jembatan pelat lengkung

Upload: andricibeo

Post on 08-Jul-2018

235 views

Category:

Documents


0 download

TRANSCRIPT

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    1/105

    MUTU BETON PELAT ATAS/LANTAI KENDARAAN :

    MUTU BETON PONDASI DLL. :

    MUTU BAJA TULANGAN :

    :

    :

    :

    BENTANG JEMBATAN ( BENTANG PENAMPANG BASAH BUSUR ) (M) :

    LEBAR JALUR KENDARAAN (M) :

    LEBAR TROTOAR (M) :

    TEBAL TANAH URUG (TENGAH BUSUR s/d LAPIS ATAS) (M)

    #DIV/0! :

    PANJANG TIANG PANCANG ANG DIPERLUKAN (M) :

    JENIS TIANG PANCANG :

    BENTUK PENAMPANG TIANG PANCANG :

    DIAMETER PENAMPANG ( D ) (C ) :

    1 1.00 #

    SPESI"IKASI :

    DATA TANAH E ISTING DI BA$AH PONDASI : BERAT JENIS TANAH E ISTING ( γs ) % &' / *

    SUDUT GESER TANAH ( + . , ' ) %φs ' *

    DA A DUKUNG TANAH KERAS ( - & - 1 ) %&' / 2*

    PROPERTIS :

    TINGGI JEMBATAN (LAPIS ASPAL s/d DASAR POOR PONDASI) ≥

    SILAHKAN DIISI DATA LANJUTAN….!!!!

    (M)

    K

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    2/105

    .00

    2

    3.00

    3.00

    LIK...PROSES...!!

    U-32

    BETON

    BULAT

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    3/105

    DATA JEMBATAN : NAMA JEMBATAN : LOKASI PADA RUAS JALAN : STA / KM :

    KABUPATEN / KOTA : NAMA DAN $ILA AH BPJ : STATUS JALAN :

    "UNGSI JALAN :

    JENIS PENANGANAN : KRITERIA PRERENCANAAN : TIPE MUATAN BEBAN :

    JENIS KONTRUKSI BANGUNAN ATAS :

    JENIS PONDASI BANGUNAN BA$AH :

    TANGGAL PERENCANAAN : Disusun oleh Engkus Sukmaja Tlp. (022) 7302552

    JEMBATAN P

    PEMBANGUNAN / PENGGANTIAN JEMBATAN

    BM 100

    PELAT BETON LENGKUNG ½ LINGKARAN

    PONDASI TIANG PANCANG

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    4/105

    2.00

    2.00

    3.00

    3.00

    1.00

    1.00MEI 2010

    LAT LENGKUNG

    PEMBANGUNAN / PENGGANTIAN JEMBATAN

    BM 100

    PELAT BETON LENGKUNG ½ LINGKARAN

    PONDASI TIANG PANCANG

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    5/105

    SI !" !$ ME$%$&&% 'E'E ! ! ME$IT S!*! +++..+

    SI !" !$ ME$%$&&% 'E'E ! ! ME$IT S!*! +++..+

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    6/105

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    7/105

    +..,,,,,

    +..,,,,,

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    8/105

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    9/105

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    10/105

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    11/105

    PEMERINTAH PROVINSI JAWA BARAT

    DINAS BINA MARGASUB DINAS BINA TEKNIK

    NAMA JEMBATAN : 0

    PROGRAM PENAGANAN : PEMBANGUNAN JEMBATAN / PENGGANTIAN JEMBATAN

    LOKASI JEMBATAN PADA RUAS JALAN : 0

    STA. / KM : 0STATUS / "UNGSI JALAN : PROVINSI / KOLEKTOR

    KABUPATEN : 0

    NAMA DAN $ILA AH BPJ : 0

    TANGGAL PERENCANAAN : MEI 2030

    PERHITUNGAN STRUKTUR JEMBATAN

    A. PERENCANAAN BANGUNAN ATAS

    3. DATA TEKNIS DAN DIMENSI

    . D & K' s&4 5s+ - Tipe ons /uksi 'angnan ! as : *em a an ela 'e on engkung Se engah ingka/an

    - Tipe on asi : Sumu/an → #DI 0, me e/ - Tipe Mua an 'e an : 'M 100

    - 'en ang : - me e/ " : - me e/

    - e a/ jem a an ' : - me e/ - e a/ *alu/ en a/aan : - me e/ - e a/ T/o oa/ 4 : - me e/

    6. D & T 7

    ke e/angan anah ke/as u/ugan

    - 'e/a jenis anah : - 1.70 - Su u gese/ anah : - 30.00 - Da6a ukung anah 0.00 0.00

    1. D & M &84+ a. Mu u 'e on

    a/ak e/. Tekan Ta/ik &ese/- ela engkung - : 350 118 9 :.0

    - Din ing Samping en6eka -: 250 :3 : 8.:- T/o oa/ - : 250 :3 : 8.:- 'e/a *enis 'e on 'e/ ulang : 2.50- 'e/a *enis 'e on Tum uk : 2.20

    . Mu u 'aja Tulangan % - : 3;200 0.20 m Tinggi lapis pon asi jalan > 0.50 m Tinggi anah u/ug > - m *a/i - ja/i alam usu/ lingka/an ( ) > #DI 0, m Te al pela usu/ > #DI 0, m Tinggi in ing iang (kaki) > #DI 0, m

    Te al /o oa/ > 0.25 m Te al in ing samping > 0.25 m Te al pela iang ( kaki ) > #DI 0, m

    Dia. >

    - Tinggi (lihat gambar dibawah )

    γ m3o

    ? all m2

    Tegangan I@in 'e on (kg

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    12/105

    2. SISTEM STATIKA DAN PERHITUNGAN BEBAN

    !sumsi se agai jem a an lengkung pa a 3 ( iga) s a is e/ en u 6ang ke ua umpuann6a engan sis em jepi

    2a. Dimensi Teo/i is B

    'en ang engkung C > > #DI 0, m anjang engkung > > #DI 0, m Tinggi engkung > > #DI 0, m Tinggi kons /uksi " > > #DI 0, m

    2 . e/hi ungan 'e an B 1. 'e an Ma i

    > #DI 0,> #DI 0,> #DI 0,

    ela 'usu/ > #DI 0,ela T/o oa/ e/ > #DI 0,

    > #DI 0,

    Din ing samping > #DI 0, onDin ing pen6eka 2;5 . > - onSan a/an 1;2 . > - on

    > #DI 0, on> #DI 0,> #DI 0,> #DI 0, on m

    2. 'e an "i upe a/ lalu lin as ken a/aan > 2.75 m

    'e an hi up e/pusa T > 10.00 on

    oeFisien keju > #DI 0,'e an hi up engan koeFisien keju

    > = 100G > #DI 0, on m

    m > > #DI 0, mp > > #DI 0,

    3. 'e an Ma i "i upg > H p > #DI 0,

    . Tekanan Tanah !k i

    > > 0.30:5

    > 30 α > 0> 0 > 10> 1.70

    > #DI 0,> #DI 0,

    - TplJ EK L. C

    Tpl 2 h

    e/ke/asan jalan 1 > γ p . h1 . ' on m2

    apis on asi *alan 2 > γ a . h2 . ' on m2Ma e/ial %/ugan 3 > γ . h3 (1-L ). N on m2

    1 > γ γ . / . 2(4 0;25) ' on m2

    H1 on m2

    3 > 2. . " - L. 2 2N.T4.γ < >

    5 >

    3 5H2 > ( 3 5 ) (C .') on m2

    H > H1 H2 on m2Din ing kaki 8 > h . 1 . γ <

    Ck

    > 20 (50 C)

    T ( 2T Ck ) . (1 )

    2 (h1 h2 h3 0;5.Tpl) 0;5T m on m2

    on m2

    !

    sin(φ δ) . sin(φ - α ) ( 0;8 h3 ) .γ . ! on m2 a2 > a1 γ . . ! on m2

    g

    O DC

    h

    E K a1a1

    a2a2

    1 2

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    13/105

    . ANALISA MEKANIKA DENGAN CARA KERJA VIRTUAL

    a. Momen Ine/sia#DI 0,

    #DI 0,

    #DI 0, ( - )

    e/samaan ga/is lengkung se engah lingka/an B 6 > =

    0.00 P Q0.00

    1.00

    > #DI 0, on m> #DI 0, on m

    > #DI 0, on.m m

    > #DI 0, on.m m> #DI 0, on.m m> #DI 0, on m> #DI 0, on m

    #DI 0, m#DI 0, m#DI 0, m#DI 0, m

    #DI 0, m#DI 0, m#DI 0, m#DI 0, m

    F. Menen ukan ja/ak i ik e/a elas is kons /uksi ( e )

    #DI 0, m> #DI 0, m

    ela engkung BΙpl > 10.Tpl 12 > m

    ela aki BΙ > 10. 1 12 > m

    k > Ι Ιpl >

    Su u ga/is usu/ pa a se iap i ik B

    6 > =2 2 Q

    > a/< g(6 ) > a/< g( = )un uk = > 0 Q >

    sin ( ) >

    .1 Momen p/ime/ M0 aki a e an e an ma i hi up ( g )

    O0g > g . C 2 8E0g > g . C 2

    M0g > - R g . C2

    .2 Momen p/ime/ M0 a aki a e an ekanan anah ak iME0 a > - ⅙( a2- a1) R a1N.h2

    MO0 a > - ( a2- a1) R a1N.h2" O0 a > h⅙ ( a1 2 a2)" E0 a > h⅙ (2 a1 a2)

    - e > M1pl( ) > -e >

    ila/ po/ al B M1 (-) > - e > M1 ( ) > e >

    . 'esa/an s a ik aki a ga6a i/ ual 2 > 1a ang eng ung B 1pl(-) > - >

    M1pl( ) > C 2 >ila/ po/ al B M1 (-)> - C 2 >

    M1 ( ) > C 2 >

    e. 'esa/an s a ik aki a i/ ual 3 > 1'a ang lengkung B M1pl(-) > 1

    1pl( ) >ila/ po/ al M1 (-)> 1

    M1 ( ) > 1

    EΙ . δ 13 = M 1 . M 3 . dx = 0 , maka engan a uan a el hasil in eg/al i apa B pa a a ang lengkung po/ al B EΙpl . V13 > U M1pl . M3pl . = > W . C - e.C

    pa a pila/ po/ al B EΙ . V13 > M1 . M3 . = > - h2

    V13 > U M1 . M3 . = > C ( W - e )Ιpl - h 2 Ι > 0C ( W - e )Ι Ιpl - h 2 > 0C (2 - 3e ).k - 3h 2 > 02k.C. - 3k.C.e - 3h2 > 03k.C.e > 2k.C. - 3h2 e > ( 2k.C. - 3h2 ) ( 3k.C ) >e > h e

    e

    2

    13

    -

    1) 'i ang-M0 aki a e an g

    ) 'i ang-M2 aki a 2 > 1

    e

    Ti ik e/a elas iskons /uksi

    1

    C 3 2

    C 3 2

    1

    C

    "

    e > ja/ak i ik e/a elas is kons /uksi

    - - M0g

    -

    M0g

    -

    M 0 g

    M 0 g

    e e

    -

    C 2

    C 2

    --e

    ee

    1

    1 1

    Ι Ι

    Ιpl Ιpl

    --$ 1pl > 1

    $ 1 > 0? 1pl > 0

    ? 1 > - 1

    $ 2pl > 0? 2pl > 1$ 2 > 1? 2 > 0

    ? 3 > 0$ 3 > 0? 3pl > 0$ 3pl > 0

    E K

    O D

    9

    9

    99

    9

    2) 'i ang-M0 aki a e an g

    9ME0 a ME0 a

    MO0 a

    ME0 a

    MO0 a

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    14/105

    > #DI 0,

    > #DI 0,

    > #DI 0,

    > #DI 0,

    > #DI 0, m

    . N+ + A57+4 M 5s+ B8s 4 S& &+5

    a. !ki a 'e an Ma i an "i up ( g )

    > #DI 0,> #DI 0,

    > #DI 0,

    > 0.00> 0.00> 0.00

    > #DI 0,> #DI 0,> #DI 0,

    e/ en u menja i B> #DI 0, on m

    > #DI 0, on m

    > #DI 0, on.m m

    Momen BTi ik Simpul E > #DI 0, on.m m

    Tumpuan > #DI 0, on.m mela engkung C 2 > #DI 0, on.m m

    &a6a $o/malTi ik Simpul E B'a ang EK > #DI 0, on m'a ang EO > #DI 0, on m

    > #DI 0, on m

    Tumpuan O > #DI 0, on mela engkung > #DI 0, on m

    &a6a in angTi ik Simpul E B'a ang EK > #DI 0, on m'a ang EO > #DI 0, on m

    > #DI 0, on m

    g. $ilai pe/u ahan en uk aki a M1 B

    EΙpl . V11pl > U M1pl . M1pl . = > C.k e2 - 2 . W .e . : 15 2 N m3

    EΙ . V11 > U M1 . M1 . = > W h e2 - e .e e2 N m3

    EΙ . V11 > U M1 . M1 . = m3

    h. $ilai pe/u ahan en uk aki a M2 B

    EΙ . V22 > U M2 . M2 . = > k.C.(XC)2 X h .C2 m3

    i. $ilai pe/u ahan en uk aki a M3 B

    EΙ . V33 > U M3 . M3 . = > C 2k.h

    1. $ilai pe/u ahan en uk aki a M0g an M1 B EΙpl . V10gpl > U M1pl . M0gpl . = > C . k .M0gpl . M1pl(-) 2 15 C .k .M0gpl . on.m3

    EΙ . V10g > U M1 . M0g . = > X h . M0g . ( e - e ) on.m3

    EΙ . V10g > U M1 . M0g . = on.m3

    2. $ilai pe/u ahan en uk aki a M0g an M2 B EΙpl . V20gpl > U M2pl . M0gpl . = >⅟ 12 C.k.M0g ( XC - XC ) on.m3

    EΙ . V20g > U M2 . M0 . = > X h . M0g .( e - e ) h.M0g.(XC) - h.M0g.(XC) on.m3

    EΙ . V10g > U M1 . M0g . = on.m3

    . a pe/u a an en u a a 0g an 3 B EΙpl . V30gpl > U M3pl . M0gpl . = > C.k.M0g on.m3 EΙ . V30g > U M3 . M0g . = > 2 h . M0g on.m3

    EΙ . V30g > U M3 . M0g . = on.m3

    a/ena i ang momen M2 e/ en uk an ime /is; se angkan i ang 6ang lainn6a sime /is maka pe/samaan s a is i ak

    1g > - V10g V11

    2g > - V20g V22

    3g > - V30g V33

    B M > M0 M1. 1 M2 . 2 M3 . 3B MEg > MO0g M1 (-) . 1g M2 (-) . 2g M3 ( ) . 3gB M

    Og > M

    O0g M

    1 (-) .

