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BAB IV PENGUMPULAN DAN PENGOLAHAN DATA
BAB IV PENGUMPULAN DAN PENGOLAHAN DATA
BAB IVPENGUMPULAN DAN PENGOLAHAN DATA4.1 Pengumpulan Data4.1.1 Pengukurn Dasara. Benda kerja 1 (BK-1) : KUNINGAN
1. Mengukur dengan Jangka SorongTabel 4.1 Mengukur Kuningan dengan Jangka Sorong
BagianPanjang(P)Lebar (L)Tinggi/tebal(T)
145 mm25 mm17,6 mm
245 mm25 mm17,6 mm
345 mm25 mm17,6 mm
445 mm25 mm17,6 mm
545 mm25 mm17,6 mm
225 mm125 mm88 mm
45 mm25 mm17,6 mm
10125 mm23125 mm21548,8 mm2
50625 mm215625 mm27744 mm2
Volume BK-1 (V) =
= 45 mm x 25 mm x 17,6 mm
= 19800 mm3
2. Mengukur dengan mikrometer sekrupTabel 4.2 Mengukur Kuningan dengan Mikrometer Sekrup
BagianTinggi/tebal (T)
(mm)
117,58 mm
217,58 mm
317,58 mm
417,58 mm
517,58 mm
3. Menimbang dengan neraca teknis
Massa BK-1 (m1) = 163 gram
b. Benda kerja 2 (BK-2) : TEMBAGA
1. Mengukur dengan Jangka SorongTabel 4.3 Mengukur Tembaga dengan Jangka Sorong
BagianPanjang(P)Lebar (L)Tinggi/tebal(T)
145 mm25,1 mm17,6 mm
245 mm25,1 mm17,6 mm
345 mm25,1 mm17,6 mm
445 mm25,1 mm17,6 mm
545 mm25,1 mm17,6 mm
225 mm125,5 mm88 mm
45 mm25,1 mm17,6 mm
10125 mm23150,05 mm21548,8 mm2
50625 mm215720,25mm27744 mm2
Volume BK-2 (V) =
= 45 mm x 25,1 mm x 17,6 mm
= 19879,2 mm3
2. Mengukur dengan mikrometer sekrupTabel 4.4 Mengukur Tembaga dengan Mikrometer Sekrup
BagianTinggi/tebal (T)
(mm)
117,54
217,54
317,54
417,54
517,54
3. Menimbang dengan neraca teknis
Massa BK-2 (m2) = 176,2 gram
c. Benda kerja 3 (BK-3) : BESI
1. Mengukur dengan Jangka SorongTabel 4.5 Mengukur Tembaga dengan Jangka Sorong
BagianPanjang(P)Lebar (L)Tinggi/tebal(T)
145,1 mm25,1 mm17,6 mm
245,1 mm25,1 mm17,6 mm
345,1 mm25,1 mm17,6 mm
445,1 mm25,1 mm17,6 mm
545,1 mm25,1 mm17,6 mm
225 mm125,5 mm88 mm
45,1 mm25,1 mm17,6 mm
10170,05 mm23150,05 mm21548,8 mm2
50850,25 mm215720,25mm27744 mm2
Volume BK-2 (V) =
= 45,1 mm x 25,1 mm x 17,6 mm
= 19923,376 mm3
2. Mengukur dengan mikrometer sekrupTabel 4.6 Mengukur Tembaga dengan Mikrometer Sekrup
BagianTinggi/tebal (T)
(mm)
117,57
217,57
317,57
417,57
517,57
3. Menimbang dengan neraca teknis
Massa BK-2 (m2) = 155,5 gram
4.1.2 PESAWAT ATWOOD MODERN DAN KONVENSIONAL Pesawat Atwood Konvensional Percobaan GLB
Beban m1 = 0,0835 kg
Beban m2 = 0,0835 kg
r katrol= 0,00625 m a. Percobaan 1Beban m3 = 0,004 kg
NoJarak A-B (m)Waktu (detik)Kecepatan (m/s)
10,42,560,15625
20,62,810,21352
30,83,460,23121
413,900,25641
b. Percobaan 2
Beban m3 =0,006 kg
NoJarak A-B (m)Waktu (detik)Kecepatan (m/s)
10,41,620,24691
20,62,090,28708
30,82,560,3125
