100 Watt InverterDescription

Here is a 100 Watt inverter circuit using minimum number of components.I think it is quite difficult to make a decent one like this with further less components.Here we use CD 4047 IC from Texas Instruments for generating the 100 Hz pulses and four 2N3055 transistors for driving the load.

The IC1 Cd4047 wired as an astable multivibrator produces two 180 degree out of phase 100 Hz pulse trains.These pulse trains are preamplifed by the two TIP122 transistors.The out puts of the TIP 122 transistors are amplified by four 2N 3055 transistors (two transistors for each half cycle) to drive the inverter transformer.The 220V AC will be available at the secondary of the transformer.Nothing complex just the elementary inverter principle and the circuit works great for small loads like a few bulbs or fans.If you need just a low cost inverter in the region of 100 W,then this is the best.Inverter Circuit Diagram with Parts List.

100 Watt Inverter Circuit Diagram

Notes. A 12 V car battery can be used as the 12V source.Use the POT R1 to set the output frequency to50Hz.For the transformer get a 9-0-9 V , 10A step down transformer.But here the 9-0-9 V winding will be the primary and 220V winding will be the secondary.

If you could not get a 10A rated transformer , don’t worry a 5A one will be just enough. But the allowed out put power will be reduced to 60W.Use a 10 A fuse in series with the battery as shown in circuit.Mount the IC on an IC holder.Remember,this circuit is nothing when compared to advanced PWM inverters.This is a low cost circuit meant for low scale applications.Inverter Design Tips.

The maximum allowed output power of an inverter depends on two factors.The maximum current rating of the transformer primary and the current rating of the driving transistors.

For example ,to get a 100 Watt output using 12 V car battery the primary current will be ~8A ,(100/12) because P=VxI.So the primary of transformer must be rated above 8A.

Also here ,each final driver transistors must be rated above 4A. Here two will be conducting parallel in each half cycle, so I=8/2 = 4A .

These are only rough calculations and enough for this circuit.

Uninterruptible Power Supply (UPS): Basic Circuit Diagram

The circuit drawn pertains to a regular industrial UPS (Uninterruptible Power Supply), which shows how the batteries take control during an outage in electrical supply or variation beyond the normal limits of the voltage line, without disruption on the operation providing a steady regulated output (5 Volts by LM7805) and an unregulated supply (12 Volts).

The input to the primary winding of the transformer (TR1) is 240V. The secondary winding can be raised up to 15 Volts if the value is at least 12 Volts running 2 amp. The fuse (FS1) acts as a mini circuit breaker for protection against short circuits, or a defective battery cell in fact. The presence of electricity will cause the LED 1 to light. The light of LED will set off upon power outage and the UPS battery will take over

The circuit was designed to offer more flexible pattern wherein it can be customized by using different regulators and batteries to produce regulated and unregulated voltages. Utilizing two 12 Volt batteries in series and a positive input 7815 regulator, can control a 15V supply.

Cable TV amplifier

Description.This is a very simple cable TV amplifier using two transistors. This amplifier circuit is most suitable for cable TV systems using 75 Ohm coaxial cables and works fine up to 150MHz. Transistor T1 performs the job of amplification. Up to 20dB gain can be expected from the circuit.T2 is wired as an emitter follower to increase current gain.

Circuit diagram.

Notes.The circuit can be assembled on a Vero board.Use 12V DC for powering the circuit.Type no of the transistors are not very critical.Any medium power NPN RF transistors can be used in place of T1 and T2.This is just an elementary circuit. Do not compare it with high quality Cable TV amplifiers available in the market.

The following diagram is the schematic diagram of variable power supply which will deliver 0 to 28V output voltage at 6/8 A electric current.

Component Part List:R1 = 2K2 Ohm 2,5 WattR2 = 240 OhmR3,R4 = 0.1 Ohm 10 WattR7 = 6K8 OhmR8 = 10K OhmR9 = 47 Ohm 0.5 WattR10 = 8K2 OhmC1, C7, C9 = 47nFC2 = 4700uF/50v – 6800uF/50vC3, C5 = 10uF/50vC4, C6 = 100nFC8 = 330uF/50vC10 = 1uF/16vC11 = 22nF D1…D4 = four MR750 (MR7510) diodes (MR750 = 6 Ampere diode) or 2 x 4 1N5401 (1N5408) diodes.D5 = 1N4148, 1N4448, 1N4151D6 = 1N4001D10 = 1N5401

D11 = LEDD7, D8, D9 = 1N4001TR = 2 x 15 volt (30volt total) 6+- AmpereIC1 = LM317T1, T2 = 2N3055P1 = 5kP2 = 47 Ohm or 220 Ohm 1 WattP3 = 10k trimmerF1 = 1 AmpF2 = 10 amp

Circuit Description:This is an easy to make power supply that has reliable, clear and regulator 0 to 28 Volt 6/8 Amp output voltage. By making use of two 2N3055 transistor, you’ll get two times the amount of electric current.

Although the 7815 power regulator may kick in on short circuit, overload and thermal overheating, the fuses in the main section of the transformer and the fuse F2 at the output will safe your power supply. The rectified voltage of: 30 volt x SQR2 = 30 x 1.41 = 42.30 volt measured on C1. So all capacitors should be rated at 50 volts. Caution: 42 volt will be the voltage that could be on the output if 1 of the transistors ought to blow.