    1g M

    2 ( ) .

    2g M

    3 ( ) .

    3gB MOgpl > 0 M1pl( ) . 1g M2pl( ) . 2g M3pl( ) . 3g

    B $ > $0 $1. 1 $2 . 2 $3 . 3

    B $EKg > - E0g . Sin( ) $1pl . 1g . Oos( )B $EKg > E0g $1 . 1g

    $ Eg

    B $Og > - O0g $1 . 1gB $gpl > $1pl. 1g

    B ? > ?0 ? 1. 1 ? 2 . 2 ? 3 . 3

    B ?EKg > E0g .Oos( ) ?1pl. 1g .Sin( )B ?EOg > - ? 1 . 1g

    ? Eg

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    15/105

    . !ki a Tekanan Tanah !k i ( a )

    > #DI 0,> #DI 0,

    > #DI 0,

    > -> -> -

    > #DI 0,

    e/ en u menja i B> #DI 0, on m

    > #DI 0, on m

    > #DI 0, on.m m

    Momen BTi ik Simpul E > #DI 0, on.m mTumpuan > #DI 0, on.m m

    ela engkung C 2 > #DI 0, on.m m

    &a6a $o/malTi ik Simpul E B'a ang EK > #DI 0, on m'a ang EO > #DI 0, on m

    > #DI 0, on mTumpuan O > #DI 0, on m

    ela engkung > #DI 0, on m

    &a6a in angTi ik Simpul E B

    'a ang EK > #DI 0, on m'a ang EO > #DI 0, on m

    > #DI 0, on mTumpuan O > #DI 0, on m

    ela engkung > #DI 0, on m

    R85 ;+& s+ :Momen BTi ik Simpul E > #DI 0, on mTumpuan > #DI 0, on m

    ela engkung C 2 > #DI 0, on m

    &a6a $o/malTi ik Simpul E > #DI 0,on mTumpuan O > #DI 0, on m

    ela engkung > #DI 0,on m

    &a6a in angTi ik Simpul E > #DI 0, on m

    1. $ilai pe/u ahan en uk aki a M0 a an M1 B

    EΙpl . V10 apl > U M1pl . M0 apl . = > C . k .M0 apl . M1pl(-) C .k .M0 apl . on.m3

    EΙ . V10 a > U M1 . M0 a . = >1 12 C.(MO0 a ME0 a) ( e - e ) on.m3

    EΙ . V10 a > U M1 . M0 a . = on.m3

    2. $ilai pe/u ahan en uk aki a M0 a an M2 B

    EΙpl . V20 apl > U M2pl . M0 apl . = > on.m3

    EΙ . V20 a > U M2 . M0 a . = > on.m3

    EΙ . V10 a > U M1 . M0 a . = on.m3

    3. $ilai pe/u ahan en uk aki a M0 a an M3 B

    EΙpl . V30 apl > U M3pl . M0 apl . = > C .k.ME0 a ⅙ h . (MO0 a ME0 a) on.m3

    a/ena i ang momen M2 e/ en uk an ime /is; se angkan i ang 6ang lainn6a sime /is maka pe/samaan s a is i ak

    1 a > - V10 a V11

    2 a > - V20 a V22

    3 a > - V30 a V33

    B M > M0 M1. 1 M2 . 2 M3 . 3B ME a > MO0 a M1 (-) . 1 a M2 (-) . 2 a M3 ( ) . 3 aB MO a > MO0 a M1 (-) . 1 a M2 ( ) . 2 a M3 ( ) . 3 aB MO apl > 0 M1pl( ) . 1 a M2pl( ) . 2 a M3pl( ) . 3 a

    B $ > $0 $1. 1 $2 . 2 $3 . 3

    B $E a > " E0 a . Sin( ) $1pl . 1 a. Oos( )B $EK a > " E0 a $1 . 1 a

    $ E aB $O a > $1 . 1 aB $apl > $ 1pl. 1 a

    B ? > ?0 ? 1. 1 ? 2 . 2 ? 3 . 3

    B ?E a > " E0 a . Oos( ) ?1pl. 1 a. Sin( )B ?EO a > - ? 1 . 1 a

    ? E aB ?O a > " O0 a- ? 1 . 1 aB ? apl > 0 ? 1pl . 1 a

    B ME > MEg ME aB MO > MOg MO aB Mpl > Mgpl M apl

    B $E > $Eg $E aB $O > $Og $O aB $pl > $gpl $ apl

    B ?E > ? Eg ? E a

    ka/ena sime /is an an ime /is

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    16/105

    1;:58.00 % - 32

    > 2;7: .00

    n > 1:.00 -

    > 115.50 - 350

    > :.0

    > 0.:93 -

    U4 + S & HASIL

    Momen M on.m m #DI 0,&a6a $o/mal $ on m #DI 0,&a6a in ang ? on m #DI 0,

    > #DI 0,> #DI 0,> ( - ) #DI 0,> ( - ) #DI 0,> on. Tulangan Sime /is

    > (-) 0.:75#DI 0, > (-) #DI 0,

    Y > (-) 0. 07> (-) #DI 0,

    @ > Z.h > Y.h > (-) 1. 8> (-) #DI 0,> (-) #DI 0,

    #DI 0, > (-) #DI 0,> #DI 0,> #DIV/0!> #DIV/0!> #DI 0,

    on /ol &ese/ > #DI 0,> #DI 0,

    σ a kg (12 σ[au) . . h (15 σ[au) .h .103 M $

    2 \ e o2 > h 30eo > eo1 eo2

    eo han eo h >\ O

    k > 0;7.C e1 > O.( k 100.h)2.h

    e2 > 0;15.he > eo e1 e2

    ea > e 0;5.h - $.e a

    Oa > > ] 1 (n.^.Z) _Xn.$.e a.̀ a

    ξ >7 :

    nω = ½ε 2/{d'/h.δ + 1 - ε(δ + 1)}

    φ > (1-ε) ε φ > (1-ε) (ε - h)

    ω = nω/n

    i.! > ω. .h +.A/+ δ .+A 20G . ! pe/lu ? ( .h.7 :) kg

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    17/105

    @. P847+& = P8 68s+ P8 & D+ d+ = K 5+

    #DIV/0!

    > 1;:58.00 % - 32

    > 2;7: .00

    n > 1:.00 -

    > 115.50 - 350

    > :.0

    > 0.:93 -

    U4 + S & HASIL

    Momen M > on.m m #DI 0,&a6a $o/mal $ > on m #DI 0,&a6a in ang ? > on m #DI 0,

    > #DI 0,> #DI 0,> ( - ) #DI 0,> ( - ) #DI 0,> on. Tulangan Sime /is

    > (-) 0.:75#DI 0, > (-) #DI 0,

    Y > (-) 0.39:> (-) #DI 0,

    @ > Z.h> Y.h > (-) 1.51> (-) #DI 0,> (-) #DI 0,

    #DI 0, > (-) #DI 0,> #DI 0,> #DIV/0!> #DIV/0!> #DI 0,

    on /ol &ese/ > #DI 0,> #DI 0,

    σ a kg (12 σ[au) . . h (15 σ[au) .h .103 M $

    2 \ e o2 > h 30eo > eo1 eo2

    eo han eo h >\ O

    k > 0;7.he1 > O.( k 100.h)2.h

    e2 > 0;15.he > eo e1 e2

    ea > e 0;5.h - $.e a

    Oa > > ] 1 (n.^.Z) _Xn.$.e a.̀ a

    ξ >7 :

    nω = ½ε 2/{d'/h.δ + 1 - ε(δ + 1)}

    φ > (1-ε) ε φ > (1-ε) (ε - h)

    ω = nω/n

    i.! > ω. .h +.A/+ δ .+A 20G . ! pe/lu ? ( .h.7 :) kg

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    18/105

    P8 68s+ P8 & L8 =5 = ( B s 4 )

    9 T 4+5 φ #DIV/0! #DIV/0!

    > mm #DI 0,

    *a/ak a > #DI 0,

    Tulangan em agi B φ #DIV/0! #DIV/0!

    > mm #DI 0,*a/ak a > #DI 0,

    9 T85 φ #DIV/0! #DIV/0!

    > mm #DI 0,*a/ak a > #DI 0,Tulangan em agi B φ #DIV/0! #DIV/0!

    > mm #DI 0,*a/ak a > #DI 0,

    #DIV/0!

    P8 68s+ P8 & D+ d+ = K 5+

    9 T 4+5 φ #DIV/0! #DIV/0!> mm #DI 0,

    *a/ak a > #DI 0,

    Tulangan em agi B φ #DIV/0! #DIV/0!> mm #DI 0,

    *a/ak a > #DI 0,

    9 T85 φ #DIV/0! #DIV/0!> mm #DI 0,

    *a/ak a > #DI 0,

    Tulangan em agi B φ #DIV/0! #DIV/0!> mm #DI 0,

    *a/ak a > #DI 0,

    Dia. φ

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    19/105

    B. PERENCANAAN BANGUNAN BA$AH

    3. P847+& = B86 M &+ B = B 7

    #DI 0, m

    - m

    - m

    - m - m

    - m - m 1.:0 m#DI 0, m

    1.:0 m 0.:0 m#DI 0, m#DI 0, m

    #DI 0, m

    #DI 0, m

    ' > 0.00 m

    u > #DI 0, m

    2. P847+& = B86 M &+

    N'. BERAT ( T' )TERHADAP TITIK O

    ( ) ( ) G (&. ) G (&. )

    3. B d K 5+a 1.00 = ### = 0.00 = #DI 0, = 2.50 > #DI 0, 0.00 #DI 0, #DI 0, #DI 0,

    0.50 = 1.:0 = 0.00 = 0.00 = 2.50 > 0.00 -0.80 0.00 0.00 0.00< 0.50 = 1.:0 = 0.00 = 0.00 = 2.50 > 0.00 0.80 0.00 0.00 0.00

    1.00 = 1.:0 = 0.00 = 0.00 = 2.50 > 0.00 -0.90 0.00 0.00 0.00e 1.00 = 1.:0 = 0.00 = 0.00 = 2.50 > 0.00 0.90 0.00 0.00 0.00

    2. S ; A6 & 8 &

    1 1.00 = 2.10 = 0.25 = 0.00 = 2.50 > 0.00 0.00 0.00 0.00 0.001 1.00 = 2.10 = 0.25 = 0.00 = 2.50 > 0.00 0.00 0.00 0.00 0.00

    . T 7 U4 =

    1 1.00 = 1.:0 = -0.50 = #DI 0, = 1.70 > #DI 0, 0.00 #DI 0, #DI 0, #DI 0,

    Σ #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    h >

    h5 >

    h8 >

    h7 >h: >

    h9 >hs >Do >

    1 >

    2 >

    <

    o >

    Do >

    Σ& ΣMa

    2

    h

    h5

    h8

    h7

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    20/105

    . G 48 5s+

    . B86 = d+s 45 8 + B = A& s

    'e an ma i angunan a as B > #DI 0, on

    Momen e/ha ap b c b B > = 0.00 > #DI 0, on.m

    2. B86 H+d ; d8 = K8 & : > #DI 0, on &a6a e/ ikal = 'M > #DI 0, = 100G > #DI 0, on

    Momen e/ha ap b c b B > p = 0.00 > #DI 0, on.m

    6. B86 P8 = 4 7 G8 ;

    > 0.15

    > 0.15 = #DI 0, > #DI 0, on M' 8 d+ &+&+5 O : = > #DI 0, = #DI 0, > #DI 0, on.m

    > 0.15 = #DI 0, > #DI 0, on M' 8 d+ &+&+5 O : = e > #DI 0, on.m

    > 0.15 = #DI 0, > #DI 0, on

    M' 8 d+ &+&+5 O : = > #DI 0, = #DI 0, > #DI 0, on.m= > #DI 0, = #DI 0, > #DI 0, on.m

    oeFisien /em 0.05> #DI 0, on

    M' 8 d+ &+&+5 O : #DI 0, on.m

    d. T85 T 7 A5&+ ( T )

    d3. P d K' d+s+ N'4 (T )

    > 0.30:5

    imana B > 30 α > 0> 0 > 10> 1.70

    9 P8 = 4 7 686 7+d ; :> #DI 0,

    9 P8 = 4 7 & 7 85s+&+ = :

    > #DI 0,

    = > #DI 0, on

    > #DI 0, on

    > #DI 0, on

    Ti ik e/a ------\ > = > #DI 0, me e/

    > > #DI 0, me e/

    M' 8 d+ &+&+5 O : > = > #DI 0, on.me e/ > = > #DI 0, on.me e/

    3. B86 M &+ ( M; )

    Mp > H = = ' 2

    M= Mp

    V; > H F K > p. '. 2 V; > H F K

    M=

    oeFisien &empa kh 63. D 4+ B = B 7 (G7 6) :

    G7 63 > kh = ΣMaM 1 > &h 1

    62. D 4+ B = A& s (G7 ; ) :

    G7 ; > kh = MpM &hp > &hp

    6 . D 4+ B = S 4 (G7 s ) :

    G7 s > kh = &s

    M &hp > &hs 65M &hp > &hp =5

    1. G R8 (R ) F / >

    R > F / = pM6 m > (1;: " ). m >

    ! >sin(φ δ) . sin(φ - α ) ( 0;8 h3 ) . γ . ! on m2

    a2 > a1 γ . . ! on m2

    h = '

    Tah > Ta1 . Ta . sin ( δ + τ )

