lab 10 write up2

Upload: tennis40love4423

Post on 06-Apr-2018

213 views

Category:

Documents


0 download

TRANSCRIPT

  • 8/3/2019 Lab 10 Write Up2

    1/2

    EllieQuirini

    Lab10:AngularAccelerationPurpose: Wearegoingtoexertatorqueonseveralsimilarsystems,creatingangular

    acceleration,andfindoutwhatwecanaboutthemomentofinertia.

    Materials: TurnTable Pulley String HangingMass MeterStick Timer

    Diagram:

    ProcedureandData:

    1. Setupthediscandpulleysystemasseenabove.

    2. Measuremassesofdiscs,ring,bar,andhangingmass.

    Discs 179.61g

    Ring 711.8g

    Bar 709.2g

    Hanging 100.6g

    3. Measuredistancefromfloorofhangingmass:0.9455m

    4.Selecteitherthedisc,ring,orbarandplaceonturntableaccordingly.

    MassCombo1:

    (onlydiscs)

    MassCombo2:

    (discsw/ring)

    MassCombo3:

    (discswithbar)

    Trial1 13.0sec 17.4sec 15.2sec

    Trial2 13.1sec 17.2sec 15.6sec

    Trial3 13.2sec 17.4sec 14.9sec

    Disc(onturntable) Ring(onturntable) Bar(onturntable)

    a1

    m1

    disc

  • 8/3/2019 Lab 10 Write Up2

    2/2

    =0t+t2

    5. Wecandeterminethemomentofinertiaforthesystemsbyusingthemomentofinertiaequations:

    6. Findtheradiiandlengthofdifferentcomponents:

    7. CalculateexpectedangularaccelerationusingInertiaandTorque:

    8. Nowweusethedatawecollectedearliertofindourownvalueforangularacceleration.

    9. Weknowtheradiusofthecylinderthatthestringpulledfrom:.0185m Usingthisandourknowledgeofgeometry,wecandeterminehowmany

    timestheturntablespuntoletoutenoughstringforthehangingmasstohit

    theground.

    10.Finally,wecanusesomesimplecalculationsusingandtheaveragetimesforeachcombowiththeTNEO(A)Mtofind:

    Combo1:(onlydiscssolidcylinder) MR2

    Combo2:(discsw/ring) MR2+MR2

    Combo3:(discsw/bar) MR2+(1/12)ML2

    Discs .1215m

    Ring .0600m

    Bar .2255m

    Discs .01755=.00133=13.23rad/sec2

    Ring .01755=.00389=4.51rad/sec2

    Bar .01755=.00433=4.053rad/sec2

    Combo1 51.12=0+(13.1)2

    Combo2

    Combo3

    MR2=(0.17961)(0.1215)2=0.00133kgm2

    MR2+MR2=(0.001326)+(0.7118)(0.06)2=0.00389kgm2

    MR2+(1/12)ML2=(0.001326)+(1/12)(0.7092)(0.2255)2

    =0.00433kgm2

    =rF =I

    r=.0178m

    F=mg=0.9858N

    =0.01755mN

    Circumference:2r=0.116m

    x=0.9455m

    0.9455/0.116=8.134revolutionsperdrop

    1rev=2rad

    8.134rev=51.12rad=