ionization energy trends
DESCRIPTION
4f. 5f. Ionization Energy Trends. Electronegativity. Increasing Electronegativity. Decreasing Electronegativity. Lewis Structure Assumptions. Only valance electrons are involved in bonding. Atoms react to form molecules, so to achieve stable noble gas electron configurations. - PowerPoint PPT PresentationTRANSCRIPT
4f
5f
Ionization Energy Trends
ElectronegativityIncreasing Electronegativity
Dec
reas
ing
Ele
ctro
nega
tivity
Lewis Structure Assumptions
• Only valance electrons are involved in bonding.• Atoms react to form molecules, so to achieve
stable noble gas electron configurations.• Atoms in molecules want eight valance electrons
(octet rule) except for hydrogen which wants two electrons (duet rule).
• In covalent compounds atoms share electrons to form bonds in order to achieve stable noble gas electron configurations. In ionic compounds electrons are transferred from one atom to another to achieve stable noble gas electron configurations.
Rules for Drawing Lewis Structures
Step 1: Count the total number of valance electrons.
Step 2: Identify the central atom (the first atom written unless that atom is hydrogen). Place all terminal atoms around that atom. Hydrogen atoms NEVER have more than one bond.
Step 3: Complete the octet for all atoms in the Lewis structure with lone pairs of electrons (except hydrogen).
Step 4: Check your structure by counting the number of valance electrons used (they will match step 1 if the structure is correct). If your valance electrons don’t match you will need to tweak your structure as follows.
Tweaking Lewis Structures
Too Many Electrons Initially: Redraw the
Lewis structure from step 2 adding a double
bond. If you still have too many electrons
add another multiple bond and repeat.
Always add double bonds before triple
bonds. Every double bonds effectively
remove two electrons from the structure while
triple bonds effectively remove 4 electrons.
“Exceptions” to the Octect
Two Few Electrons: If you only have four or
six valance electrons initially you can’t
possibly fill the octet rule (usually BeH2 or
BH3). Just place hydrogens around central
atoms and call it done.
“Exceptions” to the Octect
Odd number of electrons: One atom will
have to have less than eight electrons.
Draw the Lewis structure as if it had one
more valance electrons than it actually does.
Then subtract one electron from the least
electronegative element (often the central
atom).
“Exceptions” to the Octect
Exceeding the Octet Rule: If the central atom is inthe third row or below it may be possible to exceedeight electrons around the central atom. But only ifyou absolutely have no choice. If you can giveeverything eight and only eight do that first. Whenyou must break the octet rule draw the structure asyou would in steps 1-4 and the place the extraelectrons around the central atom. Even whenbreaking the octet rule no atom will ever havemore than 12 electrons.
Example Total # of Things
Lone Pairs
Geo. Shape 3-D Lewis
Structure
Bond Angles
Hybrid Orbitals
CO2 2 0 Linear Linear 180 sp
CH2S 3 0 Trig.Planar Trig. Planar 120 sp2
SeO2 3 1 Trig.Planar Bent 120 sp2
SiCl4 4 0 Tetra. Tetra. 109.5 sp3
PCl3 4 1 Tetra. Trig. Pyramid. 109.5 sp3
H2S 4 2 Tetra. Bent 109.5 sp3
HI 4 3 Tetra. Linear 180 sp3
Example Total # of Things
Lone Pairs
Geo. Shape 3-D Lewis
Structure
Bond Angles
Hybrid Orbitals
PF5 5 0 Trig. bipyramid
Trig. bipyramid
120, 90, 180
dsp3
SeBr4 5 1 Trig. bipyramid
See-saw 120, 90, 180
dsp3
BrCl3 5 2 Trig. bipyramid
T-shaped 90, 180 dsp3
XeCl2 5 3 Trig. bipyramid
linear 180 dsp3
TeF6 6 0 Octahed. Octahed. 90, 180 d2sp3
IF5 6 1 Octahed. Square pyramid
90, 180 d2sp3
RnBr4 6 2 Octahed. Square planar
90, 180 d2sp3
Organic Lewis Structure Rules
• Based on formal charge arguments
Atom Bonds Formed in Lewis Structure
Lone Pairs on Atom in Lewis Structure
C 4 0
N 3 1
O 2 2
F, Cl, Br, I 1 3
p-orbitals are 90 degrees from each other
1 s + 3 p = 4 sp3 orbitals
1 s + 2 p = 3 sp2 orbitals
1 s + 1 p = 2 sp orbitals
Unhybridized p-orbitals delocalize the -electrons
ALL atoms are sp2 hybridized in NO31-.
There are NO sp3 hybridized orbitals.