    6Ta

    a 1 2

    M=Ta Ta1 =Ta1 M6Ta Ta1h 6Ta1

    1 2

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    21/105

    P d S 4 5' d+s+ '4 :

    imana B> - Q > -

    > - > 1.0000

    > 0.00

    > #DI 0,

    > #DI 0, on

    > #DI 0, on> #DI 0, on

    Tinggi sumu/an B > - m

    Ti i > = > #DI 0, me /e

    > > #DI 0, m

    M' 8 d+ &+&+5 O :> = > #DI 0, .m> = > #DI 0, .m

    1.0000

    > 0.00 α > -> -:.53 > -

    τ > - > 0.15> - > :.53

    > #DI 0, me e/ > #DI 0,> #DI 0, on> #DI 0, on

    i ik e/a ------ > > #DI 0, me e/

    > > #DI 0, me e/ M' 8 d+ &+&+5 O :

    > = > #DI 0, on.m> = > #DI 0, on.m

    P d S 4 K' d+s+ G8 ; : imana B - - 1.0000

    (:.53) 0.00 -> #DI 0,> #DI 0, on> #DI 0, on> #DI 0, on

    > > #DI 0, m Ti ik e/a ------\

    > > #DI 0, m

    > = > #DI 0, .m

    φs o δs > φs 3 o

    τs o !sγ s ons m3

    a3 > a2 γ s . hs . !s on m2

    Ta3 > a3 . hs . DoTa3h > Ta3 . Ta3 . sin ( δs + τs )

    hs

    6Ta3

    =Ta3 Do 2

    M6Ta3 Ta3h s - 6Ta2 M=Ta3 Ta3 =Ta2

    d2. P d K' d+s+ G8 ; (G7 T )

    !E > sinφ . sin(φ - α −φο) an-1 kh (1-k)N o

    h4 > h3 a;g > ( h3 h ).γ . !E on m2

    Ta;gh > 0;5 . a1;g . h . o τs > o !Es >φgs > φσ − φο = o γ s > on m3 δs > o

    a;gs > a;g γ s . hs . !s on m2Ta;gs > a;gs . hs . DoTa

    h;gs > Ta

    ;gs . Ta;gs . sin( δs + τs )

    6Ta;gs hs 3

    =Ta;gs Do 2

    M6Ta;gs Tah;gs (hs - 6Ta;gs)

    a3 2.( a1 a2)Na1 a2 a3

    hs 3

    1 2

    a;g 2. a;gsa;g a;gs

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    22/105

    - Diame e/ sumu/an ihi ung e/ asa/kan alanalisa keseim angan s a ik sepe/ i i a4ah ini B

    V F Gs 9 R 9 Rs > 0

    imana B

    > &a6a e/ ikal a/i e an s /uk u/ angunan

    engan /umus !'O; maka B

    *umlah sumu/an se iap umpuan n > 2.00 uah#DI 0, on

    - #DI 0, - Q 0.00

    2.50 0.00 me e/ Di apa B #DI 0, mKak o/ eamanan 1.20 #DIV/0! m

    > #DI 0, me e/ Diam il B ### m

    > #DI 0, me e/ a au > ### - m Q 0.00 φS > Eag > a1;g ags > on m2

    µ > Tg(φs) > ? all > on m2γ < > on m3 hs >

    D7+& >Kk > Q Do > Dhi . Kk >

    - E "IT%$&!$ TE'! DI$DI$& S%M% !$ ( so )

    so1 > 0;10 0;20 = Do s ' >

    so2 > 0;15 Do 8

    - E "IT%$&!$ TE'! ! I S%M% !$ ( o )

    A > π.Do3 32 > m3

    ! o > 0;25.π.Do2 > m2

    > Do - 2.So > !

    o > 0;25.

    π.D

    o

    2 >m

    2

    1. 'e/a in ing sumu/an B 0;25.π.(Do2 - 2).hs.γ <2. 'e/a pengisi e on γ sγ <

    'e on

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    23/105

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    24/105

    @. REAKSI TANAH DASAR DI BA$AH SUMURAN (KONTROL AMBLAS)

    -

    imana B

    ? > In ensi as /eaksi anah asa/ > &a6a e/ ikal

    #DI 0,m

    #DI 0,n > *umlah sumu/an pa a se iap pangkal jem a an n > 2.00 uah

    NO. KOMBINASI PEMBEBANAN

    &' K' &4' !. om inasi I

    M " Ta #DI 0, #DI 0, #DI 0, Q #DI 0,'. om inasi II

    M Ta !h &g ! S Tm #DI 0, #DI 0, #DI 0, Q #DI 0,O. om inasi III

    om .I m &g ! S Tm S #DI 0, #DI 0, #DI 0, Q #DI 0,D. om inasi I

    #DI 0, #DI 0, #DI 0, Q #DI 0,E. om inasi

    M 1 #DI 0, #DI 0, #DI 0, Q #DI 0,K. om inasi I

    M " Ta S T #DI 0, #DI 0, #DI 0, Q #DI 0,

    - > V / A - > on m2

    Do > Diame e/ sumu/an Do > ! o > uas penampang asa/ sumu/an ! o > 0;25.π.Do2 > m2

    VS >(ΣVFGs) / - > Vs / A ' -

    &' / 2

    M &h Tag !h g

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    25/105

    . P8 = P''4 K 5+

    Tegangan i@in aj > 1;:58.00 32ua aja /en 27: .00

    n > 21.00 -

    > :2.50 250

    I@in gese/ pons > 10.2:

    > 1.071 -

    U4 + S &KOMBINASI

    I II III IV V VI

    &a6a in ang > on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,Momen > on.m #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,Tinggi eFek iF > #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    Oa > > (-) #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    LENTUR MURNIV > (-) - - - - - -Y > (-) 0.1:5 0.1:5 0.208 0.3:9 0.180 0.1:5

    6 > Y.h > (-) #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> (-) #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    @ > Z.h> (-) . 1 . 1 3.:5 1.57 5.25 . 1> (-) #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> (-) #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> #DIV/0! #DIV/0! #DIV/0! #DIV/0! #DIV/0! #DIV/0!> #DIV/0! #DIV/0! #DIV/0! #DIV/0! #DIV/0! #DIV/0!

    on /ol &ese/ ons #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,#DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    P8 = P''4 K 5+

    9 T 4+5 #DIV/0! #DIV/0!> mm #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    *umlah > uah #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,uas ! > #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    9 T85 #DIV/0! #DIV/0!> mm #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    *umlah > uah #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,uas ! > #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    9 T = S8 =5 = #DIV/0! 9 2> mm #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,*umlah > uah #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    > #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    σ a kg h8 h5 2

    > h - ! min> (12 σ[au) = = h

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    26/105

    PEMERINTAH PROVINSI JAWA BARAT

    DINAS BINA MARGASUB DINAS BINA TEKNIK

    NAMA JEMBATAN : 0

    PROGRAM PENAGANAN : PEMBANGUNAN JEMBATAN / PENGGANTIAN JEMBATAN

    LOKASI JEMBATAN PADA RUAS JALAN : 0

    STA. / KM : 0STATUS / "UNGSI JALAN : PROVINSI / KOLEKTOR

    KABUPATEN : 0

    NAMA DAN $ILA AH BPJ : 0

    TANGANGAL PERENCANAAN : MEI 2030

    PERHITUNGAN STRUKTUR JEMBATAN

    A. PERENCANAAN BANGUNAN ATAS

    3. DATA TEKNIS DAN DIMENSI

    . D & K' s&4 5s+ - Tipe ons /uksi 'angnan ! as : *em a an ela 'e on engkung a/a ola

    - Tipe on asi : Sumu/an → #DI 0, me e/ - Tipe Mua an 'e an : 'M 100

    - 'en ang : - me e/ " : - me e/

    - e a/ jem a an ' : 1.00 me e/ - e a/ *alu/ en a/aan : - me e/ - e a/ T/o oa/ 4 : - me e/

    6. D & T 7

    ke e/angan anah ke/as u/ugan

    - 'e/a jenis anah : - 1.70 - Su u gese/ anah : - 30.00 - Da6a ukung anah 0.00 0.00

    1. D & M &84+ a. Mu u 'e on

    a/ak e/. Tekan Ta/ik &ese/- ela engkung - : 350 118 9 :.0

    - Din ing Samping en6eka -: 250 :3 : 8.:- T/o oa/ - : 250 :3 : 8.:- 'e/a *enis 'e on 'e/ ulang : 2.50- 'e/a *enis 'e on Tum uk : 2.20

    . Mu u 'aja Tulangan % - : 3;200 0.20 m Tinggi lapis pon asi jalan > 0.50 m Tinggi anah u/ug > - m Tinggi usu/ ( lengkungan ) ( F ) > - m Te al pela usu/ > #DI 0, m Tinggi in ing iang (kaki) > #DI 0, m

    Te al /o oa/ > 0.25 m Te al in ing samping > 0.25 m Te al pela iang ( kaki ) > #DI 0, m

    Dia. >

    - Tinggi (lihat gambar dibawah )

    γ m3o

    ? all m2

    Tegangan I@in 'e on (kg

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    27/105

    2. SISTEM STATIKA DAN PERHITUNGAN BEBAN

    !sumsi se agai jem a an lengkung pa a 3 ( iga) s a is e/ en u 6ang ke ua umpuann6a engan sis em jepi2a. Dimensi Teo/i is B

    'en ang engkung C > > #DI 0, m anjang engkung > > #DI 0, m Tinggi engkung F > > #DI 0, m Tinggi kons /uksi " > > #DI 0, m

    2 . e/hi ungan 'e an B 1. 'e an Ma i

    > -> -> -

    ela 'usu/ > #DI 0,ela T/o oa/ e/ > 0.2:

    > #DI 0,

    Din ing samping > #DI 0, onDin ing pen6eka 2;5 . > - onSan a/an 1;2 . > - on

    > #DI 0, on> #DI 0,> #DI 0,> #DI 0, on m

    2. 'e an "i upe a/ lalu lin as ken a/aan > 2.75 m

    'e an hi up e/pusa T > 10.00 onoeFisien keju > #DI 0,

    'e an hi up engan koeFisien keju> = 100G > #DI 0, on m

    m > > #DI 0, mp > > #DI 0,

    3. 'e an Ma i "i upg > H p > #DI 0,

    . Tekanan Tanah !k i

    > > 0.30:5

    > 30 α > 0> 0 > 10> 1.70

    > #DI 0,> #DI 0,

    - TplJ EK Ud1 ( F C - :F C2.=)2

    F Tpl 2 h

    e/ke/asan jalan 1 > γ p . h1 . ' on m2

    apis on asi *alan 2 > γ a . h2 . ' on m2Ma e/ial %/ugan 3 > γ . h3 F N⅙ on m2

    1 > γ < .Tpl . J EK C on m2 2 > γ . / . 2(4 0;25) ' on m2

    H1 on m2

    3 > 2. . " - 5 8 .F . N.T4.γ < >

    5 >

    3 5H2 > ( 3 5 ) (C .') on m2

    H > H1 H2 on m2Din ing kaki 8 > h . 1 . γ <

    Ck

    > 20 (50 C)

    T ( 2T Ck ) . (1 )2 (h

    1 h

    2 h

    3 0;5.T

    pl) 0;5

    T m on m2

    on m2

    !

    sin(φ δ) . sin(φ - α ) ( 0;8 h3 ) .γ . ! on m2 a2 > a1 γ . . ! on m2

    g

    O DC

    h

    E K a1a1

    a2a2

    1 2

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    28/105

    . ANALISA MEKANIKA DENGAN CARA KERJA VIRTUAL DENGAN ELASTISITAS KONTRUKSI

    a. Momen Ine/sia#DI 0,

    #DI 0,

    #DI 0, ( - )

    e/samaan ga/is lengkung pa/a ola B

    #DI 0, P Q #DI 0,#DI 0,

    > #DI 0, on m> #DI 0, on m

    > #DI 0, on.m m

    > #DI 0, on m> #DI 0, on m> #DI 0, on.m m> #DI 0, on.m m

    #DI 0, m#DI 0, m#DI 0, m#DI 0, m

    #DI 0, m#DI 0, m#DI 0, m#DI 0, m

    F. Menen ukan ja/ak i ik e/a elas is kons /uksi ( e )

    #DI 0, m> #DI 0, m

    ela engkung BΙpl > 10.Tpl 12 > m

    ela aki BΙ > 10. 1 12 > m

    k > Ι Ιpl >

    Su u ga/is usu/ pa a se iap i ik B

    6 > F C2 (C-=)= > F C .= - F C2.=2

    6 > F C - :F C2.= > a/< g(6 ) > a/< g( F C - :F C2.=)

    un uk = > 0 Q > sin ( ) >

    .1 Momen p/ime/ M0 aki a e an e an ma i hi up ( g )

    O0g > g . C 2 8E0g > g . C 2

    M0g > - R g . C2

    .2 Momen p/ime/ M0 a aki a e an ekanan anah ak i" O0 a > h⅙ ( a1 2 a2)" E0 a > h⅙ (2 a1 a2)ME0 a > - ⅙( a2- a1) R a1N.h2