P1 lets you ‘regulate’ the output voltage to something in between 0 and 28 volts. The LM317 lowest voltage is 1.2 volt. To have a zero voltage on the output I’ve place 3 diodes D7,D8 and D9 around the output with the LM317 towards the base with the 2N3055 transistors. The LM317 optimum output voltage is 30 volts, but using the diodes D7,D8 & D9 the output voltage is approx 30v – (3x 0.6v) = 28.2volt.

Adjust your build-in voltmeter using P3 and, of course, a fine digital voltmeter is better solution.

P2 will let you to control the limit with the optimum available electric current in the output +Vcc. When utilizing a 100 Ohm / 1 watt varistor the current is limited to approx. 3 Amps @ 47 Ohm and +- 1 Amp @ 100

6A / 0-28V Variable Power Supply source:

5W Simple Inverter circuit diagramHere’s a very simple circuit inverter that converts DC current into AC current, from 12V DC to 220V AC with output power of 5W.

Inverter circuit is typically used for emergency lighting, since the power output is small, which is about 5W only. But you can use this inverter for other purposes that do not require large electric power such as mobile phone charger.

5W simple inverter circuit source:

http://skemarangkaian.com/5w-simple-inverter-circuit-with-2n3055/

50W Inverter 12VDC to 220VAC circuit diagramThis circuit is able to convert 12V DC to 220V AC dan handle about 50Watt small electronic appliance.

Component ListR1=10MohmsR2=100ohmsR3=1.2KohmsR4=560KohmsR5-6=2.2KohmsR7-8=56 ohms 5WCX=22pF trimmed capacitorC1-2=22pF ceramicC3=8.2nF 100V MKTC4=10uF 16VC5=47uF 16VC6=470nF 400VD1=5V6 0.4WD2-3=47V 1WQ1-2=BS170Q3-4=BD139Q5-6=BD249IC1=4060 IC2=4013IC3=4047CR1=3.2768 MHZ crystalT1=220Vac/2X10V 2X2.2AF1=5A FuseF2=0.25A FuseL1=1H smoothing choke

Basic Inverter circuit diagram

This is the bacis of inverter circuit diagram. The circuit will convert 12V DC to 120V AC. This circuit can handle up to 1000Watts supply depends the T1, T2 and transformer used. Please see the note.

Component list:Part Total Qty. Description SubstitutionsC1, C2 2 68 uf, 25 V Tantalum CapacitorR1, R2 2 10 Ohm, 5 Watt ResistorR3, R4 2 180 Ohm, 1 Watt ResistorD1, D22 HEP 154 Silicon DiodeQ1, Q22 2N3055 NPN Transistor (see “Notes”)T1 1 24V, Center Tapped Transformer (see “Notes”)MISC 1 Wire, Case, Receptical (For Output)

Notes:

1. Q1 and Q2, as well as T1, determine how much wattage the inverter can supply. With Q1,Q2=2N3055 and T1= 15 A, the inverter can supply about 300 watts. Larger transformers and more powerful transistors can be substituted for T1, Q1 and Q2 for more power.

2. The easiest and least expensive way to get a large T1 is to re-wind an old microwave transformer. These transformers are rated at about 1KW and are perfect. Go to a local TV repair shop and dig through the dumpster until you get the largest microwave you can find. The bigger the microwave the bigger transformer. Remove the transformer, being careful not to touch the large high voltage capacitor that might still be charged. If you want, you can test the transformer, but they are usually still good. Now, remove the old 2000 V secondary, being careful not to damage the primary. Leave the primary in tact. Now, wind on 12 turns of wire, twist a loop (center tap), and wind on 12 more turns. The guage of the wire will depend on how much current you plan to have the transformer

supply. Enamel covered magnet wire works great for this. Now secure the windings with tape. Thats all there is to it. Remember to use high current transistors for Q1 and Q2. The 2N3055′s in the parts list can only handle 15 amps each.

3. Remember, when operating at high wattages, this circuit draws huge amounts of current. Don’t let your battery go dead .

4. Since this project produces 120 VAC, you must include a fuse and build the project in a case.

5. You must use tantalum capacitors for C1 and C2. Regular electrolytics will overheat and explode. And yes, 68uF is the correct value. There are no substitutions.

6. This circuit can be tricky to get going. Differences in transformers, transistors, parts substitutions or anything else not on this page may cause it to not function.

Transistorized Inverter 60W 12V DC to 230V AC circuit diagramThis is low cost fully transistorised inverter circuit capable of driving medium loads of the order of 40 to 60 watts using battery of 12V, 15 Ah or higher capacity.

Transistors T1 and T2 (BC548) form a 50Hz multivibrator. For obtaining correct frequency, the values of resistors R3 and R4 may have to be changed after testing. The complementary outputs from collectors of transistors T1 and T2 are given to PNP darlington driver stages formed by transistor pairs T3-T4 and T6-T7 (utilising transistors BD140 and 2N6107). The outputs from the drivers are fed to transistors T5 and T8 (2N3055) connected for push-pull operation.

Somewhat higher wattage can be achieved by increasing the drive to 2N3055 transistors (by lowering the value of resistors R7 and R8 while increasing their wattage). Suitable heatsinks may be used for the output stage transistors. Transformer X1 is a 230V primary to 9V-0-9V, 10A secondary used in reverse.