, water re-absorption
is considerably reduced.
(1) A (2) B (3) C (4) D
174. Assertion :- Ovarian follicles secrete gonadotropin
hormone.
Reason :- Estrogen hormone is responsible for
negative feed back mechanism at mid menstrual
phase which lead to ovulation.
(1) A (2) B (3) C (4) D
175. Assertion :- Muscle contraction force increases
with rise in strength of stimulus.
Reason :- This is due to increased contraction of
individual muscle fibres with increase in stimulus
strength.
(1) A (2) B (3) C (4) D
176. Assertion :- Cyclosporin A is used as an
immunosuppressive agent in organ transplant
patients.
Reason :- Cyclosporin A is produce by Monascus
purpureus.
(1) A (2) B (3) C (4) D
177. Assertion :- Myasthania Gravis is a neuromuscular
disorder of autoimmune origin.
Reason :- The acetylcholine is synthesized in the
motor nerve terminal.
(1) A (2) B (3) C (4) D
170. dFku :- ,d izk:fid vko`Ùkchth ijkxdks"k f}ikfyr gksrkgSAdkj.k :- ,d ijkxdks"k dh f}ikfyr izd`fr] ijkxdks"k dhvuqizLFk dkV esa cgqr gh lqO;dr gksrh gSA(1) A (2) B (3) C (4) D
171. dFku :- eSaxuht dh vkfo"krk ls ykSg ,oa eSXuhf'k;e dhvi;kZIrrk gks tkrh gSAdkj.k :- eSaxuht] yksg ,oa eSXuh'kh;e ds lkFk vUrZxzg.kds fy, izfr;ksfxrk djrk gSA(1) A (2) B (3) C (4) D
172. dFku :- ukfHkdk] chtk.M ,oa chtkaMo`Ur ds laf/k fcUnqdk izfrfuf/kRo djrh gSAdkj.k :- chtk.Mdk; chtk.Mo`Ur ds lkFk ukfHkdk uked{ks= esa laxfyr gksrh gSA(1) A (2) B (3) C (4) D
173. dFku :- ,UVhMkb;wjsfVd gkWeksZu collecting duct (DCT)
dh ty ds fy, ikjxE;rk c<+krk gSAdkj.k :- ADH, dh vuqifLFkfr esa ty dk iqujko'kks"k.kvR;f/kd ?kV tkrk gSA(1) A (2) B (3) C (4) D
174. dFku :- vaMk'k;h iqfVdk;s xksusMksVªksihu gkeksZu dk L=kodjrh gSAdkj.k :- ekfld pØ ds e/; esa bLVªkstu gkeksZu ds dkj.kusxsfVo&fQMcSd (positive feedback) gksrk gS] tksvaMksRlxZ dk dkjd gSA(1) A (2) B (3) C (4) D
175. dFku :- is'kh; ladqpu dh 'kfDr esa o`f¼] mÙkstuk esa o`f¼
ds lkFk gksrh gSA
dkj.k :- ;g mÙkstuk dh 'kfDr esa o`f¼ ds lkFk ,d fo'ks"k
is'kh rUrq esa ladqpu esa o`f¼ ds dkj.k gksrh gSA
(1) A (2) B (3) C (4) D
176. dFku :- lkbDyksLiksfju A dk iz;ksx vax izfrjksi.k es izfrj{kk
fujks/kd dkjd ds :i es jksfx;ks es fd;k tkrk gSA
dkj.k :- lkbDyksLiksfju A] eksukWLdl ijI;wjhvl ls izkIr
gksrk gSA
(1) A (2) B (3) C (4) D
177. dFku :- ek;LFksfu;k xzsfol Lo&izfrjf{kr ewy dk ,draf=dk is'kh dk fodkj gSAdkj.k :- ,lhVkbydksyhu dk la'ys"k.k pkyd raf=dk dsvafre fljs ls gksrk gSA(1) A (2) B (3) C (4) D
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178. Assertion :- In male grasshopper, some of the
sperms bear x-chromosome whereas some do not.
Reason :- Grasshopper is an example of xx-xo
type of sex determination.
(1) A (2) B (3) C (4) D
179. Assertion :- Through tissue culture exclusively
disease resistant plant can be obtained.
Reason :- Plants develop from meristem are
disease free and resistant.
(1) A (2) B (3) C (4) D
180. Assertion :- The proinsulin contains an extra
stretch called as C-peptide.
Reason :- Insulin consists of two short
polypeptide chains A and B that are linked
together by phosphodiester bonds.
(1) A (2) B (3) C (4) D
181. Who among the following was the first lady Prime
Minister in the World?
(1) Indira Gandhi
(2) Margaret Thatcher
(3) Sirimavo Bandaranaike
(4) Golda Meir
182. The total number of Puranas in Hindu Religion are :
(1) 10 (2) 12 (3) 16 (4) 18
183. What was the name of the town established by
Akbar ?