    MO0 a > - ( a2- a1) R a1N.h2

    - e > M1pl( ) > -e >

    ila/ po/ al B M1 (-) > - e > M1 ( ) > e >

    . 'esa/an s a ik aki a ga6a i/ ual 2 > 1a ang eng ung B 1pl(-) > - >

    M1pl( ) > C 2 >ila/ po/ al B M1 (-)> - C 2 >

    M1 ( ) > C 2 >

    e. 'esa/an s a ik aki a i/ ual 3 > 1'a ang lengkung B M1pl(-) > 1

    1pl( ) >ila/ po/ al M1 (-)> 1

    M1 ( ) > 1

    EΙ . δ 13 = U M1 . M 3 . dx = 0 , maka engan a uan a el hasil in eg/al i apa B pa a a ang lengkung po/ al B EΙpl . V13 > U M1pl . M3pl . = > W . C - e.C

    pa a pila/ po/ al B EΙ . V13 > M1 . M3 . = > - h2

    V13 > U M1 . M3 . = > C ( W - e )Ιpl - h 2 Ι > 0C ( W - e )Ι Ιpl - h 2 > 0C (2 - 3e ).k - 3h 2 > 02k.C. - 3k.C.e - 3h2 > 03k.C.e > 2k.C. - 3h2 e > ( 2k.C.F - 3h2 ) ( 3k.C ) >e > h e

    e

    2

    13

    -

    1) 'i ang-M0 aki a e an g

    ) 'i ang-M2 aki a 2 > 1

    e

    Ti ik e/a elas iskons /uksi

    1

    C 3 2

    C 3 2

    1

    C

    e > ja/ak i ik e/a elas is kons /uksi

    - -

    -

    M0g M

    0 g

    M 0 g

    e

    -

    C 2

    C 2

    --

    e

    ee

    1

    1 1

    Ι Ι

    ΙplΙpl

    --$ 1pl > 1

    $ 1 > 0? 1pl > 0

    ? 1 > -1

    $ 2pl > 0? 2pl > 1$ 2 > 1? 2 > 0

    ? 3 > 0$ 3 > 0? 3pl > 0$ 3pl > 0

    E K

    O D

    9

    9

    99

    9

    2) 'i ang-M0 aki a e an g

    9ME0 a

    MO0 a

    ME0 a

    M

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    29/105

    M0g

    -

    e

    E0 a

    O0 a

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    30/105

    > #DI 0,

    > #DI 0,

    > #DI 0,

    > #DI 0,

    > #DI 0, m

    . N+ + A57+4 M 5s+ B8s 4 S& &+5

    a. !ki a 'e an Ma i an "i up ( g )

    > #DI 0,> #DI 0,

    > #DI 0,

    > 0.00> 0.00> 0.00

    > #DI 0,> #DI 0,> #DI 0,

    e/ en u menja i B> #DI 0, on m

    > #DI 0,

    > #DI 0, on.m m

    Momen BTi ik Simpul E > #DI 0, on.m m

    Tumpuan O > #DI 0, on.m mela engkung C 2 > #DI 0, on.m m

    &a6a $o/malTi ik Simpul E B'a ang EK > #DI 0, on m'a ang EO > #DI 0, on m

    > #DI 0, on m

    Tumpuan O > #DI 0, on mela engkung > #DI 0, on m

    &a6a in angTi ik Simpul E B'a ang EK > #DI 0, on m'a ang EO > #DI 0, on m

    > #DI 0, on m

    g. $ilai pe/u ahan en uk aki a M1 B

    EΙpl . V11pl > U M1pl . M1pl . = > C.k e2 - 2 . W .e . : 15 2 N m3

    EΙ . V11 > U M1 . M1 . = > W h e2 - e .e e2 N m3

    EΙ . V11 > U M1 . M1 . = m3

    h. $ilai pe/u ahan en uk aki a M2 B

    EΙ . V22 > U M2 . M2 . = > k.C.(XC)2 X h .C2 m3

    i. $ilai pe/u ahan en uk aki a M3 B

    EΙ . V33 > U M3 . M3 . = > C 2k.h

    1. $ilai pe/u ahan en uk aki a M0g an M1 B EΙpl . V10gpl > U M1pl . M0gpl . = > C . k .M0gpl . M1pl(-) 2 15 C .k .M0gpl . F on.m3

    EΙ . V10g > U M1 . M0g . = > X h . M0g . ( e - e ) on.m3

    EΙ . V10g > U M1 . M0g . = on.m3

    2. $ilai pe/u ahan en uk aki a M0g an M2 B EΙpl . V20gpl > U M2pl . M0gpl . = >⅟ 12 C.k.M0g ( XC - XC ) on.m3

    EΙ . V20g > U M2 . M0 . = > X h . M0g .( e - e ) h.M0g.(XC) - h.M0g.(XC) on.m3

    EΙ . V10g > U M1 . M0g . = on.m3

    3. $ilai pe/u ahan en uk aki a M0g an M3 B EΙpl . V30gpl > U M3pl . M0gpl . = > C.k.M0g on.m3 EΙ . V30g > U M3 . M0g . = > 2 h . M0g on.m3

    EΙ . V30g > U M3 . M0g . = on.m3

    a/ena i ang momen M2 e/ en uk an ime /is; se angkan i ang 6ang lainn6a sime /is maka pe/samaan s a is i ak

    1g > - V10g V11

    2g > - V20g V22

    3g > - V30g V33

    B M > M0 M1. 1 M2 . 2 M3 . 3B MEg > MO0g M1 (-) . 1g M2 (-) . 2g M3 ( ) . 3gB MOg > MO0g M1 (-) . 1g M2 ( ) . 2g M3 ( ) . 3gB MOgpl > 0 M1pl( ) . 1g M2pl ( ) . 2g M3pl( ) . 3g

    B $ > $0 $1. 1 $2 . 2 $3 . 3

    B $EKg > - E0g . Sin( ) $1pl . 1g . Oos( )B $EKg > E0g $1 . 1g

    $ Eg

    B $Og > - O0g $1 . 1gB $gpl > $1pl. 1g

    B ? > ?0 ? 1. 1 ? 2 . 2 ? 3 . 3

    B ?EKg > E0g .Oos( ) ?1pl. 1g .Sin( )B ?EOg > - ? 1 . 1g

    ? Eg

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    31/105

    . !ki a Tekanan Tanah !k i ( a )

    > #DI 0,> #DI 0,

    > #DI 0,

    > -> -> -

    > #DI 0,

    e/ en u menja i B> #DI 0, on m

    > #DI 0,

    > #DI 0, on.m m

    Momen BTi ik Simpul E > #DI 0, on.m mTumpuan O > #DI 0, on.m m

    ela engkung C 2 > #DI 0, on.m m

    &a6a $o/malTi ik Simpul E B'a ang EK > #DI 0, on m'a ang EO > #DI 0, on m

    > #DI 0, on mTumpuan O > #DI 0, on m

    ela engkung > #DI 0, on m

    &a6a in angTi ik Simpul E B

    'a ang EK > #DI 0, on m'a ang EO > #DI 0, on m

    > #DI 0, on mTumpuan O > #DI 0, on m

    ela engkung > #DI 0, on m

    R85 ;+& s+ :Momen BTi ik Simpul E > #DI 0, on mTumpuan O > #DI 0, on m

    ela engkung C 2 > #DI 0, on m

    &a6a $o/malTi ik Simpul E > #DI 0,on mTumpuan O > #DI 0, on m

    ela engkung > #DI 0,on m

    &a6a in angTi ik Simpul E > #DI 0, on m

    1. $ilai pe/u ahan en uk aki a M0 a an M1 B

    EΙpl . V10 apl > U M1pl . M0 apl . = > C . k .M0 apl . M1pl(-) C .k .M0 apl . on.m3

    EΙ . V10 a > U M1 . M0 a . = >1 12 C.(MO0 a ME0 a) ( e - e ) on.m3

    EΙ . V10 a > U M1 . M0 a . = on.m3

    2. $ilai pe/u ahan en uk aki a M0 a an M2 B

    EΙpl . V20 apl > U M2pl . M0 apl . = > on.m3

    EΙ . V20 a > U M2 . M0 a . = > on.m3

    EΙ . V10 a > U M1 . M0 a . = on.m3

    3. $ilai pe/u ahan en uk aki a M0 a an M3 B

    EΙpl . V30 apl > U M3pl . M0 apl . = > C .k.ME0 a ⅙ h . (MO0 a ME0 a) on.m3

    a/ena i ang momen M2 e/ en uk an ime /is; se angkan i ang 6ang lainn6a sime /is maka pe/samaan s a is i ak

    1 a > - V10 a V11

    2 a > - V20 a V22

    3 a > - V30 a V33

    B M > M0 M1. 1 M2 . 2 M3 . 3B ME a > MO0 a M1 (-) . 1 a M2 (-) . 2 a M3 ( ) . 3 aB MO a > MO0 a M1 (-) . 1 a M2 ( ) . 2 a M3 ( ) . 3 aB MO apl > 0 M1pl( ) . 1 a M2pl( ) . 2 a M3pl( ) . 3 a

    B $ > $0 $1. 1 $2 . 2 $3 . 3

    B $E a > " E0 a . Sin( ) $1pl . 1 a. Oos( )B $EK a > " E0 a $1 . 1 a

    $ E aB $O a > $1 . 1 aB $apl > $ 1pl. 1 a

    B ? > ?0 ? 1. 1 ? 2 . 2 ? 3 . 3

    B ?E a > " E0 a . Oos( ) ?1pl. 1 a. Sin( )B ?EO a > - ? 1 . 1 a

    ? E aB ?O a > " O0 a- ? 1 . 1 aB ? apl > 0 ? 1pl . 1 a

    B ME > MEg ME aB MO > MOg MO aB Mpl > Mgpl M apl

    B $E > $Eg $E aB $O > $Og $O aB $pl > $gpl $ apl

    B ?E > ? Eg ? E a

    ka/ena sime /is an an ime /is

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    32/105

    1;:58.00 % - 32

    > 2;7: .00

    n > 1:.00 -

    > 115.50 - 350

    > :.0

    > 0.:93 -

    U4 + S & HASIL

    Momen M on.m m #DI 0,&a6a $o/mal $ on m #DI 0,&a6a in ang ? on m #DI 0,

    > #DI 0,> #DI 0,> ( - ) #DI 0,> ( - ) #DI 0,> on. Tulangan Sime /is

    > (-) 0.:75#DI 0, > (-) #DI 0,

    Y > (-) 0. 07> (-) #DI 0,

    @ > Z.h > Y.h > (-) 1. 8> (-) #DI 0,> (-) #DI 0,

    #DI 0, > (-) #DI 0,> #DI 0,> #DIV/0!> #DIV/0!> #DI 0,

    on /ol &ese/ > #DI 0,> #DI 0,

    σ a kg (12 σ[au) . . h (15 σ[au) .h .103 M $

    2 \ e o2 > h 30eo > eo1 eo2

    eo han eo h >\ O

    k > 0;7.Ce1 > O.( k 100.h)2.h

    e2 > 0;15.he > eo e1 e2

    ea > e 0;5.h - $.e a

    Oa > > ] 1 (n.^.Z) _Xn.$.e a.̀ a

    ξ >7 :

    nω = ½ε 2/{d'/h.δ + 1 - ε(δ + 1)}

    φ > (1-ε) ε φ > (1-ε) (ε - h)

    ω = nω/n

    i.! > ω. .h +.A/+ δ .+A 20G . ! pe/lu ? ( .h.7 :) kg

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    33/105

    @. P847+& = P8 68s+ P8 & D+ d+ = K 5+

    #DIV/0!

    > 1;:58.00 % - 32

    > 2;7: .00

    n > 1:.00 -

    > 115.50 - 350

    > :.0

    > 0.:93 -

    U4 + S & HASIL

    Momen M > on.m m #DI 0,&a6a $o/mal $ > on m #DI 0,&a6a in ang ? > on m #DI 0,

    > #DI 0,> #DI 0,> ( - ) #DI 0,> ( - ) #DI 0,> on. Tulangan Sime /is

    > (-) 0.:75#DI 0, > (-) #DI 0,

    Y > (-) 0.39:> (-) #DI 0,

    @ > Z.h> Y.h > (-) 1.51> (-) #DI 0,> (-) #DI 0,

    #DI 0, > (-) #DI 0,> #DI 0,> #DIV/0!> #DIV/0!> #DI 0,

    on /ol &ese/ > #DI 0,> #DI 0,

    σ a kg (12 σ[au) . . h (15 σ[au) .h .103 M $

    2 \ e o2 > h 30eo > eo1 eo2

    eo han eo h >\ O

    k > 0;7.he1 > O.( k 100.h)2.h

    e2 > 0;15.he > eo e1 e2

    ea > e 0;5.h - $.e a

    Oa > > ] 1 (n.^.Z) _Xn.$.e a.̀ a

    ξ >7 :

    nω = ½ε 2/{d'/h.δ + 1 - ε(δ + 1)}

    φ > (1-ε) ε φ > (1-ε) (ε - h)

    ω = nω/n

    i.! > ω. .h +.A/+ δ .+A 20G . ! pe/lu ? ( .h.7 :) kg

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    34/105

    P8 68s+ P8 & L8 =5 = ( B s 4 )

    9 T 4+5 φ #DIV/0! #DIV/0!

    > mm #DI 0,

    *a/ak a > #DI 0,

    Tulangan em agi B φ #DIV/0! #DIV/0!

    > mm #DI 0,*a/ak a > #DI 0,

    9 T85 φ #DIV/0! #DIV/0!

    > mm #DI 0,*a/ak a > #DI 0,Tulangan em agi B φ #DIV/0! #DIV/0!

    > mm #DI 0,*a/ak a > #DI 0,

    #DIV/0!

