kfhc kelompok 2
TRANSCRIPT
8/18/2019 KFHC KELOMPOK 2
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Nama kelompok :
1.
FIRMAN DWI PRASETYO (1401046)
2. AGISTIYANI (1401038)
3.
SITI AISYAH (1401037)
KELAS : S1. TPA.2014
TUGAS : KFHC
GROUP TASK
EACH GROUP CONTAINS MAX 3 PERSONS
1. For the gas composition given in the following text, determine apparent molecular weight,
specific gravity, pseudo-critical pressure, pseudo critical temperature of gas.
Component Mole Fraction
C1 0.775
C2 0.083
C3 0.021
i-C4 0.006
n-C4 0.002
i-C5 0.003
n-C5 0.008
C6 0.001
C7 0.001
N2 0.05
CO2 0.03H2S 0.03
2. After you determine Ppc and Tpc, determine Pseudo-Reduce Pressure and Pseudo-Reduce
Temperature. After that find the gas compressibility Factor using Standing Kartz Correlation
and Beggs Brill Correlation. (standing kartz chart is attached).
Jawab :
PERHITUNGAN
1.
* MENCARI AMWRUMUS : XMW )
= 0,775 X 16 = 12,4
= 0,083 X 30 = 2,49
= 0,021 X 44 = 0,924
= 0.006 X 58,12 = 0,348
= 0,002 X 58,12 = 0,116
= 0,003 X 72,14 = 0,216
= 0,008 X 72,14 = 0,577
= 0,001 X 86,17 = 0,086
= 0,001 X 100,19 = 0,100
8/18/2019 KFHC KELOMPOK 2
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= 0,050 X 28 =1,4
= 0,030 X 44 = 1,32
= 0,020 X 34 = 0,68
AMW = 20,657
SG
SG =
=
= 0,712
Ppc = 709.604 – 58.718(0,712) = 709.604-(41.807) = 667.797
Tpc = 170.491+ 307.344(0,712) = 170.491 + (218.83) = 389.321
2. * Ppr =
=
= 4.866
*Tpr =
=
=
= 1,728
Menggunakan beggs and brill correlation
A =
–
0,36(1,728) –
0,1 = 0,527
B = (0,62 – 0,23(1,728))4,866 + (
) – 0,0037) +
= 42,25
C = 0,132 – 0,32log(1,728) = 0,056
D = = = 1,023
E = 9(1,728 – 1) = 6,5
F = 0,3106 – 0,49(1,728) + 0,1824 = 0,01
DAN
Z = A +
+ C
= 0,527 +
+ 0,270 = 0,797
+