412,840,35211
Percobaan GLBB
a. Percobaan 1
Beban M3= 0,004 kg
Jarak A-B= 0,5m
NoJarak B-C (m)Waktu (detik)Kecepatan (m/s)Percepatan (m/s2)
10,20,250,057360,22947
20,30,620,142270,22947
30,40,870,199630,22947
40,51,180,270770,22947
b. Percobaan 2
Beban m3= 0,006 kg
Jarak A-B= 0,5m
NoJarak B-C (m)Waktu (detik)Kecepatan (m/s)Percepatan (m/s2)
10,20,180,061240,34023
20,30,400,136090,34023
30,40,750,255170,34023
40,51,030,350430,34023
Pesawat atwood modern
Beban m1 = 0,0835 kg
Beban m2 = 0,0835 kg
r katrol= 0,00625 m Percobaan GLB
a. Percobaan 1M3= 0,01kgNoJarak A-B (m)Waktu (detik)Kecepatan (m/s)
10,40,1123,57142
20,60,1145,26135
b. Percobaan 2
M3= 0.02kgNoJarak A-B (m)Waktu (detik)Kecepatan (m/s)
10,40,0775,19480
20,60,0678,95522
Percobaan GLBB
a. Percobaan 1
M3 = 10gr
Jarak A-B = 0,5 mNoJarak (m)Waktu (s)Kecepatan (m/s)Percepatan (m/s2)
10,20,0640,073710,55432
20,30,0750,106410,55432
b. Percobaan 2
M3
= 0,02 kgJarak A-B = 0,5 m
NoJarak (m)Waktu (s)Kecepatan (m/s)Percepatan (m/s2)
10,20,0640,073711,040919
20,30,0750,105681,040919
4.1.3 Modulus Elastisitas Batang I ( Kecil )
Panjang Tumpuan L0 = 950 mm
Daerah
PengukuranPanjang Batang (mm)Lebar (b) (mm)Tebal (h)
(mm)Luas Penampang (A)
(mm2)
I10009,99,998,01
II10009,89,593,1
III10009,79,693,12
IV10009,79,996,03
V100010,09,797,0
P = 1000 b = 9,82 h = 9,74A = 95,45
Tabel data pengamatan :Jumlah Beban (kg)Kedudukan G
Pada PenambahanPada PenguranganRata - rata
0,0000
0,5555
1,0101010
1,5151515
2,0101010
2,5242424
3,0292929
3,5343434
4,0393939
Batang II ( Sedang )Panjang Tumpuan L0 = 900 mm
Daerah
PengukuranPanjang Batang (mm)Lebar (b) (mm)Tebal (h)
(mm)Luas Penampang (A)
(mm)
I100021,19,9208,89
II100021,39,6204,48
III100020,89,6199,68
IV100021,49,8209,72
V100021,09,8205,8
P = 1000 b = 21,12 h = 9,74A = 205,714
Tabel data pengamatan :
Jumlah Beban (kg)Kedudukan G
Pada PenambahanPada PenguranganRata - rata
0,0000
0,5555
1,0999
1,5141414
2,0181818
2,5232323
3,0282828
3,5323232
4,0373737
Batang III ( Besar )Panjang Tumpuan L0 = 850 mm
Daerah
PengukuranPanjang Batang (mm)Lebar (b) (mm)Tebal (h)
(mm)Luas Penampang (A)
(mm)
I100016,516,5272,25
II100016,016,4262,4
III100015,316,6253,98
IV100017,416,5287,1
V100017,216,6285,52
P =1000b = 16,48 h = 16,52A = 272,25
Tabel data pengamatan Jumlah Beban (kg)Kedudukan G
Pada PenambahanPada PenguranganRata - rata
0,0000
0,5111
1,0222
1,5333
2,0444
2,5555
3,0666
3,5777
4,0888
4.1.4 Bandul Sederhana dan Resonansi Bandul Sederhana Tabel 1 Hubungan antara T dan l, m dibuat tetapMasa Bola Bandul35 Gram