    P8 68s+ P8 & D+ d+ = K 5+

    9 T 4+5 φ #DIV/0! #DIV/0!> mm #DI 0,

    *a/ak a > #DI 0,

    Tulangan em agi B φ #DIV/0! #DIV/0!> mm #DI 0,

    *a/ak a > #DI 0,

    9 T85 φ #DIV/0! #DIV/0!> mm #DI 0,

    *a/ak a > #DI 0,

    Tulangan em agi B φ #DIV/0! #DIV/0!> mm #DI 0,

    *a/ak a > #DI 0,

    Dia. φ

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    35/105

    B. PERENCANAAN BANGUNAN BA$AH

    3. P847+& = B86 M &+ B = B 7

    #DI 0, m

    - m

    - m

    - m - m

    - m - m

    #DI 0, m

    1.:0 m 0.:0 m#DI 0, m#DI 0, m

    #DI 0, m

    #DI 0, m

    ' > 1.00 m

    u > #DI 0, m

    N'. BERAT ( T' )TERHADAP TITIK O

    ( ) ( ) G (&. ) G (&. )

    3. B d K 5+a 1.00 = 0.00 = 1.00 = #DI 0, = 2.50 > #DI 0, 0.00 #DI 0, #DI 0, #DI 0,

    0.50 = 1.:0 = 1.00 = 0.00 = 2.50 > 0.00 -0.80 0.00 0.00 0.00< 0.50 = 1.:0 = 1.00 = 0.00 = 2.50 > 0.00 0.80 0.00 0.00 0.00

    1.00 = 1.:0 = 1.00 = 0.00 = 2.50 > 0.00 -0.90 0.00 0.00 0.00e 1.00 = 1.:0 = 1.00 = 0.00 = 2.50 > 0.00 0.90 0.00 0.00 0.00

    2. S ; A6 & 8 &

    1 1.00 = 0.00 = 0.25 = 0.00 = 2.50 > 0.00 0.00 0.00 0.00 0.001 1.00 = 0.00 = 0.25 = 0.00 = 2.50 > 0.00 0.00 0.00 0.00 0.00

    . T 7 U4 =

    1 1.00 = 1.:0 = 0.50 = #DI 0, = 1.70 > #DI 0, 0.00 #DI 0, #DI 0, #DI 0,

    Σ #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    h >

    h5 >

    h8 >

    h7 >h: >

    8 >hs >

    1 >

    2 >

    <

    o >

    Do >

    Σ& ΣMa

    2

    h

    h5

    h8

    h7

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    36/105

    2. G 48 5s+

    . B86 = d+s 45 8 + B = A& s

    'e an ma i angunan a as B > #DI 0, on

    Momen e/ha ap b c b B > = 0.00 > #DI 0, on.m

    2. B86 H+d ; d8 = K8 & : > #DI 0, on

    &a6a e/ ikal = 'M > #DI 0, = 100G > #DI 0, on Momen e/ha ap b c b B > p = 0.00 > #DI 0, on.m

    6. B86 P8 = 4 7 G8 ;

    > 0.15

    > 0.15 = #DI 0, > #DI 0, on M' 8 d+ &+&+5 O : = > #DI 0, = #DI 0, > #DI 0, on.m

    > 0.15 = #DI 0, > #DI 0, on M' 8 d+ &+&+5 O : = e > #DI 0, on.m

    > 0.15 = #DI 0, > #DI 0, on

    M' 8 d+ &+&+5 O : = > #DI 0, = #DI 0, > #DI 0, on.m= > #DI 0, = #DI 0, > #DI 0, on.m

    oeFisien /em 0.05#DI 0, on

    M' 8 d+ &+&+5 O : #DI 0, on.m

    d. T85 T 7 A5&+ ( T ) d3. P d K' d+s+ N'4 (T )

    > 0.30:5

    imana B > 30 α > 0> 0 > 10> 1.70

    9 P8 = 4 7 686 7+d ; :> #DI 0,

    9 P8 = 4 7 & 7 85s+&+ = :

    > #DI 0,

    = > #DI 0, on

    > #DI 0, on

    > #DI 0, on

    Ti ik e/a ------\ > = > #DI 0, me e/

    a > > #DI 0, me e/

    M' 8 d+ &+&+5 O : > = > #DI 0, on.me e/ > = > #DI 0, on.me e/

    3. B86 M &+ ( M; )

    Mp > H = = ' 2

    M= Mp V; > H F K > p. '. 2

    V; > H F K M=

    oeFisien &empa kh 63. D 4+ B = B 7 (G7 6) :

    G7 63 > kh = ΣMaM 1 > &h 1

    62. D 4+ B = A& s (G7 ; ) :

    G7 ; > kh = MpM &hp > &hp

    6 . D 4+ B = S 4 (G7 s ) : G7 s > kh = &s

    M &hp > &hs 65M &hp > &hp =5

    1. G R8 (R ) F / >

    R > F / = p >M6 m > (1;: " ). m >

    ! >sin(φ δ) . sin(φ - α ) ( 0;8 h3 ) . γ . ! on m2

    a2 > a1 γ . . ! on m2

    h = '

    Tah > Ta1 . Ta . sin ( δ + τ )

    6Ta

    1 2

    M=Ta Ta1 =Ta1 M6Ta Ta1h 6Ta1

    1 2

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    37/105

    9 P d S 4 5' d+s+ '4 :

    imana B> - Q > -

    > - > 1.0000

    > 0.00

    > #DI 0,

    > #DI 0, on

    > #DI 0, on> #DI 0, on

    Tinggi sumu/an B > - m

    Ti i > = > #DI 0, m

    > > #DI 0, m

    M' 8 d+ &+&+5 O :> = > #DI 0, .m> = > #DI 0, .m

    > > 1.0000

    > 0.00 α > -> -:.53 > -

    τ > - > 0.15> - > :.53

    > #DI 0, me e/ > #DI 0,> #DI 0, on> #DI 0, on

    i ik e/a ------ > > #DI 0, me e/ > > #DI 0, me e/

    M' 8 d+ &+&+5 O :> = > #DI 0, on.m> = > #DI 0, on.m

    9 P d S 4 K' d+s+ G8 ; : imana B - - 1.0000

    (:.53) 0.00 -

    > #DI 0,> #DI 0, on

    > #DI 0, on> #DI 0, on

    Ti ik e/a --- > > #DI 0, m

    > > #DI 0, m

    M' 8 d+ &+&+5 O :

    φs o δs > φs 3 o

    τs o !sγ s ons m3

    a3 > a2 γ s . hs . !s on m2

    Ta3 > a3 . hs . DoTa3h > Ta3 . Ta3 . sin ( δs + τs )

    hs

    6Ta3

    =Ta3 Do 2

    6Ta3 a3h s - 6Ta2 M=Ta3 Ta3 =Ta2

    d2. K' d+s+ G8 ; (G7 T )

    !E

    sinφ . sin(φ - α −φο) an-1 h - o

    h4 > h3 a;g > ( h3 h ).γ . !E on m2

    Ta;gh > 0;5 . a1;g . h . o τs > o !Es >φgs > φσ − φο = o γ s > on m3 δs > o

    a;gs > a;g γ s . hs . !s on m2Ta;gs > a;gs . hs . DoTah;gs > Ta;gs . Ta;gs . sin( δs + τs )

    6Ta;gs hs 3

    =Ta;gs Do 2

    a3 2.( a1 a2)Na1 a2 a3

    hs 3

    1 2

    a;g 2. a;gsa;g a;gs

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    38/105

    Diame e/ sumu/an ihi ung e/ asa/kan alanalisa keseim angan s a ik sepe/ i i a4ah ini B

    V F Gs 9 R 9 Rs > 0

    imana B

    > &a6a e/ ikal a/i e an s /uk u/ angunan

    engan /umus !'O; maka B

    *umlah sumu/an se iap umpuan n > 2.00 uah#DI 0, on

    - #DI 0, - Q 0.00

    2.50 0.00 me e/

    Di apa B #DI 0, m

    Kak o/ eamanan 1.20 #DIV/0! m

    > #DI 0, me e/ Diam il B ### m> #DI 0, me e/ a au > ### - m Q 0.00 φS > Eag > a1;g ags > on m2

    µ > Tg(φs) > ? all > on m2γ < > on m3 hs >

    D7+& >

    Kk > Q Do > Dhi . Kk >

    - E "IT%$&!$ TE'! DI$DI$& S%M% !$ ( so )

    so1 > 0;10 0;20 = Do s ' >so2 > 0;15 Do 8

    - E "IT%$&!$ TE'! ! I S%M% !$ ( o )

    A > π.Do3 32 > m3

    ! o > 0;25.π.Do2 > m2

    > Do - 2.So > ! o > 0;25.π.Do2 > m2

    1. 'e/a in ing sumu/an B 0;25.π.(Do2 - 2).hs.γ <2. 'e/a pengisi e on γ sγ <

    'e on

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    39/105

    . R85 ;+& s+ R8 5s+ G

    NO. JENIS BEBAN GA A MOMEN DI TITIK O

    V H M M

    &' &' &' . &' .

    I 'E'!$ M!TI ( M ) Ba. 'angunan 'a4ah ( Ma ) #DI 0, - #DI 0, -

    - - - -

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    40/105

    < REAKSI TANAH DASAR DI BA$AH SUMURAN (KONTROL AMBLAS)

    -

    imana B

    ? > In ensi as /eaksi anah asa/ > &a6a e/ ikal

    #DI 0,m

    #DI 0,n > *umlah sumu/an pa a se iap pangkal jem a an n > 2.00 uah

    NO. KOMBINASI PEMBEBANAN

    &' K' &4' !. om inasi I

    M " Ta #DI 0, #DI 0, #DI 0, Q #DI 0,'. om inasi II

    M Ta !h &g ! S Tm #DI 0, #DI 0, #DI 0, Q #DI 0,O. om inasi III

    om .I m &g ! S Tm S #DI 0, #DI 0, #DI 0, Q #DI 0,D. om inasi I

    #DI 0, #DI 0, #DI 0, Q #DI 0,E. om inasi

    M 1 #DI 0, #DI 0, #DI 0, Q #DI 0,K. om inasi I

    M " Ta S T #DI 0, #DI 0, #DI 0, Q #DI 0,

    - > V / A - > on m2

    Do > Diame e/ sumu/an Do > ! o > uas penampang asa/ sumu/an ! o > 0;25.π.Do2 > m2

    VS >ΣV / - > Vs / A ' -

    &' / 2

    M &h Tag !h g

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    41/105

    @. P8 = P''4 K 5+

    Tegangan i@in aj > 1;:58.00 32ua aja /en 27: .00

    n > 21.00 -

    > :2.50 250

    I@in gese/ pons > 10.2:

    > 1.071 -

    U4 + S &KOMBINASI

    I II III IV V VI

    &a6a in ang > on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,Momen > on.m #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,Tinggi eFek iF > #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    Oa > > (-) #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    LENTUR MURNIV > (-) - - - - - -Y > (-) 0.19 0.19 0.21 0.39 0.17 0.19

    6 > Y.h > (-) #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> (-) #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    @ > Z.h> (-) . 1 . 1 3.:5 1.57 .:: . 1> (-) #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> (-) #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> #DIV/0! #DIV/0! #DIV/0! #DIV/0! #DIV/0! #DIV/0!> #DIV/0! #DIV/0! #DIV/0! #DIV/0! #DIV/0! #DIV/0!

    #DIV/0! #DIV/0! #DIV/0! #DIV/0! #DIV/0! #DIV/0!on /ol &ese/ ons #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    P8 = P''4 K 5+

    9 T 4+5 #DIV/0! #DIV/0!

    > mm #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,*umlah > uah #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    uas ! > #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    9 T85 #DIV/0! #DIV/0!

    > mm #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,*umlah > uah #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    uas ! > #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    9 T = S8 =5 = #DIV/0! 9 2

    > mm #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    *umlah > uah m .00 .00 .00 .00 .00 .00> #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    σ a kg h8 h5 2

    > 2 2 1

    h > h - ! min> (12 σ[au) = = h

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    42/105

    PEMERINTAH PROVINSI JAWA BARAT

    DINAS BINA MARGASUB DINAS BINA TEKNIK

    NAMA JEMBATAN : 0

    PROGRAM PENAGANAN : PEMBANGUNAN JEMBATAN / PENGGANTIAN JEMBATAN

    LOKASI JEMBATAN PADA RUAS JALAN : 0

    STA. / KM : 0STATUS / "UNGSI JALAN : PROVINSI / KOLEKTOR

    KABUPATEN : 0

    NAMA DAN $ILA AH BPJ : 0

    TANGANGAL PERENCANAAN : MEI 2030

    PERHITUNGAN STRUKTUR JEMBATAN

    A. PERENCANAAN BANGUNAN ATAS

    3. DATA TEKNIS DAN DIMENSI

    . D & K' s&4 5s+ - Tipe ons /uksi 'angnan ! as : *em a an ela 'e on engkung a/a ola

    - Tipe on asi : Tiang an 0.50 m Tinggi anah u/ug > - m Tinggi usu/ ( lengkungan ) ( F ) > - m Te al pela usu/ > #DI 0, m Tinggi in ing iang (kaki) > #DI 0, m

    Te al /o oa/ > 0.25 m Te al in ing samping > 0.25 m Te al pela iang ( kaki ) > #DI 0, m

    Dia. >

    - Tinggi (lihat gambar dibawah )

    γ m3o

    ? all m2

    Tegangan I@in 'e on (kg

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    43/105

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    44/105

    2. SISTEM STATIKA DAN PERHITUNGAN BEBAN

    !sumsi se agai jem a an lengkung pa a 3 ( iga) s a is e/ en u 6ang ke ua umpuann6a engan sis em jepi2a. Dimensi Teo/i is B

    'en ang engkung C > > #DI 0, m anjang engkung > > #DI 0, m Tinggi engkung F > > #DI 0, m Tinggi kons /uksi " > > #DI 0, m

    2 . e/hi ungan 'e an B 1. 'e an Ma i

    > -> -> -

    ela 'usu/ > #DI 0,ela T/o oa/ e/ > 0.2:

    > #DI 0,

    Din ing samping > #DI 0, onDin ing pen6eka 2;5 . > - onSan a/an 1;2 . > - on

    > #DI 0, on> #DI 0,> #DI 0,> #DI 0, on m

    2. 'e an "i upe a/ lalu lin as ken a/aan > 2.75 m

    'e an hi up e/pusa T > 10.00 onoeFisien keju > #DI 0,

    'e an hi up engan koeFisien keju> = 100G > #DI 0, on m

    m > > #DI 0, mp > > #DI 0,

    3. 'e an Ma i "i upg > H p > #DI 0,

    . Tekanan Tanah !k i

    > > 0.30:5

    > 30α

    > 0> 0 > 10> 1.70

    > #DI 0,> #DI 0,

    - TplJ EK Ud1 ( F C - :F C2.=)2

    F Tpl 2 h

    e/ke/asan jalan 1 > γ p . h1 . ' on m2

    apis on asi *alan 2 > γ a . h2 . ' on m2Ma e/ial %/ugan 3 > γ . h3 F N⅙ on m2

    1 > γ < .Tpl . J EK C on m2 2 > γ . / . 2(4 0;25) ' on m2

    H1 on m2

    3 > 2. . " - 5 8 .F . N.T4.γ < >

    5 >

    3 5H2 > ( 3 5 ) (C .') on m2

    H > H1 H2 on m2Din ing kaki 8 > h . 1 . γ <

    Ck

    > 20 (50 C)