(1) Agra (2) Delhi
(3) Fatehpur Sikari (4) Nizamabad
184. The device used for locating submerged objects
under sea is :-
(1) SONAR (2) RADAR
(3) LASER (4) MASER
185. India's oldest iron and steel plant is :-
(1) TISCO at Jamshedpur
(2) TISCO at Burnpur
(3) Durgapur Iron and steel plant
(4) Rourkela Iron and steel plant
178. dFku :- uj fVM~Ms esa dqN 'kqØk.kqvksa esa X-xq.klw= gksrk
gS tcfd dqN es ugh gksrk gSA
dkj.k :- fVM~Mk xx-xo izdkj ds fyax fu/kkZj.k dk mnkgj.k
gSA
(1) A (2) B (3) C (4) D
179. dFku :- mÙkd lao/kZu rduhd }kjk iw.kZ :i ls jksx izfrjksèkh
ikni izkIr fd;s tk ldrs gSA
dkj.k :- foHkT;ksrd ls fodflr ikni jksx eqDr ,oa jksx
izfrjks/kh gksrs gSA
(1) A (2) B (3) C (4) D
180. dFku :- izksbalqfyu es ,d vfrfjDr QSyko gksrk gS ftls
C-isIVkbM dgrs gSA
dkj.k :- balqyhu nks NksVh ikWyhisIVkbM Jqa[kykvks A o B
dk cuk gksrk gS] tks vkil es QkWLQksMkbLVj ca/kks }kjk tqM+h
gksrh gSA
(1) A (2) B (3) C (4) D
181. fo'o dh izFke efgyk iz/kkuea=h dkSu Fkh\
(1) bafnjk xka/kh
(2) ekxZjsV FkSpj
(3) fljhekoks HkaMkjuk;ds
(4) xksYMk ehj
182. fgUnw /keZ esa dqy iqjk.kksa dh la[;k fdruh gS :
(1) 10 (2) 12 (3) 16 (4) 18
183. vdcj }kjk clk;s x;s 'kgj dk D;k uke Fkk\
(1) vkxjk (2) fnYyh
(3) Qrsgiqj lhdjh (4) futkekckn
184. leqnz ds vUnj tyeXu oLrqvksa dk irk yxkus ds fy;s mi;ksx
dh tkus okyh ;qfDr gSa :-
(1) lksukj (2) jkMkj
(3) ystj (4) eslj
185. Hkkjr dk lcls iqjkuk ykSg ,oa bLikr la;a= dkSulk gS :-
(1) fVLdks] te'ksniqj
(2) fVLdks] cuZiqj
(3) nqxkZiqj ykSg ,oa bLikr la;a=
(4) jkmjdsyk ykSg ,oa bLikr la;a=
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186. When was the Reserve Bank of India taken over
by the Government ?
(1) 1945 (2) 1949
(3) 1952 (4) 1956
187. Which of the following appointments is not made
by the President of India ?
(1) Chief of the Army
(2) Chief of the Air force
(3) Chief Justice of India
(4) Speaker of the Lok Sabha
188. Which country has won the World Cup Cricket
for the maximum times ?
(1) India (2) Australia
(3) West Indies (4) Pakistan
189. Which of these international tennis events is
played on a grass court ?
(1) Australian Open
(2) French Open
(3) US Open
(4) Wimbeldon
190. The British Prime Minister at the time of Indian
Independence was :-
(1) Clement Attlee
(2) Anthony Eden
(3) Winston Churchill
(4) Harold Macmillan
191. Which of the following match is not correct?
(1) Indian Institute of Horticulture Research
: Hyderabad
(2) Central Drug Research Institute : Lucknow
(3) Central Potato Research Institute : Shimla
(4) Central Rice Research Institute : Cuttack
192. Hard soaps are :-
(1) Calcium salts of higher fatty acids
(2) Magnesium salts of higher fatty acids
(3) Potassium salts of higher fatty acids
(4) Sodium salts of higher fatty acids
193. Areawise, which one of the following is the largest
Lok Sabha Constituency :-
(1) Kutch (2) Kangra
(3) Ladakh (4) Patna Sahib
186. ljdkj }kjk Hkkjrh; fjtoZ cSad dk vf/kxzg.k dc fd;k
x;k Fkk\
(1) 1945 (2) 1949
(3) 1952 (4) 1956
187. Hkkjr ds jk"Vªifr }kjk fuEu esa ls fdldh fu;qfDr ugha dh
tkrh gS\(1) Fky lsuk izeq[k
(2) ok;q lsuk izeq[k
(3) Hkkjr ds iz/kku U;k;k/kh'k
(4) yksd lHkk v/;{k
188. fo'o di fØdsV dks lcls vf/kd ckj thrus okyk ns'k
dkSulk gS ?
(1) Hkkjr (2) vkWLVªsfy;k
(3) osLV baMht (4) ikfdLrku
189. fuEu esa ls dkSulh varjkZ"Vªh; Vsful izfr;ksfxrk ?kkl dh
lrg ij [ksyh tkrh gS ?