Panjang Bandul0,20 m0,40 m0,60 m
Waktu Untuk 20 Ayunan19,4 s26,7 s31,6 s
Perioda T0,97 s1,335 s1,58 s
T2 (s2)0,94091,78222,4964
Tabel 2 Hubungan antara T dan m, l dibuat tetapPanjang Bandul0,60 m
Massa Bola Bandul35gr70gr
Waktu Untuk 20 Ayunan31,6 s32 s
Perioda T1,58 s1,6 s
T2 (s2)2,49642,56
Tabel 3 Hasil pengamatan resonansi bandul sederhana
m=70grPanjang BandulPerioda T0Perioda Trf0fr
50 cm1,41 s1,42 s0,709 Hz0,704 Hz
25 cm10,1 s1,085 s0.990 Hz0,921 Hz
4.1.5 Resonansi Pada Pegas HelikPegas Helik 4,5 N/M
Massa
(gram)Periode T0(s)Periode Tr
(s)F0(Hz)Fr
(Hz)
1001,0621,0390,9410,962
2001,3351,3170,7490,759
Pegas Helik 25 N/M
Massa
(gram)Periode T0(s)Periode Tr
(s)F0(Hz)Fr
(Hz)
1000,5250,53751,9041,860
2000,66650,6891,51,451
4.1.6 Hambatan Listrik1. Resistor 50 / 8 WNOV (Volt)I ( Ampere)
10,071,5x10-3 46,6
21,1622,3x10-352,0
33,9274,3x10-352,7
45,86110,3x10-353,1
55,88110,9x10-353,0
67,64144,5x10-352,8
711,350,2154,0
2. Resistor 100 / 4 WNOV (Volt)I ( Ampere)
10,151,5x10-3100
21,9119,3x10-398,9
33,7137,2x10-399,7
45,6056,4x10-399,2
57,7677,7x10-399,8
69,5495,8x10-399,3
711,55116,4x10-399,2
4.1.7 Elektromagnet4.1.8 Kalorimeter
Pengukuran awal
Massa kalorimeter + pengaduk kosong mk=79,2x10-3Kg
Menentukan kalor jenis besi
Massa balok besi mfe=18,6x10-3Kg
Massa kalorimeter +pengaduk berisi air mk+p=140,5x10-3Kg
Massa air dalam kalorimete mair=60,8x10-3kgSuhu awal kalorimeter + isi 0= 300 K, suhu balok besi panas b=368 KSuhu akhir kalorimeter A= 302 K
Kalor Jenis air ditentukan Cair=4,2x103 J/Kg
Kalor jenis besi Cfe=624,32 J/Kg Menentukan kalor jenis tembaga
Massa balok besi mCu=70,65x10-3Kg
Massa kalorimeter +pengaduk berisi air mk+p=148x10-3Kg
Massa air dalam kalorimeter mair=68,8x10-3kgSuhu awal kalorimeter + isi 0= 299.5 K, suhu butir tembaga panas b=368 K
Suhu akhir kalorimeter A= 305 K
Kalor jenis air ditentukan Cair=4,2x103 J/Kg
Kalor jenis alumunium ditentukan CAl=9,1x102 J/Kg
Kalor jenis tembaga Ccu=357,3 J/Kg
Menentukan kalor jenis alumunium
Massa balok besi mAl=21,7x10-3Kg
Massa kalorimeter +pengaduk berisi air mk+p=150x10-3Kg
Massa air dalam kalorimeter mair=70,8x10-3kgSuhu awal kalorimeter + isi 0= 299,5 K, suhu butir tembaga panas b=368 K
Suhu akhir kalorimeter A= 303,5 K
Kalor jenis air ditentukan Cair=4,2x103 J/Kg
Kalor jenis alumunium CAl=1240,48 J/Kg
4.2 Pengolahan Data4.2.1 Pengukuran Dasara. Benda kerja 1 (BK-1): KUNINGAN
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3
1. Nilai ketidakpastian dan nilai intervalnya
Nilai ketidakpastian panjang
EMBED Equation.3
=
=
= Nilai ketidakpastian