    T ( 2T Ck ) . (1 )2 (h

    1 h

    2 h

    3 0;5.T

    pl) 0;5

    T m on m2

    on m2

    !

    sin(φ δ) . sin(φ - α ) ( 0;8 h3 ) .γ . ! on m2 a2 > a1 γ . . ! on m2

    g

    O DC

    h

    E K a1a1

    a2a2

    1 2

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    45/105

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    46/105

    . ANALISA MEKANIKA DENGAN CARA KERJA VIRTUAL DENGAN ELASTISITAS KONTRUKSI

    a. Momen Ine/sia#DI 0,

    #DI 0,

    #DI 0, ( - )

    e/samaan ga/is lengkung pa/a ola B

    #DI 0, P Q #DI 0,#DI 0,

    > #DI 0, on m> #DI 0, on m

    > #DI 0, on.m m

    > #DI 0, on m> #DI 0, on m> #DI 0, on.m m> #DI 0, on.m m

    #DI 0, m#DI 0, m#DI 0, m#DI 0, m

    #DI 0, m#DI 0, m#DI 0, m#DI 0, m

    F. Menen ukan ja/ak i ik e/a elas is kons /uksi ( e )

    #DI 0, m> #DI 0, m

    ela engkung BΙpl > 10.Tpl 12 > m

    ela aki BΙ > 10. 1 12 > m

    k > Ι Ιpl >

    Su u ga/is usu/ pa a se iap i ik B

    6 > F C2 (C-=)= > F C .= - F C2.=2

    6 > F C - :F C2.=

    > a/< g(6 ) > a/< g( F C - :F C2.=)un uk = > 0 Q > sin ( ) >

    .1 Momen p/ime/ M0 aki a e an e an ma i hi up ( g )

    O0g > g . C 2 8E0g > g . C 2

    M0g > - R g . C2

    .2 Momen p/ime/ M0 a aki a e an ekanan anah ak i" O0 a > h⅙ ( a1 2 a2)" E0 a > h⅙ (2 a1 a2)ME0 a > - ⅙( a2- a1) R a1N.h2

    MO0 a > - ( a2- a1) R a1N.h2

    - e > M1pl( ) > -e >

    ila/ po/ al B M1 (-) > - e > M1 ( ) > e >

    . 'esa/an s a ik aki a ga6a i/ ual 2 > 1a ang eng ung B 1pl(-) > - >

    M1pl( ) > C 2 >ila/ po/ al B M1 (-)> - C 2 >

    M1 ( ) > C 2 >

    e. esa/an s a a a / ua 3 >'a ang lengkung B M1pl(-) > 1

    1pl( ) >ila/ po/ al M1 (-)> 1

    M1 ( ) > 1

    EΙ . δ 13 = U M1 . M 3 . dx = 0 , maka engan a uan a el hasil in eg/al i apa B pa a a ang lengkung po/ al B EΙpl . V13 > U M1pl . M3pl . = > W . C - e.C

    pa a pila/ po/ al B EΙ . V13 > M1 . M3 . = > - h2

    V13 > U M1 . M3 . = > C ( W - e )Ιpl - h 2 Ι > 0C ( W - e )Ι Ιpl - h 2 > 0C (2 - 3e ).k - 3h 2 > 02k.C. - 3k.C.e - 3h2 > 03k.C.e > 2k.C. - 3h2 e > ( 2k.C.F - 3h2 ) ( 3k.C ) >e > h e

    e

    2

    13

    -

    1) 'i ang-M0 aki a e an g

    ) 'i ang-M2 aki a 2 > 1

    e

    Ti ik e/a elas iskons /uksi

    1

    C 3 2

    C 3 2

    1

    C

    e > ja/ak i ik e/a elas is kons /uksi

    - -

    -

    M0g M

    0 g

    M 0 g

    e

    -

    C 2

    C 2

    --e

    ee

    1

    1 1

    Ι Ι

    ΙplΙpl

    --$ 1pl > 1

    $ 1 > 0? 1pl > 0

    ? 1 > -1

    $ 2pl > 0? 2pl > 1$ 2 > 1? 2 > 0

    ? 3 > 0$ 3 > 0? 3pl > 0$ 3pl > 0

    E K

    O D

    9

    9

    99

    9

    2) 'i ang-M0 aki a e an g

    9ME0 a

    MO0 a

    ME0 a

    M

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    47/105

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    48/105

    M0g

    -

    e

    E0 a

    O0 a

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    49/105

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    50/105

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    51/105

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    52/105

    . !ki a Tekanan Tanah !k i ( a )

    > #DI 0,> #DI 0,

    > #DI 0,

    > -> -> -

    > #DI 0,

    e/ en u menja i B> #DI 0, on m

    > #DI 0,

    > #DI 0, on.m m

    Momen BTi ik Simpul E > #DI 0, on.m mTumpuan O > #DI 0, on.m m

    ela engkung C 2 > #DI 0, on.m m

    &a6a $o/malTi ik Simpul E B'a ang EK > #DI 0, on m'a ang EO > #DI 0, on m

    > #DI 0, on mTumpuan O > #DI 0, on m

    ela engkung > #DI 0, on m

    &a6a in angTi ik Simpul E B

    'a ang EK > #DI 0, on m'a ang EO > #DI 0, on m

    > #DI 0, on mTumpuan O > #DI 0, on m

    ela engkung > #DI 0, on m

    R85 ;+& s+ :Momen BTi ik Simpul E > #DI 0, on mTumpuan O > #DI 0, on m

    ela engkung C 2 > #DI 0, on m

    &a6a $o/malTi ik Simpul E > #DI 0,on mTumpuan O > #DI 0, on m

    ela engkung > #DI 0,on m

    &a6a in angTi ik Simpul E > #DI 0, on m

    1. $ilai pe/u ahan en uk aki a M0 a an M1 B

    EΙpl . V10 apl > U M1pl . M0 apl . = > C . k .M0 apl . M1pl(-) C .k .M0 apl . on.m3

    EΙ . V10 a > U M1 . M0 a . = >1 12 C.(MO0 a ME0 a) ( e - e ) on.m3

    EΙ . V10 a > U M1 . M0 a . = on.m3

    2. $ilai pe/u ahan en uk aki a M0 a an M2 B

    EΙpl . V20 apl > U M2pl . M0 apl . = > on.m3

    EΙ . V20 a > U M2 . M0 a . = > on.m3

    EΙ . V10 a > U M1 . M0 a . = on.m3

    3. $ilai pe/u ahan en uk aki a M0 a an M3 B

    EΙpl . V30 apl > U M3pl . M0 apl . = > C .k.ME0 a ⅙ h . (MO0 a ME0 a) on.m3

    a/ena i ang momen M2 e/ en uk an ime /is; se angkan i ang 6ang lainn6a sime /is maka pe/samaan s a is i ak

    1 a > - V10 a V11

    2 a > - V20 a V22

    3 a > - V30 a V33

    B M > M0 M1. 1 M2 . 2 M3 . 3B ME a > MO0 a M1 (-) . 1 a M2 (-) . 2 a M3 ( ) . 3 aB MO a > MO0 a M1 (-) . 1 a M2 ( ) . 2 a M3 ( ) . 3 aB MO apl > 0 M1pl( ) . 1 a M2pl( ) . 2 a M3pl( ) . 3 a

    B $ > $0 $1. 1 $2 . 2 $3 . 3

    B $E a > " E0 a . Sin( ) $1pl . 1 a. Oos( )B $EK a > " E0 a $1 . 1 a

    $ E aB $O a > $1 . 1 aB $apl > $ 1pl. 1 a

    B ? > ?0 ? 1. 1 ? 2 . 2 ? 3 . 3

    B ?E a > " E0 a . Oos( ) ?1pl. 1 a. Sin( )B ?EO a > - ? 1 . 1 a

    ? E aB ?O a > " O0 a- ? 1 . 1 aB ? apl > 0 ? 1pl. 1 a

    B ME > MEg ME aB MO > MOg MO aB Mpl > Mgpl M apl

    B $E > $Eg $E aB $O > $Og $O aB $pl > $gpl $ apl

    B ?E > ? Eg ? E a

    ka/ena sime /is an an ime /is

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    53/105

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    54/105

    1;:58.00 % - 32

    > 2;7: .00

    n > 1:.00 -

    > 115.50 - 350

    > :.0

    > 0.:93 -

    U4 + S & HASIL

    Momen M on.m m #DI 0,&a6a $o/mal $ on m #DI 0,&a6a in ang ? on m #DI 0,

    > #DI 0,> #DI 0,> ( - ) #DI 0,> ( - ) #DI 0,> on. Tulangan Sime /is

    > (-) 0.:75#DI 0, > (-) #DI 0,

    Y > (-) 0. 07> (-) #DI 0,

    @ > Z.h > Y.h > (-) 1. 8> (-) #DI 0,> (-) #DI 0,

    #DI 0, > (-) #DI 0,> #DI 0,> #DIV/0!> #DIV/0!> #DI 0,

    on /ol &ese/ > #DI 0,> #DI 0,

    σ a kg (12 σ[au) . . h (15 σ[au) .h .103 M $

    2 \ e o2 > h 30eo > eo1 eo2

    eo han eo h >\ O

    k > 0;7.Ce1 > O.( k 100.h)2.h

    e2 > 0;15.he > eo e1 e2

    ea > e 0;5.h - $.e a

    Oa > > ] 1 (n.^.Z) _Xn.$.e a.̀ a

    ξ >7 :

    nω = ½ε 2/{d'/h.δ + 1 - ε(δ + 1)}

    φ > (1-ε) ε φ > (1-ε) (ε - h)

    ω = nω/n

    i.! > ω. .h +.A/+ δ .+A 20G . ! pe/lu ? ( .h.7 :) kg

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    55/105

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    56/105

    @. P847+& = P8 68s+ P8 & D+ d+ = K 5+

    #DIV/0!

    > 1;:58.00 % - 32

    > 2;7: .00

    n > 1:.00 -

    > 115.50 - 350

    > :.0

    > 0.:93 -

    U4 + S & HASIL

    Momen M > on.m m #DI 0,&a6a $o/mal $ > on m #DI 0,&a6a in ang ? > on m #DI 0,

    > #DI 0,> #DI 0,> ( - ) #DI 0,> ( - ) #DI 0,> on. Tulangan Sime /is

    > (-) 0.:75#DI 0, > (-) #DI 0,

    Y > (-) 0.39:> (-) #DI 0,

    @ > Z.h> Y.h > (-) 1.51> (-) #DI 0,> (-) #DI 0,

    #DI 0, > (-) #DI 0,> #DI 0,> #DIV/0!> #DIV/0!> #DI 0,

    on /ol &ese/ > #DI 0,> #DI 0,

    σ a kg (12 σ[au) . . h (15 σ[au) .h .103 M $

    2 \ e o2 > h 30eo > eo1 eo2

    eo han eo h >\ O

    k > 0;7.he1 > O.( k 100.h)2.h

    e2 > 0;15.he > eo e1 e2

    ea > e 0;5.h - $.e a

    Oa > > ] 1 (n.^.Z) _Xn.$.e a.̀ a

    ξ >7 :

    nω = ½ε 2/{d'/h.δ + 1 - ε(δ + 1)}

    φ > (1-ε) ε φ > (1-ε) (ε - h)

    ω = nω/n

    i.! > ω. .h +.A/+ δ .+A 20G . ! pe/lu ? ( .h.7 :) kg

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    57/105

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    58/105

    P8 68s+ P8 & L8 =5 = ( B s 4 )

    9 T 4+5 φ #DIV/0! #DIV/0!

    > mm #DI 0,

    *a/ak a > #DI 0,

    Tulangan em agi B φ #DIV/0! #DIV/0!

    > mm #DI 0,

    *a/ak a > #DI 0,

    9 T85 φ #DIV/0! #DIV/0!

    > mm #DI 0,*a/ak a > #DI 0,Tulangan em agi B φ #DIV/0! #DIV/0!

    > mm #DI 0,*a/ak a > #DI 0,

    #DIV/0!