(1) vkLVªsfy;u vksiu
(2) Ýsap vksiu(3) ;w-,l-vksiu
(4) foEcyMu
190. Hkkjr dh vktknh ds le; fczVsu dk iz/kkuea=h dkSu
Fkk :-
(1) DyhesUV ,Vyh
(2) ,aFkksuh bMu(3) foaLVu pfpZy
(4) gsjkYM esdfeyku
191. fuEu esa ls dkSulk feyku lgh ugha gS ?
(1) Hkkjrh; ckxokuh vuqla/kku laLFkku : gSnjkckn
(2) dsUæh; vkS"kf/k vuqla/kku laLFkku : y[kuÅ
(3) dsUæh; vkyw vuqla/kku laLFkku : f'keyk
(4) dsUæh; pkoy vuqla/kku laLFkku : dVd
192. dBksj lkcqu gksrs gS :-
(1) mPp olh; vEyksa ds dsfY'k;e yo.k
(2) mPp olh; vEyksa ds eSXuhf'k;e yo.k
(3) mPp olh; vEyksa ds ikSVsf'k;e yo.k(4) mPp olh; vEyksa ds lksfM;e yo.k
193. {ks=Qy dh n`f"V ls] fuEu esa ls dkSulk yksdlHkk {ks= lcls
cM+k gS :-
(1) dPN (2) dkaxM+k
(3) yn~nk[k (4) iVuk lkfgc
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ALL INDIA OPEN TEST/Pre-Medical /AIIMS/21-02-2016
194. Who among the following scientists proved that thestars with mass less than 1.44 times the mass ofthe Sun, end up as White Dwarfs when they die?
(1) Edwin Hubble
(2) S. Chandrashekhar
(3) Stephen Hawking
(4) Steven Weinberg
195. Which date is recently declared as InternationalYoga Day by United Nations ?
(1) June 10 (2) June 21
(3) July 21 (4) July 28
196. 'Jyoti Punj' is the name of the book written by-
(1) Jaswant Singh (2) Sushma Swaraj
(3) Narendra Modi (4) Sushil Modi
197. Which state in India is the least populated?
(1) Nagaland (2) Goa
(3) Sikkim (4) Himachal Pradesh
198. The Attorney General of India is the legaladvisor to :-
(1) The President of India
(2) The Government of India
(3) Prime Minister on foreign policies
(4) The Government on finance policies
199. Which Indian Scientist has had the distinction ofreceiving not only the Nobel Prize, but also BharatRatna ?
(1) Dr. Homi Bhabha
(2) Dr. J. C. Bose
(3) Dr. C.V. Raman
(4) Dr. Vikram Sarabhai
200. Who was the founder of 'Parsi Religion' ?
(1) Moses (2) Darius
(3) Zoroaster (4) Cyrus
194. fuEufyf[kr esa ls dkSuls oSKkfud us ;g fl¼ fd;k Fkk fdlw;Z ds nzO;eku ds 1.44 xqus ls de nzO;eku okys rkjs viuhe`R;q ds le; ,d OgkbV M~okQZ ds :i eas lekIr gks tkrs gS?(1) ,Mfou gCcy(2) ,l- pUnz'ks[kj(3) LVhQu gkWfdax(4) LVhou ohucxZ
195. la;qDr jk"Vª la?k }kjk gky gh esa fdl fnu dks varjkZ"Vªh;;ksx fnol ?kksf"kr fd;k x;k gS ?
(1) 10 twu (2) 21 twu(3) 21 tqykbZ (4) 28 tqykbZ
196. 'T;ksfr iqat' uked iqLrd ds ys[kd gS-(1) tloar flag (2) lq"kek Lojkt(3) ujsUnz eksnh (4) lq'khy eksnh
197. Hkkjr esa fdl jkT; dh tula[;k lcls de gS?(1) ukxkyS.M (2) xksok(3) flfDde (4) fgekpy izns'k
198. Hkkjr dk vVkWuhZ tujy fdldk dkuwuh lykgdkjgksrk gS :-
(1) Hkkjr ds jk"Vªifr dk(2) Hkkjr ljdkj dk(3) fons'kh uhfr;ksa ij iz/kkuea=h dk(4) foÙkh; uhfr;ksa ij ljdkj dk
199. dkSuls Hkkjrh; oSKkfud us vf}rh; :i ls ukscsy iqjLdkjrFkk Hkkjr jRu izkIr djus dk lkSHkkX; izkIr fd;kgS ?
(1) MkW- gkseh HkkHkk(2) MkW- ts-lh- cksl(3) MkW- lh-oh- jeu(4) MkW- foØe lkjkHkkbZ
200. 'ikjlh /keZ' dk laLFkkid dkSu Fkk ?
(1) eksT+kst (2) Msfj;l(3) tjFkq"Vª (4) lk;jl
Your moral dutyis to prove that ALLEN is ALLEN
Your Target is to secure Good Rank in Pre-Medical 2015
ALL INDIA OPEN TEST/Pre-Medical /AIIMS/21-02-2016
37/370999DM310315021
SPACE FOR ROUGH WORK / jQ dk;Z ds fy;s txg