Nilai interval panjang
P2 = P = P1
45 mm = 45 mm = 45 mm Nilai ketidakpastian lebar
=
=
= Nilai ketidakpastian
Nilai interval lebar L2 = = L1
25 mm = 25 mm = 25 mm Nilai ketidakpastian tinggi/tebal
=
=
= Nilai ketidakpastian
Nilai interval tinggi/tebal T2 = T = T1
17,6 mm = 17,6 mm = 17,6 mm Nilai ketidakpastian volume
Nilai interval volume
V2 = V = V1
19800 mm = 19800 mm = 19800mm
Nilai massa jenis
Nilai interval massa jenis
(1 = ( = (2
= =
b. Benda kerja 2 (BK-2): Tembaga
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3
1. Nilai ketidakpastian dan nilai intervalnya
Nilai ketidakpastian panjang
EMBED Equation.3
=
=
= Nilai ketidakpastian
Nilai interval panjang
P2 = P = P1
45 mm = 45 mm = 45 mm Nilai ketidakpastian lebar
=
=
= Nilai ketidakpastian
Nilai interval lebar L2 = = L1
25,1 mm = 25,1 mm = 25,1 mm Nilai ketidakpastian tinggi/tebal
=
=
= Nilai ketidakpastian
Nilai interval tinggi/tebal T2 = T = T1
17,6 mm = 17,6 mm = 17,6 mm Nilai ketidakpastian volume
Nilai interval volume
V2 = V = V1
19879,2 mm = 19879,2 mm = 19879,2 mm
Nilai massa jenis
EMBED Equation.3
Nilai interval massa jenis
(1 = ( = (2
= =
c. Benda kerja 2 (BK-2): Besi
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3
1. Nilai ketidakpastian dan nilai intervalnya
Nilai ketidakpastian panjang
EMBED Equation.3
=
=
= Nilai ketidakpastian
Nilai interval panjang
P2 = P = P1
45,1 mm = 45,1 mm = 45,1 mm Nilai ketidakpastian lebar
=
=
= Nilai ketidakpastian
Nilai interval lebar L2 = = L1
25,1 mm = 25,1 mm = 25,1 mm Nilai ketidakpastian tinggi/tebal
=
=
= Nilai ketidakpastian
Nilai interval tinggi/tebal T2 = T = T1
17,6 mm = 17,6 mm = 17,6 mm Nilai ketidakpastian volume
Nilai interval volume
V2 = V = V1
mm = mm = mm
Nilai massa jenis
EMBED Equation.3
Nilai interval massa jenis
(1 = ( = (2
= =
4.2.2 Pesawat Atwood Modern dan Konvensional Percobaan GLB Pesawat Atwood Konvensional
Percobaan 1
1)
2)
3)
4)
Percobaan 21)
2)
3)
4)
Percobaan GLBB
Percobaan 1
Percobaan 2
Perhitungan atwood modern
Percobaan GLB
Percobaan 1
1)
2)
Percobaan 21)
2)
Percobaan GLBB
Percobaan 1
Percobaan 2
Momen Inersia GLBB Pesawat Atwood Modern
Percobaan 1
Percobaan 2
Pesawat Atwood Modern Percobaan 1
Percobaan 2
Percobaan I GLBB
I = (m3g -2m m3)r2
= (=
= (0,17 0,161 ) (0,00625)2
= (0,17 0,161) (3,9 .10-5)
= 0,007 . 3,9 . 10-5
= 2,73 . 10-7 kg m2 Percobaan II GLBB
I = (= r2= (= = (0,17 0,161) (0,00625)2
=0,009 . 3,9 . 10-5
=0,9 . 60-2 .3,9 . 10-5
=3,51 .10-7 kgm2
1.2.3 Modulus Elastisitas
Batang I
Pengukuran : KecilPanjang Tumpuan , L0 = .... ?