    P8 68s+ P8 & D+ d+ = K 5+

    9 T 4+5 φ #DIV/0! #DIV/0!> mm #DI 0,

    *a/ak a > #DI 0,

    Tulangan em agi B φ #DIV/0! #DIV/0!> mm #DI 0,

    *a/ak a > #DI 0,

    9 T85 φ #DIV/0! #DIV/0!> mm #DI 0,

    *a/ak a > #DI 0,

    Tulangan em agi B φ #DIV/0! #DIV/0!> mm #DI 0,

    *a/ak a > #DI 0,

    Dia. φ

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    59/105

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    60/105

    B. PERENCANAAN BANGUNAN BA$AH

    3. PERHITUNGAN BEBAN MATI BANGUNAN BA$AH

    #DI 0, m

    - m - m

    #DI 0, m#DI 0, m

    2.50 m

    1.:0 m

    0.25 m 0.25 m

    0.50 m 0.07 m 1.00 m

    - m0.50 m

    0.75 m

    K8&84 = :

    *umlah Tiang an #DI 0, 0.00 0.00 #DI 0, #DI 0,

    0.50 = ### = 1.00 = 0.00 = 2.50 > #DI 0, #DI 0, 0.00 #DI 0, #DI 0,< 0.50 = ### = 1.00 = 0.00 = 2.50 > #DI 0, #DI 0, 0.00 #DI 0, #DI 0,

    1.00 = ### = 1.00 = 0.00 = 2.50 > #DI 0, #DI 0, 0.00 #DI 0, #DI 0,e 1.00 = ### = 1.00 = 0.00 = 2.50 > #DI 0, #DI 0, 0.00 #DI 0, #DI 0,

    2. S ; A6 & 8 &1 1.00 = 0.00 = 0.25 = 0.00 = 2.50 > 0.00 0.00 0.00 0.00 0.00

    1 1.00 = 0.00 = 0.25 = 0.00 = 2.50 > 0.00 0.00 0.00 0.00 0.00. T 7 U4 =

    1 1.00 = ### = 0.50 = #DI 0, = 1.70 > #DI 0, 0.00 #DI 0, #DI 0, #DI 0,

    Σ #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    h >

    h5

    >

    h8 >

    1 >

    2 >

    >

    Do >

    1 >2 >

    p1 >p2 >

    o >

    Do >p1 >

    p2 >

    Σ& ΣMa

    2

    h

    h5

    h8

    1

    a<

    e

    1 2

    bcb

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    61/105

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    62/105

    2. GA A REAKSI

    . B86 = d+s 45 8 + B = A& s

    'e an ma i angunan a as B > #DI 0, on

    Momen e/ha ap b c b B > = 0.00 > #DI 0, on.m

    2. B86 H+d ; d8 = K8 & : > #DI 0, on

    &a6a e/ ikal B = 'M > #DI 0, = 100G > #DI 0, on Momen e/ha ap b c b B > p = 0.00 > #DI 0, on.m

    6. B86 P8 = 4 7 G8 ;

    > 0.15

    > 0.15 = #DI 0, > #DI 0, on M' 8 d+ &+&+5 O : = > #DI 0, = #DI 0, > #DI 0, on.m

    > 0.15 = #DI 0, > #DI 0, on

    M' 8 d+ &+&+5 O : = e > #DI 0, on.m

    0.05> #DI 0, on

    M' 8 d+ &+&+5 O : #DI 0, on.m

    d. T85 T 7 A5&+ ( T ) d3. P d K' d+s+ N'4 (T )

    > 0.30:5

    imana B > 30 α > 0> 0 > 10> 1.70

    > 0.31 > #DI 0,

    = > #DI 0, on> #DI 0, on> #DI 0, on

    Ti ik e/a ------\ > = > #DI 0, me e/

    > > #DI 0, me e/ M' 8 d+ &+&+5 O : > = > #DI 0, on.me e/

    > = > #DI 0, on.me e/

    > 0.8317

    imana B > 30.00 α > -> 21. 7 > -

    τ > - > 0.15> - > :.53

    > 0.00 me e/ > #DI 0,> #DI 0, on> #DI 0, on

    i ik e/a ------\ > > #DI 0, me e/ > > #DI 0, me e/

    M' 8 d+ &+&+5 O : > = > #DI 0, on.m

    3. B86 M &+ ( M; )

    Mp > H = = ' 2

    M= Mp V; > H F K > p. '. 2

    V; > H F K M=

    oeFisien &empa

    63. D 4+ B = B 7 (G7 6) :

    G7 63 > kh = ΣMaM 1 > &h 1

    62. D 4+ B = A& s (G7 ; ) :

    G7 ; > kh = MpM

    &hp> &h

    p

    1. G R8 (R )

    oeFisien /em F / > R > F / =

    M6 m > (1;: " ). m >

    ! >sin(φ δ) . sin(φ - α )

    ( 0;8 h3 ) . γ . ! on m2 a2 > a1 γ . . ! on m2

    h = 'Tah > Ta1 . Ta1 . sin ( δ + τ )

    6Ta1

    Ta1 1 2 M=Ta1 Ta1 =Ta1 M6Ta1 Ta1h 6Ta1

    d2. K' d+s+ G8 ; (G7 T )

    ! >sinφ . sin(φ - α −φο) an-1 kh (1-k)N o

    h4 > h3

    a;g > ( h3 h ).γ . !E on m2

    Ta;gh > 0;5 . a1;g . h .

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    63/105

    > = > #DI 0, on.m M6& ;Ta &h;Ta 6Ta;g

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    64/105

    1. R85 ;+& s+ G R8 5s+

    NO. JENIS BEBAN GA A MOMEN DI TITIK O

    V H M M

    &' &' &' . &' .

    I 'E'!$ M!TI ( M ) Ba. 'angunan 'a4ah ( Ma ) #DI 0, - #DI 0, -

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    65/105

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    66/105

    . PENULANGAN POOR KAKI

    Tegang > 1;:58.00 32ua > 27: .00

    n > 21.00 -

    > :2.50 250

    I@in > 10.2:

    > 1.071 -

    U4 + S &KOMBINASI

    I II III IV V VI

    &a6a in a > on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,Momen > on.m #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,Tinggi eFek > #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    Oa > > (-) #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    LENTUR MURNIV > (-) - - - - - -Y > (-) 0.1:5 0.1:5 0.208 0.3:9 0.19: 0.1:5

    6 > Y.h > (-) #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> (-) #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    @ > Z.h> (-) . 1 . 1 3.:5 1.57 .05 . 1> (-) #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> (-) #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> #DIV/0! #DIV/0! #DIV/0! #DIV/0! #DIV/0! #DIV/0!> #DIV/0! #DIV/0! #DIV/0! #DIV/0! #DIV/0! #DIV/0!

    #DIV/0! #DIV/0! #DIV/0! #DIV/0! #DIV/0! #DIV/0!on /ol &e #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    P8 = P''4 K 5+

    9 T 4+5 #DIV/0! #DIV/0!

    > mm #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,*umlah > uah #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    uas ! > #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    9 T85 #DIV/0! #DIV/0!

    > mm #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,*umlah > uah #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    uas ! > #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    9 T = S8 =5 = #DIV/0! 9 2

    > mm #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    *umlah > uah m .00 .00 .00 .00 .00 .00> #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    σ a kg h8 h5 2

    > 2 2 1

    h > h - ! min> (12 σ[au) = = h

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    67/105

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    68/105

    . GA A ANG BEKERJA DAN JUMLAH TIANG PANCANG

    DISKRIPSI SATUANKOMBINASI 3 KOMBINASI 2

    I II III Σ I II III Σn > uah 5.00 5.00 5.00 15.00 5.00 5.00 5.00 15.00

    M > on.m #DI 0, #DI 0,

    > on #DI 0, #DI 0,

    " > on #DI 0, #DI 0,

    > on h #DI 0, #DI 0,

    > 0.05 0.05> on m #DI 0, #DI 0,> m 0.07 - -0.07 0.07 - -0.07

    > on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> 10.00 - 10.00 10.00 - 10.00> ] - _ 0.17 - 0.17 0.17 - 0.17> ] - _ 0.9:5 1.00 0.9: 1 .:5 0.9:5 1.00 0.9: 1 .:5> ] - _ 0.178 - 0.1: 0.178 - 0.1:> on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> on #DI 0, #DI 0,> on #DI 0, #DI 0,> on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> on #DIV/0! #DIV/0! #DIV/0! #DIV/0! #DIV/0! #DIV/0!> on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> on #DIV/0! #DIV/0! #DIV/0! #DIV/0! #DIV/0! #DIV/0!

    DISKRIPSI SATUANKOMBINASI KOMBINASI

    I II III Σ I II III Σn > h 5.00 5.00 5.00 15.00 5.00 5.00 5.00 15.00M > on.m #DI 0, #DI 0,

    > on #DI 0, #DI 0," > on #DI 0, #DI 0,

    > on h #DI 0, #DI 0,> 0.05 0.05> on m #DI 0, #DI 0,> m 0.07 - -0.07 0.07 - -0.07> on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> 10 - 10.00 10 - 10.00> ] - _ 0.17 - 0.17 0.17 - 0.17> ] - _ 0.9:5 1.00 0.9: 1 .:5 0.9:5 1.00 0.9: 1 .:5> ] - _ 0.178 - 0.1: 0.178 - 0.1:> on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> on #DI 0, #DI 0,> on #DI 0, #DI 0,> on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> on #DIV/0! #DIV/0! #DIV/0! #DIV/0! #DIV/0! #DIV/0!> on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    ΣnI = Σi.x t

    2 m2

    M I= > p2

    (MI). => n (MI). =

    θ o

    sin θ .sin θ

    2 > . . anθ ∆" > " - Σ 3

    ∆ " = ∆" Σ 3 ∆ " . . .sn θ

    P N&> V2 F H 3

    1 > .sin θ" 2 > " . H 2 9 V3

    ΣnI = Σi.x t

    2 m2

    M I= > p2

    (MI). => n (MI). =

    θ o

    sin θ .sin θ

    2 > . . anθ

    ∆" > " - Σ 3∆ " = ∆" Σ 3 ∆ " . . V2 F H 3

    1 > .sin θ2 > .

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    69/105

    > on #DIV/0! #DIV/0! #DIV/0! #DIV/0! #DIV/0! #DIV/0!P T&> H 2 FV3

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    70/105

    lanjutan…….

    DISKRIPSIKOMBINASI < KOMBINASI @

    I II III Σ I II III Σn > h 5.00 5.00 5.00 15.00 5.00 5.00 5.00 15.00

    M > on.m #DI 0, #DI 0,

    > on #DI 0, #DI 0,

    " > on 0.00 #DI 0,

    > on h #DI 0, #DI 0,

    > 0.05 0.05> on m #DI 0, #DI 0,> m 0.07 - -0.07 0.07 - -0.07

    > on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> 10.00 - 10.00 10.00 - 10.00> ] - _ 0.17 - 0.17 0.17 #DI 0, 0.17> ] - _ 0.9:5 1.00 0.9: 1 .:5 0.9:5 1.00 0.9: 1 .:5> ] - _ 0.178 - 0.1: 0.178 - 0.1:> on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> on #DI 0, #DI 0,> on #DI 0, #DI 0,> on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> on #DIV/0! #DIV/0! #DIV/0! #DIV/0! #DIV/0! #DIV/0!> on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> on #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,> on #DIV/0! #DIV/0! #DIV/0! #DIV/0! #DIV/0! #DIV/0!

    1.2:E 05

    Diame e/ enampang Tiang an 0.00 0 > - on

    Ta/ik > 0.00 on

    0.00 kg > 0.00 on

    n > 15.00> > 0.00 on

    SATUAN

    ΣnI = Σi.x t

    2 m2

    M I= > p2

    (MI). =

    > n (MI). =θ o

    sin θ .sin θ

    2 > . . anθ ∆" > " - Σ 3

    ∆ " = ∆" Σ 3 ∆ " . . V2 F H 3

    1 > .sin θ" 2 > " . H 2 9 V3

    ` e kg

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    71/105

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    72/105

    @. REKAPITULASI GA A ANG BEKERJA PADA SETIAP TIANG PANCANG

    DIS I SI cDE&! ! (Tc$) D! !M cM'I$!SI EM'E'!$!$

    1 2 3 5 8

    &a6a "o/ison al #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    &a6a e/ ikal Maks. #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    &a6a e/ ikal Min. #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,&a6a To/si #DI 0, #DI 0, #DI 0, #DI 0, #DI 0, #DI 0,

    . TEGANGAN ANG TERJADI DAN PENURUNAN PADA TIANG PANCANG

    . T8= = ; d K8; T+ = P 1 =

    &a6a ho/ison al maksimum 6ang eke/ja#DI 0, on

    &a6a e/ ikal maksimum 6ang eke/ja

    #DI 0, #DI 0, - on &a6a e/ ikal minimum 6ang eke/ja#DI 0, on Q #DIV/0!#DI 0, on.m

    Tegangan 6ang e/ja i B ( beban sementara )#DI 0, #DI 0, ` e > 22 .00 #DIV/0!

    #DI 0, #DI 0, ` e > 22 .00 #DIV/0!

    6. T8= = ; d 6 =+ S 6=4 d8 Momen maksimum pa a agian su g/a e B

    > > #DI 0, on.m

    > > #DI 0, m&a6a e/ ikal maksimum 6ang eke/ja > #DI 0, on

    Tegangan 6ang e/ja i B ( beban sementara )#DI 0, #DI 0, ` e > 22 .00 #DIV/0!

    1. T8= = ; d 6 =+ S 6 = Momen maksimum pa a agian sam ungan B TIDAK ADA SAMBUNGAN .&+ = ;8 d85...!!!

    > #DI 0, on> 0.00 m #DI 0,

    β > #DI 0, #DI 0,

    > #DI 0, #DI 0,

    > #DI 0, on.m

    Tegangan 6ang e/ja i B ( beban sementara )#DI 0, #DI 0, ` e > 22 .00 #DIV/0!

    d. PENURUNAN KAKI PONDASI

    > #DI 0, on #DI 0, on #DI 0, on> #DI 0, on

    n > 15.00 uah > #DI 0, &a6a ho/ison al maksimum 6ang eke/ja pa a iang pan

    ma=> maks.

    $ n >

    i >

    min> min. $ n > M > "ma= 2β >

    σa > ma= ! M A > kg min ! - M A > kg ma= ! Ms A > kg k.Dβ> 2! .E pan

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    73/105

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    74/105

    PEMERINTAH PROVINSI JAWA BARAT

    DINAS BINA MARGASUB DINAS BINA TEKNIK

    NAMA JEMBATAN : 0

    PROGRAM PENAGANAN : PEMBANGUNAN JEMBATAN / PENGGANTIAN JEMBATAN

    LOKASI JEMBATAN PADA RUAS JALAN : 0

    STA. / KM : 0

    STATUS / "UNGSI JALAN : PROVINSI / KOLEKTOR

    KABUPATEN : 0

    NAMA DAN $ILA AH BPJ : 0

    TANGANGAL PERENCANAAN : MEI 2030

    PERHITUNGAN STRUKTUR JEMBATAN

    A. PERENCANAAN BANGUNAN ATAS

    3. DATA TEKNIS DAN DIMENSI

    . D & K' s&4 5s+ - Tipe ons /uksi 'angnan ! as : *em a an ela 'e on engkung Se engah ingka/an

    - Tipe on asi : Tiang an 0.50 m Tinggi anah u/ug > - m *a/i - ja/i alam usu/ lingka/an ( ) > #DI 0, m Te al pela usu/ > #DI 0, m Tinggi in ing iang (kaki) > #DI 0, m

    Te al /o oa/ > 0.25 m Te al in ing samping > 0.25 m Te al pela iang ( kaki ) > #DI 0, m

    Dia. >

    - Tinggi (lihat gambar dibawah )

    γ m3

    o

    ? all m2

    Tegangan I@in 'e on (kg

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    75/105

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    76/105

    2. SISTEM STATIKA DAN PERHITUNGAN BEBAN

    !sumsi se agai jem a an lengkung pa a 3 ( iga) s a is e/ en u 6ang ke ua umpuann6a engan sis em jepi

    2a. Dimensi Teo/i is B

    'en ang engkung C > > #DI 0, m anjang engkung > > #DI 0, m Tinggi engkung > > #DI 0, m Tinggi kons /uksi " > > #DI 0, m

    2 . e/hi ungan 'e an B 1. 'e an Ma i

    > -> -> #DI 0,

    ela 'usu/ > #DI 0,ela T/o oa/ e/ > 0.2:

    > #DI 0,

    Din ing samping > #DI 0, onDin ing pen6eka 2;5 . > - onSan a/an 1;2 . > - on

    > #DI 0, on> #DI 0,> #DI 0,> #DI 0, on m

    2. 'e an "i upe a/ lalu lin as ken a/aan > 2.75 m

    'e an hi up e/pusa T > 10.00 onoeFisien keju > #DI 0,

    'e an hi up engan koeFisien keju> = 100G > #DI 0, on m

    m > > #DI 0, mp > > #DI 0,

    3. 'e an Ma i "i upg > H p > #DI 0,

    . Tekanan Tanah !k i

    > > 0.30:5

    > 30 α > 0> 0 > 10> 1.70

    > #DI 0,> #DI 0,

    - TplJ EK L. C

    Tpl 2 h

    e/ke/asan jalan 1 > γ p . h1 . ' on m2

    apis on asi *alan 2 > γ a . h2 . ' on m2Ma e/ial %/ugan 3 > γ . h3 (1-L ). N on m2

    1 > γ γ . / . 2(4 0;25) ' on m2

    H1 on m2

    3 > 2. . " - L. 2 2N.T4.γ < >

    5 >

    3 5H2 > ( 3 5 ) (C .') on m2

    H > H1 H2 on m2Din ing kaki 8 > h . 1 . γ <

    Ck

    > 20 (50 C)

    T ( 2T Ck ) . (1 )

    2 (h1 h2 h3 0;5.Tpl) 0;5T m on m2

    on m2

    !

    sin(φ δ) . sin(φ - α) ( 0;8 h3 ) .γ . ! on m2 a2 > a1 γ . . ! on m2

    g

    O DC

    h

    E K

    1 2

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    77/105

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    78/105

    . ANALISA MEKANIKA DENGAN CARA KERJA VIRTUAL

    a. Momen Ine/sia#DI 0,

    #DI 0,

    #DI 0, ( - )

    e/samaan ga/is lengkung se engah lingka/an B 6 > =

    0.00 P Q

    0.00

    1.00

    > #DI 0, on m> #DI 0, on m> #DI 0, on.m m

    > #DI 0, on.m m> #DI 0, on.m m> #DI 0, on m> #DI 0, on m

    #DI 0, m#DI 0, m#DI 0, m#DI 0, m

    #DI 0, m#DI 0, m#DI 0, m#DI 0, m

    F. Menen ukan ja/ak i ik e/a elas is kons /uksi ( e )

    ### m> ### m

    ela engkung BΙpl > 10.Tpl 12 > m

    ela aki BΙ > 10. 1 12 > m

    k > Ι Ιpl >

    Su u ga/is usu/ pa a se iap i ik B

    6 > =2 2 Q

    > a/< g(6 ) > a/< g( = )un uk = > 0 Q >

    sin ( ) >

    .1 Momen p/ime/ M0 aki a e an e an ma i hi up ( g )

    O0g > g . C 2 8E0g > g . C 2

    M0g > - R g . C2

    .2 Momen p/ime/ M0 a aki a e an ekanan anah ak iME0 a > - ⅙( a2- a1) R a1N.h2

    MO0 a > - ( a2- a1) R a1N.h2" O0 a > h⅙ ( a1 2 a2)" E0 a > h⅙ (2 a1 a2)

    - e > M1pl( ) > -e >

    a/ po/ a B 1 (-) > - e > M1 ( ) > e >

    . 'esa/an s a ik aki a ga6a i/ ual 2 > 1'a ang lengkung B M1pl(-) > - C 2 > M1pl( ) > C 2 >

    ila/ po/ al B M1 (-)> - C 2 > M1 ( ) > C 2 >

    e. 'esa/an s a ik aki a i/ ual 3 > 1'a ang lengkung B M1pl(-) > 1

    1pl( ) >ila/ po/ al M1 (-)> 1

    M1 ( ) > 1

    EΙ . δ 13 = U M1 . M 3 . dx = 0 , maka engan a uan a el hasil in eg/al i apa B pa a a ang lengkung po/ al B EΙpl . V13 > U M1pl . M3pl . = > W . C - e.C

    pa a pila/ po/ al B EΙ . V13 > M1 . M3 . = > - h2

    V13 > U M1 . M3 . = > C ( W - e )Ιpl - h 2 Ι > 0C ( W - e )Ι Ιpl - h 2 > 0C (2 - 3e ).k - 3h 2 > 02k.C. - 3k.C.e - 3h2 > 03k.C.e > 2k.C. - 3h2 e > ( 2k.C. - 3h2 ) ( 3k.C ) >e > h e

    e

    2

    13

    -

    1) 'i ang-M0 aki a e an g

    ) 'i ang-M2 aki a 2 > 1

    e

    Ti ik e/a elas iskons /uksi

    1

    C 3 2

    C 3 2

    1

    C

    "

    e > ja/ak i ik e/a elas is kons /uksi

    - - M0g

    -

    M0g

    -

    M 0 g

    M 0 g

    e e

    -

    C 2

    C 2

    --e

    ee

    1

    1 1

    Ι Ι

    Ιpl Ιpl

    --

    $ 1pl > 1

    $ 1 > 0? 1pl > 0

    ? 1 > -1

    $ 2pl > 0

    ? 2pl > 1$ 2 > 1

    ? 2 > 0

    ? 3 > 0$ 3 > 0? 3pl > 0$ 3pl > 0

    E K

    O D

    9

    9

    99

    9

    2) 'i ang-M0 aki a e an g

    9ME0 a ME0 a

    MO0 a

    ME0 a

    MO0 a

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    79/105

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    80/105

    > #DI 0,

    > #DI 0,

    > #DI 0,

    > #DI 0,

    > #DI 0, m

    . N+ + A57+4 M 5s+ B8s 4 S& &+5

    . A5+6 & B86 M &+ d H+d ; ( = )

    > #DI 0,> #DI 0,

    > #DI 0,

    > 0.00> 0.00> 0.00

    > #DI 0,> #DI 0,> #DI 0,

    e/ en u menja i B> #DI 0, on m

    > #DI 0,

    > #DI 0, on.m m

    Momen BTumpuan > #DI 0, on.m m

    Ti ik Simpul E > #DI 0, on.m mela engkung C 2 > #DI 0, on.m m

    &a6a $o/malTi ik Simpul E B'a ang EK > #DI 0, on m'a ang EO > #DI 0, on m

    > #DI 0, on m

    Tumpuan O > #DI 0, on m

    ela engkung>

    #DI 0,on m

    &a6a in angTi ik Simpul E B'a ang EK > #DI 0, on m'a ang EO > #DI 0, on m

    > #DI 0, on m

    g. $ilai pe/u ahan en uk aki a M1 B

    EΙpl . V11pl > U M1pl . M1pl . = > C.k e2 - 2 . W .e . : 15 2 N m3

    EΙ . V11 > U M1 . M1 . = > W h e2 - e .e e2 N m3

    EΙ . V11 > U M1 . M1 . = m3

    h. $ilai pe/u ahan en uk aki a M2 B

    EΙ . V22 > U M2 . M2 . = > k.C.(XC)2 X h .C2 m3

    i. $ilai pe/u ahan en uk aki a M3 B

    EΙ . V33 > U M3 . M3 . = > C 2k.h

    1. $ilai pe/u ahan en uk aki a M0g an M1 B EΙpl . V10gpl > U M1pl . M0gpl . = > C . k .M0gpl. M1pl(-) 2 15 C .k .M0gpl . on.m3

    EΙ . V10g > U M1 . M0g . = > X h . M0g . ( e - e ) on.m3

    EΙ . V10g > U M1 . M0g . = on.m3

    2. $ilai pe/u ahan en uk aki a M0g an M2 B EΙpl . V20gpl > U M2pl . M0gpl . = >⅟ 12 C.k.M0g ( XC - XC ) on.m3

    EΙ . V20g > U M2 . M0 . = > X h . M0g .( e - e ) h.M0g.(XC) - h.M0g.(XC) on.m3

    EΙ . V10g > U M1 . M0g . = on.m3

    3. $ilai pe/u ahan en uk aki a M0g an M3 B EΙpl . V30gpl > U M3pl . M0gpl . = > C.k.M0g on.m3 EΙ . V30g > U M3 . M0g . = > 2 h . M0g on.m3

    EΙ . V30g > U M3 . M0g . = on.m3

    a/ena i ang momen M2 e/ en uk an ime /is; se angkan i ang 6ang lainn6a sime /is maka pe/samaan s a is i ak

    1g > - V10g V11

    2g > - V20g V22

    3g > - V30g V33

    B M > M0 M1. 1 M2 . 2 M3 . 3B MOg > MO0g M1 (-) . 1g M2 ( ) . 2g M3 ( ) . 3g

    B MEg > MO0g M1 (-) . 1g M2 (-) . 2g M3 ( ) . 3gB MOgpl > MO0gpl M1pl( ) . 1g M2pl( ) . 2g M3pl( ) . 3g

    B $ > $0 $1. 1 $2 . 2 $3 . 3

    B $EKg > - E0g . Sin( ) $1pl . 1g . Oos( )B $EKg > E0g $1 . 1g

    $ Eg

    B $Og > - O0g $1 . 1gB $

    gpl > $

    1pl.

    1g

    B ? > ?0 ? 1. 1 ? 2 . 2 ? 3 . 3

    B ?EKg > E0g .Oos( ) ?1pl. 1g .Sin( )B ?EOg > - ? 1 . 1g

    ? Eg

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    81/105

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    82/105

    6. A5+6 & T85 T 7 A5&+ ( & )

    > #DI 0,> #DI 0,

    > #DI 0,

    > -> -> -

    > #DI 0,

    e/ en u menja i B> #DI 0, on m

    > #DI 0,

    > #DI 0, on.m m

    Momen BTi ik Simpul E > #DI 0,Tumpuan O > #DI 0,

    ela engkung C 2 > #DI 0,

    &a6a $o/malTi ik Simpul E B'a ang EK > #DI 0,'a ang EO > #DI 0,

    > #DI 0,Tumpuan O > #DI 0,

    ela engkung > #DI 0,

    &a6a in angTi ik Simpul E B

    'a ang EK > #DI 0,'a ang EO > #DI 0,

    > #DI 0,Tumpuan O > #DI 0,

    ela engkung > -

    R85 ;+& s+ :Momen BTi ik Simpul E > #DI 0, on mTumpuan O > #DI 0, on m

    ela engkung C 2 > #DI 0, on m

    &a6a $o/malTi ik Simpul E > #DI 0,on mTumpuan O > #DI 0, on m

    ela engkung C 2 > #DI 0,on m

    1. $ilai pe/u ahan en uk aki a M0 a an M1 B

    EΙpl . V10 apl > U M1pl . M0 apl . = > C . k .M0 apl . M1pl(-) C .k .M0 apl .

    EΙ . V10 a > U M1 . M0 a . = >1 12 C.(MO0 a ME0 a) ( e - e )

    EΙ . V10 a > U M1 . M0 a . =

    2. $ilai pe/u ahan en uk aki a M0 a an M2 B

    EΙpl . V20 apl > U M2pl . M0 apl . = >

    EΙ . V20 a > U M2 . M0 a . = >

    EΙ . V10 a > U M1 . M0 a . =

    3. $ilai pe/u ahan en uk aki a M0 a an M3 B

    EΙpl . V30 apl > U M3pl . M0 apl . = > C .k.ME0 a ⅙ h . (MO0 a ME0 a)

    a/ena i ang momen M2 e/ en uk an ime /is; se angkan i ang 6ang lainn6a sime /is maka pe/samaan s a i

    1 a > - V10 a V11

    2 a > - V20 a V22

    3 a > - V30 a V33

    B M > M0 M1. 1 M2 . 2 M3 . 3B ME a > MO0 a M1 (-) . 1 a M2 (-) . 2 a M3 ( ) . 3 aB MO a > MO0 a M1 (-) . 1 a M2 ( ) . 2 a M3 ( ) . 3 aB MO apl > 0 M1pl( ) . 1 a M2pl( ) . 2 a M3pl( ) . 3 a

    B $ > $0 $1. 1 $2 . 2 $3 . 3

    B $E a > " E0 a . Sin( ) $1pl . 1 a. Oos( )B $EK a > " E0 a $1 . 1 a

    $ EgB $O a > $ 1 . 1 aB $apl > $1pl. 1 a

    B ? > ?0 ? 1. 1 ? 2 . 2 ? 3 . 3

    B ?E a > " E0 a . Oos( ) ?1pl. 1 a. Sin( )B ?EO a > - ? 1 . 1 a

    ? EgB ?O a > " O0 a- ? 1 . 1 aB ? apl > 0 ? 1pl . 1 a

    B ME > MEg ME aB MO > MOg MO a

    B Mpl > Mgpl M apl

    B $E > $Eg $E aB $O > $Og $O aB $pl > $gpl $ apl

    ka/ena sime /is an an ime /is

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    83/105

  • 8/19/2019 JEMBATAN PELAT LENGKUNG

    84/105

    1;:58.00 % - 32

    > 2;7: .00

    n > 1:.00 -

    > 115.50 - 350

    > :.0

    > 0.:93 -

    U4 + S & HASIL

    Momen M on.m m #DI 0,&a6a $o/mal $ on m #DI 0,&a6a in ang ? on m #DI 0,

    > #DI 0,> #DI 0,> ( - ) #DI 0,

    > ( - ) #DI 0,> on.

    Tulangan Sime /is> (-)

    on m #DI 0, > (-) #DI 0,on m Y > (-)on m > (-) #DI 0,

    on m @ > Z.h > Y.h > (-)> (-) #DI 0,> (-) #DI 0,

    #DI 0, > (-) #DI 0,> #DI 0,> #DIV/0!