L0 = L 5%
A = 95,45mm2 = 1000 50 = 950 mm Tegangan
Rumus dari tegangan yaitu :
Regangan Rumus dari regangan yaitu :
diketahui L0 = 950mm2
Modulus Elastisitas ( E )
Rumus dari Modulus elastisitas yaitu:
Nilai f ( Pelenturan )
Rumus nilai f ( Pelenturan ) yaitu : Dimana B = beban
L0 = panjang awal
E = Modulus elastisitas
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3 Batang IIPengukuran : SedangPanjang Tumpuan , L0 = .... ?
L0 = L 10%
A = 205,714mm2 = 1000 10 = 900 mm
Tegangan
Rumus dari tegangan yaitu :
Regangan Rumus dari regangan yaitu :
diketahui L0 = 900mm2
Modulus Elastisitas ( E )
Rumus dari Modulus elastisitas yaitu:
Nilai f ( Pelenturan )
Rumus nilai f ( Pelenturan ) yaitu : Dimana B = beban
L0 = panjang awal
E = Modulus elastisitas
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3 Batang IIIPengukuran : BesarPanjang Tumpuan , L0 = .... ?
L0 = L 15%
A = 272,25mm2 = 1000 150 = 850 mm
Tegangan
Rumus dari tegangan yaitu :
Regangan Rumus dari regangan yaitu :
diketahui L0 = 850mm2
Modulus Elastisitas ( E )
Rumus dari Modulus elastisitas yaitu:
Nilai f ( Pelenturan )
Rumus nilai f ( Pelenturan ) yaitu : Dimana B = beban
L0 = panjang awal
E = Modulus elastisitas
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3
EMBED Equation.3 4.2.4 Bandul Sederhana dan Resonansi Bandul Sederhana
- Bandul Sederhana
Massa bola bandul 35gr
1. Panjang bandul 0,20 m
Diketahui : t=19,23 s
Jawab: T=
=
= 0,96 s
T2 = 0,9216 s22. Panjang bandul 0,40 m
Diketahui : t=24,95 s
Jawab : T=
=
= 1,25 s
T2 = 1,5625 s23. Panjang bandul 0,60
Diketahui : t=31,72 s
Jawab : T=
=
= 1,59 s
T2 = 2,5281 s2 Panjang bandul 0,60 m1. Massa bola 35gr
Diketahui : t= 31,32 s
Jawab: T=
=
= 1,575 s
T2 = 2,4649 s22. Massa bandul 70gr
Diketahui : t=31,75 s
Jawab : T=
=
= 1,595 s
T2 = 2,5281 s2 Resonansi Bandul Sederhana1. Panjang bandul 50cm dan massa bandul 35gr
Diketahui : t0 = 1,31 s
T20=27,80 s
Jawab : T0 =1,31 s
T20 =
=
= 1,37s
f0 =
f20 = 2. Panjang bandul 25cm dan massa bandul 35gr
Diketahui : t0 = 0,95 s
T20=20,25 s
Jawab : T0 =0,95 s
T20 =
=
= 1,0125 s
f0 =
f20 = 1.2.5 Resonansi Pada Pegas Helik Percobaan 1 Pegas Heliks k = 4,5 N/m
Beban m1 = 100 gram
Beban m2 = 200 gram
Percobaan 2 Pegas Heliks k = 4,5 N/m
Beban m1 = 100 gram
Beban m2 = 200 gram
1.2.6 Hambatan Listrik
Percobaan 1 (50 / 8 W)
Percobaan 2 (100 / 4 W)
2.
3.
4.
5.
6.
7.
8.
8.2.5 Elektromagnet
Nilai Ketidakpastian
Nilai Ketidakpastian
[Labolatorium Fisika 2015]55
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